1.
The capacity of 1 jug is the same as the total capacity of 6 similar glasses. 10. 36 litres of
water is needed to fill 3 jugs and 19 glasses. What is the capacity of one glass?
10​

If a time capsule has been buried 98m away from the cave at a bearing of 312. the time capsule is buried about 82.2 meters west of the cave.

To find how far west the time capsule is buried, we need to find the horizontal component of the displacement vector that points from the cave to the location of the time capsule. We can use trigonometry to do this:

cos(312°) = adjacent/hypotenuse

The hypotenuse is the distance between the cave and the time capsule, which is 98m. The adjacent side represents the horizontal distance between the two points, which is what we want to find. Rearranging the equation, we get:

adjacent = cos(312°) x hypotenuse

adjacent = cos(312°) x 98

adjacent ≈ 82.2

Therefore, the time capsule is buried about 82.2 meters west of the cave.

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Jane's closet space decreased by approximately 38.97%.

To find the percentage decrease of Jane's closet space, we need to first calculate the amount of decrease and then express it as a percentage of the original value.

The amount of decrease is the difference between the original closet space and the new closet space:

Decrease = Original closet space - New closet space

Decrease = 78 - 47.58

Decrease = 30.42

So Jane's closet space decreased by 30.42 square feet.

To express this decrease as a percentage of the original value, we use the following formula:

Percentage decrease = (Decrease / Original value) x 100%

Substituting the values, we get:

Percentage decrease = (30.42 / 78) x 100%

Percentage decrease ≈ 38.97%

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The average wage for receptionists in this group is $11.60

It's important to note that "average wage" can be calculated in a few different ways, such as mean, median, and mode. Mean is the sum of all wages divided by the number of individuals, while median is the middle value in a range of wages. Depending on which method is used, the average wage figure can vary.

The table of hourly wages for receptionists working for various companies, the average wage for receptionists in this group will be:

= $58 / 5

= $11.60

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The cost of fencing for the semicircular statuary garden is $651.99.

Finding the circumference of the full circle:
C = πd, where d is the diameter.
C = 3.14 × 26
C ≈ 81.64 feet

Since it's a semicircular garden, dividing the circumference by 2:
Semi-circular perimeter = 81.64 ÷ 2
Semi-circular perimeter ≈ 40.82 feet

Now, Adding the diameter to the semi-circular perimeter to get the total fence length:
Total fence length = 40.82 + 26
Total fence length ≈ 66.82 feet

Then, Calculating the total cost of fencing:
Cost = Total fence length × Cost per linear foot
Cost = 66.82 × $9.75
Cost ≈ $651.99

So, the cost of fencing the semicircular statuary garden will be approximately $651.99.

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Using the fundamental counting principle, there are 20 possible outcomes for the fitness tracker, considering its battery life and color options.

To find the total number of possible outcomes for the given criteria, we can use the fundamental counting principle. This principle states that if there are m ways to perform one task and n ways to perform another task, then there are m x n ways to perform both tasks together.

In this case, we have 4 options for battery life (1 day, 3 days, 5 days, and 7 days) and 4 options for color (silver, green, blue, pink, and black). Using the fundamental counting principle, we can multiply the number of options for battery life by the number of options for color to find the total number of possible outcomes:

4 options for battery life x 5 options for color = 20 possible outcomes.

Therefore, there are 20 possible combinations of battery life and color for a fitness tracker.

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When the radius is 6cm, the rate at which the area of the circle is increasing is 60π cm^2/sec.

To find the rate at which the area of the circle is increasing, we need to use the formula for the area of a circle: A = πr^2. We can differentiate both sides of this equation with respect to time to get:

dA/dt = 2πr(dr/dt)

where dA/dt is the rate at which the area of the circle is increasing, dr/dt is the rate at which the radius is increasing (which we know is 5cm/sec), and r is the current radius of the circle.

So, when the radius is 6cm, we have:

r = 6cm
dr/dt = 5cm/sec

Plugging these values into the formula above, we get:

dA/dt = 2π(6cm)(5cm/sec)
dA/dt = 60π cm^2/sec

Therefore, when the radius is 6cm, the rate at which the area of the circle is increasing is 60π cm^2/sec.

