Which location in the diagram above is the Southern Hemisphere experiencing summer?

Location A

Location B

Location C

Location D

Answer:

J

Explanation:

Because the vapor can be turned back to water and the vapor is still considered water.

Answer:

it does not have a control group

Explanation:

3 moles of O2 will be produced from 2moles of NaCLO3.

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Answer: 3 significant figures

Explanation: because in scientific notation only the before and after decimal number are considered but in standard form all numbers including exponents are all significant figures

Answer:

3 significant figures

Explanation:

0's are not significant.

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[tex]GraceRosalia[/tex]

If an element has three valence electrons, it is most likely a metal.

In the periodic table, metals are found towards the left hand side of the table. Metals have fewer valence electrons than nonmetals. In the periodic table, there are more metallic than nonmetallic elements.

Metals of group 13 typically have three valence electrons. Hence, if an element has three valence electrons, it is most likely a metal of group 13.

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For the reaction of deprotonation of formic acid, the concentration of HCOO⁻ at equilibrium is 0.0151 M if the initial concentration of formic acid is 1.35 M.  

The reaction of deprotonation of formic acid is the following:

CHOOH + H₂O ⇄ HCOO⁻ + H₃O⁺

At the equilibrium we have:

CHOOH + H₂O ⇄ HCOO⁻ + H₃O⁺    (1)

1.35 - x                         x           x

The acid equilibrium constant for this reaction is:

[tex] K_{a} = \frac{[HCOO^{-}][H_{3}O^{+}]}{[CHOOH]} = 1.7 \cdot 10^{-4} [/tex]  (2)

Entering the values of [CHOOH] = 1.35-x, [HCOO⁻] = [H₃O⁺] = x, into equation (2) we have:

[tex] 1.7 \cdot 10^{-4} = \frac{[HCOO^{-}][H_{3}O^{+}]}{[CHOOH]} = \frac{x^{2}}{(1.35 - x)} [/tex]  

[tex]1.7 \cdot 10^{-4}(1.35 - x) - x^{2} = 0[/tex]

After solving the above quadratic equation and taking the positive value for x (concentrations cannot be negative), we have:

[tex] x = [HCOO^{-}] = [H_{3}O^{+}] = 0.0151 M [/tex]

Therefore, the concentration of HCOO⁻ at equilibrium is 0.0151 M.

Learn more about the equilibrium constant here:

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CAN YOU BRAINLEST ME

Answer:

2 electrons is the correct answer hope u pass !!!!!!

Explanation:

The added greenhouse gases absorb the heat. They then radiate this heat. Some of the heat will head away from the Earth, some of it will be absorbed by another greenhouse gas molecule, and some of it will wind up back at the planet's surface again. With more greenhouse gases, heat will stick around, warming the planet.

Answer:

Please click above answer.

Answer:

285 kJ

Explanation:

potential energy

= m g h

= 95,000 g × 10 m/s² × 300 meters

= 95 kg × 10 m/s² × 300 meters

= 950 kgm/s² × 300 meters

= 285,000 J

= 285 kJ

Answer:

D. Grass Health

Explanation:

Answer:

hh

Explanation:

There are 2.72 kilograms of nitrogen present in a 3.50 L sample of N₂O.

To find the mass of nitrogen in N₂O, we must calculate the number of moles of N₂O.  

[tex] n_{N_{2}O} = \frac{m_{N_{2}O}}{M{N_{2}O}} [/tex]  (1)

Where:

[tex] m_{N_{2}O}[/tex]: is the mass of N₂O

[tex]M_{N_{2}O}[/tex]: is the molar mass of N₂O = 44.013 g/mol

The mass of N₂O can be founded from the density:

[tex] d = \frac{m}{V} [/tex] (2)

Where:

d: is the density of N₂O = 1.22 g/mL

V: is the volume = 3.50 L = 3500 mL

Then, the mass of N₂O is (eq 2):

[tex] m = d*V = 1.22 g/mL*3500 mL = 4270 g [/tex]

Now, the number of moles of N₂O is (eq 1):

[tex] n_{N_{2}O} = \frac{4270 g}{44.013 g/mol} = 97.02 \:moles [/tex]

Knowing that in 1 mol of N₂O we have 2 moles of N, the number of moles of nitrogen is:

[tex] n_{N} = \frac{2\: moles \: N}{1 \:mol \: N_{2}O}*n_{N_{2}O} = \frac{2\: moles \: N}{1 \:mol \: N_{2}O}*97.02 \:moles \:N_{2}O = 194.04 \: moles [/tex]

Finally, with the number of moles of N we can find its mass:

[tex] m = n_{N}*M_{N} = 194.04 \:moles*14.007 g/mol = 2717.9 g = 2.72 kg [/tex]

Therefore, there are 2.72 kilograms of nitrogen.  

