Which definition best describes a regulator?
Oamechanical deice that presses gas into a smal container
O an incompressibie iquid ike oil or water
O a device that helips control the fow of a fuid
O adevice that coilects liquid in a hydraulic system and keeps it under pres

Answer:

linear partial differential

Explanation:

The Schrödinger equation is a linear partial differential equation that describes the wave function or state function of a quantum-mechanical system. It is a key result in quantum mechanics, and its discovery was a significant landmark in the development of the subject.

Answer:

Talcum powder!

Explanation:

How to find the source of an oil leak:

This method simply involves using Talcum Powder as a visual aid to help pinpoint the location of an oil leak,

so you use Talcum powder for small oil leak :]

Have a wonderful day!

Answer:

The term "green" describes initiatives and products that preserve the environment

Explanation:

In order to preserve the environment the Environmental Protection Agency has provides tips for "Being Green on the Road", which highlights the topics including, Green Vehicle Guides, guides for Fuel Economy, guides for Clean Diesel and many more ways our environmental footprint can be reduced

A green economy is an economy that focuses on the reduction of risk of economic activity on the environment, such as the reduction of carbon emission and reduction in environmental pollution, biodiversity loss prevention, and promotes a sustainable development

A green tech aims to protect the environment and to reverse previous damage done to the environment, including technology for clean energy, water purification, and waste recycling.

Answer:

The correct answer is stressor. The durability of building products and structures is affected by stressors such as rain, heat, snow, and hurricanes. Construction standards consider these potential stressors.

Answer:

339.4625

Explanation:

correct me if i am wrong

Answer:

hydraulics

Explanation:

Answer:

b

Explanation:

Answer:

9A

Explanation:

This question is incomplete, the complete question is;

For some transformation having kinetics that obey the Avrami equation, the parameter n is known to have a value of 2. If, after 100 s, the reaction is 40% complete, how long (total time in seconds) will it take the transformation to go to 95% completion

y = 1 - exp( -ktⁿ )

Answer: the time required for 95% transformation is 242.17 s

Explanation:

First, we calculate the value of k which is the dependent variable in Avrami equation

y = 1 - exp( -ktⁿ )

exp( -ktⁿ ) = 1 - y

-ktⁿ = In( 1 - y )

k = - In( 1 - y ) / tⁿ

now given that; n = 2, y = 40% = 0.40, and t = 100 s

we substitute

k = - In( 1 - 0.40 ) / 100²

k = - In(0.60) / 10000

k = 0.5108 / 10000

k = 0.00005108 ≈ 5.108 × 10⁻⁵

Now calculate the time required for 95% transformation

tⁿ = - In( 1 - y ) / k

t = [- In( 1 - y ) / k ]^1/n

n = 2, y = 95% = 0.95 and k = 5.108 × 10⁻⁵

we substitute our values

t = [- In( 1 - 0.95 ) / 5.108 × 10⁻⁵ ]^1/2

t = [2.9957 / 5.108 × 10⁻⁵]^1/2

t = [ 58647.22 ]^1/2

t = 242.17 s

Therefore the time required for 95% transformation is 242.17 s

Answer:

the answer is scientifically science chemistry biochemistry aerospace engineering plato english history world ap history yes

Explanation:

que

Answer:

E = 8.83 kips

Explanation:

First, we determine the stress on the rod:

[tex]\sigma = \frac{F}{A}\\\\[/tex]

where,

σ = stress = ?

F = Force Applied = 1300 lb

A = Cross-sectional Area of rod = 0.5[tex]\pi \frac{d^2}{4} = \pi \frac{(0.5\ in)^2}{4} = 0.1963\ in^2[/tex]

Therefore,

[tex]\sigma = \frac{1300\ lb}{0.1963\ in^2} \\\\\sigma = 6.62\ kips[/tex]

Now, we determine the strain:

[tex]strain = \epsilon = \frac{elongation}{original\ length} \\\\\epsilon = \frac{0.009\ in}{12\ in}\\\\\epsilon = 7.5\ x\ 10^{-4}[/tex]

Now, the modulus of elasticity (E) is given as:

[tex]E = \frac{\sigma}{\epsilon}\\\\E = \frac{6.62\ kips}{7.5\ x\ 10^{-4}}[/tex]

E = 8.83 kips

Answer:

R=v/i.... So V=R*i=10*1.7=17 volt

Answer:

I am pretty confident it is the Employer!

