What's the lateral area of the cylinder?

A. 251 yd.²

B. 314 yd.²

C. 503 yd.²

D. 13 yd.²

Answer:

What is the base, height? Is it a right triangle?

Answer:

The equation of a hyperbola with co-vertices at (0, 7) and (0, -7) and a transverse axis that is 12 units long is:

x²/36 - y²/49 = 1.

Therefore, the correct equation is: x²/36 - y²/49 = 1.

The equation of the new function after shifting 6 units right and 4 units down is f(x) = (x + 6)² - 4.

If we are to apply the changes below to the quadratic parent function, F(x) = x², what is the equation of the new function, given that we are to shift 6 units to the right and 4 units down? We will approach this question by following the steps outlined below.

Step 1: Identify the parent function F(x) = x² and its transformations

Step 2: Write the equation of the new function

Step 3: Simplify the new equation of the function.Step 1: Identify the parent function F(x) = x² and its transformations

Here, we are given the quadratic parent function F(x) = x² and two transformations: shift 6 units right and shift 4 units down.

The general equation for the horizontal and vertical shifts of a quadratic function is given by:f(x) = a(x - h)² + k, where a, h, and k are constants.

The value of a determines the direction of opening of the parabola, while (h, k) represents the vertex of the parabola.

If a > 0, the parabola opens upwards, while a < 0, the parabola opens downwards. If the values of (h, k) are positive, the parabola is shifted right and up, respectively. On the other hand, if the values of (h, k) are negative, the parabola is shifted left and down, respectively.

Therefore, given the quadratic parent function F(x) = x² and two transformations: shift 6 units right and shift 4 units down, we can represent these changes by the following:

a = 1 (since the parabola opens upwards)h = -6 (since we are shifting the parabola 6 units to the right)k = -4 (since we are shifting the parabola 4 units down)

Step 2: Write the equation of the new function Now that we have identified the constants a, h, and k, we can write the equation of the new function as follows:f(x) = a(x - h)² + kf(x) = 1(x - (-6))² + (-4)Replacing the constants a, h, and k in the equation, we have:f(x) = (x + 6)² - 4

Step 3: Simplify the new equation of the function.f(x) = (x + 6)² - 4= (x + 6)(x + 6) - 4= x² + 12x + 36 - 4= x² + 12x + 32Therefore, the equation of the new function after shifting 6 units right and 4 units down is f(x) = x² + 12x + 32.

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Answer:

B , D , A

Step-by-step explanation:

(4x³ - 4 + 7x) - (2x³ - x - 8)

distribute the first parenthesis by 1 and the second by - 1

= 4x³ - 4 + 7x - 2x³ + x + 8 ← collect like terms

= 2x³ + 8x + 4 ← equivalent to expression B

---------------------------------------------------------------

(- 3x² + [tex]x^{4}[/tex] + x) + (2[tex]x^{4}[/tex] - 7 + 4x) ← remove parenthesis

= - 3x² + [tex]x^{4}[/tex] + x + 2[tex]x^{4}[/tex] - 7 + 4x ← collect like terms

= 3[tex]x^{4}[/tex] - 3x² + 5x - 7 ← equivalent to expression D

------------------------------------------------------------------

(x² - 2x)(2x + 3)

each term in the second factor is multiplied by each term in the first factor, that is

x²(2x + 3) - 2x(2x + 3) ← distribute parenthesis

= 2x³ + 3x² - 4x² - 6x ← collect like terms

= 2x³ - x² - 6x ← equivalent to expression A

Answer:

3x - x²

Step-by-step explanation:

x(3 - x)

each term in the parenthesis is multiplied by the x outside. This is called the Distributive law

= (x × 3) + (x× - x)

= 3x + (- x²)

= 3x - x²

The answer is:

Work/explanation:

To simplify this expression, we will use the distributive property:

[tex]\sf{x(3-x)}[/tex]

Distribute the x:

[tex]\sf{x\cdot3-x\cdot x}[/tex]

[tex]\sf{3x-x^2}[/tex]

The measure of the outside angle F indicated in the figure is 61 degrees,

The external angle theorem states that "the measure of an angle formed by two secant lines, two tangent lines, or a secant line and a tangent line from a point outside the circle is half the difference of the measures of the intercepted arcs.

