what are 2, 3, and 4

The balance of the CD after 6 years will be $678.35.

To calculate the balance of the CD after 6 years, we need to use the formula:

[tex]A = P(1 + r/n)^{(nt)[/tex]

Where:
A = the balance after 6 years
P = the initial deposit of $500
r = the annual interest rate of 2.25%
n = the number of times the interest is compounded per year (biweekly = 26 times per year)
t = the number of years (6)

Plugging in the values, we get:

A = [tex]500(1 + 0.0225/26)^{(26*6)[/tex]
A = 500(1.001727)¹⁵⁶
A = 500(1.3567)
A = $678.35

Therefore, the balance of the CD after 6 years will be $678.35.

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The type of triangle formed from the side lengths of a triangle 2, 10, 11 is a scalene triangle.

Based on the given side lengths of a triangle (2, 10, 11), we can determine the type of triangle formed by examining their relationships. First, let's check if these side lengths can form a valid triangle using the Triangle Inequality Theorem, which states that the sum of the lengths of any two sides must be greater than the length of the remaining side. In this case, 2 + 10 > 11, 2 + 11 > 10, and 10 + 11 > 2, so a triangle can be formed.

Now let's identify the type of triangle. There are three main categories to consider: equilateral, isosceles, and scalene. An equilateral triangle has all three sides equal in length, which doesn't apply here. An isosceles triangle has two sides with equal lengths, but in this case, all three sides have distinct lengths. Therefore, the triangle is a scalene triangle, meaning it has no sides of equal length.

In summary, the triangle formed by side lengths 2, 10, and 11 is a scalene triangle because all three sides have different lengths and satisfy the Triangle Inequality Theorem.

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The lateral area of the rectangular prism with base square with the side 2 cm and height 125 mm is 10,000 mm².

To calculate the lateral area of a rectangular prism, we need to add up the areas of all its lateral faces.

In this case, the base of the prism is a square with side length 2 cm. Since there are four lateral faces on a rectangular prism, and each lateral face of the rectangular prism is a rectangle, we know that the length and width of each lateral face is equal to the height of the prism, which is 125 mm.

First, let's convert the side length of the base to millimeters to match the unit of the height:

2 cm = 20 mm

Now, we can calculate the lateral area of the rectangular prism as follows:

Lateral area = 4 x (length x height)

= 4 x (20 mm x 125 mm)

= 10,000 mm²

Therefore, the lateral area of the rectangular prism with base square with the side 2 cm and height 125 mm is 10,000 mm².

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Answer:

x = (-2 + 3) * (4-(-8))

Step-by-step explanation:

The arc measure of major arc BDC in degrees is 240 degrees.

To find the arc measure of major arc BDC in degrees, you'll need to provide more information about the given circle or angles within it. However, I can guide you on how to find the arc measure once you have the necessary information.

1. Determine the measure of the central angle corresponding to the major arc BDC. This can be done by subtracting the measure of the minor arc from 360 degrees.

2. Use the central angle measure to find the arc measure of major arc BDC. Since the arc measure is equal to the measure of the central angle in degrees, the arc measure of major arc BDC will be the same as the central angle measure you found in step 1.

Please provide more information or details about the given circle or angles to help you find the arc measure of major arc BDC.

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The total number of bags farmers need to buy to fertilize the lawn twice a year is 3.

The label on the fertilizer bag is 4lb bag can fertilize 5000 Sq. Ft.

4lb = 5000

1lb = 5000/4

1lb = 1250

1lb bag can fertilize 1250 Sq. Ft.

