Two math classes took the same quiz. The scores of 10 randomly selected students from each class are listed below.
Sample of Class A: 75, 80, 60, 90, 85, 80, 70, 90, 70, 65
Sample of Class B: 95, 90, 85, 90, 100, 75, 90, 85, 90, 85
Based on the medians of the scores for each class, what inference would you make
about the quiz scores of all the students in Class A compared to all the students in
Class B? Explain your reasoning to justify your answer.
(written answer)
Answer:
The score of class b were better than the scores of class a.
the median for class a was 77.5
the median for class b was 90
therefore class b overall scored better on the quiz than class a
Step-by-step explanation:
hope this helps :)
A model satellite has a scale of 1 cm : 3 m. If the real satellite is 18 m wide, then how wide is the model satellite?
A. 54 cm
B. 1 cm
C. 6 cm
D. 15 cm
The value of 30 is between which two integers
[tex]5 < \sqrt{30} < 6[/tex]
Step-by-step explanation:[tex]Locate\ \sqrt{30}\ between\ two\ integers:\\ \downarrow\\ 5 < \sqrt{30} < 6[/tex]
I hope this helps you
:)
Baker, Inc. uses the sum-of-the-years’-digits method to depreciate a $79,600.00 piece of equipment that has an estimated life of 20 years. The salvage value is $4,000.00. The book value at the end of year 2 is
The book value at the end of year 2 of the equipment depreciated using the sum-of-the-years’-digits method is $65,560.
What is the book value at the end of year 2?Depreciation is a method used to expense the cost of an asset. Book value is the cost of the asset less the accumulated depreciation.
Sum-of-the-year digits = (remaining useful life / sum of the years ) x (Cost of asset - Salvage value)
Depreciation expense in year 1:
Sum of the years = 1 +2 +3 +4 + 5 + 6 + 7 + 8 + 9 + 10+ 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210
Undepreciated life of the asset = 20
(20 / 210) x ($79,600 - 4,000) = 7200
Depreciation expense in year 2:
19 / 210 x ($79,600 - 4,000) = 6840
Book value = 79600 - 7200 - 6840 = $65,560
To learn more about depreciation, please check: https://brainly.com/question/25552427
Hi can someone help me find domain and range
Answer:
Step-by-step explanation:
Domain is ( - ∞ , ∞ )
Range is [ 0 , 1 ] ∪ ( 2 , ∞ )
What is the length of the diameter of a circle with a radius that is 13 centimeters? cm
Answer:
13 this is the ansewer to this
The half-life of Radium-226 is 1590 years. If a sample contains 400 mg, how many mg will remain after 1000
years?
Answer:
258.65 mg will be remain after 1000 years
Step-by-step explanation:
This problem can be solved several ways, I prefer the natural log approach for reasons I won’t go into here:
Activity final = Activity initial e^-kt, where
k = the decay constant, = ln2/half life = 0.693/1590, = 0.000436/year
t = the decay time, in the same time base as k
The problem can be worked in units of activity, mass, or number of atoms.
400 x e^-0.000436 x 1000 = 400 x e^-.436 = 258.65 mg
you can check this by estimating. There is about 2/3 of a half life, so there should be more than 200 mg, which would be the value at one half life.
The volume of the given figure is __ ft3
Answer:
I believe the answer is 20
Tori invests $1,500 into the stock market which earns 9% per year. In 20 years, how much will Tori's investment be worth if interest is compounded semiannually (twice a year)?
MY SISTER NEEDS HELP IN MATH...
Answer:
[tex]b. \: 16[/tex]
Step-by-step explanation:
Divide the numbers ⬇
16 ÷ 4 = 4[tex](4 + 2) \times 2 + 4[/tex]
Add the numbers ⬇
4+2=6[tex]6 \times 2 + 4[/tex]
Multiply the numbers ⬇
6 x 2 = 12[tex]12 + 4[/tex]
Add the numbers ⬇
[tex]12 + 4 = 16[/tex]
OPTION B IS RIGHT :)
hope this helps!! Mark me brainliest please!
Answer: B. 16
Step-by-step explanation:
Hope this helps!
When my pot of paint is half full, it weighs 5.8 kg. When my pot of paint is one quarter full, it weighs 3.1 kg.
What is the weight of the full pot?
The paint in the pot is an illustration of a linear equation and the weight of the full pot is 11.2 kg
How to determine the weight of the full pot?The given parameters can be represented using the following ordered pairs:
(x,y) = {(0.5, 5.8) and (0.25, 3.1)}
The slope of the equation is calculated using:
m = (y2 - y1)/(x2 - x1)
This gives
m = (3.1 - 5.8)/(0.25 - 0.5)
Evaluate
m = 10.8
The equation is then calculated using:
y = m(x - x1) + y1
This gives
y = 10.8(x - 0.5) + 5.8
Expand
y = 10.8x + 0.4
When the pot is full, we have x = 1
So, the equation becomes:
y = 10.8 * 1 + 0.4
Evaluate
y = 11.2
Hence, the weight of the full pot is 11.2 kg
Read more about linear equations at:
https://brainly.com/question/14323743
Complete the equation of the line through (-10,-7)(-5,−9)
Find all zeros of ƒ(x) = 2x^4 – 72x^2. Then determine the multiplicity at each zero. State whether the graph will touch or cross the x-axis at the zero.
