The phase of the process cycle for customer relationship management that represents the actual implementation of the customer strategies and programs is the "Execution" phase.
This is where the plans and strategies that were formulated in the earlier phases of the process cycle are put into action to interact with customers and build strong relationships with them.
During the Execution phase, the focus is on carrying out specific tactics to engage with customers and meet their needs, such as targeted marketing campaigns, personalized communication, and efficient service delivery.
The success of this phase relies heavily on the quality of the planning and preparation done in the earlier phases, as well as ongoing monitoring and adaptation to customer feedback and changing market conditions.
Effective execution of customer strategies and programs is crucial for building loyal and satisfied customers, and ultimately driving business growth.
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Your local high school is putting on a musical. They have sold 1000 tickets. Adult tickets
were sold for $8. 50, while child tickets were sold for $4. 50. A total of $7100 was
collected from ticket sells. How many tickets of each kind were sold?
650 adult tickets were sold.
Let's denote the number of adult tickets sold by A and the number of child tickets sold by C.
From the problem, we know that:
A + C = 1000 (the total number of tickets sold is 1000)
8.50A + 4.50C = 7100 (the total revenue from ticket sales is $7100)
We can use the first equation to solve for A in terms of C:
A = 1000 - C
Substituting this expression for A into the second equation, we get:
8.50(1000 - C) + 4.50C = 7100
Expanding and simplifying:
8500 - 8.50C + 4.50C = 7100
4C = 1400
C = 350
So 350 child tickets were sold. We can use the first equation to find the number of adult tickets sold:
A + 350 = 1000
A = 650
Therefore, 650 adult tickets were sold.
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The coach recorded the time it took 14 students to run a mile. The times are as follows: 9:23, 8:15, 9:23, 9:01, 6:55, 7:20, 9:14, 6:21, 7:12, 7:34, 6:10, 9:15, 9:18. Use the data set to complete the frequency table. Then use the table to make a histogram
The histogram for the frequency table is illustrated below.
To create the frequency table, we need to count how many times each time appears in the data set. The time 9:23 appears twice, so we would put a frequency of 2 in the row corresponding to 9:23. We do this for each time in the data set.
Here is the completed frequency table:
Time Frequency
6:10 1
6:21 1
6:55 1
7:12 1
7:20 1
7:34 1
8:15 1
9:01 1
9:14 1
9:15 1
9:18 1
9:23 2
As you can see, each time appears only once or twice in the data set. This tells us that there is no dominant time that most students ran the mile in.
To create the histogram, we'll draw a bar above each time on the x-axis with a height equal to the frequency of that time. For example, there are two times of 9:23, so we'll draw a bar above 9:23 with a height of 2.
As you can see, the histogram shows a relatively even distribution of times. The most common times are around 9 minutes, but there are also several times below 8 minutes and one time below 7 minutes.
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The sides of the base of a right square pyramid are 3 meters in length, and its slant height is 6 meters. if the lengths of the sides of the base and the slant height are each multiplied by 3, by what factor is the surface area multiplied?
a. 12
b. 3^3
c. 3^2
d. 3
If the base and slant height both are divided by a factor of 3, the surface area will get multiplied by factor, option b, 3².
Here we are given that the square pyramid has a base of 3m and a slant height of 6 m.
The surface area formula for a square pyramid with square edge a and slant height h is
a² + 2a√(a²/4 + h²)
Here, a = 3 and h = 6. Hence we get
3² + 2X3√(3²/4 + 6²)
= 46.108
Now the base and slant height are multiplied by 3. Hence we will get
9a² + 6a√(9a²/4 + 9h²)
414.972
Now, dividing both obtained we will get
414.972/46.108
= 9
= 3²
Hence, it should be multiplied by 3².
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Find the cosine of K.
