What are the equilibrium concentration of each species for the complex ion 0. 500M Co(NH3)6+3? Kd=2. 2 x 10-34

The abaxial (lower) surface of the sepal is typically more damaged than the adaxial (upper) surface, as it is more exposed to pollutants in the air.

Air pollution can damage the sepal of a flower in various ways. Pollutants in the air can reduce the size and number of stomata, which are small pores that allow for gas exchange in the leaf tissue.

The concentration of minerals in the tissue can also be altered by pollution, which can affect plant growth and development. Additionally, air pollution can cause the cuticle, a waxy layer that covers the leaf surface, to become thicker. This can further restrict gas exchange and reduce photosynthesis.

Studies have shown that the abaxial surface of the sepal is typically more damaged by pollution than the adaxial surface. This is likely due to the fact that the abaxial surface is more exposed to pollutants in the air.

The stomata on the abaxial surface may close or become blocked due to the accumulation of pollutants, which can lead to reduced gas exchange and decreased photosynthesis. The thickening of the cuticle on the abaxial surface can further restrict gas exchange and exacerbate the effects of pollution.

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Because the fourth electron of each carbon atom is unbound, graphite conducts electricity. As a result of the existence of free electrons in the structure, we may deduce that graphite is an excellent conductor of electricity.

The volume of oxygen gas produced at STP when 3.81 g of Mg(ClO₃)₂ decomposes is 0.511 L.

When magnesium chlorate (Mg(ClO₃)₂) is decomposed, oxygen gas and magnesium chloride are produced. To find the volume of oxygen gas at STP when 3.81 g of Mg(ClO₃)₂ decomposes, follow these steps:

1. Write the balanced chemical equation for the decomposition of magnesium chlorate:
  Mg(ClO₃)₂ (s) → 2ClO₂ (g) + MgCl₂ (s)

2. Calculate the molar mass of Mg(ClO₃)₂:
  Mg: 24.31 g/mol
  Cl: 35.45 g/mol (2 Cl atoms)
  O: 16.00 g/mol (6 O atoms)
  Total: 24.31 + (2 x 35.45) + (6 x 16.00) = 167.21 g/mol

3. Determine the moles of Mg(ClO₃)₂:
  Moles = (mass of Mg(ClO₃)₂) / (molar mass of Mg(ClO₃)₂)
  Moles = 3.81 g / 167.21 g/mol ≈ 0.0228 mol

4. Use the balanced equation to find the moles of oxygen gas produced:
  From the equation, 1 mol of Mg(ClO₃)₂ produces 1 mol of O₂. Therefore, 0.0228 mol of Mg(ClO₃)₂ will produce 0.0228 mol of O₂.

5. Use the molar volume of a gas at STP (22.4 L/mol) to find the volume of O₂ produced:
  Volume of O₂ = (moles of O₂) x (molar volume at STP)
  Volume of O₂ = 0.0228 mol x 22.4 L/mol ≈ 0.511 L

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The mass of the ionic compound dissolved in 100 g of water is 7.44 grams.

To solve this problem, we need to use the formula:

m = n x M x MW

where m is the mass of the compound in grams, n is the number of moles of the compound, M is the molarity of the solution, and MW is the molar mass of the compound.

First, we need to calculate the number of moles of the compound dissolved in 100 g of water:

density of solution = mass of solution / volume of solution

volume of solution = mass of solution / density of solution = 100 g / 1.094 g/mL = 91.29 mL = 0.09129 L

moles of compound = M x volume of solution = 0.531 mol/L x 0.09129 L = 0.0485 mol

Now, we can calculate the mass of the compound:

m = n x M x MW = 0.0485 mol x 153.5 g/mol = 7.44 g

Therefore, the mass of the ionic compound dissolved in 100 g of water is 7.44 grams.

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The type of waves that come naturally from the decay of radioactive isotopes and are used in medicine for diagnostic imaging are gamma rays.

Gamma rays are a type of electromagnetic radiation with the highest energy and shortest wavelength in the electromagnetic spectrum. They are produced naturally by the decay of radioactive isotopes, such as uranium and radon, and are also emitted during nuclear reactions and explosions.

