IF PASSPORT is written as RCUURQTV, then how will BOOKLET be coded?
Answer: DQQMNGV
Step-by-step explanation: Each letter is shifted two letters to the right on a letter strip (a -> b -> c), so BOOKLET would be DQQMNGV.
Hope this helps!
A picture is to be printed onto a sheet of paper with dimensions of 81/2 x 11 inches, A margin of 1 1/2 inches is to be left on all sides of the picture. What is the area of the printed picture?
Answer:
The area of the printed picture is 172.5 square inches.
Step-by-step explanation:
Since a picture is to be printed onto a sheet of paper with dimensions of 81/2 x 11 inches, and a margin of 1 1/2 inches is to be left on all sides of the picture, to determine what is the area of the printed picture the following calculation must be carried out, knowing that the area of a rectangle is equal to the base multiplied by the height:
81/2 = 40.5
1/2 = 0.5
40.5 - 1.5 x 4 = 34.5
11 - 1.5 x 4 = 5
34.5 x 5 = 172.5
Therefore, the area of the printed picture is 172.5 square inches.
Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions the population follows a logistic growth model: P(t) = d 1 + ke−ct where c, d, and k are positive constants. For a certain fish population in a small pond d = 1200, k = 11, c = 0.2, and t is measured in years. The fish were introduced into the pond at time t = 0. (a) How many fish were originally put in the pond? 100 Correct: Your answer is correct. fish (b) Find the population after 10, 20, and 30 years. (Round your answers to the nearest whole number.) 10 years 1 Changed: Your submitted answer was incorrect. Your current answer has not been submitted. fish 20 years fish 30 years fish (c) Evaluate P(t) for large values of t. What value does the population approach as t → [infinity]? P(t) =
Answer:
(a) 100 fishes
(b) t = 10: 483 fishes
t = 20: 999 fishes
t = 30: 1168 fishes
(c)
[tex]P(\infty) = 1200[/tex]
Step-by-step explanation:
Given
[tex]P(t) =\frac{d}{1+ke^-{ct}}[/tex]
[tex]d = 1200\\k = 11\\c=0.2[/tex]
Solving (a): Fishes at t = 0
This gives:
[tex]P(0) =\frac{1200}{1+11*e^-{0.2*0}}[/tex]
[tex]P(0) =\frac{1200}{1+11*e^-{0}}[/tex]
[tex]P(0) =\frac{1200}{1+11*1}[/tex]
[tex]P(0) =\frac{1200}{1+11}[/tex]
[tex]P(0) =\frac{1200}{12}[/tex]
[tex]P(0) = 100[/tex]
Solving (a): Fishes at t = 10, 20, 30
[tex]t = 10[/tex]
[tex]P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483[/tex]
[tex]t = 20[/tex]
[tex]P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999[/tex]
[tex]t = 30[/tex]
[tex]P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168[/tex]
Solving (c): [tex]\lim_{t \to \infty} P(t)[/tex]
In (b) above.
Notice that as t increases from 10 to 20 to 30, the values of [tex]e^{-ct}[/tex] decreases
This implies that:
[tex]{t \to \infty} = {e^{-ct} \to 0}[/tex]
So:
The value of P(t) for large values is:
[tex]P(\infty) = \frac{1200}{1 + 11 * 0}[/tex]
[tex]P(\infty) = \frac{1200}{1 + 0}[/tex]
[tex]P(\infty) = \frac{1200}{1}[/tex]
[tex]P(\infty) = 1200[/tex]
I need help asap please! 20 points!
Graph the parabola.
y=x²–2x-4
Plot five points on the parabola: the vertex, two points to the left of the vertex, and two points to the right of the vertex. Then click on the graph-a-function
button
This is the graph I hope this helps
Help me I have this due today!!!
Answer:
The answer is 21/25.
Step-by-step explanation:
I hope this helps! Have a great rest of your day!
