What is 3x-(2x+9) + 4x?
Please help^^

2(2.5) + 5(23) = 150

3(2.5) + 4(23) = 144.5

Both equations are satisfied, so our solution is correct.

To solve the problem, let's first assign some variables. Let x be the cost of one pine tree and y be the cost of one hydrangea bush. We can then use these variables to set up a system of equations:

2x + 5y = 150 (equation 1)

3x + 4y = 144.5 (equation 2)

We can solve this system of equations using various methods. Here, we will use the substitution method.

From equation 1, we can solve for x in terms of y:

2x = 150 - 5y

x = (150 - 5y)/2

We can then substitute this expression for x into equation 2:

3((150 - 5y)/2) + 4y = 144.5

Multiplying both sides by 2 to eliminate the fraction:

3(150 - 5y) + 8y = 289

Expanding and simplifying:

450 - 15y + 8y = 289

-7y = -161

y = 23

We can now substitute this value for y into either equation 1 or 2 to solve for x:

2x + 5(23) = 150

2x = 5

x = 2.5

Therefore, one pine tree costs $2.50 and one hydrangea bush costs $23.

To check our work, we can substitute these values into both equations:

2(2.5) + 5(23) = 150

3(2.5) + 4(23) = 144.5

Both equations are satisfied, so our solution is correct.

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To solve the equation, we need to first simplify both sides:

(4x - 6)/5 + 1 = (x + 1)/5 - 2/5

Multiplying both sides by 5 to eliminate the denominator:

4x - 6 + 5 = x + 1 - 2

Simplifying further:

4x - 1 = x - 1

Subtracting x from both sides:

3x - 1 = -1

Adding 1 to both sides:

3x = 0

Dividing both sides by 3:

x = 0

Therefore, the solution to the equation is x = 0.

Answer:  x=28

Step-by-step explanation:

Given:      <A=68

Find:     x

Reasoning:  

<B = 2x+x

<B= 3x

<C=x     they say the sides across from <C is same as other side so the

             angles are the same

Solution:

All angles of a triangle =180

<A + <B + <C =180    >substitute

68 + 3x + x =180      > combine like terms

68 + 4x = 180           > subtract 68 from both sides

4x=112                       >divide both sides by 4

x=28

The random variable in the first situation is the number of hits for the players of a baseball team and in the second situation is the distance traveled by the tee shots in a golf game.

1) The random variable in this distribution is the number of hits for the players of a baseball team. This is a discrete random variable because hits are counted as whole numbers and cannot take on non-integer values.

2) The random variable in this distribution is the distance traveled by the tee shots in a golf game. This is a continuous random variable because the distances traveled can take on any value within a certain range, including non-integer values. The exact distance traveled by a tee shot can be measured to any degree of precision, and there are infinitely many possible distances within the range of possible outcomes. Therefore, it is a continuous random variable.

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(a) Indefinite integral of 5(5x^4 - 5sinx)dx is (5/3)x^5 + 5cosx + C. Definite integral over [0, π/2] is (125π/6) - 5.

We can evaluate the indefinite integral by applying the power rule and integration by substitution. The definite integral can be evaluated by substituting the limits of integration and simplifying.

(b) Indefinite integral of [(18x^2 - 1)(6x^3 - 9x^2 - 3)]^6dx is (18x^11 - 77x^9 + 126x^7 - 108x^5 + 49x^3 - 9x) / 11 + C.

To simplify the given expression, we can first expand the polynomial and then apply the power rule to integrate each term. The constant of integration can be added at the end.

(c) Definite integral of ∫tan^2(x)sec^2(x)dx over [0,π/4] is 1.

We can use the trigonometric identity sec^2(x) - 1 = tan^2(x) to simplify the integrand. Then we can apply the power rule and substitute the limits of integration to evaluate the definite integral.

(d) Indefinite integral of ∫(x+4)^2√(3x^2+4)dx is (1/15)(3x^2+4)^(3/2)(x+4) - (4/45)(3x^2+4)^(3/2) + C.

We can use substitution to simplify the integrand by setting u = 3x^2 + 4. After integrating, we can substitute back for u and simplify the constant of integration.

(e) Indefinite integral of ∫(120/(1+2x^2))dx is 60√2tan^(-1)(√2x) + C.