In medicine, gamma rays are used in a diagnostic imaging technique called gamma-ray spectroscopy, which detects and measures gamma rays emitted by radioactive isotopes in the body. This technique can be used to diagnose various conditions, such as cancer and heart disease, by identifying areas of the body with abnormal radioactive activity.

Gamma rays are also used in radiation therapy to treat cancer. In this treatment, high-energy gamma rays are directed at cancerous cells to damage and kill them. However, the high energy of gamma rays can also damage healthy cells, so careful targeting and dose management is necessary to minimize side effects.

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Answer:

C

Explanation:

First of all, the law of conservation of matter states that " In an ordinary chemical reaction, the mass of the products is equal to the mass of the reactants."

So, the answer should be C since the mass of Al and O₂ is equal on both the reactant's and product's side.

4Al + 3O₂ → 2Al₂O₃

Reactants Side: 4 aluminum and 6(3*2) oxygen

Products Side: 4(2*2) aluminum and 6(2*3) oxygen

The precipitate that forms when the solution of the compound produced from the oxidation of elemental silicon in the presence of O₂ and dissolving in molten Na₂CO₃ is treated with aqueous hydrochloric acid is likely to be silicon dioxide. The oxidation of elemental silicon results in the formation of silicon dioxide, which is soluble in molten Na₂CO₃, but when the solution is treated with aqueous hydrochloric acid, silicon dioxide will precipitate out. This reaction can be explained by the fact that hydrochloric acid reacts with the Na₂CO₃ to form H₂O, CO₂, and NaCl, which allows the silicon dioxide to no longer remain in the solution, leading to its precipitation.

Here is the step-by-step solution:

1. Elemental silicon (Si) reacts with O₂ to form silicon dioxide (SiO₂): Si + O₂ → SiO₂.

2. SiO₂ dissolves in molten Na₂CO₃, forming sodium silicate (Na₂SiO₃) and carbon dioxide (CO₂): SiO₂ + Na₂CO₃ → Na₂SiO₃ + CO2.

3. When the sodium silicate solution is treated with aqueous hydrochloric acid (HCl), silicon dioxide (SiO₂) precipitates out, and sodium chloride (NaCl) and water (H₂O) are formed: Na₂SiO₃ + 2HCl → SiO₂ (precipitate) + 2NaCl + H₂O.

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A single compound decomposes into two or more smaller compounds or components during a decomposition reaction. Option D

A number of mechanisms, such as heat, light, or the addition of another molecule, can cause this. A significant quantity of potential energy is often held in the chemical bonds of the reactant component, and this energy is released during the reaction.

For instance, hydrogen peroxide's typical breakdown reaction involves the molecule dissolving into water and oxygen gas:

[tex]2H_2O_2 \rightarrow 2 H_2O + O_2[/tex]

The heat breakdown of calcium carbonate to produce calcium oxide and carbon dioxide gas is another illustration:

[tex]CaO + CO_2 = CaCO_3[/tex]

Decomposition reactions are crucial components of several chemical processes in both nature and industry. They are characterised by the dissolution of bigger molecules into smaller ones. Option D

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We need 157 grams of K₂SO4 to prepare 2.25 L of a 0.400 M solution.

To calculate the grams of K₂SO4 needed to prepare a 0.400 M solution in 2.25 L, we need to use the formula:

moles = Molarity x Volume

First, we can calculate the moles of K₂SO4 required:

moles = 0.400 mol/L x 2.25 L = 0.90 moles

Next, we can use the molar mass of K₂SO4 to convert the moles to grams:

molar mass of K₂SO4 = 2 x (39.10 g/mol for K) + 1 x (32.06 g/mol for S) + 4 x (16.00 g/mol for O) = 174.24 g/mol

grams = moles x molar mass = 0.90 moles x 174.24 g/mol = 157 g

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The mass of copper sulfate in 30.0 cm3 of this solution is 0.957 g.

