Which of the following is an example of the identity property of 1?
O 0+2 = 24
O 3 - 2 = 1
O (1) = 1
1.11(0) = 0

Answer:

[tex](-\infty, \infty)[/tex]

Step-by-step explanation:

There are no restrictions on the possible values of [tex]x[/tex], because you can square any number.

Because [tex]x[/tex] can be anything, the domain is all reals or [tex]\boxed{(-\infty, \infty)}[/tex] which means [tex]x[/tex] can be any real number.

Answer:

Get the perimeter of the each shape and add it all up to get the total fencing material required. 2 square flower beds = 2 x 4a = 8a 1 rectangular play ground = 2l + 2w  total fencing material = 8a + 2l + 2w  

Answer:

2l + 2w + 8a

Step-by-step explanation:

Answer:

11 flowers

Step-by-step explanation:

Step-by-step explanation:

Perimeter of the quadrilateral = sum of the length of all the four sides. Note: Missing side of the quadrilateral = Perimeter of the quadrilateral - Sum of the length of three sides.

[tex]k(x) \times f(x)[/tex]

[tex](2x + 5) \times (x - 1)[/tex]

[tex]2 x(x - 1) + 5(x - 1)[/tex]

[tex] ({2 x }^{2} - 2x) + (5x - 5)[/tex]

[tex] {2x}^{2} - 3x - 5[/tex]

________________________________

[tex]k(x) \times g(x) \times f(x)[/tex]

[tex]g(x) \times (k(x) \times f(x))[/tex]

[tex] ({6x }^{2} - 4x + {3x}^{4} ) \times ( {2x}^{2} - 3x - 5)[/tex]

[tex] {6x}^{2} ( {2x}^{2} - 3x - 5) - 4x ( {2x}^{2} - 3x - 5) + {3x}^{4} ( {2x}^{2} - 3x - 5)[/tex]

[tex]12 {x}^{4} - 18 {x}^{3} - 30 {x}^{2} - {8x}^{3} - 12 {x}^{2} - 20x + {6x}^{6} - 9x {}^{5} - {15x}^{4} [/tex]

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The value of the numerical expression {[(20 – 32) ÷ (–6)]² – 11} ÷ (–7) will be 1.

When the relevant factors and natural laws of a mathematical model are given values, the outcome of the calculation it describes is the expression's outcome.

The expression is given below.

⇒ {[(20 – 32) ÷ (–6)]² – 11} ÷ (–7)

Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction are all part of the PEMDAS formula. To answer the problem properly and accurately, this rule must be followed.

⇒ {[(20 – 32) ÷ (–6)]² – 11} ÷ (–7)

⇒ {[(–12) ÷ (–6)]² – 11} ÷ (–7)

⇒ {[2]² – 11} ÷ (–7)

⇒ {4 – 11} ÷ (–7)

⇒ (– 7) ÷ (–7)

⇒ 1

The value of the numerical expression {[(20 – 32) ÷ (–6)]² – 11} ÷ (–7) will be 1.

More about the value of the expression link is given below.

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Answer:

3 4/5

Step-by-step explanation:

Answer:

22 3/4 inches.

Step-by-step explanation:

First what I like to do is find least common denominator.

Since 2 of the ribbons are measured in /4's, and the other ribbon is measured by half ( /2). 4 will be your new denominator making the 18 1/2 in. long ribbon 18 2/4 inches.

Now, the Blue ribbon is 3/4 greater than the Red ribbon, making it the 18 2/4 inch ribbon.

The Yellow ribbon is 4 3/4 inches longer than the Blue ribbon which means add 4 3/4's to 18 2/4, and you get = 22 3/4 in. for the yellow ribbon.

Hopes this Help!

