When a mass is suspended from a spring the latter extends over a distance of 10cm. What will be the period of oscillations of the same system if it is placed horizontal on a frictionless surface
Answer:
0.64 s
Explanation:
It's period of oscillation (T) can be determined by,
T = 2[tex]\pi[/tex][tex]\sqrt{\frac{l}{g} }[/tex]
Where l is the length (extension on the spring), and g the acceleration due to gravity.
But,
l = 10 cm = 0.1 m
g = 9.8 m/[tex]s^{2}[/tex]
Thus,
T = 2 x [tex]\frac{22}{7}[/tex] [tex]\sqrt{\frac{0.1}{9.8} }[/tex]
= 0.6350
T = 0.64 s
The period of oscillation would be 0.64 s.
The drawing shows four sheets of polarizing material, each with its transmission axis oriented differently. Light that is polarized in the vertical direction is incident from the left and has an average intensity of 20 W/m2. Determine the average intensity of the light that emerges on the right in the drawing (a) when sheet A alone is removed, (b) when sheet B alone is removed, (c) when sheet C alone is removed, and (d) when sheet D alone is removed.
Answer:
Explanation:
At the point when light is vertically polarized is incident on the polarizer whose axes are situated at angle points [tex]\theta _1 , \theta _2 , \theta _3[/tex] the intensity power in the wake of going through all the polarisers is given by the Malus law, applied threefold for every one of the three axes.
[tex]I = I_o \ cos \theta _1 \ cos \theta _2 \ cos \theta _ 3[/tex]
The heading of the direction of the polarization is equivalent to the pivoted axes of the polarizer provided that light is an electromagnetic wave, its course of polarization is therefore controlled by the electric field part.
∴
a)
When sheet A is removed, the transmitted light goes through B, at 30°.
[tex]I = I_o \ cos ^2 \theta _1 \ cos ^2 \theta _2 \ cos^2 \theta _3[/tex]
[tex]I = 20 \ cos ^2 30 \ cos ^2 60 \ cos ^2 30[/tex]
[tex]I = 2.81 \ W/m^2[/tex]
b)
When B is removed, No light passes since the axis of A and the axis of C are perpendicular to each other.
c)
When C is removed, the intensity is indeed zero since the axes are aligned and adjusted at 90° to one another.
[tex]\mathbf{d) \ I - I_o cos^2 (0) cos^2 (30) \ cos^2 (60)}[/tex]
[tex]\mathbf{d = 3.75 \ W/m^2}[/tex]
As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.01 mm apart and position your screen 3.09 m from the slits. Although Young had to struggle to achieve a monochromatic light beam of sufficient intensity, you simply turn on a laser with a wavelength of 639 nm . How far on the screen are the first bright fringe and the second dark fringe from the central bright fringe
Answer:
[tex]0.00195\ \text{m}[/tex]
[tex]0.00293\ \text{m}[/tex]
Explanation:
m = Order = 1
D = Distance between screen and slit = 3.09 m
d = Slit distance = 1.01 mm
[tex]\lambda[/tex] = Wavelength = 639 nm
Distance from the first bright fringe from the central bright fringe is given by
[tex]y=\dfrac{m\lambda D}{d}\\\Rightarrow y=\dfrac{1\times 639\times 10^{-9}\times 3.09}{1.01\times 10^{-3}}\\\Rightarrow y=0.00195\ \text{m}[/tex]
Distance from the first bright fringe from the central bright fringe is [tex]0.00195\ \text{m}[/tex]
Distance from the second dark fringe from the central bright fringe is given by
[tex]y=(m+\dfrac{1}{2})\dfrac{\lambda D}{d}\\\Rightarrow y=(1+\dfrac{1}{2})\dfrac{639\times 10^{-9}\times 3.09}{1.01\times 10^{-3}}\\\Rightarrow y=0.00293\ \text{m}[/tex]
Distance from the second dark fringe from the central bright fringe is [tex]0.00293\ \text{m}[/tex].
