Answer:
Some motor tyre contain Graphite to contain friction.
Answer:
to contain friction
Explanation:
PLEASE HELP
Which statement about matter is true?
Matter is anything that is made of atoms and that has mass (and volume).
Matter is anything that is made of organic substances and is found on the earth.
Matter is an element.
Matter is a compound
Answer: Matter is anything that is made of atoms and that has mass (A)
Explanation: All everyday objects that can be touched are ultimately composed of atoms. Even you are made of atoms. Anything that you can touch has moving particles unless the object is at absolute zero, which is not possible.
Hope this helps!
Oxygen is needed by all cells of most organisms for the release of
energy from what in photosynthesis?
Answer:
From the SUN
Explanation:
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A 8.2 kg solid sphere, made of metal whose density is 2300 kg/m3, is suspended by a cord. When the sphere is immersed in a liquid of unknown density, the tension in the cord is 23 N. The density of the liquid is
The density of the liquid is 1470.43 kg/m³. Density is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.
What is density?Density is defined as the mass per unit volume. The mass and density relation is given as;
mass = density × volume
The given data in the problem is as ;
m is the mass of a solid sphere=8.2 kg
[tex]\rm \rho_s[/tex] is the density of the metal= 2300 kg/m³
T is the tension in the cord = 23 N.
The volume of the liquid is found as;
[tex]\rm V_{sphere} = \frac{m}{\rho} \\\\ \rm V_{sphere} =\frac{8.2}{2300} \\\\ \rm V_{sphere} = 0.00356 \ m^3[/tex]
The volume of the sphere is equal to the volume displaced;
Volume displaced = 0.00356 m³
The buoyant force is found as;
[tex]\rm F_B = \rho g V \\\\[/tex]
From the given condition it is observed that the weight of the sphere is equal to the sum of buoyancy force and the tension in the cord.
[tex]\rm mg = \rho g V+T \\\\ 8.2 \times 9.81 = \rho \times 9.81 \times 0.00356+23 \\\\\ 80.442=\rho \times 0.0349 +23 \\\\ \rho = 1645.90 \ kg/m^3[/tex]
Hence the density of the liquid is 1645.90 kg/m³.
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how do i turtle answer fast
Answer:
Take your TIme maaaaaan
Explanation:
Chillax
Here's a question for you Care to go bowling?
Answer:
By taking it Slow.
Don't go too fast
Calculate the solar angle for the day at 10am and 2pm individually for the location of 21.23 south latitude on the 18th march 1993 (Assume it is non leap year)
Based on the latitude and time of the place, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.
What is the solar hour angle?The solar hour angle of a point on the earth’s surface is the angle through which the earth would turn to bring the meridian of the point directly under the sun.
The rotation of the earth on its axis is 15° per hour where before noon is negative and after noon is positive. For example, at 10:00 a.m. local apparent time the hour angle is −30°.
Therefore, based on the latitude and time, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.
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T F
Organisms get energy from food
Answer:
It's true that organisms get energy from food.
Answer:
Explanation:
Organisms ingest large molecules, like carbohydrates, proteins, and fats, and convert them into smaller molecules like carbon dioxide and water. This process is called cellular respiration, a form of catabolism, and makes energy available for the cell to use
please solve the given question
I know the answer but I need explanation also
PLEASE help
R² = F1² + F2² + 2 F1.F2 cos α ⇒cosinus
F1 and F2 perpendicular, α = 90°, cos 90° = 0
[tex]\tt R=\sqrt{3^3+4^2}=5[/tex]
To reduce auto emissions in the United States, modifications to automobile engines have been required since the 1960s.
a) true
b) false
Answer:
True
Explanation:
the base is a polygon and its faces are triangles (cone, cube, cylinder, pyramid, rectangular prism
Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B
Answer:
Explanation:
Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B
PLSSSS HELPPPP ASAPPP
A fluorescent light bulb produces just as much light in the same electrical circuit as an incandescent bulb , but requires much less energy to produce it. Which of the following is the most logical explanation for this?
A. The incandescent bulb produces more forms of energy than just light, like heat.
B. The fluorescent light bulb produces more light than any other bulb.
C. The incandescent bulb has to be connected to another circuit.
D. The fluorescent light bulb generates more current than any other type.
Answer:
The most logical explanation is A.