Explanation:

They have the responsibility to provide a safe workplace that is free from serious hazards, according to the General Duty Clause of the OSH Act (OSHA Standards)

I hope this helped you!! :D

Answer:

Employers

Explanation:

OSHA requires employers to: Provide working conditions that are free of known dangers. Keep floors in work areas in a clean and, so far as possible, a dry condition. Select and provide required personal protective equipment at no cost to workers.

Answer:

v₀ = 2.68 m/s.

[tex]v_{B}[/tex] = 3.33 m/s

d = 1.61 m

Explanation:

Searching on the internet I found the picture of the answer in which the height between point A and point B is equal to 0.2 m.

To determine the value of v₀ we need to use the following equation:

[tex] v_{f} = v_{0} - gt [/tex]

Taking the initial vertical velocity ([tex]v_{0_{y}}[/tex]) as [tex]v_{A_{y}}[/tex] and the final vertical velocity ([tex]v_{f_{y}}[/tex]) as [tex]v_{B_{y}}[/tex] we have:

[tex]v_{B_{y}} = v_{A_{y}} - gt[/tex]  

We can express the time (t) in terms of the velocities of A and B:

[tex] t = \frac{v_{A_{y}} - v_{B_{y}}}{g} [/tex]    (1)

Now, we can use the equation:

[tex]y_{f} = y_{0} + v_{A_{y}}t - \frac{1}{2}gt^{2}[/tex]   (2)

By entering equation (1) into equation (2):

[tex]y_{f} = y_{0} + v_{A_{y}}*(\frac{v_{A_{y}} - v_{B_{y}}}{g}) - \frac{1}{2}g(\frac{v_{A_{y}} - v_{B_{y}}}{g})^{2}[/tex]      (3)

Since [tex]v_{A_{x}} = v_{B_{x}} [/tex] because there is no acceleration in the horizontal movement, we have:

[tex] v_{A}sin(15) = v_{B}sin(12) [/tex]

[tex] v_{A} = \frac{v_{B}sin(12)}{sin(15)} [/tex]    (4)

Taking:

[tex]y_{f}[/tex] = 0

[tex]y_{0}[/tex] = 0.2 m

g = 9.81 m/s²

[tex]v_{A_{y}} = v_{A}cos(15)[/tex]

[tex]v_{B_{y}} = v_{B}cos(12)[/tex]

Entering the above values and equation (4) into equation (3) we have:

[tex] -0.4 m*9.81 m/s^{2} = (\frac{v_{B}sin(12)cos(15)}{sin(15)})^{2} - (v_{B}cos(12))^{2} [/tex]  

By solving the above quadratic equation:

[tex]v_{B} = 3.33 m/s [/tex]

Hence, the velocity of the ball [tex]v_{B}[/tex] is 3.33 m/s.

Now, we can find [tex]v_{A}[/tex] by using equation (4):

[tex]v_{A} = \frac{v_{B}sin(12)}{sin(15)} = \frac{3.33 m/s*sin(12)}{sin(15)} = 2.68 m/s [/tex]

Then, the value of v₀ of the ball is 2.68 m/s.

Finally, to find the distance between point A and point B we need to calculate the time by using equation (1):

[tex]t = \frac{v_{A_{y}} - (-v_{B_{y}})}{g} = \frac{v_{A_{y}} + v_{B_{y}}}{g}[/tex]

The minus sign in [tex]v_{B_{y}}[/tex] is because the vertical component of the vector is negative.

[tex] t = \frac{v_{A_{y}} + v_{B_{y}}}{g} = \frac{2.68 m/s*cos(15) + 3.33 m/s*cos(12)}{9.81 m/s^{2}} = 0.60 s [/tex]

Now, the distance is:

[tex] x = v_{0}*t = 2.68 m/s*0.60 s = 1.61 m [/tex]

I hope it helps you!            

Answer:

Answered below.

Explanation:

A) Both spheroidite & tempered martensite possess sphere - like cementite particles within their microstructure known as a ferrite matrix. However, the difference is that these particles are much larger for spheroidite than tempered.

B) Tempered martensite is much harder and stronger than spheroidite primarily because there is much more ferrite - cementite phase boundary area for its sphere - like cementite particles.

This is because the greater the boundary area, the more the hardness.

