Answer: Simple Machines are useful and important because they reduce effort or extend the ability of people to form tasks beyond their normal capabilities . So they help us in our daily lives by reducing the amount of effort it takes for humans to perform certain tasks .
HOPE IT HELPS YOU .PLEASE GIVE BRAINLIEST .THANKS .
A net force of 24 N is acting on a 4.0-kg object. Find the acceleration in m/s2.
Hi there!
We can use Newton's Second Law:
[tex]\Sigma F = ma[/tex]
ΣF = Net force (N)
m = mass (kg)
a = acceleration (m/s²)
We can rearrange the equation to solve for the acceleration.
[tex]a = \frac{\Sigma F}{m}\\\\a = \frac{24}{4} = \boxed{6 \frac{m}{s^2}}[/tex]
The figure shows the electric field inside a cylinder of radius R= 3.2 mm. The field strength is increasing with time as E= 1.4 ×108t2V/m, where t is in s. The electric field outside the cylinder is always zero, and the field inside the cylinder was zero for t<0. Find an expression for magnetic field strength as a function of time at a distance r>R from the center.
The Magnetic field strength as a function of time will be 2.4 ×10⁻¹¹ T.it is denoted by B.
What is magnetic field strength?The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength
Given
The radius of cylinder is,R=2.8 mm = 0.028 m
[tex]\rm \oint B.ds = \frac{\mu_0 \epsilon_0 d\phi}{dt} \\\\ B \times 2\pi r = \frac{\mu_0 \EPSILON_0 d (EA)i}{dt} \\\\\ b = \frac{\mu_0 \epsilon_0 \times \PI r^ 2 d(E)}{dt} \times \frac{1}{2\pir} \\\\ B= \frac{\mu_0 \epsilon_0 \times rd (E)}{2dt} \\\\ B= \frac{1.26 \times 10^{-5}\times 8.85 \times 10^{-12}\times (3.2 \times 10^{-3})\times 1.4 \times 10^8}{2} \\\\ B =2.4 \times 10^{-11} \ T[/tex]
Hence, magnetic field strength as a function of time will be 2.4 ×10⁻¹¹ T.
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Why are undergraments usually made of cotton
The atoms in a magnet are ___________ according to their poles.
Answer:
north and south poles
Explanation:
Both natural processes and human activity are causing some of Earth's permanent
bodies of ice to melt. If enough of this ice melts, it will add warm freshwater to the
northern Atlantic Ocean, where deep water currents start. What effect is this likely to
have on the circulation of ocean water around the globe?
Answer:
The water will get more warm fresh water
Explanation:
NEED HELP ASAP I WILL MARK YOU BRAINLIEST!!
What is constructive and destructive interference? In your own words.
Answer:
When the lines (representing peaks) pass over each other, constructive interference occurs. To put it another way, when two waves are in phase, they constructively interfere. When two waves are entirely out of phase (a peak lies in the middle of two waves), destructive interference ensues.
Explanation:
The figure shows the cross section of a long cylindrical wire of
radius aa, which carries a uniform current ii0. Determine the module of the field
magnetic produced by the current at a distance from the axis of the wire equal to (a)
0, (b) a/2, (c) a (wire surface) and (d) 2a.
Hi there!
Recall Ampere's Law:
[tex]\oint B \cdot dl = \mu_0 i_{encl}[/tex]
B = Magnetic Field Strength (T)
μ₀ = Permeability of Free Space (Tm/A)
i = Enclosed Current (A)
dL = differential path length
To begin, we must derive an expression for the magnetic field strength inside a wire that contains a uniformly-distributed current.
Using the expression:
[tex]i = \int J \cdot dA[/tex]
Where 'J' is the density of current, and A is the cross-sectional area:
[tex]A = \pi r^2\\\\dA = 2\pi r dr[/tex]
We know that:
[tex]J = \frac{i_0 }{A}\\\\J = \frac{i_0}{\pi a^2}[/tex]
This is the current density. We can now integrate:
[tex]i = \int\limits^r_0 {\frac{i_0}{\pi a^2} \cdot 2\pi r} \, dr\\ \\i =\frac{i_0}{a^2}\int\limits^r_0 {2r } \, dr\\\\i = \frac{i_0}{a^2} \cdot r^2 = \frac{i_0 r^2}{a^2}[/tex]
Now, substitute this expression back into the above equation for the magnetic field:
[tex]\oint B \cdot dl = \mu _0 \frac{i_0r^2}{a^2}[/tex]
The path of integration is a closed loop of length 2πr, so:
[tex]B \cdot 2\pi r = \mu_0 \frac{i_0r^2}{a^2}\\\\B = \frac{\mu_0 i_0r}{2\pi a^2}[/tex]
We can now use this equation for the first 2 parts.
