Vectors u and v are shown on the graph.
Which of the following vectors represents v – u?

Answer:

14

Step-by-step explanation:

because if you subract -17 it will become a postive 17 and 17-3 is 14

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All the values of x that solve the given system of equations are as follows:

x = 17/2.

A system of equations is when multiple variables are related by equations, which are solved to find the values of each variable. Usually, these relations are linear, but they may also be quadratic, as is the case in this problem.

For this problem, we are given two equations, as follows:

From the second equation, we have that:

x = 9 - 3y.

Replacing in the first, we have that:

(9 - 3y)² - 9y² = 72.

9y² - 54y + 81 = 72.

54y = 9.

y = 9/54

y = 1/6, as 9/9 = 1, 54/9 = 6.

Hence the solution for x of the system of equations is found by replacement, as follows:

x = 9 - 3y = 9 - 3/6 = 9 - 1/2 = 18/2 - 1/2 = 17/2.

The solution is x = 17/2.

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The relationship between distances biked and distances run is

D(bike) = 2 × D(run)

Here, we have been shown that when distance run is, lets say x then distance run is 2x

When distance run is 2 then distance biked is 4, twice as distance run.

Again in distance run 3[tex]\frac{1}{2}[/tex], distance biked is 7, so this proves that

D(bike) = 2 × D(run)

The measurement of distance between two objects or points can be quantitative or occasionally qualitative. Distance in physics or common language can refer to a physical length or an assumption based on other factors (e.g. "two counties over").

Since spatial thinking is a rich source of conceptual metaphors in human thought, the term is also frequently used metaphorically to denote a measure of the degree of separation or the statistical distance between two similar objects (such as edit distance between strings of text or statistical distance between probability distributions) (as exemplified by distance between people in a social network).

A metric space is a mathematical concept that is used to define the majority of these conceptions of distance, both literal and figurative.

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An equation of the function in standard form is equal to -x²/4 + 1 = 0.

A quadratic function can be defined as a mathematical expression (equation) that can be used to define and represent the relationship that exists between two or more variable on a graph.

In Mathematics, the standard form of a quadratic equation is given by;

ax² + bx + c = 0

y = f(x) = ax² + bx + c

Next, we would formulate a system of equations from the data contained in the table above:

-3 = a(-4)² + b(-4) + c  ⇒ -3 = 16a - 4b + c      .......equation 1.

0 = a(-2)² + b(-2) + c  ⇒   0 = 4a - 2b + c      .......equation 2.

1 = a(0)² + b(0) + c  ⇒   1 = c                            .......equation 3.

Substituting the value of c into eqn. 1 and eqn. 2, we have:

-4 = 16a - 4b        .......equation 4.

-1 = 4a - 2b          .......equation 5.

Multiplying eqn. 5 by 2 and solving simultaneously, we have:

-4 = 16a - 4b

-2 = 8a - 4b

-2 = 8a

a = -2/8

a = -1/4  

For the value of b, we have:

-1 = 4a - 2b

-1 = 4(-1/4) - 2b

-1 = -1 - 2b

2b = 0

b = 0

Substituting the values of a, b and c into the standard form of a quadratic equation:

ax² + bx + c = 0

-1/4x² + (0)x + 1 = 0

-x²/4 + 1 = 0

Check:

When x = 2, we have:

-x²/4 + 1 = 0

-2²/4 + 1 = 0

-4/4 + 1 = 0

-1 + 1 = 0

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The weighted average of the points on the line is 3/5 after applying the concept of the weighted average.

It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.

It is given that:

The number line is shown in the picture:

The number line can be defined as the representation of the numbers on a straight line that goes infinitely on both sides.

From the number line:

The weighted average = [2(-5) + 8(2)]/(2 + 8)

The weighted average = [-10 + 16]/(10)

The weighted average = [6]/(10)

The weighted average = 3/5

Thus, the weighted average of the points on the line is 3/5 after applying the concept of the weighted average.

