what 2 integers are closest to the number 75

Answer:

who where when what how?!!?

Step-by-step explanation:

Answer:

don't click the link the bot put it's a bad link btw

Answer: 32ft

Step-by-step explanation:

got it right

Answer:

Average

Step-by-step explanation:

Mean is the average of a set of numbers that you are given.

To get the mean you need to add up all the numbers and divide that total number by the amount of numbers you had.

Answer:

b

Step-by-step explanation:

Answer:

21 ft by 66 ft

Step-by-step explanation:

From the question,

P = 2(L+W)............... Equation 1

Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.

If the Length of the Field is 45 ft longer than the width,

L = 45+W............ Equation 2

Substitute Equation 2 into equation 1

P = 2(45+W+W)

P = 90+4W............. Equation 3

Given: P = 174 ft.

Substitute into equation 3

174 = 90+4W

4W = 174-90

4W = 84

W = 84/4

W = 21 ft.

Substituting the value of W into equation 2

L = 45+21

L = 66 ft.

Hence the dimensions of the playing field is 21 ft by 66 ft

Answer:

(-9, 14)

Step-by-step explanation:

Let the column vector be represented as a = (3, 4) and b = (5, -2)

2a = 2(3,4)

2a = (6,8)

3b = 3(5, -2)

3b = (15, -6)

Take the difference 2a - 3b

2a - 3b = (6,8) - (15, -6)

2a - 3b = (6-15, 8 -(-6))

2a - 3b = (-9, 14)

Hence the column vector is (-9, 14)

We want to find 2a - 3b as a column vector, we will get:

[tex]2a - 3b = \left[\begin{array}{ccc}-9\\14\end{array}\right][/tex]

So we want to perform a sum (difference actually) of vectors, we have that:

[tex]a = \left[\begin{array}{ccc}3\\4\end{array}\right] \\\\\\b= \left[\begin{array}{ccc}5\\-2\end{array}\right][/tex]

Remember that when we multiply a vector by a scalar, each component gets multiplied by that scalar, so we have:

[tex]2a = \left[\begin{array}{ccc}2*3\\2*4\end{array}\right] = \left[\begin{array}{ccc}6\\8\end{array}\right] \\\\\\3b= \left[\begin{array}{ccc}3*5\\3*-2\end{array}\right] = \left[\begin{array}{ccc}15\\-6\end{array}\right][/tex]

Now we just perform the direct difference:

[tex]2a - 3b = \left[\begin{array}{ccc}6\\8\end{array}\right] - \left[\begin{array}{ccc}15\\-6\end{array}\right] = \left[\begin{array}{ccc}6 - 15\\8 + 6\end{array}\right] = \left[\begin{array}{ccc}-9\\14\end{array}\right][/tex]

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Answer:

2

Step-by-step explanation:

A=[tex]\pi[/tex]r²

(19/6)[tex]\pi[/tex]=(285/360)[tex]\pi[/tex]r²

Divide both sides by pi, and they cancel out.

x is the radius, so replace r with x.

19/6=285/360x²

19/6÷285/360=x²

(19/6)·(360/285)=x²

4=x²

√4=x

2=x

Answer:

last 4rd

Step-by-step explanation:

The algebraic expression for [tex]8[/tex] more than [tex]5[/tex] times a number will be [tex](8+5x)[/tex] and the verbal expression for [tex]4(n + 6)[/tex] will be four times the sum of a number and six.

Expressions is a finite combination of symbols that is well-formed according to rules that depend on the context.

We have,

[tex]8[/tex] more than [tex]5[/tex] times a number

Now,

Let a number [tex]=x[/tex]

So,

According to the question,

We get, [tex](8+5x)[/tex]

So, this is the algebraic expression .

We have,

[tex]4(n + 6)[/tex]

So,

According to the question,

[tex]4(n + 6)[/tex] will be written as four times the sum of a number and six.

So, this is the verbal expression .

Hence, we can say that the algebraic expression for [tex]8[/tex] more than [tex]5[/tex] times a number will be [tex](8+5x)[/tex] and the verbal expression for [tex]4(n + 6)[/tex] will be four times the sum of a number and six.

