6. Find cos C using the triangle below. Answers may be in decimal OR fraction form.​

Answer:

5x−4y

Step-by-step explanation:

:D

Answer: 5x - 4y

Step-by-step explanation: combining like terms means to combine the terms that have the same letter. so since the 3 and 2 have an x you combine them and the 3 and -7 have a y you combine them. hope this helped:)

Answer:

8.6

Step-by-step explanation:

Mean = Sum of numbers/amount of numbers

= (11+13+8+9+4+8+7)/7

= 60/7

= 8.6

Answer:

sinD ≈ 0.44

Step-by-step explanation:

sinD = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{CE}{CD}[/tex] = [tex]\frac{39}{89}[/tex] ≈ 0.44 ( to the nearest hundredth )

Answer:

a = 191/81

Step-by-step explanation:

a+ 1 1/6 = 11 7/9

1 1/6 = 7/6

11 7/9 = 106/9

So, our equation is

a + 7/6 = 106/9

Subtract 7/6 from both sides

a = 191/81

So, the answer is

a = 191/81

Answer:

B

Step-by-step explanation:

Theorem: If a quadrilateral has 2 sets of opposite sides congruent, 2 sets of opposite angles congruent, and has consecutive angles which are supplementary, then it is a parallelogram.

Hope this helps!

Answer:

$254.20 -  5%= 241.49 US$

so you will save up to 14

Answer:

What do you mean?

Step-by-step explanation:

We know that :

⊕   Area of a Rectangle is given by : Length × Width

Let us calculate the Area of the Rectangle in the Left side of the figure

⇒   Area of Left Rectangle : (x - 3) (x + 2x)

⇒   Area of Left Rectangle : (x - 3) (3x)

⇒   Area of Left Rectangle : 3x² - 9x

Let us calculate the Area of the Rectangle in the right side of the figure

⇒   Area of the Right Rectangle : (x - 1)(x)

⇒   Area of the Right Rectangle : x² - x

Given : Combined area of both rectangles is 50 cm²

⇒   3x² - 9x + x² - x = 50

⇒   4x² - 10x = 50

⇒   2x² - 5x - 25 = 0

Comparing the above equation with ax² + bx + c = 0,

we can notice that :

→   a = 2

→   b = -5

→   c = -25

The function be f(x) = (6) then growth factor for the given equation (b) = 6.

Quantity grows exponentially over time. It happens when a quantity's instantaneous rate of change with regard to time is proportional to the quantity itself.

A function called exponential growth illustrates an expansion within a population that happens at the same pace across time. When a population's per capita growth rate remains constant across time, regardless of population size, exponential growth occurs, causing the population to grow exponentially as the population increases.

The general exponential growth function is given by :-

[tex]$f(t)=A b^t$[/tex] , where A is the initial amount , b is the growth factor and t is the time period.

The given function : [tex]$f(x)=(6)^x$[/tex]

When we compare it to the general exponential equation , we get

The growth factor for the given equation (b) = 6.

The complete question is:

Consider the function f(x) = (6)x. What is the value of the growth factor of the function?

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The function be f(x) = (6) then growth factor for the given equation (b) = 6.

Quantity grows exponentially over time. It happens when a quantity's instantaneous rate of change with regard to time is proportional to the quantity itself.

A function called exponential growth illustrates an expansion within a population that happens at the same pace across time. When a population's per capita growth rate remains constant across time, regardless of population size, exponential growth occurs, causing the population to grow exponentially as the population increases.

The general exponential growth function is given by :-

F(t) = AB^t, where A is the initial amount , b is the growth factor and t is the time period.

The given function : f(t) = (6)^x

When we compare it to the general exponential equation , we get

The growth factor for the given equation (b) = 6.

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The complete question is:

Consider the function f(x) = (6)x. What is the value of the growth factor of the function?

Step-by-step explanation:

A = (1/2)bh ---> h = 2A/b = 2(12 cm^2)/(5 cm) = 4.80 cm

---> x^2 = h^2 + (b/2)^2

= (4.8 cm)^2 + (2.5)^2

= 23.04 cm^2 + 6.25 cm^2

or x = 5.41 cm

Therefore, the perimeter P is

P = 2x + b = 2(5.41 cm) + 5 cm = 15.8 cm

The coordinate of N' is (2, -3)

Now, According to the question:

We have the point n (-2, -3) and we need to rotate it 270 degrees clockwise about the origin.

When rotating 270 clockwise about the origin you switch the x and y coordinate and use the opposite sign of the original y coordinate.