a)
If 'r' equals 0:
[tex]B = \frac{\mu _0 i_0 (0)}{2\pi a^2} = \boxed{0 T}[/tex]
b)
If 'r' equals a/2:
[tex]B = \frac{\mu _0 i_0 (\frac{a}{2})}{2\pi a^2} =B =\boxed{ \frac{\mu _0 i_0 }{4\pi a} T}[/tex]
c)
At the wire's surface, 'r' = a:
[tex]B = \frac{\mu _0 i_0 (a)}{2\pi a^2} =B =\boxed{ \frac{\mu _0 i_0 }{2\pi a} T}[/tex]
d)
At 'r' = 2a, since this is outside of the wire, the relationship between magnetic field and distance from the wire becomes a 1/r (inverse) relationship. This is found using Ampere's Law:
[tex]B = \frac{\mu_0 i_0}{2\pi r}\\[/tex]
[tex]B = \frac{\mu_0 i_0}{2\pi (2a)} \\\\\boxed{B = \frac{\mu_0 i_0}{4\pi a}\\}[/tex]
A student makes the argument that light travels faster in the glass block than the air surrounding it. The student explains that the angle between the edge of the block and the ray of light is bigger in the glass than it is in the air, and a bigger angle is associated with a higher speed . Is he correct or not and why ?
Light travels faster in air than in glass because air is an optically rarer medium.
Speed of light?The term speed of light refers to the speed with which light travels through diverse materials. We know that light travels faster in air than in glass owing the the difference in the nature and composition of the two materials.
Hence, the explanation of the student concerning the differences in angles does not account for the differences in the speed of light in materials. Light travels faster in air than in glass because air is an optically rarer medium.
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What is the voltage drop across the 10.0 2 resistor?
OA. 2.00 V
OB. 20.0 V
OC. 10.0 V
OD. 12.0 V
Answer:
the answer is equal to 2.00v
The voltage drops across 10 Ω resistance with voltage 120V is 20 V. Hence, option B is correct.
What is voltage drop?The potential difference between two points is defined as the amount of work done in moving a unit of positive charge from one point to another. The potential difference or voltage is measured in volts(v).
According to Ohm's law, voltage is directly proportional to the current flow in the circuit. Voltage drop in the circuit is defined as a decrease in electric potential along the path of the current in the circuit.
The voltage drop occurs because of the current flow in the circuit. It is related to resistance and impedance to the current flow in the circuit.
From the given,
the resistors are connected in series,
R(eq) = R₁ + R₂ + R₃
= 10 + 20 + 30
= 60 ohm
The equivalent resistance is 60 ohms.
To find current by using Ohm's law:
V= I×R
I = V/R
= 120/60
= 2 A
The current flow in the circuit is 2 amperes.
To find voltage drop:
V= I×R
= 2×10
= 20 V
The voltage drop across the resistor 10Ω is 20 V.
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What is magnestism? Explain
Answer:
a physical phenomenon produced by the motion of electric charge, which results in attractive and repulsive forces between objects.the ability to attract and charm people.Answer:
Magnetism is the force of attraction or repulsion between substances.
Magnetism is defined as an attractive and repulsive phenomenon produced by a moving electric charge. The affected region around a moving charge consists of both an electric field and a magnetic field. The most familiar example of magnetism is a bar magnet, which is attracted to a magnetic field and can attract or repel other magnets.Magnetism is caused by the electromagnetic force, which is one of the four fundamental forces of nature. Any moving electric charge (electric current) generates a magnetic field perpendicular to it.
what kind of substance has particles that are close together, but can change shape depending on its container
Answer:
the liquid state
Explanation:
because the particles can move about freely, a liquid has no definite shape and takes a shape dictated by its container.
