What happens when acetate rubs with wool

Answers

Answer 1

When a Cellulose Acetate rod is rubbed with a woolen duster, friction occurs, rubbing loosely held electrons from the rod onto the duster. So, this time, the rod loses electrons. Since the Acetate rod now has fewer electrons than protons it has become positively charged. Hope this helps!

Answer 2

Answer:

The charge becomes positive.

Explanation:

When rubbed with cellulose acetate the charge of the fur/wool will become negative.


Related Questions

PLEASEEEEEE HELPPPPPPP MEEEEEEEE!!!!!!!!!!!!!

Answers

Answer:

[tex]2 \\ because \\ 2 - 2 = 0 \\ 5 - 5 = 0[/tex]

Suppose that John lives on a square block that is 180 yards per side, and in the evenings, he walks with his dog around the block for a little exercise.

A) If John walks once around the block, what distance does he travel?

B) If John walks once around the block, what is his final displacement?

Answers

Answer:

It's A

Explanation:

Although I'm not sure about the second one, I'm sure the first one is A

please answer me!!! asappp​

Answers

Answer:

omg this is hard

Explanation:

Yes it is lol

Which of the following statements is false about photosynthesis and cellular respiration?
O Photosynthesis uses carbon dioxide.
O Cellular respiration gives off carbon dioxide.
O Photosynthesis makes glucose.
O Both photosynthesis and cellular respiration occur in all living things.

Answers

Answer:

photosynthesis uses carbon dioxide

Explanation:

Consider the following statements:

1. Carbon dioxide, chlorophyll, and sunlight are all essential for photosynthesis.

2. Rate of photosynthesis is maximum in red light and minimum in green light.

3. Increase

concentration decreases the rate of photosynthesis.

Which of the statements given above are correct about photosynthesis?

Is the answer 0.055 seconds? (Only problem 13)

Answers

Answer:

98.7 seconds

Explanation:

I believe the answer is not 0.055s

Both trains have the same speed and are approaching each other.

They both have to cover 8.5km, and since they are going the same speed they need to cover half the distance each (4.25km)

So, how long will it take a train going 155km/h to travel 4.25km?

The ratio of

[tex]\frac{155km}{1hour} = \frac{4.25km}{x hours}[/tex]

There are 60 x 60 seconds in one hour (3600 seconds)

[tex]\frac{155km}{3600 seconds} = \frac{4.25km}{x seconds}[/tex]

Solve for x to get 98.7 seconds

We can do this by flipping both sides of the ratio

[tex]\frac{3600 s}{155 km} = \frac{x seconds}{4.25 km}[/tex]

Multiply both sides by 4.25km

4.25 ×  [tex]\frac{3600 s}{155 km} ={x seconds}[/tex]

Our unknown x = 98.7 seconds

Helen is riding down a freeway on her motorcycle at 95kilometersperhour. At this speed, how far will Helen ride in 2hours?

Answers

The answer is 190kikometersperhour because of you multiply 95 times 2 it equals 190

A 500 kg airplane wing is hanging on a rope from the ceiling. What is the tension force being supplied by the rope?
a.5000
b.2500
c.250
d.500

Answers

Answer:

a. 5000 N

Explanation:

If gravity is 10 m/s² and the wing is motionless.

F = ma = 500(10) = 5000 N

the position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) determine the distance

Answers

Answer:

[tex] |d| = \sqrt{ {(x_{2} -x_{1})}^{2} + {(y_{2} -y_{1})}^{2} + {(z_{2} -z_{1})}^{2}} \\ = \sqrt{ {(6 - 2)}^{2} + {(3 - 0)}^{2} +{(5 - 8)}^{2} } \\ = \sqrt{16 + 9 + 9} \\ = \sqrt{34} [/tex]

The position of an ant and a spider in a room are A(2,3,5) and B(6,0,8)  the distance between ant and spider is 5.83 m.

What is Distance between two points?

The distance formula states that the distance between two points in xyz-space is the square root of the sum of the squares of the differences between corresponding coordinates A( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] , [tex]z_{1}[/tex] ) and B( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] ,[tex]z_{2}[/tex]),

AB² = ([tex]x_{2}[/tex] - [tex]x_{1}[/tex])² + ([tex]y_{2}[/tex] - [tex]y_{1}[/tex])² + ( [tex]z_{2}[/tex]  - [tex]z_{1}[/tex] )²

In reality, the Pythagorean Theorem is nothing more than the distance formula. Draw a right triangle using the segment AB as its hypotenuse in order to get the distance AB between points  A( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] )  and B( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] ).

