Answers:
2.857142 mph
4.190476 ft per second
Both values are approximate
=======================================================
Work Shown:
21 min = 21/60 = 0.35 hrs which is exact
distance = rate*time
rate = distance/time
rate = (1 mile)/(0.35 hrs)
rate = (1/0.35) mph
rate = 2.857142 mph which is approximate
------------------
21 min = 21*60 = 1260 seconds
1 mile = 5280 ft
rate = distance/time
rate = (5280 ft)/(1260 seconds)
rate = (5280/1260) ft per second
rate = 4.190476 ft per second approximately
Answer: 2.857 miles/hr
4.19 ft/sec
Step-by-step explanation:
60 min=1 hr.
1 mi/21 min*60 min=
60 min*1 mi/21 min=2.857 miles/hr
60 sec=1 min
60*60 sec=1 hr
1 hr=3600 sec
2.857 miles/hr=
2.857/3600 miles/sec=0.00079 miles/sec
1 mile=5280 ft
0.00079 miles/sec=
0.00079*5280 ft/sec=4.19 ft/sec
Let D={12,15,17), E = {12,14,15,16) and F = {11,13,14,15,17).
List the elements in the set D UE.
DUE= (Use commas to separate answers.)
The elements that will be coming in the set D∪E will be {12, 14, 15, 16, 17}.
A set may be defined as a collection of letters or numbers that are written in order to depict a certain value or entity. A set is always represented by a capital letter symbol and is always written in curly brackets { }. Union of two sets may be defined as a new set which has the collection of all the elements of the two individual sets. Union of two sets is represented by the symbol '∪'. Union of two Indvidual sets, set A and set b is written as A∪B.
Now, according to the question set D is = {12, 15, 17} and set E is = {12, 14, 15, 16}.
The union of the two sets contains all the elements of the sets D and E.
Thus, D∪E will be given by {12, 14, 15, 16, 17}.
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If f(x) is a decreasing function, which of the following statements must be true? Select all that apply.
(Assume that f(x) is always decreasing.)
a) f(5)−f(1) / 5−1 > 0
b) f(5)−f(1) / 5−1 < 0
c) For some value of x≠5, f(x)=f(5)
d) f(5) < f(1)
e) f(5) > f(1)
The two true statements are:
b) (f(5)−f(1)) / (5−1) < 0
d) f(5) < f(1)
Which of the following statements must be true?
We know that f(x) is a decreasing function, this means that, as x increases, the value of f(x) decreases.
So, if there are two values in the domain a and b, such that a < b, we will have that:
f(a) > f(b).
Then the statement:
[ f(5) - f(1)]/(5 - 1) < 0
Is true, because f(1) is larger than f(5).
Which means that statement d ( f(5) < f(1)) is also true.
Then the two correct options are b and d.
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A quadratic function has its vertex at the point
(
2
,
−
10
)
(
2
,
-
10
)
. The function passes through the point
(
−
6
,
−
5
)
(
-
6
,
-
5
)
. Find the quadratic and linear coefficients and the constant term of the function.
the standard form equation is y=ax²+bx+c where a is the quadratic coefficient, b is the linear coefficient, and c is the constant coefficient.
therefore, for y = 5/16x² - 5x/4 -35/4
Quadratic coefficient = 5/16, linear coefficient = 5/4, constant term = -35/4
What are zeros ?
zeros denotes the factors of the given equation in other words the zeros of the function are the values that make the factors zero. The factors need to multiply out to give the original standard-form equation.
Polynomial roots are the same as polynomial zeros, so they can be found by factoring the quadratic equation into two linear factors, after which they can be equating to zero.
Its easiest to first start out with a vertex form equation because it can then be converted to a standard quadratic equation.
given a vertex at (2,-10) , and point of intersection at (6,-5), the equation can be set up like this in the form of :
y = a(x-h)²+ k
y = a(x-2)^2-10, as we know h and k from the vertex.
We also know y and x from the given point of intersection so a can be solved by substituting the values of x and y to get value of a.
y = a(x-2)²-10
-5 = a(6-2)² - 10
16a = 10-5
a = 5/16
a = 5/16 which is also known as the quadratic coefficient because it is part of a second degree quantity and a Trinomial as a whole(quadratic).
since all the variables are known, you can expand the equation and set it to standard form :
y = 5/16(x-2)²-10
y = 5/16(x-2)² - 10
y = 5/16(x²+4-4x) -10
y = 5/16x² + 5/4 - 5x/4 - 10
y = 5/16x² - 5x/4 -35/4
For reference, the standard form equation is y=ax²+bx+c where a is the quadratic coefficient, b is the linear coefficient, and c is the constant coefficient.
