Write the chemical formula for the ionic compound formed by lithium and fluorine.

Answer:

         B             B

W      BW          BW        

W       BW          BW

Explanation:

Hope this helps

Answer:

60.0 mL

Explanation:

Using CAVA = CBVB

CA = 0.300M

VA = 20.0 mL

CB = 0.100M

VB = ?

VB = CAVA

CB

VB = 0.300 * 20/ 0.100

VB = 60.0 mL

Explanation:

Threshold frequency: Threshold frequency is the minimum frequency of the incident radiation below which photoelectric emission is not possible irrespective of the intensity of the incident radiation. ... Emitted electrons are called photoelectrons.

Hope this helps you dear :)

Good morning!

Answer: Yes , the equation is balanced.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The given chemical equation is:

[tex]2Al+Fe_2O_3\rightarrow 2Fe+Al_2O_3[/tex]

As the number of atoms on reactant side is equal to the number of atoms on product side, the equation is balanced.

Answer:

deez cutz

Explanation:

did i get it right

Answer:

Because a redox reaction holds for both oxidation and reduction.

One half equation is of oxidation and the other is of reduction.

When these two half equations are combined, we get an overall equation of the redox reaction.

Answer:

moles Na = 0.1114 g / 22.9898 g/mol=0.004846

moles Tc = 0.4562g /98.9063 g/mol=0.004612

mass O = 0.8961 - ( 0.1114 + 0.4562)=03285 g

moles O = 0.3285 g/ 15.999 g/mol=0.02053

divide by the smallest

0.02053/ 0.004612 =4.45 => O

0.004846/ 0.004612 = 1.0 => Tc

to get whole numbers multiply by 2

Na2Tc2O 9

Explanation:

Hope it right hope it helps

Explanation:

B) 3CuCl2+2AL..….2AlCl3+3Cu

hope it helps.

Balanced Equation:

3CuCl₂ + 2Al = 2AlCl₃ + 3Cu

Answer:

1. 24.45 moles

2. 437.90 grams

Bonus :

0.75 grams

Explanation:

Hope it was helpful ;)

Answer:

the reducing agent is Bromine

The oxidation state of an element is calculated by subtracting and the total sum of oxidation states of all the individual atom (excluding the one that has to be calculated) from total charge on the molecule. Bromine is the reducing agent in the following reaction.

Oxidation state of an element is a number that is assigned to an element in a molecule that represents the number of electron gained or lost during the formation of that molecule or compound.

The ionic equation is given as

2 Br⁻(aq) + H[tex]_2[/tex]O[tex]_2[/tex](aq) + 2 H⁺(aq) → Br[tex]_2[/tex](aq) + 2 H[tex]_2[/tex]O(l)

The oxidation state of bromine on reactant side is -1 while on product side it is 0 so, oxidation state of bromine has increased by 1 so,  bromine is oxidized. If it is oxidized that means it must have reduced someone. So, bromine is acting as a reducing agent.

Therefore, bromine is the reducing agent in the given reaction.

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Answer:

Wind

Explanation:

Wind turbines make energy by the movement of the natural force on earth called 'wind' and renewable resources are resources that can be made from natural and environment-safe objects or things (e.g. Water, Geothermal Heat, The Sun, and Wind)

Answer:

D

Explanation:

A growing body of scientific evidence shows that the felling of tropical forests creates optimal conditions for the spread of mosquito-borne scourges, including malaria and dengue. Primates and other animals are also spreading disease from cleared forests to people.

Answer:

The trait of the other cactus stopped it from being able to reproduce and survive.

The more concentrated the buffer solution, the greater its buffer capacity.

An acid is any substance that in water solution tastes sour, changes blue litmus paper to red, reacts with some metals to liberate hydrogen, reacts with bases to form salts, and promotes chemical reactions.

The more concentrated the buffer solution, the greater its buffer capacity.

If the buffer capacity is 10 times larger, then the buffer solution can absorb 10 times more strong acid or base before undergoing a significant change in pH.

Hence, we need to take this into consideration when increasing either the acid or base concentration in order to increase the buffering capacity of a solution.

