do transistors amplfy a.c or d.c
Explanation:
thet amplify DC, because of the voltage ( small current input signal)
Answer:
Yes,by using direct coupling(transistors) amplifier we will amplify low frequency (DC) signals. A transistor is certainly capable of taking a small-current input signal and controlling a high-current output at the same voltage, thereby amplifying the power of the input signal whether it's AC or DC.
Can you give me brainliest?please?
Order the electromagnetic waves from lowest frequency (1) to highest (4). gamma: infrared: x-ray: visible light:
Gamma: 4
Infrared: 1
X-Ray: 3
Visible Light: 2
Infrared has the longest wavelength between the four options, meaning that it has the lowest frequency. Since the longer the frequency, the lower the frequency. While the shorter the wavelength, the higher the frequency.
The portions of the electromagnetic spectrum are called from greatest to lowest energy: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves. Microwaves (such as those used in microwave ovens) are a subset of the electromagnetic spectrum's radio wave segment.
Next would be visible light since it has the second longest wavelength out of the given options. Then it would be X-Ray. And finally Gamma since it has the shortest wavelength.
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Decribe the motion of a body following under gravity and write the related equation
It states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration an of its center of mass, or F = ma.
What is the body's equation of motion?The fundamental equation of motion in classical mechanics is F = ma.
Since gravity affects an object's vertical motion, while it moves, it is said to be in motion under gravity.
The force that pushes objects downward is called gravity. In reality, gravity draws things toward the centre of the Earth. Homogeneous acceleration is experienced by a body in free fall.
Motion. It is said that the body is moving at an accelerated rate. Therefore, if a body falls freely while being affected by gravity, its velocity will begin to increase at a rate of 9.8 m/s2.
When a body falls freely under the effect of gravity alone in a vacuum, potential energy continuously decreases and kinetic energy continuously increases; as a result, the conservative force acts on the body.
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If the work done to move a toy car by a force of 20N is 60J how far did the car move?
Answer: Distance = 60 J / 20 N = 3 meters. So the car moved a distance of 3 meters.
Explanation: To determine how far the car moved, you need to know how long the force was applied. The equation for work is work = force * distance, so if you know the force and the work, you can solve for the distance. In this case, you know that the force applied was 20 N and the work done was 60 J, so you can calculate the distance by rearranging the equation to solve for distance: distance = work/force. Plugging in the values, you get distance = 60 J / 20 N = 3 meters. So the car moved a distance of 3 meters.
Important Formulas:
[tex]w=Fd[/tex]
work(measured in joules) = force(measured in newtons) * distance(measured in meters)
__________________________________________________________
Given:
[tex]w=60J[/tex]
[tex]F=20N[/tex]
[tex]d=?[/tex]
__________________________________________________________
Rearranging formula to make distance the subject:
[tex]w=Fd[/tex]
[tex]\dfrac{w}{F} =\dfrac{Fd}{F}[/tex]
[tex]d=\dfrac{w}{F}[/tex]
__________________________________________________________
Finding distance:
[tex]d=\dfrac{w}{F}[/tex]
[tex]d=\dfrac{60}{20}[/tex]
__________________________________________________________
[tex]\fbox{d = 3 meters}[/tex]
Someone help me with these questions
Answer:
Im not 100% sure so don't completly rely on these answer s
#1 is B
#2 ia B
#3 is A
#4 is A
#5 is A
and i think #6 is A
im 100% sure that 3 and 4 are A tho
Explanation:
A proton moving at 3.40 106 m/s through a magnetic field of 1.97 T experiences a magnetic force of magnitude 7.71 10-13 N. What is the angle between the proton's velocity and the field
When the proton passed through magnetic field then the angle between the proton velocity and the field is 49° degrees.
Given
Speed v = 4.00 m/s
Mg field =1.7 T
Force = 8.21 10-3 N
Given:- Velocity of the particle = 4.00x10m/3. 2 Magnitude of the magnetic field B= 1.701.
Force experienced by the particle: 8.20x10¹³N.
To find: The between the particle velocity and field. angle a
We know that :- F= q(√xB)
9 (VBSino) 928 - Sina
Sina = 8.20×10-13 1.6×10-19×4×10 6 x 1.70 = 0.7536.