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Answer:

225

Step-by-step explanation:

since the ratio is 4 to 5 and the number of union workers are 100 you divide the number of union workers by their respective ratio which is four then multiply that by the 5

Emma should choose A. Wednesday to maximize the probability that both managers will be available.

A. Wednesday. The probability that both managers will be available is 0.74.

To calculate this, multiply the probabilities of each manager's availability for each day:

- Monday: Manager A (0.82) x Manager B (0.88) = 0.7216
- Wednesday: Manager A (0.87) x Manager B (0.85) = 0.7395

Since 0.7395 (Wednesday) is higher than 0.7216 (Monday), Emma should choose Wednesday to maximize the probability that both managers will be available.

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2 cos x - 1 = 0, cos x = 1/2, and x = π/3 or 5π/3. These are the critical numbers of g(x) on (0,7). the absolute maximum value of g(x) on (0,7) is √3 - π/3 and the absolute minimum value is -√3 - 5π/3.

To find the critical numbers for g(x) = 2sin(r) - r on the interval (0, 7), follow these steps:
1. Find the derivative of g(x): g'(x) = 2cos(r) - 1
2. Set the derivative equal to zero: 2cos(r) - 1 = 0
3. Solve for r: r = cos^(-1)(1/2)
Now, find the absolute maximum and minimum values for g(x) on the interval (0, 7):
1. Evaluate g(x) at the critical numbers: g(cos^(-1)(1/2)) = 2sin(cos^(-1)(1/2)) - cos^(-1)(1/2)
2. Evaluate g(x) at the endpoints of the interval: g(0) = 2sin(0) - 0, g(7) = 2sin(7) - 7
3. Compare the values from steps 1 and 2 to find the maximum and minimum values.
The critical numbers for g(x) = 2sin(r) - r on the interval (0, 7) are r = cos^(-1)(1/2). The absolute maximum and minimum values for g(x) on the interval (0, 7) can be found by comparing g(cos^(-1)(1/2)), g(0), and g(7).

To find the critical numbers of g(x) = 2 sin x - x on (0,7), we first need to find its derivative:
g'(x) = 2 cos x - 1
Setting g'(x) = 0, we get:
2 cos x - 1 = 0
cos x = 1/2
x = π/3 or 5π/3
These are the critical numbers of g(x) on (0,7).

To find the absolute maximum and minimum values of g(x) on (0,7), we need to evaluate g(x) at the critical numbers and at the endpoints of the interval (0,7).
g(0) = 0
g(π/3) = 2 sin(π/3) - π/3 = √3 - π/3
g(5π/3) = 2 sin(5π/3) - 5π/3 = -√3 - 5π/3
g(7) = 2 sin(7) - 7
To determine the absolute maximum and minimum values, we compare these values:
The absolute maximum value is √3 - π/3, which occurs at x = π/3.
The absolute minimum value is -√3 - 5π/3, which occurs at x = 5π/3.
Therefore, the absolute maximum value of g(x) on (0,7) is √3 - π/3 and the absolute minimum value is -√3 - 5π/3.

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For function f(x,y) = x² e^{3xy} ,  fx = 2xe^{3xy} + 3x²y e^{3xy}, fy = 3x² e^{3xy}

The given function is f(x,y) = x² e^{3xy}.

To find the partial derivatives of f(x,y) with respect to x and y,

we differentiate the function with respect to each variable while treating the other variable as a constant.

To find fx, we differentiate the function f(x,y) with respect to x while treating y as a constant.

The derivative of x² is 2x, and the derivative of e^{3xy} is e^{3xy} times the derivative of 3xy with respect to x, which is 3y.

Therefore, we get:

fx = (d/dx)(x² e^{3xy}) = 2xe^{3xy} + 3x²y e^{3xy}

To find fy,

we differentiate the function f(x,y) with respect to y while treating x as a constant.