Given that in the question two points are A(2,3,5) and B(6,0,8), so the distance between them is

AB² = ([tex]x_{2}[/tex] - [tex]x_{1}[/tex])² + ([tex]y_{2}[/tex] - [tex]y_{1}[/tex])² + ( [tex]z_{2}[/tex]  - [tex]z_{1}[/tex] )²

AB² = 4² + 3² + 3²

AB² = 34

AB  = 5.83 m

Position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) the distance between ant and spider is 5.83 m.

To learn more about distance between two point refer to the link

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the velocity of an object must include these two things ________ and _________

will give brainlest

Answers

Answer:

The velocity of an object must include these two things displacement and time.

Explanation:

Hope this helps you. Have a nice day^_^

Please mark as brainliest. It helps a lot. :)

31) what is the energy required to change 20g of copper, whose specific heat is 0.39j/gc,
change from 20 to 40 degrees?

Answers

Explanation:

given :

m = 20 g

sh = 0.39 J/g°C

∆T = 40-20 = 20°C

Find the Energy!

solution :

E =m. sh. ∆T

= 20 × 0.39 × 20

= 156 J

♪Answer : mass = 20g sh = 0.39j/g°c∆T = 40° - 20° = 20°

So, energy required is

Energy = mass*sh*∆T

Energy = 20g*0.39j/g°c*20°

Energy = 156joule

~Physics#1

A ball rolls with a constant acceleration of 2.5 m/s^2 for 5.0 s with an initial velocity of 5.0 m/s. Calculate the
ball's distance from the starting point at 1.0 s intervals. Make a position-time graph for the object's motion. In
your response, show what you are given, the equation that you used, any algebra/work required, a table of
data, and your graph.

Answers

The kinematics allows finding the answers for the positions of the body as a function of time and making its graph are:

       

The positions according to time are in the table In the attachment we can see a graphic representation

Given parameters

The acceleration a = 2.5 m / s² Time t = 5.0 s The initial velocity vo = 5.0 m / s

To find

The distance each Dt = 1.0 s

Kinematics studies the motion of bodies, gives relationships between the position, velocity and acceleration of bodies, let's use the relationship

          x = v₀ t + ½ a t²

Where x is the position, v or the initial velocity, at the acceleration and t is the time.

Let's substitute

           x = 5 t + ½ 2.5 t²

           x = 5 t + 1.25 t²

Let's calculate the position and write it in the table

t = 0 s       x = 0 m

t = 1 s        x = 5 1 + 1.25 1² = 6.25 m

t = 2 s       x = 5 2 + 1.25 2² = 15 m

t = 3s        x = 5 3 + 1.25 3² = 26.25 m

t = 4 s       x = 5 4 + 1.25 4² = 40 m

t = 5 s       x = 5 5 + 1.25 5² = 56.25 m

In the following table the time and positions of the body are given, these given are used for the attached graph

time (s)      position (m)

   0                  0

    1                  6.25

   2                 15

   3                 26.25

   4                 40

   5                 56.25

In conclusion, using kinematics we can find the answers for the positions of the body as a function of time and make its graph are:

       

The positions according to time are in the tableIn the attachment we can see a graphic representation

Learn more here:

https://brainly.com/question/5063616

Potential energy is due to_blank_?

Answers

Answer:

To summarize, potential energy is the energy that is stored in an object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height.

Explanation:

if it helped plz mark brainiest

what are adaptations needed for animals to survive on grassland?

Answers

Answer:

short teeth, short hair, camoflauge, and speed

Explanation:

Answer:

speed and awareness

Explanation:

An engine raises 120kg of water through a height of 40m in 30s.What is the power of the engine take gravity to be = 10m/s.​

Answers

Answer:

  1600 W

Explanation:

Power is the product of force and distance, divided by time.

