Explanation:
This intense stretching method uses bouncing movements to push your body beyond its normal range of motion. Whereas static stretches are performed slowly and gradually, the ballistic method stretches muscles much farther and faster. You can do many of the same stretches as ballistic or static stretches.
how to say hi in french
Explanation:
Bonjour
it is hi or hello you can also say the name after
Example:Bonjour(say the name of the person you want to greet)
Answer:
Bonjour
Explanation:
Its just bonjour, you could always expand and say more then just Hi though.
Inducing magnetic properties on a substance means you are
aligning the electrons to spin in the opposite direction
aligning the electrons to spin in the same direction
pairing up electrons to spin together
separating electrons to move freely in the substance
Inducing magnetic properties on a substance means you are aligning the electrons to spin in the same direction, 2nd option.
How are magnetic properties induced?The magnetic intensity is the magnetic field produced solely by the electric current flowing in a solenoid. The magnetic property of a material is induced by an external magnetic field. When a material is exposed to an external magnetic field, it becomes magnetized.
A strong magnetic field is produced when the majority of electrons in an atom spin in the same direction. The magnetic field's direction is determined by the direction of electron spin.
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when a falling firecracker explodes, the momenta of its pieces _______.
when a falling firecracker explodes, the momenta of its pieces vectorially add up to equal the initial momentum of the firecracker.
When the firecracker bursts, the vector sum of the momenta of its fragments adds up to the firecracker’s momentum just before bursting.
A falling firecracker explodes into two pieces. The momenta of the fragments combine by vector rules to equal the original momentum of the falling firecracker. Momentum is equal to mass multiplied by velocity.
According to the conservation of momentum, the initial momentum of the system is equal to the final momentum. The condition for the validity of momentum conservation is that no external force should exert on the system.
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Which organism is a producer
Answer:
Producers are organisms that create food from inorganic matter. The best examples of producers are plants, lichens and algae, which convert water, sunlight and carbon dioxide into carbohydrates. Consumers are organisms that cannot create their food.
A 20.0 N force is applied at an angle of 40.0 degrees above the horizontal to a 4.00 kg box. The box moves a horizontal distance of 4.00 meters. Friction is negligible. The work done by the 20.0 N force is
a. 61.3 J.
b. 46.3 J.
c. 50.1 J.
d. 75.0 J.
Answer:
The work done by the 20 N force is 61.3 J
Explanation:
20 N Force at horizon is: F=20 N*cos 40=15.32 N
The work done by 20 N at horizon is: W=F*S=15.32 N* 4 m=61.3 J
Answer:
The work done by the 20 N force is 61.3 J
Explanation:
1. A force of 60 Newtons is applied to the end of a wrench 0. 12 m long. How much torque is produced?
Answer: The amount of Torque produced is 7.2 Nm.
Explanation:
Given:
Force applied (F) to the end of a wrench = 60 Newton
Length of wrench = 0.12 meter
To find:
Quantity of Torque produced
Solution:
The quantity of Torque produced can be calculated from the following formula:
Ƭ = r F sin(θ)
Where,
Ƭ = Torque, r = radius, F = Force, (θ) = angle between F and the lever arm
In the given question,
r = 0.12,
F= 60,
(θ)= 900 {Since the force is applied at the end of a wrench, it must be perpendicular}
Torque (Ƭ) = 0.12* 60 * sin 900
= 7.2 m {sin 900 = 1}
Hence, in the given situation, 7.2 Nm Torque will be produced.
A 120 Kg man is diving off a 40 meter cliff. What is his kinetic energy when he is 10 meters from the water?
The required kinetic energy of man diving out at 10 m from water is calculated to be 35.3 kJ.
Given that,
Mass of the man m = 120 kg
Height of the cliff H = 40 m
Distance from the water surface h' = 10 m
The mathematical equation of velocity efflux is
v = √( 2g ( H - h') = √( 2 × 9.8(40-10) = 24.25 m/s
The expression for kinetic energy of the man = 1/2 m v²
K.E = 1/2 m v² = 1/2 × 120 × 24.25² = 35283.75 J = 35.3 kJ
Thus, we can conclude that the kinetic energy of man diving out at 10 m from water is 35.3 kJ.
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How long will it take for a body
accelerating by 2 m/s² to gain a
velocity of 10 m/s, starting from rest.