The derivative of e^{3xy} with respect to y is e^{3xy} times the derivative of 3xy with respect to y, which is 3x². Therefore, we get:

fy = (d/dy)(x² e^{3xy}) = 3x² e^{3xy}

Hence, the partial derivatives of f(x,y) are fx = 2xe^{3xy} + 3x^2y e^{3xy} and fy = 3x² e^{3xy}.

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To find the Laplace transform of f(t), we use the formula:

L{f(t)} = ∫[0,∞) [tex]e^(-st)[/tex] f(t) dt

where L{f(t)} denotes the Laplace transform of f(t) and u(t) is the unit step function.

Using the linearity of the Laplace transform, we can find the Laplace transform of each term separately and add them up.

L{6u(t-2)} = [tex]6e^(-2s)[/tex] / s (applying the time-shift property)

L{3u(t-5)} = [tex]3e^(-5s)[/tex] / s (applying the time-shift property)

L{-4u(t-6)} = -[tex]4e^(-6s[/tex]) / s (applying the time-shift property)

Therefore, the Laplace transform of f(t) is:

F(s) = L{f(t)} = 6[tex]e^(-2s)[/tex] / s + [tex]3e^(-5s)[/tex] / s - [tex]4e^(-6s)[/tex]/ s

= [tex](6e^(-2s) + 3e^(-5s) - 4e^(-6s)) / s[/tex]

Hence, the Laplace transform of f(t) is F(s) = [tex](6e^(-2s) + 3e^(-5s) - 4e^(-6s)) / s.[/tex]

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If length of rectangle is 5 more than twice it's width and having perimeter as 88 feet, then the dimensions of the rectangle are, length is 31 feet, width is 13 feet.

Let width of the rectangle be represented as = "w" feet.

It is given that, the length of rectangle is 5 more than twice it's width,

So, Length can be represented as "2w + 5" in feet;

We use formula for perimeter of rectangle, which is "P = 2Length + 2Width", where P = perimeter, L = length, and W = width.

In this case, we know that the perimeter is 88 feet, so we substitute the values,

We get,

⇒ 88 = 2(2w + 5) + 2w;

⇒ 88 = 4w + 10 + 2w,

⇒ 88 = 6w + 10,

⇒ 78 = 6w,

⇒ w = 13,

So the width is 13 feet. We use this value of width to find length of the rectangle:

⇒ L = 2w + 5,

⇒ L = 2(13) + 5,

⇒ L = 31

Therefore, the dimensions of the rectangle are 31 feet by 13 feet.

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Based on the inequality, 24.5x > 162 + 4.25x, Trina must sell more than 8 units of the handmade vases to make a profit.

Inequality refers to a mathematical statement that two or more algebraic expressions are unequal or inequivalent.

Mathematically, inequalities are depicted as:

Selling price per handmade vase = $24.50

Variable cost per unit = $4.25

Fixed selling cost = $162

Let the number of vases to sell to make a profit = x

The total sales revenue = 24.5x

The total cost = 162 + 4.25x

To make a profit, 24.5x must be greater than 162 + 4.25x.

24.5x > 162 + 4.25x

20.25x > 162

x > 8

Check:

Total sales revenue = $196 ($24.5(8)

Total cost = $196 ($162 + $4.25(8)

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Answer:41,160 meters in 2 minutes at the speed of 343 meters per second.

Step-by-step explanation:

The speed of sound varies depending on the medium it's traveling through, but assuming you meant the speed of sound in air at room temperature, it's approximately 343 meters per second.

To find out how far sound will travel in 2 minutes (120 seconds), we can simply multiply the speed of sound by the time:

Distance = Speed x Time

Distance = 343 m/s x 120 s

Distance = 41,160 meters

Therefore, sound will travel approximately 41,160 meters in 2 minutes at the speed of 343 meters per second.

Pythagorean Theorem: a^2 + b^2 = c^2

---a and b are the legs of the triangle

---c is the hypotenuse/diagonal

a = 6

b = 1

c = ?

(6)^2 + (1)^2 = c^2

36 + 1 = c^2

37 = c^2

c = 6.0827

c (rounded) = 6.1

Answer = 6.1 meters

The students will need $74 on the third day.

