Answer:
2^1/6
Step-by-step explanation:
either find the result of all equations or
times square root(2) by cube root (3) and put it over 1
... 1/6 and put this as the power to the number in the question
Which are the foci of the hyperbola represented by 5x2 – 4y2 + 80 = 0?
Step-by-step explanation:
[tex]5 {x}^{2} - 4 {y}^{2} + 80 = 0[/tex]
[tex]5 {x}^{2} - 4 {y}^{2} = - 80[/tex]
[tex] - \frac{ 5{x}^{2} }{16} + \frac{ {y}^{2} }{20} = 1[/tex]
[tex] \frac{ {y}^{2} }{20} - \frac{5 {x}^{2} }{16} = 1[/tex]
To find foci,
[tex]c = \sqrt{ {a}^{2} + b {}^{2} } [/tex]
so
[tex]c = \sqrt{20 + 16} [/tex]
[tex]c = \sqrt{36} [/tex]
[tex]c = ±6[/tex]
Since the y term has a greater denomiator, our foci is
(0,6) and (0,-6)
i don't get it
-5/6x-3>1
Answer: [tex]x < -\frac{24}{5}[/tex]
Step-by-step explanation:
You have:
[tex]-\frac{5}{6} x-3 > 1[/tex]
Add 3 to both sides to get:
[tex]-\frac{5}{6} x > 4[/tex]
Multiply both sides by 6 to get:
[tex]-{5} x > 24[/tex]
Divide both sides by -5. When you divide an inequality by a negative number, you must switch the signs. Therefore:
[tex]x < -\frac{24}{5}[/tex]
Answer:
The equation is saying multiply or add negative 5/6 to x, then subtract by positive 3 which makes the number go upwards, but not making it positive, and lastly, the equation is saying the result will be greater than 1.
One of the values for x is 5, because...
[tex]-\frac{5}{6} * 5 = -4\frac{1}{6} - 3 = 7\frac{1}{6} > 1[/tex]
With that information, the statement is now complete and true. If you make 5 or anything more than 5 the value for x, the statement will still be true.
Note that I just used 5 as one of the solutions. There are many more than that.
I’ll give you brainliest for the first person with an answer
Solve the follwing please:
[tex]\dfrac{(-9-11)/(-4)}{-7^2+(11 \times 2^2)}\\\\=\dfrac{(-20)/(-4)}{-49+44}\\\\=\dfrac{5}{-5}\\\\=-1[/tex]
Calculate the exact perimeter and area of the equilateral triangle.
10 cm
Answer:
30 cm
Step-by-step explanation:
just times it by three because theres three sides
PLS ANSWER ASAP
There are 567 calories in nine ounces of a certain ice cream. How many calories are there in three pounds?
Before we start, we gotta acknowledge that one pound is 16 oz.
Okay, so to solve this we need to make a ratio. We know there are 567 calories for every 9 oz. That'll look like 567/9. And to compare this to pounds we have to convert those three pounds to ounces by multiplying: 3*16 = 48. So now we can grab that ratio and use cross multiplication to find the answer:
567/9 = x/48
9x = 567*48
9x = 27216
x = 3024
So there are 3024 calories in three pounds of the ice cream.
There are 3024 calories in a certain type of ice cream.
What is a unitary method?A unitary method is a mathematical way of obtaining the value of a single unit and then deriving any no. of given units by multiplying it with the single unit.
We know one pound is equal to 16 ounces.
So, 9 ounces is equal to 9/16 pounds.
Given, There are 567 calories in nine ounces of certain ice cream.
So, There are 567 calories in (9/16) pounds of certain ice cream.
Or, (567)/(9/16).
= 567×(16/9).
= 1008 calories in one pound.
Therefore, There is 1008×3 = 3024 calories in 3 pounds of ice cream.
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5. Six eggs are used in a recipe to make 12
pancakes. If Chef Conrad uses exactly one dozen
eggs for the morning pancake orders, how many
3-pancake servings can he prepare?
Answer:
He can make eight 3-pancake servings.
Step-by-step explanation:
6 eggs make 12 pancakes.
12 eggs make 24 pancakes.
24 divided by 3 is 8.
If u(x) = x5 – x4 x2 and v(x) = –x2, which expression is equivalent to (startfraction u over v endfraction) (x)? x3 – x2 –x3 x2 –x3 x2 – 1 x3 – x2 1
An expression is defined as a set of numbers, variables, and mathematical operations. The expression that can represent u/v is -x³+x²-1.
What is an Expression?In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.