  P = (120 kg)(10 m/s²)(40 m)/(30 s) = 1600 kg·m²/s³ = 1600 W

Anne pushed a cart by 12 N. How far did the cart move if the work done was 9 J?​

Answers

Force=12NWork=9J

[tex]\\ \sf\longmapsto W=Fd[/tex]

[tex]\\ \sf\longmapsto d=\dfrac{W}{F}[/tex]

[tex]\\ \sf\longmapsto d=\dfrac{9}{12}=0.72m[/tex]

Answer:

Anne pushed a cart by 12 N.

● Force = 12 N

Work done is 9 J

● Work = 9 J

=> Work = Force × distance

[tex]=> distance = \frac{work}{force} [/tex]

[tex]=> distance = \frac{9}{2} [/tex]

[tex]=> distance = 0.72m[/tex]

▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Is the answer 0.055 seconds? (Only problem 13)

Answers

Answer:

155÷8.5

=18.235294117647

find the current and voltage across each resistor in the given circuit.​

Answers

Answer:

R1, R4: 1.3433 VR2: 0 VR3: 6.3134 V

Explanation:

The resistor R2 is shorted out, so is not in the circuit. The remaining resistors are in a series circuit with a total resistance of ...

  R1 +R3 +R4 = 1k +4.7k +1k = 6.7k

The current is the ratio of the applied voltage to this total resistance:

  I = V/R = (9 v)/(6.7k) ≈ 1.3433 mA

The voltage across each resistor is the product of this current value and the resistance:

  R1 voltage = (1 kΩ)(1.3433 mA) = 1.3433 volts

  R2 voltage = 0

  R3 voltage = (4.7 kΩ)(1.3433 mA) = 6.3134 volts

  R4 voltage = (1 kΩ)(1.3433 mA) = 1.3433 volts

A spring scale is used to measure the weight of various objects. When a 100 g empty glass bottle is placed on the scale, the spring stretches down 1.8 cm. How much water should be poured into the glass bottle to stretch the spring down by 2.7 cm?

A: 44 mL
B: 50 mL
C: 33 mL
D: 150 mL

Answers

The answer is B. 50ml

50 mL of water have to poured to the glass bottle of 100 g to increase the stretching of the spring from 1.8 cm to 2.7 cm.

What is spring stretching?

A spring can hang when it loads a weight. The stretching of spring is the change in length of the spring end from its initial length.  Spring balance works with the principle of Hooks law.

The stretching is made by the elasticity of the spring which make it in a wave like motion.

Given that the glass bottle with 100 g weight when loaded on the spring scale, it will stretch down to 1.8 cm. Then the weight required to make a stretch of 2.7 cm is calculated as follows:

weight required  = (100 g × 1.8 cm) /2.7 cm

                            = 150 g.

A total of 150 g is needed to stretch into 2.7 cm. Thus we have to add 50 g of water to the glass weighing 100 g . 50 g is equivalent to 50 ml, since density of water is 1 g/L.

Hence, 50 ml of water should be poured to the glass.

To find more about spring scale, refer the link below:

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David was driving at a velocity of 5 m/s. He accelerates to a velocity of 8 m/s in 4 seconds. What is the acceleration?

Identify the given variables and the unknown
x distance


t time


Vi initial velocity


Vf final velocity


a acceleration


F force

Answers

If David was driving at a velocity of 5 m/s and accelerates to a velocity of 8 m/s in 4 seconds, David's acceleration is 0.75 [tex]m/s^2[/tex].

Given the following data:

Initial velocity, Vi = 5 m/sFinal velocity, Vf = 8 m/sTime, t = 4 seconds.

To find David's acceleration:

Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.

Mathematically, acceleration is given by the formula;

[tex]Acceleration = \frac{V_f\; - \;V_i}{t}[/tex]

Where:

Vf is the final velocity.Vi is the initial velocity.t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

[tex]Acceleration = \frac{8\; - \;5}{4}\\\\Acceleration = \frac{3}{4}[/tex]

Acceleration = 0.75 [tex]m/s^2[/tex].

Therefore, the David's acceleration is 0.75 [tex]m/s^2[/tex].