We can use substitution to simplify the integrand by setting u = 1 + 2x^2. After integrating, we can substitute back for u and simplify the constant of integration.

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Answer:

61 degrees

Step-by-step explanation:

Triangle interior measures add up to 180 degrees.

61 + 58 + x = 180

119 + x = 180

x = 61

hope this helps :) !!!

a) P(x) = R(x) - C(x) = 6x - (0.001x^2 + 18x + 40) = -0.001x^2 - 12x - 40

b) R(200) = 6(200) = 1200
  C(200) = 0.001(200)^2 + 18(200) + 40 = 4000
  P(200) = R(200) - C(200) = 1200 - 4000 = -2800

c) R'(x) = 6
  C'(x) = 0.002x + 18
  P'(x) = R'(x) - C'(x) = 6 - (0.002x + 18) = -0.002x - 12

d) R'(200) = 6
  C'(200) = 0.002(200) + 18 = 18.4
  P'(200) = -0.002(200) - 12 = -12.4

Here are the answers to each part:

a) P(x) is the profit function, which is calculated as the difference between the revenue function and the cost function: P(x) = R(x) - C(x). In this case, P(x) = 6x - (0.001x^2 + 18x + 40).

b) To find R(200), C(200), and P(200), plug x = 200 into each function:
R(200) = 6(200) = 1200
C(200) = 0.001(200^2) + 18(200) + 40 = 7600
P(200) = 1200 - 7600 = -6400

c) To find R'(x), C'(x), and P'(x), we need to find the derivative of each function with respect to x:
R'(x) = d(6x)/dx = 6
C'(x) = d(0.001x^2 + 18x + 40)/dx = 0.002x + 18
P'(x) = R'(x) - C'(x) = 6 - (0.002x + 18)

d) To find R'(200), C'(200), and P'(200), plug x = 200 into each derivative function:
R'(200) = 6
C'(200) = 0.002(200) + 18 = 18.4
P'(200) = 6 - 18.4 = -12.4

I hope this helps! Let me know if you have any further questions.

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Answer:

60%

Step-by-step explanation:

Take 96 and divide it by 160.

(easier if done on a calculator.)

For example: Find A/B as a percentage: take "A" and divide it by "B"

Answer:

x = 16

Step-by-step explanation:

(2x + 16) = 48

Subtract 16 with the positive 16 to cancel the numbers.

Subtract 16 with 48.

2x = 32

divide 32 by 2 to isolate the x.

32/2 = 16

x = 16

The situation represents exponential decay.

The rate of growth or decay, r, is equal to 0.02.

So the depth of the lake each year is 0.98 times the depth in the previous year.

It will take between 11 and 12 years for the depth of the lake to reach 26. 7 meters.

The situation represents exponential decay, as the depth of the lake decreases by a constant percentage each year. The rate of decay is 2% per year, so the rate of growth or decay, r, is equal to 0.98 (1 - 0.02). This means that the depth of the lake each year is 0.98 times the depth in the previous year.

To find the number of years it will take for the depth of the lake to reach 26.7 meters, we can use the formula for exponential decay:\

D = D₀ *[tex]e^{(-rt)[/tex]

where D is the current depth, D₀ is the initial depth, r is the rate of decay, and t is the number of years.

Substituting the given values, we get:

26.7 = 30 * [tex]e^{(-0.02t)[/tex]

Solving for t, we get:

t = ln(26.7/30) / (-0.02) ≈ 11.33

Therefore, it will take between 11 and 12 years for the depth of the lake to reach 26.7 meters.

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To find the value of tan(θ), we first need to calculate the values of sine and cosine for the given point (4, 3) terminal side. We can use the Pythagorean theorem to find the length of the hypotenuse (r):

r = √((4)^2 + (3)^2) = √(16 + 9) = √25 = 5

Now, we can find sin(θ) and cos(θ) at the terminal side:

sin(θ) = opposite/hypotenuse = 3/5
cos(θ) = adjacent/hypotenuse = 4/5

Then, we can calculate tan(θ):

tan(θ) = sin(θ) / cos(θ) = (3/5) / (4/5) = 3/4

Now we need to find tan(2θ). We can use the double-angle formula for tangent:

tan(2θ) = (2 * tan(θ)) / (1 - tan^2(θ))