Expressed as:

Outside angle = 1/2 × ( major arc - minor arc )

From the figure:

Major arc = 195 degrees

Minor arc = 73 degrees

Outside angle F = ?

Plug the value of the minor and major arc into the above formula and solve for the outside angle F:

Outside angle = 1/2 × ( major arc - minor arc )

Outside angle = 1/2 × ( 195 - 73 )

Outside angle = 1/2 × ( 122 )

Outside angle = 122/2

Outside angle = 61°

Therefore, the outside angle measures 61 degrees.

Option C) 61° is the correct answer.

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Jacob bought 0.7 yards of ribbon.

To find out how many yards of ribbon Jacob bought, we need to determine 4/5 of the length of ribbon that Cindy bought.

Cindy bought 7/8 yard of ribbon. To find 4/5 of this length, we multiply 7/8 by 4/5:

(7/8) * (4/5) = (7 * 4) / (8 * 5) = 28/40

To simplify the fraction, we can divide both the numerator and denominator by their greatest common divisor, which is 4:

(28/4) / (40/4) = 7/10

Therefore, Jacob bought 7/10 yard of ribbon.

However, we can convert this fraction to a mixed number or decimal to express it in yards.

To convert 7/10 to a mixed number, we divide the numerator (7) by the denominator (10):

7 ÷ 10 = 0 with a remainder of 7

So, 7/10 is equivalent to 0 7/10 or 0.7 yards.

Therefore, Jacob bought 0.7 yards of ribbon.

In summary, Jacob bought 7/10 yard or 0.7 yards of ribbon.

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Answer:

Independent

Step-by-step explanation:

Flipping a coin is independent of each flip.

Answer:

Independent

Step-by-step explanation:

The flipping of two coins are an independent event. The reason for this is that one coin flip does not affect the outcome of the other flip. An example of a dependent event would be coat sales and weather, as cold weather would affect the amount of coats sold.

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When [tex]sin(\theta) = -0.42[/tex] and [tex]\pi < \theta < 3\pi/2[/tex], the value of [tex]cos(\theta)[/tex] is approximately 0.9071.

To find the value of cos([tex]\theta[/tex]) given[tex]sin(\theta) = -0.42[/tex] and [tex]\pi < \theta < 3\pi/2[/tex], we can use the trigonometric identity:

[tex]sin^2(\theta) + cos^2(\theta) = 1[/tex]

Since we are given sin(theta) = -0.42, we can substitute this value into the equation:

[tex](-0.42)^2 + cos^2(\theta) = 1[/tex]

Simplifying:

[tex]0.1764 + cos^2(\theta) = 1[/tex]

Subtracting 0.1764 from both sides:

[tex]cos^2(\theta) = 0.8236[/tex]

Taking the square root of both sides (since cos(theta) is positive):

[tex]cos(\theta) = \sqrt{(0.8236)} \\cos(\theta) = 0.9071[/tex]

Therefore, when [tex]sin(\theta) = -0.42[/tex] and [tex]\pi < \theta < 3\pi/2[/tex], the value of [tex]cos(\theta)[/tex]is approximately 0.9071.

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A sequence of transformations that maps quadrilateral MATH onto quadrilateral M"A"T"H" is a rotation of 180° about the origin and a translation by 1 unit left and 1 unit up.

In Mathematics and Geometry, the rotation of a point 180° about the origin in a clockwise or counterclockwise direction would produce a point that has these coordinates (-x, -y).

