Write the equation of the line parallel to the line and passing through the point.
y=x+5, (8, 1)

Based on the information given, the value of the two numbers will be 2 and 1 respectively.

The equation to solve the question will be:

7a + 8b = 22 .... i

5a + 8b = 18 ..... ii

Subtract equation ii from I

2a= 4

a = 4/2

a = 2

Therefore, 7a + 8b = 22

7(2) + 8b = 22

14 + 8b = 22

8b = 22 - 14.

8b = 8

b = 8/8 = 1

Therefore, the numbers are 2 and 1.

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Work Shown:

7.5% = (7.5)/100 = 0.075

7.5% of $1580 = 0.075*1580 = 118.50

Answer:

c

Step-by-step explanation:

I think that is the answer

Answer:

c

Step-by-step explanation:

it is equal to.

Answer:

slope: 4/12

Simplified to: 1/3

Negative slope so: -1/3

Y intercept:4

Form: Y=mx+b

Y=-1/3x+4

1. 5

2.2

3.2,5

4.2,5

5.2

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Answer:

-2

Step-by-step explanation:

-4x-2x ≤ 17-5

-6x ≤ 12 | /(-6)

x ≥ -2

Answer:

-4[tex]\frac{1}{2}[/tex]

Step-by-step explanation:

I hope this helps!

Answer:

0.75 and 10.00

Step-by-step explanation:

Answer:

The graph moved down 5 units

Step-by-step explanation:

Answer:

Step-by-step explanation:

The best way to get an answer to this question is to study the graph you get when you study the result from Desmos, which is a free  graphing program.

Notice the way the graph is laid out. If the graph was simply y = x^2 - 6x  then the y value for the minimum value would be x = 3 (just like the 2 values you do get) and y = -9

But y = x^2 - 6x + 3 has you moving up 3 units to y = - 6 and y = x^2 - 6x + 8 moves you to y = - 1. Which way are you going? The difference is 5 units and you are moving down because you start  at y = x^2 - 6x + 8 and move down to x^2 - 6x + 3.

Without finding minimums (which is a cumbersome process which needs to be done twice) there's no easy way to do this except graphing.

The answer is B.

Answer:

5:13

Step-by-step explanation:

The total number of students = 5+8 = 13

Answer: A) y = x + 3

Step-by-step explanation:

Use two points given in the table and plug them into slope-intercept form y = mx + b.

In order to solve for m, the slope, by plugging them into  [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex].

(0, 3) (2, 5)

[tex]\frac{5-3}{2-0}[/tex] = [tex]\frac{2}{2}[/tex] = 1

Use one of the points and plug it into the slope-intercept form y = mx + b.

3 = 1(0) + b

3 = 0 + b

3 = b

The linear equation to the table would be y = x + 3.

Answer:

4, 2, 1, 1

Step-by-step explanation:

Answer:

$14

Step-by-step explanation:

We can make an equation

30%. . . . . .X

--------- = ---------

100. . . . . . .20

Now we cross multiply

100x = 600

x = 6

Now we subtract to find how much we will take home.

20 - 6 = $14 every hour will be made

Variance is the exact average deviation of data values from the mean in squared units and the Standard deviation of data values from the mean in regular units.

Variance is a statistical measure of the dispersion of numbers in a data collection. Variance estimates how much more each number in the set deviates from the mean, and from each and every other number in the set.

The variance is a measure of the degree of variability. It is determined by averaging the squared deviations out of the mean.

The greater the spread of the data, the greater the variance in proportion to the mean.

The standard deviation is determined as the square root of variance by calculating the departure of each data point from the mean. The standard deviation represents the average level of variation in your dataset. It informs you how far each number deviates from the mean on average.

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make two pair of line segment of PQ andQP and construct use of a scale and the parallel line give the point name

Answer:

Step-by-step explanation:

sinθ < 0 means below the x axis

cotθ = cosθ/sinθ < 0

As sinθ  is already < 0 means cosθ has to be > 0 meaning right of the y axis.

Right of y and below x is the IV quadrant.

The quadrant in which angle theta lie if sin theta < 0 and cot theta < 0 exists Quadrant IV (4).