We are given:
Initial velocity (u) = 0 m/s [starting from rest]
Final velocity (v) = 10 m/s
Acceleration (a) = 2 m/s²
Time taken = t
Solving for time taken:
v = u + at [first equation of motion]
10 = 0 + (2)(t) [plugging the values]
10 = 2t
t = 5 seconds
The hanging mass is referred to as M and it sets the centripetal force.
True
False
Answer:
False
Explanation:
The centripetal force is the force that points towards the center and is responsible for keeping an object in a curved path. This force is provided by the tension in the string, not the mass of the object.
The height of an object is 10 cm, and the height of its image is 6 cm. What is the magnification?
Question 23 options:
4
16
0.6
1.67
magnification = [tex]\bf\dfrac{height of image}{height of object}[/tex]
= [tex]\bf\dfrac{6cm}{10cm}[/tex]
= 0.6
An elaborate pulley consists of four identical balls at the ends of spokes extending out from a rotating drum. A box is connected to a light, thin rope wound around the rim of the drum. When it is released from rest, the box acquires a speed V after having fallen a distance d. Now the four balls are moved inward closer to the drum, and the box is again released from rest. After it has fallen a distance d, will its speed be equal to V, greater than V, or less than V? Show or explain why.
Answer:
its speed will be less than V
Explanation:
When the ball falls a distance d, its final kinetic energy plus rotational kinetic energy of the drum equals its initial potential energy.
K = U
With its speed V at the end of d, we have
1/2mV² + 1/2Iω² = mgd where I = rotational inertia of drum and balls, ω = angular speed of drum and balls and m = mass of box
1/2mV² + 1/2Iω² = mgd
1/2mV² = mgd - 1/2Iω²
V² = [2(mgd - 1/2Iω²)/m]
V = √[2(mgd - 1/2Iω²)/m]
When the four balls are moved inward closer to the drum, their rotational inertia increases and also its angular speed which thus causes an increase in rotational kinetic energy. But, since the box still falls the same distance of d, its final kinetic energy plus rotational kinetic energy of the drum plus balls still equals its initial potential energy
K = U
I' = new rotational inertia of drum and balls, ω' = new angular speed of drum and balls
With its new speed is now V' at the end of d,
1/2mV'² + 1/2I'ω'² = mgd
1/2mV'² = mgd - 1/2I'ω'²
V² = [2(mgd - 1/2I'ω'²)/m]
V' = √[2(mgd - 1/2I'ω'²)/m]
Since I' and ω' increase, the rotational kinetic energy of the drum and balls (1/2I'ω'²) increases. Thus, the difference (mgd - 1/2I'ω'²) < (mgd - 1/2Iω²) which implies that the kinetic energy of the box decreases. Hence, since its kinetic energy decreases, its speed V' also decreases.
So, V' < V
So, its speed will be less than V.
if the bat and softball are in contact for 0.80m/s, what is the average force that the bat exerts on the ball
The changes in the momentum of the ball and the time over which that change occurs. The formula for average force is: average force = change in momentum/time.
Calculation-Given: The ball's mass is 0.144 kilogram.
speed v = 38 m/s, shift in momentum presently
P = m v- ( - mv) ( - mv)= 2 mv
=2 x (0.144) x (38) (38)
= 10.944 kg-m/s
t Impulse J=F.
The impulse is equivalent to the change in momentum.
J = 10.944 kg-m/s
What forces are at play when a baseball bat strikes a fastball?Think about how a baseball bat and a ball interact, for instance. The bat forces the ball to the right while the baseball forces the bat to the left. The action-reaction force pair is made up of these two forces acting on two different objects combined.
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Pitch a baseball horizontally at 38.0 m/s weighing 0.144 kg. The baseball moves in the opposite direction and at the same speed after being struck by the bat. What is the ball's change in momentum? What kind of impetus does the bat deliver? What was the average force the bat applied to the ball during the 0.80 milliseconds that they were in contact?
Bill weighs 160 lb. He is standing on a scale inside an elevator. What is the reading on the scale if the elevator is accelerating downward
the scale's readout if indeed the elevator is decelerating faster than 160 lb .
The elevator speeds up or down, right?Your perceived weight is equal to the normal force.Therefore, whenever the elevator accelerates or upwards downward, you truly feel tiny bit heavier than normal and a little lighter than usual.