Additionally, the mapping rule for the rotation of a geometric figure 180° counterclockwise about the origin is given by this mathematical expression:

(x, y)                                            →            (-x, -y)

Coordinates of point M (2, 4)  →  Coordinates of point M' = (-2, -4)

By applying a translation to the image (M') vertically upward by 1 unit and horizontally left by 1 unit, the new coordinate M" of quadrilateral M"A"T"H" include the following:

(x, y)                               →                  (x - 1, y + 1)

M' (-2, -4)                        →                  (-2 - 1, -4 + 1) = M" (-3, -3)

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Answer:

x = 11.62

Step-by-step explanation:

opp / adj would be tangent, so the equation would be 4*tan(71) giving us 11.616, and rounding to the nearest hundredth gives you 11.62

Hope this helps :)

Answer:

8cm

Step-by-step explanation:

perimiter A = 11+11+4+4=30

perimiter B = 4+4+8+8=24

24+30=54

perimeter c =4+8+8+4+11+7+4=46

so perimiter of c is 8cm shorter than A and B total

hope this helps

The given number 132 from base 6 to base 10 by expanding its digits using powers of 6. The number 132 in base 6 is equal to 211 in base 5.

To express the number 132 in base 6 as a number in base 5, we need to convert the given number from base 6 to base 10 and then from base 10 to base 5.

In base 6, the digits range from 0 to 5. The positional values of the digits increase from right to left by powers of 6. Let's break down the given number 132 in base 6:

1 * 6^2 + 3 * 6^1 + 2 * 6^0

= 1 * 36 + 3 * 6 + 2 * 1

= 36 + 18 + 2

= 56 in base 10

Now, we have the number 56 in base 10. To convert it to base 5, we divide the number by 5 and record the remainders from right to left until the quotient becomes 0.

56 divided by 5 is 11 with a remainder of 1.

11 divided by 5 is 2 with a remainder of 1.

2 divided by 5 is 0 with a remainder of 2.

The remainders in reverse order give us 211 in base 5.

Therefore, the number 132 in base 6 is equal to 211 in base 5.

In summary, we converted the given number 132 from base 6 to base 10 by expanding its digits using powers of 6. Then, we divided the resulting number in base 10 by 5 to obtain the equivalent number in base 5 by recording the remainders. The final result is 211 in base 5.

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The statement that is correct option d: The spread of the number of activities for Class N is less than for Class M.

The term 'spread' in mathematics refers to the difference between the largest and smallest values in a dataset or the range of the data. It's the extent to which the dataset is spread out.The median is the center of a dataset. It's the number that lies in the middle of the sorted values. Half the values are greater than the median, while the other half are lesser than the median.

An outlier is a value that is very different from the other values in the dataset.In class M, there are no outliers. The distribution is skewed to the right since most students have only a few activities, and some have many. The median is between 2 and 3.

In class N, there are no outliers. Most students have a moderate number of activities, and the spread is less than in Class M. The median is between 5 and 6.Hence, the correct statement is The spread of the number of activities for Class N is less than for Class M.The correct answer is d

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Answer:

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It will take approximately 5.33 minutes for Jeff to catch up to Roger. Both Jeff and Roger will have run a distance of 1 mile.

Let's calculate the time it takes for Jeff to catch up to Roger and the distance each will have run.

First, we need to determine how much distance Roger covers during the 1-minute head start. Since Roger runs one mile in 9 minutes, in 1 minute, he would cover 1/9 of a mile.

Now, let's set up an equation to represent the time it takes for Jeff to catch up to Roger:

Distance covered by Jeff = Distance covered by Roger + Distance covered during the head start

Let's denote the time it takes for Jeff to catch up as t minutes. During this time, Jeff runs a distance of 1 mile, while Roger runs a distance of 1/9 of a mile (from the head start).

Distance covered by Jeff = Distance covered by Roger + Distance covered during the head start

1 mile = (1/9) mile + (6 minutes) × t × (1 mile/6 minutes)

Now, let's solve this equation to find the time it takes for Jeff to catch up:

1 = (1/9) + (1/6)t

Multiplying the equation by the least common multiple (LCM) of 9 and 6, which is 18, to clear the fractions:

18 = 2 + 3t

Subtracting 2 from both sides:

16 = 3t

Dividing by 3:

t = 16/3 = 5.33 minutes (rounded to two decimal places)

Therefore, it will take approximately 5.33 minutes for Jeff to catch up to Roger. Both Jeff and Roger will have run a distance of 1 mile.