Answer: See below
Step-by-step explanation:
To find the factor,
f(x) = 0
[tex]\begin{aligned}&2 x^{4}-72 x^{2}=0 \\&2 x^{2}\left(x^{2}-36\right)=0 \\&x^{2}\left(x^{2}-36\right)=0 \\&x \times x \times(x-6) \times(x+6)=0 \\&\mathrm{x}=0,0,6,-6\end{aligned}[/tex]
So,
x = 0 multiplicity 2
x = -6 multiplicity 1
x = 6 multiplicity 1
For an even multiplicty, the graph touches the x-axis, and for an odd multiplicty, the graph crosses the x-axis
Therefore,
x = 0 multiplicty 2, Touch
x = -6 multiplicty 1, Cross
x = 6 multiplicty 1, Cross
Which of the following sets of ordered pairs defines a relation that
is NOT a function?
O {(1, 5), (5, 1), (7, 9), (9, 7)}
O {(6, 7), (8, 10), (13, 9), (21, 10)}
O {(2, 2), (3, 4), (5, 8), (12, 16)}
O {(5, 14), (5, 16), (7, 23), (11, 31)}
para lang po sa points hehe
Two point particles are attached to each other via a light in-extensible string that passes over a ring hanging from the ceiling via a chain. Find an expres- sion for the tension in the string and the chain.
a. The expression for the tension in the string is T = mg
b. The expression for the tension in the chain is T = 2mg
To solve the problem, we need to know what tension is.
What is tension?This is the opposing force in a stretched material.
a. Tension in the stringThe expression for the tension in the string is T = mg
Since the string supports the weight of the object, the tension in the string equals the weight of the particle.
Let
T = tension in sring and W = weight of particle = mg where m = mass of particle and g = acceleration due to gravitySo, T = W
T = mg
So, the expression for the tension in the string is T = mg
b. Tension in chainThe expression for the tension in the chain is T = 2mg
Since the chain supports both strings, the tension in the chain equals the tension in both strings.
Let
T' = tension in chain and T = tension in each stringSo, T' = T + T
T' = 2T
T' = 2W
T' = 2mg
So, the expression for the tension in the chain is T = 2mg
Learn more about tension here:
https://brainly.com/question/24994188
four dice are thrown simultaneously. what will be the probability that all of them have the same face ?
Answer:
1/216
Step-by-step explanation:
A dice (assuming it is from 1-6) has 6 faces. There are 4 dices.
equation will be
6*6*6=answer
Multiply 6 three times by itself because there are 4 dices. That is because One die would be 1
Two would be 1/6
Three would be 1/36
And four would be the ...
Asnwer=216
Find the area of the sector.
a. 11.16 in²
b. 44.66 in²
c. 50.24 in²
d. 2.8 in²
Hi!
Circle Area Formula[tex]A=\pi r^2[/tex]
We will start by solving for the area of the entire figure.
Plugin the values into the circle area formula. We will use 3.14 for pi:
[tex]A=3.14(4)^2[/tex]
Simplify:
[tex]A=50.24[/tex]
Now, this is the area of the entire circle, but we only want that certain shaded region.
We know that a circle has a total of 360 degrees, and the shaded sector is simply 80 degrees.
We can divide to see how much of the circle is shaded:
80 / 360 = 0.22...
Now, we can take this number and multiply it by 50.24 (our answer from above) to get the area of the shaded sector:
0.22 * 50.24 = 11.16
Therefore, your answer is A.For a similar problem, see:
https://brainly.com/question/11952845
need help with #10 :’)
the # is “Which of the following expressions is equivalent to 42 + 63?
A- 3(15+21)
B- 6(7+9)
C- 7(6+9)
D- 14(3+3)
8
Answer:
the answer is c
Step-by-step explanation:
first add : 42+63=105
so you need to solve the expressions until you find the one that equal the same amount.
start with the problem in the parenthesis then multiply.
you will find that C equals 105
6+9=15
15×7=105
Please help i have an assignment due TODAY i need to get this done
rules:
NO LINKS! im not getting myself a virus
Answer:
Line LK is the dimameter
Step-by-step explanation:
A diameter is a line that goes through the center and goes from one end a the circle to the other end of the circle.
Hope this helps!!
Which pairs of polygons are similar?
Select each correct answer.
Answer:
Two polygons are similar if their corresponding angles are congruent and the corresponding sides have a constant ratio (in other words, if they are proportional). Typically, problems with similar polygons ask for missing sides.