Explanation:
because we are explaining why the incandescent bulb uses less energy we can eliminate answers B and D then, because we are talking about energy efficiency which has nothing to do with connecting to another circuit we can go with, A because Ultraviolet light generated by fluorescent light bulbs is nothing compared to the heat of an incandescent light bulb because it was engineered to be so.
Obtain the potential on the x-axis at x = 0 for the following point charge distributions on the x-axis: 200 μC at x = 20 cm, -300 μC at x = 30 cm and -400 μC at x = 40 cm.
The eletric potential on the x - axis at x = 0 cm for the given three charges is determined as 9 x 10⁶ V.
Electric potentialThe electric potential at a point is the work done in moving a test charge from infinity to a certain point.
Eletric potential at x = 0 cmV(net) = V1 + V2 + V3
[tex]V = - \frac{kq}{r} \\\\V(net) = V_1 + V_2 + V_3\\\\V_{(net)} = -\frac{9\times 10^9 \times 200\times 10^{-6}}{0.2} + \frac{9\times 10^9 \times 300\times 10^{-6}}{0.3}+ \frac{9\times 10^9 \times 400\times 10^{-6}}{0.4}\\\\V_{(net)} = -9\times 10^6 \ + \ 9\times 10^6 \ + \ 9\times 10^6 \\\\V_{(net)} = 9\times 10^6 \ V[/tex]
Thus, the eletric potential on the x - axis at x = 0 cm for the given three charges is determined as 9 x 10⁶ V.
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What is the average velocity if the initial velocity of an object is 10 and the a final velocity is 28
Answer:
19
Explanation:
Avg. Vel = (28 + 10)/2
= 19
BTW, don't forget your units!
Identify a scenario from
gym class that has an action-reaction force. Describe the situation
Answer:
A person is doing push-ups against a wall (action force), and the wall exerts an equal and opposite force against the person (reaction force).
Explanation:
A 2.8 F capacitor and a 3,440
Ω
resistor are connected to a battery of voltage 5 V as shown in the circuit. After
closing the switch, how long will it take for the capacitor voltage to be 45 % of
the battery voltage?
Express your answer in seconds (s)
The time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.
Discharge of the capacitor voltage
The rate at which the capacitor voltage discharges is given by the following formula;
[tex]V = V_0(1 - e^{-t/RC})[/tex]
Where;
V₀ is the initial voltageV is the final voltaget is the time of dischargeR is resistanceC is capacitanceThe final voltage = 0.45 x 5 V = 2.25 V
[tex]2.25 = 5(1 - e^{-t/RC})\\\\(1 - e^{-t/RC}) = \frac{2.25}{5} \\\\(1 - e^{-t/RC}) = 0.45\\\\e^{-t/RC} = 1- 0.45\\\\e^{-t/RC} = 0.55\\\\\frac{-t}{RC} = ln(0.55)\\\\\frac{-t}{RC} = -0.597\\\\t = 0.597 (RC)\\\\t = 0.597(3440 \times 2.8)\\\\t = 5,750.3 \ s[/tex]
Thus, the time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.
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in the diagram, q1,q2, and q3 are in a straight line. each of these particles has a charge of -2.35x10^-6 C. particles q1 and q2 are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. what is the net force on particle q3?
The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.
Given the following data:
Charge = [tex]-2.35 \times 10^{-6}[/tex] C.
Distance = 0.100 m.
Scientific data:
Coulomb's constant = [tex]8.988\times 10^9 \;Nm^2/C^2[/tex]
How to calculate the net force.In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = F₁₃ + F₂₃
Mathematically, the electrostatic force between two (2) charges is given by this formula:
[tex]F = k\frac{q_1q_2}{r^2}[/tex]
Where:
q represent the charge.r is the distance between two charges.k is Coulomb's constant.Note: d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.
For electrostatic force (F₁₃);
[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.200^2}\\\\F_{13} = \frac{0.0496}{0.04}[/tex]
F₁₃ = 1.24 Newton.
For electrostatic force (F₂₃);
[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.100^2}\\\\F_{13} = \frac{0.0496}{0.01}[/tex]
F₂₃ = 4.96 Newton.
Therefore, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = 1.24 + 4.96
F₃ = 6.2 Newton.
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Answer:
6.2
Explanation:
acellus
A car starts moving from rest; If it gains avelocity of 72km/ht after to seconds what is the acceleration of the car.