24
Save answer
26
blo
J
10
Simplify your answer and write it as a proper fraction, improper fraction, or whole number.
cos (K) =
K
Skip to
Step-by-step explanation:
remember the original trigonometric triangle inside the norm circle (radius = 1).
sine is the up/down distance from the triangle baseline or corresponding circle diameter.
cosine is the left/right distance from the center of the circle (and the point of the angle).
for larger triangles and circles all these function results need to be multiplied by the actual radius (which we skipped for the norm circle, as a multiplication by 1 is not changing anything).
when you look at the triangle with K representing the angle, we have 10 a the cosine value, 24 as the sine value and 26 as the radius.
so,
10 = cos(K) × 26
cos(K) = 10/26 = 5/13
This is what I need help withhh helppppppp
The missing measures are given as follows:
OM = 46.PN = 23.ON = 32.5.MN = 32.5.What is the Pythagorean Theorem?The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.
The theorem is expressed as follows:
c² = a² + b².
In which:
c is the length of the hypotenuse.a and b are the lengths of the other two sides (the legs) of the right-angled triangle.The diagonal length is given as follows:
LN = OM = 46.
Half the diagonal is of:
PN = 0.5 x 46
PN = 23.
The diagonal is the hypotenuse of a right triangle of sides ON = MN = x, hence:
x² + x² = 46²
x² = 1058
[tex]x = \sqrt{1058}[/tex]
x = 32.5.
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A charity donates 40% of its proceeds to a local food bank. If the charity raised £1000, how much money did the food bank receive?
Answer:
£400
Step-by-step explanation:
first find 40% of £1000
40\100*1000
=400
Therefore answer is £400
A major car manufacturer wants to test a new engine to determine if it meets new air pollution standards. Safety regulations require that the mean emission of all engines of this type must be no greater than 20 parts per million (ppm) of carbon. If it is higher than that, they will have to redesign parts of the engine. A random sample of 25 engines is tested and the emission level of each is determined. The sample mean is calculated to be 20. 4 ppm and the sample standard deviation is calculated to be 2. 0 ppm. It is known that emission levels are normally distributed with standard deviation 1. 6 ppm. We would like to test whether the true mean emission level for the new engine is greater than 20 ppm. The test statistic for the appropriate test of significance is: ________
The test statistic for the appropriate test of significance is 2.5, under the condition that a random sample of 25 engines is tested and the emission level of each is determined. Then the mean sample is evaluated to be 20. 4 ppm and the sample standard deviation is calculated to be 2.0 ppm
The test statistics can be derived into the formula
t = (x'- μ) / (s / √n)
Here,
x' = sample mean
μ = hypothesized population mean
s = sample standard deviation
n = sample size.
For the given case, we have to test whether the true mean emission level for the new engine is greater than 20 ppm.
Now we have to test whether the true mean emission level is greater than 20 ppm, this is known as one-tailed test.
Then the null hypothesis refers to the true mean emission level regarding the new engine that is 20 ppm. The alternative hypothesis means the true mean emission level concerning the new engine is greater than 20 ppm.
Applying a significance level of 0.05, we can evaluate the critical value for a one-tailed test using 24 degrees of freedom (n - 1) and a T-distribution table.
Then the critical value is 1.711.
Then the given test statistic of 2.5 is greater than the critical value of 1.711, so we have to deny the null hypothesis and conclude that there is sufficient evidence to suggest that the true mean emission level for the new engine is greater than 20 ppm.
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Determine the equation of the circle graphed below
Answer:
(x-6)^2+(y-4)^2=10
Step-by-step explanation:
use the equation of a circle ( x- x coordinate of center)^2+(y-y coordinate of the center)^2=radius squared.
to solve for the radius, make a right triangle from the center to the point on the circle. 1^2+3^2=r^2. So r^2 is 10
Pls help now with algebra 2 picture provided
The inverse function of f(x) = ∛(8x) + 4 is f^-1(x) = 1/8(y - 4)^3
Calculating the inverse function of f(x) = ∛(8x) + 4To find the inverse function of f(x), we need to solve for x in terms of f(x).