Read more: https://brainly.com/question/8898885

a father and his son are racing down a mountain. if they're traveling at the same velocity who has more kinetic energy​

Answers

Answer:

I think it's the son

Explanation:

bcs he might love it


A particular car can go from rest to 90 kmh in 10 seconds. What is its
acceleration. (Show your calculation

Answers

Answer:

Im sorry i dont know But thank you for the points

In an electrostatic field, path 1 between points A and B is twice as long as path 2. The electrostatic work done on a negatively charged particle that moves from A to B along path 1 is W1.

How much work is done on this particle if it later goes from A to B along path 2? Express your answer in terms of W1.

W2=??​

Answers

Answer:

W2 = W1

Explanation:

work is independent of the path taken between the points.

What is the magnitude of the momentum of a 1000 kg car traveling
at 5 m/s?

Answers

Answer:

5000 kg.m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question

mass = 1000 kg

velocity = 5 m/s

We have

momentum = 1000 × 5 = 5000

We have the final answer as

5000 kg.m/s

Hope this helps you

which is an example of qualitative data?

A) the number of golfers who use callaway clubs

B) the scores of the golfers who use callaway clubs

C) the rating that the golfers give Callaway clubs

D) the number of putts per round of golfers using Callaway clubs

Answers

The answer is C)the rating that the golfers give Callaway clubs

if 2 magnets were forced together vertically on the same poles and suddenly released, how high would the top magnet travel? The magnets are disc-shaped with a circumference of 6.5" and a mass of 8 lbs, the combined force of the magnets is 13,200lbs.

Answers

Woahhhhhhhhh!!!!! Ahhh

If you push on a door for 12 seconds with a force of 53 N, how much impulse
have you applied to the door?
A. 815 kg•m/s
B. 332 kg•m/s
C. 636 kg•m/s
D. 4.42 kg•m/s

Answers

Answer:

C. 636 kg•m/s

Explanation:

53(12) = 636 N•s or kg•m/s

Si la fuerza de repulsión entre dos cargas es 18 × 1013

Answers

Answer:

Explanation:

F = kQq/r²

r = √(kQq/F)

a)  r = √(8.899(10⁹)(8)(4) / 18(10¹³)) = 0.0397749... m

  r = 40 mm

b) r = √(8.899(10⁹)(12)(3) / 18(10¹³)) = 0.0421876... m

   r = 42 mm

how is th ekinetic energy of the particles




will mark brainliest

Answers

The kinetic energy of the particle is less after it changes from gas to liquid,  (Option B).

What is the kinetic energy of a particle?

The kinetic energy of a particle is the energy it possesses due to its motion. It is a scalar quantity and is dependent on the mass and speed of the particle.

The formula to calculate the kinetic energy (KE) of a particle is:

KE = ¹/₂ mv²

Where:

KE = Kinetic Energym = Mass of the particlev = Speed (velocity) of the particle

Thus, the kinetic energy of the particle is less after it changes from gas to liquid, because the speed of the particle is less in liquid phase than in gaseous phase.

Learn more about kinetic energy here: https://brainly.com/question/25959744

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1)How fast is a ball moving when falling from rest and hits the ground 1.70
seconds later?

Answers

The final velocity of the ball is16.66 m/s.

Given the following data:

Initial velocity, U = 0 m/s (since the ball is falling from rest). Time, t = 1.70 seconds.

We know that acceleration due to gravity (a) for a ball in free fall is equal to 9.8 meter per seconds square.

To find how fast (velocity) the ball is moving, we would use the first equation of motion:

Mathematically, the first equation of motion is calculated by using the formula;

[tex]V = U + at[/tex]

Where:

V is the final velocity. U is the initial velocity.a is the acceleration. t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

[tex]V = 0 + 9.8(1.7)[/tex]

[tex]V = 9.8[/tex] × [tex]1.70[/tex]

Final velocity, V = 16.66 m/s.

Therefore, the final velocity of the ball is16.66 m/s.

Read more: https://brainly.com/question/8898885

help please this is due in an hour!!!

Answers

[tex]▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ [/tex]

Charge on one electron :

[tex]1.602 \times 10 {}^{ - 19} \: \: coulombs[/tex]

So, charge on ball having 97 electrons is equal to :

[tex]97 \times 1.602 \times 10 {}^{ - 19} [/tex]

[tex]155.394 \times 10 {}^{ - 19} [/tex]

[tex]1.554 \times 10 {}^{ - 17} \: \: coulombs[/tex]
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