An inductor of inductance 0.02H and capacitor of capacitance 2 microF are connected in series to an AC source of frequency 200/pi Hz. What is the impedance in the circuit?
derive an expression to show tha v=✓2Gr
Answer:
From this equation, it can be said that the escape velocity depends on the radius of the planet and the mass of the planet only and not on the mass of the body. Escape Velocity of Earth= 11.2 km/s. This was the derivation of the escape velocity of earth or any other planet.
Explanation:
Which of the following statements about height and strength gains is true?
In boys, the strength spurt occurs about a year after their height spurt.
O In girls, the strength spurt occurs about a year after their height spurt.
O In boys, the spurts in height and strength tend to occur synchronously.
O In girls, the height spurt occurs about a year after their strength spurt.
The statement that is true about height and strength is that In boys, the strength spurt occurs about a year after their height spurt
What is puberty?Puberty is the transformational change that occur between childhood and adulthood. It is a stage of maturity
Height of a person is the distance from the feet of a person to the peak or his head.
Strength is the ability of a person to be very strong and can do vigorous things.
Therefore, The statement that is true about height and strength is that In boys, the strength spurt occurs about a year after their height spurt.
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Which of the following was NOT one of Ghana's chief trading exports?
A. Gold
B. Ivory
C. Horses
the answer is option C, because there were no horses in Ghana
Question 20 of 20
Which statement accurately describes how the velocity of an object in free
fall changes?
A. The distance it travels each second increases at a constant rate.
B. The distance it travels each second decreases at a constant rate.
• C. The distance it travels each second is constant. iS
• D. The distance it travels each second varies irregularly.
SUBMIT
Answer:
a
Explanation:
hI I
Two transverse sinusoidal waves combining in a medium are described by the wave functions y1 = 3.00 sin π(x - 0.600t), y2 = 3.00 sin π(x - 0.600t) where x, y1, and y2 are in centimeters and t is in seconds. Determine the maximum transverse position of an element of the medium at (a) x=0.250 cm, (b) x =0.500 cm, and (c) x = 1.50 cm. (d) Find the three smallest values of x corresponding to antinodes.
Answer:
Explanation:
The interfering waves have form y
1
=Asin(kx−ωt) and y
2
=Asin(kx+ωt)
Thus the resultant wave has displacement y=y
1
+y
2
=2Asin(kx)cos(ωt)
Maximum displacement is obtained when cos(ωt)=1
Thus y
max
=2×3×sin(π×0.25)=4.24cm
The maximum transverse position of an element of the medium is 3.00 cm at x=0.250 cm, 0 cm at x=0.500 cm, and -3.00 cm at x=1.50 cm, and the three smallest values of x corresponding to antinodes are 0.150 cm, 0.450 cm, and 0.750 cm.
What is a transverse wave?A transverse wave is a type of wave where the disturbance, or displacement, of the medium, is perpendicular to the direction in which the wave travels.
Here in the Question,
There appears to be a typo in the given wave functions, as they are both the same. I will assume that the second wave function is actually y2 = 3.00 sin(2πx - 0.600t).
The resulting wave function for the two waves is y = y1 + y2 = 3.00 sin π(x - 0.600t) + 3.00 sin(2πx - 0.600t).
(a) At x = 0.250 cm, the maximum transverse position occurs when sin π(x - 0.600t) = 1 and sin(2πx - 0.600t) = 0. Therefore, y = 3.00 cm.
(b) At x = 0.500 cm, the maximum transverse position occurs when sin π(x - 0.600t) = 0 and sin(2πx - 0.600t) = -1. Therefore, y = -3.00 cm.
(c) At x = 1.50 cm, the maximum transverse position occurs when sin π(x - 0.600t) = -1 and sin(2πx - 0.600t) = 0. Therefore, y = -3.00 cm.
(d) The antinodes occur at the maximum values of y, which correspond to when sin π(x - 0.600t) = 1 or -1 and sin(2πx - 0.600t) = 0. The three smallest values of x that satisfy these conditions are:
x = 0.25 cm, as found in part (a)
x = 0.75 cm, where sin π(x - 0.600t) = -1 and sin(2πx - 0.600t) = 0
x = 1.25 cm, where sin π(x - 0.600t) = 1 and sin(2πx - 0.600t) = 0
Therefore, The maximum transverse position of an element of the medium is 3.00 cm at x=0.250 cm, 0 cm at x=0.500 cm, and -3.00 cm at x=1.50 cm, and the three smallest values of x corresponding to antinodes are 0.150 cm, 0.450 cm, and 0.750 cm.