What is the mass of a jet that accelerates at 4 m/s2 after a 4,000 N force from the engines?
Answer:
1000kg
Explanation:
F=MA
Rearrange the formula: M=F/A
plug in values for F (force), and A (acceleration).
M=4000/4
M=1000kg
i think.
not sure tho.
The mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
What is Newton's second law of motion?Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, the law can be expressed as F = ma, where F is the net force acting on the object, m is its mass, and a is its acceleration. This law is fundamental to the understanding of the motion of objects under the influence of external forces.
Rearranging the formula to solve for mass, we get:
m = F / a
Substituting the given values, we get:
[tex]m = 4000 N / 4 m/s^2[/tex]
m = 1000 kg
Therefore, the mass of the jet that accelerates at 4 m/s^2 after a 4000 N force from the engines is 1000 kg.
Learn more about Newton's second law of motion, here:
https://brainly.com/question/13447525?referrer=searchRes
#SPJ3
What structure is represented by the letter C?
PLEASE HELP!!!!!!!!!!!!!
Choose 1 answer:
A) Lysosome
B) Nucleus
C) Vacuole
D) Mitochondria
Answer:
The picture is blacked out.
Answer:
If I'm correct the answer would be A) Lysosome.
The attachment is black so I can't promise you that it's the one you're looking for. But I did it on khan
the ice and steam point on a thermometer are found to be 96ml apart. what temperature is recorded when the length of mercury thread is 33.6ml above the ice point
Answer:
33.6 / 96 is the fraction of the temperature between ice and freezing
33.6 / 96 = .35
So C = .35 * 100 = 35 deg C where the ice point would be 0 deg C
You can convert C to F
F = 9 / 5 * C + 32 = 9/5 * 35 + 32 = 95 deg F
1. What is transferred from place to place by waves?
Answer:
Energy
Explanation:
A wave is a disturbance that transfers energy from one place to another without transferring matter. Waves transfer energy away from the source, or starting place, of the energy.
Moira is experiencing noticeable memory loss, muscle loss, and bone loss. What age group is Moira most likely in?
adolescence
early adulthood
middle adulthood
late adulthood
Answer:
Late adulthood
Explanation:
Just did it :)
what is the planet that scientists are exploring now?
Answer:
Mars
Explanation:
In the 1960s, humans set out to discover what the red planet has to teach us. Now, NASA is hoping to land the first humans on Mars by the 2030s. Mars has captivated humans since we first set eyes on it as a star-like object in the night sky.
good luck
please mark me as a brainliest
What do microwaves have In common with light waves?
Answer:
Both are electromagnetic waves
Explanation:
Hope this helped!!
Find the Net Force on a truck with a mass of 1,500kg and an acceleration
of 10m/s2?
Answer:
15,000 N
Explanation:
F = ma = (1,500 kg)(10 m/s^2) = 15,000 N
the speed of light in a certain medium is 0.6c. find critical angle , if the index of refraction is 1.67
Answer:
[tex]\theta_c = 36.78^o[/tex]
Explanation:
The relationship between the refractive index and the critical angle is given as follows:
[tex]\eta = \frac{1}{Sin\ \theta_c} \\\\Sin\ \theta_c = \frac{1}{\eta}\\\\\theta_c = Sin^{-1}(\frac{1}{\eta} )[/tex]
where,
η = refractive index = 1.67
θc = critical angle =?
Therefore,
[tex]\theta_c = Sin^{-1}(\frac{1}{1.67} )[/tex]
[tex]\theta_c = 36.78^o[/tex]
What is meant by the terms critical mass and supercritical?
Answer:
Critical mass is the minimum mass of fissionable material required to sustain a nuclear fission reaction, and a supercritical mass, which will provide more than enough neutrons to sustain a fission reaction at the time of detonation.
Explanation:
A student pushes a 12 N book to the
right with a force of 10 N. The book
experiences a frictional force of 3 N.