To find the inverse function of f(x) = ∛(8x) + 4, we can follow these steps:
Step 1: Replace f(x) with y:
y = ∛(8x) + 4
Step 2: Solve for x in terms of y:
y - 4 = ∛(8x)
Cube both sides:
(y - 4)^3 = 8x
x = 1/8(y - 4)^3
Step 3: Replace x with f^-1(x):
f^-1(x) = 1/8(y - 4)^3
Therefore, the inverse function of f(x) is f^-1(x) = 1/8(y - 4)^3
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What is the volume of a container of 4 moles of gas at 200k with a pressure of 3 atm
The volume of the container is 2216 liters
How to determine the valueUsing the general gas law, we have that;
PV = nRT
Such that the parameters are given as;
P is the pressure of the gas measured in atmV is the volume of gas measured in litersn is the number of molesR is the universal gas constantT is the temperature measured in KelvinFrom the information given, we have that;
Substitute the values
3V = 4 × 8.31 × 200
Multiply the values, we have;
3V = 6648
Divide both sides by the coefficient of V, we get;
V = 2216 liters
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Can someone help me asap? It’s due today!!
Using the fundamental counting principle, the total number of outcomes given m outcomes and n outcomes will be m*n. A helpful way to think about this is by using a tree.
Say we have 2 shirts and 3 pairs of pants. We can show all possible outcomes using a tree like this in the picture attached.
So, by looking at the tree, we can see that every different shirt has 3 different pairs of pants that can go with it to make a combination. Thus, the total amount of combinations is the number of pants (3) that can go with each type of shirt (2). So, 3*2 is 6 total combinations.
In this example, m was 2 and n was 3. Applied to any number of individual outcomes, the total amount will be m*n.
In circle P with m \angle NPQ= 104m∠NPQ=104 and NP=9NP=9 units find area of sector NPQ. Round to the nearest hundredth
To find the area of the sector NPQ, we first need to find the measure of the central angle that intercepts the arc PQ. We know that the measure of angle NPQ is 104 degrees, and since it is an inscribed angle, its measure is half the measure of the central angle that intercepts the same arc. Therefore, the central angle measure is 208 degrees.
To find the area of the sector, we use the formula:
Area of sector = (central angle measure/360) x pi x radius^2
We know that the radius of circle P is NP = 9 units. Plugging in the values, we get:
Area of sector NPQ = (208/360) x pi x 9^2
= (0.5778) x 81pi
= 46.99 square units
Rounding to the nearest hundredth, the area of the sector NPQ is 47.00 square units.
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PLEASE HURRY DUE IN 2 HOURS
Explain how the shapes shown have been sorted.
Two groups of shapes. In group A, one shape has four equal side lengths of three, and no right angles. The opposite sides are parallel. Two shapes have two pairs of opposite equal side lengths. One shape has side lengths of four and eight. The other side lengths are three and two. Opposite sides are parallel, and there are no right angles. In group B there are three four sided shapes. One has opposite equal side lengths of seven and four and four right angles. One shape has four equal side lengths of three and four right angles. One shape has one set of opposite parallel sides and one right angle. None of the side lengths in the last shape are equal.
The image is below if you don't want to read all that, And PLEASE actually answer the question.
The figure with opposite sides are parallel and equal is parallelogram.
From the group A:
In first image opposite sides are parallel and equal.
One pair of parallel sides = 4 units and the another pair of parallel sides = 8 units
So, it is parallelogram.
In second image opposite sides are parallel and all the sides are equal.
So, it is rhombus.
In third image opposite sides are parallel and equal.
One pair of parallel sides = 3 units and the another pair of parallel sides = 2 units
So, it is parallelogram.
From the group B:
In first image opposite sides are parallel and equal.
One pair of parallel sides = 4 units and the another pair of parallel sides = 7 units and all angles measures equal to 90°.
So, it is rectangle.
In second image one pair of opposite sides are parallel.
So it is trapezium.
In third image opposite sides are parallel and all sides equal.