A(x, y) becomes A' (-y, x)

This means that point N becomes:

N (-2, -3) => N'(-(-2), (-3))

              => N'(2,- 3)

Hence, The coordinate of N' is (2, -3)

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Answer:

Step-by-step explanation:

Join line EG with a straight edge.

Put a point in the middle of the circle.

Call it O.

GO and EO form a central angle.

GOE = 120 degrees

Any point on the circumference of a circle that is on the same side of EG as the peak of the central angle = 1/2 the central angle. It's much easier to do this with an example

Arc EOG = 120 degrees.       The Central angle = the arc.

EFG = 1/2 EOG

EFG = 1/2 120

EFG = 60

11x + 5 = 60                           Given

     -5       -5                           Subtract 5 from both sides.

11x        = 55                           Divide by 11

x = 55/11

x = 5

Answer:

do your own work don't ask any question

Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

1.

Cylinder:

[tex]V = \pi r^{2}h[/tex]               *Plug in numbers*

[tex](3.14)(2.5)^{2}(7)[/tex]         *Square 2.5*

[tex](3.14)(6.25)(7)[/tex]        *Solve*

≈ [tex]137.375in^{3}[/tex]

Sphere:

[tex]V = \frac{4}{3}\pi r^{3}[/tex]              *Plug in numbers*

[tex]\frac{4}{3} (3.14)(2.5)^{3}[/tex]         *Cube 2.5*

[tex]\frac{\frac{4}{3}(3.14)(15.625)}{2}[/tex]         *Divide by 2 and Solve*

≈ [tex]32.7083 in^{3}[/tex]

Add both volumes

[tex]137.375 + 32.7083[/tex] ≈ [tex]170.083in^{3}[/tex]

2.

Cylinder:

[tex]V = \pi r^{2}h[/tex]         *Plug in numbers*

[tex]\pi (3)^{2}(10)[/tex]            *Square 3*

[tex]\pi (9)(10)[/tex]             *Multiply*

[tex]90\pi[/tex]

Sphere:

[tex]V = \frac{4}{3}[/tex] π [tex]r^{3}[/tex]            *Plug in numbers*

[tex]\frac{4}{3}\pi (3)^{3}[/tex]                   *Cube 3*

[tex]\frac{4}{3} \pi (27)[/tex]                   *Multiply*

[tex]36\pi[/tex]

Add both Volumes to get total

[tex]90\pi + 36\pi = 126in^{3}[/tex]

3.

Sphere:

[tex]V = \frac{4}{3}\pi r^{3}[/tex]              *Plug in numbers*

[tex]\frac{4}{3} (3.14)(3)^{3}[/tex]            *Cube 3*

[tex]\frac{4}{3} (3.14)(27)[/tex]            *Multiply*

[tex]113.04m^{3}[/tex]

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]             *Plug in numbers*

[tex]\frac{(3.14)(2)^{2}(5)}{3}[/tex]           *Square 2*

[tex]\frac{(3.14)(4)(5)}{3}[/tex]             *Solve*

[tex]20.93m^{3}[/tex]

Subtract the volumes to get the volume of the blue area

[tex]113.04 - 20.93 = 92.106m^{3}[/tex]

4.

Sphere:

[tex]V = \frac{4}{3} \pi r^{3}[/tex]            *Plug in numbers*

[tex]\frac{4}{3}\pi (8)^{3}[/tex]                 *Cube 8*

[tex]\\\frac{4}{3}\pi (512)[/tex]               *Multiply*

[tex]\\\\\pi (682.6)[/tex]              *Solve*

[tex]2133.66in^{3}[/tex]           *Divide by 2 since it's a hemisphere*

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]            *Plug in numbers*

[tex]\frac{\pi (8)^{2}(20)}{3}[/tex]              *Square 8*

[tex]\frac{\pi (64)(20)}{3}[/tex]              *Multiply and Divide*

[tex]1340.41 in^{3}[/tex]

Add both volumes

[tex]1072.33 + 1340.41 = 2412.74in^{3}[/tex]

5.

