Which statement describes the interaction between the north and south poles of two magents?

Answer:

it has to be b contact forces

Explanation: because the two objects are next to each other but they still have force

Answer:

c

Explanation:

The acceleration/deceleration of the truck is 11.56 m/s^2

Velocity = change in displacement/ time

Acceleration = change in velocity/ time.

The acceleration, velocity and distance travelled of a body is related by the equation below:

where v is the initial velocity

u is the final velocity

a is the acceleration, and

s is the distance travelled

From the data provided:

v = 0

u = 34 m/s

s = 50 m

a = ?

making a subject of the formula

a = -u^2/2s

a = - 34^2 / 2 × 50

a = -11.56 m/s^2

Therefore, the acceleration/deceleration of the truck is 11.56 m/s^2

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Answer:

Net force = 11340 N

Explanation:

Given that,

Mass of an automobile, m = 2100 kg

Acceleration of the automobile, a = 5.4 m/s²

We need to find the net force required for the automobile. The net force is the product of mass and acceleration. It can be given by the formula as follows :

[tex]F=ma\\\\F=2100\ kg\times 5.4\ m/s^2\\\\F=11340\ N[/tex]

So, the net force is 11340 N.

Answer:

it is algae- shrimp- artic cod-ringed seals- polar bears

Explanation:

you had it right

Answer:

I'm pretty sure it's false

Answer:

a) v = 7.28 m/s

b) t = 0.74 s

Explanation:

a) The initial speed of the ball can be calculated using the following equation:

[tex] V_{f}^{2} = V_{0}^{2} - 2gh [/tex]

Where:

[tex]V_{f}[/tex] is the final speed = 0

[tex]V_{0}[/tex] is the initial speed =?

g: is the gravity = 9.81 m/s²

h: is the height = 2.70 m

[tex] V_{0} = \sqrt{2gh} = \sqrt{2*9.81 m/s^{2}*2.70 m} = 7.28 m/s [/tex]

Hence, the initial speed of the ball is 7.28 m/s.

b) To find the time that takes the balls to reach the ceiling we can use the next equation:

[tex] V_{f} = V_{0} - gt [/tex]

[tex] t = \frac{V_{0} - V_{f}}{g} = \frac{7.28 m/s}{9.81 m/s^{2}} = 0.74 s [/tex]

Therefore, the time it takes for the ball to reach the ceiling is 0.74 s.

I hope it helps you!

Answer:

the awnser is A becuse the hair help.

On a drive from your home to town, you wish

to average 33.6 mph. The distance from your

home to town is 90 miles. However, at 45 miles

(half way), you find you have averaged only

25.2 mph.

What average speed must you maintain in

the remaining distance in order to have an

overall average speed of 33.6 mph?

Answer in units of mph

let the speed be x

total average = 33.6

Answer:

32m

Explanation:

v=u+at

v=0+2×4

v=8m/s

d=vt

d=8×4

d=32m

Given parameters:

Mass on earth  = 50kg

Unknown:

Mass on planet Xenon = ?

Weight on planet Xenon = ?

Mass is the amount of matter contained in a particular substance.

Weight is the force on a body and it is derived from the product of mass and acceleration due to gravity.

         Weight  = mass x acceleration due to gravity

Planet Xenon has half the gravitational force of Earth.

 This translated gives [tex]\frac{9.8}{2}[/tex]   = 4.9m/s²

Now, mass is always the same every where if the amount of matter in a substance does not change.

In this problem, mass = 50kg on planet xenon.

Weight =  mass x acceleration due to gravity  = 50 x 4.9  = 245N

The weight on Xenon is 245N and the mass is 50kg

Answer:

shortening its length.

The period of a pendulum is not dependent on the mass of the ball, but only on the length of its string. The period of a pendulum may be decreased by shortening the length of pendulum

The shortening of the pendulum length often affect its period.  The length of the string do influence the pendulum's period making it to be like the longer the length of the string, the longer the pendulum's period.

A pendulum that has a longer string often has a lower frequency. That is, it will swings back and forth in little times in a given amount of time than when the pendulum is with a shorter string length.

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Answer:

methane is a gas

Explanation:

in chemistry

Answer:

The corridor's distance is "90 m".

Explanation:

Now,

⇒  [tex]2x + 2y = 60[/tex]

⇒  [tex]x + y = 30[/tex]

The total distance of the corridor will be:

=  [tex]x + 2x + 2y + y[/tex]

=  [tex]3\times (x + y)[/tex]

=  [tex]3\times 30[/tex]

=  [tex]90 \ m[/tex]

Answer:

Objects float in outer space because there is no gravitational force. The farther you get from earth, the less gravity.

