2.
for the reaction c + 2h2 - ch4, how many grams of hydrogen are required
to produce 0.6 moles of methane, ch4 ?
cannu help em do the whole paper

Answers

Answer 1

1.21 grams of hydrogen are required to produce 0.6 moles of methane (CH₄) in the given reaction.

The given reaction is:

C + 2H₂ → CH₄

We can see that 2 moles of hydrogen (H₂) are required to produce 1 mole of methane (CH₄) according to the balanced chemical equation. Therefore, to produce 0.6 moles of methane, we will need 2 times as many moles of hydrogen, which is:

number of moles of hydrogen = 2 × number of moles of methane

number of moles of hydrogen = 2 × 0.6 moles

number of moles of hydrogen = 1.2 moles

To convert the number of moles of hydrogen to grams, we need to use the molar mass of hydrogen, which is approximately 1.008 g/mol. Thus, the mass of hydrogen required can be calculated as:

mass of hydrogen = number of moles of hydrogen × molar mass of hydrogen

mass of hydrogen = 1.2 moles × 1.008 g/mol

mass of hydrogen = 1.21 g

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The complete question is:

For the reaction C+2H₂ → CH₄, how many grams of hydrogen are required to produce 0.6 moles of methane, CH₄?


Related Questions

How much propane is used to produce 1000 grams of water

Answers

To produce 1000 grams of water, approximately 612.72 grams of propane are used in the combustion reaction.

To determine how much propane is used to produce 1000 grams of water, we must first understand the combustion reaction involving propane.

Propane (C3H8) is a hydrocarbon that undergoes combustion in the presence of oxygen (O2) to produce water (H2O) and carbon dioxide (CO2). The balanced chemical equation for this reaction is:

C3H8 + 5O2 → 3CO2 + 4H2O

From the balanced equation, we can see that 1 mole of propane (C3H8) produces 4 moles of water (H2O).

Next, we need to convert the mass of water (1000 grams) into moles, using the molar mass of water (18.015 g/mol):

1000 g H2O × (1 mol H2O / 18.015 g H2O) = 55.56 moles H2O

Now, using the stoichiometry from the balanced equation, we can find the moles of propane needed:

55.56 moles H2O × (1 mol C3H8 / 4 moles H2O) = 13.89 moles C3H8

Finally, we need to convert moles of propane into grams, using the molar mass of propane (44.097 g/mol):

13.89 moles C3H8 × (44.097 g C3H8 / 1 mol C3H8) = 612.72 grams

So, to produce 1000 grams of water, approximately 612.72 grams of propane are used in the combustion reaction.

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all chlorides, bromides, and iodides are soluble, except for the following ions.
Ag+ Hg2^2+ Pb^2+ Ca^2+ Sr^2+ Ba^2+ NH4+ alkali metals
There are no known exceptions

Answers

This statement refers to the solubility rules for ionic compounds in water. According to these rules, most chloride, bromide, and iodide compounds are soluble in water, meaning they can dissolve and form aqueous solutions.

However, there are some exceptions to this rule, and those exceptions involve the chloride, bromide, and iodide compounds of the ions Ag+, Hg2^2+, Pb^2+, Ca^2+, Sr^2+, Ba^2+, NH4+ and the alkali metals (Li+, Na+, K+, Rb+, Cs+). These compounds are generally insoluble in water, meaning they cannot dissolve and form aqueous solutions.

It is important to note that while these are general solubility rules, there may be some exceptions to them depending on the specific conditions of a given chemical system.

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If the molal concentration in water is the same for the following substances, rank these solutions in decreasing melting point. Highest placed in the rank will have the highest melting point.


calcium phosphate, Ca3(PO4)2


glucose, c6h12o6


sodium chloride, NaCl


magnesium chloride, MgCl2

Answers

The ranking of these solutions in decreasing melting point is: calcium phosphate > magnesium chloride > sodium chloride > glucose.

To rank the solutions with the same molal concentration in decreasing order of their melting points, we need to consider their van't Hoff factor (i), which represents the number of particles a solute dissociates into when dissolved in water. The formula to calculate the effect of a solute on the melting point of a solution is ΔTf = Kf × m × i, where Kf is the cryoscopic constant of water, m is the molality, and i is the van't Hoff factor.

Here are the van't Hoff factors for each substance:

1. Calcium phosphate, Ca₃(PO₄)₂: This substance dissociates into 5 ions (3 Ca²⁺ + 2 PO₄³⁻), so i = 5.
2. Glucose, C₆H₁₂O₆: This substance is a molecular compound and does not dissociate into ions, so i = 1.
3. Sodium chloride, NaCl: This substance dissociates into 2 ions (Na⁺ + Cl⁻), so i = 2.
4. Magnesium chloride, MgCl₂: This substance dissociates into 3 ions (Mg²⁺ + 2 Cl⁻), so i = 3.

Using the van't Hoff factor, we can rank the solutions in decreasing order of their melting points:

1. Calcium phosphate, Ca₃(PO₄)₂ (i = 5)
2. Magnesium chloride, MgCl₂(i = 3)
3. Sodium chloride, NaCl (i = 2)
4. Glucose, C₆H₁₂O₆ (i = 1)

So, the ranking of these solutions in decreasing melting point is: calcium phosphate > magnesium chloride > sodium chloride > glucose.

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What is the ph of a solution that has a poh of 9.1

Answers

The pH of the solution is 4.9.

The pH and pOH of a solution are related by the equation:

pH + pOH = 14

Therefore, if the pOH of a solution is 9.1, we can calculate its pH as:

pH = 14 - pOH

pH = 14 - 9.1

pH = 4.9

So, the pH of the solution is 4.9. The pH scale is a logarithmic scale that measures the acidity or basicity of a solution. A pH of 7 is neutral, while a pH below 7 is acidic and a pH above 7 is basic. In this case, the pH is below 7, which means the solution is acidic.

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which nutrients are most responsible for eutrophication?
a. carbon and oxygen
b. carbon and phosphorus
c. nitrogen and oxygen
d. nitrogen and phosphorus

Answers

Answer:

C. Nitrogen and Phosphorous.

Explanation:

the answer is nitrogen and oxygen

can someone check these answers for me and give the right answer? (explanation would be super helpful but not required) studying for a chem test

Answers

Based on the properties of elements, the correct options for the reactivity and composition of elements and compounds are:

B)A) C)C)B)B)D)D)

What are reactive elements?

Reactive elements are elements that readily react with other elements by gaining or losing electrons.

Reactive elements may be metals such as alkali metals and alkaline earth metals or they may be non-metals such as halogens.

Considering the given questions about the properties of elements, the correct options are:

B) Noble gases are the least reactive group of elements.A) CO is a molecule made up of the elements carbon and oxygen.C) Mg, Ca, and Sr belong to the alkaline earth metal family.C) elements in the periodic table are arranged according to their atomic number.B) the atomic number tells us the number of protons in an atom.B) an electron carries a negative charge and is very small compared to the proton.D) the identity of an element is determined by the number of protons in its atom.D) the outermost electron orbits of noble gases have the maximum number of electrons.False. In a neutral atom, the number of electrons always equals the number of protons.False. In a physical change, no new substance is produced.True. Burning is an example of a chemical change.False. Non-metals are not lustrous, ductile, or malleable.True. Compounds are made up of two or more elements.True. Compounds cannot be broken down into simpler substances by physical means.True. To determine the number of neutrons, subtract the atomic number from the mass number.False. In Bohr's atomic model, the first electron orbit holds a maximum of 2 electrons.True. In the alkali metal family, the elements lower in the column are more reactive.True. Hydrogen, oxygen, and nitrogen are examples of non-metals.True. A gas that can re-ignite a glowing splint is oxygen.A change of state is a physical change.A change of color is evidence of a chemical change.Corrosion is a reaction between a metal and oxygen.

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If 3.57 g of barium sulfate is formed, how many grams of sodium sulfate reacted

Answers

Answer:2.18 g.

Explanation:To find the mass of sodium sulfate reacted, we use the balanced chemical equation to know that 1 mole of sodium sulfate reacts with 1 mole of barium sulfate. From the given mass of barium sulfate formed, we calculate the number of moles of barium sulfate. Since the stoichiometry of the reaction is 1:1, the number of moles of sodium sulfate reacted is the same as the number of moles of barium sulfate formed. We then use the molar mass of sodium sulfate to calculate the mass of sodium sulfate reacted. The final answer is 2.18 g.

how do you read an electron dot diagram?

Answers

When reading an electron dot diagram, you can determine the number of valence electrons an atom has and use that information to predict how it will bond with other atoms. Atoms tend to form bonds in order to achieve a full outer shell of electrons, which is the most stable arrangement. By looking at the number of dots in the electron dot diagram, you can predict how many bonds an atom is likely to form and what types of atoms it will bond with.

To read an electron dot diagram, you first need to understand what it represents. An electron dot diagram, also known as a Lewis structure, shows the number of valence electrons that an atom has. Valence electrons are the electrons in the outermost energy level of an atom and are involved in chemical bonding.

The dot diagram shows the symbol for the element surrounded by dots representing the valence electrons. Each dot represents one electron, and the dots are placed around the symbol in pairs, with no more than two dots on each side.

For example, carbon has four valence electrons, so its electron dot diagram would show four dots surrounding the symbol for carbon. Nitrogen, on the other hand, has five valence electrons, so its electron dot diagram would show five dots.

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A student places a metal sphere with a temperature of 98 degress Celsius into a container of water with a temperature of 50 degress Celsius. Which of these is most likely the temperature of the water after the sphere and the water have reached thermal equilibium?



40 degree Celsius



50 degrees Celsius



70 degrees Celsius



100 degrees Celsius

Answers

The most likely temperature of the water after the sphere and the water has reached thermal equilibrium is approximately 70 degrees Celsius. So option C is correct.

This is because heat energy will flow from the metal sphere to the water until they both reach the same temperature. The initial temperature difference between the metal sphere and the water will cause heat to flow from the sphere to the water. As the heat flows, the metal sphere will cool down and the water will heat up. Eventually, they will both reach the same temperature, which will be somewhere between the initial temperatures of the sphere and the water. Therefore option: c is Correct.

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9. the volume of a gas filled balloon is 30.0 l at 313 k and 1.5 atm. what would the volume be if the balloon was changed to stp?

Answers

The volume of the gas-filled balloon at STP would be 36.7 L.

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

(P1V1)/T1 = (P2V2)/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

At STP (standard temperature and pressure), the temperature is 273 K and the pressure is 1 atm. So we have:

(P1V1)/T1 = (P2V2)/T2

(1.5 atm x 30.0 L)/313 K = (1 atm x V2)/273 K

Solving for V2:

V2 = (1.5 atm x 30.0 L x 273 K)/(1 atm x 313 K)

V2 = 36.7 L

Therefore, the volume of the gas-filled balloon at STP would be 36.7 L.

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how does backbone help?​

Answers

Answer:

Backbone help us to be straight ,walk ,sleep etc

Explanation:

Backbone is the part of human body which is located back of our body.

It effort helps us to be straight do various work

The spine or the backbone is the central structure of the vertebrate body and it serves a few imperative capacities:

Bolster: The spine gives bolster for the body and makes a difference keep up its shape.Security: The spine encases and ensures the spinal rope, which is mindful for transmitting signals between the brain and the rest of the body.Connection: Muscles, tendons, and ligaments join to the spine, permitting for development and giving steadiness.Blood cell generation: The springy tissue interior a few of the bones of the spine produces ruddy and white blood cells.Mineral capacity: The bones of the spine store minerals such as calcium and phosphorus, which are imperative for bone quality and other substantial capacities. 

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If 32.0 g of hcl is to be diluted to make a 4.80 m solution, how much water should be added? question 7 options: 0.18 l 0.92 l 6.7 l 18 l

Answers

To answer this question, we need to use the equation for molarity, which is:
Molarity = moles of solute / volume of solution in liters
We can rearrange this equation to solve for the volume of solution:

Volume of solution = moles of solute / molarity
First, we need to calculate the number of moles of HCl in 32.0 g. The molar mass of HCl is 36.5 g/mol, so:
32.0 g / 36.5 g/mol = 0.8767 mol HCl

Next, we need to calculate the volume of solution needed to make a 4.80 m solution. Using the equation above:
Volume of solution = 0.8767 mol / 4.80 mol/L = 0.1826 L or 182.6 mL
Finally, we need to calculate how much water needs to be added. We started with 32.0 g of HCl and added water to make a total volume of 182.6 mL. The volume of water added is therefore:

Volume of water added = 182.6 mL - 32.0 g / 1 g/mL = 150.6 mL
Converting to liters:
Volume of water added = 150.6 mL / 1000 mL/L = 0.1506 L

Therefore, the answer is 0.18 L of water should be added to 32.0 g of HCl to make a 4.80 m solution.

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What mass of solid CH2Cl2 can be melted by applying 7. 80 kJ of energy at the melting point?


grams (3 sig figs)

Answers

The mass of CH2Cl2 that can be melted by applying 7.80 kJ of energy at the melting point can be calculated using the equation of q = m * c * ΔT, where q is the energy applied, m is the mass, c is the heat capacity, and ΔT is the difference between the final and initial temperatures. In this case, the mass can be calculated as m = q / (c * ΔT). Plugging in the given values yields a mass of 0.126 g, rounded to three significant figures.

Therefore, 7.80 kJ of energy can melt 0.126 g of solid CH2Cl2 at the melting point. The equation used for this calculation assumes that the heat capacity and melting point of CH2Cl2 remain constant throughout the process, and thus the calculated value is only an estimate.

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An ethanol plant distills alcohol from corn. The distiller processes 2. 0 t/h of feed containing 15% alcohol and 82% water; the rest is inert material. The bottoms (waste) produced is 85% of the feed and contains 94% water, 3. 5% inert material, and 2. 5% alcohol. The vapor (product) from the top of the distiller is passed through a condenser and cooled to produce the final product. Determine the rate of production of the final product and its composition

Answers

To determine the rate of production of the final product and its composition, we can start by calculating the mass balance for the alcohol in the system.

Given:

Feed rate = 2.0 t/h

Alcohol content in the feed = 15%

Water content in the feed = 82%

Bottoms composition: 94% water, 3.5% inert material, and 2.5% alcohol

We can assume that the inert material remains constant throughout the process, so we only need to consider the alcohol and water components.

Calculation of alcohol mass in the feed:

Alcohol mass in feed = Feed rate * Alcohol content

= 2.0 t/h * 0.15

= 0.3 t/h

Calculation of water mass in the feed:

Water mass in feed = Feed rate * Water content

= 2.0 t/h * 0.82

= 1.64 t/h

Calculation of alcohol mass in the bottoms:

Alcohol mass in bottoms = Alcohol mass in feed * Bottoms composition (alcohol)

= 0.3 t/h * 0.025

= 0.0075 t/h

Calculation of water mass in the bottoms:

Water mass in bottoms = Water mass in feed * Bottoms composition (water)

= 1.64 t/h * 0.94

= 1.5416 t/h

Calculation of alcohol mass in the product:

Alcohol mass in product = Alcohol mass in feed - Alcohol mass in bottoms

= 0.3 t/h - 0.0075 t/h

= 0.2925 t/h

Calculation of water mass in the product:

Water mass in product = Water mass in feed - Water mass in bottoms

= 1.64 t/h - 1.5416 t/h

= 0.0984 t/h

Therefore, the rate of production of the final product is 0.2925 t/h, and its composition is approximately 2.5% alcohol and 97.5% water.

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Describe the following mixtures by checking all of the terms that apply.

Cranberry juice smoke

THESE ARE THE ANSWERS!!!!!

Answers

The appropriate term for the following mixtures are;

Cranberry juice: homogeneous, solution Smoke: heterogeneous, colloid

What is a mixture?

A mixture is a substance made when two or more substances are combined, but they are not combined chemically.

The components of a mixture can be easily separated because each component keep their original properties or identity.

A homogenous mixture is a gaseous, liquid or solid mixture that has the same proportions of its components throughout a given sample e.g. juice while heterogenous mixture is a mixture in which the composition is not uniform throughout the mixture e.g. smoke.

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Answer:

Its in my screenshot

Explanation:

There is a transfer of chemical energy from producers to consumers. What is this chemical energy?.

Answers

The chemical energy referred to in the transfer from producers to consumers is the energy stored in the organic molecules synthesized by the producers during photosynthesis.

Producers, such as plants and algae, use energy from sunlight to convert carbon dioxide and water into glucose and other organic molecules through the process of photosynthesis. The energy from the sunlight is converted into chemical energy and stored in the organic molecules.

Consumers, such as herbivores and carnivores, obtain this stored chemical energy by consuming the organic molecules synthesized by the producers. The organic molecules are broken down during cellular respiration to release the stored chemical energy, which is used by the consumer to power its cellular processes.

Thus, the transfer of chemical energy from producers to consumers is a fundamental process in the food chain, and it is essential for the maintenance of life on earth.

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It is the basic element of drawing that helps us illustrate the realistic view of an object *

line

alphabet of lines

drawing

lay-out

Answers

The basic element of drawing that helps us illustrate the realistic view of an object is the "line."

Lines are essential as they define shapes, outlines, and edges of objects in drawings. The "alphabet of lines" refers to the different types of lines used in technical drawing, such as continuous, dashed, and dotted lines.

These lines help convey various details and aspects of the object being drawn.

In the "drawing" process, you use these lines to create a realistic representation of an object by capturing its dimensions, proportions, and perspective.

The "layout" is the arrangement of these lines and shapes on the drawing surface, ensuring a clear and organized presentation. To "generate" a drawing, you must effectively utilize these lines, the alphabet of lines, and the layout to create a visually accurate representation of the object you are depicting.

By incorporating these terms and concepts, you can create a detailed and realistic drawing that effectively communicates the appearance and characteristics of the object in question.

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Help what’s the answer

Answers

The limiting reagent is F₂, the number of OF₂ molecules formed is 2 and the number of F₂ atoms/molecules in excess is 2.

How to determine limiting reagent?

Since there are two oxygen molecules and four fluorine molecules, fluorine is in excess.

The balanced equation is O₂ + 2 F₂ → OF₂, which shows that 1 molecule of O₂ reacts with 2 molecules of F₂ to form 2 molecules of OF₂. Therefore, since there are only 2 molecules of F₂ available, the limiting reagent is F₂.

As F₂ is the limiting reagent, only 1 molecule of O₂ will react with 2 molecules of F₂ to form 2 molecules of OF₂. Therefore, the number of OF₂ molecules formed is 2.

The number of atoms/molecules in excess is the difference between the number of atoms/molecules available and the number of atoms/molecules used in the reaction. In this case, since F₂ is in excess, the number of F₂ molecules in excess is 2.

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Image transcribed:

Use the References to access important values if needed for this question.

The illustration to the left represents a mixture of oxygen (red) and fluorine (green) molecules.

If the molecules in the above illustration react to form OF₂ according to the equation

O₂ + 2 F₂ →  OF₂,

the limiting reagent is _______, the number of OF₂ molecules formed is ______ and

the number of ______ atoms/molecules in excess is ________.

List three ways in which the octet rule can sometimes fail to be obeyed.

Answers

The  three general exceptions to the octet rule is:

When  Molecules, such as NO, with an odd number of electrons; When Molecules in which one or more atoms possess more than eight electrons like SF6.When  Molecules like BCl3, in which one or more atoms possess less than eight electrons.

What is the octet rule?

The octet rule is  described as a chemical rule of thumb that reflects the theory that main-group elements tend to bond in such a way that each atom has eight electrons in its valence shell, giving it the same electronic configuration as a noble gas.

The structure of the octet is usually held responsible for the relative inertness of the noble gases and the chemical behavior of certain other elements.

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If i contain 3. 15 moles in a container with a volume of 67 liters and at a temperature Of 472 K what is the pressure

Answers

Answer:1.8

Explanation:

=nrt/v

P=(3.15)(.0821)(472)/67

P=1.82atm

Which of the following solutions will have the greatest concentration?
a. 2 moles of solute dissolved in 1 liter of solution
b. 0.3 mole of solute dissolved in 0.6 liter of solution
c. 2 moles of solute dissolved in 10 liters of solution
d. 0.1 mole of solute dissolved in 0.5 liter of solution​

Answers

2 moles of solute dissolved in 1 liter of solution has the greatest concentration.

What is concentration of a solution?

Concentration refers to the quantity of solute that is dissolved in a specific amount of solution, and it is commonly measured in units such as moles per liter or grams per liter.

Equation:

To determine which solution has the greatest concentration, we need to calculate the number of moles of solute present in each solution and then compare the values.

a. Concentration = 2 moles / 1 liter = 2 M

b. Concentration = 0.3 moles / 0.6 liters = 0.5 M

c. Concentration = 2 moles / 10 liters = 0.2 M

d. Concentration = 0.1 moles / 0.5 liters = 0.2 M

Comparing the concentrations, we see that solution (a) has the greatest concentration of 2 M, while the other solutions have concentrations of 0.5 M or lower.

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A mixture contains 1. 00kg of aluminium and 3. 00 kg of iron oxide. The equation for the reaction is 2Al+Fe2O3 =2Fe +Al2o3 Show that aluminium is a limiting reactant Relative atomic masses:O=16 Al=27 Fe=56​

Answers

The maximum amount of Al₂O₃ that can be produced in this reaction is 1.00 kg, which confirms that aluminium is the limiting reactant.

To determine if aluminium is the limiting reactant in this reaction, we need to first calculate the theoretical yield of the reaction using both reactants.

From the balanced equation, we can see that for every 2 moles of aluminium, we need 1 mole of iron oxide.

1.00 kg of aluminium has a mass of 1000 g / 27 g/mol = 37.04 moles.

3.00 kg of iron oxide has a mass of 3000 g / (2 x 56 g/mol + 3 x 16 g/mol) = 13.39 moles.

Since we need half as many moles of iron oxide as aluminium for the reaction, the aluminium is the limiting reactant.

To calculate the theoretical yield of the reaction, we need to use the amount of aluminium as the limiting factor.

Since the balanced equation shows that 2 moles of aluminium react to produce 1 mole of Al₂O₃, we can calculate the theoretical yield of Al₂O₃ as:

37.04 moles Al x (1 mol Al₂O₃ / 2 mol Al) x (2 x 27 g/mol Al₂O₃) = 999.5 g or 1.00 kg (rounded to two significant figures).

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Identify the molecular geometry around each carbon atom in ch2chch3 using vsepr theory.

Answers

The molecular geometry around each carbon atom in [tex]CH_2CHCH_3[\tex]

using vsepr theory is tetrahedral and trigonal planar.

What is molecular geometry?

The three-dimensional shape that a molecule takes up in space is known as molecular geometry. It depends on the surrounding atoms and electron pairs as well as the core atom.

By assessing the amount of electron pairs surrounding an atom, the Valence Shell Electron Pair Repulsion (VSEPR) theory predicts molecular shapes and bond angles. Electron couples will reject one another because they are negatively charged. According to the idea, electron pairs will position themselves in three dimensions to minimise repulsion.

VSEPR Guidelines

Determine the main atom.

tally the valence electrons in it.

For every atom with a bond, add one electron.

For charge, add or subtract electrons (see Top Tip).

To determine the total, divide them by 2.

the quantity of electron pairs.

Make a shape prediction using this number.

Molecular geometry around propane is tetrahedral and trigonal planar.

Therefore, molecular geometry around [tex]CH_2CHCH_3[\tex] is tetrahedral and trigonal planar.

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A 100ml sample of 0.40m hydrofluoric acid is mixed with 100ml of 0.40m lithium hydroxide. will the ph of the final solution be less than 7, equal to 7, or greater than 7

Answers

The pH of the final solution will be equal to 7.

When 100 mL of 0.40 M hydrofluoric acid (a weak acid) is mixed with 100 mL of 0.40 M lithium hydroxide (a strong base), the reaction can be represented as:

HF + LiOH → LiF + H₂O

As both solutions have equal concentrations and volumes, they will completely neutralize each other. The product, LiF, is a soluble salt and will dissociate into Li+ and F- ions in water.

Since the number of moles of H+ and OH- ions is the same in the reaction, they will react to form water (H₂O), resulting in a neutral solution with a pH of 7. The formation of water from equal amounts of H⁺ and OH⁻ ions indicates that the solution is neither acidic nor basic, thus leading to a pH of 7.

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What is the mass of 6. 02 x 10^22 molecules of fluorine gas at stop

Answers

Answer:

3.7996 g

Explanation:

From the number of molecules we can find the number of moles of Fluorine gas (F2) and multiply by Fluorine Gas' molecular weight. Fluorine gas is F2,

F = 18.998g/mol.

F2 (g) = 18.998*2 =37.996g F2(g)/mol

1 mol = 6.02 x 10^23 molecules

[tex]\frac{6.02*10^{22} molecules}{6.02*10^{23}molecules / mole }\\\\ = 0.1 mole[/tex]

0.1 mol x 37.996g F2 (g) / mol

3.7996 g F2

you need to make an aqueous solution of 0.172 m iron(ii) nitrate for an experiment in lab, using a 250 ml volumetric flask. how much solid iron(ii) nitrate should you add?

Answers

We need to add 7.7 g of solid iron(II) nitrate to make a 0.172 M solution in 250 mL volumetric flask.

First, we can use molarity and volume of solution to find the number of moles of iron(II) nitrate needed:

moles of [tex]Fe(NO_3)_2[/tex]= Molarity × Volume in liters

moles of [tex]Fe(NO_3)_2[/tex] = 0.172 mol/L × 0.250 L = 0.043 mol

Next, we can use the molar mass of iron(II) nitrate to find the mass of the solid that needs to be added:

mass of [tex]Fe(NO_3)_2[/tex] = moles of [tex]Fe(NO_3)_2[/tex] × molar mass of [tex]Fe(NO_3)_2[/tex]

mass of [tex]Fe(NO_3)_2[/tex]= 0.043 mol × (55.85 g/mol + 2 × 14.01 g/mol + 6 × 16.00 g/mol)

mass of [tex]Fe(NO_3)_2[/tex]= 0.043 mol × 179.86 g/mol = 7.7 g

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If the original volume of a gas was 300 L at 0. 250 atm and 400. 0 K, what is the volume of the gas at 2. 00 atm and 200. 0 K?

Answers

The volume of the gas at 2.00 atm and 200.0 K is 18.75 L.

We can use the combined to solve this problem:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

where P is pressure, V is volume, and T is temperature.

Plugging in the given values:

(0.250 atm * 300 L) / (400.0 K) = (2.00 atm * V2) / (200.0 K)

Simplifying:

V2 = (0.250 atm * 300 L * 200.0 K) / (2.00 atm * 400.0 K)

V2 = 18.75 L

Therefore, the volume of the gas at 2.00 atm and 200.0 K is 18.75 L.

Gas laws refer to a set of principles that describe the behavior of gases under different conditions, including pressure, temperature, and volume.

There are several gas laws, including Boyle's law, Charles's law, Gay-Lussac's law, and the ideal gas law.

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1. 98 g of calcium chloride and 3. 75 g of sodium oxide are combined. Theoretically,


what mass of solid product could be formed from these amounts of reactants? What


is the limiting reactant?

Answers

Based on the stoichiometry, sodium oxide is the limiting reactant because it produces less product compared to the calcium chloride. Therefore, 0.998 g of calcium oxide is the maximum amount of product that can be formed.

To determine the theoretically possible mass of solid product and the limiting reactant, we need to first write the balanced chemical equation for the reaction between calcium chloride and sodium oxide:

[tex]CaCl2 + Na2O → CaO + 2NaCl[/tex]

The stoichiometric ratio of calcium chloride to sodium oxide in the equation is 1:1, which means that for every 1 mole of calcium chloride that reacts, 1 mole of sodium oxide is required. We can use this ratio to calculate the moles of each reactant:

moles of [tex]CaCl2[/tex] = 1.98 g / 110.98 g/mol = 0.0178 mol

moles of [tex]Na2O[/tex] = 3.75 g / 61.98 g/mol = 0.0604 mol

According to the balanced equation, for every mole of calcium chloride that reacts, 1 mole of calcium oxide is produced. Therefore, the theoretical yield of calcium oxide can be calculated based on the moles of calcium chloride:

moles of [tex]CaO[/tex] = 0.0178 mol

mass of [tex]CaO[/tex] = moles of[tex]CaO[/tex] x molar mass of [tex]CaO[/tex]

mass of [tex]CaO[/tex] = 0.0178 mol x 56.08 g/mol

mass of [tex]CaO[/tex]= 0.998 g

Similarly, we can calculate the maximum amount of product that can be formed based on the moles of sodium oxide:

moles of [tex]NaCl[/tex]= 2 x moles of [tex]Na2O[/tex] = 0.1208 mol

mass of[tex]NaCl[/tex] = moles of [tex]NaCl[/tex] x molar mass of[tex]NaCl[/tex]

mass of [tex]NaCl[/tex]= 0.1208 mol x 58.44 g/mol

mass of [tex]NaCl[/tex] = 7.06 g

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How many grams are in a sample of 7.9 moles of zinc?

Answers

There are 516.682 grams in a sample of 7.9 moles of zinc.

To determine the number of grams in a sample of 7.9 moles of zinc, we need to use the molar mass of zinc. The molar mass of zinc is 65.38 g/mol.

Therefore, to calculate the number of grams in 7.9 moles of zinc, we can multiply 7.9 moles by 65.38 g/mol. The calculation is as follows:

7.9 moles x 65.38 g/mol = 516.682 g

Therefore, there are 516.682 grams in a sample of 7.9 moles of zinc. It's important to remember to always use the molar mass of the element or compound when converting between moles and grams.

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Plan an investigation to explore the relationship between properties of substances and the electrical forces within those substances.


What can properties of substances tell us about the electrical forces within those substances?


In this activity, you will plan and conduct an investigation to compare a single property across several substances. You must select a measurable property, such as boiling point or surface tension. After your investigation, you will compare the results and use your data to make inferences about the strength of the electrical forces in each substance you tested

Answers

The first step in this investigation will be to select several substances to test. It is important to choose substances that have similar chemical composition but differ in physical properties.

Once the substances have been selected, the next step is to measure the single property across each of the substances. This can be done through a variety of methods, such as using a thermometer to measure boiling points or a microscope to measure surface tension.

After the data has been collected, it should be compared and analyzed to determine how the property is related to the strength of the electrical forces in the substance. By comparing the data and making inferences, it is possible to determine how properties of substances can indicate the strength of the electrical forces within those substances.

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