Answer:
10 m/s²
Explanation:
Given
u = 0 (initial velocity as it is at rest)v = 72 km/h x 5/18 = 20 m/st = 2sSolving
v = u + at20 = 0 + 2a2a = 20a = 10 m/s²The correct answer is 10 m/s² .
An 80.0 kg merry-go-round of radius 1.20 m is accelerating horizontally from rest by a constant force of 70.0 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go-round after 5.00 s. (Assume it is a solid cylinder.)
The kinetic energy of the merry-go-round after 5.00 s, when a constant force is applied tangentially to it, is determined as 3,069.5 J.
Conservation of angular momentumThe kinetic energy of the merry-go-round is determined by applying the principle of conservation of angular momentum as follows;
Iα = rF
where;
I is moment of inertia of the merry-go-round (solid cylinder)I = ¹/₂mr²
I = ¹/₂ x 80 x (1.2)²
I = 57.6 kgm²
α = (rF)/I
α = ( 1.2 x 70) / (57.6)
α = 1.46 rad/s²
Tangential acceleration of the merry-go-rounda = αR
a = 1.46 x 1.2
a = 1.752 m/s²
Velocity of the merry-go-roundThe velocity of the merry-go-round after 5 s is calculated as follows;
v = u + at
v = 0 + (1.752x 5)
v = 8.76 m/s
Kinetic energy of the merry-go-roundK.E = ¹/₂mv²
K.E = ¹/₂ x 80 x 8.76²
K.E = 3,069.5 J
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brainly an andean condor with a wingspan and a mass soars along a horizontal path. model its wings as a rectangle with a width. determine the difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces brainly
The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is 101,204 Pa.
Difference in pressure between the top and bottom of the wingspanThe difference in pressure between the top and bottom of the wingspan is calculated as follows;
ΔP = P(top) - P(bottom)
Area of the wingspanA = bh
A = 2.7 m x 0.27 m
A = 0.729 m²
Weight of the Andean condorW = mg
W = 9 x 9.8
W = 88.2 N
Pressure at the top surface of condor's wingsThe pressure at the top surface of condor's wings is due to atmospheric pressure
P(top) = 14.7 Psi = 101,325 Pa
Pressure at the bottom surface of condor's wingsThe pressure at the bottom surface is due to weight of andean condor.
P = W/A
P(bottom) = 88.2/0.729
P(bottom) = 120.99 Pa
The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is calculated as;
ΔP = P(top) - P(bottom)
ΔP = 101,325 Pa - 120.99 Pa
ΔP = 101,204 Pa
The complete question is below;
An Andean condor with a wingspan of 270 cm and a mass of 9.00 kg soars along a horizontal path. Model its wings as a rectangle with a width of 27.0 cm.
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if every Galaxy have black hole in center than is that mean there used to humongous star that collapsed that formed galaxy and supermassive black hole?
Answer:
Yes, It does mean that there was a Red Giant in the middle of the galaxy.
Explanation:
The star at the middle of the galaxy will forever stay at the middle from the gravity it has on itself and it implodes and turns into a black hole with a mass equal to at least 10 suns
Which of the following is true about how pressure varies with depth in a fluid? a. Pressure decreases with depth because it must support the fluid weight above it. b. Pressure increases with depth because it must support the fluid weight above it. c. Pressure decreases with depth because it is supported by the fluid weight below it. d. Pressure increases with depth because it is supported by the fluid weight below it.
Answer:
b) pressure increases with depth because of the weight of the fluid above
P = ρ g H density * gravity * fluid depth
(Note - force from the fluid below is an example of Newton's Third Law - for every action there is an equal and opposite reaction)
Which definition refers to electrical power?
A. The rate at which an electric charge flows past a point in a circuit
B. The energy of an electric charge minus the resistance in a circuit
C. The energy of an electric charge due to its position in an electric
field
D. The rate at which electrical energy is transferred in a circuit
The diagram shows a box being pulled along a horizontal surface with a force of 200.0 N.
Calculate the work done on the box to pull it a distance of 5.0 m.
Answer:
The formula for work is
W= fd
work= force X distance
so, this is
200 X 5 =1,000
and the unit for work is Joules
so.. 1,000 joules
Explanation:
hope that helps!
3. The property of sound called intensity is proportional
to the rate at which energy flows through
A.an area perpendicular to the direction of
propagation.
B.an area parallel to the direction of propagation.
