The standard form of the expression (4 × 10) + (3 × 1/100) + (5 × 1/1000) is 40.035
What is an arithmetic operation?It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.
We have expression:
= (4 × 10) + (3 × 1/100) + (5 × 1/1000)
= 40 + 0.03 + 0.005
= 40.035
Thus, the standard form of the expression (4 × 10) + (3 × 1/100) + (5 × 1/1000) is 40.035
Learn more about the arithmetic operation here:
brainly.com/question/20595275
#SPJ1
Calc I optimization problem, Please see attachment!
=======================================================
Explanation:
Let C be the corner point.
x = distance from P to C
That makes segment AP to be 70-x feet long
Focus on the right triangle PBC. Use the pythagorean theorem to find the hypotenuse PB.
[tex]a^2 + b^2 = c^2\\\\c = \sqrt{a^2 + b^2}\\\\PB = \sqrt{(PC)^2 + (CB)^2}\\\\PB = \sqrt{x^2 + 90^2}\\\\PB = \sqrt{x^2 + 8100}\\\\[/tex]
If we knew what x was, then we could find a numeric value for PB.
---------------------
It costs $28 per foot to run cable along the ground. This is the portion from A to P. So it costs 28(70-x) dollars to run that portion of cable above ground. Simply multiply the cost per foot by the number of feet.
Similarly, the cost from P to B is [tex]53\sqrt{x^2+8100}[/tex] since it costs $53 per foot to have it run underground.
The total cost is therefore [tex]28(70-x) + 53\sqrt{x^2 + 8100}[/tex]
The derivative of this will help determine when the cost is minimized.
Type that function into GeoGebra and have it compute the derivative.
You should find that the x intercept of the derivative curve is exactly x = 56
If x = 56, then 70-x = 70-56 = 14
This means AP = 14 feet is the amount of cable to run along main street.
This also leads to [tex]PB = \sqrt{x^2 + 8100} = \sqrt{56^2 + 8100} = 106[/tex]
The total length of the wire is 14+106 = 120 feet
It costs $28 per foot along the 14 ft section, so 28*14 = 392 dollars is the cost for this section.
It costs $53 per foot along the 106 ft section, so 53*106 = 5618 dollars is the cost for this other section.
The total min cost is 392+5618 = 6010 dollars
------------------
Side note: You could do all this without a calculator to compute the derivative and use algebra to end up with x = 56. However, I think the use of technology is beneficial because it's fast/efficient. In real world settings, you won't be likely to pull out pencil/paper to get things done. The modern world relies on computers. It's refreshing to see that your teacher encourages the use of technology.
Let me know if you need me to go over the algebraic steps and I'll update my answer.
Find all solutions in the interval [0,2π)
Answer:
Its B
Step-by-step explanation:
A triangle has perimeter 38 cm.
Two sides of the shapes are put
together to make a pentagon
A square has perimeter 48 cm.
What is the perimeter
of the pentagon?
cm
Answer:
62cm
Step-by-step explanation:
You were told the perimeter of the triangle is 38
but two sides are added to make a Pentagon. and that Pentagon is made up of a triangle and a square.
so if we find the side of the square, we can equally get the other two sides of the triangle.
hint: (because it's a square, we would be getting an isosceles triangle, meaning two sides are equal)
because one side of the pentagon added to the other two sides of the triangles gives us the perimeter of the triangle.
we first find the sides of the square with all sides equal by diving by 2
[tex] \frac{48}{2} = 12[/tex]
the sides of the square making the perimeter of the square 12cm.
now we subtract 12 from the perimeter of the triangle 38
[tex]38 - 12 = 26[/tex]
now that we have gotten one side we can get the other two by dividing the result by 2
[tex] \frac{26}{2} = 13[/tex]
so the other two sides of the triangle are 13cm.
now since we have the sides of the square and the triangle, we can find the perimeter of the pentagon by adding.
all the sides of the triangle without the base which is also the top of the square.
so instead of adding 4 times of 12, we add 3 times of 12 and 2 times of 13.