To fertilize 7400 sq. Ft. lawn twice a year

Total = 7400 + 7400

Total = 14800

No. of 1lb bag can need to fertilize 14800 sq. Ft. lawn = 14800/1250

No. of 1lb bag can need to fertilize 14800 sq. Ft. lawn = 11.84

As each bag is 4lb

No. of bags needed = 11.84/4

No. of bags needed = 2.96 ≈ 3

Total no. of bag needed is 3

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The drink mix that is needed to make one cup of drink is 21/20

Ali uses 21/2 scoops of drink mix to make 10 cups off drinks

The amount of drink mix needed to make one cup can be calculated as follows

21/2= 10

x= 1

cross multiply both sides

10x= 21/2

Divide by the coefficient of x which is 10

x= 21/2 ÷ 10

x= 21/2 × 1/10

x= 21/20

Hence the drink mix needed to make one cup is 21/20

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The value of the side lengths b and h in the right-angle triangle is [tex]3\sqrt{2} , and[/tex] 8.

Trigonometric ratios are the ratios of a right triangle's sides. The sine (sin), cosine (cos), and tangent are three often used trigonometric ratios. (tan).

The given figure is a right-angle triangle.

To find the value of b and h we need to apply the trigonometric ratio.

In the first triangle,

[tex]cos45 = \frac{adjacent}{hypotenuse}[/tex]

[tex]cos45 = \frac{b}{6}[/tex]

[tex]\frac{1}{\sqrt{2} } = \frac{b}{6}[/tex]

[tex]b = \frac{1}{\sqrt{2} } * 6[/tex]

[tex]b = 3\sqrt{2}[/tex]

In the second triangle

[tex]cos60 = \frac{adjacent}{hypotenuse} \\cos60 = \frac{4}{h} \\\frac{1}{2} = \frac{4}{h} \\h= 2 *4\\h = 8[/tex]

Therefore the value of the b and h is [tex]3\sqrt{2}[/tex] , and 8 respectively.

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The derivative of the function y = 2(2^x)-2 is 12 * 2^x ln(2) or 12ln(2)x(2^x-1).

To find the derivative of the function y = 2(2^x)-2, we will use the power rule and the chain rule of differentiation.

Apply the power rule to the function y = 2(2^x)-2. The power rule states that if f(x) = x^n, then f'(x) = nx^(n-1).

y' = [2(2^x)-2]'

= 2[(2^x)-2]'

= 2ln(2^x)'

Apply the chain rule to (2^x)'. The chain rule states that if f(x) = g(h(x)), then f'(x) = g'(h(x))h'(x). In this case, g(x) = 2^x, so g'(x) = ln(2)*2^x.

y' = 2ln(2^x)'

= 2ln(2^x)

= 2ln(2)x(2^x-1)

Therefore, the derivative of the function y = 2(2^x)-2 is 12 * 2^x ln(2) or 12ln(2)x(2^x-1).

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To satisfy the conditions that the mode is larger than the median, and the median is larger than the mean, one possible set of frequencies is 1 person chooses 1, 3 people choose 2, 4 people choose 3, 1 person chooses 4 and 11 people choose 5 This results in a mode of 5, a median of 4, and a mean of approximately 3.75.

Since we are given that the mode is larger than the median, that means that at least 11 people must choose the same number. Let's assume that 11 people choose the number 5.

Now, since the median is larger than the mean, we want to make sure that the remaining 9 people choose numbers that are smaller than 5. If they all choose 1, 2, or 3, then the median will be 3, which is larger than the mean. Therefore, we need to make sure that at least one person chooses 4.

So one possible set of frequencies could be

1 person chooses 1

3 people choose 2

4 people choose 3

1 person chooses 4

11 people choose 5

This set of frequencies gives us a mode of 5 (since 11 people choose 5), a median of 4 (since the middle value is 4), and a mean of

(11 + 32 + 43 + 14 + 11*5) / 20 = 3.7

Since the median is larger than the mean, this set of frequencies satisfies all the given conditions.

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The absolute maximum value of the function on the interval (-5, 11) is 670, which occurs at x = -5, and the absolute minimum value is approximately 400.847, which occurs at x ≈ 1.154.

To find the absolute maximum and minimum values of the function f(x) = -2x^3 + 8x + 400 on the interval (-5, 11), we need to consider the critical points and the endpoints of the interval.