A company that manufactures electronic components wants to know the mean discharge time of one particular type of capacitor that it makes. In order to estimate this value, they randomly select 100 capacitors and measure how long they take to discharge. The mean of this sample was 7.25 seconds with a standard deviation of 0.15 seconds. Assuming that this distribution is normal, construct a 99% confidence interval to estimate the mean discharge time for all capacitors of this type. Is this question asking for a confidence interval or hypothesis test
Answer:
99% confidence interval to estimate the mean discharge time for all capacitors of this type
(7.2146, 7.2854)
Step-by-step explanation:
Step(i):-
Given that the sample size 'n' = 100
Given that the mean of sample x⁻ = 7.25 seconds
Given that the standard deviation of the sample (S) = 0.15 seconds
Level of significance = 0.01
Degrees of freedom = n-1 =100-1 =99
t₀.₀₁ , ₉₉ = 2.3646
We have to find that the 99% of the confidence interval of the mean
Step(ii):-
99% confidence interval to estimate the mean discharge time for all capacitors
[tex](x^{-} - t_{0.01 , 99} \frac{S}{\sqrt{n} } , x^{-} + t_{0.01 , 99} \frac{S}{\sqrt{n} } )[/tex]
[tex](7.25 - 2.3646 \frac{0.15}{\sqrt{100} } , 7.25 + 2.3646 \frac{0.15}{\sqrt{100} } )[/tex]
(7.25 - 0.0354 , 7.25 + 0.0354)
(7.2146, 7.2854)
Final answer:-
99% confidence interval to estimate the mean discharge time for all capacitors of this type
(7.2146, 7.2854)
$102 headphones, 7.5% tax
Answer:
You are correct the tax would be that
Step-by-step explanation:
9 decreased by 4 times a number
Answer:
4x - 9
Step-by-step explanation:
4 times a number means 4x
9 decreased by means -9
Combined:
4x - 9
Answer:
9 - 4x
Step-by-step explanation:
this is so easy
A family spends 1/10 of it's annual income for housing 1/4 for food and clothing 1/5 for general expenses and 2/15 for entertainment what fractional part of their income is spent on these items altogether.
Answer:
The family spends 41/60 of its income on these items altogether.
Step-by-step explanation:
Given that a family spends 1/10 of it's annual income for housing, 1/4 for food and clothing, 1/5 for general expenses and 2/15 for entertainment, to determine what fractional part of their income is spent on these items altogether the following calculation must be performed:
10, 4, 5, and 15 have a common least multiple at 60.
1/10 = 6/60
1/4 = 15/60
1/5 = 12/60
2/15 = 8/60
6 + 15 + 12 + 8 = 41
Therefore, the family spends 41/60 of its income on these items altogether.
Can u guys help me pls ill give u 20 points
Answer:
Its either L or N im not sure but if i had to guess out of the two i think its L.
Step-by-step explanation:
Which equation goes with the t-chart below?
Answer:
y = 2 x^2 + 5
Step-by-step explanation:
y = 2x^2 + 5
y = 2(-2)^2 + 5
y= 2(4) + 5
y = 8 + 5
y = 13
you can try for yourself using the other values
PLEASE HELPPO?!!!! Look at the attachment below
Answer:
157
Step-by-step explanation:
just trust me bro
HELP! WILL GIVE BRANLIEST!
Answer:
Step-by-step explanation:
z = 119 Vertically opposite angles are equal.
5x + 41 + 119 = 180 5x + 41 and 119 are supplementary.
4x + 160 = 180 Subtract 160 from both sides
4x = 180 - 160
4x = 20 Divide by 4
x = 20/4
x = 5
I keep looking and I can’t find the answer
Answer:
B
Step-by-step explanation:
sInce his average is equal or greater than league's average
divide 12 unto two parts such that
their product is 35
Which property of quadrilaterals inscribed in a circle can be used to find value of X in the figure below?