The expression which can represent the u/v can be found in the following manner,
[tex]\dfrac {u}{v} = \dfrac{x^5-x^4+x^2}{-x^2}\\\\\dfrac {u}{v} = \dfrac{x^2(x^3-x^2+1)}{-x^2}\\\\\dfrac {u}{v} = \dfrac{(x^3-x^2+1)}{-1}\\\\\dfrac {u}{v} = -x^3+x^2-1[/tex]
Thus, the expression that can represent u/v is -x³+x²-1.
Learn more about Expression:
https://brainly.com/question/13947055
Answer:
C
Step-by-step explanation:
NO BOTS!! What’s The Answer of this math image?
Answer:
In part B the answer is 71.
Step-by-step explanation:
In the 3 lines the 2 uppermost and downer most lines look like they make up a 90 degree angle.. since the first one is 19 all we have to do is 90 - 19 which equals 71. Sorry I do not know the answer to part A :(
GIVING BRAINLEST TO THE PERSON THAT CAN EXPLAIN HOW TO DO THIS THE BEST :)
Answer:
4π
Step-by-step explanation:
since the shaded in area is the tile and the radius is 2 and we only need the SHADED IN area 2^2 is 4 therefore 4pi is the correct answer
Is -14 greater than 9
Answer:
No, -14 is not greater than 9
Step-by-step explanation:
because -14 is a negative interger making the postive a higher/greater number
Do you think that extrapolation or interpolation is more accurate? Explain.
Answer:
Interpolation is used to predict values that exist within a data set, and extrapolation is used to predict values that fall outside of a data set and use known values to predict unknown values. Often, interpolation is more reliable than extrapolation, but both types of prediction can be valuable for different purposes
What is the value of the expression, written in standard form?
We are told to the write the given expression in standard form ;
[tex]{:\implies \quad \sf \dfrac{6.6\times 10^{-2}}{3.3\times 10^{-4}}}[/tex]
Rewrite as ;
[tex]{:\implies \quad \sf \dfrac{66\times 10\times 10^{-2}}{33\times 10\times 10^{-4}}}[/tex]
[tex]{:\implies \quad \sf \dfrac{2\times 10^{-2}}{10^{-4}}}[/tex]
[tex]{:\implies \quad \sf 2\times \dfrac{10^{-2}}{10^{-4}}}[/tex]
[tex]{:\implies \quad \sf 2\times 10^{-2-(4)}\quad \qquad \bigg\{\because \dfrac{a^m}{a^n}=a^{m-n}\bigg\}}[/tex]
[tex]{:\implies \quad \sf 2\times 10^{-2+4}}[/tex]
[tex]{:\implies \quad \boxed{\bf{2\times 10^{2}}}}[/tex]
This is the required answer
Help! I will give brainliest!!!
Answer:
[tex] r = 8.58~cm [/tex]
Step-by-step explanation:
[tex] S = \dfrac{n}{360^\circ}2\pi r [/tex]
[tex] 38.95~cm = \dfrac{260^\circ}{360^\circ}2\pi r [/tex]
[tex] 38.95~cm = 4.5378r [/tex]
[tex] r = 8.58~cm [/tex]
HELP ASAP MY SIS NEEDS HELP AGAIN
Answer:
$128.10
Step-by-step explanation: (8 * 16.95) - 7.50(135.6) - 7.50128.1
Hopefully this helps you if you don't mind clicking brainliest :)
Find the center, vertices, and foci of the ellipse with the given equation. (x+4)2/400 + (y+3)2/144 = 1
[tex]\textit{ellipse, horizontal major axis} \\\\ \cfrac{(x- h)^2}{ a^2}+\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2- b ^2} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\cfrac{(x+4)^2}{400}~~ + ~~\cfrac{(y+3)^2}{144}~~ = ~~1\implies \cfrac{[x-(-4)]^2}{20^2}~~ + ~~\cfrac{[y-(-3)]^2}{12^2}~~ = ~~1 \\\\\\ \begin{cases} h=-4\\ k=-3\\ a=20\\ b=12 \end{cases}\qquad \qquad c=\sqrt{20^2-12^2}\implies c=\sqrt{256}\implies \boxed{c=16} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\stackrel{center}{(-4,-3)}\qquad vertices \begin{cases} (\stackrel{-4-20}{-24}~~,~~-3)\\\\ (\stackrel{-4+20}{16}~~,~~-3) \end{cases}\qquad foci \begin{cases} (\stackrel{-4-16}{-20}~~,~~-3)\\\\ (\stackrel{-4+16}{12}~~,~~-3) \end{cases}[/tex]
Pls help i dont understand angles
Joanne is making punch. She uses 1/2 gallon of orange juice, 3 quarts of lemonade, and 1 1/4 gallons of apple cider. How many quarts of punch will she have all together?