Substitute the value of tan(θ):

tan(2θ) = (2 * (3/4)) / (1 - (3/4)^2) = (3/2) / (1 - 9/16) = (3/2) / (7/16)

Now, we'll multiply by the reciprocal to solve for tan(2θ):

tan(2θ) = (3/2) * (16/7) = 24/7

So, tan2θ = 24/7. Your answer is: 24/7

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The inverse for each relation:

1. {(1,‐2), (2, 3),(3, ‐3),(4, 2)} - {(-2, 1), (3, 2), (-3, 3), (2, 4)}

2. {(4,2),(5,1),(6,0),(7,‐1)} - {(2, 4), (1, 5), (0, 6), (-1, 7)}

3. Inverse equation: y=(-1/8)x+3/8

4. Inverse equation: y=3/2x+15/2

5. Inverse equation: y=2x-20

6. Inverse equation: y=[tex]x^{(1/2)}+3[/tex]

7. Since fog(x) = gof(x) = x, f and g are inverse functions.

8. Since fog(x) = gof(x) = x, f and g are inverse functions.

1. To find the inverse of the relation, we need to swap the positions of x and y for each point and then solve for y.

{(1, -2), (2, 3), (3, -3), (4, 2)}

Inverse: {(-2, 1), (3, 2), (-3, 3), (2, 4)}

2. Again, we swap x and y and solve for y.

{(4, 2), (5, 1), (6, 0), (7, -1)}

Inverse: {(2, 4), (1, 5), (0, 6), (-1, 7)}

3. To find the inverse equation for y=-8x+3, we swap x and y and solve for y.

x=-8y+3

x-3=-8y

y=(x-3)/-8

Inverse equation: y=(-1/8)x+3/8

4. To find the inverse equation for y=2/3x-5, we swap x and y and solve for y.

x=2/3y-5

x+5=2/3y

y=3/2(x+5)

Inverse equation: y=3/2x+15/2

5. To find the inverse equation for y=1/2x+10, we swap x and y and solve for y.

x=1/2y+10

x-10=1/2y

y=2(x-10)

Inverse equation: y=2x-20

6. To find the inverse equation for y=(x-3)², we swap x and y and solve for y.

x=(y-3)²

[tex]x^{(1/2)}=y-3[/tex]

[tex]y=x^{(1/2)}+3[/tex]

Inverse equation: [tex]y=x^{(1/2)}+3[/tex]

7. To verify that f(x)=5x+2 and g(x)=(x-2)/5 are inverse functions, we need to show that fog(x)=gof(x)=x for all x in the domain of f and g.

fog(x) = f(g(x)) = f((x-2)/5) = 5((x-2)/5) + 2 = x

gof(x) = g(f(x)) = g(5x+2) = ((5x+2)-2)/5 = x/5

Since fog(x) = gof(x) = x, f and g are inverse functions.

8. To verify that f(x)=1/2x-7 and g(x)=2x+14 are inverse functions, we need to show that fog(x)=gof(x)=x for all x in the domain of f and g.

fog(x) = f(g(x)) = f(2x+14) = 1/2(2x+14) - 7 = x

gof(x) = g(f(x)) = g(1/2x-7) = 2(1/2x-7) + 14 = x

Since fog(x) = gof(x) = x, f and g are inverse functions.

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The equation is (x^2 + y^2 - 38x + 6y = -369).

The center of the lake is 19 miles east and 3 miles south of the town hall, which means the coordinates of the center are (19,-3). The radius of the lake is 0.5 miles.

Using the standard equation of a circle, we have:

(x - h)^2 + (y - k)^2 = r^2

where (h,k) is the center of the circle and r is the radius.

Substituting the given values, we get: (x - 19)^2 + (y + 3)^2 = 0.5^2

Expanding the left side, we get: x^2 - 38x + 361 + y^2 + 6y + 9 = 0.25

Simplifying and rearranging terms, we get:

x^2 + y^2 - 38x + 6y + 369.25 = 0.25

Subtracting 369 from both sides, we get:

x^2 + y^2 - 38x + 6y = -369

Therefore, the equation that represents the lake on the map is:

(x - 19)^2 + (y + 3)^2 = 0.5^2, which can be simplified to (x^2 + y^2 - 38x + 6y = -369).