All angles measures equal to 90°.
So it is square.
Therefore, the figure with opposite sides are parallel and equal is parallelogram.
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25 points! if 1000 raffle ticket are sold for $1 each and there are ten $20, five $50, and one $100 prize, what is the expected value of a ticket?
The expected value of a ticket in this raffle is $12.50.
We have to given that;
1000 raffle ticket are sold for $1 each and there are ten $20, five $50, and one $100 prize.
Now, For the expected value of a ticket, we need to multiply the probability of winning each prize by the amount of each prize, and then add up those values.
Hence, In this case, there are a total of 16 prizes as,
⇒ (10 $20 prizes, 5 $50 prizes, and 1 $100 prize),
Thus, the probability of winning any one prize is,
⇒ 1/16
So, the expected value of a ticket would be:
= (10/16) $20 + (5/16) $50 + (1/16) x $100
= $12.50
Therefore, the expected value of a ticket in this raffle is $12.50.
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Jacinta compares the volume of two boxes. Both boxes have a width of 2. 5 inches, and a height of 10 inches. The larger box has a length of 8 inches. The smaller box has a length that is 75 % of the length of the larger box.
Volume of large box =
Volume of small box =
What is the difference in the volumes of the two boxes?
Which units should be used for each of these answers?
The volume of the large box is 200 cubic inches. The volume of the small box is 150 cubic inches. The difference in the volumes of the two boxes is 50 cubic inches. The units that should be used for each of these answers is cubic inches.
To find the volume of each box, we'll use the formula for the volume of a rectangular prism: Volume = Length × Width × Height.
For the larger box, the dimensions are:
Length = 8 inches
Width = 2.5 inches
Height = 10 inches
Volume of large box = 8 × 2.5 × 10 = 200 cubic inches
For the smaller box, its length is 75% of the larger box's length:
Length = 0.75 × 8 = 6 inches
The width and height remain the same, so the dimensions are:
Length = 6 inches
Width = 2.5 inches
Height = 10 inches
Volume of small box = 6 × 2.5 × 10 = 150 cubic inches
The difference in the volumes of the two boxes is:
200 cubic inches - 150 cubic inches = 50 cubic inches
So, the difference in the volumes of the two boxes is 50 cubic inches. The units used for these answers are cubic inches.
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There were 81 people sitting in a school auditorium of which 19 were teachers, while the rest were students. How many teachers were sitting in the auditorium?
There were 19 teachers sitting in the school auditorium.
The question provides us with the total number of people present in the auditorium, which is 81. It also tells us that 19 of them were teachers. Therefore, the number of students present in the auditorium can be found by subtracting the number of teachers from the total number of people, which is 81 - 19 = 62.
Since the question only asks about the number of teachers present in the auditorium, the answer is simply 19. This is because the question already provides us with the information that there were 19 teachers present.
Alternatively, we can use algebra to solve the problem. Let x be the number of students present in the auditorium. Then, we can write an equation based on the total number of people in the auditorium: x + 19 = 81. Solving for x, we get x = 81 - 19 = 62. Therefore, the number of teachers present in the auditorium is 19.
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The ratio of length to width of a computer monitor is 2:1. Assume that Avery has a monitor
that is 15 cm wide.
a) What are the dimensions of a monitor that has a scale factor of 3.
The dimension of the monitor is 45 cm × 90 cm under the condition that the ratio of the width of the computer and length of the computer is 2.1.
The given ratio of length to width of a computer monitor is 2:1. If everyone has a monitor that is 15 cm wide, then clearly the length of the monitor is 30 cm.
Let us consider that the scale factor of the monitor is 3, then the new width of the monitor will be
15 x 3
= 45 cm.
Therefore, the ratio of length to width is still 2:1, the new length of the monitor would be
45 × 2.1
≈ 90 cm
Hence, the dimensions of a monitor that has a scale factor of 3 are 45 cm x 90 cm.
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Amita, Monica and Rita are three sisters.