Sin a = 0.7536. ~ Sin 0 = 0.754
a = sin' (0.7536)
a = 49°
we have a point charge q0 located at r and a set of external charges conspire so as to exert a force F on this charge. We can define the electric field at the point r by: E =Fq0
The (vector) value of the E field depends only on the values and locations of the external charges, because from Coulomb’s law the force on any “test charge” proportional to the value of the charge. However to make this definition really kosher we have to stipulate that the test charge q0 is “small”; otherwise its presence will significantly influence the locations of the external charges.
The electric field is a vector. we can see that its SI units must be It follows from Coulomb’s law that the electric field at point r due to a charge q located at the origin is given by E = kq where r is the unit vector which points in the same direction as r.
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When using a 20 ft ladder how far from a building should the base of the ladder be?
When using a 20 ft ladder the distance from a building should be the base of the ladder by 5 ft
The base of a ladder should be positioned one-quarter of the working length of the ladder from the building. Therefore, when using a 20 ft ladder, the base should be positioned 5 ft from the building. Additionally, the ladder should be placed on a solid and level surface, and the feet of the ladder should be securely wedged to prevent slipping.
Extend the top of the ladder three feet above the work table to get access to it, or fasten the ladder at the top.
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The mass of the Earth is 5.972 x 1024-kg and its orbital radius is an average of 1.496 x 1011 meters. Calculate its linear momentum. (Hint: It takes the Earth 365 days to complete one orbit.)
The linear momentum of the earth when mass and orbital radius are given is calculated to be 17.8 × 10²⁸ kg m/s.
The orbital radius (r) of earth is 1.496 × 10¹¹ m. So, the distance covered by one rotation is,
Distance = 2 π r = 2π (1.496 x 10¹¹) m
365 day when converted into seconds is, 365 × 24 × 60 ×60 s
So, the period of one rotation is 3.15 × 10⁷ s.
The velocity of earth (v) = distance/time = [2π (1.496 × 10¹¹)]/ 3.15 x 10⁷ = 298840 m/s
Linear momentum = mass × velocity = 5.972 × 10²⁴ kg × 298840 m/s = 17.8 × 10²⁸ kg m/s
Therefore, the linear momentum of earth is 17.8 × 10²⁸ kg m/s
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A tsunami caused by an earthquake occurring in Alaska in 1946 consisted of several huge waves which were found to travel a distance of 3607 km. The first of the waves reached Hawaii 4.567 hours after the earthquake occurred. From this data, calculate the speed of the tsunami.
From the given data, the speed of the tsunami is 789.8 km/h.
What is the speed of the tsunami?The speed of the tsunami is calculated from the relationship between distance travelled by the wave and the time of motion of the wave.
Mathematically, this formula is given as;
v = d / t
where;
d is the distance travelled by the wave of the earthquaket is the time of motion of the waveFrom the given data, the speed of the tsunami is calculated as follows;
v = ( 3607 km ) / ( 4.567 hr )
v = 789.8 km/h
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A person on a bike (m=90kg) is traveling 4m/s at the top of a 2m hill. What is his/her kinetic energy?
Answer:
Ek = 720J
Explanation:
Ek = 0.5mv^2
Ek = 0.5(90)(4)^2
Ek = 720J
The drop time can be calculated as follows: where y is the vertical height of the table and g is the
acceleration due to gravity. How did the calculated drop time compare to the average of your measured drop
times? Find the percent error using the following equation:
What factors might cause the differences?
Answer:
Tt can be calculated by copy
A 2.5-kg cart is rolling along a frictionless, horizontal track towards a 1.3-kg cart that is held initially at rest. The carts are loaded with strong magnets that cause them to attract one another. Thus, the speed of each cart increases. At a certain instant before the carts collide, the first cart's velocity is 4.6 m/s, and the second cart's velocity is -1.8 m/s. (a) What is the total momentum of the system of the two carts at this instant
The required total momentum of the system at this instant is calculated to be 9.16 kg m/s.
Given that,
Mass of the first cart, m₁ = 2.5 kg
Mass of the second cart, m₂ = 1.3 kg
Velocity of the first cart before collision, u₁ = 4.6 m/s
Velocity of the second cart before collision, u₂ = -1.8 m/s
The total momentum of the system before collision is calculated as follows,
P t = P₁ + P₂
P t = m₁ u₁ + m₂ u₂ = 2.5 × 4.6 + (1.3 × -1.8) = 11.5 - 2.34 = 9.16 kg m/s
Thus, total momentum of the system of the two carts at this instant is 9.16 kg m/s.