First, we find the derivative of the function:

f'(x) = -6x^2 + 8

Setting f'(x) = 0 to find the critical points, we get:

-6x^2 + 8 = 0

x^2 = 4/3

x = ±√(4/3)

Since only √(4/3) is within the interval (-5, 11), this is the only critical point we need to consider.

Next, we evaluate the function at the endpoints of the interval:

f(-5) = -2(-5)^3 + 8(-5) + 400 = 670

f(11) = -2(11)^3 + 8(11) + 400 = -1666

Finally, we evaluate the function at the critical point:

f(√(4/3)) = -2(√(4/3))^3 + 8(√(4/3)) + 400 ≈ 400.847

Therefore, the absolute maximum value of the function on the interval (-5, 11) is 670, which occurs at x = -5, and the absolute minimum value is approximately 400.847, which occurs at x ≈ 1.154.

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If the mean time for problem 1 is 10 minutes, and the mean time for problem 2 is 15 minutes, The dot plots show the amount of time it takes each person in a random sample to complete two similar problems.

To find the mean time for each problem, we need to add up all the times and divide by the total number of people in the sample. Let's assume that the first dot plot represents problem 1 and the second dot plot represents problem 2.

After calculating the mean times for each problem, we can make a comparative inference based on the mean values. For instance, if the mean time for problem 1 is 10 minutes, and the mean time for problem 2 is 15 minutes, we can infer that problem 2 takes longer to complete on average than problem 1.

Comparative inference refers to the process of comparing two or more sets of data to draw conclusions about their similarities or differences. In this case, we are comparing the mean times for two similar problems to see which one takes longer on average.

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Answer: 7x=30.5

Step-by-step explanation: If you were to answer this equation with the given information it would not be correct. 7(4.25)=29.75.  You need to go through BEDMAS to answer this.

You what you need to do is divide 30.5 by 7 to get the amount she needs to jog for a week, if you do that you get 4.37 miles each day to get to 30.5 in a week.

To express u = (7, -10) as a linear combination u = rv + sw, where v = (2, 1) and w = (1,4), we need to find the values of r and s such that:

u = rv + sw

Substituting the given values, we get:

(7, -10) = r(2, 1) + s(1,4)

Using the symbolic notation, we can write this as a system of equations:

7 = 2r + s
-10 = r + 4s

We can solve this system of equations by using the elimination method:

Multiply the second equation by 2:

7 = 2r + s
-20 = 2r + 8s

Subtracting the first equation from the second, we get:

-27 = 7s

Dividing both sides by 7, we get:

s = -27/7

Substituting this value of s into the first equation, we get:

7 = 2r - 27/7

Multiplying both sides by 7, we get:

49 = 14r - 27

Adding 27 to both sides, we get:

76 = 14r

Dividing both sides by 14, we get:

r = 38/7

Therefore, u = (7, -10) can be expressed as the linear combination:

u = (38/7)(2,1) + (-27/7)(1,4)

Using fractions where needed, the answer is:

u = (76/7, 38/7) + (-27/7, -108/7)
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x^(1/2) = 0

This equation has no real solutions, since no real number raised to any power can equal 0.

Therefore, the sum of all values of x satisfying r*(x) = 0 or P(x) is undefined is just 2, the only value of x for which r*(x) - 0.

To find the values of x for which r*(x) - 0 or P(x) is undefined, we first need to determine what r*(x) and P(x) are.

r*(x) is the derivative of f(x), which we can find using the product rule:

r*(x) = (1/2)x^(-1/2)(x-4) + x^1/2(1)

Simplifying this expression, we get:

r*(x) = (x-2)/sqrt(x)

To find the values of x for which r*(x) - 0, we can set r*(x) equal to 0 and solve for x:

(x-2)/sqrt(x) = 0

x - 2 = 0

x = 2

So the only value of x for which r*(x) - 0 is x = 2.