3(12)+2(13) = 62
or
12 + 12 + 12 + 13 + 13 = 62cm
1 box of blue counters from which 25 counters have been removed and then the remaining number has been doubled
Hello can u guys help me please
Answer:
[tex]\displaystyle \frac{1}{4}[/tex]
Step-by-step explanation:
Given:
[tex]\displaystyle\frac{4^{6} }{4^{7}}[/tex]
Expand:
[tex]\displaystyle\frac{4*4*4*4*4*4 }{4*4*4*4*4*4*4}[/tex]
Simplify ones, in this case [tex]\frac{4}{4}[/tex]:
[tex]\displaystyle \frac{1}{4}[/tex]
If you raise 4 to the power of 6, to the power of 7, and then simplify the fraction, you will get the same result. This method is much quicker when you have numbers with the same bases (here the base is 4) so I used this way.
a sphere is inscribed in a cube with a volume of 125 cubic inches what is the volume of the sphere
Answer:
using [tex]\pi[/tex]: 65.45 in³ (nearest hundredth)
using [tex]\pi =3.14[/tex]: 65.42 in³ (nearest hundredth)
Step-by-step explanation:
The radius of the sphere is half the side length of the cube (see attached diagram). Therefore, the side length of the cube = 2r
Given:
volume of the cube = 125 in³side length of cube = 2r[tex]\textsf{Volume of a cube}=x^3\quad \textsf{(where}\:x\:\textsf{is the side length)}[/tex]
[tex]\implies 125=(2r)^3[/tex]
[tex]\implies \sqrt[3]{125}=2r[/tex]
[tex]\implies 5=2r[/tex]
[tex]\implies r=\dfrac52[/tex]
Substitute the found value of r into the volume of a sphere equation:
[tex]\begin{aligned}\textsf{Volume of a sphere} & =\dfrac43 \pi r^3\\\\ & =\dfrac43 \pi \left(\dfrac52\right)^3\\\\ & =\dfrac43 \pi \left(\dfrac{125}{8}\right)\\\\ & =\dfrac{500}{24} \pi\\\\ & =\dfrac{125}{6} \pi\\\\ & =65.45\:\sf in^3\:(nearest\:hundredth) \end{aligned}[/tex]
Jennifer jones has an idea. Join the bbq parties together . She thinks they can rope off more total area if the tie two ropes together to make one giant bbq than the families could have separately. Is this true?
Jennifer idea of roping off more total area if the tie two ropes together to make one giant BBQ is a true statement.
What is total surface area?The total surface area is known to be the addition of all the sum of any given area of surfaces of a solid together.
Conclusively, Note that by joining together the 2 parties, one can cut off some activities that will be be doubled if it were two separate event and as such, the use of space is been maximize and then the area of the space they will use for the event will be reduced.
Learn more about total surface area from
https://brainly.com/question/26638955
please help me thanks
Answer:
y = 3x
Step-by-step explanation:
i cant see any equations
but the equaiton would be..
NO LINKS!! Please help me with this problem
FGHIJ ≅ STUQR
Solve for HI
[tex]\sf \dfrac{HI}{GH} = \dfrac{UQ}{UT}[/tex]
[tex]\rightarrow \sf \dfrac{HI}{56} = \dfrac{25}{35}[/tex]
[tex]\rightarrow \sf HI = 40[/tex]
Solve for QR
[tex]\sf \dfrac{IJ}{GH} = \dfrac{QR}{UT}[/tex]
[tex]\rightarrow \sf \dfrac{72}{56} = \dfrac{QR}{35}[/tex]
[tex]\rightarrow \sf QR = 45[/tex]
Solve for ST
[tex]\sf \dfrac{FG}{GH} = \dfrac{ST}{UT}[/tex]
[tex]\rightarrow \sf \dfrac{48}{56} = \dfrac{ST}{35}[/tex]
[tex]\rightarrow \sf ST =30[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{GH}{HI}=\dfrac{UT}{UQ}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{56}{HI}=\dfrac{35}{25}=\dfrac{7}{5}[/tex]
[tex]\\ \rm\Rrightarrow HI=56(5)/7=8(5)=40[/tex]
#QR
[tex]\\ \rm\Rrightarrow \dfrac{GH}{JI}=\dfrac{UT}{RQ}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{56}{72}=\dfrac{35}{RQ}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{7}{9}=\dfrac{35}{RQ}[/tex]
[tex]\\ \rm\Rrightarrow RQ=35(9)/7=5(9)=45[/tex]
#ST
[tex]\\ \rm\Rrightarrow \dfrac{GH}{FG}=\dfrac{UT}{ST}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{56}{48}=\dfrac{7}{6}=\dfrac{35}{ST}[/tex]
[tex]\\ \rm\Rrightarrow ST=6(35)/7=6(5)=30[/tex]
I am playing a number game, there are 2 tiles for each number from 0 thru 9. One tile is chosen at random, can you list the possible outcomes ?