Answer:

     [tex]-64u^{3}[/tex][tex]v^{6}[/tex]

Step-by-step explanation:

Answer:

(-64u³vto the 6th power)

Step-by-step explanation:

(4³u³v to the 6th power)

(-64u³vto the 6th power)

Answer:

Step-by-step explanation:

Lisa's rate is 1/3 of job per hour

Rachel's rate is 1/4 of job per hour

Their rate if worked together:

Job will be done in:

Answer:

243.5

Step-by-step explanation:

3409/14 times 7/7

By the way i divided both numerator and denominator by 77 because of gcf

Reduce

487/2

243.5

Answer:

0.8413

Step-by-step explanation:

bad explainer srry

Answer:

Step-by-step explanation:

[tex](\frac{115-100}{15})=1[/tex]

because we're looking for the zscore associated with it being greater than we flip the sign

so the answer is just -1

Answer:

Step-by-step explanation:

w = width

3w = three times the width

3w-7=7 feet less than three times the width

l = length = 3w-7

A=length × width (lw)

66 = (3w-7) × (w)

66 = 3w^2 - 7w

3w^2 - 7w -66 =0

factor

3 = 3 × 1 and 66 = 6 × 11,

6 × 3 = 18,  11 × 1 = 11,  18 - 11 = 7

(3w   )(w   )=0 so far

(3w   )(w  6)=0 so far

(3w   11)(w   6)=0 so far

(3w+11)(w-6)=0

w-6=0

w=6

3w=3*6=18

3w-7=3*6-7=18-7=11

w=6 feet

l=11 feet

Answer:

3

Step-by-step explanation:

Move the terms : 2x + 1 =10 -x

Collect like terms

Calculate : 2x + x=10-1

Divide both sides

3x = 9

x = 3

Step-by-step explanation:

the explantion is in the photo

Answer:

1/2

Step-by-step explanation:

Your equation is 16-2^3/16

First, you find out what 2^3 is equal to

2 x 2 x 2=8

Your equation will then be 16-8/16

Next, you subtract 8 from 16

16-8=8

Your equation will then be 8/16

divide both 8 and 16 by 4

8/4=2, 16/4=4

=2/4

You then simplify 2/4 to it's lowest terms

2/2=1 , 4/2=2

=1/2

Answer:

x=14/9

Step-by-step explanation:

Answer:

x = 0

Step-by-step explanation:

9x - 7 = -7

9x - 7 + 7 = -7 + 7

9x = 0

9/9x = 0/9

x = 0

Answer:

seventeen plus twelve minus thirty

Step-by-step explanation:

17 + 12 - 30 = -1

is it a big number or short number

The required number of cars that can be washed by Damien in 40 hours is 25.

Given that,
Damien washes cars on his summer vacation to earn money. It took him 16 hours to wash 10 cars. Use scaling to complete the table to determine the number of cars Damien could wash in 40 hours, is to be determined.

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,

Here,
Let the number of cars that were washed in 40 hours be x,
Now, according to the question.
16 / 10 = 40 / x
x = 400 / 16
x = 25

Thus, the required number of cars that can be washed by Damien in 40 hours is 25.

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C)50mph

speed= distance÷time

so ....

we find how much 25 miles took therefore we do

25÷0.5

which is

=50

Hope this helped you, have a good day bro cya)

Answer:

fast

Step-by-step explanation:

historical definition

Italian physicist Galileo Galilei is usually credited with being the first to measure speed by considering the distance covered and the time it takes. Galileo defined speed as the distance covered per unit of time.[3] In equation form, that is

{\displaystyle v={\frac {d}{t}},}v={\frac  {d}{t}},

where {\displaystyle v}v is speed, {\displaystyle d}d is distance, and {\displaystyle t}t is time. A cyclist who covers 30 metres in a time of 2 seconds, for example, has a speed of 15 metres per second. Objects in motion often have variations in speed (a car might travel along a street at 50 km/h, slow to 0 km/h, and then reach 30 km/h).

Instantaneous speed

Speed at some instant, or assumed constant during a very short period of time, is called instantaneous speed. By looking at a speedometer, one can read the instantaneous speed of a car at any instant.[3] A car travelling at 50 km/h generally goes for less than one hour at a constant speed, but if it did go at that speed for a full hour, it would travel 50 km. If the vehicle continued at that speed for half an hour, it would cover half that distance (25 km). If it continued for only one minute, it would cover about 833 m.

In mathematical terms, the instantaneous speed {\displaystyle v}v is defined as the magnitude of the instantaneous velocity {\displaystyle {\boldsymbol {v}}}{\boldsymbol {v}}, that is, the derivative of the position {\displaystyle {\boldsymbol {r}}}{\boldsymbol {r}} with respect to time:[2][4]

{\displaystyle v=\left|{\boldsymbol {v}}\right|=\left|{\dot {\boldsymbol {r}}}\right|=\left|{\frac {d{\boldsymbol {r}}}{dt}}\right|\,.}v=\left|{\boldsymbol  v}\right|=\left|{\dot  {{\boldsymbol  r}}}\right|=\left|{\frac  {d{\boldsymbol  r}}{dt}}\right|\,.