Answer:
10 Quarts
Step-by-step explanation:
First, convert 1/2 gallons into quarts. 1/2x4=2. Then convert 1 1/4 to quarts. 1 1/4x4=5. Finally, add it all togher. 2+5+3=10. So, the answer is 10 quarts.
Here are the numbers of times 9 people ate out last month. 3,3,4 ,4 ,3 ,7,6 ,7,7 Find the modes of this data set. If there is more than one mode, write them separated by commas. If there is no mode, click on "No mode."
Answer:
3, 7
Step-by-step explanation:
3, 3, 3, 4, 4, 6, 7, 7, 7
3 and 7
A person standing at the edge of a cliff 48 feet tall throws a ball up and just off the cliff with an initial upward velocity of 8 feet per second. What is the maximum height of the ball? When will the ball hit the ground?
The ball will be at its highest at ___
feet.
The ball will hit the ground at t =___
second(s)
Check the picture below.
since the cliff is 48 feet tall, thus that its initial height.
[tex]~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&8\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&48\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases} \\\\\\ h(t)=-16t^2+8t+48[/tex]
well, as you can see in the picture, its maximum is at its vertex, so
[tex]\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-16}x^2\stackrel{\stackrel{b}{\downarrow }}{+8}x\stackrel{\stackrel{c}{\downarrow }}{+48} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 8}{2(-16)}~~~~ ,~~~~ 48-\cfrac{ (8)^2}{4(-16)}\right)\implies \left(\cfrac{1}{4}~~,~~48-\cfrac{64}{-64} \right)[/tex]
[tex]\left( \frac{1}{4}~~,~~48+1 \right)\implies \stackrel{\textit{the ball is at highest}}{\left(\frac{1}{4}~~,~~\stackrel{\downarrow }{49} \right)}[/tex]
well, it hits the ground when y = 0.
[tex]\stackrel{h(t)}{0}=-16t^2+8t+48\implies 0=8(-2t^2+t+6)\implies 2t^2-t-6=0 \\\\\\ (2t+3)(t-2)=0\implies t= \begin{cases} -\frac{3}{2}\\\\ 2~~\textit{\large \checkmark} \end{cases}[/tex]
notice, we didn't use the negative value, since "t" must be greater than 0.
About how many times greater is 17*10^8 than 4*10^8?
Answer:
8 x 10^5
Step-by-step explanation:
find the length of the segment with endpoints at (2, 7) and (8, -1)
Answer:
10
Step-by-step explanation:
→ Find the difference in x coordinates
8 - 2= 6
→ Find the difference in y coordinates
-1 - 7 = -8
→ Use Pythagoras
√6² + (-8)² = 10
trigonometric angles without a calculator
[tex]~~~~~~~\cos x = \dfrac{ \text{Base}}{\text{Hypotenuse}}\\ \\\\\implies \cos x= \dfrac{9}{18}\\\\\\\implies \cos x = \dfrac 12\\\\\\\implies x= \cos^{-1} \left( \dfrac 12\right)\\ \\ \\\implies x = 60^{\circ}[/tex]
Pls help thankssssss
PLEAASSEE HELP 15 POINTS!!!!
Answer:
Step-by-step explanation:
Remark
The purple lines cross but once. A solution to a set of functions counts how many times the functions cross. Since these two lines cross but once, there is only 1 solution.
If the lines are parallel, they never cross. That means there are no solutions.
If you are given 2 equations and one is the same line as the second one, then there are an infinite number of solutions.
Hi!
Solutions to systems of equations are only where the lines intersect at a point.
That means that if the lines cross over at any point, they have a solution. Lines that don't have a solution -- parallel lines -- do not cross over.
In this graph, we can see that it crosses over at only one point.
That means that this system of equations has exactly one solution.
For a similar problem, see:
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The circumference of a dinner plate is 19.4 cm. What is its radius ?
We are given that:
Circumference = 19.4 cm
Formula:
2πr = Circumference
Rewrite the equation:
⇒ 2πr = Circumference = 19.4 cm⇒ 2πr = 19.4 cmThe "r" variable represents the radius of the circle. Thus, we need to isolate it on one side to determine the radius. This can be done with the four mathematical operations (+ - × ÷). Since the "÷" is included, we can divide both sides by 2π to isolate the "r" variable.