Let x be the cost of one item at Store A and y be the cost of one item at Store B. Then the system of equations to model the situation is:

4x + 7y = 30
3x + 5y = 22

To find the cost on Day 3, we need to solve for x and y, and then use those values to calculate:

10x + 17y = ?

Part B: Solve the system of equations to find x and y
To solve the system of equations, we can use elimination or substitution. Here, we'll use substitution.

From the first equation, we can solve for x:

4x + 7y = 30
4x = 30 - 7y
x = (30 - 7y)/4

Substitute this expression for x into the second equation:

3x + 5y = 22
3((30 - 7y)/4) + 5y = 22
(90 - 21y)/4 + 5y = 22
90 - 21y + 20y = 88
-y = -2
y = 2

Now that we know y = 2, we can substitute this value back into either equation to find x:

4x + 7y = 30
4x + 7(2) = 30
4x + 14 = 30
4x = 16
x = 4

So x = 4 and y = 2.

Part C: Calculate the amount of money needed on Day 3
Finally, we can use these values to calculate the amount of money needed on Day 3:

10x + 17y = 10(4) + 17(2) = 40 + 34 = 74

Therefore, the students will need $74 on the third day.

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Ruben painted a total area of [tex]130.5 square feet.[/tex]

To determine the total area that Ruben painted, we need to find the area

of each wall and then add them together. Since the dimensions of the

walls are given in different units (yards and feet), we will first need to

convert them to a common unit.The first wall is 3 1/2 yards long by 9 feet

tall, which is equivalent to 10 1/2 feet long by 9 feet tall (since 1 yard = 3

feet).

The area of this wall is:

[tex]10 1/2 feet * 9 feet = 94.5 square feet[/tex]

The second two walls are each 4 feet tall by 1 1/2 yards long, which is

equivalent to 4 feet tall by 4.5 feet long (since 1 yard = 3 feet).

The area of each of these walls is:

[tex]4 feet* 4.5 feet = 18 square feet[/tex]

Since Ruben painted one coat on each wall, the total area he painted is:

[tex]94.5 square feet + 2 * 18 square feet = 130.5 square feet[/tex]

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The value of X and y when substitution method is used to solve the given quadratic equation would be = 8 and 2 respectively.

The equations that are given is listed below:

X - 3y = 2 ---> equation 1

2x - 6y = 6 ----> equation 2

In equation 1, make X the subject of formula;

X = 2 + 3y

Substitute X = 2 + 3y into equation 2,

2( 2 + 3y) - 6y = 6

4 + 6y - 6y = 6

y = 6-4

y = 2

Substitute y = 2 into equation 1;

x - 3(2) = 2

X = 2 + 6

X= 8

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(a)The position function is:x(t) = -sin(t) + t + 5

To find the velocity function, we need to integrate the acceleration function:

v(t) = ∫ a(t) dt = -cos(t) + C1

We know that the particle is initially at rest, so v(0) = 0:

0 = -cos(0) + C1
C1 = 1

Therefore, the velocity function is:

v(t) = -cos(t) + 1

To find the position function, we need to integrate the velocity function:

x(t) = ∫ v(t) dt = -sin(t) + t + C2

Using the initial position x(0) = 5, we can find C2:

5 = -sin(0) + 0 + C2
C2 = 5

Therefore, the position function is:

x(t) = -sin(t) + t + 5

(b) The particle is at rest when its velocity is zero. So we need to solve for t when v(t) = 0:

0 = -cos(t) + 1

cos(t) = 1

t = 2πn, where n is an integer.

Therefore, the particle is at rest at times t = 2πn, where n is an integer.

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Answer 1: Together, Streetcar and Cable Car are the preferred transportation for 168 residents.

The circle graph shows the percentage of residents who prefer each transportation method, and the total sample size is 400.

For streetcar, (15/100) x 400 = 60 residents prefer it, and for cable car, (27/100) x 400 = 108 residents prefer it.

Together, Streetcar and Cable Car are the preferred transportation for 60 + 108 = 168 residents.

Answer 2: The median is the best measure of center, and it equals 19.

The box plot shows the distribution of the number of tickets sold for a school dance.