A. The difference between an opposite pair of angles 180°.
B. The difference between an opposite a pair of angles is 0°.
C. The some of an opposite pair of angles is 180°.
D. The sum of an opposite pair of angles is 360°.
Answer: that’s the answer c
Step-by-step explanation:
Bc of the work you put in
Which of the following are solutions to the following equation?
4x^2-100=0.
Check all that apply.
A. 5
B. -10
C. -5
D. 10
Answer:x=5 or x=−5
Step-by-step explanation:
4x^2−100=0
Step 1: Add 100 to both sides.
4x^2−100+100=0+100
4x^2=100
Step 2: Divide both sides by 4.
4x^2/4=100/4
x^2=25
Step 3: Take square root.
x=±√25
x=5 or x=−5
Answer:
x=5 or x=−5
I have to go to a few places but my friend needs help with this specific equation!
Thank you!
~Hocus Pocus
Answer:
Hello, this would be a vertical angle graph. Since this graph is a supplementary graph since it stretches about 180 degrees, you would take both 7x and x+20 and set it equal to 180 like this:
7x+x+20=180
Then, you combine the xs and you would get this:
8x+20=180
Then, subtract 20 from both sides like this:
8x=160
Lastly, you would divide 8 by both sides and get x which is:
x=20
Step-by-step explanation:
I hope this helped you!
Nevaeh invested $660 in an account paying an interest rate of 3% compounded
continuously. Jonathan invested $660 in an account paying an interest rate of 3 %
compounded monthly. After 14 years, how much more money would Nevaeh have in
her account than Jonathan, to the nearest dollar?
Answer:
19
Step-by-step explanation:
Rate 1: 3
4
1
%=3+1/4=
\,\,3.25\%\rightarrow 0.0325
3.25%→0.0325
\text{Rate 2: }3\tfrac{1}{8}\%=3+1/8=
Rate 2: 3
8
1
%=3+1/8=
\,\,3.125\%\rightarrow 0.03125
3.125%→0.03125
\text{Calculate Final Amount for Nevaeh}
Calculate Final Amount for Nevaeh
\overline{\phantom{\text{Calculate Final Amount for Nevaeh}}}
Calculate Final Amount for Nevaeh
\text{Compounded Continuously:}
Compounded Continuously:
A=Pe^{rt}
A=Pe
rt
P=660\hspace{35px}r=0.0325\hspace{35px}t=14
P=660r=0.0325t=14
Given values
A=660e^{0.0325(14)}
A=660e
0.0325(14)
Plug in
A=660e^{0.455}
A=660e
0.455
Multiply
A=1040.2744
A=1040.2744
Use calculator (with e button)
\text{Calculate Final Amount for Jonathan}
Calculate Final Amount for Jonathan
\overline{\phantom{\text{Calculate Final Amount for Jonathan}}}
Calculate Final Amount for Jonathan
\text{Compounded Monthly:}
Compounded Monthly:
A=P\left(1+\frac{r}{n}\right)^{nt}
A=P(1+
n
r
)
nt
Compound interest formula
P=660\hspace{35px}r=0.03125\hspace{35px}t=14\hspace{35px}n=12
P=660r=0.03125t=14n=12
Given values
A=660\left(1+\frac{0.03125}{12}\right)^{12(14)}
A=660(1+
12
0.03125
)
12(14)
Plug in values
A=660(1.0026042)^{168}
A=660(1.0026042)
168
Simplify
A=1021.6468
A=1021.6468
Use calculator
\text{How much more money Nevaeh has:}
How much more money Nevaeh has:
1040.2744-1021.6468
1040.2744−1021.6468
18.6276
18.6276
\$ 19
$19
Solve for x using
cross multiplication.
3x - 3
2x – 2
=
5
4
x = [?]