C.a cylindrical tube.
D.a sound wave of a certain frequency.
Answer:
A. an area perpendicular to the direction of propagation.
Explanation:
The property of sound called intensity is proportional
to the rate at which energy flows through an area perpendicular to the direction of propagation.
4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid
Question
4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid
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Answer:
Explanation:4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid
When a potential difference of 2 volt is applied across the ends of a wire of 5 metre length a current of 1 ampere flows through it,calculate :-
(i) the resistance per unit length of the wire
(ii) the resistance of 2 metre length of the wire
(iii) the resistance across the ends of the wire if it is doubled on itself
[tex]\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} ⟿}[/tex]
(i) 0.4 Ω m^-1
(ii) 0.8 Ω
(iii) 0.5 Ω
Explanation:
(i) Given, V = 2 volt, I = 1 AResistance of 5 m length of wire :-
[tex] = > R = \frac{V}{I} = \frac{2}{1} = 2 \: Ω [/tex]
Resistance per unit length of the wire :-
[tex] = > \frac{R}{l} = \frac{2}{5} = 0.4 \: Ω \: {m}^{ - 1} [/tex]
(ii) Resistance of 2m length of the wire~
[tex] = \: 0.4 \: Ω \: {m}^{ - 1} \times 2 \: m = 0.8 \: Ω [/tex]
(iii) When the wire is doubled on itself, its area of cross section becomes twice and the length becomes half. Let a be the initial cross section and ρ be the specific resistance of the material of wire. Then,
[tex]from \ relation \: \: ➪ \: R = ρ \times \frac{1}{a}. \\ \\ we \: have, \\ \\ initial \: resistance \:➪ \: 2 = ρ\times \frac{5}{a}....eqn(i) \\ \\ new \: resistance \: ➪ \: R` = ρ\times \frac{2.5}{2a}....eqn(ii) \\ \\ on \: dividing \: eqn(ii) \: by \: eqn(i)... \\ \\ \frac{R`}{2} = \frac{2.5ρ}{2a} \div \frac{5ρ}{a} = \frac{1}{4} \\ \\ R` = \frac{2}{4} = 0.5 \: Ω[/tex]
Thus, on doubling the wire on itself, its resistance becomes one-fourth.
Hope it helps you!!Why is cellular reproduction important for homeostasis?
It helps cells make oxygen.
It helps cells make glucose.
It removes waste from cells.
It splits a cell into new cell
Answer:
(It was a remove waste from cells)
Explanation:
the cell produces carbon dioxide and water, which are released as waste.
The marble has its maximum gravitational potential energy when it is at the starting point: the
highest point on the roller coaster. How much of this potential energy is converted to the
marble's kinetic energy?
Answer:
Explanation:
This depends on the height.
Using the formula mgh + 1/2mv^2 = total mechanical energy, we can determine the amount of kinetic and potential energy. I'm assuming your talking about if the marble goes all the down, then all of the energy is converted.
A 3.0-kg block moves up a 40° incline with constant speed under the action of a 26-N force acting up and parallel to the incline. What magnitude force must act up and parallel to the incline for the block to move down the incline at constant velocity?
Explanation:
Sooooo, first,
Constant Speed means that the body isn't accelerating.
a= 0
Let the force that causes it to move up the incline be P and Q be the force that causes the body to move down the incline. Let Fr be the frictional force.
The force that pulls the body downwards is given by,
F = mgsin40°
F= 18.898N
P -(F+Fr) = ma, but, a= 0
P = F + Fr
Fr = 26-18.898
= 7.102N
If the block must move down the incline, Q and Fr will act in the same direction.
Q + Fr = F
Q = 11.796N
A negative charge of -6.0x10-6 C exerts an
attractive force of 65 N on a second charge that is
0.050 m away. What is the magnitude of the second
charge?
The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C
Coulomb's law equationF = Kq₁q₂ / r²
Where
F is the force of attraction K is the electrical constant q₁ and q₂ are two point charges r is the distance apart How to determine the second charge Charge 1 (q₁) = –6×10¯⁶ CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 0.05 mForce (F) = 65 NCharge 2 (q₂) =?F = Kq₁q₂ / r²
Cross multiply
Fr² = Kq₁q₂
Divide both side by Kq₁
q₂ = Fr² / Kq₁
q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)
q₂ = +3.0×10¯⁶ C (since the force is attractive)
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