Next, we need to find the values of x for which P(x) is undefined. P(x) is undefined when the denominator of the expression for f(x) is equal to 0, since division by 0 is undefined. The denominator of f(x) is x^(1/2), so we need to solve the equation x^(1/2) = 0:

x^(1/2) = 0

This equation has no real solutions, since no real number raised to any power can equal 0.

Therefore, the sum of all values of x satisfying r*(x) = 0 or P(x) is undefined is just 2, the only value of x for which r*(x) - 0.

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The new measurement based on the given scale factor of 4 is 36. The scale factor is the ratio of the new size of an object to its original size. In this case, the scale factor is 4, which means the new size is 4 times larger than the original size.

If the original measurement is 9, then the new measurement can be calculated by multiplying the original measurement by the scale factor.
New measurement = Original measurement x Scale factor
New measurement = 9 x 4
New measurement = 36
Therefore, the new measurement based on the given scale factor of 4 is 36.

To explain it further, imagine you have a drawing that is 9 inches wide. If you were to increase the scale factor to 4, the new drawing would be 4 times larger, which means it would be 36 inches wide. This concept is commonly used in architecture, engineering, and other fields where scaling drawings or models is necessary to represent them accurately. Understanding scale factors is important in order to make accurate and proportional changes to objects and designs.

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The volume of small cone-shaped cups is 11.8 in³.

To find the volume of the small shake in a cone-shaped cup that is 7 inches tall and has a diameter of 3 inches, we can use the formula for the volume of a cone:

V = 1/3 πr²h

where V = volume

r = radius

h = height of the cone

Given, diameter of come is 3 inches

We know r = d/2

r = 3/2

= 1.5

Substituting the value in the formula

V = 1/3 × 3.14 × 7 × (1.5)²

= 11.78

Rounding to nearest tenth

V = 11.8

Hence, the volume of small cone-shaped cups is 11.8 in³.

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To find the average rate of change of a function in a given interval, we need to calculate the difference in the function values at the endpoints of the interval and divide it by the length of the interval.

In this case, the interval is (0,2) and the function is f(x) = x^2 - 3x.

At the left endpoint, x=0, we have f(0) = 0^2 - 3(0) = 0.

At the right endpoint, x=2, we have f(2) = 2^2 - 3(2) = -2.

Therefore, the difference in the function values is f(2) - f(0) = -2 - 0 = -2.

The length of the interval is 2 - 0 = 2.

So the average rate of change of f(x) over the interval (0,2) is:

(-2)/2 = -1

Therefore, the average rate of change of f(x) over the interval (0,2) is -1.
Hi! To find the average rate of change in the interval (0, 2) for the function f(x) = x^2 - 3x, you can use the following formula:

Average Rate of Change = (f(b) - f(a)) / (b - a)

In this case, a = 0 and b = 2. First, calculate the function values at these points:

f(0) = (0)^2 - 3(0) = 0
f(2) = (2)^2 - 3(2) = 4 - 6 = -2

Now, apply the formula:

Average Rate of Change = (f(2) - f(0)) / (2 - 0) = (-2 - 0) / (2) = -2 / 2 = -1

So, the average rate of change in the interval (0, 2) for the function f(x) = x^2 - 3x is -1.

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The crate can hold 175 bricks.

First, we need to convert the volume of the crate from cubic meters to cubic centimeters because the volume of each brick is given in cubic centimeters.

1 m = 100 cm

Volume of crate = 2.8 m3 = 2.8 x (100 cm)3 = 2,800,000 cm3

Now we can find the number of bricks that can be packed into the crate by dividing the volume of the crate by the volume of each brick:

Number of bricks = Volume of crate / Volume of each brick

= 2,800,000 cm3 / 16,000 cm3

= 175 bricks

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The function given is y = 18000(0.76)^t, where y represents the value of the car and t represents the time in years.