Answer:
Explanation:
My name is Jeff
If the radius of the Earth is 6400.0 km and the atmosphere is 10.0 km high, then the volume of air around the Earth is what?
Answer:
5.16 x 10^18 m^3
Explanation:
An example of conservation of angular momentum is jumping on a Merry-Go-Round. Watch this video (it starts part way through but the only thing you miss is the people pushing the Merry-Go-Round) to see someone jumping on a Merry-Gr-Round in motion like this problem. You can model the Merry-Go-Round as a solid disk with a radius of 2.70 m and a mass of 77.0 kg. Initially the Merry-Go-Round has an angular velocity 7.40 radians / second. Then the person jumps on and change the Moment of Inertia of the system. The person lands on the outer edge of the Merry-Go-Round and has a mass of 58.0 kg. What is the final angular velocity of the system after the person jumps on
Answer:
ωf = 2.95 rad/sec
Explanation:
Assuming no external torques acting while the person jumps on, total angular momentum must be conserved.Angular momentum for a rotating rigid body can be expressed as follows:[tex]L = I * \omega (1)[/tex]
where I = moment of inertia regarding the rotating axis, and ω= angular velocity.Since total angular momentum must be conserved, this means that the following equality must be satisfied:[tex]L_{o} = L_{f} (2)[/tex]
The initial angular momentum, taking into account that the Merry-Go-Round can be modeled as solid disk, can be expressed as follows:[tex]L_{o} = I_{o} * \omega_{o} = \frac{1}{2}* M* R^{2}* \omega_{o} =\\ \frac{1}{2} * 77.0 kg* (2.70m)^{2}* 7.40 rad/sec = 2076.92 kg*m2*rad/sec (3)[/tex]
The final angular momentum, is just the product of the new moment of inertia times the final angular velocity.The new moment of inertia, is just the sum of the original moment of inertia I₀ and the moment of inertia due to the person that jumps on.Assuming that we can treat him as a point mass, his moment of inertia is just the product of his mass times to the distance to the axis of rotation (the radius of the Merry-Go-Round) squared.So, we can write the new moment of inertia If as follows:[tex]I_{f} = I_{o} +( m_{p} * R^{2}) = (\frac{1}{2} * M* R^{2}) + ( m_{p} * R^{2}) =\\ (\frac{1}{2} * 77.0 kg* (2.70m)^{2}) +( 58.0 kg * (2.70m)^{2}) = \\ 280.67 kg*m2 + 422.82 kg*m2 = \\ 703.49 kg*m2 (4)[/tex]
The final angular momentum can be written as follows:[tex]L_{f} = I_{f} * \omega_{f} (5)[/tex]
Since (3) and (5) must be equal each other, replacing If by its value from (4) in (5), we can solve for ωf, as follows:[tex]\omega_{f} = \frac{L_{o} }{I_{f}} = \frac{2076.92kg*m2*rad/sec}{703.49kg*m2} = 2.95 rad/sec (6)[/tex]
If velocity decreases what happens to acceleration
Answer: Velocity is a vector; the word decreasing only applies to its magnitude (not its direction) which is called speed. If speed is increasing and direction is not changing, then acceleration is positive. If speed is constant then acceleration is zero. If speed is decreasing then acceleration is negative.
Explanation:
Water enters a shower head
through a pipe of radius 0.0112 m
at 3.75 m/s. It flows through 25
small holes, each of radius
0.001200 m. At what speed does
water come out of the shower
head? (Don't forget, there are 25
holes, not 1.)
(Unit = m/s)
Answer:
13.1
Explanation:
thats what i put in for acellus and its right
A 30 kg child went down a 10 m tall slide. Assuming no energy was lost as friction, what was the child's velocity when he reached the
bottom?
I
Which is a form of precipitation?
A. Runoff
B. Rain
C. Gas
D. Evaporation
Answer:
D. Evaporation
Explanation:
Just did it made 100%
Which is the correct formula for calculating speed?