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The mean travel time is 60 minutes, the standard deviation is approximately 6.08 minutes, and the probability that Alice will not be late for her class is 0.50 or 50%.

To find the mean travel time, we need to add up the mean times for each stage of Alice's journey. Let's calculate it step by step:

Step 1: Alice's walking time from home to the bus stop:

Mean walking time = 13 minutes

Step 2: Waiting time for the bus to arrive:

Mean waiting time = 5 minutes

Step 3: Bus journey time from the bus loop:

Mean bus journey time = 24 minutes

Step 4: Walking time from the bus loop to the lecture theatre:

Mean walking time = 18 minutes

Now, let's calculate the total mean travel time:

Mean travel time = Mean walking time + Mean waiting time + Mean bus journey time + Mean walking time

= 13 + 5 + 24 + 18

= 60 minutes

So, the mean travel time is 60 minutes.

To find the standard deviation of Alice's travel time, we need to calculate the variance for each stage and then sum them up. Finally, we take the square root to get the standard deviation. Let's calculate it step by step:

Step 1: Alice's walking time from home to the bus stop:

The variance of walking time = 4 minutes squared

Step 2: Waiting time for the bus to arrive:

The standard deviation of waiting time = 2 minutes

Step 3: Bus journey time from the bus loop:

The standard deviation of bus journey time = 5 minutes

Step 4: Walking time from the bus loop to the lecture theatre:

The variance of walking time = 4 minutes squared

Now, let's calculate the total variance of travel time:

Variance of travel time = Variance of walking time + Variance of waiting time + Variance of bus journey time + Variance of walking time

= 4 + 4 + 25 + 4

= 37 minutes squared

Finally, the standard deviation of travel time is the square root of the variance:

The standard deviation of travel time = [tex]\sqrt(37)[/tex]

≈ 6.08 minutes (rounded to 2 decimal places)

So, the standard deviation of Alice's travel time is approximately 6.08 minutes.

To find the probability that Alice will not be late for her class, we need to calculate the z-score for the desired arrival time and then find the corresponding probability from the standard normal distribution table. Let's calculate it step by step:

Step 1: Calculate the total travel time from home to the lecture theatre:

Total travel time = Mean travel time = 60 minutes

Step 2: Calculate the difference between the desired arrival time and the total travel time:

Time difference = 8 am - 7 am = 1 hour = 60 minutes

Step 3: Calculate the z-score using the formula:

z = (Time difference - Mean travel time) / Standard deviation of travel time

z = [tex]\frac{(60 - 60) }{ 6.08}[/tex]

z = 0

Step 4: Find the probability corresponding to the z-score from the standard normal distribution table.

Since the z-score is 0, the probability is 0.50 (or 50%).

Therefore, the probability (to 2 decimal places) that Alice will not be late for her class is 0.50 or 50%.

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The  true triangle  statement regarding the diagram are:

1.  m∠5 + m∠6 = 180°  ________Linear Pair

2. ∠ 2+ ∠ 3 = ∠ 6________Exterior angle Property of Triangle

3. m∠2 + m∠3 + m∠5 = 180°________Triangle Sum Property

From the question,  Δ ABC with Exterior angles as ∠ 1 , ∠ 4 ,and ∠ 6

Note that the  Exterior angle Property of Triangle state that An exterior angle of a triangle is equal to the sum of the opposite interior angles.

Hence: For Exterior ∠ 1 :

∠ 1 = ∠ 5 + ∠ 3 ________Exterior angle Property of Triangle

Also,

For Exterior ∠ 4:

∠ 4 = ∠ 5 + ∠ 2 ________Exterior angle Property of Triangle

Also,

In regards to Exterior ∠ 6:

∠ 6 = ∠ 2 + ∠ 3 ________ Exterior angle Property of Triangle

Using Triangle Sum Property, it state that In a triangle sum of the measures of angles is equal to 180° Hence:  m∠2 + m∠3 + m∠5 = 180° ________Triangle Sum Property

The Linear Pair will be: The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.