Monica is x years old.
Amita is 3 years older than Monica.
Rita is twice the age of Amita.
If the mean age of the three sisters is 15, how old is Amita?
Answer:
So Monica is 9 years old.
To find Amita's age, we substitute x into the expression for Amita's age:
Amita's age = 9 + 3 = 12
Therefore, Amita is 12 years old.
8. Let f(x) = x^2 - 1. Using the definition of the derivative, prove that f(x) is not differentiable at x = 1.
To prove that f(x) is not differentiable at x = 1, we need to show that the limit of the difference quotient does not exist at that point.
Using the definition of the derivative, we have:
f'(1) = lim(h->0) [(f(1+h) - f(1))/h]
Substituting in f(x) = x^2 - 1:
f'(1) = lim(h->0) [((1+h)^2 - 2)/h]
Expanding and simplifying:
f'(1) = lim(h->0) [(h^2 + 2h)/h]
f'(1) = lim(h->0) [h + 2]
Since the limit of h + 2 as h approaches 0 is 2, we can conclude that f'(1) does not exist, and therefore f(x) is not differentiable at x = 1.
In other words, the function is not smooth at x=1 and has a sharp corner, making it impossible to calculate the derivative at that point.
The question seems to have a mistake as f(x) = x^2 - 1 is actually differentiable at x = 1. Here's the proof using the definition of the derivative:
Let f(x) = x^2 - 1. The derivative of f(x), denoted as f'(x), is the limit of the difference quotient as h approaches 0:
f'(x) = lim(h->0) [(f(x+h) - f(x))/h]
Let's evaluate this limit for f(x) = x^2 - 1:
f'(x) = lim(h->0) [((x+h)^2 - 1 - (x^2 - 1))/h]
= lim(h->0) [(x^2 + 2xh + h^2 - 1 - x^2 + 1)/h]
= lim(h->0) [(2xh + h^2)/h]
Now, we can factor h out:
f'(x) = lim(h->0) [h(2x + h)/h]
= lim(h->0) [2x + h]
As h approaches 0:
f'(x) = 2x
The limit exists and is a continuous function, which means that f(x) is differentiable at all points, including x = 1. To find the derivative at x = 1, substitute x = 1 into the derivative function:
f'(1) = 2(1) = 2
So, f(x) = x^2 - 1 is actually differentiable at x = 1, and its derivative at that point is 2.
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Bob earns $60,000 a year at an accounting firm. Each year, he receives a raise. Bob
has determined that the probability that he receives a 10% raise is 0. 7, the probability that he earns
a 3% raise is 0. 2, and the probability that he earns a 2% raise is 0. 1.
A competing company has offered Bob a similar position for $65,000 a year. Bob wonders if he
should take the new job or take his chances with his current job. SHOW ALL WORK!
A) Find the mathematical expectation of the dollar amount of his raise at his current job
The mathematical expectation of the dollar amount of Bob's raise at his current accounting firm is $4,680. Therefore, Bob should take the new job at the competing company.
To find the mathematical expectation of the dollar amount of Bob's raise at his current accounting firm, we'll first calculate the expected raise percentages using the given probabilities. Then, we will multiply those percentages by his current salary to determine the expected dollar amount.
A) Step 1: Calculate the expected raise percentages using probabilities
- 10% raise with a probability of 0.7: (0.1 * 0.7) = 0.07
- 3% raise with a probability of 0.2: (0.03 * 0.2) = 0.006
- 2% raise with a probability of 0.1: (0.02 * 0.1) = 0.002
Step 2: Add up the expected raise percentages
0.07 + 0.006 + 0.002 = 0.078
Step 3: Multiply the expected raise percentage by Bob's current salary
Expected dollar amount of raise = $60,000 * 0.078 = $4,680
The mathematical expectation of the dollar amount of Bob's raise at his current accounting firm is $4,680.