Answer:
If each tile has a number from 0 thru 9 then the possible outcomes for each tile are 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.
Can someone please go into detail on how they simplified this expression? Thanks!
: 4a - (4a-3)=4a 1(4a 3) Identity property
4a -4a + 3 Distributive property
0 -3 Combine like terms.
3 simplify
I really don't get how they got plus 3
Thanks again!
Answer:
Step-by-step explanation:
4a - (4a-3)
= 4a -1(4a - 3)
= 4a - 4a + 3 <--- Distributing the -1 over the parenthes
= 3 <---- ( as 4a - 4a = 0)
what is the volume of this prism ?
Answer:
576cm³
Step-by-step explanation:
8×6=48
48×12=576
Expand 96•06 using powers
Answer:
Step-by-step explanation:
Use long multiplication to evaluate.
576
Helpppppp pleaseeeee ):
Answer:
Smily face=5 lightning=8
Step-by-step explanation:
5+5=10 8x3=24 24+10=34
8x5=40 5x8=40
4th question!!! Can anyone help me ?
Answer:
₹528Step-by-step explanation:
Length of Fence
Circumference = 2πr or πdπd22/7 x 21 m22 x 3 m66 m2 rounds = 66 x 2 = 132 mCost
₹4 x 132₹528cosx(tanx+cotx)=
Pls Help
Step-by-step explanation:
Tangent is equal to sine over cosine. Cotangent is equal to cosine over sine. Therefore:
[tex]cos(x)( \frac{sin(x)}{cos(x)} + \frac{cos(x)}{sin(x)} )[/tex]
Distribute the cos(x) into the sum to get:
[tex]sin(x) + \frac{ {cos(x)}^{2} }{sin(x)} [/tex]
Get a common denominator by multiplying the first term by sine over sine to get:
[tex] \frac{ {sin(x)}^{2} }{sin(x)} + \frac{ {cos(x)}^{2} }{sin(x)} [/tex]
The numerator adds to equal 1 due to a common trigonometric identity. Therefore the only remaining term is:
[tex] \frac{1}{sin(x)} [/tex]
What is the area, in square centimeters, of the parallelogram?
(20 points)
Answer:
30
Step-by-step explanation:
10 x 3 = 30
Answer:
30 centimeters squared
Step-by-step explanation:
The area of a parallelogram can be found by using the formula base x height. The base of this parallelogram is 10, and the height is 3. Therefore the area is 30 square centimeters.
Find the area of the triangle.
Answer:
40m^2 :)
Step-by-step explanation:
Area of a triange = (h·b)/2
Now lets solve :)
4 + 6 = 10
(8·10)/2
80/2
40
Have an amazing day!!
Please rate and mark brainliest!!
At a local school,940 students each wrote 40 letters to students in another country.How many letters were written in all?
Answer:
37,600
Step-by-step explanation:
940 X 40 = 37,600.
simple multiplication
Answer:
, 37,000
Step-by-step explanation:
940 x 40= 37,000
What is the surface area?