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A horizontal force of 12 Newtons is applied to a 4.0 kg box that slides on a horizontal surface. The box starts from rest moves a horizontal distance of 10 meters and obtains a velocity of 5.0 m/s. The surface has friction. The friction force is
Group of answer choices
4.9 N.
6.0 N.
7.0 N.
6.5 N.
Answer:
7.0N
Explanation:
F=ma
v2=u2+2as
25=0+20a
a=1.25m/s2
F=ma
F=0.4×1.25
Fn=5N
F=12
12-5=Ff
=7.0N
A horizontal force of 12 newtons is applied on a box of 4 kg then the friction force will be equal to 7 N. Hence option C is correct.
What is Velocity?Velocity is the rate at which a moving object's direction changes as perceived from a certain vantage point and measured by a particular unit of time. Kinematics, the area of special relativity that investigates how bodies move, starts with the fundamental idea of speed.
In order to be explained, the scientific vector quantity known as velocity needs to have both a magnitude and a direction.
As per the given information in the question,
Use the equation of motion:
v² = u² + 2as
25 = 0 + 20a
a = 1.25 m/s2
F = ma
F = 0.4 × 1.25
Fn = 5 N
F = 12
Ff = 12 - 5
Ff = 7.0 N
Therefore, it concludes that the friction force will be equal to 7.0 N.
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A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 110,000 kg of scrap metal into it. (a) What is the final velocity of the loaded freight car
The freight car which is being dumped into the metal scrap has the final velocity of 0.18 m/s.
In this problem, we use the principle of conservation of linear momentum.
Given that,
Mass of the freight car m₁ = 30,000 kg
Mass of the hopper m₂ = 110,000 kg
Velocity of the freight car u₁ = 0.85 m/s
Velocity of the hopper u₂ = 0
Let the velocity of the loaded freight car = v
We need to find out v.
m₁ u₁ + m₂ u₂ = ( m₁ + m₂) v
After putting the values into the equation above, we have,
30,000 × 0.85 + 110,000 × 0 = (30,000 + 110,000) v
140,000 v = 25500
v = 0.18 m/s
Thus, the required velocity of the loaded freight car is calculated to be 0.18 m/s.
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Why does the pattern of colors repeat in a thin soap film? Please use 2 content related sentences. Need to refer to constructive interference and half wavelength intervals.
Answer:
A colorful interference pattern is observed when light is reflected from the top and bottom boundaries of a thin oil film. The different bands form as the film's thickness diminishes from a central runoff-point. ... So one set of light rays shine into a soap bubble, but two sets of rays come back out again.
A 1200 kg car rounds a curve of radius 80 meters banked at an angle of 20°. What speed must the car travel to experience no friction between the tires and the road?
Answer:
if you wanna watch it in English it's called dub
A passenger elevator operates at an average speed of 8 m/s. if the 60th floor is 219 m above the first floor,how long does it take the elevator to go from the first floor to the 60th floor?
Answer:
27s
Explanation:
Time = distance/speed
Time = 219/8
Time = 27.375 s
Activity C (continued from previous page)
5. Draw connections: The uranium fission reactions are triggered by a neutron, and each
reaction produces two or three more neutrons. What do you think will happen next?
114
TA
Answer:
The neutrons released in the 1st fission reaction will trigger more fission reactions to occur., thus creating a chain reaction.
The fission reaction is a chain reaction. When the fissile nucleus is bombarded with a neutron, more neutrons are produced and the reaction continues indefinitely.
One of the types of artificial radioactive decay is nuclear fission. Nuclear fission occurs when a fissile nucleus is bombarded with a nucleus. When this occurs, the nucleus is broken up into smaller fragments called daughter nuclei and energy is produced.
Also, more neutrons are produced that can continue to bombard more of the fissile material in order to continue the reaction. As a result of this, nuclear fission is often referred to as a chain reaction because it is self sustaining.
Learn more:
an object with mass m is dropped from rest, one model for its speed v after t seconds, taking air resistance into account, is
The required lim t → ∝ v(t) when an object is dropped from rest is calculated to be mg/c.
Given that,
An object with mass m is dropped from rest and taking air resistance into account.
The velocity as a function of time is,
v(t) = (m g)/c [ 1 - e^-(ct/m)]
v(t) = (m g)/c [ 1 - 1/e^(ct/m)]
lim t → ∝ v(t) = (m g)/c [ 1 - 1/∝]
lim t → ∝ v(t) = (m g)/c ( 1 - 0)
lim t → ∝ v(t) = (m g)/c
Thus, the required lim t → ∝ v(t) when an object is dropped from rest is calculated to be mg/c.