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Answer:

Line A is the  

✔ y-axis

Region B is  

✔ a quadrant

Point C is the  

✔ origin

Line D is the  

✔ x-axis

Step-by-step explanation: Did it on Edgen

Answer:

its line d

Step-by-step explanation:

I did the test

Answer:

3.75 liters a day

Step-by-step explanation:

Answer:

Step-by-step explanation:

T-Ball 52%                   Soccer 48%               Basketball 35%

Answer:

The answer is 0

Step-by-step explanation:

Jesus will help you he think you got this

Answer: =-2(x+1)

Step-by-step explanation:

Answer:

-2x-2

Step-by-step explanation:

6-8=-2

x-3x=-2x

Answer:

not a straight line

Step-by-step explanation:

Linear has the word "line" in it. A linear relation has a graph shaped like a straight line.

Nonlinear means "not like a straight line".

Answer: not a straight line

its 1/6 because all together u have 12 books and there are 2 comics so 2/12 simplified is 1/6

Answer:

It does not absorb moisture, but does absorb oil; this quality makes polyester the perfect fabric for the application of water-, soil-, and fire-resistant finishes. Its low absorbency also makes it naturally resistant to stains.

Step-by-step explanation:

I cant see the question's very well so ^

Answer:

2nd one

Step-by-step explanation:

Polyester is what a call hydrophobic meaning it doesn’t absorb water. Even after washing it it’ll repel the clean water making still dirty.

Answer:

1. ∠CFD = 28°

2. ∠RPQ = 53°

Step-by-step explanation:

For the first one:

∠CFD and ∠DFE are angles on a straight line

Angles on a straight line add up to equal 180

That being said we can find the missing angle (∠CFD) by subtracting the given angle measure (152°) from 180

so ∠CFD = 180 - 152

180 - 152 = 28

Hence, ∠CFD = 28°

For the second one:

Complementary angles have a sum of 90°

If ∠RPQ and ∠SPR are complementary angles we can find the missing angle ( ∠RPQ in this case ) by subtract the given angle measure ( 37° ) from 90

so ∠RPQ = 90 - 37

90 - 37 = 53

Hence , ∠RPQ = 53°

9514 1404 393

Answer:

  work shown is incorrect

Step-by-step explanation:

An equal sign is a sacred symbol. It needs to be treated with respect. The equal sign can only be used legitimately when the expression on one side is actually equal to the expression on the other side.

Here, you seem to have ...

  16 -7 = 11 . . . . . FALSE

  9 ≠ 11 . . . . . . . . why the equal sign should not be used

So, the inequality you're trying to solve depends on which of the "equal" values you intend.

7 + x < 16 - 7

Subtracting 7 from both sides gives ...

  x < 2

This graphs as an open circle at x=2 and shading of the number line to the left from there. See the attachment for the graph.

__

7 + x < 11

Subtracting 7 from both sides gives ...

  x < 4

This graphs as an open circle at x=4 and shading of the number line to the left from there. The graph is similar to the one attached, but has the point at x=4 instead of x=2.

__

Your solution

Somehow you have concluded that x < 11. If that is correct, and you want to graph that, you need to draw an open circle at x=11 (not x=12), and shade the number line to the left from that point. A solid dot at x=12 and a line left of that does not represent the inequality x < 11.

A solid dot is used only for the "or equal to" case. You have graphed x ≤ 12.

Answer:

there are 21 students in her class.

Step-by-step explanation:

Since the 12 girls corresponds to the 4 in the ratio, I multiplied the 3 by three to get the amount of boys. then add the boys to the girls to get 21 students.

Answer:

A fraction is in simplest form when the top and bottom cannot be any smaller, while still being whole numbers.

Step-by-step explanation:

Answer:

The first picture on the second page

Step-by-step explanation:

The first picture on the second page would be the answer because it gives exactly one input for each output. It also passes the vertical line test because no point throughout the line creates a vertical line.

Answer:

The measure of ∠X is 45°.

Step-by-step explanation:

Complementary angles are two angles that have a sum of 90°.

I subtracted 45 from 90 (90-45) and got 45°.

Answer:

[tex]\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}[/tex]

Step-by-step explanation:

Given

[tex]\sqrt{128a^{6}b^{13}}[/tex]

Required

Solve

[tex]\sqrt{128a^{6}b^{13}}[/tex]

The expression can be split to:

[tex]\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}[/tex]

So, we have:

[tex]\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{3} * b^{6} * \sqrt{b}[/tex]

Rewrite as:

[tex]\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2} * \sqrt{b}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}[/tex]

[tex]\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}[/tex]