2 ft
5 ft
3 ft
square feet
Submit
image coordinate plane with points plotted at ordered pairs Q (-4, 4) R (2, 4) S (5,-3) T(2,-3) and U (-4, -3) first persin to get it in 30 min get brainlest
Answer:
I have graphed them on desmos and given you three options to choose from:
Step-by-step explanation:
1. with lines (complete shape)
2. with lines (incomplete shape)
3. without lines
Hope this helps!
Answer:
here
Step-by-step explanation:
Will the product of 2 2/5 x 1/6 be larger or smaller than 2 2/5
Answer:
Smaller
Step-by-step explanation:
2 2/5 * 1/6 = 2/
5
= 0.4
Conversion a mixed number 2 2/
5
to a improper fraction: 2 2/5 = 2 2/
5
= 2 · 5 + 2/
5
= 10 + 2/
5
= 12/
5
To find a new numerator:
a) Multiply the whole number 2 by the denominator 5. Whole number 2 equally 2 * 5/
5
= 10/
5
b) Add the answer from previous step 10 to the numerator 2. New numerator is 10 + 2 = 12
c) Write a previous answer (new numerator 12) over the denominator 5.
Two and two fifths is twelve fifths
Multiple: 12/
5
* 1/
6
= 12 · 1/
5 · 6
= 12/
30
= 2 · 6/
5 · 6
= 2/
5
Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(12, 30) = 6. In the following intermediate step, cancel by a common factor of 6 gives 2/
5
.
In other words - twelve fifths multiplied by one sixth = two fifths.
The graph shows the function f(x) = 3* What is the value of f-1(x) at x = 3?
Answer:
1
I've attached a screenshot from my graphing calculator of [tex]f(x)[/tex] in blue and [tex]f^{-1}(x)[/tex] in red. Notice how the red line (inverse function) has (3, 1)
Step-by-step explanation:
[tex]f(x) = 3^x\\f^{-1}(x) =\ ?\\[/tex]
We must first figure out the inverse function of [tex]f(x)[/tex] which is [tex]f^{-1}(x)[/tex]
[tex]y = f(x) = 3^x\\y = 3^x\\log\ y = log\ 3^x\\log\ y = x \times log\ 3\\x = \frac{log\ y}{log\ 3}\\[/tex]
We say y = f(x) to begin with, but after find x = ...
we must 'swap' x and y
[tex]x = \frac{log\ y}{log\ 3}\\y = \frac{log\ x}{log\ 3}\\[/tex]
[tex]f^{-1}(x) = \frac{log\ x}{log\ 3}[/tex]
[tex]f^{-1}(3) = \frac{log\ 3}{log\ 3} = 1[/tex]
can someone please help? :((
if you want another 50 points or more you could maybe help with one of the previous unanswered questions on my profile
Just find the vertex and then compare with graph
#a
y=2x²-8y=2(x-0)²-8Parabola opening upwards
Vertex at (0,-8)Graph 3
#2
y=(x+3)²+0Vertex at (-3,0)
Graph IV
#3
y=-2(x-4)²+8Parabola opening downwards as a is -ve
Graph I
#4
One graph is left
Graph IiAnswer:
a) graph iii)
b) graph iv)
c) graph i)
d) graph ii)
Step-by-step explanation:
Vertex form of a quadratic equation: [tex]y = a(x - h)^2 + k[/tex]
where [tex](h, k)[/tex] is the vertex (turning point)
First, determine the vertices of the parabolas by inspection of the graphs:
Graph i) → vertex = (4, 8)Graph ii) → vertex = (3, -8)Graph iii) → vertex = (0, -8)Graph iv) → vertex = (-3, 0)Next, write each given equation in vertex form and compare to the vertices above.
