What molecular shape is oxygen dibrimide

Answers

Answer 1

Answer:As predicted by VSEPR theory, the molecule adopts a "bent" molecular geometry similar to that of water.

Explanation:


Related Questions

Measuring the volume of air near 100°C

Answers

Answer:

[tex]1m ^ {3}[/tex]

Explanation:

UwU

Describing Rock Texture

Answers

The name "flint" is often the preferred name used for material with a very fine grain size and a slightly higher luster. These "fine-grained" materials break with greater predictability and produce a sharper edge. So the middle answer

Please answer 39 and beyond

Answers

39) 6.4109 g
40) 1.09 cm
41) 2.79 m
42) 29.74 g/mL
43) a. 6.730 x 10^-4
b. 5.0 x 10^4
c. 3.010 x 10^-6
44) a. 7050 g
b. 40000500 mg
c. 23500 mL

Using one or more of your senses to gather information is called
observing
c predicting
b inferring
d classifiying

Answers

Answer:

using one or more of your senses is Observing

How would a descriptive model of Earth's layers be categorized?
a. abstract model
b. prototype model
c. concrete model
d. conceptual model

Answers

The Earth can be divided into one of two ways – mechanically or chemically. Mechanically – or rheological, meaning the study of liquid states – it can be divided into the lithosphere, asthenosphere, mesospheric mantle, outer core, and the inner core.

Explanation:

Determine the number of moles of Al2O3 that contain 6.25 x 10^23 O atoms.​

Answers

Answer:

1.04 moles

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} \\[/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

[tex]n = \frac{6.25 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{6.25}{6.02} \\ = 1.0382059[/tex]

We have the final answer as

1.04 moles

Hope this helps you

please answer this correctly​

Answers

Answer:

5: tomato and vinegar

6: air


If 8.0 g of sulfur dioxide came in contact with a cloud containing 2.2 g of oxygen, indicate the
Limiting Reactant and calculate the theoretical yield (in grams) of sulfur trioxide produced.

Answers

Answer:

Limiting reactant= SO₂, Theoretical yield = 9.6g SO₃

Explanation:

The first step is is to find the limiting reactant; you do this using stoichiometry.

The reactant that produces the smallest amount of sulfur trioxide SO₃, is the limiting reactant.

In this problem, SO₂ is the limiting reactant.

Now to find the theoretical yield we will use the smallest value of SO₃.

I have uploaded a picture to better illustrate the problem and hope it helps.

Help Help Help!:

Which option would be an appropriate model of nuclear fission?

A. dividing a stack of paper equally between two people

B. taking a teaspoon of sugar from a bowl

C. disturbing a drop of water such that it breaks into smaller droplets

D. cutting a cake in half

Answers

Answer:

c

Explanation:

because your separating the atoms in the water

The appropriate model for nuclear fission is disturbing a drop of water such that it breaks into smaller droplets.

Nuclear fission refers to the disintegration of a large nucleus when it is bombarded with a small particle.

Usually, the protons in the nucleus repel each other strongly. Hence, as the atomic number of atoms continues to increase, this repulsion exceeds the nuclear attractive force causing the atom to disintegrate into smaller fragments called daughter nuclei when disturbed just as a drop of water such that it breaks into smaller droplets  when disturbed.

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Nitroglycerine, used to treat patients with angina, is prescribed for a patient by IV at a rate of 2.10 x 102 ug/min. The IV bag
contains 50. mg nitroglycerine/250 mL D5W. How many milliliters per hour should the patient receive?

Answers

Given the flow rate and the amount of nitroglycerine contained in the IV bag, the patient should receive 63 milliliters per hours.

Rate of prescribed dose by IV: [tex]2.10*10^2 ug/min = 210ug/min[/tex]

Available: [tex]50mg nitroglycerine = 50000ug[/tex]

Available Volume: [tex]150mL[/tex]

Hence, [tex]50000ug = 250ml[/tex]

and volume for [tex]210ug = x[/tex]

We cross multiply to find x

[tex]x = \frac{210ug * 250mL}{50000ug} \\\\x = 1.05mL[/tex]

Meaning that in a single minute, 1.05mL is been infused into the patient

Now, for an hour, ( 60 minutes ) the volume infused will be;

[tex]1min = 1.05mL[/tex]

[tex]60min = x[/tex]

We cross multiply to find x

[tex]x = \frac{1.05mL*60min}{1min}\\\\x = 63mL[/tex]

Therefore, given the flow rate and the amount of nitroglycerine contained in the IV bag, the patient should receive 63 milliliters per hours.

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HELP LAST ATTEMPT !?!!

Answers

Answer:

111Cd 12.80% stable

Explanation:

Maybe?

Which element in row 6 of the periodic table has the largest radius

Answers

Answer:

Cesium atomic number 55

PLS GUYS HELP!!!! Examine the table with the distances and times recorded for five different trains. Calculate the average speed for each train and select the correct answer choices. Select ALL that apply.

Answers

Answer:

A: Train I had the fastest average speed

C: Trains II and V had the same average speed

E: Trains III and IV had the same average speed

Explanation:

Describe how you will separate suspension from colloidal solution?