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Answer:

x=30 degrees, 2x=60 degrees, 3x=90 degrees

Step-by-step explanation:

in a triangle the sum of angles is 180 so

x+2x+3x=180

6x=180

x=180/6

x=30

so the angle x is 30 degrees, the angle that is 2x is 60 degrees and the angle the angle 3x is 90

Based on the average scores and standard deviations, it appears that Millman's group still has room for improvement before they can reach the level of professional golfers.

To determine whether Millman's golfing group is ready to turn pro, we can compare their performance to that of professional golfers. Based on the provided data, Millman's group consists of 9 amateurs with an average score of 82 and a standard deviation of 2.6.

On the other hand, the professional golfers consist of 500 individuals with an average score of 71 and a standard deviation of 3.1.

To make a meaningful comparison, we can look at the average scores of the two groups. The average score is an indicator of the overall performance, with lower scores being better in golf.

In this case, the professional golfers have an average score of 71, while Millman's group has an average score of 82. This suggests that the professional golfers perform better, on average, than Millman's group.

However, it is also essential to consider the standard deviation, which measures the variability of scores within each group. A smaller standard deviation indicates less variation and greater consistency in performance.

The professional golfers have a standard deviation of 3.1, while Millman's group has a standard deviation of 2.6. This suggests that Millman's group has slightly less variation in scores compared to the professional golfers.

Overall, based on the average scores and standard deviations, it appears that Millman's group still has room for improvement before they can reach the level of professional golfers.

The professional golfers demonstrate better performance, on average, and a slightly higher variability in scores compared to Millman's group. Therefore, it would be advisable for Millman's group to continue refining their skills and striving to improve their scores before considering turning pro.

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The correct statements are: B. Circle F and circle D are similar and D. The center of circle F is (0, 3).

Explanation:

A. The radius of circle F is not 28. When a circle is translated, the radius remains the same. So, circle F has the same radius as circle D, which is 7.

B. Circle F and circle D are similar. Similarity means that the two shapes have the same shape but possibly different sizes. Since circle F is a translation of circle D, it has the same shape and proportions as circle D. Therefore, they are similar.

C. Circle F and circle D are not congruent. Congruence means that two shapes are identical in both shape and size. While circle F and circle D have the same shape, they have different positions due to the translation. Thus, they are not congruent.

D. The center of circle F is (0, 3). When a circle is translated horizontally by a certain amount, the x-coordinate of the center changes, while the y-coordinate remains the same. Since circle F is translated 2 units to the right, the x-coordinate of the center of circle F would be 2 + 0 = 2. As the y-coordinate remains the same, the center of circle F is (2, 3). Therefore, the statement is incorrect.

In summary, the correct statements are B and D. Circle F and circle D are similar, and the center of circle F is (0, 3). Therefore, Option B and D are correct.

The question was incomplete. find the full content below:

According to these three facts, which statements are true?

• Circle D has center (2, 3) and radius 7.

• Circle F is a translation of circle D, 2 units right.

• Circle F is a dilation of circle D with a scale factor of 4.

Select each correct answer.

A. The radius of circle F is 28.

B. Circle F and circle D are similar.

C. Circle F and circle D are congruent.

D. The center of circle F is (0, 3)

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The tangent and normal lines of the curve:

Case (i): y = (4 / 5) · x + 13 / 5

Case (ii): (x, y) = (0, 13 / 5)

Case (iii): y = - (5 / 4) · x + 35 / 4

In this problem we have the representation of a curve whose equations for tangent and normal lines must be found. Lines are expressions of the form:

y = m · x + b

Where:

Both tangent and normal lines are perpendicular, the relationship between the slopes of the two perpendicular lines is:

m · m' = - 1

Where:

The slope of the tangent line is found by evaluating the first derivative of the curve at intersection point.