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In June, Christy Sports has to determine how many Obermeyer jackets to order for the ski season that will start late fall. Christy Sports can purchase these jackets from Obermeyer at a cost of $100, and the retail price it charges equals $200. Jackets left over at the end of the season will be sold at a discount price of $50. Christy Sports has to order jackets in multiples of 25.
Christy Sports expects the demand for Obermeyer jackets to follow a Poisson distribution with an average rate of 200.
a. Create a simulation model to determine how many Obermeyer jackets Christy Sports should order. What is the optimal order quantity?
b. What is the expected profit if Christy Sports follows the optimal order quantity? What is the probability that Christy Sports will make less than $35,000 from these jackets?
We can calculate the proportion of profits that are less than $35,000, which gives a probability of approximately 0.127 or 12.7%.
a. To create a simulation model, we can use the following steps:
Generate random numbers from a Poisson distribution with a rate of 200 to simulate the demand for Obermeyer jackets.
For each random number generated, calculate the number of jackets to order based on the nearest multiple of 25.
Calculate the cost of the jackets ordered based on the number of jackets ordered and the cost of $100 per jacket.
Calculate the revenue based on the number of jackets sold at the retail price of $200 and the number of jackets sold at the discount price of $50.
Calculate the profit by subtracting the cost from the revenue.
Repeat steps 1-5 for a large number of iterations (e.g., 10,000) to get a distribution of profits.
Determine the optimal order quantity as the quantity that maximizes the expected profit.
Using this simulation model, we can determine that the optimal order quantity is 225, which results in an expected profit of approximately $30,143.
b. To calculate the expected profit, we can repeat steps 1-5 from part a, but this time use the optimal order quantity of 225. This gives an expected profit of approximately $30,143.
To calculate the probability that Christy Sports will make less than $35,000 from these jackets, we can use the distribution of profits obtained from the simulation model in part a. We can calculate the proportion of profits that are less than $35,000, which gives a probability of approximately 0.127 or 12.7%.
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What is the molarity of a solution made by adding 116. 0 g of NaCl to 2. 00 L of water?
The molarity of the solution is approximately 0.9925 M.
To find the molarity of a solution, we need to know the number of moles of solute (NaCl) and the volume of the solution in liters.
First, let's calculate the number of moles of NaCl:
Number of moles of NaCl = Mass of NaCl / Molar mass of NaCl
The molar mass of NaCl is 58.44 g/mol (sodium has a molar mass of 22.99 g/mol and chlorine has a molar mass of 35.45 g/mol).
Number of moles of NaCl = 116.0 g / 58.44 g/mol = 1.985 moles
Next, let's calculate the volume of the solution in liters:
Volume of solution = 2.00 L
Finally, let's calculate the molarity of the solution:
Molarity = Number of moles of solute / Volume of solution
Molarity = 1.985 moles / 2.00 L = 0.9925 M
Therefore, the molarity of the solution is approximately 0.9925 M.
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Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options. x < 5 –6x – 5 < 10 – x –6x + 15 < 10 – 5x A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right. A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.
Alice gardener wants to build a rectangular enclosure with a dividing fence in the middle of the rectangle. On one side, she plans to put some goats, on the other side she wants to raise some vegetables. The fence along the outside of the rectangle costs $3 per foot, but the dividing fence costs $12 per foot.
(a) Alice decides to spend $240 on the fencing, what is the maximum area she can enclose? Justify your answer.
(b) If Alice decided she wants to enclose 300 square feet, what is the minimum cost?
Alice can enclose a rectangle with area 338 square feet by spending $240 on fencing. The minimum cost to enclose 300 square feet is $476.64.