Cylinder:

[tex]V = \pi r^{2}h[/tex]            *Plug in numbers*

[tex]\pi (6)^{2}(16)[/tex]              *Square 6*

[tex]\pi (36)(16)[/tex]             *Multiply*

[tex]576\pi[/tex]

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]            *Plug in numbers*

[tex]\frac{\pi (6)^{2}3}{3}[/tex]                  *Square 6*

[tex]36\pi[/tex]

Add both volumes

[tex]576\pi + 36\pi = 612\pi m^{3}[/tex]

Alternative: *Multiply π*

[tex]1922m^{3}[/tex]

Answer:

1) 175 [tex]in^2[/tex]

2) 1st option

3) 92 [tex]m^2[/tex]

4) 2412 [tex]in^3\\[/tex]

5) 2nd option

Step-by-step explanation:

[tex]1)\ A = D * Pi = 5 * 3.14 = 15.7\\[/tex]

[tex]2)\ V_{1} = 15.7 * 7 = 109.9[/tex]

[tex]3)\ V_{2} = 4Pi*\frac{R^3}{3} = 12.56*\frac{15.625}{3} = 65.41(6)[/tex]

[tex]4)\ V_1 + V_2 = 65.4 + 109.9 = 175.3[/tex] which is close to 175

[tex]1)\ A = Pi * R^2 = 3.14 * (\frac{6}{2})^2 = 3.14 * 3^2 = 28.26\\[/tex]

[tex]2)\ V_1 = A * h = 28.26 * 10 = 282.6[/tex]

[tex]3)\ V_2 = \frac{4}{3} * Pi * R^3 = \frac{4}{3} * 3.14 * (\frac{6}{2})^3 = 113.04[/tex]

[tex]4)\ V_1 + V_2 = 282.6 + 113 = 395.6[/tex] which is very close to 396

[tex]5)\ 396 = 126 * pi[/tex]

[tex]1) V_1 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * 3.14 * 2^2 * 5 = 20.9(3)[/tex] =

[tex]2)\ V_2 = \frac{4}{3} * Pi * R^3 = \frac{4}{3} * 3.14 * 3^3 = 113.04\\[/tex]

[tex]3)\ V_2 - V_1 = 113.04 - 20.93 = 92.14[/tex] which is very close to 92

[tex]1)\ V_1 = \frac{\frac{4}{3} * Pi * R^3}{2} = \frac{\frac{4}{3} * 3.14 * 512}{2} = 1,071.786\\[/tex]

[tex]2)\ V_2 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * 3.14 * 64 * 20 = 1,339.733[/tex]

[tex]3)\ V_1 + V_2 = 1072 + 1340 = 2,411 = 2412[/tex]

[tex]1)\ A = Pi * R^2 = 36*Pi\\[/tex]

[tex]2)\ V_1 = 36*Pi * 16 = 576 * Pi\\[/tex]

[tex]3)\ V_2 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * Pi * 36 * 3 = 36 * Pi[/tex]

[tex]4) V_1 + V_2 = 576Pi + 36Pi = 612Pi[/tex]

Answer:

Step-by-step explanation:

a.[tex]1.9[/tex]·[tex]10^{-8}[/tex]=190000·[tex]10^{-13}[/tex]

b.so 190000÷4.2=4523

c.finally, about 4523 times

According to the given algebra Darla is 17 years old and Maria is 30 years old.

Numbers, parameters, constants, expressions, equations, linear equations, and quadratic equations are all part of the fundamentals of algebra. Additionally, the algebraic expressions contain the fundamental arithmetic operations of addition, subtraction, multiplication, as well as division.

Maria is 4 years younger than Don,

thus if Don is x years old, then Maria is x years younger. (2x-4)

If their ages added together equal 47,

then x + (2x-4) = 47

Solving for x, then determining Maria's age (2x-4)

3x=47+4

3x=51

x=51/3

x=17 years

Maria's age=2*17-4=30 years

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The third term of the arithmetic sequence will be negative 14.

A series of integers called an arithmetic succession or arithmetic chain of events has a fixed difference between the terms.

Let a₁ be the first term and d be a common difference.

Then the nth term of the arithmetic sequence is given as,

aₙ = a₁ + (n - 1)d

The first term is 20 and the common difference is calculated as,

aₙ = aₙ₋₁ - 17

aₙ - aₙ₋₁ = - 17

d = - 17

Then the third term is calculated as,

a₃ = 20 + (3 - 1) (-17)

a₃ = 20 + 2 (-17)

a₃ = 20 - 34

a₃ = - 14

The third term of the arithmetic sequence will be negative 14.

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Answer:

rectangular prism maybe

Step-by-step explanation:

The four names of an angle are acute angle, right angle, obtuse angle, and reflex angle.

An acute angle measures less than 90 degrees.

A right angle measures exactly 90 degrees.

An obtuse angle measures greater than 90 degrees but less than 180 degrees.

A reflex angle measures greater than 180 degrees but less than 360 degrees.