Answers

Answer:Unlike those in a suspension, particles in a colloid do not separate when sitting still. The particles in a suspension may be separated by filtration unlike those in a colloid. Colloids are able to scatter light, but suspensions cannot transmit light

Write a balanced chemical equation for the standard formation reaction of gaseous nitrogen monoxide (NO). Please help me

Answers

Answer:

N2 + O2 ------------->2NO(Balanced Reaction)

A balanced chemical equation for the standard formation reaction of gaseous nitrogen monoxide (NO) -

1/2 [tex]N_{2}[/tex] (g)   + 1/2 [tex]O_2[/tex] (g)   -----------------> NO (g)

Synthesis or formation reactions involve the combination of two or more substances that will react. There is only one product of a synthesis reaction.

Chemical reactions involve the rearrangement of electrons between elements resulting in the formation of a new substance.in a standard formation reaction, one mole of a substance is produced from its elements in their standard states.Standard formation reaction at 25 degrees C and 1 atm pressure.

1/2 [tex]N_{2}[/tex] (g)   + 1/2 [tex]O_2[/tex] (g)   -----------------> NO (g)

Thus, A balanced chemical equation for the standard formation reaction of gaseous nitrogen monoxide (NO) -

1/2 [tex]N_{2}[/tex] (g)   + 1/2 [tex]O_2[/tex] (g)   -----------------> NO (g)

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Which types of energy can be TRANSFERRED? Select ALL that apply.

-thermal
-electromagnetic
-mechanical
-electrical

Answers

Help me first ok? With my work

The element radium has a mass number of 226 and an atomic number of 88. How many neutrons does an atom of radium have?

A. 226.
B. 88.
C. 138.
D. 314.

Answers

Answer:

if you subtract 88 from 226 you get 138

so uour answer would be C.

Answer:

138

the conversion of an atom of one element into a different element through nuclear changes

A nuclear equation is balanced according to mass number. A chemical equation is balanced according to the total mass before and after the change

82

Some of the matter is converted to energy

Explanation:

I've used this website enough I think its time for me to give back.

Which of these is a function of all cells ?

A. To produce oxygen through photosynthesis
B. To combine with other cells to form tissues
C. To subdivide to form cells for sexual reproduction
D. To transfer genetic information from one generation to the next

Answers

Answer:

a because it help in protecting disease

The element that is in the same family as element C (gas) is likely to have which properties. 2 valence electrons, solid, metal 6 valence electrons, gas, nonmetal, 6 valence electrons, solid, nonmetal, 2 valence electrons, solid, nonmetal

Answers

Answer:

that element is likely to be a non metaland a gas

What is an ionic bond?

A. A bond that forms when electrons are transferred from one atom to another
B. A bond that forms when the electrons of two different atoms repel each other
C. A bond that forms when two atoms with neutral charges come close to one another
D. A bond that forms when one atoms nucleus comes close to another atoms electrons

Please answer!!! No links please!!!

Answers

Answer:

A. A bond that forms when electrons are transferred from one atom to another

[tex].[/tex]

Answer:

A. A bond that forms when electrons are transferred from one atom to another

is mercury homogeneous or heterogeneous?

Answers

Answer:

homogenous

Explanation:

its a pure element, so it is a pure substance

homogeneous
hope this helps!

Please help! How do you calculate the "average percent yield"? I just need the formula.

I already know how to find the theoretical yield and percent yield, I just don't know how to find the average or what it means by average.

Answers

Answer:

First make sure the both weights have the same units.

Take your experimental yield and divide it by the theoretical yield.

Multiply this value by 100 to find the percent yield.

Explanation:

For the Average. Add up the two percent yields that you found and divide by 2.

The table shows the densities of Earth's layers.


Which of these is most likely the density of Earth's mantle?

1.5-2.2 g/cm3

3.4-5.6 g/cm3

10.6-12.4 g/cm3

13.5-15.2 g/cm3

Answers

Answer:3.4 - 5.6

Explanation:

How are energy and work related?
O A. Work and energy are the same.
B. Work times energy is force.
C. Energy is the force needed to do work.
D. Energy is the capacity to do work.
SUBMI

Answers

Answer:

c

Explanation:

because u need the energy to be able to work

Hello there
i am looking for some quick help on this question thank you.


Liquid B has a mass of 75 g and a volume of 25 ml. What is liquid B's density?

1: .33 g/ml

2: 3 g/ml

3: 75 g

4: 25 ml



i will give brainliest if able to.

Answers

if density = m(mass) / v(volume) then the answer would be 3

PLEASE HELP ME WITH THID IFK IT!! ILL GIVE YOU EXTRA POINTS

Answers

But a check at the bottom and x at the top

In a living organism, the organic material contains 0.22 Bq of 14C per gram of carbon. A sample of charcoal from a campfire contains 0.055 Bq of 14C per gram of carbon. How long ago was this campfire in use? (14C half-life is 5730 yr)

Answers

Answer:

6

Explanation:

The age of the charcoal sample in the campfire in use is equal to the time taken for the decay of 0.22 of C-14 to 0.055 Bq. Hence its age is 11552.45 years.