The concentration of the copper sulfate solution is given by:

c = n ÷ V

c = 0.100 mol/0.500 dm³

c = 0.200 mol/dm³

To calculate the mass of copper sulfate in 30.0 cm³ of this solution, we first need to calculate the number of moles of copper sulfate in this volume:

n = c x V

n = 0.200 mol/dm³ x (30.0 cm³ ÷ 1000 cm³/dm³)

n = 0.006 mol

The mass of copper sulfate can be calculated using its molar mass:

m = n x Mr

m = 0.006 mol x 159.5 g/mol

m = 0.957 g

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3.75 moles CO₂ × 22.4 L/mole = 84 liters of CO₂ are produced when 32.6 liters of propane gas reacts with excess oxygen at STP.

Based on the balanced equation provided, 1 mole of propane gas (C₃H₈) reacts with 5 moles of oxygen gas (O₂) to produce 3 moles of carbon dioxide gas (CO₂) at STP (Standard Temperature and Pressure, which is 0°C and 1 atm pressure).

To determine the number of moles of propane gas (C₃H₈) in 32.6 liters, we need to use the Ideal Gas Law:

PV = nRT

where P is the pressure (1 atm), V is the volume (32.6 L), n is the number of moles, R is the ideal gas constant (0.0821 L•atm/mol•K), and T is the temperature in Kelvin (273 K at STP).

Rearranging the equation to solve for n, we get:
n = PV/RT = (1 atm)(32.6 L)/(0.0821 L•atm/mol•K)(273 K) = 1.25 moles of C₃H₈

Since 1 mole of C₃H₈ produces 3 moles of CO₂, we can use a mole ratio to determine the number of moles of CO₂ produced:
1.25 moles C₃H₈ × 3 moles CO₂/1 mole C₃H₈ = 3.75 moles CO₂

Finally, we can convert moles to volume at STP using the molar volume of a gas:
1 mole of gas = 22.4 L at STP

So, 3.75 moles CO₂ × 22.4 L/mole = 84 liters of CO₂ are produced when 32.6 liters of propane gas reacts with excess oxygen at STP.

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The pH of the 0.227 M C₅H₅N solution at 25°C is 9.3.

The equilibrium expression for the reaction of C₅H₅N with water:

C₅H₅N + H₂O ⇌ C₅H₅NH⁺ + OH.

The Kb for C₅H₅N is given as 1.7 × 10⁻⁹, so we can use this value to calculate the concentration of OH⁻ in the solution. First, we need to calculate the concentration of C₅H₅N that has dissociated:

Kb = [C₅H₅NH⁺][OH⁻]/[C₅H₅N]

1.7 × 10⁻⁹ = [C₅H₅NH⁺][OH⁻]/0.227

Solving for [OH⁻], we get:

[OH⁻] = √(Kb[C₅H₅N]/[C₅H₅NH⁺])

= √[(1.7 × 10⁻⁹)(0.227)/x]

= 2.0 × 10⁻⁵ M

The concentration of H⁺ ions in the solution. Since the solution is not neutral (it is basic), we know that [OH⁻] > [H⁺], so we can use the equation:

Kw = [H⁺][OH⁻]

1.0 × 10⁻¹⁴ = [H⁺](2.0 × 10⁻⁵)

Solving for [H⁺], we get:

[H⁺] = 5.0 × 10⁻¹⁰ M

Finally, we can use the equation:

pH = -㏒[H⁺]

to calculate the pH of the solution:

pH = -㏒(5.0 × 10⁻¹⁰)

= 9.3

At 25°C, the pH of the 0.227 M C₅H₅N solution is 9.3.

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The volume of gas at 140.0 °C is calculated as 1033 ml.

Space occupied by gaseous particles at the standard temperature and pressure conditions is called the volume of gas

T1 = 32.0 °C + 273.15 = 305.15 K

T2 = 140.0 °C + 273.15 = 413.15 K

Next, we can set up the proportion: V1/T1 = V2/T2

V1 is initial volume, V2 is final volume, T1 is initial temperature, and T2 is final temperature.

762.0 mL/305.15 K = V2/413.15 K

V2 = 762.0 mL × (413.15 K/305.15 K) = 1033 mL

Therefore, the volume of the gas at 140.0 °C is 1033 ml.