In this instance, 5/16x² - 5x/4 -35/4 = ax²+bx+c
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Find x
A. 2.6
B 3.1
C 2.9
D 4
Answer:x=
Step-by-step explanation:
Which of the following equations represents a linear function?
Question 8 options:
y =[tex]\sqrt4{x}[/tex]
y =6/x
2x – 4y = 6
x3 – y = –2
Answer:
2x – 4y = 6
x3 – y = –2
Step-by-step explanation:
When graphing these two are linear.
Answer:
2x - 4y = –2
x3 – y = –2
Step-by-step explanation:
'cause they both have two unknown digits and this can be worked out with 3 methods;
1. substitution method
2. elimination method
3. grahical method
please rate brainliest if found helpful
question is in the photos
Answer:
n(AuB)=15
n(AnB)=8 is the answer!
Which equations have the same value of x as Two-thirds (6 x + 12) = negative 24? Select two options.
4 x + 8 = negative 24 , 9 x + 18 = negative 24 are equations have the same value of x .
What in mathematics is a linear equation?
There are only one or two variables in a linear equation. No variable can be multiplied by a number larger than one or used as the denominator of a fraction in a linear equation. All of the points fall on the same line when you identify the values that together make a linear equation true and plot those values on a coordinate grid.A - 4 x + 8 = negative 24
E - 4 x = negative 32
ARE CORRECT ON EDGE.
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The complete question is-
Which equations have the same value of x as Two-thirds (6 x + 12) = negative 24? Select two options.
4 x + 8 = negative 24
9 x + 18 = negative 24
4 x = negative 16
StartFraction 18 x + 36 over 2 EndFraction = negative 24
4 x = negative 32
The tax on a $30 item is $1.50.
Find the tax on a $50 item.
Answer: $2.50
Step-by-step explanation: To find the tax rate, you need to divide 1.50 by 30
1.5/30 = .05, which is the percent taxed. To find the tax amount for a $50 item, you just need to multiply $50 by the tax rate, which is .05, to get $2.50
The upper arm length of males over 20
years old in the United States is approximately Normal with mean 39.1
centimeters (cm) and standard deviation 5.1
cm. Use the 68−95−99.7
rule to answer the following questions. (Start by making a sketch of the Normal distribution for upper arm lengths for this population.)
A normal plot shows the range of Iowa test scores for 68% of the data, 95% of the data and 99.7% of the data. About 68% of the distribution of scores ranges from 5.29 to 8.39. About 95% of the distribution of scores ranges from 3.74 to 9.94. About 99.7% of the distribution of scores ranges from 2.19 to 11.49. There is an annotation that One standard deviation is 1.55 and another annotation that 2.5% of sores are below 3.74.
What percentage of men over 20
have upper arm lengths greater than 44.2 cm?
Provide your answer to one decimal place.
Using the Empirical Rule, it is found that 16% of men over 20 have upper arm lengths greater than 44.2 cm.
What does the Empirical Rule state?It states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.Approximately 95% of the measures are within 2 standard deviations of the mean.Approximately 99.7% of the measures are within 3 standard deviations of the mean.For the distribution in this problem, we have that:
The mean is of 39.1 cm.The standard deviation is of 5.1 cm.Hence, 44.2 is one standard deviation above the mean, as 44.2 = 39.1 + 1 x 5.1.
The normal distribution is symmetric, meaning that 50% of the measures are above the mean and 50% are below. Of those measures above the mean, 68% are less than 44.2 and 32% are more than 44.2 cm, hence:
0.5 x 32 = 16%.
16% of men over 20 have upper arm lengths greater than 44.2 cm.
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11. Represent and Connect After a recycling
awareness program, the number of tons of
recyclable material taken to the landfill is
reduced by 13 tons per month. Represent
the total change in the tons of recyclable
material taken to the landfill after
10
7 months resulting from the awareness
program. Show your work.
The total change in the tons of recyclable material taken to the landfill after 10 7 months resulting from the awareness program = (x - 95.9) tons, where x is the initial amount.
In this question, we have been given after a recycling awareness program, the number of tons of recyclable material taken to the landfill is reduced by 13 tons per month.