Find more about the number of moles here:

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Answer:

I think it's number one option

Answer: 49,603.4011

Explanation:

Answer:

49603.4011

Explanation:

89.001

+. 0.0001

348.4

49166

answer: 49603.4011

Answer:  See below

Explanation:  a.  The mass of an element is composed of:

protons:     1 amu each

neutrons:   1 amu each

electrons:   0 amu each

Only the protons and neutrons are counted in the atomic mass of an element

b.  Electrons are assigned a mass of 0.  They do have a mass, but it is exceedingly small compared to the protons and neutrons, so they are left out of the calculation of an element's mass.

c.  An element becomes unstable if the neutrons exceed the protons by a certain ratio, dependent on the element.

Answer:

A a chemical change

Explanation:

because a chemical change is when you mix tow substance together and they creat a new substance

Answer:

See below

Explanation:

2C2H6 + 7O2 = 4CO2 + 6H2O

2C2H2 + 5O2 = 4CO2 + 2H2O

A lot of this is trial and error.  I start from left to right.  For the first reaction, you had

C2H6 + O2  =  CO2  +  H2O

You have 2 carbons on the left so you can try adding a 2 in front of the carbons on the right and keep going from there.  Now you have

C2H6  +  O2  =  2CO2  + H2O

You now have 2 C on each side.  C2 is the same as 2C.

The next step is to look at the hydrogens on the left.  You have 6 so you need 6 on the right.  You can add a 3 in front of the H on the right.  The H already has a subscript of a 2 so having the 3 in front will now make it 6H.  You now have this

C2H6  +  O2  =  2CO2  +  3H2O

So your C are equal (2 on each side) and your H is equal (6 on each side).  All that is left is the O.  So far you have 2 on the left but you have 7 on the right (4 from the 2CO2 and 3 more from 3H2O).  Since you have an even number on one side and an odd number on the other, there is no way to make this work.  So it's time to start over.

My next step was to put a 2 in front of C2H6 and keep going as we did above.  Start with this

2C2H6   + O2  = CO2  + H2O

You have 4 C on the left.  So you need to add a 4 in front of CO2 to get 4 C on the right.  Now you have this

2C2H6  +  O2  =  4CO2  +  H2O

Now on the left you have 12 H (2 in front times the 6 subscript on the H).  You need to have 12 on the right.  We can get that by putting a 6 in front of the H2O ( again the 6 in front times the 2 subscript of the H is 12 total).  You have this now

2C2H6  +  O2  = 4CO2  +  6H2O

You now have 4 C on both sides, 12 H on both sides.  All that is left now is the O.

On the right side, you have a total of 14 ( 8 from the 4CO2 and 6 from 6H2O).  So you'd need to add 7 in front of the O2 to make it 14.

You're done.  4 C on both sides, 12 H on both sides and 14 O on both sides.

The second equation I just did the same process.

Answer:

7.96 x 10^-22 J

Explanation:

Answer:

B. Living organism can be created from nonliving matter

Explanation:

The theory of spontaneous generation states that life could come from non-living things.

Answer:

d

Explanation:

thanks so much to you welcomeeee for me and my brother in the same situation and he does it for a year of life in your relationship

Answer:

molecular compound

Explanation:

it has two or more nonmetal elements and are covalently bonded

Under conditions of very high pressures, the volume would be lower than predicted by the Ideal Gas Law.

According to the kinetic theory of gases, a gas spreads out to fill the volume of the container holding it. Hence a gas does not have a definite volume due to the fact that there is no inter-molecular interaction between gas molecules.

When the gas is subjected to very high pressure, inter-molecular interactions become significant leading to a decrease in the volume of the gas.

Therefore, when subjected to high pressure, the experimental volume would be lower than predicted by the Ideal Gas Law.

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Answer:

30 protons

Explanation: Each zinc isotope contains 30 protons, 30 massive, positively charged nuclear particles

30 protons, 34 neutrons, and 30 electrons.

v=5.0×10^12Hz

[tex]\\ \sf\longmapsto E=hv[/tex]

[tex]\\ \sf\longmapsto E=6.626\times 10^{-34}Js\times 5\times 10^12s^{-1}[/tex]

[tex]\\ \sf\longmapsto E=33.13\times 10^{-22}J[/tex]