If an elevator malfunctions, should you lay down?Any jump you make would only slow the lift's descent to the ground by a very small amount.Even though you could jump perfectly timed and with all the force your legs could produce, it would be pointless.Your greatest option, as opposed to jumping, is to fold down.
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A 600 g steel block rotates on a steel table (μk = 0.6) while attached to a 1.0 m long hollow tube. Compressed air fed through the tube and ejected from a nozzle on the back of the block exerts a thrust force of 4.2 N perpendicular to the tube. The maximum tension the tube can withstand without breaking is 50 N. If the block starts from rest, how many revolutions does it make before the tube breaks?
If the block starts from rest, then revolutions that it make before the tube breaks is 0.947 rotations.
What is meant by revolution?When object turns around an internal axis, it is called a rotation. When object circles an external axis, it is called revolution.
Given mass of block = 600 g = 0.6 kg ; Radius of rotation = 1.0 m-long
Given thrust force of 4.2 N
The maximum tension is 50 N.
As thrust is perpendicular to the tube. So, tangential component of the thrust force is Ft=4.2 N and radial component Fr=0
As we know, α = F/m r
= 4.2/0.6 * 1
α = 7 rad/s²
As, m r ω²= 50 N
ω² = 50/ 0.6 * 1.0
ω = 9.128 rad/s
Ф = ω² - ω0²/2α
= (9.128² - 0)/2 * 7
Ф = 5.951 rad
As 1 Radians = 0.1592 Rotations,
5.951 rad = 0.947 rotations.
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1. Identify Which of the following is not a factor of global climate change:
a. slight changes in Earth’s tilt
b. movement of continents
c. reversing of the magnetic poles
d. increase or decrease of solar energy
Answer:
B.movement of continents
Please help I have to turn it in tomorrow
Answer:
i think the answer is a
Explanation:
hope i am right
At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 3.0 m/s, and an 83-kg person feels a 545-N force pressing against his back. What is the radius of a chamber
When the outer wall moves at a speed of 3.0 m/s, and an 83-kg person feels a 545-N force pressing against his back then the radius of a chamber is 8.5 meters.
The radius of the chamber can be calculated using the equation
F = mv²/r, where F is the force felt by the person, m is the mass of the person, v is the velocity of the chamber and r is the radius of the chamber. In this case, F is 545 N, m is 83 kg, and v is 3.0 m/s.
Plugging in these values, we get
r= mv²/F
r= 83×3²/545
r = 8.5 m.
Therefore, the radius of the chamber is 8.5 m.
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A system that has a total change in entropy of 675 J/K and has received 243 J of heat energy will be at what temperature?
The required temperature of the system which has a certain entropy change and receives heat energy is 273.36 °C.
Given that,
The change in entropy of the system = 675 J/K
Heat energy = 243 J
Temperature of the system = ?
The temperature of the system is calculated below.
ΔS = ΔH/T
where,
ΔH is the heat energy
ΔS is the change in entropy of the system
T = ΔH/ΔS = 243/675 = 0.36 K
By converting temperature in kelvin to temperature in degrees centigrade, we get,
T = 273 + 0.36 = 273.36 °C
Thus, temperature of the system which has a certain entropy change and receives heat energy is 273.36 °C.
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3. Calculate the force of gravity that Saturn (mass = 5. 7 x 1026 kg) exerts
on a woman on Earth (mass = 61 kg) when Saturn is closest to Earth,
1. 2 x 10° km.
The force of gravity that Saturn (mass = 5. 7 x 1026 kg) exerts on a woman on Earth (mass = 61 kg) when Saturn is closest to Earth = 1. 2 x 10° km.
Explanation of the given answer:Formula used in step two. F = G m 1 m 2 r 2. Step 3: Determine the gravitational force.
Calculating the gravitational force is step three. F = 6.7 10 11 by changing the values in the formula above. 2 × 10 30 × 6 × 10 24 1 .5 × 10 11 2 F = 3 .
The formula for the gravitational constant of the universe is G = 6.674 x 10 - 11 m3/kg s2. Thus, this is the gravitational pull of the sun on the planet.
F = Gm1m2R2, where G is the gravitational constant of the universe. The gravitational force between two bodies of equal mass that are kept at an equal distance from one another constitutes the universal gravitational constant.
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Suppose a molecule has neutrons, a Coulomb total electric charge, and electrons. About how many protons must it have
molecule possesses neutrons and a total electric charge of one Coulomb. e is the electronic value, 1.60 x 10-19 Coulombs, and the proton has a cost of +e while the electron has a fee of -e.