We need to represent the total change in the tons of recyclable material taken to the landfill after 10 7 months resulting from the awareness program.
Given that reduction in materials = 13 7/10 tons per month
We rewrite the improper fraction 13 7/10 as a proper fraction.
13 7/10 = 137/10
Monthly reduction = 137/10 tons
After 7 months : (7 × 137/10)
= 959/10 tons
= 95.9 tons
Change in amount of material taken to the land fill:
Initial amount - amount after 7 months
If initial amount be x, then the change in amount = (x - 95.9) tons
So, we get an expression (x - 95.9)
Therefore, the total change in the tons of recyclable material taken to the landfill after 10 7 months resulting from the awareness program = (x - 95.9) tons, where x is the initial amount.
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Using company C’s phone plan, the cost of an overseas phone call is a $0.80 connection fee plus 23 cents per minute. If the total cost of the call is 7.93, how long is the phone call?
Answer: 31 Minutes
Step-by-step explanation:
Minus 0.80 from 7.93, and then divide 7.13 by 0.23 and you get 31
Choose the estimate closest to the length of a woman's hand : 30 cm, 200mm, or 20 mm. Which is the correct answer?
Answer:
200mm
Step-by-step explanation:
200mm can be rewritten as 20 cm
a womans hand is on average 17.3 cm
this is the closest estimate out of the three
Can y’all help me please??
Answer: 29/21
Quotient: 1
Reminder: 8
Step-by-step explanation:
Add up the amount of 7th graders playing instruments (not including drums) total and put that number under the amount of 8th graders playing a instrument.
Use the 1st digit 2 from dividend 29
21 & 29 squared root
Since 2 is less than 21, use the next digit 9 from dividend 29 and add 0 to the quotient. Find the closest multiple of 21 to 29.
1×21=21 is the nearest. Now subtract 21 from 29 to get reminder 8. Add 1 to quotient.
Since 8 is less than 21, stop the division. The reminder is 8. The topmost line 01 is the quotient. Remove all zeros at the start of the quotient to get the actual quotient 1.
find the coordinates of pint P along the directed line segment AB so that AP to PB is the give ratio 2 to 6
Coordinates of P is 8
Since 3+2 = 5, we are dividing line segment AB into 5 congruent parts with point P 3/5 of the way from A to B.
x-coordinate of P = x-coordinate of A + (3/5)(change in x from A to B) = -4 + (3/5)(20) = 8
y-coordinate of P = y-coordinate of A + (3/5)(change in y from A to B) = 8 + (3/5)(-10) = 2
P = (8,2)
In each axis, find the distance from A to B, apply the ratio to get the distance from A to P, and add that value to A.
Note the ratio: We are given the ratio of AP to PB as 3/2. This means that the ratio of AP to AB is 3/5
Here is is for the X-axis:
AB = 20
AP = 20 *3/5 = 12
So P = -4 + 12 = 8
It is one of the branches of geometry where the position of a point is defined using coordinates.
Coordinates are a set of values which helps to show the exact position of a point in the coordinate plane.
A coordinate plane is a 2D plane which is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.
It is used to divide any line into two parts, in m:n ratio
The number line which is also known as a Cartesian plane is divided into four quadrants by two axes perpendicular to each other, labelled as the x-axis (horizontal line) and the y-axis(vertical line).
The four quadrants along with their respective values are represented in the graph below-
Quadrant 1 : (+x, +y)
Quadrant 2 : (-x, +y)
Quadrant 3 : (-x, -y)
Quadrant 4 : (+x, -y)
The point at which the axes intersect is known as the origin. The location of any point on a plane is expressed by a pair of values (x, y) and these pairs are known as the coordinates.
How To Find Coordinates of a Point on Graph With Examples
A set of values that shows the exact position of a point in a two-dimensional coordinate plane are called the coordinates. These represent the exact location of a point on a coordinate graph having both x, y axes. You can check the definition of coordinates, step by step detailed procedure to find the coordinates of a point with solved examples.
Coordinates Definition
A pair of numbers that describe the exact position of a point on a cartesian plane by using the horizontal and vertical lines called the coordinates. Usually represented by (x, y) the x value and y value of the point on a graph. Every point or an ordered pair contains two coordinates. The first one is the x coordinate or abscissa and the second is the y coordinate or ordinate. The values of the coordinates of a point can be any positive or negative real number.