This is an exponential decay function, meaning that the value of the car decreases over time. To determine if the value of the function will ever be 0, we would need to find if there exists a time t when y = 0. Let's analyze the function:

0 = 18000(0.76)^t

In an exponential decay function, the base (0.76 in this case) is between 0 and 1, so as time (t) increases, (0.76)^t will approach 0, but it will never actually reach 0. Thus, the value of the car will keep decreasing over time but will never be exactly 0.

In summary, the value of the function, which represents the car's value, will never be 0, but it will get infinitely close to 0 as time progresses. This is a characteristic of exponential decay functions, where the value never reaches 0 but approaches it as time goes on.

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The value of the scale factor for the similar figures is 1/3

From the question, we have the following parameters that can be used in our computation:

The similar figures

The corresponsing sides of the similar figures are

Original = 12

New = 4

Using the above as a guide, we have the following:

Scale factor = New /Original

substitute the known values in the above equation, so, we have the following representation

Scale factor = 4/12

Evaluate

Scale factor = 1/3

Hence, the scale factor for the similar figures is 1/3

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The value of the coordinates of point D is, (3, - 1)

We have to given that;

All the coordinates of rectangles are,

A(-2,1), B(-6, -9), C(-1, -11)

Now, Let the fourth coordinate of rectangle is,

D (x, y)

Hence, Midpoint of AC and BD are same.

So., Midpoint of AC is,

⇒ AC = (- 2 + (- 1))/ 2, (1 + (- 11))/2

          = (- 3/2 , - 5)

And, Midpoint of BD,

⇒ BD = (- 6 + x)/2, (- 9 + y)/2

By comparing;

⇒ (- 6 + x)/2 = - 3/2

⇒ - 6 + x = - 3

⇒ x = - 3 + 6

⇒ x = 3

⇒ (- 9 + y)/2 = - 5

⇒ - 9 + y = - 10

⇒ y = -10 + 9

⇒ y = - 1

Thus, The value of the coordinates of point D is, (3, - 1)

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Therefore , the solution of the given problem of unitary method comes out to be (Sum of Daily Balances) / Average Daily Balance (Number of Days in Period).

The well-known minimalist approach, current variables, and any crucial elements from the initial Diocesan tailored query can all be used to accomplish the work. In response, you can be granted another chance to utilise the item. If not, important impacts on our understanding of algorithms will vanish.

Here,

You must be aware of an account's daily balance over a specific time period in order to determine the average daily amount. how to get an average daily balance:

The time frame for which you wish to compute the average daily balance should be chosen. This could, for instance, be a month, a quarter, or a year.

Find the account balance at the end of each day during the specified period.

Sum up each day's balance for the duration.

By the number of days in the time frame, divide the sum. You are then given the daily average balance.

The formula for determining the typical daily balance is as follows:

=> (Sum of Daily Balances) / Average Daily Balance (Number of Days in Period)

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When we look at [tex]f(t)=1/7 t^3-4t-12[/tex], this is a cubic equation, and solving it analytically is not straightforward.

To find the value of r such that f(r) = 0, we need to solve the equation:

[tex]1/7 r^3 - 4r - 12 = 0[/tex]

This is a cubic equation, and solving it analytically is not straightforward.

Yet, it is possible to obtain the value of r that meets the equation using numerical schemes such as Newton-Raphson or bisection. Additionally, one can take advantage of calculation tools and graphical software to calculate an estimation of r.

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Step-by-step explanation:

there is no explanation about x so wierd

Points lie on the graph of the inverse of f(x)=5x−2.

Hence, the correct option is C,E,F.

To find the points on the graph of the inverse of f(x), we need to switch the x and y coordinates of each point on the graph of f(x). Then, we can simplify the equation to isolate y and get the inverse function.

f(x) = 5x - 2

y = 5x - 2 (replace f(x) with y)

x = 5y - 2 (switch x and y)

x + 2 = 5y (add 2 to both sides)

y = (x + 2)/5 (divide both sides by 5)

So, the inverse function of f(x) is

[tex]f^{-1}[/tex](x) = (x + 2)/5

Now, we can substitute each point from the given options into the inverse function to see if it lies on the graph of the inverse of f(x).

