Answer:
the car slows down
Explanation:
if 2 magnets were forced together vertically on the same poles and suddenly released, how high would the top magnet travel? The magnets are disc-shaped with a circumference of 6.5" and a mass of 8 lbs, the combined force of the magnets is 13,200lbs.
the velocity of an object must include these two things ________ and _________
will give brainlest
Answer:
The velocity of an object must include these two things displacement and time.
Explanation:
Hope this helps you. Have a nice day^_^
Please mark as brainliest. It helps a lot. :)
please answer me!!! asappp
Answer:
omg this is hard
Explanation:
Yes it is lol
An engine raises 120kg of water through a height of 40m in 30s.What is the power of the engine take gravity to be = 10m/s.
Answer:
1600 W
Explanation:
Power is the product of force and distance, divided by time.
P = (120 kg)(10 m/s²)(40 m)/(30 s) = 1600 kg·m²/s³ = 1600 W
Anne pushed a cart by 12 N. How far did the cart move if the work done was 9 J?
[tex]\\ \sf\longmapsto W=Fd[/tex]
[tex]\\ \sf\longmapsto d=\dfrac{W}{F}[/tex]
[tex]\\ \sf\longmapsto d=\dfrac{9}{12}=0.72m[/tex]
Answer:
Anne pushed a cart by 12 N.
● Force = 12 N
Work done is 9 J
● Work = 9 J
=> Work = Force × distance
[tex]=> distance = \frac{work}{force} [/tex]
[tex]=> distance = \frac{9}{2} [/tex]
[tex]=> distance = 0.72m[/tex]
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Kelvin is a unit of temperature, whereas ampere is a unit of current.
True or False
Answer:
Kelvin is a unit of temperature, whereas ampere is a unit of current.
True or False
Explanation:
true
Water is used to fill hot water bottles for
warming beds. A hot block of concrete
wrapped in a cloth can also be used.
Why are these two materials the best for
warming something up?
Worth 25 points!!!
Answer:
Because they both hold the heat
Si la fuerza de repulsión entre dos cargas es 18 × 1013
Answer:
Explanation:
F = kQq/r²
r = √(kQq/F)
a) r = √(8.899(10⁹)(8)(4) / 18(10¹³)) = 0.0397749... m
r = 40 mm
b) r = √(8.899(10⁹)(12)(3) / 18(10¹³)) = 0.0421876... m
r = 42 mm
Suppose that John lives on a square block that is 180 yards per side, and in the evenings, he walks with his dog around the block for a little exercise.
A) If John walks once around the block, what distance does he travel?
B) If John walks once around the block, what is his final displacement?
Answer:
It's A
Explanation:
Although I'm not sure about the second one, I'm sure the first one is A
3)(20pts) Un barco invasor se encuentra a 560m de un puerto de defensa, el puerto tiene cañones que
disparan con una velocidad de 82m/s. a) ¿Qué ángulo debe de tener el barco para poder golpear el
barco invasor? b) ¿Cuál es el tiempo de vuelo de las balas disparadas por el cañón utilizando el ángulo
de la respuesta "a"? c) ¿Qué tan lejos debe alejarse el barco invasor de la costa para lograr estar fuera
del alcance de los cañones?
a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.
b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.
c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.
a)
Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.
[tex]x=\frac{v_{i}^{2}sin(2\alpha)}{g}[/tex] (1)
Donde:
v(i) es la velocidad inicial del cañon (82 m/s)α es el ángulo de tirog es la gravedad (9.81 m/s²)x es el desplazamiento total (560 m)Lo que debemos hacer es depejar α de la ecuación 1
[tex]sin(2\alpha)=\frac{xg}{v_{i}^{2}}[/tex]
[tex]sin(2\alpha)=\frac{560*9.81}{82^{2}}[/tex]
[tex]sin(2\alpha)=0.82[/tex]
[tex]\alpha=\frac{sin^{-1}(0.82)}{2}[/tex]
[tex]\alpha=27.39^{\circ}[/tex]
Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.
b)
Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.
[tex]v_{x}=\frac{x}{t}[/tex]
La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:
[tex]v_{i}cos(\alpha)=\frac{x}{t}[/tex]
[tex]t=\frac{x}{v_{i}cos(\alpha)}[/tex]
[tex]t=\frac{560}{82cos(27.39)}[/tex]
[tex]t=7.69\: s[/tex]
El tiempo total de vuelo de las balas de cañon es de 7.69 s.
c)
Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.
Puedes encontrar más información sobre tiro parabólico aquí:
https://brainly.lat/tarea/3605927
Espero te haya sido de ayuda!
A 500 kg airplane wing is hanging on a rope from the ceiling. What is the tension force being supplied by the rope?
a.5000
b.2500
c.250
d.500
Answer:
a. 5000 N
Explanation:
If gravity is 10 m/s² and the wing is motionless.
F = ma = 500(10) = 5000 N
David was driving at a velocity of 5 m/s. He accelerates to a velocity of 8 m/s in 4 seconds. What is the acceleration?