[tex]\textsf{a)}\quad y=2x^2-8[/tex]
[tex]\textsf{Vertex form}: \quad y=2(x-0)^2-8[/tex]
⇒ Vertex = (0, -8)
Therefore, graph iii)
[tex]\textsf{b)} \quad y=(x+3)^2[/tex]
[tex]\textsf{Vertex form}: \quad y=(x+3)^2+0[/tex]
⇒ Vertex = (-3, 0)
Therefore, graph iv)
[tex]\textsf{c)} \quad y=-2|x-4|^2+8[/tex]
[tex]\textsf{Vertex form}: \quad y=-2|x-4|^2+8[/tex]
⇒ Vertex = (4, 8)
Therefore, graph i)
[tex]\textsf{d)} \quad y=(x-3)^2-8[/tex]
[tex]\textsf{Vertex form}: \quad y=(x-3)^2-8[/tex]
⇒ Vertex = (3, -8)
Therefore, graph ii)
What key features do the functions f(x) = 12x and g of x equals the square root of x minus 12 end root have in common?
Both f(x) and g(x) include domain values of [-12, ∞) and range values of (-∞, ∞), and both functions have an x-intercept in common.
Both f(x) and g(x) include domain values of [12, ∞) and range values of [0, ∞), and both functions have a y-intercept in common.
Both f(x) and g(x) include domain values of [-12, ∞) and range values of (-∞, ∞), and both functions increase over the interval (-6, 0).
Both f(x) and g(x) include domain values of [12, ∞), and both functions increase over the interval (12, ∞).
Both f(x) and g(x) include domain values of [12, ∞), and both functions increase over the interval (12, ∞). Then the correct option is D.
What are domain and range?The domain means all the possible values of the x and the range means all the possible values of the y.
The functions are given below.
[tex]\rm f(x) = 12x \\\\g(x) = \sqrt{x - 12}[/tex]
Then the domain of f(x) is (-∞, ∞) and the domain of g(x) is (12, ∞). And both the functions increases in the interval of (12, ∞).
More about the domain and range link is given below.
https://brainly.com/question/12208715
#SPJ1
Find center and radius of this circle:
[tex](x-2)^2+(x+12)^2=81[/tex]
Answer:
center: (2,-12)
radius: 9
Step-by-step explanation:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
[tex]h=2\\k=-12\\r=9[/tex]
get r by getting square root of 81
center = (h,k)
Answer:
center: (2,-12)
radius: 9
Step-by-step explanation:
(x-h)^2+(y-k)^2=r^2
h=2
k=-12
r=9
What solution value does not satisfy the compound inequality X - 7 < 17 or -6x >
36?
O A) x = -1
OB) x=0
O C) x= - 10
C
O D) x=25
Dx = 25
Inequalities are expressions not separated by an equal sign. The solution of the compound inequality will be -6 < x < 24
Compound inequalityInequalities are expressions not separated by an equal sign.
Given the compound inequalities
X - 7 < 17 or -6x >36
For the inequality
x - 7 < 17
x < 17 + 7
x < 24
Similarly for -6x >36
x < -36/6
x < -6
The solution of the compound inequality will be -6 < x < 24
Learn more on inequality here: https://brainly.com/question/11613554
A rectangular field is 30 yards in length and 81 feet in width.
What is the area of the field in square feet?
Answer:
7290in ^2
Step-by-step explanation:
covert 30yd to feet which equals too 90ft.
Then multiple 90 x 81 = 7290
A property's value is $400,000 and its land value is $75,000. Assuming a depreciation term of 39 years, what is the amount of annual depreciation?
[tex]\qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{current amount}\dotfill &75000\\ P=\textit{initial amount}\dotfill &400000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &39\\ \end{cases} \\\\\\ 75000=400000(1 - \frac{r}{100})^{39}\implies \cfrac{75000}{400000}=\left( \cfrac{100-r}{100} \right)^{39}[/tex]
[tex]\cfrac{3}{16}=\left( \cfrac{100-r}{100} \right)^{39}\implies \sqrt[39]{\cfrac{3}{16}}=\cfrac{100-r}{100}\implies 100\sqrt[39]{\cfrac{3}{16}}=100-r \\\\\\ r=100-100\sqrt[39]{\cfrac{3}{16}}\implies r\approx 4.2[/tex]
For each of the following prisms,find (I) its volume (ii) its total surface area