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THE 40-kg WOMAN STANDS AT
THE END OF A 4-METER-LONG
UNIFORM PLANK. IF THE MAXIMUM
OVERHANG FOR BALANCE IS 1 METER,
ESTIMATE THE MASS OF THE PLANK.
Answer:
Let x be the overhang of the plank
(4 - x) = Y portion of plank less the overhang
Y / 2 M g = clockwise torque due to weight of plank
40 x = counterclockwise torque due to weight of woman
(4 - x) M g / 2 = 40 x
(4 - x) M g = 80 x (I)
4 M g = (80 + M g) x (II)
x = 4 M g / (80 + M g) = 4 / (80 / M g + 1)
x would be shorter with an increase in M
if x were 1 then
4 M g = 80 + M g using (II)
M = 80 / (3 g) = 2.72 kg
Check: use x = 1 in equaton (I)
3 M g = 80
M = 80 / (3 * 9.8) = 2.72 kg
Two sound sources generate pure tones of 65 Hz and 75 Hz. What is the beat frequency?
a
15Hz
b
20Hz
c
10Hz
d
5Hz
Answer:
D) 5 HzExplanation:
First, prime factorize the two pure tone values.
65 = 5 x 1375 = 5 x 5 x 3It is clear that the Highest Common Factor (HCF) is 5
The two tones can only be pure if they resonate from the same beat frequency.
As 5 is a common factor, it is the beat frequency.
derive the value of electric field due to a uniform sphere of charge.
thankyou! :)
[tex]\\ \\ \\ [/tex]
The Force "F" applied on the unit electric charge "q" at a point describes the electric field.
☆ Formula to find electric charge:E = F/qHope it helpsThe equation for water is H₂ +0₂ → H₂O. To balance the equation, which coefficient should be placed in front of H₂ and H₂O?
1
2
3
4
How many planets are in our solar system?
Answer:
8
Explanation:
Answer: Eight planets in our Solar System.
Explanation:
identify a theorist, summarize their theory and explain the aspects of that theory thsat relate to the biological perspective
Answer:
the theorist that I chose is John Watson. He focused on the behaviors of a person on the outside. “He believed that a person’s physical responses provided the only insight into internal actions.”[ CITATION Goo15 \l 1033 ] He believed that behaviors are learned, as with the rat white and “Albert”. He taught “Albert” to fear the rat by making a sound any time the rat was shown. “Through learning, an initially neutral stimulus, the white rat, had become a stimulus for fear.”[CITATION Car17 \p 41 \l 1033
Explanation:
this is the answer
The biologist who had summarized the theory to explain the aspects of the theory is john watson.
Who was john watson?
John B. Watson was a trailblazing psychologist who made significant contributions to the growth of behaviorism. Watson thought that the main focus of psychology should be on observable behavior in science. He is famous for his studies on the process of conditioning.
Watson is particularly well-known for the Little Albert experiment, in which he showed how a young kid may be taught to fear a stimulus that was previously neutral. Additionally, his studies shown that this phobia might extend to other similar things.
Therefore, The biologist who had summarized the theory to explain the aspects of the theory is john watson.
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you do 185 J of work in 45 seconds. how much power do you use?
Answer:
1.11 watts
Explanation:
power = joules / sec
184/45 = 1.11 Watts
The chart shows data for four moving objects.
Object
Initial Velocity
Final Velocity
Change in
(m/s)
(m/s)
Time (s)
29
6
X>N
10
34
12
12
40
20
28
8
Which object has the greatest acceleration?
W
x
Y
Z
Answer:
Explanation:
The chart shows data for four moving objects.
Object
Initial Velocity
Final Velocity
Change in
(m/s)
(m/s)
Time (s)
29
6
X>N
10
34
12
12
40
20
28
8
Which object has the greatest acceleration?
W
x
Y
Hide Time Remaining
15. A puck is set in motion across a frozen pond. Friction and air resistance may be neglected. If you see the puck change its direction but not its speed, then the
force on the puck is
OA Non-zero, and equal to the product of its mass times its weight
OB. Non-zero, and equal to its weight
OC. Zero
OD. Non-zero, and depends on the puck's new direction
Reset Section
Answer:
the answer is equal to non zero
Water flows through a horizontal pipe with a cross-sectional area of 3mat a speed of 10 m/s with a pressure of 3 Bars at a Point A, which is 20m higher than Points B and C. At Point B, the cross-sectional area remains the same as Point A, but it has doubled at Point C. Now, calculate the pressure and speed of the water at Points B and C respectively.