The median is the middle value of the data when arranged in order, and it is represented by the line in the box. In this case, the median is 19. The mean, on the other hand, can be influenced by extreme values, and we cannot determine it from the box plot alone.

Answer 3: Median, because Sunny Town is skewed.

When comparing the data, we need to consider the measure of center that is less affected by extreme values, and that is the median.

The median is the middle value of the data when arranged in order. The histogram for Sunny Town is skewed to the right, which means that there are some very high values that are affecting the mean.

Therefore, the median is the better measure of center to determine which location typically has the cooler temperature.

Answer 4: The IQR of 13 is the most accurate to use, since the data is skewed.

The histogram shows the frequency of donations received by a charity, and the data is skewed to the right.

The IQR (Interquartile Range) is the difference between the third quartile (Q3) and the first quartile (Q1), which represents the middle 50% of the data.

The IQR is less sensitive to extreme values and is a better measure of variability for skewed data. In this case, the IQR is 49 - 42 = 7, which is the most accurate measure of variability to use.

Answer 5: There were about 15 principals in attendance.

In the exhibit room, out of 80 people, 15 are principals.

We can assume that the proportion of principals in the exhibit room is the same as the proportion of principals in the conference.

Therefore, the estimated number of principals in the conference is (15/80) x 900 = 168.75, which is approximately 169.

Answer 6: Histogram

The teacher wants to represent the subject preferences of 100 students. A histogram would be the best graphical representation to use because it shows the frequency distribution of a continuous variable, which in this case could be the number of students who prefer each subject.

A stem-and-leaf plot is used for small datasets, and a box plot is used to display the distribution of a continuous variable across categories. A circle graph is more appropriate for displaying categorical data, such as the percentage of students who prefer each subject.

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X represents the number of basketballs in Chris's gym class.

Chris represents the number of students in his gym class with the expression 4x + 2. We know that the number of students is four times the number of basketballs, so we can set up the equation 4x = the number of basketballs.

If we substitute this expression for the number of students in the gym class, we get 4(4x) + 2 = the total number of students in the gym class and locker room. We also know that there are two more students in the locker room, so we can add 2 to this expression to get 4(4x) + 4 = the total number of students in the gym class and locker room.

Now we can set this expression equal to the original expression for the number of students, 4x + 2, and solve for x:

4(4x) + 4 = 4x + 2

16x + 4 = 4x + 2

12x = -2

x = -1/6

However, x cannot represent a negative number of basketballs, so there must be an error in the problem.

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Maria's average quiz score is 9.6.

B. The standard deviation of her quizzes is approximately 0.5 (rounded to the nearest tenth).

(a) The average of Maria's quizzes can be found by adding up all her scores and dividing by the total number of quizzes:

Average = (10 + 9 + 10 + 9 + 10) / 5 = 9.6

Therefore, Maria's average quiz score is 9.6.

(b) To calculate the standard deviation of her quizzes, we first need to find the variance. We can do this by finding the average of the squared differences between each score and the mean:

[(10 - 9.6)² + (9 - 9.6)² + (10 - 9.6)² + (9 - 9.6)² + (10 - 9.6)²] / 5 = 0.24

So the variance is 0.24. To find the standard deviation, we take the square root of the variance:

√0.24 ≈ 0.5

So the standard deviation of her quizzes is approximately 0.5 (rounded to the nearest tenth).

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The value of integral ∫(x^2+10x-9)e^-4x dx is  (-1/4)(x^2+10x-9)e^-4x - (1/8)(x+5)e^-4x - (1/32)e^-4x + C.

To evaluate the integral ∫(x^2+10x-9)e^-4x dx using integration by parts, we need to choose two functions to multiply together, one of which we differentiate and the other we integrate. A common choice is to let u = x^2+10x-9 and dv = e^-4x dx, which gives du = (2x+10) dx and v = (-1/4)e^-4x.

Using the formula for integration by parts, we have:

∫(x^2+10x-9)e^-4x dx = uv - ∫v du

= (-1/4)(x^2+10x-9)e^-4x - ∫(-1/4)(2x+10)e^-4x dx

= (-1/4)(x^2+10x-9)e^-4x + (1/2)∫(x+5)e^-4x dx.