Case (i) - First, determine the slope of the tangent line:

y = √(8 · x + 1)

y' = 4 / √(8 · x + 1)

y' = 4 / √25

y' = 4 / 5

Second, determine the intercept of the tangent line:

b = y - m · x

b = 5 - (4 / 5) · 3

b = 5 - 12 / 5

b = 13 / 5

Third, write the equation of the tangent line:

y = (4 / 5) · x + 13 / 5

Case (ii) - Find the coordinates of the intercept of the tangent line:

(x, y) = (0, 13 / 5)

Case (iii) - First, find the slope of the normal line:

m' = - 1 / (4 / 5)

m' = - 5 / 4

Second, determine the intercept of the normal line:

b = y - m' · x

b = 5 - (- 5 / 4) · 3

b = 5 + 15 / 4

b = 35 / 4

Third, write the equation of the normal line:

y = - (5 / 4) · x + 35 / 4

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The amount of medication needed for 30 days is approximately 59.84 tablets of carprofen.

To calculate the amount of carprofen medication needed for 30 days, we need to consider the prescribed dosage, the weight of the patient, and the concentration of the tablets.

The prescribed dosage is 2.2 mg/kg BID x 30d. This means that the patient should take 2.2 milligrams of carprofen per kilogram of body weight, twice a day, for 30 days.

The weight of the patient is 34 kilograms. So, we need to calculate the total amount of carprofen needed for the entire treatment period.

First, we calculate the daily dosage by multiplying the weight of the patient (34 kg) by the prescribed dosage (2.2 mg/kg).

Daily dosage = 34 kg * 2.2 mg/kg = 74.8 mg/day.

Since the medication is prescribed twice a day, we multiply the daily dosage by 2 to get the total dosage per day.

Total dosage per day = 74.8 mg/day * 2 = 149.6 mg/day.

Finally, to find the total amount of medication needed for 30 days, we multiply the total dosage per day by the number of days.

Total medication needed = 149.6 mg/day * 30 days = 4488 mg.

Since the concentration of the tablets is 75 mg, we divide the total medication needed by the tablet concentration to find the number of tablets required.

Number of tablets needed = 4488 mg / 75 mg = 59.84.

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If all the values in the series are the same, the A.M, G.M, and H.M are all equal and can be represented as A.M = G.M = H.M = x.

If all the values in the series are the same, the arithmetic mean (A.M), geometric mean (G.M), and harmonic mean (H.M) will all be equal.

Let's consider a series with the same value repeated n times, denoted as x:

Series: x, x, x, ..., x (n times)

Arithmetic Mean (A.M):

The arithmetic mean is calculated by summing all the values in the series and dividing by the total number of values. In this case, the sum of all the values is nx, and since there are n values, the arithmetic mean is (nx) / n = x. So, A.M = x.

Geometric Mean (G.M):

The geometric mean is calculated by taking the nth root of the product of all the values in the series. In this case, the product of all the values is x^n, and since there are n values, the nth root of x^n is x. So, G.M = x.

Harmonic Mean (H.M):

The harmonic mean is calculated by taking the reciprocal of the arithmetic mean of the reciprocals of all the values in the series. Since all the values are the same, the reciprocal of each value is 1/x. The arithmetic mean of the reciprocals is (1/x + 1/x + ... + 1/x) / n = (n/x) / n = 1/x. Taking the reciprocal of 1/x gives x. So, H.M = x.

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Answer:

There were 126 student tickets sold and 252 adult ticket sold.

Step-by-step explanation:

Let x be the number of adult tickets sold

y be the number of students tickets sold

Twice as many student tickets as adult tickets were sold

a.

x = 2y  ---equation 1

6x + 4y = 2016   ---equation 2

b.

