what is the expanded notation of -6⁷​

The other value of x where g(x) = 15 is 16 in the absolute value function

Since the vertex of the absolute value function is at (10,0), the equation for the function can be written as:

g(x) = a|x - 10|

To find the value of a, we can use the fact that the function passes through the point (4,15):

15 = a|4 - 10|

15 = 6a

a = 2.5

So the equation for the absolute value function is:

g(x) = 2.5|x - 10|

To find another value of x where g(x) = 15, we can set the equation equal to 15 and solve for x:

2.5|x - 10| = 15

|x - 10| = 6

x - 10 = 6 or x - 10 = -6

x = 16 or x = 4

Therefore, there are two possible values of x where g(x) = 15: x = 16 and x = 4.

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Answer: 27.33

Step-by-step explanation: If you use a calculator to do the hard stuff the rest is a breeze

The distance between the two junctions is, 90 meters, when rounded off to the nearest meter.

:: Radius of trundle wheel = 30 cm = 0.3 meter (as 100 cm = 1 m)

:: No. of rotations = 48

:: Circumference of a circle = ( 2 x π x r )

where, r is radius of the circle

So, as,

Distance between junctions = [ (circumference of trundle wheel) x (no. of rotations) ]

Therefore,

Distance = (2 x π x 0.3) x (48)

Distance = 2 x (3.14) x 0.3 x 48

Distance = 90.432 meters

When rounded off to the nearest meter,

Distance = 90 meters.

So, The distance between the two junctions is, 90 meters, when rounded off to the nearest meter.

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The decimal used to figure the price of their clothing is 2.1

The improvement in Larry's test score written as a decimal is 1.52

Markup = 210%

= 210/100

= 21/10

= 2.1

Larry's increased test score percentage = 152%

= 152/100

= 1.52

In conclusion, the price of clothing and Larry's test score in decimals is 2.1 and 1.52 respectively.

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In the quadratic formula, the number for "a" is filled in with the coefficient of x².

In Mathematics and Geometry, a quadratic equation can be defined as a mathematical expression that can be used to define and represent the relationship that exists between two or more variable on a graph.

In Mathematics, the standard form of a quadratic equation is represented by the following equation;

ax² + bx + c = 0

Mathematically, the quadratic formula is represented by this mathematical equation:

[tex]x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}[/tex]

For instance, given the quadratic equation 2x² - 3x - 1 = 0, we have:

a = 2

b = -3

c = -1

[tex]x = \frac{-(-3)\; \pm \;\sqrt{(-3)^2 - 4(2)(-1)}}{2(2)}\\\\x = \frac{3\; \pm \;\sqrt{9 + 8}}{4}\\\\x = \frac{3\; \pm \;\sqrt{17}}{4}[/tex]

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Answer:

$30.25

Step-by-step explanation:

55% of 55$ is $30.25. she wants 45 % off of 55$. which is $24.75. 55-24.75 is 30.25

$30.25

since it's 45% off, you need to subtract 45% from 100%

100%-45%=55%

then turn the % into a decimal

55%/100=0.55

now multiply the original price by 0.55

0.55*55=30.25

Answer:

Step-by-step explanation: 0+0=0

Answer:

0

Step-by-step explanation:

0+0= nothing that why.

To solve the problem, we need to find Julian's average speed, given that he started biking from a position behind the simulated biker at a speed of 20 km/h, and after 15 minutes, his position was reported as -214 km.

We can use the formula for average speed:

Average speed = total distance / total time

To find the total distance, we need to calculate the displacement of Julian from the initial position of -d (where d is the distance between Julian and the simulated biker when he started biking) to the position of -214 km after 15 minutes.

Displacement = final position - initial position

Displacement = (-214 km) - (-d) = d - 214 km

The total distance covered by Julian is equal to the absolute value of the displacement, since the direction of the motion does not matter when computing distance.

