What do you mean by 100W power ?​

Answer:

a

Explanation:

if forces on an object are balanced a moving object continues to move at the same speed and in the same direction

Hi there!

Since the ball is thrown with an initial HORIZONTAL velocity, we can treat this as a free-fall situation since the horizontal motion does NOT impact the ball's vertical motion.

We can use the derived kinematic equation:

[tex]t = \sqrt{\frac{2h}{g}}[/tex]

Plug in the given values:

[tex]t = \sqrt{\frac{2(150)}{9.8}} = \large\boxed{5.53 s}}[/tex]

The angle of projection is 0° because there is no vertical component to the velocity as the initial velocity is purely horizontal.

Range:

We can use the equation:

dₓ = vₓt

displacement (x direction) = velocity (x direction) · time

Used the solved-for time and given velocity:

dₓ = 100 · 5.53 = 553 m

we know 1kg=9.8N​ so 30 kg= 30 x 9.8 = 294 N

work is done when a 30 kg mass is to be lifted through a height 6m :

A = 294 x 6 = 1764 J

ok done. Thank to me :>

Answer:

Most earthquakes and volcanoes occur because of the movement of the plates, especially as plates interact at their edges or boundaries.

Explanation:

The white disk has a larger radius.

We know that the speed of the coin v = rω where r = radius of the disk and ω = angular speed of the disk.

Now, since both disks rotate at constant speed, ω = constant.

So, v ∝ r

For the black disk, its radius is r, the coins speed is v.

For the white disk, let its radius be R, the coins rotates at a speed V = 4v

We know that v ∝ r.

Since the coin on the white disk has a greater speed, so its radius would be greater.

So, the white disk has a larger radius.

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Answer:

[tex]\boxed {\boxed {\sf A. \ 2 \ m/s}}[/tex]

Explanation:

Speed is the distance traveled per unit of time, or how fast an object is moving.

It is calculated by dividing the distance by the time.

[tex]s= \frac{d}{t}[/tex]

Jake traveled 10 meters in 5 seconds.

Substitute the values into the formula.

[tex]s= \frac{10 \ m}{5 \ s}[/tex]

Divide.

[tex]s= 2 \ m/s[/tex]

Jake's speed was 2 meters per second and choice A is correct.

Answer:

Oh wow, that's a long answer. I don't know what voltage is on the circuit.

Answer:

potential energy depends on position or shape

Hi there!

We know that:

∑F = ma

If you tripled the net force and halved the mass:

3F = 1/2ma

Rearrange for 'a':

3F × 2 = ma

6F = ma

Thus, the new acceleration would be 6 times the original, or 36 m/s².

Answer:

facilitated diffusion

Hi there!

We know that:

U (Potential energy) = mgh

We are given the potential energy, so we can rearrange to solve for h (height):

U/mg = h

g = 9.81 m/s²

m = 30 g ⇒ 0.03 kg

0.062/(0.03 · 9.81) = 0.211 m

The hazards of using electricity in this kitchen include the following below:

Risk of electric shocks: These electrical appliances use an electric source for their various functions in which electric current flows through them when

turned on. Exposure and contact of the naked wire with individuals will bring

about shock.

Risk of burns: The kitchen has various heating appliances such as toaster,

kettle,iron and oven which may result in burns if not carefully handled.

Risks of fire : The heat and electric current from these appliances can trigger a spark and fire which may raze down the building is also another hazard.

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The characteristics of the universal gravitation law allow finding the results for which statements are true:

    2. Real stars must be at least 2 to 3 times more massive than our sun to become a black hole.

The universal gravitational law states that the gravitational force is always attractive and is proportional to the masses and inversely proportional to the square of the distance.

       [tex]F = - G \frac{Mm}{r^2}[/tex]

Where F is the force, G is the universal gravitational constant, M and m are the masses and r the distance between the bodies.

Let's analyze the expressions:

1. The gravitational field around a planet is oriented radically outward

False. The force is attractive therefore it is directed towards the center of the planet.

2. Real stars must be at least 2 to 3 times more massive than our sun to become a black hole.

True. From observations of super-novae the minimum mass is 3 solar masses.