Now we can use integration by substitution to evaluate the second integral on the right-hand side:

(1/2)∫(x+5)e^-4x dx = (-1/8)(x+5)e^-4x - (1/32)e^-4x + C,

where C is the constant of integration.

Substituting this back into our previous equation, we get:

∫(x^2+10x-9)e^-4x dx = (-1/4)(x^2+10x-9)e^-4x - (1/8)(x+5)e^-4x - (1/32)e^-4x + C.

Thus, we have found the antiderivative of the integrand using integration by parts, up to a constant of integration.

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Complete question is:

Use integration by parts to evaluate the integral: ∫(x^2+ 10x – 9)e ^-4x dx

The probability model for choosing a marble from the box is P(green) = 36/50 and P(blue) = 14/50.

To create this probability model, first, count the total number of marbles chosen, which is 50. Then, count the number of green and blue marbles chosen, which are 36 and 14, respectively.

Divide the number of each color by the total number of marbles to find the probability of choosing a green or blue marble.

P(green) is calculated as 36/50 or 0.72, and P(blue) is calculated as 14/50 or 0.28. This model represents the likelihood of choosing a green or blue marble from the box based on Yosef's experiment.

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Answer:

Step-by-step explanation:

50.24n2

Answer:

The radius of the circle is 5/√2 = (5√2)/2 inches.

Area of circle = π((5√2)/2)^2

= 25π/2 square inches

Area of triangle = (1/2)(5√2)((5√2)/2)

= 25/2 square inches

Area of shaded region

= (25/2)(π - 1) = 26.77 square inches

y=3/14(x-5)(+10)

Step-by-step explanation:

.........................

The function has a horizontal asymptote at y = 3. Other types of discontinuities can also occur in rational functions

A polynomial is a mathematical expression that consists of variables and coefficients, which are combined using arithmetic operations such as addition, subtraction, multiplication, and non-negative integer exponents.

A rational function can have a discontinuity at any point where the denominator of the function becomes zero since division by zero is undefined. These points are called "vertical asymptotes."

For example, consider the rational function f(x) = (x² - 1) / (x - 1). The denominator becomes zero when x = 1, which causes a vertical asymptote at x = 1. At x = 1, the function approaches positive infinity from the left-hand side and negative infinity from the right-hand side. This creates a "hole" or a "removable discontinuity" in the graph of the function.

Another type of discontinuity that can occur in a rational function is a "horizontal asymptote." This occurs when the degree of the numerator is less than the degree of the denominator. In this case, the function approaches a horizontal line (the horizontal asymptote) as x approaches infinity or negative infinity.

For example, consider the rational function f(x) = (3x² - 2x + 1) / (x² + 1). As x approaches infinity or negative infinity, the function approaches the horizontal line y = 3.

Therefore, the function has a horizontal asymptote at y = 3.

Other types of discontinuities can also occur in rational functions, such as "slant asymptotes" or "oscillating behavior," but these are less common and typically require more advanced techniques to identify.

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The cardboard box with the largest volume can hold the greatest number of 1 in x 2 in x 4 in sponges.

To find the box with the largest volume, first determine the volume of each sponge: V_sponge = 1 in x 2 in x 4 in = 8 cubic inches. Next, find the volume of each box by multiplying its length, width, and height (V_box = L x W x H).

To determine how many sponges each box can hold, divide the volume of the box by the volume of the sponge (V_box / V_sponge). The box with the highest resulting quotient can hold the most 1 in x 2 in x 4 in sponges.

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The driver was driving at a speed of about 14 mi/h at the time of the skid. option is C. 14 mi/h

Using the formula s = √(30fd), where f is the coefficient of friction (0.7) and d is the length of the skid marks in feet (9), we can estimate the speed at the time of the skid:

s = √(30 × 0.7 × 9)

s ≈ 14.53 mi/h

Rounding to the nearest mi/h, the driver was driving at approximately 15 mi/h at the time of the skid. However, none of the given options match this result. The closest option is C. 14 mi/h, so I would choose that as the best available answer.

More on speed: https://brainly.com/question/13175601

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