Total distance = |d - 214 km|

To find the total time, we need to convert 15 minutes to hours:

Total time = 15 minutes / 60 minutes/hour = 0.25 hours

Now we can substitute the values into the formula for average speed:

Average speed = total distance / total time

Average speed = |d - 214 km| / 0.25 hours

Since Julian was traveling at a constant speed of 20 km/h, we can also express the distance in terms of time:

Average speed = (20 km/h) x t / 0.25 hours

where t is the time Julian biked in hours.

Setting the two expressions for average speed equal to each other, we can solve for t:

|d - 214 km| / 0.25 hours = (20 km/h) x t / 0.25 hours

|d - 214 km| = 20 km/h x t

Solving for t:

t = |d - 214 km| / 20 km/h

Now we can substitute this expression for t into either expression for average speed:

Average speed = (20 km/h) x t / 0.25 hours

Average speed = |d - 214 km| / 0.25 hours

Substituting the expression for t:

Average speed = |d - 214 km| x 4 / |d - 214 km|

Simplifying:

Average speed = 80 km/h

Therefore, Julian's average speed so far has been 80 km/h.

The missing parameters of the regular polygons are listed below:

Case 1: θ = 45°, a = 10.864 cm

Case 2: θ = 72°, s = 5.812 cm

In this problem we must determine missing parameters of regular polygons, that is, polygons with sides of equal length. All parameters are summarized below:

Central angle

θ = 360 / n

Relationship between apothema and side length

a = s / [2 · tan (180 / n)]

Where:

Now we proceed to find missing parameters:

Case 1: s = 9 cm, n = 8

θ = 360 / 8

θ = 45°

a = (9 cm) / [2 · tan (180 / 8)]

a = 10.864 cm

Case 2: a = 8 cm, n = 5

θ = 360 / 5

θ = 72°

s = 2 · a · tan (180 / n)

s = 2 · (8 cm) · tan (180 / 5)

s = 5.812 cm

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After 4 years, the investment of $700 at 4% compounded daily results in a future value of $821.45.

The future value represents the present value or investment compounded at an interest rate periodically for a certain number of years.

The future value can be determined using the FV formula or an online finance calculator.

N (# of periods) = 1,460 days (4 years x 365)

I/Y (Interest per year) = 4%

PV (Present Value) = $700

PMT (Periodic Payment) = $0

Results:

Future Value (FV) = $821.45

Total Interest = $121.45

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Answer:

(x-3)(x+4)

Step-by-step explanation:

This way is how it s done in Greece. If u don't understand don't read the explanation Δ=β2-4αγ=81-32=49

χ1,2=-1+-7^2=3

=-4

Therefore, the slope of line s is equal to (d + b) / (a - c).

In mathematics, the slope is a measure of the steepness of a line. It is defined as the ratio of the vertical change (rise) between two points on the line to the horizontal change (run) between those same two points. In other words, the slope is the change in the y-coordinate divided by the change in the x-coordinate. If the slope is positive, the line is increasing from left to right and has an upward direction. If the slope is negative, the line is decreasing from left to right and has a downward direction. If the slope is zero, the line is horizontal. If the slope is undefined, the line is vertical. The concept of slope is important in various fields of mathematics, science, and engineering, as it helps to describe the relationship between two variables and make predictions based on that relationship. It is also used in calculus to find the rate of change of a function, and in geometry to find the equation of a line or the angle between two lines.

Here,

Since line s is parallel to line t, it has the same slope as line t. The slope of a line passing through two points (x₁, y₁) and (x₂, y₂) can be calculated using the formula:

slope = (y₂ - y₁) / (x₂ - x₁)

In this case, the points on line t are (a, -b) and (-c, d), so the slope of line t is:

slope of t = (d - (-b)) / (-c - a)

slope of t = (d + b) / (a - c)

Since line s is parallel to line t, it has the same slope as line t:

slope of s = (d + b) / (a - c)

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Answer: y = -|x + 1| + 1

Step-by-step explanation:

This is a "V" shaped graph, so we know it uses the absolute value function. This is the parent function:

    y = |x|

This represents the possible transformations:

➜ a is amplitude

➜ h is horizontal shift

➜ k is vertical shift

    f(x) = a | x - h | + k

Next, we see it is shifted one unit upwards.

    y = |x| + 1

Then, we see it is also shifted one unit left.

➜ Note that this shift is -h units, so we will use positive for moving left.

    y = |x + 1| + 1

Lastly, we see this graph is flipped and has a negative slope, or amplitude.

    y = -|x + 1| + 1

Based on the information, we identified that the scale used in the construction is approximately 1:35.2.

To find the scale used in the construction of the Crazy Horse Monument, we need to divide the height of the actual monument by the height of the model. Let's use the following formula to calculate the scale:

The height of the actual monument is 563 feet and the height of the scale model is 16 feet. Substituting these values in the formula, we get:

Simplifying the fraction, we get:

Therefore, the scale used in the construction of the Crazy Horse Monument is approximately 1:35.2.

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If cos(x) = -5/6, and x lies in quadrant"II", then exact values are:

sin(2x) = (-5√11)/(18);

cos(2x) = 7/18;

tan (2x) = -5√11/7.

We know that, Cos(x) = -5/6 and "x" is in quadrant II, so, we can use the Pythagorean identity to find sin(x):

sin(x) = √(1 - cos²(x)) = √(1 - (-5/6)²) = √(1 - 25/36) = √(11/36) = √11/6

Using the double angle trigonometry identities for sine and cosine, we find sin(2x) and cos(2x):

Substituting the value of Sin(x) and Cos(x),

We get,

sin(2x) = 2sin(x)cos(x) = 2(√11/6)(-5/6) = (-5√11)/(18);

cos(2x) = cos²(x) - sin²(x) = (-5/6)² - (11/6) = 25/36 - 11/36 = 14/36 = 7/18;

Finally, we find tan(2x) by using the identity:

tan(2x) = sin(2x)/cos(2x) = (-5√11/18) / (7/18) = -5√11/7.

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A)  The continuous rate of growth of this bacterium population = 0.35

B) The initial population of the culture = 920

C) The number of bacteria at time t=5 are 5294

Here, the function [tex]n(t)=920\times e^{(0.35\times t)}[/tex] represents the number of bacteria in a culture at time t

A) We know that in exponential function f(x) = [tex]ae^{kx}[/tex], k is the rate of growth

Here, in this function n(t) = [tex]920\times e^{(0.35\times t)}[/tex],  the continuous rate of growth is 0.35

B) To find the initial population of the culture

Substitute t = 0, in n(t)

n(0) = [tex]920\times e^{(0.35 \times 0 )}[/tex]

n(0) = 920 × e⁰

n(0) = 920

This is the initial population.

C) Now we find the number of bacteria at time t=5

[tex]n(t)=920\times e^{(0.35\times t)}[/tex]

Substitute t = 5 in above equation.

n(5) =[tex]920 \times e^{(0.35 \times 5)}[/tex]

n(5) = 5294.23

n(5) ≈ 5294

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The number of bacteria in a culture is given by the function

n(t) =920e^0.35t Where t is measured in hours

A) what is the continuous rate of growth of this bacterium population? Your answer is __ percent

B) what is the initial population of the culture (at t=0) your answer is __

C) how many bacteria will the culture contain at time t=5 ? Your answer is __ Round to the nearest bacteria

Answer:

15h-6k+12m

Step-by-step explanation:

The perimeter of the triangle is the sum of all of its side lengths

P=a+b+c

If a=5h-4k

b=10h+7m

c=5m-2k

Then the formula would be

P=(5h-4k)+(10h+7m)+(5m-2k)

P=15h-6k+12m

Hope this helps!

There were 64 players at the start of the tournament.

To determine the number of players at the start of the tournament

We need to work backwards from the final round to the first round.

In the final round, there will be only two players remaining since the winner of that match will be declared the overall champion.