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0.21 dm³ of 0.1 mol/dm³ hydrochloric acid is required to neutralize 20 cm³ of 2.0 mol/dm³ sodium hydroxide.

The volume of 0.1 mol/dm³ hydrochloric acid required to neutralize 20 cm³ of 2.0 mol/dm³ sodium hydroxide can be calculated using the formula:

Volume of acid = (Volume of alkali x Concentration of alkali x Molar mass of acid) / (Molar mass of alkali x Concentration of acid)

Firstly, we need to convert the volume of alkali from cm³ to dm³, which gives us 0.02 dm³. The molar mass of hydrochloric acid (HCl) is 36.5 g/mol, and the molar mass of sodium hydroxide (NaOH) is 40 g/mol.

Substituting these values and the given concentrations into the formula, we get:

Volume of acid = (0.02 x 2.0 x 40) / (36.5 x 0.1) = 0.21 dm³

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The expected effects on the people if the alpine and the tidewater glaciers melted is the melting the glaciers add to the rising sea levels.

The melting glaciers add to the rising sea levels, which in the turn will increases the coastal erosion and the elevates storm to surge the warming air and the ocean temperatures that will create the more frequent and the intense coastal storms such as the hurricanes and the typhoons.

The glaciers has been the melting for the decades because of the climate warming and therefore the monitoring of it is very important. The melting of the alpine and the tidewater glacier rises the sea level.

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The volume of the balloon after the dry ice sublimes will be 3.40 L at STP.

The balanced chemical equation for the sublimation of solid CO₂ is:

CO₂(s) → CO₂(g)

At STP (standard temperature and pressure), which is 0°C (273.15 K) and 1 atm (101.325 kPa), one mole of any ideal gas occupies 22.4 L of volume. We can use this information to calculate the volume of CO₂ gas produced by the sublimation of 7.00 g of dry ice.

First, we need to convert the mass of dry ice to moles of CO₂ using the molar mass of CO₂, which is 44.01 g/mol:

7.00 g CO₂ × (1 mol CO₂/44.01 g CO₂) = 0.159 moles CO₂

Next, we can use the ideal gas law to calculate the volume of CO₂ gas produced:

PV = nRT

where P is the pressure (1 atm), V is the volume we want to find, n is the number of moles of CO₂ (0.159 moles), R is the gas constant (0.08206 L·atm/mol·K), and T is the temperature (273.15 K):

V = nRT/P = (0.159 mol)(0.08206 L·atm/mol·K)(273.15 K)/(1 atm) = 3.40 L

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A pH of 13 indicates a highly basic solution. To calculate the H3O+ concentration in household bleach, we can use the following formula:

pH = -log[H3O+]

Rearranging the formula, we get:

[H3O+] = 10^(-pH)

Substituting pH = 13 into the formula, we get:

[H3O+] = 10^(-13)

[H3O+] = 1 x 10^(-13) mol/L

Therefore, the H3O+ concentration in household bleach is approximately 1 x 10^(-13) mol/L.

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When working with a heat source, one should always assume that glassware and metal objects are hot. Option A is correct.

Working with a heat source requires special precautions to ensure safety in the laboratory. Heat sources such as Bunsen burners, hot plates, and ovens can generate high temperatures that can cause burns or fires if not handled properly. One important safety rule when working with a heat source is to assume that glassware and metal objects are hot.

This means that one should avoid touching or handling these objects without protective equipment, even if they appear to be cool or inactive. This is because they may still be hot from exposure to the heat source and can cause burns or injuries. Other safety measures when working with a heat source include using appropriate personal protective equipment, such as heat-resistant gloves and safety goggles, and ensuring good ventilation in the laboratory to prevent exposure to fumes or volatile chemicals. Option A is correct.

What should you do when working with a heat source?

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Non-smokers can breathe 3.6 liters of air per minute at sea level (1 atm).

At high altitudes, pressure decreases to 0.5 atm. Non-smokers can breathe 7.2L of air per minute. How many liters of air can they breathe at sea level? (1 atm)

To answer this question, we will use the Boyle's Law, which states that the product of pressure (P) and volume (V) is constant for a given amount of gas at a constant temperature. In this case, we have two different pressure conditions: high altitudes (0.5 atm) and sea level (1 atm).