Identify the given variables and the unknown
x distance
t time
Vi initial velocity
Vf final velocity
a acceleration
F force
If David was driving at a velocity of 5 m/s and accelerates to a velocity of 8 m/s in 4 seconds, David's acceleration is 0.75 [tex]m/s^2[/tex].
Given the following data:
Initial velocity, Vi = 5 m/sFinal velocity, Vf = 8 m/sTime, t = 4 seconds.To find David's acceleration:
Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
[tex]Acceleration = \frac{V_f\; - \;V_i}{t}[/tex]
Where:
Vf is the final velocity.Vi is the initial velocity.t is the time measured in seconds.Substituting the given parameters into the formula, we have;
[tex]Acceleration = \frac{8\; - \;5}{4}\\\\Acceleration = \frac{3}{4}[/tex]
Acceleration = 0.75 [tex]m/s^2[/tex].
Therefore, the David's acceleration is 0.75 [tex]m/s^2[/tex].
Read more: https://brainly.com/question/8898885
A particular car can go from rest to 90 kmh in 10 seconds. What is its
acceleration. (Show your calculation
Answer:
Im sorry i dont know But thank you for the points
40. What is the acceleration of a 10 kg object if a force of 3 N is applied to it?
a stone is dropped down an empty mine shaft. it takes 3 seconds to reach the bottom. assuming that the stone falls from rest and accelerates at 10m/s^2, calculate.
a) the maximum speed reached by the stone before hitting the bottom.
b) the average speed of the stone in flight.
c) the depth of the mine shaft.
Answer:
I think A. I had a similar question
Explanation:
which is an example of qualitative data?
A) the number of golfers who use callaway clubs
B) the scores of the golfers who use callaway clubs
C) the rating that the golfers give Callaway clubs
D) the number of putts per round of golfers using Callaway clubs
what are adaptations needed for animals to survive on grassland?
Answer:
short teeth, short hair, camoflauge, and speed
Explanation:
Answer:
speed and awareness
Explanation:
A ball rolls with a constant acceleration of 2.5 m/s^2 for 5.0 s with an initial velocity of 5.0 m/s. Calculate the
ball's distance from the starting point at 1.0 s intervals. Make a position-time graph for the object's motion. In
your response, show what you are given, the equation that you used, any algebra/work required, a table of
data, and your graph.
The kinematics allows finding the answers for the positions of the body as a function of time and making its graph are:
The positions according to time are in the table In the attachment we can see a graphic representation
Given parameters
The acceleration a = 2.5 m / s² Time t = 5.0 s The initial velocity vo = 5.0 m / sTo find
The distance each Dt = 1.0 s
Kinematics studies the motion of bodies, gives relationships between the position, velocity and acceleration of bodies, let's use the relationship
x = v₀ t + ½ a t²
Where x is the position, v or the initial velocity, at the acceleration and t is the time.
Let's substitute
x = 5 t + ½ 2.5 t²
x = 5 t + 1.25 t²
Let's calculate the position and write it in the table
t = 0 s x = 0 m
t = 1 s x = 5 1 + 1.25 1² = 6.25 m
t = 2 s x = 5 2 + 1.25 2² = 15 m
t = 3s x = 5 3 + 1.25 3² = 26.25 m
t = 4 s x = 5 4 + 1.25 4² = 40 m
t = 5 s x = 5 5 + 1.25 5² = 56.25 m
In the following table the time and positions of the body are given, these given are used for the attached graph
time (s) position (m)
0 0
1 6.25
2 15
3 26.25
4 40
5 56.25
In conclusion, using kinematics we can find the answers for the positions of the body as a function of time and make its graph are:
The positions according to time are in the tableIn the attachment we can see a graphic representation
Learn more here:
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the position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) determine the distance
Answer:
[tex] |d| = \sqrt{ {(x_{2} -x_{1})}^{2} + {(y_{2} -y_{1})}^{2} + {(z_{2} -z_{1})}^{2}} \\ = \sqrt{ {(6 - 2)}^{2} + {(3 - 0)}^{2} +{(5 - 8)}^{2} } \\ = \sqrt{16 + 9 + 9} \\ = \sqrt{34} [/tex]
The position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) the distance between ant and spider is 5.83 m.
What is Distance between two points?The distance formula states that the distance between two points in xyz-space is the square root of the sum of the squares of the differences between corresponding coordinates A( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] , [tex]z_{1}[/tex] ) and B( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] ,[tex]z_{2}[/tex]),
AB² = ([tex]x_{2}[/tex] - [tex]x_{1}[/tex])² + ([tex]y_{2}[/tex] - [tex]y_{1}[/tex])² + ( [tex]z_{2}[/tex] - [tex]z_{1}[/tex] )²
In reality, the Pythagorean Theorem is nothing more than the distance formula. Draw a right triangle using the segment AB as its hypotenuse in order to get the distance AB between points A( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] ) and B( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] ).
