Answer:
R =V/ I =12.6 ÷ 0.53= 27.77 ohm
A rod is heated at the rate of 30 watts at the middle point and is insulated at its two ends. The two half sections are cooled by convection by an ambient fluid at 20 degree Celsius with a heat transfer coefficient of 30 W/m^2 C. The diameter of the rod is 0.5 cm, its length is 18 cm and its thermal conductivity is 206 W/mC. Determine the temperature in the middle of the rod and at the insulated ends. Please describe your strategy of solving this problem.
thanks for the points
Explanation:
sinat
Accelerationa
2 2.84
7 34
TABLE
in Elination
t2 t3 T2 2
1=0.04
2.29 1.25 1.28 1.271.61
2 460 = 0.00 4.59 1.16 1.081.12 1-25
3 so = 0.12 6.89 0.88
097 0.53
4. = 0.16 9.210.8
9.21 0.850.796. 82/0.67
(So
0.72 0.77 0.75 l 0-56/
0.28
49. al
27. 49
13 11%.
41. 2L
= 0.2 11.54
Answer:
so you have a question
Explanation:
either way,you have a nice day
Which is not poor conductor?
a) pure water
b) Cotton thread
c) plastic spoon
d) metal vase
Answer:
Metal vase
Explanation:
Pure water is not a good conductor, and neither is plastic or cotton. Metal is the only one of the four that actually is a good conductor. For example, lighting hitting metal, this happens because the lightning connects to anything that has some kind of conductant.
Write down the units for the following physical quantities:
a. Velocity
b. Acceleration
c. Momentum
d. Force
e. Power
f. Energy
g. Pressure
at 30°c an almunium spher is 30cm³ long
the cofficen linear expansion is 24×10`⁶ if the final volume is 30.5cm³
what's the final temperatur of the almunium sphere
Answer:
Change volume / volume = .5 / 30 = .01666
coefficient of volume expansion = 3 * 24E-6 = 72E-6
Change in temp = .0167 / 24E-6 = 232 deg C
Final temp = 232 + 30 = 262 deg C
Change in volume / volume = 3 * coeff linear expansion * change in deg C
plz help owo
What characteristic is shared by sunspots, solar flares, and coronal mass ejections? Select the two correct responses.
They are caused by outward fluctuations of the sun's magnetic field.
They appear as dark spots on the sun's surface.
They tend to occur during active periods of the solar cycle.
They appear as bright spots on the sun's surface.
Answer:
They are caused by outward fluctuations of the sun's magnetic field.
They tend to occur during active periods of the solar cycle.
Explanation:
While sun spots will appear darker than the surrounding surface, flares will tend to appear brighter. CME's are associated with massive flares.
The two correct responses are as follows:
They are caused by outward fluctuations of the sun's magnetic field.They tend to occur during active periods of the solar cycle.The following information should be considered:
At the time when sunspots should appear darker as compared to the surrounding surface, so flares should be appear brighter. CME's are along with massive flares.Due to this, the above answers are considered.Learn more: brainly.com/question/16911495
If a person weighs 160 Newtons on Earth, what is their weight in pounds on Earth?
A. 27
B. 36
C. 712
D. 534
Answer:
B. 36 lb
Explanation:
m = 160/9.8 = 16.3 kg
16.3 kg ( 2.205 lb/kg) = 36 lb
Help ,I wanna know if this is correct or not
Answer:
it looks correct to me but im not 11% sure
Explanation:
The concepts in this problem are similar to those in Multiple-Concept Example 4, except that the force doing the work in this problem is the tension in the cable. A rescue helicopter lifts a 81.7-kg person straight up by means of a cable. The person has an upward acceleration of 0.729 m/s2 and is lifted from rest through a distance of 7.86 m. (a) What is the tension in the cable
Answer:
Explanation:
Given that:
distance (z) = 7.86 m
mass of the person = 81.7 kg
Acceleration (a) = 0.729 m/s²
By using Newton's second law along the vertical axis:
[tex]T - mg = ma\\ \\ T = ma + mg \\ \\ T = m(a+g) \\ \\[/tex]
T = 81.7 (0.729 +9.8)
T = 860.22 N
The work done now is:
[tex]W_T = T\times z \\ \\[/tex]
[tex]W_T = 860.22 \times 7.86[/tex]
[tex]\mathbf{W_T =6761.3292\ N}[/tex]
Please help on these two thanks
Explanation:
Number 29
= 10 N (from rocket) + 10 N (from wheels) - 7 N (from parachute 'cause force in other direction)
= 20 N - 7 N
= 13 N ✔
Number 30
= 100 N - 85 N
= 15 N to the left ✔
1.00 x 10^8 kg of clear liquid (specific heat
capacity = 5.11 x 10^2 J/kg•°C) at a temperature
of 15.0°C gains 3.33 x 10^6 J of heat. What is the
final temperature of the liquid? (Assume the
melting point is less than 15.0°C and the boiling
point is greater than 62.0°C.)
5. Sarah is standing 32.0 m away from Jason. If Sarah throws a snowball at a 45 degree
angle for maximum distance, what velocity must the snowball have to hit Jason directly.
(Assume Jason and Sarah are about the same height so that if she throws the snowball
from head level, it will hit Jason in the head.)
Answer:
Explanation:
If air resistance is ignored and assume UP and Toward Jason are the positive directions.
horizontal analysis
d = (vx₀)t
t = d/vx₀
horizontal analysis
0 = vy₀t + ½gt²
0 = vy₀(d/vx₀)+ ½g(d/vx₀)²
as vy₀ = v₀sin45 and vx₀ = v₀cos45 and are equal.
0 = d + ½g(d²/v₀²cos²45)
-d = ½g(d²/v₀²cos²45)
-dv₀² = ½g(d²/cos²45)
v₀² = -½g(d/cos²45)
v₀² = -½(-9.81(32.0/cos²45)
v₀² = 313.92
v₀ = 17.717787...
v₀ = 17.7 m/s
In the absence of air resistance, as an object falls freely, its
O velocity increases
O acceleration increases
both A and B
O none of the above
Answer:
None of the above
Explanation:
None of the above
In the free-body diagram, the magnitude of the normal force is 40 N, the friction force is
25N, the net force is 80N: What is the magnitude of the applied force?
Answer:
Explanation:
F = 80 + 25 = 105 N
DUE IN AN HOUR! HELP!!
A charged ball has a charge of -3.5x10-17c . How many electrons are found in the ball?
Answer:
218 electrons
Explanation:
pls find the attached image for solution
Children start to gain control over their attention beginning in preschool. This control is related to a growth
spurt in the brain's lobe.
Answer:
occipital parietal
Explanation:
Hope this helps, plus I took the test
A heavy train of mass 200 tonnes has a maximum speed of 20m/s up a hill inclined at 1.15⁰ to the horizontal when the engine is working at 800 kwatts. What is the resistance to the motion of the train?
Answer:
https://www.brainlyanswer.com
Explanation:
click the link the answer is in the link:)
Answer:
train to busan
shadow train
the horror train
train game
A substance with a pH value of 2.3 would be classified as
O strong acid
O weak acid
O strong base
O weak base
A substance with a pH value of 2.3 would be classified as a strong acid. Option A is correct.
What is ph value?pH stands for "potential hydrogen," and it is a measure of the acidity or basicity (alkalinity) of a solution. The pH scale ranges from 0 to 14, with 7 being neutral (neither acidic nor basic). Solutions with a pH less than 7 are considered acidic, and solutions with a pH greater than 7 are considered basic.
Here,
The pH scale is used to measure the acidity or basicity of a solution. Values on the pH scale range from 0 to 14. Solutions with a pH value less than 7 are considered acidic, and solutions with a pH value greater than 7 are considered basic. The lower the pH value, the more acidic the solution.
A pH value of 2.3 indicates that the solution is strongly acidic, as it is well below the neutral value of 7.
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1. A 6-volt battery produces a current of 0.5 amps. What is the power in the circuit?
Answer:
hope this will help you
have a great day
Explanation:
please mark me as the brainliest
If the tension in the string is equal to 2 W when the stone is at its lowest point, then the tension when the stone is at the highest point will be
This question involves the concept of tension, centripetal force, centrifugal force, and weight.
The tension of the stone at the highest point is "0 N".
The centrifugal force always acts away from the circle. The tension always acts toward the support that is the center of the circle in this case. When the stone is at its lowest point, the centrifugal force, and the weight of the stone, both act downward. But the tension is pointing in the upward direction. Hence, the equilibrium equation will be:
[tex]Tension = Weight\ + \ Cenrifugal\ Force\\T = W + F_c\\T = 2\ W\ (given)\\2\ W = W+F_c\\F_c = 2\ W - W\\F_c = W[/tex]
Now, we consider the stone at the top position. Here, the centrifugal force will act in the upward direction (away from the center of the circle), while the weight and tension will be acting in the downward direction. Thus, the equilibrium equation, in this case, will be:
[tex]F_c = W+T\\T=F_c-W\\T = W-W\\[/tex]
T = 0 N
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The attached picture shows the free body diagram of the stone at different locations.
Ti3N + MgO → Mg3N2 +Ti2O balance chemical equation
We have that the balanced chemical equation is mathematically given as.
2Ti_3N + 3MgO → Mg_3N_2 +3Ti_2O
From the question we are told
Ti3N + MgO → Mg3N2 +Ti2O balance chemical equation.
Generally the way to balance an equation is by making all elements present on the Left hand side(LHS) same with the right hand side RHS.
Therefore
The equation is mathematically given as.
Ti_3N + MgO → Mg_3N_2 +Ti_2OWe consider the Left hand side(LHS) first.
2Ti_3N + 3MgO → Mg_3N_2 +Ti_2OThen we consider the right hand side RHS.
2Ti_3N + 3MgO → Mg_3N_2 +3Ti_2OTherefore the balanced chemical equation is mathematically given as.
2Ti_3N + 3MgO → Mg_3N_2 +3Ti_2OFor more information on this visit
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How to find force if mass time and distance is given?
Answer:
For example, speed is a length divided by time. Force is mass times acceleration, and is therefore a mass times a distance divided by the square of a time. We therefore say that [Force] = MLT−2.
The Sun's primary energy source is
Answer:
nuclear fusion
Explanation:
converting hydrogen to helium.
Does time stand still in space
Answer:
[tex]\underline{\textsf{\textbf{Answer -}}}[/tex]
No & Yes - the case depends actually.
You can't make the velocity zero and expect to stay in space. you will need to constantly fire the engine to hold youself in position (this is possible, until you run out of fuel).
Yes, it is possible to fire the engine and lift off earth into space, and then fire in the opposite direction to earths movement until you are still, relative to the sun. But if you now turn the engine off, the suns gravity will pull you down and directly into the sun.
its the earths forward motion that prevents it falling into the sun
Answer:
No & Yes - the case depends actually.
You can't make the velocity zero and expect to stay in space. you will need to constantly fire the engine to hold youself in position (this is possible, until you run out of fuel).
Yes, it is possible to fire the engine and lift off earth into space, and then fire in the opposite direction to earths movement until you are still, relative to the sun. But if you now turn the engine off, the suns gravity will pull you down and directly into the sun.
its the earths forward motion that prevents it falling into the sun
Someone pls help I don’t understand this
Answer:
[tex]{ \rm{F _{ball \: on \: bat} = - F _{bat \: on \: ball} }}[/tex]
Explanation:
• This is due to the third newtons law of motion which states that "Every action has an equal and opposite reaction".
When a car's acceleration is negative, what is happening to the car's motion?
the car slows down
the car speeds up
the car travels at a constant speed
the car remains at rest
Answer:
the car slows down
Explanation:
Two skaters face one another and stand motionless, then push against each other on the ice. If one's mass is 55 kg and he moves to the left after the push at a velocity of 4.3 m/s, how fast was the other skater traveling after the push if her mass was 48 kg.
Answer:
3.75 m/s
Explanation:
55/4.3 = 48/x
12.8 = 48/x
x = 48 : 12.8
x = 3.75 m/s
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The weight of an object is 180 N at a distance of 150 km above a planet's center. What is the weight of the object when it moves 450 km above the center of the planet?
By using Newton law of gravitation, the weight of the object when it moves 450 km above the center of the planet is 20N
Given that the weight of an object is 180 N at a distance of 150 km above a planet's center.
F = GMm/[tex]r^{2}[/tex]
F = mg = 180N
r = 150
When it moves 450 km above the center of the planet, G, M and m will be constant. only r will vary.
180 = GMm/[tex]150^{2}[/tex]
Make GMm the subject of the formula
GMm = 180 x 22500
GMm = 4050000
As it moves 450 km above the center of the planet, Its weight will be
F = GMm/[tex]r^{2}[/tex]
Substitute all the values and parameters
F = 4050000/[tex]450^{2}[/tex]
F = 20 N
Therefore, the weight of the object When it moves 450 km above the center of the planet is 20 Newtons
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A train travels meters in the first second of travel, 6 meters again during the second second of travel, and 6 meters again during the third second. Its
acceleration is
O 0 m/s
6 m/s
O 12 m/s/s
18 m/s
O None of the above
Answer:
0 m/sExplanation:
there is no acceleration, it's velocity is always 6m/s
so your answer is 0m/s
g A projectile of mass 3 kg is launched horizontally from an initial height 3 m with an initial velocity 10 m/s. This velocity in the x direction is preserved when you ignore air resistance. The projectile still accelerates in the vertical y direction toward the ground, but this is exactly the energy lost from potential energy. Energy is conserved as long as you use the total mechanical energy equation. What is the final kinetic energy as the projectile just reaches the ground
Answer:
The kinetic energy at ground will be "238.2 J".
Explanation:
The given values are:
mass,
m = 3 kg
Initial height,
h = 3 m
Initial velocity,
v = 10 m/s
By using the conservation of energy at points A and B,
⇒ [tex]E_A=E_B[/tex]
⇒ [tex]mgh+\frac{1}{2}mv^2=k_B[/tex]
On substituting the values, we get
⇒ [tex]3\times 9.8\times 3+\frac{1}{2}\times 3\times (10)^2=k_B[/tex]
⇒ [tex]88.2+0.5\times 3\times 100=k_B[/tex]
⇒ [tex]88.2+150=k_B[/tex]
⇒ [tex]238.2 =k_B[/tex]