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Answer:

A.The sound becomes louder.

And

C.The sound waves get further.

Explanation:

Louder the sound it will travel long.

Answer:

1.sea water 2.fresh water 3. Salt and ice

4.salted roads 5. Sugar solution used for making candy

Explanation:

Because Truck

Answer:

salted roads

sugar something

pure water

Explanation:

trust me bro

Answer:Ammonia is a compound that contains one nitrogen atom and three hydrogen atoms. Ordinarily having a characteristic of a pungent and gaseous compound.

Elemet: Hydrogen, Symbol: H, # of Atoms:5

Elemet:Nitrogen, Symbol: N, # of Atoms:1

Elemet:Oxygen, Symbol: O, #of Atoms:1

Explanation:

The number of  atoms presennt in one mole of ammonium hydroxide is 6.02 * 10^23 atoms.

The mole refers to the amount of a substance that can be used as a reference. According to Avogadro, one mole of a substance contains 6.02 * 10^23 atoms, molecules, ions etc.

In that case, we can say that the number of  atoms presennt in one mole of ammonium hydroxide is 6.02 * 10^23 atoms.

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Answer:

[tex]\color{Blue}\huge\boxed{Question} [/tex]

[tex]\color{Blue}\huge\boxed{Answer} [/tex]

Answer:

d

Explanation:

wave a and b clashing constructively would make c a bigger wave and clashing destructively would make d a smaller wave, which they are.

Answer:

d

Explanation:

I think it's true.

Explanation:

Muscles move bones through contracting and relaxing

Answer: acid

Explanation:

Answer:

A) Acid

Explanation:

I got the same question and answered correctly

Answer:

see explanations

Explanation:

a. The central atom bonded to four substituent atoms and having no lone pair.

This is an AX₄ geometry => tetrahedron

b. The central atom bonded to three substituent atoms and having one lone pair.

This is an AX₃E geometry => pyramidal

c. The central atom bonded to two substituent atoms ảnd having

one lone pair.

This is an AX₂E geometry => bent angular

d. The central atom bonded to two substituent atoms and having no lone pair.

This is an AX₂ geometry => linear

_______________________________

Based upon the VSEPR Theory there are 6 parent geometry configurations and associated derived geometries.

Parent geometries  => Derivatives => Examples

For graphic images of each geometry do an internet search for 'molecular geometry'.

Answer:

Its a punnet square

Explanation:

These questions all involve special cases of the ideal gas law, namely Boyle's, Charles', and Gay-Lussac's Laws. The ideal gas law relates together the absolute pressure (P), volume (V), the absolute temperature (T), and number of moles (n) of a gas by the following:

PV = nRT

where R is the universal gas constant.

The special cases of the ideal gas law are obtained by holding constant all but two of the variables of a gas.

Boyle's Law relates the pressure and volume of a given mass of gas at a constant temperature: PV = k or P₁V₁ = P₂V₂.

Charles' Law relates the volume and temperature of a given mass of gas at a constant pressure: V/T = k or V₁/T₁ = V₂/T₂.

Gay-Lussac's Law relates the pressure and temperature of a given mass of gas at a constant volume: P/T = k or P₁/T₁ = P₂/T₂.

Depending on what we're given and instructed to find in each question, we can figure out which law to use.

---

Question 2:

We are given the volume of a gas at some pressure, and we're to find the new volume of the gas at a different pressure. Here, we use Boyle's Law: P₁V₁ = P₂V₂ where P₁ = 60 atm, V₁ = 20.0 L, and P₂ = 30 atm. We want to find V₂, which we can determine by rearranging the equation into the form V₂ = P₁V₁/P₂. Note that pressure and volume are inversely related according to Boyle's Law; since we're decreasing the pressure, the new volume of the gas should be greater than the initial volume of 20.0 L.

V₂ = (60 atm)(20.0 L)/(30.0 atm) = 40.0 L.

So, at 30 atm, the balloon will have a volume of 40.0 L.

