Venessa has a piggy bank that contains a collection of nickels, pennies, dimes and quarters. She randomly draws a coin out of the
Egy bank, records the result, and then replaces the coin. The results of her draws are shown below.

Based on the results above, predict the number of times a dime would be drawn if Venessa draws a coin 336 times.

A. 58

B. 36


C. 64

D. 38

Answer:

-1/2

Step-by-step explanation:

pemdas rules

1. 18 x 2 - 30 = 6

2. 3-6= -3

3. 36/-3 = -12

4. 96/-12 = -8

5.  (31-16+1) = 16

6. -8/16 = -1/2

Answer:

Step-by-step explanation:

We know that first 150 postive even Integers are 2,4,6,8,10... 300.

Here,

[tex]\\[/tex]

Substituting values in the formula:

[tex] \\ :\implies \sf \: \: S_{n} = \dfrac{n}{2} (a + a_{n}) \\ \\[/tex]

[tex] :\implies \sf \: \: S_{n} = \dfrac{150}{2} (2 + 300) \\ \\ [/tex]

[tex] :\implies \sf \: \: S_{n} = 75(302) \\ \\ [/tex]

[tex] :\implies \: \:{ \underline{ \boxed{ \pmb{ \pink { \rm{S_{n} = 22650 }}}}}} \\ \\[/tex]

Answer:

Formula for finding sum of nth terms =

n/2 × (a + an)

putting the known values ,

Sum = 150/2 × ( 2+300)

Sum = 75 × 302

Sum of first 150 positive even integers = 22650

Step-by-step explanation:

The centroid O cuts every median in the ratio 2:1. The distance between a vertex and the centroid is twice the distance between the centroid and the midpoint of the opposite side.

Therefore: |OD| = 2|OCI

3x-2=2(5x)

3x-2=10x

7x=-2

x=(-2/7)

Answer:

282.3 gallons

Step-by-step explanation:

if needed you can round to 282

Answer:

180 units^2

Step-by-step explanation:

The formula to find the area of a sphere is:

A=4(pi)(r)^2

A sphere with radius 2r has an area = 4π(2r)² = 4π.4r² = 16πr²

The ratio of the larger sphere to the smaller = 16πr² : 4πr² = 4 : 1

If the area of the smaller sphere is 45 units then the area of the larger sphere is 45 x 4 = 180 units^2.

hope this helps :)

Answer:

Step-by-step explanation:

In the question we have given volume of Sphere that is 562.5 π in³ and we have asked to find the radius of given sphere. We know that the volume of sphere ,

[tex] \blue{ \boxed{ \rm{Volume \: of \: Sphere = \frac{4}{3} \pi r {}^{3} }}}[/tex]

So equating it with given volume for finding the radius of sphere :

[tex] \longmapsto \: \frac{4}{3} \pi r{}^{3} = 562.5\pi[/tex]

Step 1 : Cancelling π as it was present in both side :

[tex]\longmapsto\:\frac{4}{3} \cancel{\pi }r{}^{3} = 562.5 \cancel{\pi}[/tex]

Step 2 : Transposing 4/3 to right hand side :

[tex]\longmapsto \: r {}^{3} = 562.5 \times \frac{3}{4} [/tex]

Step 3 : Multiplying 562.5 with 3 :

[tex]\longmapsto \:r {}^{3} = \frac{1687.5}{4} [/tex]

Step 4 : Dividing 1687.5 by 4 :

[tex]\longmapsto \:r {}^{3} = 421.875[/tex]

Step 5 : Finding cube root of 421.875

[tex]\longmapsto \:r = \sqrt[3]{421.875} [/tex]

Step 6 : We get :

[tex]\longmapsto \: \red{ \boxed{r = 7.5}}[/tex]

Answer:

0

Step-by-step explanation:

tan(x + [tex]\frac{\pi }{2}[/tex] ) ← substitute x = [tex]\frac{\pi }{2}[/tex]

tan([tex]\frac{\pi }{2}[/tex] + [tex]\frac{\pi }{2}[/tex] )