Substitute equation 1 to equation 2

6(2y) + 4y = 2016

12y + 4y = 2016

16y = 2016

Divide both sides of the equation by 16

16y/16 = 2016/16

y = 126

Substitute y = 126 to equation 1

x = 2y

x = 2(126)

x = 252

The difference quotient of the function f(x) = 12x + 1 is 12.

The difference quotient of a function measures the average rate of change of the function between two points. To find the difference quotient of the function f(x) = 12x + 1, we can follow these steps:

Select two points on the function, let's call them x and x + h, where h is a small positive value.

Evaluate the function at those two points to get the corresponding y-values. For f(x) = 12x + 1, we have:

f(x) = 12x + 1

f(x + h) = 12(x + h) + 1

Calculate the difference quotient by subtracting the values and dividing by h:

[f(x + h) - f(x)] / h

= [(12(x + h) + 1) - (12x + 1)] / h

= [12x + 12h + 1 - 12x - 1] / h

= (12h) / h

= 12

In this case, since the function is linear with a slope of 12, the difference quotient is constant and equal to the slope of the function. This means that for every unit increase in x, the function f(x) increases by 12.

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The diagonal distance from home plate to third base is approximately √16,200 feet.

The correct answers are:

B. 90 feet

C. √16,200 feet

D. 180 feet.

In baseball, the bases are arranged in a square shape.

The distance between each base is 90 feet.

Therefore, the correct answer for the distance a player at first base has to throw to a player at third base is 90 feet (option B).

To find the diagonal distance from home plate to third base, we can use the Pythagorean theorem.

Since the area of the baseball field is a square, the diagonal distance represents the hypotenuse of a right triangles.

The two legs of the right triangle are the sides of the square, which are 90 feet each.

Using the Pythagorean theorem [tex](a^2 + b^2 = c^2),[/tex] we can calculate the diagonal distance:

a = b = 90 feet

[tex]c^2 = 90^2 + 90^2[/tex]

[tex]c^2 = 8,100 + 8,100[/tex]

[tex]c^2 = 16,200[/tex]

c = √16,200 feet (option C)

Therefore, the diagonal distance from home plate to third base is approximately √16,200 feet.

The options A, √180 feet, and 180 feet are incorrect because they do not represent the correct distances in the given scenario.

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The approximate solution to the equation 1/x-1 = |x-2| after three iterations of successive approximation is x ≈ 5/2 or x ≈ 2.5.

To solve the equation 1/x-1 = |x-2| using three iterations of successive approximation, we will start with an initial guess and refine it using an iterative process.

Given that the equation involves absolute value, we will consider two cases:

Case 1: x - 2 ≥ 0

In this case, |x-2| simplifies to x-2, and the equation becomes 1/(x-1) = x-2.

Case 2: x - 2 < 0

In this case, |x-2| simplifies to -(x-2), and the equation becomes 1/(x-1) = -(x-2).

Now, let's perform the successive approximation:

Iteration 1:

Let's start with an initial guess, x = 2.

Case 1: When x - 2 ≥ 0,

1/(2-1) = 2-2,

1/1 = 0,

which is not true.

Case 2: When x - 2 < 0,

1/(2-1) = -(2-2),

1/1 = 0,

which is not true.

Since our initial guess did not satisfy the equation in either case, we need to choose a different initial guess.

Iteration 2:

Let's try x = 3.

Case 1: When x - 2 ≥ 0,

1/(3-1) = 3-2,

1/2 = 1,

which is not true.

Case 2: When x - 2 < 0,

1/(3-1) = -(3-2),

1/2 = -1,

which is not true.

Again, our guess did not satisfy the equation in either case.

Iteration 3:

Let's try x = 2.5.

Case 1: When x - 2 ≥ 0,

1/(2.5-1) = 2.5-2,

1/1.5 = 0.5,

which is true.

Case 2: When x - 2 < 0,

1/(2.5-1) = -(2.5-2),

1/1.5 = -0.5,

which is not true.

Our guess of x = 2.5 satisfies the equation in Case 1.

