The enzyme that can proof-read the DNA molecule during the process of DNA replication is called DNA polymerase. DNA polymerase is responsible for adding nucleotides to the growing strand of DNA during replication.
Some DNA polymerases, such as DNA polymerase III and DNA polymerase I, have a proofreading exonuclease activity that allows them to remove any nucleotides that are not correctly paired with the template strand during replication.
The proofreading exonuclease activity of DNA polymerase works by recognizing mismatches between the nucleotides that have been added to the growing strand and the template strand. When a mismatch is detected, the exonuclease activity of the enzyme removes the incorrectly paired nucleotide, allowing the polymerase to add the correct nucleotide in its place.
This proofreading activity increases the accuracy of DNA replication, reducing the number of errors made during replication to approximately 1 in 10^5 nucleotides.
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More people get injured from skateboarding than any other sport
Select the correct picture.
Which picture shows a portion of a plant that is directly involved in pollination?
The portion of the plant that is directly involved in the pollination process is the flower portion that is present in the second option, as the flower has the female part that can fertilize to give rise to the zygote.
What is the pollination process in plants?In plants, the pollination process happens, and as a result, a new plant is developed and the pollination can be carried out by many factors, such as the wind, honey bees, and others, and they help the flowers be fertilized.
Hence, the portion of the plant that is directly involved in the pollination process is the flower portion that is present in the second option, as the flower has the female part that can fertilize to give rise to the zygote.
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Answer:
The second option, the pink flower
Explanation:
explain each step of meiosis
Answer
(mitosis steps first)
Prophase II: Starting cells are the haploid cells made in meiosis I. Chromosomes condense.
Metaphase II: Chromosomes line up at the metaphase plate.
Anaphase II: Sister chromatids separate to opposite ends of the cell.
Telophase II: Newly forming gametes are haploid, and each chromosome now has just one chromatid.
Which of the following is true about the fate of fatty acids after their absorption?
Select one:
a. Fatty acids of 16 or more carbons enter the blood and then the liver via the portal vein.
b. Fatty acids of less than 12 carbons enter the lymphatic system packaged in chylomicrons.
c. Fatty acids of less than 12 carbons enter the blood and then the liver via the portal vein.
d. Fatty acids of 16 or more carbons enter the lymphatic system directly and then enter the blood via the aorta.
The correct answer to the question is b. Fatty acids of less than 12 carbons enter the lymphatic system packaged in chylomicrons.
After absorption, fatty acids are taken up by the lymphatic system and transported in the form of chylomicrons. Chylomicrons are lipoproteins composed of lipids, proteins and other substances, and are the largest form of lipoproteins.
Chylomicrons are mainly composed of triglycerides and cholesterol esters, and are responsible for the transport of fatty acids from the small intestine to the rest of the body. These chylomicrons contain fatty acids of less than 12 carbons, which are then transported throughout the body via the lymphatic system.
Once the fatty acids reach the liver, they are either metabolized or stored as fats. In order to enter the blood, fatty acids of 16 or more carbons must be packaged in lipoproteins, such as very low density lipoproteins (VLDL). These VLDLs are then transported to the liver via the portal vein.
In summary, fatty acids of less than 12 carbons enter the lymphatic system packaged in chylomicrons, while fatty acids of 16 or more carbons enter the blood and then the liver via the portal vein.
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