In the penultimate (fifth) round, there will be four players remaining.

These four players must have come from the previous round, where there were eight players.

Continuing this pattern, in the fourth round, there will be eight players, and in the third round, there will be 16 players.

In the second round, there will be 32 players, and in the first (initial) round, there will be 64 players.

Therefore, there were 64 players at the start of the tournament.

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The scale factor between a square of dimensions 7 by 7 and a scaled copy of dimensions 21/2 by 21/2 is 3/2 or 1.5.

We know that the dimensions of the square on the left are 7 by 7, and the dimensions of the square on the right are 21/2 by 21/2.

To find the scale factor, we can divide the dimensions of the square on the right by the dimensions of the square on the left

scale factor = (21/2) / 7

We can simplify this fraction by dividing both the numerator and the denominator by the greatest common factor, which is 7

scale factor = (21/2) / 7 = (21/2) * (1/7) = 3/2

Therefore, the scale factor is 3/2, or 1.5.

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Answer:

Step-by-step explanation:  find the circumference and then consider the shape (circle) after that get rid of options that don't make sense like 7.3 and 7.1, 8 for the radius might be too big leaving you with    7     (use a calculator if needed)

Answer:

To write the Hindu-Arabic numeral 872 as a Babylonian numeral using the symbols I and <, we need to break it down into its place values:

The digit 8 is in the hundreds place.

The digit 7 is in the tens place.

The digit 2 is in the ones place.

To represent 800 in the hundreds place, we use 8 symbols <. To represent 70 in the tens place, we use 7 symbols < followed by 1 symbol I. To represent 2 in the ones place, we use 2 symbols I.

Putting these symbols together, we get the Babylonian numeral:

<<<<< <<<< <<<< <<<< IIII

So, the Babylonian numeral equivalent of the Hindu-Arabic numeral 872 is <<<<< <<<< <<<< <<<< IIII.

Answer:

Step-by-step explanation:

Typically you see f(x)=something like you do up in the original equation.

that is your function/graph.

a) f(0)  means plug in 0 for x

   f(0) =  (-0)³-0²-0+13

   f(0) = 13

b)  f(2) =(-2)³-2²-2+13          >simplify the exponenents first

                                               (-2)³ = (-2)(-2)(-2)= -8

    f(2) = -8-4-2+13               >simplify work from left to right

    f(2) = -12-2+13

    f(2) = -14+13

    f(2) = -1

c)  f(-2) = [-(-2)]³-(-2)²-(-2)+13              >multiply - and -  for  (-(-2))³

    f(-2) = (2)³-(-2)²-(-2)+13                  >simplify exponents

    f(-2) = 8-4-(-2)+13          

    f(-2) = 4-(-2)+13

    f(-2) = 6+13

    f(-2) = 18

d)  means add f(1) and f(-1)

f(1) +f(-1) = (-1)³-1²-1+13 +[-(-1)]³-(-1)²-(-1)+13  

f(1) +f(-1) = -1-1-1+13 +[1]³-1-(-1)+13

f(1) +f(-1) = -1-1-1+13 +1-1+1+13            

f(1) +f(-1) = -2-1+13 +1-1+1+13

f(1) +f(-1) = -3 +13 +1-1+1+13

f(1) +f(-1) = 10+1-1+1+13

f(1) +f(-1) = 11 -1+1+13

f(1) +f(-1) = 10 +1 +13

f(1) +f(-1) = 24

The integral for this problem has the result given as follows:

[tex]\int_2^5 -8f(x) dx = 168[/tex]

The integral over the largest region for this problem is given as follows:

[tex]\int_2^9 f(x) dx = -14[/tex]

The integral can be divided into two smaller regions, as follows:

[tex]\int_2^9 f(x) dx = \int_2^5 f(x) dx + \int_5^9 f(x) dx[/tex]

Hence the integral from x = 5 to x = 9 is given as follows:

[tex]-14 = \int_2^5 f(x) dx + 7[/tex]

[tex]\int_2^5 f(x) dx = -21[/tex]

Multiplying -21 by -8, the result of the integral is given as follows:

[tex]\int_2^5 -8f(x) dx = 168[/tex]

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If population of rabbits is increasing at a rate of 1.5% per month, after 10 months, there will be approximately 71 rabbits in the population.