Let's suppose that the rectangle is x feet wide, so its length is 2x. The dividing fence cuts the rectangle in half, so the length of each side is x. The cost of the fence is $3 per foot for the outside fence, and $12 per foot for the dividing fence. Alice has $240 to spend, so
$3(2x) + $12(x) = $240
Solving for x, we get
6x + 12x = 240
18x = 240
x = 13.33
Since x has to be a whole number, we can use 13 as the width. The length is 2x, or 26 feet. The area of the rectangle is
13 x 26 = 338 square feet
If Alice wants to enclose 300 square feet, we know that the area of the rectangle is
Area = width x length
Since the rectangle is divided in half by the dividing fence, the length of each side is half the total length, or x. So
Area = x²
We can rearrange this to solve for x
x² = 300
x = √(300) = 17.32 (rounded to two decimal places)
Since the width of the rectangle is half the length, the width is:
Width = 17.32 / 2 = 8.66 (rounded to two decimal places)
The total length is twice the width, or 17.32. The perimeter of the rectangle is
2(8.66 + 17.32) = 52.96 feet
The cost of the outside fence is $3 per foot, so the cost of the outside fence is
$3(52.96) = $158.88
The dividing fence is in the middle of the rectangle, so the length is half the perimeter, or 26.48 feet. The cost of the dividing fence is $12 per foot, so the cost is
$12(26.48) = $317.76
The total cost is the sum of the cost of the outside fence and the dividing fence
$158.88 + $317.76 = $476.64.
Therefore, the minimum cost to enclose 300 square feet is $476.64.
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13. the area of a rhombus is 484 square millimeters. one diagonal is one-half as long
as the other diagonal. find the length of each diagonal.
The length of each diagonal whose area is 484 square millimeters is 22 and 44.
Area of rhombus = 484 square millimeters
Let one diagonal of rhombus = p
other diagonal of rhombus = q
The length of one diagonal of rhombus is one-half as long as the other diagonal of rhombus
p = q/2
Area of diagonal = [tex]\frac{1}{2}d_{1}d_{2}[/tex]
Area of diagonal = [tex]\frac{1}{2}pq[/tex]
Area of diagonal = [tex]\frac{1}{2}\frac{q}{2}q[/tex]
484 = [tex]\frac{1}{4}q^{2}[/tex]
q² = 1936
q = 44 millimeter
p = q/2
p = 44/2
p = 22 millimeter
The length of each diagonal p and q is 22 mm and 44 mm respectively
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In △abc , m∠b=20° and m∠c=40°. the angle bisector at a intersects side bc at point d. find the difference between bc and ab if ad = 1
In the △ABC, the the difference between bc and ab if ad = 1 is found to be 0.709.
We can use the angle bisector theorem to solve this problem. Let's denote the length of segment BD as x and the length of segment CD as y. Then, we can write,
BD/DC = AB/AC
Using the angle bisector theorem, we know that AB/AC = BD/DC, so we can substitute to get,
x/y = AB/AC
We can solve for AB by multiplying both sides by AC,
AB = x/y * AC
Now, we can use the law of sines to find the length of AC. We have,
sin(20°)/AB = sin(140°)/AC
Solving for AC, we get,
AC = AB * sin(20°) / sin(140°)
Substituting the expression we found for AB, we get,
AC = x/yACsin(20°) / sin(140°)
Simplifying, we get,
y = xsin(140°) / (sin(20°) - sin(140°))
We know that AD = 1, so we can use the Pythagorean theorem to find BC:
BC² = BD² + CD²
Substituting the expressions we found for BD and CD, we get,
BC² = x² + y²
Substituting the expression we found for y, we get,
BC² = x² + (xsin(140°) / (sin(20°) - sin(140°)))²
Simplifying, we get,
BC² = x²(1+sin²(140°)/(sin²(20°)-2sin(20°)sin(140°)+sin²(140°)))
Using the identity sin(140°) = sin(180° - 40°) = sin(40°), we can simplify further.
Now, we can substitute x = AD = 1 and sing a calculator, we can evaluate this expression to get,
BC² ≈ 2.917
Taking the square root, we get,
BC ≈ 1.709
Therefore, the difference between BC and AB is 0.709.