1. (0, -2)

[tex]f^{-1}[/tex](0) = (0 + 2)/5 = 2/5

No, this point does not lie on the graph of the inverse of f(x).

2. (1, 3)

[tex]f^{-1}[/tex](1) = (1 + 2)/5 = 3/5

No, this point does not lie on the graph of the inverse of f(x).

3. (-2, 0)

[tex]f^{-1}[/tex](-2) = (-2 + 2)/5 = 0

Yes, this point lies on the graph of the inverse of f(x).

4. (2/5, 1)

[tex]f^{-1}[/tex](2/5) = (2/5 + 2)/5 = 6/25

No, this point does not lie on the graph of the inverse of f(x).

5. (0, 2/5)

[tex]f^{-1}[/tex](0) = (0 + 2)/5 = 2/5

Yes, this point lies on the graph of the inverse of f(x).

6. (3, 1)

[tex]f^{-1}[/tex](3) = (3 + 2)/5 = 1

Yes, this point lies on the graph of the inverse of f(x).

Therefore, the points that lie on the graph of the inverse of f(x) are (-2, 0),  (0, 2/5) and (3, 1),

Hence, the correct option is C,E,F.

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Answer:

? equals 80

Step-by-step explanation:

6.7 times 10 to the power of 8 in scientific notation is [tex]6.7\times 10^8.[/tex]

We must adhere to the norms of the acronym PEMDAS, which stands for Parentheses, Exponents, Multiplication and Division and Addition and Subtraction, in that sequence to conduct the order of operations with scientific notation for 6.7 × 108.

Write the number 6.7.

Multiply it by 10 raised to the power of 8. This means you move the decimal point 8 places to the right.

[tex]6.7\times 10^8[/tex]

The final answer is 670,000,000 in standard form or [tex]6.7\times 10^8[/tex] in scientific notation.

Therefore, 6.7 times 10 to the power of 8 in scientific notation is [tex]6.7\times 10^8.[/tex]

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Answer:

The answer to your problem is, F = 15N

Step-by-step explanation:

You have: F = ka

Where F is the force acting on the object, A is the object's acceleration and is the constant of proportionality.

Which will be our letters that we will NEED to use for today.

You can calculate the constant of proportionality by substituting F = 18 and a = 6 into the equation and solving for k: Then we can now figure out the “ formula of expression “

18 = k6

k = [tex]\frac{18}{6}[/tex]

K = 3

We would need to calculate the force when the acceleration of the object becomes 5 m/s², as following: F = 3 x 5 ( Basic math )

= F = 15

Thus the answer to your problem is, F = 15N

The probability of choosing exactly 13 students who dressed up as the 40s out of the 16 selected students is approx. 0.4334.

We can model this situation as a hypergeometric distribution, where we have a population of 19 students, 15 of whom dressed up as the 40s.

We want to choose a sample of 16 students and find the probability that exactly 13 of them dressed up as the '40s.

The probability of choosing exactly 13 students who dressed up as the 40s can be calculated:

(number of ways to choose 13 students who dressed up as the 40s) * (number of ways to choose 3 students who dressed up as other decades) / (total number of ways to choose 16 students)

The number of ways to choose 13 students who dressed up as the '40s is the number of combinations of 15 choose 13:

(15 choose 13) = 105

The number of ways to choose 3 students who dressed up as other decades is the number of combinations of 4 choose 3, which is:

(4 choose 3) = 4

The total number of ways to choose 16 students from 19 is the number of combinations of 19 choose 16, which is:

(19 choose 16) = 969

105 * 4 / 969 = 0.4334

Therefore, the probability of choosing exactly 13 students who dressed up as the 40s = 0.4334 (rounded to four decimal places)

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