Therefore,  m∠5 + m∠6 = 180°  ________Linear Pair

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See full question below

A triangle is shown with its exterior angles. The interior angles of the triangle are angles 2, 3, 5. The exterior angle at angle 2 is angle 1. The exterior angle at angle 3 is angle 4. The exterior angle at angle 5 is angle 6. Which statements are always true regarding the diagram? Select three options.

m∠5 + m∠3 = m∠4

m∠3 + m∠4 + m∠5 = 180°

m∠5 + m∠6 =180°

m∠2 + m∠3 =

m∠6 m∠2 + m∠3 + m∠5 = 180°

The average depth of the Indian Ocean is 3.7 time greater than that of Arctic Ocean. Therefore, the correct option is A.

To find how many times as great the average depth of the Indian Ocean is compared to the Arctic Ocean, we need to divide the average depth of the Indian Ocean by the average depth of the Arctic Ocean.

1: Divide the average depth of the Indian Ocean by the average depth of the Arctic Ocean:

3900 meters (Indian Ocean) / 1050 meters (Arctic Ocean) = 3.7142857

2: Round the result to the nearest tenth:

3.7

So, the average depth of the Indian Ocean is approximately 3.7 times greater than the average depth of the Arctic Ocean. The correct answer is A. 3.7.

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The correct statement is given as follows:

The function g(t) reveals the market value of the house increases by 3.6% each year.

An exponential function has the definition presented as follows:

[tex]y = ab^x[/tex]

In which the parameters are given as follows:

The parameter b for this problem is given as follows:

b = 1.036.

As the parameter b has an absolute value greater than 1, the function is increasing, with a rate given as follows:

1.036 - 1 = 0.036 = 3.6% a year.

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The coordinates of point M come out to be 4.8, 4.4

This case is solved by using the section formula which states that

The coordinate of point P that divides the line segment AB in the ratio of m:n where the coordinate of A is [tex]x_1,y_1[/tex] and the B is [tex]x_2,y_2[/tex] is described as

[tex]\frac{mx_2+nx_1}{m+n}[/tex],[tex]\frac{my_2+ny_1}{m+n}[/tex]

The line to be divided = PQ

Coordinates of P = (6,2)

Coordinates of Q = (3,8)

Ratio = 2:3

Thus, the coordinates of M = [tex]\frac{2*3+3*6}{2+3}[/tex],[tex]\frac{8*2+2*3}{2+3}[/tex]

= 24/5 , 22/5

= 4.8, 4.4

Point M with coordinates (4.8,4.4) lies on PQ and divides the segment so that the ratio of PM-MQ is 2-3

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So the expression that represents the average distance of a planet from the sun using radicals is: d = k/2√13 * √x

An exponent, also known as a power, is a mathematical notation that indicates the number of times a quantity is multiplied by itself. It is usually written as a small number (the exponent) placed to the right and above a larger number (the base). Exponents are used in many mathematical concepts, including logarithms, roots, and scientific notation.

Here,

The expression ((1)/∛(52)x)²) can be simplified using exponent rules:

((1)/∛(52)x)²) =((1)/∛(52)x)²) * ∛x²)

= 1/(∛52² * ∛x²)

The average distance of a planet from the sun measured in astronomical units can be represented using the formula:

d = k * √T

where d is the distance from the sun, T is the time it takes for the planet to orbit the sun, and k is a constant of proportionality.

We can rewrite this formula in terms of Earth weeks by noting that there are 52 weeks in a year, so T = (1/52)x years. Substituting this into the formula, we get:

d = k * √((1/52)x)

Simplifying this expression using exponent rules, we get:

d = k * √(1/52)* √x

So an equivalent expression using radicals to represent the average distance of a planet from the sun is:

d = k * √(1/(52)) * √x

which simplifies to:

d = k/√(52) * √x

or

d = k/2√13 * √x

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The expression that represents the amount of ore sold and how much ore can the mine sell after extracting ore for 12 hours is option B: The expression is 2t−14t. The amount of ore is 21 metric tons.

The reasoning for the selection of the expression and amount of ore can the mine sell after extracting ore for 12 hours  is as follows.

1: Determine the amount of coal used for electricity generation in terms of t.

The mine uses 14 tons of coal every hour, so the total amount used for electricity generation is 14t.

2: Determine the total amount of coal extracted in terms of t.

The mine extracts 2 tons of coal every hour, so the total amount extracted is 2t.