Explanation:

Answer:

they float do to gravity

Explanation:

here if you tossed a ball in the air it would come back down fast in space however it would only float up and stay do to gravity

Answer:

D) Lifting it to a high shelf

Explanation:

Potential energy is where energy could be released at any moment. For example, if a cat gets on a tree it's creating potential energy, once that cat jumps from the tree the energy releases. D is the answers because if you set the book in a high shelf, you are only creating more potential energy.

hope I explain my self well enough

cheers man and good luck

Answer:

The answer is "between 20 s and 30 s".

Explanation:

Calculating the value of positive displacement:

[tex]\ (x_{+ve}) = \frac{1}{2} \times 15 \times 20 \\\\[/tex]

          [tex]= \frac{1}{2} \times 300 \\\\= 150 \\\\[/tex]

Calculating the value of negative displacement upon the time t:

[tex](x_{-ve}) = \frac{1}{2} \times 5 \times 20- 20(t-20) \\\\[/tex]

          [tex]= \frac{1}{2} \times 100- 20t+ 400 \\\\= 50- 20t+ 400 \\\\[/tex]

[tex]\to X= X_{+ve} + X_{-ve} \\\\[/tex]

[tex]\to 150 - 50 -20t+400 =0\\\\\to 100 -20t+400 =0 \\\\\to 500 -20t =0\\\\\to 20t =500 \\\\\to t=\frac{500}{20}\\\\\to t=\frac{50}{2}\\\\\to t= 25[/tex]

That's why its value lie in "between 20 s and 30 s".

Answer:

Energy storage plays an important role in this balancing act and helps to create a more flexible and reliable grid system. For example, when there is more supply than demand, such as during the night when low-cost power plants continue to operate, the excess electricity generation can be used to power storage devices.

Explanation:

I hope this helps you out and if your feeling generous plz mark brainliest it helps me a lot thank you:)

It important for scientists to find better ways to store solar and wind energy because solar and wind energy have variable outputs.

Lately, the world have begun to gradually gravitate away from non renewable energy sources such as fossil fuels and research efforts have been concentrated on renewable energy sources such as solar and wind energy.

However, the energy output from these sources are variable. Therefore, it is necessary to device ways to store energy from these sources in order to improve overall energy supply.

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The question is incomplete. Here is the complete question.

As mentioned in problem 1.2 from Chapter 1, if you stand on one leg the load exerted on the hip jpint is 2.4 times your body weight. Assuming a simple cylindrical model for the implant, calculate the corresponding stress (in MPa) on a hip implant in a 175lb individual with a hip implant with cross-sectional area of 5.6cm². If the implant is made of Ti6AI4V (124 GPa elastic modulus), what is the atrain for the given loading conditions?

Answer: σ = 3.336 MPa

             Strain = 2.69.[tex]10^{-5}[/tex]

Explanation: Stress is the measurement of how hard a weight works to change a material's shape. Its symbol is σ and is calculated as

[tex]\sigma = \frac{F}{A}[/tex]

where

F is force

A is cross sectional area

For the hip implant, force is 2.4x of an 175lb individual:

F = 2.4 * 175

F = 420lb

As the question is asking for Pa and 1 Pa = 1 N/m², transform lb in Newtons:

F = 420lb * 4.448N/lb

F = 1868 N

And cm² in m²:

A = [tex]5.6.10^{-4}[/tex] m²

Calculating Stress:

[tex]\sigma=\frac{1868}{5.6.10^{-4}}[/tex]

[tex]\sigma=333.6.10^{4}[/tex] Pa

or

σ = 3.336 MPa

Stress on a hip implant of an individual with weight 175lb is 3.336 MPa.

Strain is the measure of the deformation of a material due to a load. It can be calculated as:

strain = [tex]\frac{stress}{modulus}[/tex]

But first, change MPa into GPa:

3.336 MPa = [tex]3.336.10^{-3}[/tex] GPa

strain = [tex]\frac{0.003336}{124}[/tex]

strain = [tex]2.69.10^{-5}[/tex]

Ti6Al4V is a titanium alloy used in implants. So, the strain the alloy does on a hip implant of a 175lb individual is [tex]2.69.10^{-5}[/tex].