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Answer:

5x+10

Step-by-step explanation:

[tex](f \circ g)(x)=f(g(x)) \\ \\ =f(-5x-6) \\ \\ =-(-5x-6)+4 \\ \\ =5x+6+4 \\ \\ =5x+10[/tex]

The values of all the variables are:

Given equations:

To find the values of x, y, w, and z:

Substitute (w = -3) in z + w = 2:

Substitute (w = -3) and (z = 5) in 3y + 18z + 6w = 24:

Substitute (y = - 16), (w = -3) and (z = 5) in -4x - 8y - 2z - 6w = 5

Therefore, the values of all the variables are:

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The answers are -0.5, 2.2, 3.8, and 9.0

We need to evaluate the expression 3.8 + 0 + y for the given values of y.

Let x = 3.8 + 0 + y

The values of y are -4.3, -1.6, 0, and 5.2

Let's substitute the value of y in the expression and calculate the values of x.

Refer to the attached image for the values of the expression corresponding to the values of y.

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Answer:

-0.5, 2.2, 3.8, and 9.0

Step-by-step explanation:

Answer: 90 degrees

Step-by-step explanation:

Dilations preserve angle measure.

Answer:

R 19734.32

Step-by-step explanation:

If an amount P is deposited at R% interest compounded annually for n years, the amount at the end of n years is given by the formula

[tex]P = P(1 + r)^t[/tex]

r = R/100

Note

Interest rate 8% = 8/100 =0.08 for computation

Interest rate 9% = 8/100 =0.09 for computation

Since the interest rate changes after 3 years, the first thing to do is to find out how much the value is after 3 years

[tex]V(3 years) = 6000(1 + 0.08)^3[/tex] = 6000 x1.08³ = 6000 x 1.259712 = 7558.27

After 3rd year interest changes to 9%(0..09) but an additional amount is deposited

Let's find the value after the 4th year at 9% compounded annually using the general formula with r = 0.09 and t =1

V (after 4th year) = 7558.27(1.09)¹ = 7558.27 x 1.09 = 8238.51

We are depositing 7000 at the end of the 4th year so the principal becomes 8238.51 + 7000 = 15,238.51

This new amount accrues interest at 9% for 3 more years (7-4)

So value of savings at end of 7th year is

V = 15238.51(1+0.09)³ = 15238.51 x 1.259712 = 19734.32

Answer:

R19734.32

Step-by-step explanation:

Annual Compound Interest Formula

[tex]\large \text{$ \sf A=P\left(1+r\right)^{t} $}[/tex]

where:

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=6000(1+0.08)^3[/tex]

[tex]\implies \sf A=6000(1.08)^3[/tex]

[tex]\implies \sf A=6000(1.259712)[/tex]

[tex]\implies \sf A=7558.272[/tex]

Therefore, the amount in the account after 3 years was R7558.272.

The interest rate changed to 9%.

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=7558.272(1+0.09)^1[/tex]

[tex]\implies \sf A=7558.272(1.09)[/tex]

[tex]\implies \sf A=8238.51648[/tex]

Therefore, the value of savings at the end of the 4th year was R8238.51648.

After four years, R7000 was added to the account.

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15238.21648(1+0.09)^3[/tex]

[tex]\implies \sf A=15238.21648(1.09)^3[/tex]

[tex]\implies \sf A=15238.21648(1.295029)[/tex]

[tex]\implies \sf A=19734.3207...[/tex]

Therefore, the value of the savings at the end of the seventh year is R19734.32.

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The  option which represents the situation described if a is the number of shares of Stock X purchased and b is the number of shares of Stock Y purchased is:

D. 22a + 35b ≤ 4,500

a + b ≥ 100

a ≥ 20

b ≥ 15

What does at least and no more than mean in this instance?

At least is interpreted in inequalities as greater than or equals to whereas "no more than" implies that it cannot be greater, hence, can be less than or equals to, as a result, the following relationships are determined:

a≥20(the least number of X shares is a, which is 20)

b≥ 15(the least number of Y shares is a, which is 15)

total amount spent on X=22*a=22a

total amount spent  on Y=35*b=35b

maximum amount to invest=4500(less than or equals to)

22a+35b≤ 4500

sum of X and Y shares altogether(least)=100

a+b≥100

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Full question:

Heinrich must buy at least 100 shares of stock for his portfolio. The shares he buys will be from Stock X, which costs $22 per share and Stock Y, which costs $35 per share. His budget for buying stock is no more than $4,500. He must buy at least 20 shares of Stock X and 15 shares of Stock Y. Which of the following represents the situation described if a is the number of shares of Stock X purchased and b is the number of shares of Stock Y purchased?