We are given the volume of air breathed at high altitudes (7.2L) and asked to find the volume at sea level.

Step 1: Write down the given information:
P1 = 0.5 atm (pressure at high altitudes)
V1 = 7.2L (volume of air breathed at high altitudes)
P2 = 1 atm (pressure at sea level)
V2 = ? (volume of air breathed at sea level; this is what we need to find)

Step 2: Apply Boyle's Law:
P1 × V1 = P2 × V2

Step 3: Plug in the given values and solve for V2:
(0.5 atm) × (7.2L) = (1 atm) × V2

Step 4: Solve for V2:
V2 = (0.5 × 7.2) / 1
V2 = 3.6L

So, non-smokers can breathe 3.6 liters of air per minute at sea level (1 atm).

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The product of fermentation that is always produced regardless of the electron or hydrogen acceptor used is ethanol (C2H5OH) or lactic acid (C3H6O3) depending on the type of fermentation.

Fermentation is a metabolic process that occurs in the absence of oxygen and involves the breakdown of glucose or other organic compounds by microorganisms.

It is a type of anaerobic respiration, which does not require oxygen as the final electron acceptor. During fermentation, the organic compounds are partially oxidized, and the energy released is used to generate ATP, the energy currency of cells.

Different microorganisms can carry out fermentation using different electron or hydrogen acceptors, such as pyruvate, acetaldehyde, or acetyl-CoA.

However, regardless of the acceptor used, the end products are typically ethanol or lactic acid, along with carbon dioxide and small amounts of other byproducts.

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About 2.0 billion years ago, the atmosphere of the Earth was rich in carbon dioxide and lacked oxygen.  The correct answer is G.

However, over time, photosynthetic organisms like cyanobacteria began to evolve and release oxygen into the atmosphere.

This event, known as the Great Oxygenation Event, fundamentally altered the chemistry of the Earth's atmosphere and allowed for the development of complex organisms. The availability of oxygen facilitated the evolution of aerobic respiration, which allowed for more efficient energy production and the development of complex, multicellular organisms.

Therefore, the primary reason for the development of complex organisms about 2.0 billion years ago was the changes in atmospheric gases, specifically the increase in atmospheric oxygen.

The eruption of volcanoes and the impact of comets may have also played a role in the evolution of life on Earth, but the changes in atmospheric gases were the driving force behind the development of complex organisms.

The correct answer is G.

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One simple experiment that can be conducted to demonstrate that living materials contain water is heating of simple matter.

The following experimental procedure deminstrates the presence of water on living matter.

If the sample contains water, the final weight will be less than the initial weight, indicating that some of the water has been lost due to the heating process.

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In the field of chemistry, the term "conjugate" is used to describe pairs of molecules or ions that are connected through the transfer of a proton, which is represented as H⁺. Conjugate acids and bases, specifically, are pairs of molecules or ions that vary by the presence or absence of one proton.

These equilibrium equations represent the transfer of a proton between a weak acid or base and water, resulting in the formation of its conjugate acid or base.

Answer of the given questions are as follows :

1. The formula of the conjugate acid: HCO₂H

2. The formula of the conjugate base: C₆HNH₃⁺

3. The formula of the conjugate acid of the brønsted-lowry base: H₂CO₃

4. The formula of the conjugate acid of the brønsted-lowry base:

C₆H₅NH₃⁺

5. The acidic equilibrium equation for HC₂H₃O₂: HC₂H₃O₂ + H₂O ⇌ H₃O⁺ + C₂H₃O²⁻

6. The basic equilibrium equation for C₆H₅NH₂

C₆H₅NH₂ + H₂O ⇌ C₆H₅NH₃⁺ + OH⁻

7. The basic equilibrium equation for NH₃

NH₃ + H₂O ⇌ NH₄⁺ + OH⁻

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The commonly used rules of thumb used by chemists to make buffers are:

Buffers are solutions that resist changes in pH when small amounts of acid or base are added to them. They are commonly used in many chemical and biological applications. The rules of thumb mentioned above provide guidelines for making effective buffers. Rule a) ensures that there is an adequate amount of buffering capacity in the solution. Rule b) is based on the fact that weak acids have a pH-dependent dissociation constant, and therefore, the pH of a buffer made from a weak acid will be close to the pKa of the weak acid.