How much is one coulomb?The quantity of charge carried by a present of one amp for one second is measured in coulombs, which is the unit of measurement used in the SI for electric charge. It may also be a quality of a substance that causes magnetic and electric effects to occur. The symbol for it is C. According to math, 1 Coulomb equals 1 Ampere x 1/sec.
A coulomb quizlet: what is it?A coulomb is an unit of power charge that represents the charge that is transmitted over one ampere of current in one second. Colomb's rule. depending on the charged items, electric force.
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A candy-filled piñata is hung from a tree for Matthew's birthday. During an unsuccessful attempt to break the 4. 4-kg piñata, Hayden cracks it with a 0. 54-kg stick moving at 4. 8 m/s. The stick stops and the piñata undergoes a gentle swinging motion. Determine the swing speed of the piñata immediately after being cracked by the stick
The velocity of the other piece of the pinata which has a mass of 3.86 kg
is 0.67 m/s
The mass of the candy-filled pinata = 4.4 kg
The mass of the first piece of the pinata = 0.54 kg
The velocity of the first piece of the pinata = 4.8 m/s
The mass of the second piece = 3.86 kg
The velocity of the other piece can be found using the formula,
mu = m₁v₁ + m₂v₂
where m is the mass of the pinata
u is the velocity of the pinata at rest
m₁,m₂ are the masses of the first and second pieces of pinata
v₁,v₂ is the velocity of the two pieces
Let us substitute the known values in the above equation, we get
4.4 x 0 = 0.54 x 4.8 + 3.86v₂
= 2.592 + 3.86v₂
3.86v₂ = -2.592
v₂ = 2.592/3.86
= 0.67 m/s
Therefore, the velocity of the other piece is 0.67 m/s
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A red cart is moving rightward with a momentum of 50 kg cm/s when it collides with a blue cart of equal mass that is initially at rest. The two carts stick together and move to the right with the same speed after the collision.
The final velocity of the red-blue carts system is 5 cm/s.
What is the final speed of the two carts after collision?
The final speed of the two carts, that is the red cart and the blue cart system after the collision is calculated by applying the principle of conservation of linear momentum.
Pi = Pf
m₁u₁ + m₂u₂ = v ( m₁ + m₂ )
where;
m₁ is mass of the red cartm₂ is the mass of the blue cartu₁ is initial velocity of the red cartu₂ is the initial velocity of the blue cartv is the final velocity of the two carts after the collisionm₁u₁ + 0 = v ( m₁ + m₂ )
m₁u₁ = v ( m₁ + m₂ )
v = ( m₁u₁ ) / ( m₁ + m₂ )
The final velocity of the red-blue carts system is calculated as;
v = ( 50 kg cm/s ) / ( 5 kg + 5kg )
v = 5 cm/s
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The complete question is below:
A red cart is moving rightward with a momentum of 50 kg cm/s when it collides with a blue cart of equal mass that is initially at rest. The two carts stick together and move to the right with the same speed after the collision. What is the final velocity of the two carts system after the collision if the mass of the blue cart is 5 kg.
Which of the following accurately states the claim made by special relativity?
A. The speed of light in a vacuum is the same for stationary frames
of reference.
B. The speed of light in a vacuum is faster for accelerating frames of
reference.
C. The speed of light in a vacuum is the same for all frames of
reference.
D. The speed of light in a vacuum is slower for frames of reference
that have a constant velocity.
Answer:
The Answer is C
The speed of light in a vacuum is the same for all frames of reference.
Explanation:
Answer:
C .The speed of light in the vacuum is same for all frames of reference.
Explanation:
What do you understand by frame of reference?A set of abstract coordinate system that explains the position or motion of something mathematically and physically by the set of reference points and geometric points.
What is Special relativity ?
It explains the effect on mass ,time and space by the speed . It also relates the speed of light , mass and energy.
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Warm air rising at the equator and cold air sinking at the poles is one reason for which type of movement of air?
Answer:
Convection cells
Explanation:
As the cold air moves away from poles, it begins to warm up. This warm air now becomes lighter and the pressure drops significantly at 60° N and 60° south latitude. The air from poles further gushes into these belts because the low pressure created. Thus, convection cells are formed because this rise and fall of air in circular pattern.