3. Astronauts in orbit are weightless due to the absence of a supporting force.

False. Astronauts have no weight because the force of gravity binds to change the direction of their velocity.

4. The outer planets of our solar system wobble in their orbits because the gravitational effects of the sun are very small.

False. The attraction of the sun decreases with the square of the distance, but the wobble is due to the attraction of the other large planets in this area.

5. The earth falls towards the sun.

False. The earth has a speed parallel to the orbit around the sun and the acceleration due to the attraction of the sun changes the direction of the orbital velocity, but the earth is not directed at the sun.

6, As you move away from the ground, the gravitational force acting on you increases.

False. The gravitational force is inversely proportional to the distance, therefore it decreases when leaving the earth.

In conclusion with the characteristics of the universal gravitation law we can find which statements are true:

     2. Real stars must be at least 2 to 3 times more massive than our sun to become a black hole.

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Answer:

1.5 g/cm

3

Let d be the density of fluid.

So , Initial reading of balance, F

1

=30dg N

After the level reaches 50cm

3

Final reading of balance , F

2

=50dg N

Given that difference between final and initial reading is 30g

i.e, F

2

−F

1

=30 g

⟹50dg−30dg=30g

⟹20dg=30g

⟹d=

20g

30g

⟹d=1.5g/cm

3

So, density of fluid is 1.5g/cm

3

Explanation:

The resulting displacement of the medium during complete overlap is -1 unit. This is still destructive interference since the two interfering pulses have opposite displacements.

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass in kg

v is the velocity of the object in m/s

From the question

m = 100 kg

v = 10 m/s

We have

[tex]k = \frac{1}{2} \times 100 \times {10}^{2} \\ = 50 \times 100 \\ = 5000 \: \: \: \: \: \: \: \: [/tex]

We have the final answer as

Hope this helps you

The force which counteracts the thrust force for the flight is known as the drag force, as it opposes the flow.

Drag is a force that opposes an object's relative motion to a fluid environment in the field of fluid dynamics. It may be among two liquid film (or surfaces) or in between a liquid and a flat wall. The drag force is influenced by velocity, as opposed to other resistive forces like dry contact, which are essentially independent of it.

When a flow is moving at low or high speed, the drag force is equal to the speed for low pressure and to the square of the velocity for high-speed flow. Although viscous friction is what ultimately causes drag, turbulent drag is unaffected by viscosity.

A force in physics is an input that has the power to change an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe forces.

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The drag force, which resists the flow, is the force that balances the propulsion force for flight.

In the study of fluid dynamics, drag is a force that opposes an object's relative motion to a fluid environment. It could be situated between two liquid surfaces (or films) or between a liquid and a flat wall.

Unlike other resistive forces like dry contact, which are largely independent of velocity, the drag force is affected by it.

For low pressure and high speed flows, respectively, the drag force is equal to the speed for low pressure and the square of the velocity. Although drag is ultimately caused by viscous friction, turbulent.

Thus, The drag force, which resists the flow, is the force that balances the propulsion force for flight.

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Answer:

3, 4, 6, 7, 8 are manners of death.

Answer:

The photon or quantum of light

Explanation:

Explanation:

time =4.5sec

gravity =9.8m/s square

so to determime the height we can use the formula

1/2 of gravity times time square

which results in 99.25

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Answer:

Massm=2.5kg

Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .

Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .P.E.=U=mgh

Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .P.E.=U=mghU=2.5×10×15

Massm=2.5kgGravitational potential energy is the work done against force of gravity is stored in the body at a height h .P.E.=U=mghU=2.5×10×15U=25/10×10×=375j

Answer:

Explanation:

d

Answer:

This demonstration is often done following a discussion of the ideal gas equation of state, PV=nRT.

We begin by weighing a balloon, then blowing it up and weighing it again. In the photo shown on right, the mass indication increased from 3.4 to 3.5 grams. At this point, it is important to note that the scale measures force, even though it reports a conclusion about mass based on the force measurement.

One assumption made in reaching the conclusion is that the buoyant force on the object being weighed is negligible. In the case of the balloon, this is incorrect. The buoyant force on this balloon is equal to the weight of the air displaced.