Trigonometric Identities are equality conditions that hold for all possible values of the variables in the equation and use trigonometry functions. There exists numerous unique trigonometric identities that relate a triangle's side length and angle.

here, we have,

Sine, cosine, and tangent are the fundamental three operations in trigonometry. The cotangent, secant, and cosecant functions are derived from these three basic functions. On these functions, all trigonometrical notions exists built.

Trigonometric identities are equality conditions in trigonometry that hold for all values of the variables that appear and are defined on both sides of the equivalence. These exists identities that, geometrically speaking, involve certain functions of one or more angles.

we have,

sinθ < 0 means below the x axis

cotθ = cosθ/sinθ < 0

As sinθ  is already < 0 means cosθ has to be > 0 meaning right of the y axis.

Right of y and below x is the IV quadrant.

Hence, The quadrant in which angle theta lie if sin theta < 0 and cot theta < 0 exists Quadrant IV (4).

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Answer:

Yes, what is your question

Step-by-step explanation:

Answer:

yes what is your question

Answer:

When you explain the problem, it makes it easier to understand how you solved it.​

I hope this helped at all.

Answer:

B: 8

Step-by-step explanation:

When you add a negative number, it means you subtract that number.

[tex]17+-9=17-9=8[/tex]

Step-by-step explanation:

Alrighty! here you go image.

Answer:x=15

Step-by-step explanation:

Answer:

Step-by-step explanation:

−2x − 4 = −6

−2x − 4 + 4 = −6 + 4

−2x = −2

−2x/-2 = −2/-2

x = 1

The equation is,

→ -2x - 4 = -6

Let's solve for the value of x,

→ -2x - 4 = -6

→ -2x = -6 + 4

→ x = (-2)/(-2)

→ x = 2/2

→ [ x = 1 ]

Thus, the value of x is 1.

The perimeter of the rectangle is the sum of its dimensions

The dimensions that minimize the perimeter are [tex]\mathbf{10\sqrt{10 },10\sqrt{10 }}[/tex]

The area is given as:

[tex]\mathbf{A = 1000}[/tex]

Let the dimension be x and y.

So, we have:

[tex]\mathbf{A = xy = 1000}[/tex]

Make x the subject

[tex]\mathbf{x = \frac{1000}{y}}[/tex]

The perimeter is calculated as:

[tex]\mathbf{P = 2(x + y)}[/tex]

Substitute [tex]\mathbf{x = \frac{1000}{y}}[/tex]

[tex]\mathbf{P = 2(\frac{1000}{y} + y)}[/tex]

Expand

[tex]\mathbf{P = \frac{2000}{y} + 2y}[/tex]

Differentiate

[tex]\mathbf{P' = -\frac{2000}{y^2} + 2}[/tex]

Set to 0

[tex]\mathbf{ -\frac{2000}{y^2} + 2 = 0}[/tex]

Rewrite as:

[tex]\mathbf{ -\frac{2000}{y^2} = -2}[/tex]

Divide both sides by -1

[tex]\mathbf{\frac{2000}{y^2} = 2}[/tex]

Multiply y^2

[tex]\mathbf{2000 = 2y^2}[/tex]

Divide by 2

[tex]\mathbf{1000 = y^2}[/tex]

Take square roots of both sides

[tex]\mathbf{y = \sqrt{1000 }}[/tex]

[tex]\mathbf{y = 10\sqrt{10 }}[/tex]

Substitute [tex]\mathbf{y = \sqrt{1000 }}[/tex] in [tex]\mathbf{x = \frac{1000}{y}}[/tex]

[tex]\mathbf{x = \frac{1000}{\sqrt{1000}}}[/tex]

[tex]\mathbf{x = \sqrt{1000}}[/tex]

[tex]\mathbf{x = 10\sqrt{10 }}[/tex]

Hence, the dimensions that minimize the perimeter are [tex]\mathbf{10\sqrt{10 },10\sqrt{10 }}[/tex]

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Answer: 37

Cross multiply 100x29 over 79

Answer:

It took eight hours to travel 520km

Step-by-step explanation:

Answer:

0.2

Step-by-step explanation:

30: 1

6:?

cross multiply

(6*1)/30

ans:0.2cm

Answer:

the answer is

5.6 I think