The question is incomplete. The complete question is 'v = mg c (1 − e−ct/m) where g is the acceleration due to gravity and c is a positive constant describing air resistance. (a) Calculate lim t→∞ v.'
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To lift a baby from a crib 50 J of work is done. How much power is needed if the baby is
lighted in 0.5s?
Answer:
Power = 100 Watts
Explanation:
Given the following data;
Workdone = 50 Joules
Time = 0.5 seconds
To find the power needed;
Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
[tex] Power = \frac {workdone}{time} [/tex]
Substituting into the formula, we have;
Power = 50/0.5
Power = 100 Watts
4. A 9.35 kg bowling ball would require what force to accelerate it down an alleyway at
a rate of 3.12m/s²?
The force needed is 29.2 N.
To calculate the force needed to accelerate a 9.35 kg bowling ball at a rate of 3.12 m/s²,
you can use the equation F = ma, where F is the force, m is the mass of the object (in this case, the bowling ball), and a is the acceleration. Putting in the values, you get:
F = (9.35 kg) x (3.12 m/s²)
= 29.2 N
This works out to be approximately 29.2 Newtons of force.
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The scale on a map states that 1 centimeter corresponds to 20 kilometers. On the map, two cities are 0.3 cm apart. Find the actual distance.a.6 kmc.0.6 kmb.600 kmd.60 km
The actual distance is 6 km. The solution to the problem is as follows: By ratio and proportion: 1:20 = 0.3:x, Cross multiplying: 20(0.3) = x, x = 6
Therefore the answer is the first choice or letter A which is 6 km.
How would a surface without friction feel?It just seems slick, almost like touching ice but without the frigid sensation, according to my firsthand experience of both. Sorry, it's really nothing exceptional. Any surface would be sufficient if it had some lubrication oil on it.
Is there any surface in the world without friction?In reality, there are no frictionless planes. If they did exist, items on them would almost certainly behave exactly as Galileo predicted if they did. Despite not existing, they are extremely valuable for designing things like engines, motors, roads, and even tow truck beds, to mention a few.
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Is SCID a deletion mutation?
No, SCID is not a deletion mutation.
The AK2 gene, which codes for the mitochondrial enzyme adenylate kinase 2 (AK2), is mutated (missense mutations; deletions) in SCID, which is brought on by an increase in lymphocyte apoptosis [75,76]. A category of extremely rare diseases known as severe combined immunodeficiency (SCID) are brought on by abnormalities in various genes involved in the growth and operation of immune cells that fight infections. At birth, infants with SCID seem healthy, yet they are prone to serious infections.
Due to mutations in the gene encoding the common chain for several cytokine receptors, X-linked SCID is the most prevalent kind. Adenosine deaminase deficiency (ADA def.) and IL-7R-chain deficiency are the second and third most frequent causes, respectively.
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1 Write 7 next to the statements that are true.
Write F next to the statements that are false.
Then write corrected versions of the statements thatare false.
The pressure in a liquid dec reaches with depth.
The upthrust on an object is larger when it is deeper in a pool.
The bottom of a dam is thinner than the top of a dam.
The pressure is bigger at the bottom of a lake because of the weight of water above it
Answer: The pressure in a liquid dec reaches with depth. F
The pressure in a liquid increases with depth.
The upthrust on an object is larger when it is deeper in a pool. 7
The bottom of a dam is thinner than the top of a dam. F
The bottom of a dam is thicker than the top of a dam.
The pressure is bigger at the bottom of a lake because of the weight of water above it. 7
I think these are the answers.