Hence, the name given is convection cells.
Part A
Determine the electric field strength in the region r ≤a. Give your answer as a multiple of Q/E0. Express your answer in terms of some or all of the variables a, b, c, r, and the constant π.
The electric field in the region r ≤a is E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
The total charge is enclosed within the Gaussian surface.
Q[tex]_{enc}[/tex] = 2Q - Q = Q
Therefore, applying Gauss's law over the Gaussian surface
∫[tex]_{s}[/tex]E.dS = Q[tex]_{enc}[/tex]/ε₀ ⇒ E.4πr² = Q/ε₀ ⇒ E = Q/4πε₀r²(r)
In question solution:
A[tex]_{sphere}[/tex] = 4πr²
ΦE = ∫E⋅dA
ΦE = q/ε₀
E = q/(A⋅ε₀)
E = q/(4πr²ε₀)
for r≤a, qin = -Q
E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
So, the electric field in the region is E [tex]= - \frac{r}{4\pi a^3} . \frac{Q}{e_0} r[/tex]
Your question is incomplete but most probably your full question was:
A uniformly charged ball of radius a and charge −Q is at the center of a hollow metal shell with inner radius b and outer radius c. The hollow sphere has a net charge of +2Q.
Part A: Determine the electric field strength in the region r ≤a. Give your answer as a multiple of Q/E0. Express your answer in terms of some or all of the variables a, b, c, r, and the constant π.
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What is the potential energy of a passenger jet weighing 7.0 x 10^5 N when it reaches a cruising altitude of 10.0 km?
Upon travelling at an altitude of 10.0 km, a passenger aircraft weighing 7.0 x [tex]10^{6}[/tex] N potential is the energy.
What similarities and differences do kinetic and potential energy share?Potential energy and kinetic energy are fundamentally different from one another because one is the energy of what can be and the other is the energy of what is. Or to put it another way, potential energy is immobile and ready to be unleashed;
When compared to potential energy, is kinetic energy greater?Due to the object's motion, kinetic energy loses some energy in the form of light energy, heat energy, and friction; these things do not occur in the potential energy, which is the reason why kinetic energy is not more than the potential energy.
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Roughly what percentage of matter in the universe is identical to the type of matter that comprises the planets and stars
Approximately 27% of everything in the universe is dark matter, with dark energy making up 68%. This means that all the visible matter we can see, including galaxies, stars and planets, only represents 5% of everything that exists.
What is the matter of the universe?The matter of the universe is a complex and ongoing question that scientists are still working to answer. Generally, it is believed that the universe is composed of dark matter, dark energy, and ordinary matter.
Dark energy is thought to be the energy that is causing the universe to expand, while dark matter is an unseen form of matter that is believed to make up about 27% of the universe. Ordinary matter is the form of matter that makes up:
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After falling for 5.5 seconds, what would be the final velocity of the object?
(Picture Provided)
Please I need help on this!
The first one is based on the fundamental definition of velocity that employs the widely used velocity equation.
What is Final velocity?
The second approach determines the amount of velocity change brought on by acceleration over a given period of time.
Finally, the average velocity formula is used in the third section of the velocity calculator, which may be helpful if you need to examine trips with varying speeds across different distances.
According to the definition of velocity, it is the rate at which an object's position changes over time. Consideration of body motion is one of the fundamental ideas in classical mechanics.
Therefore, The first one is based on the fundamental definition of velocity that employs the widely used velocity equation.
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What is transformation of energy
Answer:
Energy transformation
Explanation:
Energy transformation means the changing of energy from one type to another.
Ms. Estes shows her class a video from when she worked at the space center launching rockets. She asks her students which of the following items in the video were examples of Newton's first law of motion? (1 point)
-- The rocket accelerating rapidly off the launch pad
-- The astronaut being pushed back into his seat as the rocket accelerates
-- The astronaut experiencing zero gravity in orbit
-- The booster rocket falling back into the ocean after the launch
The astronaut being pushed back into his seat as the rocket accelerates - this was the example of Newton's first law of motion.
What is Newton's first law of motion?According to Newton's First Law, a body in uniform motion or at rest will remain in that state up to and unless a net external force acts on it.
When the astronaut worked at the space center launching rockets, no force is worked on him. When the rocket accelerates, according to Newton's first law of motion, the astronaut remains in same motion, that's why, he pushed back into his seat .
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