It's worth noting that these names are based on the measure of the angle, an acute angle is less than 90 degrees, a right angle is exactly 90 degrees, an obtuse angle is greater than 90 degrees but less than 180 degrees, and a reflex angle is greater than 180 degrees but less than 360 degrees.

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Answer:

Step-by-step explanation:

A. 62

B. 58

C. -19

The reasons and responses to the graphs in the question are as follows:

Graph 1.

The amplitude of the first graph is (1/2) which is the height from the midline to the peak

The value of the function at x = 0 is -(1/2), where sin(0) = 0, therefore, the function is a cosine function

The period of the graph is 2·π, which is the period of the parent cosine function

Therefore, the correct option is

Graph 2: Please find attached the graph of the function g(x) = 2×cos(x)

Graph 3: The frequency of a sinusoidal function is given as follows;

The period of the graph = π

Therefore;

The frequency of the sinusoidal graph is 2

Graph 4.  Required:

To find the equation that represents the function of the graph

Solution;

The period of the function, T = π

The graph of the function has a maximum at x = 0, therefore, the graph is similar to a cosine function, y = cos(B·x)

Where;

B = 2·π/T

Therefore;

B = 2·π/π = 2

Therefore;

The equation that represent the function in the graph is f(x) = cos(2·x)

Question 5. The given function is f(x) = cos(2·x)

The frequency factor in the given function, B = 2

The period, T = 2·π/B

Therefore, T = 2·π/2 = π

The period of the function, f(x) = cos(2·x), is 2

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[tex]sin(A)+cos(A)=\sqrt{2}\hspace{10em}tan(A)+cot(A)=2 \\\\[-0.35em] ~\dotfill\\\\ tan(A)+cot(A)=2\implies \cfrac{sin(A)}{cos(A)}+\cfrac{cos(A)}{sin(A)}=2 \\\\\\ \cfrac{sin^2(A)+cos^2(A)}{cos(A)sin(A)}=2\implies \boxed{\cfrac{1}{cos(A)sin(A)}=2} \\\\[-0.35em] ~\dotfill[/tex]

[tex]sin(A)+cos(A)=\sqrt{2}\implies (~~sin(A)+cos(A)~~)^2=(\sqrt{2})^2 \\\\\\ sin^2(A)+2sin(A)cos(A)+cos^2(A)=2 \\\\\\ 2sin(A)cos(A)+sin^2(A)+cos^2(A)=2\implies 2sin(A)+1=2 \\\\\\ 2sin(A)cos(A)=1\implies \boxed{2=\cfrac{1}{cos(A)sin(A)}}[/tex]

now, another way to look at this identity will  be as a unified system of equations

[tex]\begin{cases} (~~sin(A)+cos(A)~~)^2=2\\\\ ~~ ~tan(A)+cot(A)=2 \end{cases}\implies (~~sin(A)+cos(A)~~)^2=tan(A)+cot(A)[/tex]

and we'd end up with the same rigamarole.

Answer:

520 because 65 x 8 is 520

Step-by-step explanation:

Answer:

x= -5

Step-by-step explanation:

3x+3=2x-2

3x-2x=-3-2

x=-5

Answer:

x = -5

Step-by-step explanation:

First Expand the equation

3x+3 = 2x-2

Subtract 2x from both sides

x+3=-2

subtract 3 from both sides

x = -5

Hope this helps :)

Answer:

Step-by-step explanation:

I am assuming you mean the area of the shaded figure.

So, let's do it this way.

Let's subtract the total area from the unshaded area:

7 1/4 x 6 = 43 1/2

Area of non-shaded = 18 1/3

Area of shaded = 43 1/2 - 18 1/3 = 25 1/6

Hope that helps! :)

-Aphrodite

Answer:11 weekends

Step-by-step explanation:

it will take 11 weekends

An equation that could be used to determine the number of wreaths that Nicole could decorate using one spool of ribbon is:

                           W = S / R

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign.

An algebraic expression in mathematics is an expression created using variables, constant algebraic numbers, and algebraic operations. A good example of an algebraic expression is 3x2 2xy + c.

An equation that could be used to determine the number of wreaths that Nicole could decorate using one spool of ribbon is:

W = S / R

where W is the number of wreaths, S is the total length of ribbon on the spool, and R is the length of ribbon used per wreath.

Plugging in the given values, we get:

W = 20 / 2.5

Solving for W, we get:

W = 8

So Nicole could decorate 8 wreaths using one spool of ribbon.

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