(a) The speed of the water at point B is 10 m/s and the speed at point C is 5 m/s.
(b) The pressure of the water at point B is 4.96 bars and the pressure at point C is 5.335 bars.
Speed of the water at point BThe speed of the water at point B is determined from continuity equation as shown below;
Q = AV
A₁V₁ = A₂V₂
Since, A₁ = A₂ = 3 m²
V₁ = V₂ = 10 m/s
Thus, the speed of the water at point B is 10 m/s.
Speed of water at point CA₁V₁ = A₃V₃
A₁V₁ = (2A₁)V₃
V₃ = (A₁V₁) / 2A₁
V₃ = V₁ / 2
V₃ = 10/2
V₃ = 5 m/s
Thus, the speed of the water at point C is 5 m/s.
Pressure of the water at point BThe pressure of the water at point B is determined by appying Bernoulli's equation as shown below;
P₁ + ¹/₂ρV₁² + ρgh₁ = P₂ + ¹/₂ρV₂² + ρgh₂
where;
P₁ = 3 bars = 300,000 Paρ density of water = 1000 kg/m³g is acceleration due to gravity = 9.8 m/s²300,000 + ¹/₂(1000)(10)² + (1000)(9.8)(20) = P₂ + ¹/₂(1000)(10)²
546,000 = P₂ + 50,000
P₂ = 496,000 Pa
P₂ = 4.96 bars
Pressure of the water at point CP₁ + ¹/₂ρV₁² + ρgh₁ = P₃ + ¹/₂ρV₃² + ρgh₃
546,000 = P₃ + ¹/₂(1000)(5)²
546,000 = P₃ + 12,500
P₃ = 533,500 Pa
P₃ = 5.335 bars
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8. Il An 8.00 kg package in a mail-sorting room slides 2.00 m down a
chute that is inclined at 53.0° below the horizontal. The coefficient o
kinetic friction between the package and the chute's surface is 0.40.
Calculate the work done on the package by (a) friction, (b) gravity, and
(c) the normal force. (d) What is the net work done on the package?
Answer:
See below
Explanation:
Normal force = m g cos 53 = 8 kg * 9.8 m/s^2 * cos 53 = 47.1823 N
no work is done by this force
Force friction = coeff friction * force normal = .4 * 47.1823 = 7.55 N
work of friction = 7.55 * 2 m = 15.1 j
Force Downplane = mg sin 53 = 62.61 N
work = 62.61 * 2 = 125.22 j
Net Force downplane = force downplane - force friction = 55.06 N
net Work = force * distance = 55.06 N * 2 M = 110.12 j
Particles q1, 92, and q3 are in a straight line.
Particles q1 = -28.1 μC, q2 = +25.5 µC, and
93-47.9 μC. Particles q₁ and q2 are separated
by 0.300 m. Particles q2 and q3 are separated by
0.300 m. What is the net force on 93?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+25,5 μC
-28.1 μC
-47.9 μC
The net force on q₃ will be 17.51 N. The net force is the algebraic sum of the two forces on the pleading q₃
What is Columb's law?The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The force,by the charge q₁ on the q₃;
[tex]\rm F_{31}} = \frac{Kq_1q_3}{r^2} \\\\ \rm F_{31}} = \frac{9 \times 10^9 \times -28.1 \times 10^{-6}\times \times -47.9 \times 10^{-6}}{(0.600)^2} \\\\ F_{31}} =33.64 \ N[/tex]
The force,by the charge q₂ on the q₃;
[tex]\rm F_{32}} = \frac{Kq_2q_3}{r^2} \\\\ \rm F_{32}} = \frac{9 \times 10^9 \times 25.5 \times 10^{-6}\times \times -74.9\times 10^{-6}}{(0.300)^2} \\\\ F_{32}} =-19.09 \ N[/tex]
The net force is the sum of the two forces;
[tex]\rm F_{net}=F_{32}+F_{31}\\\\\ \rm F_{net}=36.6-19.9 \\\\ \rm F_{net}=17.51 \ N[/tex]
Hence, the net force on q₃ will be 17.51 N.
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I think its -88 on acellus