Answer:
Step-by-step explanation:
Given
(3x - 3) / 5 = (2x - 2) / 4
Begin by cross multiplying
Solution
4(3x - 3) = 5(2x - 2) Use the distributive property to remove brackets12x - 12 = 10x - 10 Add 12 to both sides.12x = 10x - 10 + 12 Combine the right12x = 10x + 2 Subtract 10x from both sides12x-10x = 2 Combine the left2x = 2 Divide by 2x = 2/2x = 1Note: the original equation gives you 0/5 = 0/4 which is 0 = 0.
What is the equation of the line shown in the graph at the right?
HELPPPP ITS TIMEDDD WILL GIVE BRAINLYISTTTT
Answer please and explain
Answer:
C=84
Step-by-step explanation:
Since you use 3 for pi. You plug the radius into the formula. C=2×3x14=84
how many oz do you think this cup is
Answer:
I'm gonna say 12??
Step-by-step explanation:
Am I close?
Have a nice day! <3
Find 0% of 44:
Find 100% of 44:
Find 50% of 44:
Find 25% of 44:
Find 75% of 44:
Answer:
0% of 44=0
100% if 44=44
50% of 44=22
25% of 44=11
75% of 44=33
Which is the correct formula to find the area of triangle AED?
Answer:
Area of triangle AED = [tex]\frac{1}{2}[/tex] × AE × DE
Step-by-step explanation:
The area of a triangle is [tex]\frac{bxh}{2}[/tex]
Answer:
Other person is right, i took the test
Step-by-step explanation:
My cousin needs help with this question.
Answer:
3 feet per minute
Step-by-step explanation:
Look at an easy to read point on a grid line intersection.
Then find the slope. Slope = constant of proportionality.
For example, look at point (2, 6) which means that when time = 2 minutes, distance = 6 feet.
(6 ft)/(2 sec) = 3 feet per minute
Answer: 3 feet per minute
All of Jenny's pets are dogs except one. All of her pets are cats except one. How many cats and dogs does Jenny have?
NO LINKS OR U GET REPORTED!
Plesse help me:) ive been stuck on this for a while
Answer:
4th number line (the one of the bottom right)
Step-by-step explanation:
First, solve the inequality, then choose the number line that mathes the solution.
3x ≤ -6
Only step: Divide by 3.
x ≤ -6/3
x ≤ -2
But which number line matches the solution?
We know this is going left, so #1 & #3 are out. This also has a closed circle (because of ≤ (less than/equal to)), so #2 is also out.
Number line #4 matches the solution (x ≤ -2), so it is the answer.
In this experiment researchers randomly assigned smokers to treatments. Of the 193 smokers taking a placebo, 29 stopped smoking by the 8th day. Of the 266 smokers taking only the antidepressant buproprion, 82 stopped smoking by the 8th day. Calculate the estimated standard error for the sampling distribution of differences in sample proportions.
Answer:
The estimated standard error for the sampling distribution of differences in sample proportions is 0.0382.
Step-by-step explanation:
To solve this question, we need to understand the Central Limit Theorem and subtraction of normal variables.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Subtraction of normal variables:
When we subtract normal variables, the mean is the subtraction of the means, while the standard error is the square root of the sum of the variances:
Of the 193 smokers taking a placebo, 29 stopped smoking by the 8th day.
This means that:
[tex]p_S = \frac{29}{193} = 0.1503[/tex]
[tex]s_S = \sqrt{\frac{0.1503*0.8497}{193}} = 0.0257[/tex]
Of the 266 smokers taking only the antidepressant buproprion, 82 stopped smoking by the 8th day.
This means that:
[tex]p_A = \frac{82}{266} = 0.3083[/tex]
[tex]s_A = \sqrt{\frac{0.3083*0.6917}{266}} = 0.0283[/tex]
Calculate the estimated standard error for the sampling distribution of differences in sample proportions.
[tex]s = \sqrt{s_S^2 + s_A^2} = \sqrt{0.0257^2 + 0.0283^2} = 0.0382[/tex]
The estimated standard error for the sampling distribution of differences in sample proportions is 0.0382.