Divide both sides by 2π:
⇒ 2πr/2π = 19.4 cm/2π⇒ r = 9.7 cm/πSubstitute the radius as 22/7:
⇒ r = 9.7 cm ÷ 22/7⇒ r = 9.7 cm x 7/22⇒ r = 67.9/22 cmYou have some money in your wallet. You don't know the exact amount, but you think you have 60 dollars give or take 15 dollars. What is the difference between the largest and smallest weight of oranges in kilograms you can buy, if oranges cost 5 dollars/kg.
Answer:
The least amount is 75 dollars.
The biggest amount is 125 dollars
Step-by-step explanation:
The absolute value function will help us determine a range of possible values since we do not know the exact amount of money.
Defining the function.
Let x be the exact amount of money in my pocket, we can define the equation
And we know that the difference between the exact amount of money with 100 dollars must be either 25 dollars more than what we estimated, or 25 dollars less than the estimation. So we can write:
We have a difference inside an absolute value, since we know the difference must be either +25 or -25.
Solving for x
Using the definition of absolute value we have
So if the inside of the absolute value is positive we have the first line of the piece-wise function, that is
Solving for x give us
If the inside of the absolute value is negative we have to use the second line of the piece-wise function definition
Solving for x give us
So the least amount of money in my pocket is 75 dollars and the biggest amount is 125 dollars.
identify the figure with the vertices A (3,5) B (3,1) C (0,1)
Answer:
It makes a right traiangle.
Step-by-step explanation:
Graph the points and you will see that it makes a right triangle.
The figure formed by the vertices A(3,5), B(3,1), and C(0,1) is a right-angled triangle.
In this triangle, side BC is the shortest side with a length of 3 units, side AB is the longest side with a length of 4 units, and side AC has a length of 5 units.
The right angle is formed between side BC and side AC at point C (0,1).
Here, we have to identify the figure with the given vertices A (3,5), B (3,1), and C (0,1), we can plot these points on a coordinate plane.
Let's plot the points A(3,5), B(3,1), and C(0,1) on a Cartesian coordinate plane.
A(3,5): This point is located at x-coordinate 3 and y-coordinate 5.
B(3,1): This point is located at x-coordinate 3 and y-coordinate 1.
C(0,1): This point is located at x-coordinate 0 and y-coordinate 1.
Since point A and point B share the same x-coordinate (x = 3), they lie on a vertical line. Point C has a different x-coordinate, so we need to connect it with the others to complete the figure.
The figure formed by connecting the points A, B, and C is a right-angled triangle.
To calculate the distances between the vertices, we'll use the distance formula:
Distance between two points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] is given by:
Distance = √[tex]((x_2 - x_1)^2 + (y_2 - y_1)^2)[/tex]
Let's calculate the distances:
Distance between A(3,5) and B(3,1):
Distance_AB = √[tex]((3 - 3)^2 + (1 - 5)^2)[/tex]
Distance_AB = √(0 + 16)
Distance_AB = √16
Distance_AB = 4 units
Distance between A(3,5) and C(0,1):
Distance_AC = √[tex]((0 - 3)^2 + (1 - 5)^2)[/tex]
Distance_AC = √[tex]((-3)^2 + (-4)^2)[/tex]
Distance_AC = √(9 + 16)
Distance_AC = √25
Distance_AC = 5 units
Distance between B(3,1) and C(0,1):
Distance_BC = √[tex]((0 - 3)^2 + (1 - 1)^2)[/tex]
Distance_BC = √[tex]((-3)^2 + 0^2)[/tex]
Distance_BC = √9
Distance_BC = 3 units
As we calculated, the distances between the vertices of the figure are:
AB = 4 units
AC = 5 units
BC = 3 units
Based on the distances, we can determine that the figure formed by the vertices A(3,5), B(3,1), and C(0,1) is a right-angled triangle.
In this triangle, side BC is the shortest side with a length of 3 units, side AB is the longest side with a length of 4 units, and side AC has a length of 5 units.
The right angle is formed between side BC and side AC at point C (0,1).
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How many triangles are inside a decagon?
Is (3,-3) a solution of the graphed system of inequalities?
Choose 1 answer:
(A) Yes
(B) No
Answer:
(B) No
Step-by-step explanation:
If I remember correctly a solution is a point that is on the shaded area or on a solid line, the point 3,-3 is not on the shaded region and not on a solid line. Even if it was on the line in this problem it wouldn't be a solution because it is a dotted line. Hope this helps!