= tanπ

= 0

Step-by-step explanation:

see this this will help you

Answer:

f(3) = -37

Step-by-step explanation:

f (x) = -6x - 19

Let x = 3

f (3) = -6*3 - 19

      = -18-19

      = -37

Answer:

Step-by-step explanation:

Use distributive property: a*(b+c) =a*b +a*c

1) 785 * 105 = 785 * (100 + 5)

                  = 785*100 + 785*5

                  = 78500 + 3925

                  = 82425

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

2) 1006 * 95 = (1000 + 6) *95

                     = 1000*95 + 6*95

                      = 95000 + 570

                     = 95570

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

3) 3096*91  = 3096 * (100 - 9)

                    = 3096*100 - 3096*9

                    = 309600 - 27864

                    = 281736

Answer:

7.1 cm^2

Step-by-step explanation:

Area  = pie * radius^2

Area = pie * 1.5^2

= 7.0685

Answer: 7.1 cm ^2

Step-by-step explanation:

Using the t-distribution, it is found that the 95% confidence interval for the population mean is (1413.18, 1564.82).

The confidence interval is:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

In which:

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 65 - 1 = 64 df, is t = 1.9977.

The parameters of the interval are given as follows:

[tex]\overline{x} = 1489, s = 306, n = 65[/tex].

Hence, the bounds of the interval are given by:

[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 1489 - 1.9977\frac{306}{\sqrt{65}} = 1413.18[/tex]

[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 1489 + 1.9977\frac{306}{\sqrt{65}} = 1564.82[/tex]

The 95% confidence interval for the population mean is (1413.18, 1564.82).

More can be learned about the t-distribution at https://brainly.com/question/16162795

Using the z-distribution, as we are working with a proportion, it is found that the p-value of the test is of 0.

At the null hypothesis, it is tested if the proportion is of 71%, that is:

[tex]H_0: p = 0.71[/tex]

At the alternative hypothesis, it is tested if the proportion has decreased, that is:

[tex]H_1: p < 0.71[/tex].

The test statistic is given by:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

In which:

In this problem, we have that the parameters are:

[tex]n = 300, \overline{p} = \frac{165}{300} = 0.55[/tex]

Hence, the value of the test statistic is found as follows:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

[tex]z = \frac{0.55 - 0.71}{\sqrt{\frac{0.71(0.29)}{300}}}[/tex]

z = -6.11

Using a z-distribution calculator, with a left-tailed test, as we are testing if the proportion is less than a value, and z = -6.11, it is found that the p-value is of 0.

More can be learned about the z-distribution at https://brainly.com/question/26454209

Answer:

y<7

Step-by-step explanation:

3y-10 < 11     add 10 to both sides of the equation

3y < 21      divide by 3

y < 7

Answer:

Step-by-step explanation:

Answer:

1)  True, True, False

Rewritten statement:  46,013.86 cm³ of water was used to fill 40 balloons

2) False, True, True

Rewritten statement:   The formula [tex]\sf V= \sf \dfrac43 \pi (2.4)^3[/tex] can be used to find the volume of the model of Earth.

3) True, False, True

Rewritten statement:  The volume of all the basketballs is 13,467.62 in³

Step-by-step explanation:

[tex]\textsf{Volume of a sphere}=\sf \dfrac43 \pi r^3 \quad \textsf{(where r is the radius)}[/tex]

Given:

Substituting the given radius into the formula:

[tex]\begin{aligned}\implies \sf V & = \sf \dfrac43 \pi (6.5)^3\\\\& =\sf \dfrac{2197}{6} \pi \\\\& = \sf 1150.35\: cm^3 \:(nearest\:hundredth)\end{aligned}[/tex]

[tex]\textsf{Volume of 40 balloons}=\sf 40 \times \dfrac{2197}{6} \pi=46013.86\:cm^3\:(nearest\:hundredth)[/tex]