A. 22a + 35b ≤ 4,500

a + b ≥ 100

a ≤ 20

b ≤ 15

B. 22a + 35b ≤ 4,500

a + b ≤ 100

a ≤ 20

b ≤ 15

C. 22a + 35b ≤ 4,500

a + b ≤ 100

a ≥ 20

b ≥ 15

D. 22a + 35b ≤ 4,500

a + b ≥ 100

a ≥ 20

b ≥ 15

Answer:

Step-by-step explanation:

the answer is 6847 if anyone solves it

Answer:

its A

Step-by-step explanation:

If the length of the insect is 2.5 inches long, then the length of the insect in centimeter is 6.35 centimeter

Given,

The length of the insect = 2.5 inches

Convert inches to centimeter

We know,

1 inches = 2.54 centimeter

2.5 inches = 2.54× 2.5

=6.35 centimeter

Hence, if the length of the insect is 2.5 inches long, then the length of the insect in centimeter is 6.35 centimeter

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Answer:

Step-by-step explanation:

y = f(x) = 3x -2

When x = -4,

y = 3(-4) -2 = -12-2 = -14

When x = 2,

y = 3(2) -2 = 6-2 = 4

When x = 3,

y = 3(3) -2 = 9-2 = 7

1. The cost per equivalent unit for materials for the month in the first processing department of Annenbaum Corporation is $20.50.

2. The cost per equivalent unit for conversion costs for the month in the first processing department of Annenbaum Corporation is $34.208.

The cost per equivalent unit is the quotient of the total costs to be accounted for divided by total equivalent units of production.

The equivalent units of production are a mathematical equivalent of completed units based on their degrees of completion.

Beginning work in process:

Materials costs = $5,700 65%

Conversion costs = $6,800 45%

Started units = 6,500 units

Transferred out units = 5,900 units

Ending inventory:

Material costs = 50%

Conversion costs = 35%

Costs incurred during the period:

Materials costs......... $125,500

Conversion costs...... $207,000

Beginning inventory  =      400 units

Started during period = 6,500 units

Total units processed = 6,900 units

Units transferred out =  5,900 units

Ending inventory =         1,000 units

                      Physical Units    Material          Conversion

Transferred out      5,900       5,900 (100%)    5,900 (100%)

Ending inventory    1,000          500 (50%)         350 (35%)

Total equivalent units            6,400 units       6,250 units

                                        Material          Conversion

Beginning WIP                  $5,700               $6,800

Costs for the period       125,500             207,000

Total production costs $131,200            $213,800

Total equivalent units    6,400 units       6,250 units

Cost per equivalent unit  $20.50         $34.208 ($213,800/6,250)

Thus, the cost per equivalent unit of materials is $20.50, while it is $34.208 for conversion costs.

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Cost Percent Complete Materials costs......... $5,700 65% Conversion costs...... $6,800 45% A total of 6,500 units were started and 5,900 units were transferred to the second processing department during the month. The following costs were incurred in the first processing department during the month: Materials costs......... $125,500 Conversion costs...... $207,000 The ending inventory was 50% complete with respect to materials and 35% complete with respect to conversion costs. Required: 1. What's the cost per equivalent unit for materials for the month in the first processing department? 2. What's the cost per equivalent unit for conversion costs for the month in the first processing department?

The employee must make a sale of $ 1,56,000 to get a total salary of $ 5000 with the commission rate as 2 %.

The basic salary of the employee = $ 2000

Now he wants to earn $ 5000.

That means he has to earn 4 500 - $ 2000 = $ 3000 from the sales commission that he gets.

Sales commission is 2 %.