3: Calculate the amount of coal sold in terms of t.

To find the amount of coal sold, subtract the amount used for electricity generation from the total amount extracted: 2t - 14t.

4: Determine the amount of coal sold after 12 hours.

Substitute t = 12 into the expression:

2(12) - 14(12) = 24 - 168 = -144.

However, since the mine uses 14 tons of the extracted coal every hour, it cannot sell more coal than it extracts. So, the correct expression should be 2t - 14 (without the t for the amount used for electricity generation).

5: Calculate the amount of coal sold after 12 hours using the corrected expression.

Substitute t = 12 into the expression: 2(12) - 14 = 24 - 14 = 10 metric tons.

The correct expression should be 2t - 14, and the amount of coal the mine can sell after extracting coal for 12 hours is 10 metric tons. Hence, the correct answer is option B.

Note: The question is incomplete. The complete question probably is: A mine extracts 2 metric tons of coal in an hour. The mine uses 14 ton of the extracted coal every hour to generate electricity for the mine and sells the rest. If t is the number of hours spent mining, which expression represents the amount of ore sold? How much ore can the mine sell after extracting ore for 12 hours? A) The expression is 2t−1/4t. The amount of ore is 23 3/4 metric tons. B) The expression is 2t−1/4t. The amount of ore is 21 metric tons. C) The expression is 2t+1/4t. The amount of ore is 24 metric tons. D) The expression is 2t+1/4t. The amount of ore is 24 1/4 metric tons.

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Answer: The amount of money you would have in 5 years if you could save your entire salary with a 1.2% increase every year would be $87,357.41.

Explanation:

The initial term, a₁, is $74,000, and the common ratio, r, is 1 + 1.2% = 1.012. To find the sum of the first 5 terms, we use the formula for a finite geometric series:

S₅ = a₁(1 - r⁶)/(1 - r)

Plugging in the values, we get:

S₅ = $74,000(1 - 1.012⁵)/(1 - 1.012) = $87,357.41 (rounded to the nearest cent)

Therefore, if you save your entire salary, you would have approximately $87,357.41 in 5 years with a 1.2% increase every year.

Note that the first coordinate of M is -1. (Option D)

Given :- coordinates of F = (-4,-2) = (x1,y1)

coordinates  of G = (2,-2) = (x2,y2)

coordinates of P = (2,-8) = (x3,y3)

and distance between point M and P is half of the distance between FG

To find :- first coordinate of point M

solution :- let the coordinate of M be (x4,y4)

as we know that distance between of the opposite point of parallel line segments are equal

so, second coordinate of M = -8

now by distance formula

FG = √(x2-x1)² + (y2-y1²)

= √[2-(-4)]² + [-2-(-2)]²

= √(2+4)² + (2-2)²

= √(6)² + (0)²

=√36

F G = 6

so, distance between point M and P = 1/2 × F G

= 1/2 × 6

= 3units

again, by distance formula

MP = √(x3-x⁴)² + (y3-y4)²

3 = √(2-x⁴)² + [-8-(-8)]²

squaring on both side

(3)² = (√(2-x⁴)² + [-8-(-8)]²)²

9 = (2-x⁴)² + [-8-(-8)]²

9 = (2-x⁴)²+(0)²

9 = (2-x⁴)²

√9 = 2-x⁴

3 = 2-x⁴

x⁴ = 2-3

x⁴ = -1

Hence the first coordinate of M is -1

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Full Question:

Although part of your question is missing, you might be referring to this full question:

Point M is located in the third quadrant.

The distance between point M and point P is half the distance between point F and point G.

• Segment MP is parallel to segment FG. What is the first coordinate of point M?

(Explanation below)

x=2

x = 2 is the solution of the equation

Two or more expressions with an Equal sign is called as Equation.

The given equation is [tex](3X-5)^(^1^/^4^) + 3 = 4[/tex]

We have to find the value of x

Subtracting 3 from both sides:

[tex](3X-5)^(^1^/^4^) = 1[/tex]

Raising both sides to the fourth power:

3X - 5 = 1^4

3X - 5 = 1

Adding 5 to both sides:

3X = 6

Dividing by 3:

X = 2

Therefore, x = 2 is the solution of the equation

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The value of (7 4/9 -8)*3.6-1.6*(1/3-3/4)+ 1 2/5 ÷(0.35) is given as 241/54.