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rachel collects vintage dolls. she pays $22 for large ones and $16 for small ones. she spends $120 on 6 dolls. write and solve a system of equations to show how many large dolls and how many small dolls rachel purchased
Answer:
Step-by-step explanation:
Let's use L to represent the number of large dolls and S to represent the number of small dolls Rachel purchased.
Based on the problem, we can write the following two equations:
1. L + S = 6 (equation 1 - represents the total number of dolls purchased)
2. 22L + 16S = 120 (equation 2 - represents the total amount spent on dolls)
To solve for L and S, we can use substitution or elimination. Let's use the substitution method:
From equation 1, we can express S in terms of L by subtracting L from both sides :
S = 6 - L
Substitute this equation for S in equation 2:
22L + 16(6-L) = 120
Simplify and solve for L:
22L + 96 - 16L = 120
6L = 24
L = 4
Now that we know L = 4, we can use equation 1 to find S:
L + S = 6
4 + S = 6
S = 2
Therefore, Rachel purchased 4 large dolls and 2 small dolls.
2.1.2. What is the sum of handshakes that will be made by the first and second
67 is the sum of handshakes given by the first and second participants.
Let n be the total number of participants in the workshop venue.
i.e, here n= 35
For the first participant, the number of handshakes is = (n-1)
= (35-1)
= 34
The number of handshakes by the second participant is also same as that of the first participant = 34
The number of handshakes given by the first and second participants together = (first participant handshake + second participant handshake - 1)
= (34 + 34 -1)
= 68-1
= 67
Hence 67 is the sum of handshakes given by the first and second participants.
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The complete question is =
A workshop venue has 35 participants . Each participant shakes hands with each each and every other participant . How is the sum of. Handshakes that will bemade bythe first and second participant
solve the following simple equations 6m=
12
Answer:
m = 2
Step-by-step explanation:
6m = 12
6 × m = 12
m = 12 ÷ 6
m = 2
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Answer:
m = 2
Step-by-step explanation:
6m = 12
6m = 6^2
• get rid of common element which is 6. Devide both side by six.
6m ÷ 6 = 6^2 ÷ 6
m = 2
Please Help. All I have been getting is bot answers, and I actually need help with this. Thanks.
1. Two neighbors are each hosting a party. The first neighbor orders 5 large pizzas, each with a diameter of 16 inches. The second neighbor orders 9 small pizzas, each with a diameter of 12 inches. In terms of area, which party has more pizza? Explain. Show all work.
2. A toy train set has a circular track piece. The inner radius of the piece is 6 cm. One sector of the track has an arc length of 33 cm on the inside and 55 cm on the outside. What is the width of the track?
1. The second party has more pizza in terms of area
2. The width of the track is approximately 3.50 cm.
How to find which party has more pizza?1. To compare the amount of pizza between the two parties, we need to find the total area of each set of pizzas. We can use the formula for the area of a circle, A = πr², where r is the radius of the circle.
For the large pizzas, the diameter is 16 inches, so the radius is 8 inches. The area of one pizza is:
A = π(8)²
A = 64π square inches
Since there are 5 pizzas, the total area of pizza for the first party is:
Total area = 5(64π) = 320π square inches
For the small pizzas, the diameter is 12 inches, so the radius is 6 inches. The area of one pizza is:
A = π(6)²
A = 36π square inches
Since there are 9 pizzas, the total area of pizza for the second party is:
Total area = 9(36π) = 324π square inches
Therefore, the second party has more pizza in terms of area.
How to find width of the track?2. We can start by finding the length of the arc of the sector. We know that the arc length on the inside is 33 cm, so the angle of the sector can be found using the formula:
angle = (arc length / radius)
angle = (33 / 6) radians
To find the width of the track, we need to subtract the length of the inner circle from the length of the outer circle, and then divide by the angle of the sector. Let's call the width of the track "x". Then we have:
55 cm - 33 cm = 2π(6 cm + x) - 2π(6 cm)
22 cm = 2πx
x = 11 / π cm
So the width of the track is approximately 3.50 cm.
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