To solve this problem, we need to use the formula for exponential growth:

A = P(1 + r)ᵗ

where A is the final amount, P is the initial amount, r is the growth rate as a decimal, and t is the time period. In this case, we have P = 60, r = 0.015 (1.5% expressed as a decimal), and t = 10.

Plugging these values into the formula, we get:

A = 60(1 + 0.015)¹⁰

A ≈ 71

t's important to round to the nearest whole, so we can't be exact, but we know the answer will be somewhere between 70 and 72 rabbits.

Exponential growth is a model that assumes continuous growth over time, which may not be entirely accurate in real-world scenarios.

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Thus, the value of x for the given set of adjacent angles is found as: x = 16 and m∠QSR = 38.

If two angles share a side and a vertex, they are said to be neighbouring in geometry. In other words, neighbouring angles do not overlap and are placed next to one another immediately.

Given data:

From the figure:

m∠RST  = m∠QST + m∠QSR

Put the values

70 = 2x + 3x - 10

5x = 80

x = 16

Thus,

m∠QSR = 3x - 10  = 3(16) - 10

m∠QSR = 38

Thus, the value of x for the given set of adjacent angles is found as: x = 16 and m∠QSR = 38.

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Complete question:

If m∠RST = 70, m∠QST = 2x, and m∠QSR = 3x - 10, what is the m∠QSR?.

The figure is attached:

16

48

32

38

The matrix operation add -4(row 1) to row 3 is[tex]\left[\begin{array}{ccc | c}1&2&1 & -5\\0&4&-2 & 3\\0&-9&2&12\end{array}\right][/tex]

From the question, we have the following parameters that can be used in our computation:

[tex]\left[\begin{array}{ccc | c}1&2&1 & -5\\0&4&-2 & 3\\4&-1&6&-8\end{array}\right][/tex]

From the question, we understand that

We are to add -4(row 1) to row 3

This means that

row 3 = row 3 - 4 * row 1

When these values are evaluated, we have

4: 4 - 4 * 1 = 0

-1: -1 - 4 * 2 = -9

6: 6 - 4 * 1 = 2

-8: -8 - 4 * -5 = 12

This means that we relace 4, -1, 6, and -8 in row 3 with 0, -9, 2 and 12

Using the above as a guide, we have the following:

[tex]\left[\begin{array}{ccc | c}1&2&1 & -5\\0&4&-2 & 3\\0&-9&2&12\end{array}\right][/tex]

Hence, the result of the matrix expression is [tex]\left[\begin{array}{ccc | c}1&2&1 & -5\\0&4&-2 & 3\\0&-9&2&12\end{array}\right][/tex]

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In a case whereby Michelle has 3 kg of strawberries that she divided equally into small bags with 1/5 kg in each bag  the number of bags of strawberries she make is 15bags of strawberries.

We should note that 1kg = 1000g

3kg = 1000g

Since each of the bag is  1/5 kg = 1000/5 g = 200g

The needed bag will now be =3000/200= 15

Therefore, we can see that she made 15bags of strawberries the conversion were made so that it can be calculated easily since ythe kg are very small.

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Answer:

Four units left and one unit up

Step-by-step explanation:

Since we're subtracting from x, the figure is going to go toward the left side of the coordinate plane, and since we're adding to y, the figure is going to go up.

Answer: 189 m^2

Step-by-step explanation:

Area = (Diagonal 1 x Diagonal 2) ÷ 2

Answer:

15.04 (3.s.f)

Step-by-step explanation:

Cos a = adjacent/ hypotenuse

Cos 43 = 11/ x

so,

x= 11 / cos 43

= 15.04