Similarly, the pH of a buffer made from a weak base will be close to the pKa of the conjugate acid. Rule c) ensures that the buffering capacity of the solution is optimized by selecting the appropriate pKa value. Overall, these rules of thumb help chemists to design effective buffers that can maintain a stable pH over a range of conditions.

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20.8 grams of C2H2 are required to react completely with 2.0 moles of O2.

The balanced chemical equation is: [tex]2C2H2 + 5O2 → 4CO2 + 2H2O[/tex]

The stoichiometry of the balanced equation shows that 2 moles of C2H2 react with 5 moles of O2 to produce 4 moles of CO2 and 2 moles of H2O.

Therefore, the mole ratio of C2H2 to O2 is 2:5.

If 2.0 moles of O2 are completely reacted, then the required moles of C2H2 can be calculated as follows:

2.0 mol O2 x (2 mol C2H2/5 mol O2) = 0.8 mol C2H2

Now, we can use the molar mass of C2H2 to calculate the mass required:

0.8 mol C2H2 x 26.04 g/mol = 20.8 g C2H2

Therefore, 20.8 grams of C2H2 are required to react completely with 2.0 moles of O2.

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The strongest type of intermolecular force present between the hydrocarbon chains of neighboring stearic acid molecules is the van der Waals dispersion force, also known as London dispersion force.

This force arises due to temporary dipoles that are created by the random motion of electrons in the molecule. These temporary dipoles induce similar dipoles in the neighboring molecules, leading to an attractive force between them.

In stearic acid, the hydrocarbon chain is nonpolar, which means that there are no permanent dipoles in the molecule. However, the electrons in the molecule are not always distributed symmetrically, leading to temporary dipoles that can induce similar dipoles in other stearic acid molecules.

The strength of the van der Waals force depends on the size of the molecule and the number of electrons in it. Stearic acid has a relatively long hydrocarbon chain, which means that it has a large surface area and a large number of electrons, making the van der Waals force between its molecules relatively strong.

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The pressure inside the car will be approximately 1.16 atm after the temperature increase.

In the solution to this question, we can assume that the temperature increase is isobaric (constant pressure), so we can use the ideal gas law to calculate the final pressure of the car:

PV=nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

We know that the amount of gas in the car will remain constant, so we can write:

[tex]P_1V = nRT_1[/tex]

and

[tex]P_2V = nRT_2[/tex]

where [tex]P_1[/tex] and [tex]T_1[/tex] are the initial pressure and the temperature, whereas [tex]P_2[/tex] and [tex]T_2[/tex] are the final pressure and temperature of the car.

We are given that [tex]P_1[/tex]=1 atm, [tex]T_1[/tex]=293 K, and [tex]T_2[/tex] = 338 K. We need to find the pressure [tex]P_2[/tex]:

We can say that [tex]P_2 = (P_1 T_2/ T_1)[/tex];

= (1 atm)(338 K/293 K)

= 1.16 atm

So, the pressure inside the car will be approximately 1.16 atm after the temperature increase.

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For question 3, we can use the relationship pH + pOH = 14 to solve for the pH, which is 1.96.

Then, we can use the equation Kw = [[H₃O⁺][OH⁻] = 1.0 x 10⁻¹⁴ to solve for the hydronium concentration, which is 5.01 x 10⁻¹³ M.

For question 4, we can use the equation for the acid dissociation constant (Ka) to solve for the concentration of the conjugate base, F-. Ka = [H₃O⁺][F⁻]/[HF].

We know the concentration of HF is 2.5 moles, so we can convert this to molarity using the volume of the solution. Then, we can plug in the values we have and solve for [F-], which is 2.77 M. This solution will be acidic, as the Ka value is less than 1.

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Answer: b

Explanation: because the light-scattering properties of our atmosphere spread sunlight across the sky. seeing the dim light of a distant star in the blanket of photons from our Sun becomes as difficult as spotting a single snowflake in a blizzard.