Will mark brainliest help last question

Answer:63745.6573

Explanation:

Answer:

26.6666666667Explanation:

80 divided by 3

The average speed was 26.67 Miles per hour (mph)

speed= distance ÷ time

speed= 80 miles ÷ 3 hours

speed= 26.67mph

Hope this helped you- have a good day bro cya)

Answer:

  1600 W

Explanation:

Power is the product of force and distance, divided by time.

  P = (120 kg)(10 m/s²)(40 m)/(30 s) = 1600 kg·m²/s³ = 1600 W

Answer:

electromagnetic spectrum is the range of frequencies of electromagnetic radiation and their respective wavelengths and photon energies.

Explanation:

brainliest me

Answer:

The electromagnetic spectrum is the range of frequencies (the spectrum) of electromagnetic radiation and their respective wavelengths and photon energies.

ok write it

Answer:

d

Explanation:

Answer:

Because they both hold the heat

Answer:

2.5 × 10-⁴¹ Ns

Explanation:

Impulse

I = F × t

I = 5000 N × 5 × 10-⁴⁵ s

I = 25 × 10-⁴² Ns

I = 2.5 × 10-⁴¹ Ns

#LearnWithEXO

1. 5 WBC's per cubic millimeter.

3. 50 to 80 mg/100 mL

4. 15 to 60 milligrams per deciliter (mg/dL) or 0.15 to 0.6 milligrams per milliliter (mg/mL)

If a test were to be performed here are normal results:

Normal values typically range as follows:

Pressure: 70 to 180 mm H2O

Appearance: clear, colorless

CSF total protein: 15 to 60 mg/100 mL

Gamma globulin: 3% to 12% of the total protein

CSF glucose: 50 to 80 mg/100 mL (or greater than two thirds of blood sugar level)

CSF cell count: 0 to 5 white blood cells (all mononuclear), and no red blood cells

Chloride: 110 to 125 mEq/L

(Source: https://medlineplus.gov/ency/article/003428.htm)

a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.

b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.

c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.

a)

Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.

[tex]x=\frac{v_{i}^{2}sin(2\alpha)}{g}[/tex] (1)

Donde:

Lo que debemos hacer es depejar α de la ecuación 1

[tex]sin(2\alpha)=\frac{xg}{v_{i}^{2}}[/tex]

[tex]sin(2\alpha)=\frac{560*9.81}{82^{2}}[/tex]

[tex]sin(2\alpha)=0.82[/tex]

[tex]\alpha=\frac{sin^{-1}(0.82)}{2}[/tex]

[tex]\alpha=27.39^{\circ}[/tex]

Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.

b)

Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.

[tex]v_{x}=\frac{x}{t}[/tex]

La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:

[tex]v_{i}cos(\alpha)=\frac{x}{t}[/tex]

[tex]t=\frac{x}{v_{i}cos(\alpha)}[/tex]

[tex]t=\frac{560}{82cos(27.39)}[/tex]

[tex]t=7.69\: s[/tex]

El tiempo total de vuelo de las balas de cañon es de 7.69 s.

c)

Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.

Puedes encontrar más información sobre tiro parabólico aquí:

https://brainly.lat/tarea/3605927

Espero te haya sido de ayuda!

Answer:

Its the last one.

Explanation:

Massive objects such as earth generate gravity, and the moon orbits the earth as it is smaller and close enough.

first resolve the initial velocity of the ball into two components

1)one parallel to ground(u)

2)another perpendicular to ground(v)

call the initial velocity=p=25.4 m/s at 58.0° deg to ground

so the horizontal component of velocity=25.4cos58=13.46 m/s

so the vertical component of velocity=25.4sin58=21.54 m/s

we have nothing to do with the horizontal component of velocity as it plays no part in the hang time

only vertical component of velocity determines the hang time

hang time=2*(vertical component of velocity)/(acceleration due to gravity)

==>hang time=2*21.54/9.8=4.39 s

==>hang time =4.39 s

If I'm wrong please let me know, thank you.

Answer:

I think it's the son

Explanation:

bcs he might love it

Answer:

[tex] |d| = \sqrt{ {(x_{2} -x_{1})}^{2} + {(y_{2} -y_{1})}^{2} + {(z_{2} -z_{1})}^{2}} \\ = \sqrt{ {(6 - 2)}^{2} + {(3 - 0)}^{2} +{(5 - 8)}^{2} } \\ = \sqrt{16 + 9 + 9} \\ = \sqrt{34} [/tex]

The position of an ant and a spider in a room are A(2,3,5) and B(6,0,8)  the distance between ant and spider is 5.83 m.

The distance formula states that the distance between two points in xyz-space is the square root of the sum of the squares of the differences between corresponding coordinates A( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] , [tex]z_{1}[/tex] ) and B( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] ,[tex]z_{2}[/tex]),

AB² = ([tex]x_{2}[/tex] - [tex]x_{1}[/tex])² + ([tex]y_{2}[/tex] - [tex]y_{1}[/tex])² + ( [tex]z_{2}[/tex]  - [tex]z_{1}[/tex] )²

In reality, the Pythagorean Theorem is nothing more than the distance formula. Draw a right triangle using the segment AB as its hypotenuse in order to get the distance AB between points  A( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] )  and B( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] ).