---

Question 3:

This is another Boyle's Law question. The standard pressure (our initial pressure) is 1 atm. Here, we are decreasing the volume of the gas, and we want to find the new pressure; the pressure of the gas should thus increase proportionally (the pressure will be greater than 1 atm). Rearranging Boyle's Law to solve for P₂, we get P₂ = P₁V₁/V₂.

P₂ = (1 atm)(8.00 L)/(3 L) = 2.67 atm.

So, the new pressure of the gas is 2.67 atm (or 3 atm if we're considering V₂ to comprise one significant figure).

---

Question 4:

Here, we are increasing the temperature of a gas at a known pressure, and we want to determine what the new pressure will be. This is a Gay-Lussac's Law question; from the law, we see that pressure and temperature are directly proportional. Since we're increasing the temperature of the gas, we should expect the pressure of the gas to be greater than the initial 200 atm. Gay-Lussac's Law rearranged to solve for P₂ gives us P₂ = P₁T₂/T₁. When working with gas laws, temperatures must be in Kelvin (°C + 273.15 = K). So, T₁ = 300.15 K, T₂ = 350.15 K, and P₁ = 200 atm.

P₂ = (200 atm)(350.15 K)/(300.15 K) = 233 atm.

So, if the temperature is increased from 27 to 77 °C, the pressure of the gas in the tennis ball will be 233 atm. Here, it's ambiguous how many sig figs to use; if we use one sig fig per P₁, then our P₂ would equal P₁, which I think would be an absurd for a question to ask for. I would stick with either 233 atm or 230 atm (following the two sig figs of the temperatures), or you may go with however you've been instructed.

---

Question 5:

This is a Charles' Law question; we're looking for the new volume of a gas when the temperature of the gas is increased. As was the case in Gay-Lussac's Law, the two parameters in Charles' Law—volume and temperature—are directly proportional. Since the temperature of the gas is increased, we should expect the new volume of the gas to also increase (V₂ will be greater than 5.00 L). Temperatures should be in Kelvin.

V₂ = V₁T₂/T₁ = (5.00 L)(300.15 K)/(250.15 K) = 5.99 L.

---

Question 6:

Another Charles' Law question. As with question 5, we want to find the new volume of the gas after a change in temperature. This time, the final temperature is lower than the initial temperature, so we should expect that V₂ will be less than the initial 0.5 L. Again, temperatures in Kelvin.

V₂ = V₁T₂/T₁ = (0.5 L)(313.15 K)/(493.15 K) = 0.317 L.

So, the volume of the balloon when it is fully cooled by your refrigerator will be 0.317 L.

---

Question 7:

This is yet another Charles' Law question, and, again, we are solving for V₂ after a change in temperature. Since the final temperature is greater than the initial temperature, V₂ should be greater than 2.2 L. Again, the temperatures should be in Kelvin.

V₂ = V₁T₂/T₁ = (2.2 L)(653.15 K)/(453.15 K) = 3.17 L.

The new volume of the gas is 3.17 L ≈ 3.2 L (two sig figs).

---

Question 8:

We return to Gay-Lussac's Law here; pressure and temperature are directly proportional, and the temperature of the gas is increased. Thus, P₂ should be greater than 3 atm. Again, remember that temperatures must be in Kelvin.

P₂ = P₁T₂/T₁ = (3 atm)(298.15 K)/(288.15 K) = 3.1 atm.

So, the pressure inside the can after the temperature rise is 3.1 atm. Not a big increase, but an increase nonetheless.

Answer:

The elements in Group 1 (lithium, sodium, potassium, rubidium, cesium, and francium) are called the alkali metals. All of the alkali metals have a single s electron in their outermost principal energy. ... For example, the electron configuration of lithium (Li), the alkali metal of Period 2, is 1s22s1.

Answer:

they have a mono positive charge of +1

Explanation:

this is due to having one electron in their outermost ns orbital

Answer:

[tex]from \: the \: equation \\ 1 \: moles \: of \: propane \: produce \: 4 \: moles \: of \: water \\ 2.50 \:moles \: of \: propane \: will \: produce \: ( \frac{(2.50 \times 4)}{1} ) \: moles \\ = 10 \: moles \: of \: water[/tex]