A. speed - distance - time
B. speed = distange + time
C. speed = distance - time
D. speed = distance - acceleration
Answer:
speed=distance/time
Explanation:
its distance over time like division
Two out-of-tune flutes play the same note. One produces a tone that has a frequency of 246 Hz, while the other produces 289 Hz. When a tuning fork is sounded together with the 246-Hz tone, a beat frequency of 18.0 Hz is produced. When the same tuning fork is sounded together with the 289-Hz tone, a beat frequency of 25.0 Hz is produced. What is the frequency of the tuning fork
Answer:
[tex]264\ \text{Hz}[/tex]
Explanation:
Beat frequency of the first case = 18 Hz
Beat frequency of the second case = 25 Hz
Tone of first fork = 246 Hz
Tone of second fork = 289 Hz
First case
Beat frequency is given by
[tex]\Delta f=|f_2-f_1|\\\Rightarrow f_1=246\pm18\\\Rightarrow f_1=264, 228\ \text{Hz}[/tex]
Second case
[tex]f_2=289\pm 25\\\Rightarrow f_2=264, 314\ \text{Hz}[/tex]
The frequency of the tuning fork is [tex]264\ \text{Hz}[/tex].
Read each example and identify whether the data are observations or inferences from observations. The fish’s ventral fin measured 8.5 cm long.
Answer:
Observation
Inference
Inference
Observation
Inference
Explanation:
A diffraction grating is placed 1.00 m from a viewing screen. Light from a hydrogen lamp goes through the grating. A hydrogen spectral line with a wavelength of 656 nm is seen 60.0 cm to one side of the center. Then, the hydrogen lamp is replaced with an unknown lamp. A spectral line is seen on the screen 36.4 cm away from the center. What is the wavelength of this spectral line
Answer:
λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
d sin θ = m λ
in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
tan θ = y / L
tan θ = [tex]\frac{sin \theta}{cos \theta}[/tex] = sin θ
sin θ = y / L
we substitute
[tex]d \ \frac{y}{L}[/tex] = m λ
with the initial data we look for the distance between the lines
d = [tex]\frac{m \lambda \ L}{y}[/tex]
d = 1 656 10⁻⁹ 1.00 / 0.600
d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
λ = d y / L m
λ = 1.09 10⁻⁶ 0.364 / 1.00 1
λ = 3.9676 10⁻⁷ m
λ = 3.967 10⁻⁷ m
we reduce nm
λ = 396.7 nm
In this image of an atom, what does the outer area consisting of tiny blue
dots represent?
O A. The electron cloud
B. Protons
C. The nucleus
D. Neutrons
What should you do after obtaining a numerical answer when solving a problem?
pleaseeeeeee help
What happens to light as it moves at an angle into a medium that has a higher index of refraction?
A. It slows down, and the angle decreases.
B. It speeds up, and the angle increases.
C. It slows down, and the angle increases.
D. It speeds up, and the angle decreases.
Families attempting to rebound from crises are advised to discontinue family rituals and leisure activities, as they may regenerate negative family stress and threaten resilience.
A. False
B. True
How many joules of kinetic energy does a pendulum have when it has 100 joules of potential energy
Answer:
The maximum kinetic energy is 100 j.
Explanation:
The kinetic energy = (potential energy) + (kinetic energy) and the potential energy of 0 J implying its kinetic energy is 100 J, which is its maximum.
Answer :100J of KE.
Explanation:
After the initial experiment, students wondered how a person's weight would influence the results. They conducted a second experiment to determine if the mass of an object affected friction, assuming the types of surfaces remained constant. A spring scale was attached to a wooden block (1 kg). The block was placed on a wooden board and the spring scale was used to pull the block. The magnitude of the force required to start the block moving was recorded in the data table. The experiment was repeated using two, three, and four blocks. The data can be seen in the data table at the top of the page. What is the relationship between static friction and weight?
Answer:
The greater the weight of the person, the more static friction.
Explanation:
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