Given that in the question two points are A(2,3,5) and B(6,0,8), so the distance between them is

AB² = ([tex]x_{2}[/tex] - [tex]x_{1}[/tex])² + ([tex]y_{2}[/tex] - [tex]y_{1}[/tex])² + ( [tex]z_{2}[/tex]  - [tex]z_{1}[/tex] )²

AB² = 4² + 3² + 3²

AB² = 34

AB  = 5.83 m

Position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) the distance between ant and spider is 5.83 m.

To learn more about distance between two point refer to the link

brainly.com/question/24746233

 #SPJ5

Explanation:

given :

m = 20 g

sh = 0.39 J/g°C

∆T = 40-20 = 20°C

Find the Energy!

solution :

E =m. sh. ∆T

= 20 × 0.39 × 20

= 156 J

So, energy required is

Energy = mass*sh*∆T

Energy = 20g*0.39j/g°c*20°

Energy = 156joule✅

~Physics#1

Answer:

To summarize, potential energy is the energy that is stored in an object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height.

Explanation:

if it helped plz mark brainiest

Answer:

Explanation:

Conservation of momentum

Initial momentum is zero

mB(1.8) + mE(-2.6) = 0

mB(1.8) = mE(2.6)

mB/mE = 2.6/1.8

Answer:

I think A. I had a similar question

Explanation:

Answer:

there are two hydrogen atoms in all reactants

Diagram:-

[tex]\setlength{\unitlength}{2mm}\begin{picture}(0,0)\thicklines\put(3,6){\circle{3}}\put(2.9,4.5){\vector(0,-3){2cm}}\put(-3.9,-10){\line(3,0){3cm}}\multiput(-3.5,-10)(0.8,0){18}{\line(1,-2){2mm}}\put(-3.7,0){$\sf\footnotesize 9.8 ms^{-2}$}\put(6,0){\vector(0,3){1.2cm}}\put(5.5,6){\line(3,0){2mm}}\put(5,-1.2){\sf\footnotesize height}\put(6,-2){\vector(0,-3){1.2cm}}\put(5.5,-8){\line(1,0){2mm}}\end{picture}[/tex]

Here

[tex]\\ \sf\longmapsto Weight=mg[/tex]

[tex]\\ \sf\longmapsto Weight=6.4(9.8)[/tex]

[tex]\\ \sf\longmapsto weight=62.72N[/tex]

Answer: B Dark matter

We have that for the Question "Which component that makes up the bulk of all galaxies?  A. gas   B. dark matter   C. dust   D. stars​" it can be said that Invariably the dark matter makes up the bulk of all galaxies

Option B

From the question we are told

Which component that makes up the bulk of all galaxies?  

A. gas  

B. dark matter  

C. dust  

D. stars​

Generally

the Galaxy have a mass of about 2*10^{12} mass of sun

This is made up of 95% of dark matter

Therefore

Invariably the dark matter makes up the bulk of all galaxies

Option B

For more information on this visit

https://brainly.com/question/17208989

Answer:

true..............yh

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question

mass = 1000 kg

velocity = 5 m/s

We have

momentum = 1000 × 5 = 5000

We have the final answer as

Hope this helps you

24.8 m/s

Explanation:

You don't have to solve for time first. You can use the equation below to solve for the velocity before impact:

[tex]v_y^2 = v_{0y}^2 + 2a_yy[/tex]

We know that [tex]v_{0y} = 0[/tex] so the equation above becomes

[tex]v_y^2 = 2a_yy \Rightarrow v_y = \sqrt{-2a_yy}[/tex]

Plugging in the numbers, we get

[tex]v_y = \sqrt{-2(-9.8\:\text{m/s}^2)(31.3\:\text{m})}[/tex]

[tex]\:\:\:\:\:=24.8\:\text{m/s}[/tex]

METHOD 2:

If you insist on using that equation for d, we can do that too. So solving for t from the equation for d. we get

[tex]t = \sqrt{\dfrac{2d}{g}} = \sqrt{\dfrac{2(31.3\:\text{m})}{9.8\:\text{m/s}^2}}[/tex]

[tex]\:\:\:\:= 2.53\:\text{s}[/tex]

So using the equation [tex]v_y = gt,[/tex] we get

[tex]v_y = (9.8\:\text{m/s}^2)(2.53\:\text{s}) = 24.8\:\text{m/s}[/tex]

So you get the same result regardless of the method you use.

Answer:

???

Explanation:

Answer:

133 kg

Explanation:

the statement was the last time I get home and get some sleep and then we can

Answer:

need my points back

Explanation:

Answer:

Kelvin is a unit of temperature, whereas ampere is a unit of current.

True or False

Explanation:

true

Answer:

you made with your performance, and then consider whether you would do anything differently if yo

Explanation:

The useful energy generated by the machine having an efficiency of 15% and an energy input of 300 J is 45 J

Efficiency = 15% = 0.15

Work input = 300 J

The useful energy generated (i.e work output) by the machine can be obtained as follow:

[tex]Efficiency = \frac{workout}{workin} * 100\\\\0.15 = \frac{Workout}{300}[/tex]

Cross multiply

Work output = 0.15 × 300

Therefore, the useful energy generated by the machine is 45 J

Learn more: https://brainly.com/question/24490706