Given that in the question two points are A(2,3,5) and B(6,0,8), so the distance between them is
AB² = ([tex]x_{2}[/tex] - [tex]x_{1}[/tex])² + ([tex]y_{2}[/tex] - [tex]y_{1}[/tex])² + ( [tex]z_{2}[/tex] - [tex]z_{1}[/tex] )²
AB² = 4² + 3² + 3²
AB² = 34
AB = 5.83 m
Position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) the distance between ant and spider is 5.83 m.
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Is the answer 0.055 seconds? (Only problem 13)
Answer:
155÷8.5
=18.235294117647
31) what is the energy required to change 20g of copper, whose specific heat is 0.39j/gc,
change from 20 to 40 degrees?
Explanation:
given :
m = 20 g
sh = 0.39 J/g°C
∆T = 40-20 = 20°C
Find the Energy!
solution :
E =m. sh. ∆T
= 20 × 0.39 × 20
= 156 J
So, energy required is
Energy = mass*sh*∆T
Energy = 20g*0.39j/g°c*20°
Energy = 156joule✅
~Physics#1
A spring scale is used to measure the weight of various objects. When a 100 g empty glass bottle is placed on the scale, the spring stretches down 1.8 cm. How much water should be poured into the glass bottle to stretch the spring down by 2.7 cm?
A: 44 mL
B: 50 mL
C: 33 mL
D: 150 mL
50 mL of water have to poured to the glass bottle of 100 g to increase the stretching of the spring from 1.8 cm to 2.7 cm.
What is spring stretching?A spring can hang when it loads a weight. The stretching of spring is the change in length of the spring end from its initial length. Spring balance works with the principle of Hooks law.
The stretching is made by the elasticity of the spring which make it in a wave like motion.
Given that the glass bottle with 100 g weight when loaded on the spring scale, it will stretch down to 1.8 cm. Then the weight required to make a stretch of 2.7 cm is calculated as follows:
weight required = (100 g × 1.8 cm) /2.7 cm
= 150 g.
A total of 150 g is needed to stretch into 2.7 cm. Thus we have to add 50 g of water to the glass weighing 100 g . 50 g is equivalent to 50 ml, since density of water is 1 g/L.
Hence, 50 ml of water should be poured to the glass.
To find more about spring scale, refer the link below:
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PLEASEEEEEE HELPPPPPPP MEEEEEEEE!!!!!!!!!!!!!
Answer:
[tex]2 \\ because \\ 2 - 2 = 0 \\ 5 - 5 = 0[/tex]
Draw a free body diagram of an 6.4 kg ball falling towards earth. Calculate the weight of the ball.
Diagram:-
[tex]\setlength{\unitlength}{2mm}\begin{picture}(0,0)\thicklines\put(3,6){\circle{3}}\put(2.9,4.5){\vector(0,-3){2cm}}\put(-3.9,-10){\line(3,0){3cm}}\multiput(-3.5,-10)(0.8,0){18}{\line(1,-2){2mm}}\put(-3.7,0){$\sf\footnotesize 9.8 ms^{-2}$}\put(6,0){\vector(0,3){1.2cm}}\put(5.5,6){\line(3,0){2mm}}\put(5,-1.2){\sf\footnotesize height}\put(6,-2){\vector(0,-3){1.2cm}}\put(5.5,-8){\line(1,0){2mm}}\end{picture}[/tex]
Here
m=6.4kg[tex]\\ \sf\longmapsto Weight=mg[/tex]
[tex]\\ \sf\longmapsto Weight=6.4(9.8)[/tex]
[tex]\\ \sf\longmapsto weight=62.72N[/tex]
Potential energy is due to_blank_?
Answer:
To summarize, potential energy is the energy that is stored in an object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height.
Explanation:
if it helped plz mark brainiest
Helen is riding down a freeway on her motorcycle at 95kilometersperhour. At this speed, how far will Helen ride in 2hours?
label the longitudinal wave
Answer:
???
Explanation:
a father and his son are racing down a mountain. if they're traveling at the same velocity who has more kinetic energy
Answer:
I think it's the son
Explanation:
bcs he might love it
What is the magnitude of the momentum of a 1000 kg car traveling
at 5 m/s?
Answer:
5000 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question
mass = 1000 kg
velocity = 5 m/s
We have
momentum = 1000 × 5 = 5000
We have the final answer as
5000 kg.m/sHope this helps you
Which component that makes up the bulk of all galaxies?
A. gas
B. dark matter
C. dust
D. stars
Answer: B Dark matter
We have that for the Question "Which component that makes up the bulk of all galaxies? A. gas B. dark matter C. dust D. stars" it can be said that Invariably the dark matter makes up the bulk of all galaxies
Option B
From the question we are told
Which component that makes up the bulk of all galaxies?
A. gas
B. dark matter
C. dust
D. stars
Generally
the Galaxy have a mass of about 2*10^{12} mass of sun
This is made up of 95% of dark matter
Therefore
Invariably the dark matter makes up the bulk of all galaxies
Option B
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