The other types of coordinates are map coordinates (north/south, east/west), three-dimensional coordinates, polar coordinates (distance, angle), etc. Detailed information about x coordinate, y coordinate of a point follows:
x‐coordinate (Abscissa): The first number or the number which is located to the left side of a comma in the point is the x coordinate of the ordered pair. It represents the amount of movement along the x-axis from the origin. The movement is to the right side if the number is positive and to the left side of the origin if the number is negative.
y‐coordinate (Ordinate): The number which is located to the right side of the comma in the ordered pair or the second number is known as the y coordinate of the ordered pair. This ordinate indicates the amount of movement along the y-axis. If the number is positive, then the movement is above the origin and the movement is below the origin if the number is negative.
Point on x-axis: A point on the x-axis means its movement along the horizontal line is always zero and the y-coordinate of all points on the x-axis is zero. Therefore, the coordinates of a point on the x-axis are of the form (x, 0).
Point on y-axis: A point on the y-axis means the distance from the y-axis is zero and the x coordinate of every point on the y-axis is zero. Hence, the coordinates of a point on the y-axis are (0, y).
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Wilson hires a financial analyst to analyse costs and profits for his cereal production business. The analyst determines that Wilson’s eventual profit function is given as: , where x is the number of bags of cereal produced. At what point or number of bags of cereal will Wilson’s profit start decreasing
If Wilson produces only one 1 bag, then his profit starts decreasing
How to determine the pointGiven the function;
Let f ( x ) = [tex]2x^4 - 4x^3 + 7[/tex]
Where;
x is the number of bags of cereal produced
[tex]f'x = 2x^4 - 4x^3 + 7[/tex]
[tex]f'(x) = 8x^3 - 12x^2[/tex]
Factorize the expression
[tex]f'(x) = 4x^2(2x - 3)[/tex]
If the value of x is decreasing, we have;
f ′ ( x ) ≤ 0
4x² (2x - 3) ≤ 0
If x² ≥ 0, then;
2x - 3 ≤ 0
x ≤ 3/ 2
With x as the number of bags
x ∈ N
x = 1 is the only possibility
Thus, if Wilson produces only one 1 bag, then his profit starts decreasing
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The complete question:
Wilson hires a financial analyst to analyse costs and profits for his cereal production business. The analyst determines that Wilson’s eventual profit function is given as: pi = 2x ^ 4 - 4x ^ 3 + 7, where x is the number of bags of cereal produced. At what point or number of bags of cereal will Wilson’s profit start decreasing
A factory bottles 360 bottles of juice in 5 minutes. Find the factory’s unit rate of bottles per minute.
Answer:
72
Step-by-step explanation:
let's begin by restating what we already know,
360 bottles of juice in 5 minutes
for goodness's sake let's abbreviate this
360 boj in 5 mins
RATIO TIME!
360 : 5
pay attention how I put the BOJ (bottles of juice) first and the time last
now to find how many boj per min. we will say
[tex]\frac{1}{5} (360: 5)[/tex]
72:1
so, we now know that the factory of juice produces 72 bottles of juices per minute ( that's ALOT of juices per minute imo)
^_^ hope this helps, happy learning
PLEASE HELP ME FIGURE THIS OUT
Cycling.
The graph below shows the ages of the top five male finishers in the Mt. Washington Auto Road Bicycle Hillclimb each year from 2017 through 2021.
1. Write the relation of this situation as a set of ordered pairs in terms of (age, finishing place).
2. Identify the domain and range of the relation.
3. Do the ordered pairs represent a function? Explain.
Answer:From the given table, we have that:
1. The relation of the situation is: (20,2), (22.5, 5), (25,4), (27.5, 4), (29,4), (29,5), (30,1), (30,2), (30,3), (30,4), (30,5), (32.5, 1), (32.5, 3), (35,4), (40,2), (42.5, 3).
2. The domain is {20, 22.5, 25, 27.5, 29, 30, 32.5, 35, 40, 42.5} and the range is {1, 2, 3, 4, 5}.
3. There are inputs such as 25, 29, 30 and 32.5 that are mapped to multiple outputs, hence the relation does not represent a function.
What is the relation of this situation?
To build the relation, we look at the graph, and write all pairs of (Age, Finishing Place), as follows:
(20,2), (22.5, 5), (25,4), (27.5, 4), (29,4), (29,5), (30,1), (30,2), (30,3), (30,4), (30,5), (32.5, 1), (32.5, 3), (35,4), (40,2), (42.5, 3).
What are the domain and the range?
The domain of a relation is the set that contains all possible input values for the values, that is, the values of x.
The range of a relation is the set that contains all possible output values for the values, that is, the values of y.
Hence, for the given relation:
The domain is {20, 22.5, 25, 27.5, 29, 30, 32.5, 35, 40, 42.5} and the range is {1, 2, 3, 4, 5}.
When does a relation represents a function?
A relation represents a function if each value of the input is mapped to only one value of the output.
For this problem, we have that:
There are inputs such as 25, 29, 30 and 32.5 that are mapped to multiple outputs, hence the relation does not represent a function.
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Step-by-step explanation:
Prove that:
( 1 - tan^4 A)cos^4 A = 1 - 2 sin^2 A
Here we go ~
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
[tex]\qquad \sf \dashrightarrow \: (1 - \tan {}^{4} (a) ) \cos {}^{4} (a) [/tex]
[tex]\qquad \sf \dashrightarrow \: (1 + \tan {}^{2} (a) )(1 - { \tan}^{2} (a)) \cos {}^{4}(a ) [/tex]
[ a² - b² = (a + b)(a - b) ]
[tex]\qquad \sf \dashrightarrow \: ( \sec {}^{2} (a) )(1 - ( \sec{}^{2} (a) - 1) )\cos {}^{4} (a) [/tex]
[ sec² a = 1 + tan² a, so : tan² a = sec²a - 1 ]
[tex]\qquad \sf \dashrightarrow \: \bigg( \dfrac{1}{{}cos^{2} (a)} \bigg)(2 - \sec{}^{2} (a) ) \cos {}^{4} (a) [/tex]
[tex]\qquad \sf \dashrightarrow \: \bigg(2 - \dfrac{1}{ \cos {}^{2} (a) } \bigg) \cos {}^{2} (a) [/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{2 \cos {}^{2} (a) - 1}{ \cos {}^{2} (a) } \times \cos {}^{2} (a) [/tex]
[tex]\qquad \sf \dashrightarrow \: 2 \cos {}^{2} (a) - 1[/tex]
[tex]\qquad \sf \dashrightarrow \: 2(1 - \sin {}^{2} (a) ) - 1[/tex]
[ sin²a + cos² a = 1, hence sin²a = 1 - cos²a ]
[tex]\qquad \sf \dashrightarrow \: 2 - 2 \sin {}^{2} (a) - 1[/tex]
[tex]\qquad \sf \dashrightarrow \: 1 - 2 \sin {}^{2} (a) [/tex]
Answer:
See proof below
Step-by-step explanation:
Prove [tex]\left(\:1\:-\:tan^4A\right)cos^4A\:=\:1\:-\:2\:sin^2A[/tex]
[tex]\left(1-\tan ^4\left(A\right)\right)\cos ^4\left(A\right)[/tex] can be expressed in sin, cos terms
Use the trigonometric identity [tex]\tan \left(x\right)=\frac{\sin \left(x\right)}{\cos \left(x\right)}[/tex]
[tex]\left(1-\tan ^4\left(A\right)\right)\cos ^4\left(A\right) = \left(1-\left(\frac{\sin \left(A\right)}{\cos \left(A\right)}\right)^4\right)\cos ^4\left(A\right)[/tex]
[tex]\mathrm{Simplify}\:\left(1-\left(\frac{\sin \left(A\right)}{\cos \left(A\right)}\right)^4\right)\cos ^4\left(A\right)[/tex]
[tex]\mathrm{Apply\:exponent\:rule}:\quad \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}[/tex]
= [tex]\left(1-\frac{\sin ^4\left(A\right)}{\cos ^4\left(A\right)}\right)\cos ^4\left(A\right)[/tex]
Multiplying the expression in parentheses by [tex]\cos ^4\left(A\right)[/tex] we get
[tex]\frac{\cos ^4\left(A\right)-\sin ^4\left(A\right)}{\cos ^4\left(A\right)}\cos ^4\left(A\right)[/tex]
Cancel the common factor [tex]\cos ^4\left(A\right)[/tex]
This gives us
[tex]\cos ^4\left(A\right)-\sin ^4\left(A\right)[/tex]
Now,
[tex]\sin ^4\left(A\right)=\left(\sin ^2\left(A\right)\right)^2[/tex]
[tex]\cos ^4\left(A\right)=\left(\cos ^2\left(A\right)\right)^2[/tex]
[tex]\:\cos ^4\left(A\right)-\sin ^4\left(A\right)[/tex] = [tex]\left(\cos ^2\left(A\right)\right)^2-\left(\sin ^2\left(A\right)\right)^2[/tex]
[tex]\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)[/tex]
[tex]\left(\cos ^2\left(A\right)\right)^2-\left(\sin ^2\left(A\right)\right)^2=\left(\cos ^2\left(A\right)+\sin ^2\left(A\right)\right)\left(\cos ^2\left(A\right)-\sin ^2\left(A\right)\right)[/tex]
= [tex]\cos ^2\left(A\right)-\sin ^2\left(A\right)[/tex] [tex]\textrm{ since }\cos ^2\left(A\right)+\sin ^2\left(A\right)[/tex] = 1
Using the fact that [tex]\cos ^2\left(A\right)=1-\sin ^2\left(A\right)[/tex]
we get
[tex]\cos ^2\left(A\right)-\sin ^2\left(A\right) = 1-\sin ^2\left(A\right)-\sin ^2\left(A\right)\\\\= 1-2\sin ^2\left(A\right)[/tex]
Proved
Write the following in terms of sin x and cos x ; then simplify if possible. sec x csc x cot x =
The expression sec x csc x cot x in terms of sin x and cos x is
1/ (sin x)^2.
According to the given question.
We have an expression sec x csc x cot x.
Here, we have to write the above expression in terms of sinx and cosx.
As we know that,
sec x = 1/cos x
csc x = 1/sin x
cot x = cos x/ sin x
Thereofore, the expression sec x csc x cot x in terms of sin x and cos x is given by
sec x csc x cot x
= (1/cos x) (1/sinx) (cosx/ sinx)
= 1/ (sin x)^2
Hence, the expression sec x csc x cot x in terms of sin x and cos x is
1/ (sin x)^2.
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A jar contains 100 marbles. There are 21 blue marbles, 19 green marbles, 37 red marbles, and 23 yellow marbles. What is the probability of randomly selecting a yellow marble? Enter the correct answer
Answer:
23% or 23/100
Step-by-step explanation:
Since there are 23 in 100 is is 23/100 or 23%
Answer:
4.348%
Step-by-step explanation:
blue marbles = 19
yellow marbles = 23
probably of getting yellow = 23/100
= 4.34782608696
then you round then number to three decimal places and there you go
What is the area of the polygon if the side length of the square is 4
Answer:
16
Step-by-step explanation: This is because when we look at the square we realize by definition it is a 4-sided shape with 4 equal side lengths this means that if one side is 4 all the 4 sides of a square are also 4 and in this case, we would do length times width and get an answer of an area of 16 units.
Simplify, if possible.
8ab² +3ab+2a-3b+5
A. The expression is in its simplest form.
B. -10ab² +5
2
C. 8ab² + 2ab +5
D.
8ab²-3ab+5
Please select the best answer from the choices provided
Answer:
A. The expression is in its simplest form.
Step-by-step explanation:
Answer:
i tried this i think the answer is 11a plus 2a subract3b ppus 5
two classes each with 21 students were given a physical fitness test. the result of the number of pull ups performed in 30 seconds were recorded in the table below
Based on the results of the physical fitness test, the reason why we are unable to calculate the mean number of pull-us done by the students in each class is that we don't have the exact number of pull-ups done by each student.
What is needed to calculate mean?To calculate the simple mean of a distribution of numbers, we would need the value of all the numbers to be known. These numbers will then be summed up and divided by the number of the distribution.
In this case of the physical fitness test, the number of pull-ups is not known for all the students as there are some that either did below 5 or above 10 and we don't know the exact number of pull-ups done.
As a result, we are unable to calculate the mean.
Question is:
Explain why we are unable to calculate the mean number of pull-ups done by the students in each class.
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1. Let f be the function given by f(x)= X/ √x²-4 Find the domain of f.
1/|2x - 9|≤5
How to solve the inequality
Answer:
5<x<7
Step-by-step explanation:
Hey there !
firstly, in inequality; we must know that we should put the x alone.
so, in order to put the x alone; we should do the following process,
1</2x-9/<5
here,
adding +9 in all sides, we get;
=1+9<2x-9+9<5+9
=10<2x<14
dividing it by 2;we get
=10/2<2x/2<14/2
=5<x<7
This is the following answer. hope it helps!
Thank you!
What is the image of the point (-7,-6) after a rotation of 270° counterclockwise
about the origin?
Submit Answer
Drivsar Police Tormer Sondico
hp
attempt 2 out of 2
Answer:
(-6, 7)
Step-by-step explanation:
90 degrees counterclockwise / 270 degrees clockwise:
(x,y) -> (-y,x)
180 degrees counterclockwise / 180 degrees clockwise:
(x,y) -> (-x,-y)
270 degrees counterclockwise / 90 degrees clockwise:
(x,y) -> (y,-x)
i need the scientific notation of 0.0000018(430,000,000) over 0.00008(0.0075)
Answer:
1.29 x [tex]10^{9}[/tex]
Step-by-step explanation:
{(1.8 x 10^-6) x (4.3 x 10^8)} / [(8 x 10^-5) x (7.5 x 10^-3)]
[(1.8 x 4.3)x(10^-6 x 8)] / [(8 x 7.5) x(10^-5 x 10^ -3)]
(.129 x 10^[2-(-8)]
.129 x 10^10
1.29 x 10^-1 x 10^10
1.29 10^9
Determine whether the quadratic function shown below has a minimum or
maximum, then determine the minimum or maximum value of the functio
ƒ(x) = x² + 6x + 7
Answer:
Minimum = (-3, -2)
Step-by-step explanation:
Standard form of a quadratic function:
[tex]f(x)=ax^2+bx+c[/tex]
If a > 0 the parabola opens upwards and the curve has a minimum point.
If a < 0 the parabola opens downwards and curve has a maximum point.
Given function:
[tex]f(x)=x^2+6x+7[/tex]
As a > 0, the parabola opens upwards and so the curve has a minimum point.
The minimum/maximum point of a quadratic function is its vertex.
Vertex form of a quadratic function:
[tex]f(x)=(x-h)^2+k[/tex]
Where (h, k) is the vertex.
To rewrite the given function in vertex form, complete the square.
Add and subtract the square of half the coefficient of the term in x:
[tex]\implies f(x)=x^2+6x+7 +\left(\dfrac{6}{2}\right)^2-\left(\dfrac{6}{2}\right)^2[/tex]
[tex]\implies f(x)=x^2+6x+7 +9-9[/tex]
[tex]\implies f(x)=x^2+6x+9+(7 -9)[/tex]
[tex]\implies f(x)=x^2+6x+9-2[/tex]
Factor the perfect square trinomial formed by x²+6x+9:
[tex]\implies f(x)=(x+3)^2-2[/tex]
Compare with the vertex form:
h = -3k = -2Therefore, the vertex is (-3, -2) and so the minimum value of the given function is (-3, -2).
please help simplify !
Answer:
B
Step-by-step explanation:
using the rule of exponents
[tex]a^{m}[/tex] ÷ [tex]a^{n}[/tex] = [tex]a^{(m-n)}[/tex] , then
[tex]6^{9}[/tex] ÷ 6³ = [tex]6^{(9-3)}[/tex] = [tex]6^{6}[/tex]
Consider the relationship chart for the a fast-food restaurant,
Assume that the areas required for each department are:
Department Area Required (Square feet)
(CB) 300
(CF) 200
(PS) 200
(DD) 200
(CS) 300
Assume facility dimension of 6 (horizontal) by 8 (vertical) squares, where each square is 5 feet on a side. As a result, for example the CB department requires 12 squares. Develop a layout for the fast-food restaurant.
The layout of the fast-food restaurant of dimensions 6 by 8 5 feet squares is presented in the attached table created with Sheets.
How can the required layout be found?The dimensions of the facility are;
Horizontal = 6 squares
Vertical = 8 squares
The side length of each square = 5 feet
Therefore;
Area of each square = 5² ft.² = 25 ft.²
Number of squares, n, required by each dependent are therefore;
CB department, n = 300 ÷ 25 = 12 squares
CF department, n = 200 ÷ 25 = 8 squares
PS department, n = 8 squares
DD department, n = 8 squares
CS department, n = 12 squares
A layout for the fast-food restaurant is therefore;
The first three vertical columns of 8 squares each are occupied by the CF, PS, and DD departments. The remaining 3 by 8 squares are occupied by the CB department, (3 by 4 squares), and the CS department, (3 by 4 squares)Please see the attached table layout created using Sheets.
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