If {\displaystyle s}s is the length of the path (also known as the distance) travelled until time {\displaystyle t}t, the speed equals the time derivative of {\displaystyle s}s:[2]

{\displaystyle v={\frac {ds}{dt}}.}v={\frac  {ds}{dt}}.

In the special case where the velocity is constant (that is, constant speed in a straight line), this can be simplified to {\displaystyle v=s/t}v=s/t. The average speed over a finite time interval is the total distance travelled divided by the time duration.

Average speed

Different from instantaneous speed, average speed is defined as the total distance covered divided by the time interval. For example, if a distance of 80 kilometres is driven in 1 hour, the average speed is 80 kilometres per hour. Likewise, if 320 kilometres are travelled in 4 hours, the average speed is also 80 kilometres per hour. When a distance in kilometres (km) is divided by a time in hours (h), the result is in kilometres per hour (km/h).

Average speed does not describe the speed variations that may have taken place during shorter time intervals (as it is the entire distance covered divided by the total time of travel), and so average speed is often quite different from a value of instantaneous speed.[3] If the average speed and the time of travel are known, the distance travelled can be calculated by rearranging the definition to

{\displaystyle d={\boldsymbol {\bar {v}}}t\,.}d={\boldsymbol  {{\bar  {v}}}}t\,.

Using this equation for an average speed of 80 kilometres per hour on a 4-hour trip, the distance covered is found to be 320 kilometres.

Expressed in graphical language, the slope of a tangent line at any point of a distance-time graph is the instantaneous speed at this point, while the slope of a chord line of the same graph is the average speed during the time interval covered by the chord. Average speed of an object is Vav = s÷t

Difference between speed and velocity

Speed denotes only how fast an object is moving, whereas velocity describes both how fast and in which direction the object is moving.[5] If a car is said to travel at 60 km/h, its speed has been specified. However, if the car is said to move at 60 km/h to the north, its velocity has now been specified.

The big difference can be discerned when considering movement around a circle. When something moves in a circular path and returns to its starting point, its average velocity is zero, but its average speed is found by dividing the circumference of the circle by the time taken to move around the circle. This is because the average velocity is calculated by considering only the displacement between the starting and end points, whereas the average speed considers only the total distance travelled.

Answer: 15km, 7.5kmh

Step-by-step explanation:

a. Distance travelled = speed * time = 15* 1 =15km

b. Distance = 15

time = 2hrs

Speed = distance/time = 15/2 = 7.5kmh

Answer:

I think it is d or a. I might be wrong sorry

Step-by-step explanation:

Answer:

1. x = -1

2. y = -1, y = 2

3. y = -½ + i [tex]\frac{\sqrt{3} }{2}[/tex]; y = -½ - i [tex]\frac{\sqrt{3} }{2}[/tex]

4. x = -3; x = -6

Step-by-step explanation:

I will only produce work for questions 1 through 4, and you could follow the same steps for questions 5 and 6 so that you could learn and get used to solving quadratic equations. I am practically using the same techniques in solving questions 1 through 4 anyway.

1.) x² + 2x + 1 = 0

where a = 1, b = 2, c = 1

Determine the nature and number of solutions based on the discriminant, b² - 4ac:

b² - 4ac = 2² - 4(1)(1) = 4 - 4 = 0  

This means that the equation has one real root.  

Next, determine the factors of the quadratic equation.  

Use the perfect square trinomial factoring technique:

u² + 2uv + v² = (u + v)²

From the equation, x² + 2x + 1 = 0

where a = 1, b = 2, c = 1

Find factors with product a × c and sum b:

Possible factors:

product a × c :  1 × 1 = 1

sum b :  1 + 1 = 2

Therefore, the binomial factors of x² + 2x + 1 = 0 is (x + 1)²

To find the roots, set x = 0:

x + 1 = 0

Subtract 1 from both sides to isolate x:

x + 1 - 1 = 0 - 1

x = -1  (This is the root of the equation).

2)  y² - y - 2 = 0

where a = 1, b = -1, and c = -2

Determine the nature and number of solutions based on the discriminant, b² - 4ac:  

b²  - 4ac = (-1)² - 4(1)(-2) = 9  

Since b² - 4ac > 0, then it means that the equation will have two real roots.