Answer:

2D CAD Software Application

Explanation:

Two Dimensional Computer-Aided Design Software Application is otherwise known as 2D CAD software application such as AutoCAD or MicroStation is used to change physical objects and 3-D ideas into a 2-D drawing that effectively describe the design and features of an object, so the object can be documented and manufactured.

The utilization of a 2D CAD software application saves time and revision to construction drawings can quickly be made without having to redesign the whole drawings from the scratch.

Answer:

[tex]F_r = 200N[/tex]

Explanation:

Given

Let the two forces be

[tex]F_1 = 130N[/tex]

[tex]F_2 = 110N[/tex]

and

[tex]\tan(\theta) = \frac{12}{5}[/tex]

Required

Determine the resultant force

Resultant force (Fr) is calculated using:

[tex]F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)[/tex]

This means that we need to first calculate [tex]\cos(\theta)[/tex]

Given that:

[tex]\tan(\theta) = \frac{12}{5}[/tex]

In trigonometry:

[tex]\tan(\theta) = \frac{Opposite}{Adjacent}[/tex]

By comparing the above formula to [tex]\tan(\theta) = \frac{12}{5}[/tex]

[tex]Opposite = 12[/tex]

[tex]Adjacent = 5[/tex]

The hypotenuse is calculated as thus:

[tex]Hypotenuse^2 = Opposite^2 + Adjacent^2[/tex]

[tex]Hypotenuse^2 = 12^2 + 5^2[/tex]

[tex]Hypotenuse^2 = 144 + 25[/tex]

[tex]Hypotenuse^2 = 169[/tex]

[tex]Hypotenuse = \sqrt{169[/tex]

[tex]Hypotenuse = 13[/tex]

[tex]\cos(\theta)[/tex] is then calculated using:

[tex]\cos(\theta)= \frac{Adjacent}{Hypotenuse}[/tex]

[tex]\cos(\theta)= \frac{5}{13}[/tex]

Substitute values for [tex]F_1[/tex], [tex]F_2[/tex] and [tex]cos(\theta)[/tex] in

[tex]F_r^2 = F_1^2 + F_2^2 + 2F_1F_2\cos(\theta)[/tex]

[tex]F_r^2 = 130^2 + 110^2 + 2*130*110*\frac{5}{13}[/tex]

[tex]F_r^2 = 16900 + 12100 + 11000[/tex]

[tex]F_r^2 = 40000[/tex]

Take square roots of both sides

[tex]F_r = \sqrt{40000[/tex]

[tex]F_r = 200N[/tex]

Hence, the resultant force is 200N

Answer:

The work of the turbine is done at the expense of the enthalpy of the fluid.

Explanation:

Ideally speaking, a turbine is a steady-state devices that has no heat interactions and generates works at the expense of enthalpy. By the First Law of Thermodynamic, we have the following definition for steady-state conditions: (all energy components are measured in joules)

[tex]E_{in} - E_{out} + E_{gen} = 0[/tex] (1)

Where:

[tex]E_{in}[/tex] - Inlet energy.

[tex]E_{out}[/tex] - Outlet energy.

[tex]E_{gen}[/tex] - Generated energy.

Generated energy is associated with endothermic and exothermic chemical reactions and fission processes in radioactive elements and isotopes. Since fluids used in turbines are usually inert, the generated energy is zero and each remaining componets of the expression are defined:

[tex]E_{in} = U_{g,in}+K_{in}+H_{in}[/tex] (2)

[tex]E_{out} = U_{g,out}+K_{out}+H_{out}+W_{out}[/tex] (3)

Where:

[tex]U_{g,in}[/tex], [tex]U_{g,out}[/tex] - Inlet and outlet gravitational potential energies.

[tex]K_{in}[/tex], [tex]K_{out}[/tex] - Inlet and outlet translational kinetic energies.

[tex]H_{in}[/tex], [tex]H_{out}[/tex] - Inlet and outlet enthalpies.

[tex]W_{out}[/tex] - Energy generated by the turbine.

Usually, turbines at steady state does not report significant changes in translational and gravitational potential energies and (2) and (3) can be reduced into this form:

[tex]E_{in} = H_{in}[/tex] (2b)

[tex]E_{out} = H_{out}+W_{out}[/tex] (3b)

And we find the following equation of work by substituting on (1):

[tex]W_{out} = H_{in}-H_{out}[/tex] (4)

In a nutshell, the work of the turbine is done at the expense of the enthalpy of the fluid.

Answer:

true

Explanation:

Answer: the answer is B and D

Explanation:

Answer:

thats a really cool design or whatever you got there.

Explanation:

niceeeeeeee :)

Answer:

The correct option is;

Terminate

Explanation:

Termination of the risk is equivalent to elimination of the risk by avoiding the activity that brings about the risk or by using a different process that does not include the risk observed in the previous process option

When the reward far outweigh the risk, it may be decided to terminate or eliminate the risk and miss the reward and also terminate the likelihood of the losses to be incurred.

Explanation:

Okay soo-

Given-

u = 60 km/hr = 60×1000/3600=50/3 m/s

t = 20 s

s = 250 m

a = ?

v = ?

Solution -

Here, acceleration is uniform.

(a) According to 2nd kinematics equation,

s = ut + ½at^2

250 = 50/3 ×20 + 0.5×a×20×20

250-1000/3=200a

(750-1000)/3=200a

a = -250/(3×200)

a = -5/12

a = 0.4167 m/s^2

The required uniform acceleration of the car is 0.4167 m/s^2.

(b) According to 1st kinematics equation

v = u + at

v = 50/3 + (-5/12)×20

v = 50/3-25/3

v = 25/3

v = 8.33 m/s

The speed of the car as it passes the traffic light is 8.33 m/s.

Good luck!

Answer:

11/8

Explanation:

7/8+4/8=11/8 if you want it on a ruler you need to go online and type fraction to decimal converter and put in 11/8 into a decimal

Answer:

The answer is "Option C".

Explanation:

The creep depends on temperature and stress whenever the temperature rise, for failure generosity, its core symptoms can be increased between about 0,5 and 0,7 TM in k (melting point of temperature). It is indeed a metal puncturing type, typically at high temperatures with stresses below the yields of a metal.

Explanation:

Creep occurs by constant stress at temperatures over 0.5 TM in K.

Creep is a phenomenon in which a material or an object is elongated over a time period under constant temperature and stress for a long period of time. For example, a belt used for a year or so, is elongated.

Answer: C) Both Techs A and B

Explanation:

Technician A and Technician B are both very right. Using a spray bottle and water, the ignition wire test can be carried out using any of the methods described above. Or, by using a grounded test lead that is connected to a multimeter, you can also conduct the test for faulty ignition wires.

Answer: Either A or B

Explanation:

Solution :

i. Slip plane (1 1 0)

Slip direction -- [1 1 1]

Applied stress direction = ( 1 0 0 ]

τ = 50 MPa    ( Here slip direction must be perpendicular to slip plane)

τ = σ cos Φ cos λ

[tex]$\cos \phi = \frac{(1,0,0) \cdot (1,1,0)}{1 \times \sqrt2}$[/tex]

       [tex]$=\frac{1}{\sqrt2 }$[/tex]

[tex]$\cos \lambda = \frac{(1,0,0) \cdot (1,-1,1)}{1 \times \sqrt3}$[/tex]

       [tex]$=\frac{1}{\sqrt3 }$[/tex]

  τ = σ cos Φ cos λ

∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]

  σ = 122.47 MPa

ii. Slip plane  --- (1 1 0)

   Slip direction -- [1 1 1]

  [tex]$\cos \phi = \frac{(1, 0, 0) \cdot (1, -1, 0)}{1 \times \sqrt2} =\frac{1}{\sqrt2}$[/tex]

   [tex]$\cos \lambda = \frac{(1, 0, 0) \cdot (1, 1, -1)}{1 \times \sqrt3} =\frac{1}{\sqrt3}$[/tex]

 τ = σ cos Φ cos λ

∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]

  σ = 122.47 MPa

iii. Slip plane  --- (1 0 1)

    Slip direction --- [1 1 1]

[tex]$\cos \phi = \frac{(1, 0, 0) \cdot (1, 0, 1)}{1 \times \sqrt2} =\frac{1}{\sqrt2}$[/tex]

   [tex]$\cos \lambda = \frac{(1, 0, 0) \cdot (1, 1, -1)}{1 \times \sqrt3} =\frac{1}{\sqrt3}$[/tex]

τ = σ cos Φ cos λ

∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]

  σ = 122.47 MPa

iv. Slip plane -- (1 0 1)

    Slip direction  ---- [1 1 1]

[tex]$\cos \phi = \frac{(1, 0, 0) \cdot (1, 0, -1)}{1 \times \sqrt2}=\frac{1}{\sqrt2}$[/tex]

[tex]$\cos \lambda = \frac{(1, 0, 0) \cdot (1, -1, 1)}{1 \times \sqrt3} =\frac{1}{\sqrt3}$[/tex]

τ = σ cos Φ cos λ

∴ [tex]$50= \sigma \times \frac{1}{\sqrt2} \times \frac{1}{\sqrt3} $[/tex]

  σ = 122.47 MPa

∴ (1, 0, -1). (1, -1, 1) = 1 + 0 - 1 = 0

Answer:

41 kW

690.2 kW

Explanation:

Given the following data

T1 = 400 K

P1 = 350 kPa

T2 = 600 K

P2 = 100 kPq

m = 1 kg/s

Q1 = 900 kW

Q2 = 50 kW

T(amb1) = 1000 K

T(amb2) = 350 K

T(amb3) = 500 K

We also will be using tables to solve the question.

R = 0.287 kJ/kgk

C(p) = 1.004 kJ/kgk

To find Q3, we'd use the formula

Q3 = m.T(amb3).[C(p).In(T2/T1) - R.In(P2/P1)] - [T(amb3)/T(amb1) * Q1] + [T(amb3)/T(amb2) * Q2]

Q3 = 1 * 500 * [1.004 * In(600/400) - 0.287 * In(100/450)] - 500/1000 * 900 + 500/350 * 50

After simplification, we find that

Q3 = 41 kW

Next, we use the equation

Q3 - Q2 + Q1 = W + m.C(p).(T2 - T1)

41 - 50 + 900 = W + 1 * 1.004 * (600 - 400)

891 = W + 1.004 * 200

891 = W + 200.8

W = 891 - 200.8

W = 690.2 kW

If we make W the subject of the formula, we have

This question is incomplete, the complete question is;

A 1,040 N force is recorded on a hemispherical vane as it redirects a 2.5 cm- blade diameter water jet through a 180 angle.

Determine the velocity of the flowing water jet if the blade is assumed to be frictionless.

Answer: the velocity of the flowing water jet is 32.55 m/s  assuming the blade is frictionless

Explanation:

Given that;

Force Ft = 1040 N

diameter d = 2.5 cm = 0.025 m

we know that; force acting on Hemispherical plate is;

Ft = 2δav²

where

a is area = π/4(0.025)²

δ is density of water = 1000 kg/m³

v is velocity = ?

now we substitute

1040 = 2 × 1000 × (π/4(0.025)²) × v²

1040 =  0.9817v²

v² = 1040 / 0.9817

v² = 1059.3867

v = √1059.3867

v = 32.5482 ≈ 32.55 m/s

Therefore the velocity of the flowing water jet is 32.55 m/s  assuming the blade is frictionless

Answer:

Each wattmeter measures a line-to-line voltage between two of the three power supply lines. In this configuration, the total power, watts is accurately measured by the algebraic sum of the two wattmeter values. Pt = P1 + P2. This holds true if the system is balanced or unbalanced.

Answer:

The correct option is;

c.  the exergy of the tank can be anything between zero to P₀·V

Explanation:

The given parameters are;

The volume of the tank = V

The pressure in the tank = 0 Pascal

The pressure of the surrounding = P₀

The temperature of the surrounding = T₀

Exergy is a measure of the amount of a given energy which a system posses that is extractable to provide useful work. It is possible work that brings about equilibrium. It is the potential the system has to bring about change

The exergy balance equation  is given as follows;

[tex]X_2 - X_1 = \int\limits^2_1 {} \, \delta Q \left (1 - \dfrac{T_0}{T} \right ) - [W - P_0 \cdot (V_2 - V_1)]- X_{destroyed}[/tex]

Where;

X₂ - X₁ is the difference between the two exergies

Therefore, the exergy of the system with regards to the environment is the work received from the environment which at is equal to done on the system by the surrounding which by equilibrium for an empty tank with 0 pressure is equal to the product of the pressure of the surrounding and the volume of the empty tank or P₀ × V less the work, exergy destroyed, while taking into consideration the change in heat of the system

Therefore, the exergy of the tank can be anything between zero to P₀·V.