the electrical potential due to a dipole on its axis at a point p at a large distance x from the dipole is given by v
The electrical potential due to a dipole at a point P on its axis at a large distance x from the dipole is given by the formula: V = (p * x) / (4 * pi * epsilon_0 * x^2)
Where:
p is the dipole moment, a vector quantity that represents the magnitude and direction of the dipole. It is defined as the product of the magnitude of one of the charges (q) and the distance between the charges (d), p = q*d.x is the distance from the dipole to point P, it is a scalar quantity.epsilon_0 is the electric constant or vacuum permittivity, it is a scalar quantity that relates the electric flux density to the electric field strength. Its value is approximately 8.85 x 10^-12 C^2/Nm^2.The equation assumes that point P is located on the axis of the dipole (the line connecting the two charges) and that the distance x is much larger than the size of the dipole. This means that the dipole can be considered as a point source of electric potential and the field at point P is well approximated by the field of a point charge.It's important to note that the formula gives the potential at point P due to the dipole, however, the dipole itself also has an electric field which can be found by taking the gradient of the potential.Learn more about the electrical potential here:
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why does increasing axon diameter increase conduction velocity conduction resistance capacitance
The increasing axon diameter increase the conduction velocity conduction in resistance capacitance because of the possibility of smooth movement of electrons in the capacitor and the smooth flow of charges in it that supports the electric current to flow in a smooth manner.
Capacitor is a body which is used to store the electricity in it and we can use it in the time when we need it in the circuit. also we can use the capacitor in the jumping the charge and electricity from the spark gap in the circuit to attain a good height and velocity as we needed it. by this information we can primarily consider that the increasing axon diameter increase the conduction velocity conduction in resistance capacitance because of the possibility of smooth movement of electrons in the capacitor and the smooth flow of charges in it that supports the electric current to flow in a smooth manner.
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(I know the velocity (1.6m/s) and now I want to find the angle of the vector. )
A rower intends to row his raft at its top speed of 1.5 m/s from the south bank of a river to a point
directly opposite on the north bank. He fails to recognise the river current which pulls a Jog west at
0.50 m/s, What is the raft's resultant velocity with respect to the bank?
Answer:
R = 1.5 to the northeast
C = .5 to the west
B = C + R adding vectors head to tail
Vector B will be straight north or directly across the river
B = (1.5^2 - .5^2)^1/2
B = 2^1/2 = 1.41
Adding the vectors as described shows that if the rower rows at 1.5 m/s in a northeasterly direction and the river carries the boat downstream at .5 m/s the net speed of the boat is 1.41 m/s straight north
A 64.5 kg astronaut is on a space walk when the tether line to the shuttle breaks. The astronaut is able to throw a 12.0 kg oxygen tank in a direction away from the shuttle with a speed of 14.9 m/s, propelling the astronaut back to the shuttle. Assuming that the astronaut starts from rest, find the final speed of the astronaut after throwing the tank.
The final speed of the astronaut after throwing the oxygen tank can be calculated using the conservation of momentum principle.
This principle states that the total momentum of an isolated system remains constant if no external forces act on the system.The momentum of the oxygen tank is given by the equation.
p_t = m_t*vThe conservation of momentum principle states that the initial momentum of the system is equal to the final momentum of the system.
p_i = p_f
The final momentum of the system is the momentum of the astronaut-tank system after the astronaut throws the tank.
p_f = (m_a + m_t)v_f = (64.5 + 12) * v_f = 76.5 * v_f
So the final momentum of the system is equal to the momentum of the oxygen tank.
p_t = m_tv = 1214.9 = 178.8We can set the two equations equal to each other and solve for v_f
178.8 = 76.5 * v_f
v_f = 178.8 / 76.5
v_f = 2.33 m/s
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A car is traveling $$ m/s when the gas pedal is released and the brakes are gradually applied, resulting in an acceleration given by the function $$ m/s^2. What is the distance traveled before the car comes to a stop?
The distance traveled before the car comes to a stop is 66.66 m. It's important to note that the negative sign on acceleration indicates that the car is slowing down.
Calculation-To find the distance traveled before the car comes to a stop, we can use the formula for distance traveled under constant acceleration. The formula is:
Distance = initial velocity * time + (1/2) * acceleration * time^2
The car is traveling at an initial velocity of 20 m/s and the acceleration is given by the function -6.0t, where t is the time in seconds.
We can find the time it takes for the car to come to a stop by setting the final velocity to 0 and solving for t.
0 = 20 + (-6.0)t
t = 20/6
t = 3.333 s
Now that we have the time, we can substitute it back into the distance formula along with the initial velocity and acceleration:
Distance = 20 * 3.333 + (1/2) * -6.0 * (3.333)^2
Distance = 66.66 m
How much further will the automobile go before stopping?The reaction distance for a vehicle traveling at 60 mph on the highway is 312 feet, and the reaction distance for a vehicle traveling at 80 mph is 496 feet. Simply put, at current speeds, doubling the car's speed will result in a three-fold increase in stopping distance.
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Expression for kinetic energy is __________ while that of potential energy is __________