From the equation, y² - y - 2 = 0

where a = 1, b = -1, and c = -2:

Find factors with product a × c and sum b:

 Product a × c :  

1 × -2 = -2

-1 × 2 = -2

Sum b:  

1+ (-2) = -1

-1 + 2 = 1

Therefore, the possible factors are: 1 and -2:

(y + 1) (y - 2)

To find the roots, set y = 0:

y + 1 = 0

Subtract 1 from both sides:

y + 1 - 1 = 0 - 1

y = -1

y - 2 = 0

Add 2 to both sides:

y -2 + 2 = 0 + 2

y = 2

Therefore, the roots of the quadratic equation, y² - y - 2 = 0 are: y = -1 and y = 2.

3.)  y² + y + 1 = 0

where a = 1, b = 1, and c = 1

Determine the nature and number of solutions based on the discriminant, b² - 4ac:  

b² - 4ac = (1)2 - 4(1)(1) = -3

Since b² - 4ac < 0, then it means that the equation will have two complex roots.

Use the Quadratic Formula:

[tex]y = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}[/tex]

[tex]y = \frac{-1 +/- \sqrt{1^{2} - 4(1)(1)} }{2(1)}[/tex]

[tex]y = \frac{-1 +/- \sqrt{1 - 4} }{2}[/tex]

[tex]y = \frac{-1 +/- \sqrt{-3} }{2}[/tex]

[tex]y = \frac{-1 +/- i\sqrt{3} }{2}[/tex]

Therefore, the roots of the quadratic equation, y² + y + 1 = 0 are:

y = -½ + i [tex]\frac{\sqrt{3} }{2}[/tex]; y = -½ - i [tex]\frac{\sqrt{3} }{2}[/tex]

4) x² + 9x + 18 = 0

where a = 1, b = 9, and c = 18.

Determine the nature and number of solutions based on the discriminant, b² - 4ac:  

b² - 4ac = (9)2 - 4(1)(18) = 9

Since b² - 4ac > 0, then it means that the equation will have two real roots.

Use the Quadratic Formula:

[tex]x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}[/tex]

[tex]x = \frac{-9 +/- \sqrt{9^{2} - 4(1)(18)} }{2(1)}[/tex]

[tex]x = \frac{-9 +/- \sqrt{9} }{2}[/tex]

[tex]x = \frac{-9 + 3}{2}; x = \frac{-9 - 3}{2}[/tex]

[tex]x = \frac{-6}{2}; x = \frac{-12}{2}[/tex]

x = -3; x = -6

Therefore, the roots of the quadratic equation, x² + 9x + 18 = 0

are: x = -3 and x = -6.  

Answer:

One of the earliest known mathematicians were Thales of Miletus.

Archimedes of Syracuse

The first calculation of π ( pi ) was done by Archimedes of Syracuse (287–212 BC), one of the greatest mathematicians of the ancient world.

Answer: 8lbs

Step-by-step explanation:

The baby gained one pound

Assuming linear growth, the baby would weigh approximately 8 lbs after 4 weeks.

Assuming linear growth, we can use the concept of a slope to estimate the baby's weight after 4 weeks.

Given information:

Weight at birth (0 weeks): 7 lbs

Weight after 20 weeks: 12 lbs

We can calculate the rate of change (slope) of the baby's weight per week:

Slope = (Change in weight) / (Change in weeks)

Slope = (12 lbs - 7 lbs) / (20 weeks - 0 weeks)

Slope = 5 lbs / 20 weeks

Slope = 0.25 lbs/week

Now, using the slope, we can estimate the baby's weight after 4 weeks:

Estimated weight change = Slope * Number of weeks

Estimated weight change = 0.25 lbs/week * 4 weeks

Estimated weight change = 1 lb

So, the baby's weight after 4 weeks would be the initial weight (7 lbs) plus the estimated weight change (1 lb):

Estimated weight after 4 weeks = Initial weight + Estimated weight change

Estimated weight after 4 weeks = 7 lbs + 1 lb

Estimated weight after 4 weeks = 8 lbs

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Answer:

Deon

Step-by-step explanation:

Deon-12 ppd

Emily-9 ppd

Deon reads more pages per day

Answer:

Deon read  3 more  pages per day than Emily.