Rewritten statement:  46,013.86 cm³ of water was used to fill 40 balloons

-------------------------------------------------------------------------------------------------------

[tex]\textsf{Volume of a sphere}=\sf \dfrac43 \pi r^3 \quad \textsf{(where r is the radius)}[/tex]

Earth

Given:

Substituting the given radius into the formula:

[tex]\implies \sf V= \sf \dfrac43 \pi (2.4)^3[/tex]

[tex]\implies \sf V=57.91\:cm^3\:(nearest\:hundredth)[/tex]

Rewritten statement:  

The formula [tex]\sf V= \sf \dfrac43 \pi (2.4)^3[/tex] can be used to find the volume of the model of Earth.

Saturn

Given:

Substituting the given radius into the formula:

[tex]\implies \sf V= \sf \dfrac43 \pi (22.8)^3[/tex]

[tex]\implies \sf V=49647.02\:cm^3\:(nearest\:hundredth)[/tex]

Difference between models= 49,647.02 - 57.91 = 49,589.11 cm³

-------------------------------------------------------------------------------------------------------

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Substituting the given values into the formula:

[tex]\implies \sf V=\pi (21)^2(54)[/tex]

[tex]\implies \sf V=23814\pi[/tex]

[tex]\implies \sf V=74813.89\:in^3\:(nearest\:hundredth)[/tex]

[tex]\textsf{Volume of a sphere}=\sf \dfrac43 \pi r^3 \quad \textsf{(where r is the radius)}[/tex]

Given:

[tex]\begin{aligned}\textsf{Volume of all 30 basketballs} &=\sf 30 \times \dfrac{4}{3}\pi (4.75)^3\\ & =\sf 13467.62\:in^3\:(nearest\:hundredth)\end{aligned}[/tex]

Rewritten statement:  The volume of all the basketballs is 13,467.62 in³

Empty space in the container = volume of container - volume of basketballs

⇒ 74813.89 - 13467.62 = 61,346.27 in³

Answer:

108m

Step-by-step explanation:

2 sides are 30m long and 2 sides are 24m long.

Add all 4 sides of the playground to find the perimeter.

30m + 24m + 30m + 24m = 108 m

Answer:

[D] 62°

Step-by-step explanation:

A right triangle = 90 degree angle

A triangle =  180 degrees

Therefore,

90 + 28 = 118

180 - 118 = 62

Hence, the measure of the other acute angle is 62

Thus, the answer is [D] 62 degree

Kavinsky

Answer:

D. 62

Step-by-step explanation:

Answer: it’s simply a

Step-by-step explanation: X =bsquare

Answer:

(7x+9)(x-5)

Hope this helps!

Answer:

If the interval is 1 < x < 3, then you are examining the points (1,4) and (3,16). From the first point, let a = 1, and f (a) = 4. From the second point, let b = 3 and f (b) = 16. The average rate of change is 6 over 1, or just 6.

Step-by-step explanation:

If the interval is 1 < x < 3, then you are examining the points (1,4) and (3,16). From the first point, let a = 1, and f (a) = 4. From the second point, let b = 3 and f (b) = 16. The average rate of change is 6 over 1, or just 6.

Answer:

5i√5

Step-by-step explanation:

Remark

125 factors

It is factored into 5*5*5

The rule for √5*5*5  is that two can be taken outside the square root sign. I is placed in front of the root sign like 5√ and the other 5 is thrown away.

The remaining 5 is left under the root sign

As usual

√-1 is i is taken outside the root sign

Solution

5i √5 is what you get.

Answer:

c po

because that is the answer in the bakc of my module hope its help

Answer:

7.

4.7 * 10^14 , 9.99 * 10^14 , 2.9 * 10^15 , 4.5 * 10^15

8.

9.99 * 10^-8 , 4.8 * 10^-8 , 9.99 * 10^-4 , 6.5 * 10^-4

Answer:

the answer is -85 good luck on your test or honework :)