Answer:

v = 190 m/s

Explanation:

Given that,

Initial velocity of a car, u = 10 m/s

Distance, d = 500 m

Time, t = 5 s

We need to find the final velocity of the car. Firstly we can find the acceleration of the car using second equation of motion as follows :

[tex]d=ut+\dfrac{1}{2}at^2\\\\500=10\times 5+\dfrac{a}{2}\times 5^2\\\\500=50+\dfrac{25a}{2}\\\\450=\dfrac{25a}{2}\\\\a=\dfrac{450\times 2}{25}\\\\a=36\ m/s^2[/tex]

let v is the final velocity. using First equation of motion to find a as follows :

v=u+at

v=10+36(5)

v=190 m/s

So, the final velocity of the car is 190 m/s.

Answer:

It is called the unit function because it is the identity element for Dirichlet convolution. It may be described as the "indicator function of 1" within the set of positive integers. It is also written as u(n) (not to be confused with μ(n), which generally denotes the Möbius function).

Answer:

dP/dt = 26.12 W/s

Explanation:

First, we need to find the value of dt at the instant when R₃ becomes 91.7 Ω. Therefore, we use:

dR₃/dt = 0.552 Ω/s

where,

dR₃ = Change in value of resistance 3 = 91.7 Ω - 7.42 Ω = 84.28 Ω

dt = time interval = ?

Therefore,

84.28 Ω = (0.552 Ω/s)(dt)

dt = (84.28 Ω)/(0.552 Ω/s)

dt = 152.68 s

Now, we find change in power (dP):

dP = V(R₁ + R₂ + dR₃)

dP = (42.1 V)(2.96 Ω + 7.48 Ω + 84.28 Ω)

dP = 3987.71 W

Dividing by dt:

dP/dt = 3987.71 W/152.68 s

dP/dt = 26.12 W/s

Answer:

meter, kilogram, second, ampere, Kelvin, candela, and mole.

Explanation:

these are all SI units.

Recall the definition of average velocity:

average v = ∆x / ∆t

The driver moves a distance of ∆x = 4.25 km = 4250 m in 2 min = 120 s, so the average velocity is

average v = (4250 m) / (120 s) ≈ 35.4 m/s

Under constant acceleration, the average velocity can also be computed by taking the average of the initial and final velocities:

average v = (initial v + final v) / 2

Solve for (final v) :

35.4 m/s = (20 m/s + final v)/2

final v ≈ 50.83 m/s

Recall the definition of average acceleration:

average a = ∆v / ∆t

Solve for a :

a = (50.83 m/s - 20 m/s) / (120 s)

a ≈ 0.257 m/s²

Answer:

the mantle.

Explanation:

The mantle is the mostly-solid bulk of Earth's interior. The mantle lies between Earth's dense, super-heated core and its thin outer layer, the crust. It's practically hot lava (Magma) Flowing and causing earthquakes and what not.

Hope this helps :)

Answer: D.  Heat transfer between the two things stops​.

Answer:

W_net = mg + 2mgh/r

Explanation:

The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.

Now, gravitational force is; F_g = mg

While centripetal force is; F_c = mv²/r

Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.

Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.

Thus;

F_c = 2mgh/r

Where;

m is ball mass

r is tube radius

h is fall height

Thus, the net force will be;

F_net = F_g + F_c

Now, Net force would be equal to the net weight that will be read on the scale.

Thus;

W_net = F_net = F_g + F_c

W_net = mg + 2mgh/r

At its lowest point, the net force of the bowling ball is equal to its net weight and this is given by [tex]F_{net} = mg + \frac{2mgh}{r}[/tex]

Given the following data:

To write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the given variables:

In this scenario, there are two (2) forces acting on the bowling ball and these include:

Mathematically, centripetal force is given by this formula:

[tex]F_c = \frac{mv^2}{r}[/tex]     .....equation 1.

Mathematically, gravitational force is given by this formula:

[tex]F_g= mg[/tex]    ....equation 2.

Where:

Next, we would derive an expression for the velocity of the ball by applying the Law of Conservation of energy:

[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\V^2=2gh[/tex] .....equation 3.

Substituting eqn. 3 into eqn. 2, we have:

[tex]F_c = \frac{m(2gh)}{r}\\\\F_c = \frac{2mgh}{r}[/tex]

At its lowest point, the net weight of the bowling ball is equal to its net force and this is given by this mathematical expression:

[tex]W_{net} = F_{net} = F_g + F_c\\\\F_{net} = mg + \frac{2mgh}{r}[/tex]

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