Therefore, the approximate solution to the equation 1/x-1 = |x-2| after three iterations of successive approximation is x ≈ 5/2 or x ≈ 2.5.

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The area of quadrilateral QUAD is 2.5 square units.

To find the area of quadrilateral QUAD with vertices Q (-4, 3), U (3, 6), 1 (6, 3), and D (1, -4), we can use the Shoelace formula (also known as Gauss's area formula or the surveyor's formula).

The Shoelace formula states that the area of a polygon with vertices (x1, y1), (x2, y2), ..., (xn, yn) can be calculated as:

[tex]Area = 1/2 * |(x1y2 + x2y3 + ... + xny1) - (x2y1 + x3y2 + ... + x1yn)|[/tex]

Using this formula, we can calculate the area of quadrilateral QUAD as follows:

Area = [tex]1/2 * |(-46 + 33 + 6*(-4) + 13) - (33 + 6*(-4) + 1*(-4) + (-4)*3)|[/tex]

Simplifying the expression, we get:

[tex]Area = 1/2 * |(-24 + 9 - 24 + 3) - (9 - 24 - 4 - 12)|Area = 1/2 * |(-36) - (-31)|Area = 1/2 * |-36 + 31|Area = 1/2 * |-5|Area = 1/2 * 5Area = 5/2[/tex]

The area of quadrilateral QUAD is 2.5 square units.

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The area of quadrilateral QUAD is 17.5 square units.

The area of quadrilateral QUAD, we can use the Shoelace Formula, also known as the Gauss's Area Formula.

The formula states that if the coordinates of the vertices of a polygon are given in order, then the area of the polygon can be calculated using the following formula:

Area = 1/2 × |(x1y2 + x2y3 + ... + xn-1yn + xny1) - (y1x2 + y2x3 + ... + yn-1xn + ynx1)|

Let's apply this formula to find the area of quadrilateral QUAD:

Q (-4, 3)

U (3, 6)

A (6, 3)

D (1, -4)

Area = 1/2 × |(-4 × 6 + 3 × 3 + 6 × (-4) + 3 × (-1)) - (3 × 3 + 6 × (-4) + (-4) × (-1) + (-1) × (-4))|

Area = 1/2 × |(-24 + 9 - 24 - 3) - (9 - 24 + 4 + 4)|

Area = 1/2 × |(-42) - (-7)|

Area = 1/2 × |-42 + 7|

Area = 1/2 × |-35|

Area = 1/2 × 35

Area = 17.5

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The probability that less than 10 out of 15 cash register receipts will show the three food items ordered is approximately 0.166.

To calculate the probability that less than 10 out of 15 cash register receipts show that the hamburger, french fries, and a drink were ordered, we can use the binomial probability formula. The formula for the probability of obtaining exactly k successes in n trials is:

P(X = k) = (nCk) * p^k * (1 - p)^(n - k)

where:

P(X = k) is the probability of obtaining k successes,

n is the number of trials,

p is the probability of success in a single trial, and

(nCk) is the binomial coefficient, which represents the number of ways to choose k successes out of n trials.

In this case, we want to find the probability of less than 10 out of 15 receipts showing the three food items ordered. We need to calculate the probabilities for k = 0, 1, 2, ..., 9, and sum them up.

Let's calculate the probabilities using the formula:

P(X < 10) = P(X = 0) + P(X = 1) + P(X = 2) + ... + P(X = 9)

where:

n = 15 (number of trials),

p = 0.60 (probability of success, i.e., ordering hamburger, french fries, and a drink).

Using a binomial calculator or a statistical software, we can calculate each individual probability and then sum them up.  The result will be the probability that less than 10 out of 15 receipts show the three food items ordered.

The probability that less than 10 out of 15 cash register receipts will show the three food items ordered is approximately 0.166.

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Answer:

a. Let tomorrow's temperature be x

b.

[tex] |93 - x | < 10[/tex]

c.

[tex] - 10 < 93 - x < 10 \\ - 103 < - x < - 83 \\ 103 > x > 83[/tex]