Since the volume of air inside the balloon is essentially the same as the volume of air displaced, we should expect that the buoyant force would support the weight of the air inside the balloon: The reported mass should not go up at all, because the force required of the scale should not change.

The increase in reported mass of .1 gram is attributed to the higher density of the air inside the balloon: The tension in the balloon compresses the air inside, as attested by the pressure required to blow the balloon up. Evidently, for this experiment, the pressure inside is greater than atmospheric by about 2%.

In the picture at right, the balloon is being pressed into a pan of liquid nitrogen. (The pan is the styrofoam lid of a small lunch box.) The balloon floats lightly on the liquid nitrogen unless pressed down. Pressing down places more surface area in contact with the cold nitrogen and speeds the demonstration. It is interesting to note the buoyant force by this liquified constituent of air.

The balloon shrinks dramatically, as indicated below. When left in contact with the liquid nitrogen long enough (perhaps 5 minutes) the oxygen inside the balloon liquifies, and then the nitrogen liquefies also. Close observation of the photo at the upper left corner of the pan shows some liquid nitrogen bubbles may forming above the dark spot in the center of the pan. One can also make out a faint line at the upper left corner of the pan which is the liquid nitrogen surface. The balloon still floats, riding rather high on that surface. Evidently, some of the balloon contents remain in the gas phase, making the mass of the balloon less than the mass of the displaced liquid nitrogen.

Next, we take the shrunken balloon and place it back on the scale, as above. In this instance, the reported mass is 8.7 grams, an increase of 5.2 grams.

A look at the figure on the right shows a faint line near the bottom of the cold balloon. Above that line, the balloon contains gas; below the liquid. That line represents the top surface of the liquid air inside the balloon. With this evidence, the easy thing to say would be, "Of course, liquids are heavier than gases," but that would be incorrect. We assert that the amount of air inside the balloon has not changed and that the mass of that air is not dependent on temperature.

If these assertions are true, then the force of gravity on the balloon has not changed. The scale reading is determined by the force which it must exert on the balloon in order to keep it stationary. Evidently, the required force is larger when the balloon is shrunken. The reason is that the buoyant force (upward) has decreased to practically zero, leaving the scale alone to balance the downward force by gravity.

From the data, we can say that the change in the buoyant force is equal to the weight associated with the apparent change in mass. The weight of 5.2 grams is about .052 newtons. The buoyant force is less now because the balloon displaces less air. If we could measure the change in volume of the balloon as DV, then the buoyant force would be (r g DV) upwards, where r is the density of air that was displaced by the balloon, and g is the gravitational field strength, 9.8 Newton/kg.

Note that the .052 newton force is not the weight of the air inside the balloon. Rather, it is the weight of the air that was displaced by the balloon. If we ignore the compression of air inside the balloon, the two numbers are the same. However, the two samples are completely different.

We can estimate the volume of the balloon by assuming that the hand in the photograph is about .1meters across. For purposes of estimation, we say that the volume shrank to almost zero when the balloon was cold so that the change in volume was nearly equal to the original volume. Plugging in numbers gives fair agreement with the book value of 1kg/cubic meter for the density of air.

The value for the density of air is secondary to two main features of this demonstration:

Large changes in temperature produce the large changes in volume that are indicated by the ideal gas equation.

The mass of air in a volume equal to the volume of a balloon can be determined provided that the buoyant force is understood.

Based on the information that is depicted from the question, the data from Najah showed that most managers focus on consideration and inspiration.

The behavioral leadership theory simply focuses on how leaders behave. The theory also assumes that other leaders copy each other's traits.

Based on the complete information, the data illustrated that most managers focus on consideration and inspiration. Managers inspire their subordinates in order to accomplish a goal.

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Explanation:

acceleration remains constant when velocity does not increase or decrease

Answer:

Explanation:

It will be B.

The correct answer is the same mass and less weight.

The weight decreases. Your weight will be 1/6 of the weight on the moon that you had on Earth. This is because the mass of the moon is less hence the gravitational pull is very low compared to Earth.

Therefore, the mass of an object on the Moon remains the same as its mass on Earth. But its weight gets less because the gravity on the moon is less than on the Earth.

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