What is the pH of 4.3x10^-7 M solution of H2CO3?

A.)7

B.)4.3

C.)6.4

D.)7.6

ASAP PLS

Answers

Answer 1

Answer:

pH = -log[H⁺] = -log(4.75 x 10⁻⁷) = -(- 6.32 ) = 6.32

Explanation:

Given 4.3 x 10⁻⁷M H₂CO₃ (Ka1 = 4.2 x 10⁻⁷ &  Ka2 = 4.8 x 10⁻¹¹)

Note: The Ka2 value for the 2nd ionization step is so small (Ka2 = 4.8 x 10⁻¹¹) It will be assumed all of the hydronium ions (H⁺) come from the 1st ionization step.  

1st Ionization step

                    H₂CO₃        ⇄   H⁺ + HCO₃⁻

C(initial)     4.3 x 10⁻⁷             0         0

ΔC                   -x                  +x        +x

C(final)      4.3 x 10⁻⁷ - x         x          x

Note: the 'x' value in this analysis can not be dropped as the Conc/Ka value is less than 10². In this case he C/Ka ratio* (4.3E-7/4.2E-7 ≈ 1)  is far below 10².

So, one sets up the equilibrium equation to be quadric and the x-value can be determined.

Ka1 = [H⁺][HSO⁻]/[H₂SO₃] = (x)(x)/(4.3 x 10⁻ - x) = x²/(4.3 x 10⁻⁷ - x) = 4.2 x 10⁻⁷

=>   x² = 4.2 x 10⁻⁷(4.3 x 10⁻⁷ - x)

=>   x² + 4.2 x 10⁻⁷x - 1.8 x 10⁻¹³ = 0              

      a = 1, b = 4.2 x 10⁻⁷, c = - 1.8 x 10⁻¹³

x = b² ± SqrRt(b² - 4(1)(-1.8 x 10⁻¹³ / 2(1) =  4.75 x 10⁻⁷

x = [H⁺] = 4.75 x 10⁻⁷

pH = -log[H⁺] = -log(4.75 x 10⁻⁷) = -(- 6.4 ) = 6.4

______________________

* The Concentration/Ka-value is the simplification test for quadratic equations used in Equilibrium studies. If the C/Ka > 100 then one can simplify the C(final) by dropping the 'x' if used in this type analysis. However, if the C/Ka value is < 100 then the x-value must be retained and the solution is determined using the quadratic equation formula.

for ax² + bx + c = 0

x = b² ± SqrRt(b² - 4ac) / 2a


Related Questions

10. A balloon is blown up to a volume of 18 L at a pressure of 1.0 atm and

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becomes 4.0 L and its temperature is 239 K?*

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Answer:

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Explanation:

10. A balloon is blown up to a volume of 18 L at a pressure of 1.0 atm and

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Answers

Answer:

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1.A sample has a mass of 15 g and a volume of 3 mL. Calculate the density.

Answers

Answer:

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Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

From the question

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Hope this helps you.

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Answer:

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Explanation:

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Answer:

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choices
magnet

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manipulation

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liquid​

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Answer:

1. Mixtures

2. Different

3. Manipulations

4. Magnet

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Answer:

 

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Explanation:

Chemistry
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Explanation:

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Explanation:

smaller particles diffuse faster

larger particles diffuse slower

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Answer:

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Explanation:

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1
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Answer:

Explanation:

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Answers

Answer:

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Explanation:

Hope this helps.

The factor which increases as the efficiency of a machine increases is: work output.

Efficiency can be defined as a ratio of work (energy) output to work (energy) input.

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Where:

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Answers

Answer:

147.28 cm³

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Pure substances are substances that are homogenous in nature, which means they are uniform and are made up of only one component.

Density is said to be the characteristic property of a pure substance because the density of a pure substance is constant and fixed but its mass and volume can vary.

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why should you not change the subscripts in chemical formulas when balancing chemical equations?

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best answer will be tagged brainliest.... no spamming pliz​

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A. Chloride ions (CI)

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Answer:

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Explanation:

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