Step-by-step explanation:
this is the correct answer
Here is a right angled triangle work out the value of x using trigonometry
[tex]~~~~~\sin 30^{\circ} = \dfrac{\text{Perpendicular}}{\text{Hypotenuse} }\\\\\\\implies \dfrac 12 = \dfrac{8}x\\\\\\\implies x = 8\cdot2\\\\\\\implies x = 16 ~ \text{cm.}[/tex]
The measure of the side length is 16 cm after applying the sin ratio which is the side opposite to the angle/hypotenuse.
What is a right-angle triangle?It is a triangle in which one of the angles is 90 degrees and the other two are sharp angles. The sides of a right-angled triangle are known as the hypotenuse, perpendicular, and base.
It is given that:
A right-angle triangle is shown in the picture.
To find the side length of the hypotenuse apply the sin ratio
sin30 = side opposite to the angle/hypotenuse
1/2 = 8/x
x = 8(2)
x = 16 cm
Thus, the measure of the side length is 16 cm after applying the sin ratio which is the side opposite to the angle/hypotenuse.
Learn more about the right-angle triangle here:
brainly.com/question/3770177
#SPJ2
32 divided by 1.6 how to work out
Answer:
20
Step-by-step explanation:
[tex]\frac{32}{1.6} =\frac{32}{\frac{16}{10}} =32*\frac{10}{16} =\frac{320}{16} =20[/tex]
So the answer is 20
Sue has $500 in an account for 9 years at a compound rate of 7.5%. How much does she have?
Answer:
she has about $3750 in her acount.
Step-by-step explanation:
hope this helps you!
Which function is represented by the graph below?
Answer:
[tex]f(x)=2^x[/tex]
Step-by-step explanation:
Exponential function:
[tex]f(x)=a(b^x)+c[/tex]
Step 1. Find a, y-intercept
Step 2. Find b, slope
Step 3. Find c, horizontal asymptote
a = 1
m = (y₂ - y₁)/(x₂ - x₁)
m = (3 - 1)/(1 - 0) = 2/1
b = 2
c = 0
[tex]f(x)=1(2^x)+0\\f(x)=2^x[/tex]
The following data shows the low temperature in Vancouver, in degrees Celsius, for two weeks in January one year.
8.40, 8.35, 8.50, 8.40, 8.90, 8.20, 8.50, 8.30, 8.50, 8.50, 8.75, 8.30, 8.10, 8.55
Which box plot best represents this data?
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.9 and the interquartile ranges approximately between 8.3 and 8.5 and the median falls approximately between 8.4 and 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.7 and interquartile ranges approximately between 8.3 and 8.6 and median falls approximately between 8.4 and 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.2 and maximum value is 8.9 and interquartile ranges approximately between 8.3 and 8.6 and median is approximately at 8.5.
Box plot titled Low Temperature in Vancouver for Two Weeks in January with horizontal axis labeled Degrees Celsius ranges from 8 to 9 by 0.1. Minimum value is 8.1 and maximum value is 8.9 and interquartile ranges approximately between 8.3 and 8.5.
To create the dot plot you will list the data in order and use the given numbers to create the box plot.
8.10, 8.20, 8.30, 8.32, 8.34, 8.50, 8.50, 8.50, 8.55, 8.60, 8.60, 8.65, 8.65, 8.90
Lower extreme: 8.10
Upper extreme: 8.90
Median: 8.50
1st/lower quartile: 8.32
3rd/upper quartile: 8.60
Please see the attached picture for the boxplot.
Does anyone know how to get free answers? I ran out, I have a lot of points I just need more free answers again
Answer: I believe that by helping or answering others you can get get questions, but I do know there is a limited amount of questions being able to ask before paying monthly. Hope this helps
Answer:
What you have to do is answer peoples question to gain more
Step-by-step explanation:
if n=14 when m=4 find n when m=23
Why is circle 1 similar to circle 2?
Circle 1: center (2, 3) and radius 4
Circle 2: center (2, 3) and radius 12
Circle 1 and circle 2 have the same center.
Circle 2 is a dilation of circle 1 with a scale factor of 3.
Circle 1 and circle 2 are reflections of each other.
Circle 2 is a dilation of circle 1 with a scale factor of 8.
Help me, paid well just answer
Answer:
30.67
Step-by-step explanation:
[tex] \frac{9}{ \sin(x) } \: = \frac{16}{ \sin(115) } \\ \\ \frac{9}{ \sin(x) } \: = \frac{16}{ 0.91 } \: \: \\ \\ \frac{9 \times 0.91}{16} = \sin(x) \\ x = 30.67[/tex]
please help
i cant do this
Answer:
42 sq. cm
Step-by-step explanation:
Answer: 42 sq. cm
Length of Big Rectangle: 7
Width of Big Rectangle 7+0.5+0.5 = 8
Area of Big Rectangle: 56
Area of Small Rectangle = 0.5*7 = 3.5
Area of 4 Small Rectangles = 3.5 *4 = 14
Shaded Area = Big Rectangle - 4 Small Rectangles = 56 - 14 = 42 sq. cm