Which inequalities are true? Select the four correct answers.
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Answer:

The radius is 3 and it is the same all around

Step-by-step explanation:

Since The hypotenuse equals the two other sides squared, let's find out what those are.

[tex]\sqrt{9} + \sqrt{9} = \sqrt{18}[/tex]

Now, let's find the square root of those 9s.

[tex]\sqrt{9} = 3[/tex]

Those other sides we talked about (more specifically the base of the triangle) are the radius of the circle because of how they extend to the exterior of the circle, which means since their length is 3, the radius is also 3.

The radius is always constant so it is supposed to be the same all around.

Answer:

[tex] \frac{25}{100} \times 1.20[/tex]

Answer:

d

Step-by-step explanation:

god a 100 on edg

ΔABC cannot be congruent to ΔADC by SSS?l because D. No, because AB ≅ DA.

It should be noted that when the three corresponding sides of the figures have the same length, it can be concluded that the triangles are congruent by SSS.

In this case, ΔABC cannot be congruent to ΔADC by SSS?l because AB is not equal to DA.

Therefore, the correct option is D.

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Answer:

[tex]\displaystyle (x,y) \longrightarrow (x+3, y+1)[/tex]

Step-by-step explanation:

We want to write a rule for the transformation shown.

We can see that ΔA'B'C' is the figure ΔABC shifted rightwards 3 units and upwards 1 unit.

In other words, all x-coordinates of ABC is increased by 3, and all y-coordiantes of ABC is increased by 1.

Therefore, the rule for the x-coordinate is:
[tex]\displaystyle x \longrightarrow x + 3[/tex]

And the rule for the y-coordinate is:

[tex]\displaystyle y \longrightarrow y + 1[/tex]

In conclusion, we have that:

[tex]\displaystyle (x,y) \longrightarrow (x+3, y+1)[/tex]

Answer:

$1350

Step-by-step explanation:

Simple Interest = Deposit ×Rate/100×Time

SI=5000×9/100×3

=$1350

The final answer of the solution is x∈ (-13,1) ∪ [1, 15 ] or, x∈(-13, 15] and x∈ (-∞ , 1) ∪ [1, ∞) or, x∈ (-∞, ∞) or x∈ R.

Inequality is defined as the relation which makes a non-equal comparison between two given functions.

For |x - 1 | + 1 < 15 , we should first break the modulus function .

Two cases are possible for this inequality ,

case 1 - when x ≥ 1

x - 1 + 1 < 15 ⇒ x < 15

putting the number line both x ≥ 1 and x≤ 15

Then, x∈ [1, 15)

case 2 - when x < 1

-x + 1 + 1 < 15

⇒ -x + 2 < 15

⇒ -x < 13 ⇒ x > -13

putting the number line both x > -13 and x < 1

then, x∈ (-13, 1)

now, answer is x∈ (-13,1) ∪ [1, 15 ] or, x∈(-13, 15]

Again, for |x - 1| + 1 > 15

Similarly z there are two cases possible for this

case 1 :- when x ≥ 1

x - 1 + 1 > 15 ⇒ x > 15

Putting the number line both x ≥ 1 and x > 15

then, x ∈ [1, ∞)

case 2 - when x < 1

-x + 1 + 1 > 15 ⇒ x < -13

putting the number line both x < 1 and x < -13

Then, x∈ (-∞, 1)

hence, final answer is x∈ (-∞ , 1) ∪ [1, ∞) or, x∈ (-∞, ∞) or x∈ R

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The 3 rules that we need to use to simplify the expression are:

As I understand, the expression that we have is:

[tex]\frac{((-8)^4)^{-5}}{(-8)^6}[/tex]

The first rule we need to use, is the exponent of an exponent rule, it says that:

[tex](a^n)^m = a^{n*m}[/tex]

If we apply that to the denominator, we get:

[tex]\frac{((-8)^4)^{-5}}{(-8)^6} = \frac{(-8)^{-20}}{(-8)^6}[/tex]

Now we need to use the quotient of powers:

[tex]\frac{a^m}{a^n} = a^{m - n}[/tex]

Using that we get:

[tex]\frac{((-8)^4)^{-5}}{(-8)^6} = \frac{(-8)^{-20}}{(-8)^6} = (-8)^{-20 - 6} = (-8)^{-26}[/tex]

Finally, we use the rule for a negative exponent:

[tex]a^{-n} = \frac{1}{a^n}[/tex]

So we get the simplified form:

[tex]\frac{((-8)^4)^{-5}}{(-8)^6} = \frac{(-8)^{-20}}{(-8)^6} = (-8)^{-26} = \frac{1}{(-8)^{26}}[/tex]

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Answer:

B, C, and E

Step-by-step explanation:

Total money Tammy has = $70

Money she is left with now = $19.54

Therefore, the money she used on coffee =

70 - 19.54 = $50.46

Now,

1 pound coffee costs $8.41

Pounds of coffee she bought = 50.46 ÷ 8.41

= 6 pounds

Answer:

22

Step-by-step explanation:

Answer:

18 8/9

Step-by-step explanation:

3 7/9 =[ (3*9) + 7] / 9

= 34/9

So we have 5 * 34/9

=  170/9

= 18 8/9.

To write the expression [tex]6 \frac{7}{12}[/tex]  in radical form.

To express the radical form in simplest it just means simplifying the radical so that there are further no more square root, cube root etc.

Use the rule:

[tex]a\frac{x}{y}[/tex] = [tex]\sqrt[y]{a^{2} }[/tex]

Apply this rule on the the given expression:

[tex]6\frac{7}{12} = \sqrt[12]{6^{7} }[/tex]

Therefore, the expression in radical form is [tex]\sqrt[12]{6^{7} }[/tex]

A quadratic equation is in the form of ax²+bx+c. The time for which the stone was in the air is 3.526.

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.

It is written in the form of ax²+bx+c.

As the height of the stone will be zero or can say that the stone will be at the ground in only two conditions. When the stone will be just thrown and when the stone will complete its flight. Therefore, we can substitute the value of heigh h in the function as 0 to get those two timings.

[tex]h(t) = 5 + 50t - 16t^2\\\\0 = 5+50t - 16t^2[/tex]

Substitute the quadratic equation in the formula of the root of the quadratic function,

[tex]x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\t = \dfrac{-50\pm\sqrt{(50)^2-4(-16)(5)}}{2(-16)}\\\\t= -0.089, 3.526[/tex]

Hence, the time for which the stone was in the air is 3.526.

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Answer:

  52°

Step-by-step explanation:

The sum of an angle and its complement is 90°.

__

The sum of 38° and its complement, x, is 90°:

  38 +x = 90 . . . . . an equation to find the complement of 38°

  x = 90 -38 . . . . subtract 38 from both sides

  x = 52 . . . . degrees

The measure of x is 52°.

Answer:

B) -2

Step-by-step explanation:

[tex]log_{6} \frac{1}{36}[/tex]                           ORIGINAL

[tex]log_{6} 6^{-2}[/tex]                          REWRITE  1/36

-2                                  LOG RULE - 6's CANCEL

Hope this helsp!

Answer:

3(3x-2)=39

9x-6=39

9x=39-6

9x=33

x=33/9

x=11/3

Answer:

x=5

Step-by-step explanation:

First, distribute the left side. 3(3x-2)=39 3 x 3x=9x 3 x -2=-6 m So, we get 9x-6=39

Next, we add six to both sides. We get 9x=45.

Lastly , we divide both sides by 9 and get x=5.

Plug x=5 into the place where x is to check your work. 3(3(5) - 2)=39

3(15-2)=39 3(13)=39 39=39 Since 39 is equal to 39, the equation is true.

Answer:

1875

Step-by-step explanation:

1335 + 0540 = 1875

Answer:

1,875

Step-by-step explanation:

[tex]1335 + 540 = 1,875[/tex]

Hope this helps! : )

Answer:

41%

Step-by-step explanation:

step one to determine what the fraction would be you just read the question: first you have to see what they want to calculate the percentage of. In this case it's students who like traveling out of state but don't like camping. 88 students like traveling out of state and 36 of those students don't like camping so the fraction you have to use is 36/88 step two next you multiply your fraction by 100 to calculate your percentage 36/88×100= 40.9% step three since you have to round to the nearest whole percent your answer would be 41%

The means of samples 1 and 2 is 3.45. The mean of sample 3 is 3.8. Based on the data, the average diner would visit the restaurant 3 or 4 times.

The mean of a sample is the average of all the data sets given in the sample. The mean of a sample is useful in calculating population averages, central tendency, standard deviation, etc.

Mathematically, the mean of a sample can be expressed as:

[tex]\mathbf{\overline X =\dfrac{sum \ of \ the \ terms }{no \ of \ terms } }[/tex]

[tex]\mathbf{\overline X =\dfrac{\sum X}{N} }[/tex]

Thus, the means of samples 1 and 2 is:

[tex]\mathbf{\overline X =\dfrac{36+33}{20} }[/tex]

[tex]\mathbf{\overline X =3.45}[/tex]

The mean of sample 3 is:

[tex]\mathbf{\overline X =\dfrac{3+3+6+4+1+5+3+4+4+5}{10} }[/tex]

[tex]\mathbf{\overline X =3.8}[/tex]

Based on the data, the average diner would visit the restaurant 3 or 4 times, because the mean of the samples lies between 3 to 4.

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The railroad crew repair 1500 km in 25 days if the railroad crew can replace 360 meters of rails in 6 days

Fraction number consists of two parts one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

We have:

A railroad crew can replace 360 meters of rails in 6 days.

Let's suppose the x kilometers of rail they can repair in 25v days

Per day they repair = 360/6 = 60 km/day

Then the x can be found:

x = 60×25

x = 1500 km

Thus, the railroad crew repair 1500 km in 25 days if the railroad crew can replace 360 meters of rails in 6 days.

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The package which the company should choose if it costs the same to produce the two products is the cylinder because it has about 27.5 in.3 less wasted space than the prism.

The term "cost of production" refers to all the costs that are involved when a company offers a service or manufactures a product.

Costs of production relate to the different expenses that a firm faces in producing a good or service.

This refers to the amount which is used to produce a good.

With this in mind, we can see that there are the given dimensions for the square prism and cylinder from the complete question.

Hence, because they cost the same, choosing the cylinder is the best choice because of the less wasted space than the prism.

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Answer:

It's A

Step-by-step explanation:

Answer:

r= 0.402

Step-by-step explanation:

The approximate area of the decagon with a side of 8cm is 492.37 cm².

Given side of the regular decagon = 8cm

A decagon is a polygon with 10 equal sides.

We know that area of a regular decagon with side a is given by:

[tex]A=\frac{5}{2} a^{2} \sqrt{5+2\sqrt{5} }[/tex]

So, the area A of the regular decagon with a side of 8cm=[tex]\frac{5}{2} 8^{2} \sqrt{5+2\sqrt{5} }[/tex]

[tex]A=160\sqrt{5+2\sqrt{5} }[/tex]

A=492.37 cm²

Therefore, the approximate area of the decagon is 492.37 cm².

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24 sq. yards

hope it helps...!!!

Answer:

Option A :- if finding lateral surface area

Other information

radius r = 6 m

height h = 8 m

slant height s = 10 m

volume V = 301.592895 m3

lateral surface area L = 188.495559 m2

base surface area B = 113.097336 m2

total surface area A = 301.592895 m2

Step-by-step explanation:

Using the formulas

A=πrl+πr²

l=√r²+h²

Solving forA

A=πr(r+√h²+r²)=π · 6 · (6+√8²+6²)≈301.59289

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's see what's the domain and range for the given function ~

[tex]\qquad \tt \dashrightarrow \:domain \in [ -5 , 4 ] [/tex]

or

[tex]\qquad \tt \dashrightarrow \: - 5 \leqslant x \leqslant 4[/tex]

Because domain = all values of x between its maximum (4) and minimum (-5) value [ including them ]

[tex]\qquad \tt \dashrightarrow \:range \in[ -4 , 9 ][/tex]

or

[tex]\qquad \tt \dashrightarrow \: - 4 \leqslant y \leqslant 9[/tex]

Because range = all values of y between its maximum (9) and minimum (-4) value [ including them ]

Using the least common factor, it is found that it would take 90 minutes for both boys to return to the starting point at the same time.

To find the least common factor, we factor the numbers by prime factors, and then multiply these factors.

The lcm represents the periodicy, that is, when two periodic amounts will be at the same value.

In this problem, the periods are of 15 minutes and 18 minutes, hence:

15 - 18|2

15 - 9|3

5 - 3|3

5 - 1|5

1 - 1

Hence:

lcm(15,18) = 2 x 3 x 3 x 5 = 90.

It would take 90 minutes for both boys to return to the starting point at the same time.

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Answer:30

Step-by-step explanation: length is 20, Width is 20-10 =10

Area = 20×10=200