Let the sales above $ 6000 be x

2 % x = 3000

2 / 100 x = 3000

2 x = 3,00,000

x = 1,50,000

Total sales = $ 6000 + $ 1,50,000 = $ 1,56,000

Therefore, the employee must make a sale of $ 1,56,000 to get a total salary of $ 5000 with the commission rate as 2 %.

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The amount that the bidder needs to put into a kitty for the other bidders to be compensated will be $57600.

It should be noted that 5 people can claim joint ownership of an item and intend to divide it by the Method of Sealed Bids and the winner offers a bid of $72,000.

Therefore, the fair share will be:

= Bids / Number of people

= 72000 / 5

= 14400

Therefore, the amount that the bidder needs to put into a kitty for the other bidders to be compensated will be:

= $72000 - $14400

= $57600

Therefore, the amount that the bidder needs to put into a kitty for the other bidders to be compensated will be $57600.

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We need to know about ratio for solving the problem. Ahmed has to divide the money as 1000, 2000 and 2500.

In simple words ratio indicates how many times one number contains other. With the help of this division we need to assume a number x which is held 2 times in first part, 4 times in second part and 5 times in third part of the total money that Ahmed wants to divide. We can find the ratio of a quantity to another by dividing one quantity by the other and cancelling the  common factors. For this question we have a total amount of money 5500 which we need to divide in ratio 2:4:5 in other words we can say that the three parts are 2x,4x and 5x, these three parts will add up to be 5500. So we can write

2x+4x+5x=5500

11x=5500

x=500

The three parts of the money will be 2x500=1000, 4x500=2000 and 5x500=2500

Therefore we found using the concept of ratio that Ahmed needs to divide his money as 1000,2000 and 2500.

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Answer:

maybe if you learn you will know

Step-by-step explanation:

Answer:

35 yd

Step-by-step explanation:

For any given [tex]0\le y\le4[/tex], a cross section in that plane is a circle whose diameter is [tex]x=\sqrt{10}\,y^2[/tex] with thickness [tex]\Delta y[/tex]. Such a cross section contributes a volume of [tex]\pi \left(\frac x2\right)^2 \, \Delta y = \frac{5\pi}2 y^4 \, \Delta y[/tex].

As [tex]\Delta y\to0[/tex] and the number of cross sectional cylindrical disks increases without bound, the infinite sum of their volumes converge to the volume of the solid, given by the definite integral

[tex]\displaystyle \frac{5\pi}2 \int_0^4 y^4 \, dy = \frac{5\pi}2 \cdot \frac{4^5}5 = \boxed{512\pi}[/tex]

Answer:

  $2780

Step-by-step explanation:

Given an income tax of 10% of the first $7000 and 16% of all after that, you want the tax on $20,000.

Manuel's income is more than $7000, so the tax is computed in two parts.

First $7000

The tax on the first $7000 of income is 10%:

  tax = $7000 × 0.10 = $700

Amount Over $7000

The amount over $7000 is ...

  $20,000 -7,000 = $13,000

The tax on that amount is 16%:

  tax = $13,000 × 0.16 = $2080

Total tax due

The tax Manuel must pay is the total of these two amounts:

  $700 +2080 = $2780

Manuel must pay $2780 in income tax for last year.

(0,0) because that is the center

Answer:

-8756 %

Step-by-step explanation:

Because 5 is a strong number

Answer:

1/5 needs to be 20 words long

When Amy picks a black marble in the fourth attempt, the probability that in the fifth attempt she will pick a red or a black marble is 0.7143.

It should be noted that after the 3rd pick we have: 4 white, 3 red and 8 black marbles.

The probability that the 4th marble is black is:

P ( Black ) = 8 / 15 = 0.5333

After the 4th pick we have: 4 white, 3 red and 7 black marbles.

P ( Red or Black ) = 10 / 14 = 5 / 7 = 0.7143.

Therefore, the probability is 0.7143.

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Amy has a box containing 6 white, 4 red, and 8 black marbles. She picks a marble randomly. It is red. The second time, she picks a white marble. In the third attempt, Amy picks a white marble again. Amy has not replaced the marbles she picked. The probability that the fourth marble Amy picks is black is . If Amy picks a black marble in the fourth attempt, the probability that in the fifth attempt she will pick a red or a black marble is____.