What is radioactive decay?

Unstable radioactive isotopes of atoms undergo nuclear decay by the emission of charged particles such alpha or beta particles. Radioactive decay is a first order reaction. Thus, the decay constant is written as:

k = 1/t ln (W0 / Wt)

where W0 be the initial weight and Wt be the weight after time t.

The decay constant is related to the half life time of the sample by the expression:

k = 0.693 / t1/2.

Given that t1/2 of C-14 = 5730 years.

Thus, k = 0.693 /5730 = 0.00012 yr⁻¹.

Now, we can calculate the time t using the first order equation.

t = 1/k ln ln (W0 / Wt)

= [ ln (0.22 Bq/  0.055 Bq) ] / 0.00012 yr⁻¹

= 11552.4 years.

Therefore, the age of the sample of charcoal is 11552.4 years.

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Fermium-253 has a half-life of 0.334 seconds. How long will it take, in seconds, for a 96 atom sample to decay to 3 atoms?​

Answers

The half life time period of decaying 96 atom sample to 3 atoms of Fermium-253 if it has a half-life of 0.334 seconds is 1.67 s.

What is half life time period?

Half life time period is defined as the time interval which is required to decay the substance into half of its concentration. It is denoted by t(1/2).

As, atom decay in first half life time = 48 atoms.

Atom decay in second half life time = 24 atoms.

Atom decay in third half life time = 12 atoms.

Atom decay in fourth half life time = 6 atoms.

Atom decay in fifth half life time = 3 atoms.

So, we can see that in 5 half life time 96 atoms decay into 3 atoms.

So, time interval require to decay 96 atoms into 3 atoms is 5 × 0.334 = 1.67 s.

Thus, we concluded that the half life time period of decaying 96 atom sample to 3 atoms of Fermium-253 if it has a half-life of 0.334 seconds is 1.67 s.

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what is the common and IUPAC name for Oxygen? ​

Answers

Answer:

International Union of Pure and Applied Chemistry (IUPAC) justified ways how to name organic compounds [ hydrocarbons ].

Oxygen has only a molecular name which is dioxide

How many significant figures are in the following number? 3,000.0 x 10⁴ grams

Answers

Answer:

5 significant figures.

Explanation:

The decimal place makes the zeros significant.

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Find the equation of the line that passes through the point (6,14) and is parallel to the equation below.y =1 - 4OA.y = r - 18OB.y = - + 20y = x + 10OC.ODy =- 52 + 8ResetNext Question x + 2x +17=25 I need the answer and need do you know how to check if it's right Which of the following is a function and a relation? Question 4 Show the work please H ELP!!!Question 4 of 7Which stem-and-leaf plot represents the data sets shown?Set A Set B67 7271 6884 8562 7656 76A.The figure shows a stem-and-leaf plot for two sets Set Upper A and Set Upper B. Stem column is shown in the middle and the leaf columns for Set Upper A and Set Upper B are shown on the left and on the right respectively. For stem as 5, there is 6 in the left column, for stem as 6, there are 2 and 7 in the left column and 8 in the right column. For stem as 7, there is 1 in the left column and 2, 6, and 6 in the right column. For 8 as stem, there is 4 in the left column and 5 in the right column. To the right of this plot it is labeled 8 as stem and 4 and 5 on the left and right respectively, equals 84 and 85.B.The figure shows a stem-and-leaf plot for two sets Set Upper A and Set Upper B. Stem column is shown in the middle and the leaf columns for Set Upper A and Set Upper B are shown on the left and on the right respectively. For stem as 5, there is 6 in the left column, for stem as 6, there are 2 and 7 in the left column and 8 in the right column. For stem as 7, there is 1 in the left column and 2, and 6 in the right column. For 8 as stem, there are 4 and 8 in the left column and 5 in the right column. To the right of this plot it is labeled 7 as stem and 1 on the left and 2 and 6 on the right respectively, equals 71, 72 and 76.C.The figure shows a stem-and-leaf plot for two sets Set Upper A and Set Upper B. Stem column is shown in the middle and the leaf columns for Set Upper A and Set Upper B are shown on the left and on the right respectively. For stem as 5, there is 6 in the right column, for stem as 6, there are 2 and 7 in the right column and 8 in the left column. For stem as 7, there is 1 in the right column and 2, 6, and 6 in the left column. For 8 as stem, there is 4 in the right column and 9 in the left column. To the right of this plot it is labeled 8 as stem and 9 and 4 on the left and right respectively, equals 89 and 84.D.The figure shows a stem-and-leaf plot for two sets Set Upper A and Set Upper B. Stem column is shown in the middle and the leaf columns for Set Upper A and Set Upper B are shown on the left and on the right respectively. For stem as 5, there is 6 in the left column, for stem as 6, there are 2 and 7 in the left column and 8 in the right column. For stem as 7, there is 1 in the left column and 2, 6, and 6 in the right column. For 8 as stem, there is 4 in the left column. 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