Answer:
A vector quantity is a quantity that has both magnitude and direction.
Explanation:
A car with a velocity of 30 m/s accelerates uniformly at the rate of 2.0 m/s2 for 10 s. What is its final velocity?
Which phrase describes speed? A. A quantity with direction only B.A vector quantity C.A scalar quantity D.A quantity with no units
Answer:
C. A scalar quantity
Explanation:
Speed does not have a direction. Speed with a direction is known as velocity.Vector quantities are quantities with magnitude and direction. As stated before, speed does not have a direction.Speed has a SI unit of m/s (meters per second).Therefore, the answer is C.
What resistance does a 25 W light bulb have if 12.6 V is applied to it?
(3 marks)
Answer:
Explanation:
W = 25 Watts
V = 12.6 Volts
I = ? I is the current in amperes.
Solution
25 = 12.6 * I
I = 25 / 12.6
I = 1.98 amperes
V = 12.6
I = 1.98
R = ??
V = I * R
12.6 = 1.98 * R
R = 12.6 / 1.98
R = 6.35 ohms
on which temperature scale does the average kinetic energy of molecules double when the temperature doubles?
Answer:
where are the choices i think 100% that is my opinion
A large cooler full of ice and drinks has a mass of 105 kg and a coefficient of static friction with the floor of 0.688. How much force will be required to move the cooler across the ground?
Answer:
Explanation: actually for moving it in an CONSTANT velocity u need a zero accleration
F-f=ma,a=0 hence F=f=Nα=mgα=1,495.63 N
A quarter is flipped from a height of 1.45 m above the ground. How much time will it take to reach the ground if the person flipping the coin gave it a velocity of 10.32 m/s? Please answer in seconds and to the third decimal place.
It will take the quarter 0.151 seconds to reach the ground.
Given the following data:
Height = 1.45 metersInitial velocity = 10.32 m/sWe know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.
To find how much time it will take the quarter to reach the ground, we would use the second equation of motion.
Mathematically, the second equation of motion is given by the formula;
[tex]S = ut + \frac{1}{2} at^2[/tex]
Where:
S is the height or distance covered. u is the initial velocity. a is the acceleration. t is the time measured in seconds.Substituting the values into the formula, we have;
[tex]1.45 = 10.32(t) + \frac{1}{2} (9.8)t^2\\\\1.45 = 10.32t + 4.9t^2\\\\4.9t^2 + 10.32t - 1.45 = 0[/tex]
The standard form of a quadratic equation is:
[tex]ax^2 + bx + c = 0[/tex]
a = 4.9, b = 10.32 and c = 1.45
We would solve the above quadratic equation by using the quadratic equation formula;
[tex]x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}[/tex]
Substituting the values, we have;
[tex]t = \frac{-10.32\; \pm \;\sqrt{10.32^2\; - \;4(4.9)(1.45)}}{2(4.9)}\\\\t = \frac{-10.32\; \pm \;\sqrt{106.5024\; - \;28.42}}{9.8}\\\\t = \frac{-10.32\; \pm \;\sqrt{78.0824}}{9.8}\\\\t = \frac{-10.32\; \pm \;8.84}{9.8}\\\\t = \frac{-10.32\; + \;8.84}{9.8}\\\\t = \frac{1.48}{9.8}[/tex]
Time, t = 0.151 seconds.
Therefore, it will take the quarter 0.151 seconds to reach the ground.
Read more: https://brainly.com/question/8898885
what is atmospheric pressure
Answer:
the pressure within the atmosphere of Earth
Explanation:
Atmospheric pressure is a force in an area pushed against a surface by the weight of the atmosphere of the earth.
will give correct answer brainliest
Which factors below will increase the momentum of a rolling ball of constant mass m? (Select only the answers that will increase the momentum of the ball.) Moving from a flat surface to moving downhill. Colliding with a ball of much lower mass moving in the opposite direction of the ball. A moving object traveling in the same direction as the ball colliding with it. Rolling uphill onto an inclined surface. Rolling onto a surface with high amounts of friction with the ball.
In order to increase the momentum of the ball, you have to increase its speed.
The first and third choices on the list ('A' and 'C') will do that.
The factors that will increase momentum of a rolling ball are:
A. Moving from a flat surface to moving downhill.
C. A moving object traveling in the same direction as the ball colliding with it.
Factors that increase momentum:The gravitational power of the Earth ready makes the ball speed up, and in this manner pick up speed.
If you increase either mass or velocity, the momentum of the object increases proportionally.
Thus, the factors that increase the momentum of a rolling ball are
A. Moving from a flat surface to moving downhill.
C. A moving object traveling in the same direction as the ball colliding with it.
Find more information about momentum here:
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PLZ HELP THIS IS FOR AN UNIT
Paul road his bike from the bottom of his street to his friend’s
house at the top of the hill on his street. He knew his PE was
5,000 J and ME was 25,000 J but wanted to find out his KE.
What is Paul’s KE energy on his bike ride to his friend’s house?
Answer:
5,000+25,000=
Explanation:
You need to plus it answer it now go girl #CarryOnLearning
helppppppppppppppppppppppp
Explanation:
v²= u² + 2as
v= final velocity.
u= initial velocity.
a= acceleration.
s= distance.
Un avión vuela hacia al norte a una velocidad de 90 m/s, pero un fuerte viento sopla hacia al este a 20 m/s y desvía su rumbo. Realiza los trazos y encuentra el vector resultante.
La adicion de vectores permite encontrar la repuesta para la velocidad resultante del avión es:
Modulo de la veloicdad v= 92,2 m/s Dirección de esta veloicdad 12,5º al Norte del Este
Las magnitudes vectoriales son cantidades tienen modulo y dirección, la velocidad es una de estas magnitudes, por lo tanto deben ser sumada usando álgebra vectorial.
Un sistema de referencia es un sistema desde donde realizar las mediciones, en este caso indican que usemos un sistema de los puntos cardinales.
En el adjunto podemos ver un esquema de los vectores velocidad y su resultante, realicemos el calculo de la resultante por método analíticos
Indican que el valor de la velocidad hacia el Este es vₓ = 20 m/s y la velocidad hacia el Norte es v_y = 90 m/s, por lo tanto, para la magnitud usamos el Teorema de Pitágoras
[tex]R= \sqrt{v_x^2 + v_y^2}[/tex]
R = [tex]\sqrt{20^2 + 90^2}[/tex]
R = 92,2 m/s
Para encontrar la direccion usemos trigonometría
tan θ = [tex]\frac{v_y}{v_x}[/tex]
θ = tan⁻¹ [tex]\frac{v_y}{v_x}[/tex]
θ = tan⁻¹ 20/90
θ = 12,5º
La dirección se lee 12,5º al Norte del Este
En conclusión usando la suma de vectores podemos encontrar la repuesta para la velocidad resultante del avión es:
v= 92,2 m/s con dirección 12,5º al Norte del EsteAprender mas aquí:
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3.1 Two waves A and B have frequencies 256 Hz and 1024 Hz respectively have amplitude in ratio 3:1 1.What is their ratio of frequencies? Which wave represents a higher pitch
2.which sound is louder
Answer:
1. the one with the raito
2. the one that stubbed their toe
Explanation:
what do the tropopause stratopause and mesopause have in common
Each is a zone of decreasing water vapor content within the atmosphere. ... Each is an interface between two layers of the atmosphere. Each is a point of maximum temperature in its layer of the atmosphere.
If y = ab, then find the maximum percentage error in the measurement of y.
Answer:
(Δa/a +Δb/b) × 100
Explanation:
Y= a/b
So, maximum percentage error
Δy/y = ( Δa/a + Δ b/b) × 100
Plz, Mark me as the brainlest
An object is traveling at a constant velocity of 8 m/s when it experiences a constant acceleration of 3.5 m/s2 for a time of 40 s. What will its velocity be after that acceleration? *
Answer:
140 m/s
Explanation:
v = u + at
v = 8 + 3.5(40) = 140 + 8 = 140
what is magnetic force?
i
Answer:
The force by which a substance (magnet) attracts a body(metals) towards it is called magnetic force
Answer:
Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion. The magnetic force between two moving charges may be described as the effect exerted upon either charge by a magnetic field created by the other.
Explanation:
Hope this helps you. Please mark as brainliest. It helps a lot. :)
why are astronauts weightless in the space station?
Answer:
Astronauts float around in space because there is no gravity in space. Everyone knows that the farther you get from Earth, the less the gravitational force is. Well, astronauts are so far from the Earth that gravity is so small. This is why NASA calls it microgravity.
Explanation:
42. The object in the figure is made of
a material of density 3000 kg/m3.
What is the tension in the rope,
which suspends the object, when
it is completely immersed in
water. The mass of the object is
200 kg.
TO?
Answerpov:
Explanation:
Describe how acceleration happens in the context of a collision.
Plz help<3
Answer:
(Hope this helps can I pls have brainlist (crown)☺️)
Explanation:
In a collision, both objects are subjected to a force that causes them to accelerate. Despite the fact that the forces are equal in magnitude and direction, the least massive item experiences the highest acceleration. When two objects of identical mass collide, they both experience the same acceleration.
A collision is a brief encounter between two or more bodies that results in a change in motion of the bodies involved as a result of internal forces acting between them. Forces are involved in collisions (there is a change in velocity ).
( In 1.5s the speed of the jumper increases from zero to 10.5 m/s. Calculate her average acceleration during this time.
Answer:
answer 7m/s^2
Explanation:
›»› The Acceleration of jumper = 7 m/s²
Given :
Initial velocity of jumper (u) = 0 m/s
Final velocity of jumper (v) = 10.5 m/s
Time taken by jumper (t) = 1.5 sec
To Find :
Acceleration of jumper (a) = ?
Required Solution :
→ Initial velocity (u) = 0 m/s (because jumper increase from zero)
† From first equation of motion
⇒ v = u + at
⇒ 10.5 = 0 + a × 1.5
⇒ 10.5 = 0 + 1.5a
⇒ 10.5 = 1.5a
⇒ a = 10.5/1.5
⇒ a = 7 m/s²
║Hence, the Acceleration of jumper is 7 m/s².║
\:
Additional Information :
★ First equation of motion :
⪼ v = u + at
Where,
v is the Final velocity in m/s.
u is the Initial velocity in m/s.
a is the Acceleration in m/s².
t is the Time taken in second.
★ Second equation of motion :
⪼ s = ut + ½ at²
Where,
s is the Distance travelled in m.
u is the Initial velocity in m/s.
a is the Acceleration in m/s².
★ Third equation of motion :
⪼ v² = u² + 2as
Where,
v is the Final velocity in m/s.
u is the Initial velocity in m/s.
a is the Acceleration in m/s².
s is the Distance travelled in m.
Can some one help me whith the answer
→ The charge in electron charge Q(e) is equal to the charge in coulombs Q(C) times 6.24150975⋅1018:
1C = 6.24150975⋅10¹⁸e
Q(e) = Q(C) × 6.24150975 × 10¹⁸
Q(e) = 96,500 × 6.24150975 × 10¹⁸
Q(e) = 6.02305690875 × 10²³
which is round off to
→ 6.03 × 10²³ electrons
Holly is conducting an experiment in which she changes the voltage across a circuit and records the relative brightness of a light bulb in the circuit. She takes notes in the notebook below.
How might these notes be useful?
A.
They could help her teacher to understand what she did in the experiment.
B.
They could help someone interested in conducting the same experiment.
C.
They could help her remember the experiment in the future.
D.
all of these
Reset Submit
Answer:
all of these
Explanation:
Answer:
D.all of there
Explanation:
A 100 kg physics teacher pushes a 1.0 kg physics textbook across a 222 kg physics demo table. The teacher applies 5.0 N of force to start the book sliding and 4.0 N to keep it sliding at a constant 0.30 m/s across the table.
Sketch a free body diagram showing all the forces acting on the book as the teacher pushes it.
1 . What is the magnitude of the weight of the book?
2. What is the magnitude of the normal force of the table on the book?
4. What is the coefficient of static friction between the book and the table?
5. What is the coefficient of kinetic friction between the book and the table?
6. If the teacher stops pushing the book, what is the magnitude of the net force on the book?
7. What acceleration does the book have after the teacher stopped pushing it?
8. How far does the book slide before coming to rest?
Answer:
1) 1kg
2) 9.81kg
4) 5N
5) 4N
6) 0N
7) 0N
8) 13
Explanation:
For the time between 5 and 9 seconds, calculate the velocity of the car.
How do longitudinal waves move
Answer:
in a direction parallel to the direction that the wave moves
Explanation:
Answer:
parallel to the direction....
a. They are measured from the Prime Meridian in a and direction. These lines are known also as
Answer:
meridians
Imaginary lines called meridians that measure distances East and West of the Prime Meridian. Longitude is different from latitude. Longitude may also be referred to as meridians. Although they measure the distance from East and West, the lines run in the direction of north and south.
Explanation:
hope this helps you if it does please mark brainiest
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a spacecraft that seems to be motionless in deep space is given some type of quick push. which statement describes what will happen?
An applied force applied causes a body such as the spacecraft to move. The magnitude of the force determines the change in the velocity
What will happen to the spacecraft is given by option C. from among the possible question options.
C. The spacecraft will begin to move and it will continue moving until it is stopped by an equal and opposite force
Reason:
The possible question options obtained from a similar question includes;
A. The spacecraft will move for some time then stop slowly
B. Air resistance will prevent the spacecraft from moving
C. The spacecraft will begin to move and the motion will continue until a force equal and opposite to the applied force stops it
D. The quick push will not cause the spacecraft to move, as a quick push works on Earth only
The state of the space craft = Motionless
Location of the spacecraft = Deep space
Type of force applied = Quick push
The statement that describes what will happen = Required
Solution;
Let F, represent the force applied, and let Δt be the duration of the applied force, we have;
The impulse of the force, F × Δt = m·(v₂ - v₁)
Where;
m = The mass of the spacecraft
v₁ = The initial velocity of the spacecraft = 0
v₂ = Final velocity of the spacecraft
Plugging in v₁ = 0, gives;
F × Δt = m·v₂
The space craft is given a velocity, v₂, and according to Newton's First Law of Motion, it continues moving in a straight line until another force acts on it
Therefore, the correct option is option C. The spacecraft will begin to move and the motion will continue until it is stopped by an equal and opposite force
Learn more about Newton's First Law of Motion here:
https://brainly.com/question/20841616
A bus slows down uniformly from 71.2 km/h
to ( km/h in 22.3 s.
How far does it travel before stopping?
Answer in units of m.
Answer:
1 km = 1,000 meters
Explanation:hey im in 7th grade and even i know that.i sorry but you seem not the smartest.jk thats a good question
What is the difference between thrust and applied force?
Answer:
Thrust acts on the accelerated object in the direction opposite to the applied force hence it accelerates the object in the direction opposite to the applied force. ... Its magnitude is equal to that of applied force. It always increases the velocity of the object.
Explanation: