50 points! Help (Vectors)

Answer:

Step-by-step explanation:

Your base would be the 4

Answer:

4

Step-by-step explanation:

When you have a something raise up to a number this can be represented as:

[tex]b^a = b_1 \cdot b_2 \cdot \cdot \cdot b_a[/tex]

Where [tex]b[/tex] is the base and [tex]a[/tex] the exponent. In this case you have five times four, then you can re-write the expression as:

[tex]4 \times 4 \times 4 \times 4 \times 4 = 4^5[/tex]

Where the [tex]b[/tex] is equal to 4 and [tex]a[/tex] equal to 5

Answer:

20

Step-by-step explanation:

4x3=12

12x4=48 after 10

48x4=192 after another 10

Answer:

6cm

Step-by-step explanation:

square root of 36 because the area of a square is base x height and a square has equal sides

Answer:

J= Javiers age

5J=60

5J/5= 60/5

J= 12

Check:

5(12)= 60

60=6p

Step-by-step explanation:

see answer

hope this helps

Answer:

I think it's True

Step-by-step explanation:

When you multiply a negative and positive, it equals a negative: (-)x(+)=(-)

^-2/5x > -8

Then multiply both sides of the inequality by ^-5/2 and flip the inequality sign

Which gives you:

x < 20

Answer:

Step-by-step explanation:

one would flip the sign on (-2/5)x > -8 because you would be multiplying by a negative number (- 5/2) to get positive x standing alone. It resolves to

x < 20

You would also flip the sign on

-x + ¾ < 10

-x + ¾ - ¾ < 10 - ¾

-x(-1) > 9¼(-1)   multiplying by a negative number flips the sign.

x > - 9¼

let's change the decials first off to fractions and get the slope and line

[tex]2.\underline{5}\implies \cfrac{25}{1\underline{0}}\implies \cfrac{5}{2}~\hfill 6.\underline{5}\implies \cfrac{65}{1\underline{0}}\implies \cfrac{13}{2} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{1}~,~\stackrel{y_1}{\frac{5}{2}})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{\frac{13}{2}})[/tex]

[tex]\stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{\frac{13}{2}}-\stackrel{y1}{\frac{5}{2}}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{1}}}\implies \cfrac{~~ \frac{8}{2}~~}{-1}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{-4}(x-\stackrel{x_1}{1})[/tex]

[tex]y-\cfrac{5}{2}=-4x+4\implies y=-4x+4+\cfrac{5}{2}\implies y = -4x+\cfrac{13}{2}[/tex]

Answer:

false

Step-by-step explanation:

-1/8 = -0.125

-1/10 = -0.100

as it is negative  

-0.125 < -0.1

so it is false

Answer:

The answer is C.

The answer is D.

Step-by-step explanation:

Thank you:)

Answer:

Step-by-step explanation:

The geometric mean is the average of the 5 numbers

8 + 6 + 3 + 5 + 4                 Just add.

Total = 26

There are 5 elements, so the average = 26/5 = 5.2

Answer:

7

Step-by-step explanation:

The factors of 28 and 63 are

28 : 1, 2, 4, 7, 14, 28

63 : 1, 3, 7, 9, 21, 63

The common factors are 1 and 7

7 is a prime factor of both 28 and 63

The formula for the speed of the wagon can be found by using Pythagoras theorem, and chain rule of differentiation.

[tex](a) \ \mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = q -\dfrac{x}{\sqrt{x^2+ 5.76}}[/tex]

(b) When x = 0.6 and q = 0.5 m/s, the speed of the wagon is approximately 0.243 m/s.

Reasons:

(a) The distance from the cart to the pulley, r is given by Pythagoras's

theorem as follows;

r = √((3 - 0.6)² + x²) = √(2.4² + x²)

The speed of the wagon = [tex]\mathbf{\dfrac{dx}{dt}}[/tex]

The speed of the rope, q = [tex]\mathbf{\dfrac{dr}{dt}}[/tex]

By chain rule, we have;

[tex]\dfrac{dr}{dt} = \mathbf{\dfrac{dr}{dx} + \dfrac{dx}{dt}}[/tex]

[tex]\dfrac{dr}{dx} = \dfrac{x}{\sqrt{x^2+ 5.76}}[/tex]

Therefore;

[tex]\dfrac{dr}{dt} = q =\dfrac{x}{\sqrt{x^2+ 5.76}}+ \dfrac{dx}{dt}[/tex]

[tex]\mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = \underline{ q -\dfrac{x}{\sqrt{x^2+ 5.76}}}[/tex]

(b) The speed of the wagon when x = 0.6 if q = 0.5 m/s is given as follows;

[tex]\dfrac{dx}{dt} = 0.5 -\dfrac{0.6}{\sqrt{0.6^2+ 5.76}} =\sqrt{\dfrac{1}{17} } \approx 0.243[/tex]

The speed of the wagon when x = 0.6 and q = 0.5 m/s, [tex]\dfrac{dx}{dt}[/tex] ≈ 0.243 m/s

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Answer:

|- 1 1/5|, 1 2/5, |-1 1/2|, 1 3/4

Step-by-step explanation:

Answer:

1728 for A

7290000 for B

Step-by-step explanation:

Answer:  40

Step-by-step explanation:

Answer:

17

Step-by-step explanation:

x + 100 = 4x + 49

100 - 49 = 3x

3x = 51

x = 17

Answer:

Step-by-step explanation:

please try to provide a more accurate information 13cm of what? 790?

Answer:

The area of parallelogram can be found by product of its base and height. The calculations are shown below:  

Step-by-step explanation:

We know that,

Area of parallelogram = base × height

assume base to be 21 cm.

Then,

sin 79° = [tex]\frac{height}{13}[/tex]

∴ height = 13 × 0.98 = 12.74

Area of parallelogram = 21 × 12.74

                                   = 267.54 [tex]cm^{2}[/tex]

The area of parallelogram is calculated as 267.54 [tex]cm^{2}[/tex]

Answer:

I honestly don't know why you are on this if your in 4th grade because this is for middle, high, and college school kids.

Answer:

2 divided by 834 is 1/417 or 417

Step By Step Explanation:

Why is a fourth-grader even on a website for middle, high school, and college...

Using the t-distribution, it is found that the p-value is of 0.177.

At the null hypothesis, it is tested that for a smartphone carrier's data speeds at airports, the mean is 19 Mbps, that is:

[tex]H_0: \mu = 19[/tex]

At the alternative hypothesis, it is tested if the mean is different than 19 Mbps, that is:

[tex]H_1: \mu \neq 19[/tex]

Inputting this information into a calculator, the p-value is of 0.177.

A similar problem is given at https://brainly.com/question/13873630

[tex]\dfrac 54 = \dfrac{25} y\\\\\\\implies \dfrac 14 = \dfrac 5y\\\\\implies y = 4 \times 5 =20[/tex]

A) S(x) = 18x + -36005

B) 18

C) 2013

Answer:8

Step-by-step explanation:

Answer:

d. It does, the points shown on the line would be part of y = −2x.

is the answer let me know if this helped

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

hope i helped

TICKET MONEY for age 16 and over,

155-49 =106

1 person pays £18.60

106 = 106 × £18.60

=£1,971.6

TICKET MONEY for under 16

1 person pays £12.80

49 people =49 × £12.80

= £627.2

TOTAL NUMBER OF TICKETS

£ 1,971.6 + £6272.2

= £2,598.8

Answer:

x=pi/4, 5pi/4

Step-by-step explanation:

cot x = cos x / sin x, csc x = 1/sin x, so we have 2 cos x / sin x = 1/ sin^2 x. multiply both sides by sin^2 x to get 2 cos x * sin x = 1, divide both sides by 2 to get cos x sin x = 1/2, this would work for angles pi/4 and 5pi/4 (3pi/4 and 7pi/4 would make cos x sin x = -1/2) since cos x = sin x = sqrt(2)/2

Answer: 34,000 Dinars

Step-by-step explanation: As 25,000 + 9000 is 34,000

Answer:

X=1

Y=2

Step-by-step explanation:

put 1 in for X

3(1)+3(y)=9

-3(1)+2(y)=1

now put 2 for Y

3(2)+3(2)=9

-3(1)+2(2)=1

3•1= 3

3•2=6

3+6=9

-3•1=-3

2•2=4

-3+4=1

you cant factorise both of them as they have nothing in common

Answer: “P hay Q” là một mệnh đề được

Step-by-step explanation: Các quy tắc tương đương logic: ... Chứng minh biểu thức mệnh đề (¬((r ∨ q) ∧ q) ∨. ¬p)∧ ((¬p

Hybrid cars have lower operational cost and reduce Green House Gases

GHG when journeys are made on a frequent basis.

Reasons:

The given parameters are;

The mass of Green House Gases GHG created by each gallon of gasoline burned = 20 pounds

Let A represent the cars that consume 40 MPG and let B represent the cars that consume 20 MPG.

Amount of GHG produced per year by cars A = 4.4 tons

4.4 US tons = 8,800 lbs

Amount of GHG produced per year by cars A = 8.8 tons

8.8 US tons = 17,600 lbs

[tex]\displaystyle Gasoline \ consumed \ per \ year \ by \ car \ A = \frac{8,800 \ lb}{20 \ lb/ gallon} = \mathbf{440 \ gallons}[/tex]

Cost of gasoline consumed per year by car A per year is therefore;

[tex]Cost_A[/tex] = 440 gallons × $2.454 = $1,079.76

[tex]\displaystyle Gasoline \ consumed \ per \ year \ by \ car\ B = \mathbf{\frac{17,600\ lb}{20 \ lb/ gallon}} = 880 \ gallons[/tex]

Cost of gasoline consumed per year by car B per year is therefore;

[tex]Cost_B[/tex] = 880 gallons × $2.454 = $2,159.52

The amount saved annually by car A compared to car B is therefore;

Fuel cost savings by Car A = $2,159.52 - $1,079.76 = $1,079.76

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