(7 4/9 -8) = -5/9.

3.6-1.6 = 2.0

1/3-3/4 = 1/3 - 3/4

= 4/12 - 9/12

= -5/12

we will have -5/9 *  2 = -10/9.

-10/9 *  -5/12

10/9 * -5/12 = (10 * 5) / (9 * 12) = 50/108

We can simplify this fraction by dividing both the numerator and denominator by their greatest common factor, which is 2:

50/108 = 25/54

we will have

25/54 + 1 2/5 ÷(0.35)

1 2/5 ÷ 0.35 = (7/5) ÷ (35/100) = (7/5) * (100/35) = 4

Now, we can substitute this value into the expression:

25/54 + 4 = (25/54) + (216/54) = 241/54

Therefore, the value of the expression 25/54 + 1 2/5 ÷(0.35) is 241/54.

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To show that Maria's claim is incorrect, we need to find a fraction that is located between 1/5 and 1/7 on a number line but does not have a denominator of 6.

One way to do this is to find the least common multiple (LCM) of 5 and 7, which is 35, and then find a fraction with a denominator of 35 that falls between 1/5 and 1/7.

To do this, we can find the equivalent fractions of 1/5 and 1/7 with a denominator of 35:

1/5 = 7/35

1/7 = 5/35

Now we need to find a fraction between 7/35 and 5/35. One such fraction is:

6/35

This fraction is located between 7/35 and 5/35 on the number line, but its denominator is 35, not 6. Therefore, Maria's claim is incorrect.

Another way to show that Maria's claim is incorrect is to find a counterexample by simply listing all the fractions between 1/5 and 1/7 and showing that not all of them have a denominator of 6. For example:

1/6, 1/7, 1/8, 1/9, 1/10, ..., 1/34, 1/35

As we can see, not all of these fractions have a denominator of 6, so Maria's claim is incorrect.

Answer:

13/70

Step-by-step explanation:

In order to  show that Maria's claim is incorrect, we need to find a fraction that is located between 1/5 and 1/7 on a number line,  but does not have a denominator of 6.

Let's  find the  common multiple (CM) of 5 and 7, which is 70, or 35. But this case try 70  and then find a fraction with a denominator of 70 that falls between 1/5 and 1/7.

equivalent fractions of 1/5 and 1/7 with a denominator of 70
1/7 < x < 1/5 , will be equivalent to 1/7 ( 10/10 ) < x < 1/5 ( (14/14)
10/70 < x < 14/70..
x is the fraction   between 10/70  and 14 /70.  Unknown  fraction is:

13/70

This fraction is located between 10/70  and 14/70  on the number line, but its denominator is 70 , not 6. Therefore, Maria's claim is incorrect.

If Ofra tried to solve an equation 3x = 4.5, The statement "Ofra correctly solved the equation" is correct. So, correct option is C.

We can see this by substituting x = 1.5 into the original equation 3x = 4.5:

3(1.5) = 4.5

Simplifying the left-hand side, we get:

4.5 = 4.5

This is a true statement, which means that x = 1.5 is a valid solution to the equation 3x = 4.5.

Therefore, Ofra did not make any mistakes in solving the equation. She correctly set up the equation 3x = 4.5 by multiplying both sides by 3 to isolate x, and then calculated the value of x to be 1.5, which is the correct solution.

Option (c) is the correct answer.

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Complete question is:

Ofra tried to solve an equation.

3x = 4.5, Setting up x = 1.5 Calculating

Where did Ofra make her first mistake?

Choose 1 answer:

a) Setting up

b)  Calculating

c) Ofra correctly solved the equation.

The statement on finding the areas of a trapezoid and a kite are True.

To determine the area of a trapezoid, it can be broken down into separate geometrical shapes. One possible breakdown would include a rectangle with two adjacent right triangles or an isosceles triangle with one right triangle configuration. By calculating each smaller compartment's size and summing them together, one can obtain the total area for the trapezoid.

Similarly, in order to find the surface area of a kite shape, drawing a diagonal creates two adjoining triangles that are easily computed individually then summed.

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Options for this question :
True

False

Answer:

18 cent

Step-by-step explanation: