A factory makes 1200 shirts every 6 hours. The factory makes shirts for 9 hours each workday. enter the fewest number of workdays the factory will need to make 12,600

Answer: 195

Step-by-step explanation:

(0.3x + 66) + (0.1x + 36) = 180. ( 180 because thats the angle of a straight line)

0.3x + 0.1x + 66 + 36 = 180

0.4x + 102 = 180

0.4x = 180 - 102

0.4x = 78

x = 195

Carlos's score in his first game was 14.

Addition in maths, a process of combining two or more numbers.

Given that, Carlos scored a total of 60 points in his last three basketball games. be improved in each game by scoring 6 more points than in the previous game.

Let the first score be x,

x+x+6x+6+6=60

3x+18 = 60

3x = 42

x = 14

Hence, Carlos's score in his first game was 14.

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Answer:

3000

Step-by-step explanation:

5430=1.81x

solving for x, we take 1, which is equal to 100%, and divide it by 1.81 to get 1/1.81 or 0.55248618

multiply 1/1.81 by 5430 to get 3000

Answer:

The area of AEBC is 36 cm²

hope it is helpful to you

Answer:

yes

Step-by-step explanation:

Answer:

412 (pls add the unit cuz i dont learn yd thx)

Step-by-step explanation:

13*12/2*4 + 10*10

= 312 + 100

= 412

9514 1404 393

Answer:

  d.  13

Step-by-step explanation:

The smallest number is 3.

The largest number is 16.

The range is the difference between these values:

  16 -3 = 13 . . . range of the data

The equation of the line that passes through the points (-2,3) and (2,7) is:

x-y=-5

Therefore, option(C) x-y= -5 is correct answer.

Step-by-step solution:

The algebraic representation of a line's equation is the collection of points that make up the line in a coordinate system.

Given the line passes through the points (-2,3) and (2,7)

So, the equation of the line passing through the two points is given by:

[tex]\frac{y-y_{1} }{y_{2}-y_{1} } =\frac{x-x_{1} }{x_{2} -x_{1} }[/tex]

[tex]\frac{y-3 }{7-3} } =\frac{x-(-2) }{2-(-2) }[/tex]

[tex]\frac{y-3}{4} =\frac{x+2}{2+2}[/tex]

[tex]\frac{y-3}{4} =\frac{x+2}{4}[/tex]

[tex]y-3 = x+2[/tex]

Now rearranging the above equation:

x - y + 3 + 2 = 0

x - y + 5 =0

Therefore, the equation of the line passing through the points (-2,3) and (2,7) is: x-y=-5

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Answer:

A

Step-by-step explanation:

The segment from the vertex to the base , bisects the base at right angles

Then there are 2 right triangles with legs x and 4 and hypotenuse [tex]\sqrt{52}[/tex]

Using Pythagoras' identity in either of the 2 right angles

x² + 4² = ([tex]\sqrt{52}[/tex] )²

x² + 16= 52 ( subtract 16 from both sides )

x² = 36 ( take the square root of both sides )

x = [tex]\sqrt{36}[/tex] = 6 → A

Answer:

Step-by-step explanation:

y=(x+4)+3

Answer:

y = x + 7

Step-by-step explanation:

Since y = x is a linear function, it may be confusing when using the translation tips you learned from class to solve it. However, there is an easy way to go about it.

1. Remember that when a function moves left, we use + inside of the parenthesis.

4 units left:

y = (x + 4)

2. Remember that when a function moves up, we use + outside of the parenthesis.

3 units up:

y = (x + 4) + 3

3. Add 'em up

y = x + 7

Since the function is linear, it may be confusing to see whether the graph moved up or left. However, by following the origin (0,0) of y = x and moving 4 units left and 3 units up, you will see that the origin has moved from (0,0) to (-4, 3), representing 4 units to the left and 3 units up on a graph.

Hope this helps :)

In response to the above problem, we may state that the triangle's - 5/13 measurements correspond to sin and cos.

The first six essential trigonometric functions are used in trigonometry. These functions are trigonometric ratios. The sine function, cosine function, secant function, co-secant function, tangent function, and co-tangent function are the six basic trigonometric functions. The side ratio of a right-angled triangle is equivalent to the identities and functions of trigonometry. Trigonometric formulas are applied to the perpendicular side, hypotenuse, and base of a right triangle in order to calculate the sine, cosine, tangent, secant, and cotangent values.

as base/hypotenuse = cos x

and sin x = hypotenuse/perpendicular

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Answer:

45ft is the missing length j.

Answer:

The percentage decrease is 25%.

Step-by-step explanation:

The difference in price is $2:

$8 - $6 = $2

Now to find the percentage decrease, we use the formula decrease in price divided by original price (or new/old) times 100:

2/8 * 100.

This equals 200/800 which is 25%.

Answer:

the other side is 5 i think

a) The function is continuous in it's entire domain.

b) The increasing and decreasing intervals for the function are given as follows:

A function f(x) is continuous at x = a if it is defined at x = a, and the lateral limits are equal, that is:

[tex]\lim_{x \rightarrow a^-} f(x) = \lim_{x \rightarrow a^+} f(x) = f(a)[/tex]

In this problem, we have a piece-wise function which has the definition changing at x = 2, hence the continuity must be studied at x = 2.

The lateral limits for the function in this problem are defined as follows:

The second limit is also equals to the numeric value at x = 2, due to the equal sign in the definition, hence the function is continuous at x = 2 and for all other values in the domain.

The intervals of increase and decrease are given as follows:

The function for this problem is the piece-wise function A(x).

Item a asks if the function is continuous.

Item b asks when the function is increasing and when it is decreasing.

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Answer:

the value of FJ would end up being 10

Answer:

10

Step-by-step explanation:

Answer:

D) 4b

Step-by-step explanation:

The required solution for the inequality a + 5 > -7 is (-12, ∞).

Inequality shows relation between two expression which are not equal to each others.

The given inequality is,

a + 5 > -7

To find the solution for the inequality,

Simplify the inequality,

a + 5 > - 7

a > - 7 - 5

a > -12

The value of a is greater than -12, implies that,

The solution for the value of the given inequality is (-12, ∞).

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By drawing a side on any one of the points, points X, Y, and Z can be used to create the circle.

It is described as a collection of points, each of which is spaced uniformly apart from a fixed point (called the centre of a circle)

First, draw three circles, each with the compass's drawing side on one of the points and the centre on another. The point of your compass should be on that point, and then you should place the drawing side on any one of the three points where they will all intersect in the middle.

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9514 1404 393

Answer:

  AB = 10

  BC ≈ 11.40

Step-by-step explanation:

The distance formula is useful for finding distances between points.

  d = √((x2 -x1)² +(y2 -y1)²)

  AB = √((18 -10)² +(4 -10)²) = √(8² +(-6)²) = √100

  AB = 10

__

  BC = √((25 -18)² +(-5-4)²) = √(7² +(-9)²) = √130

  BC ≈ 11.40

_____

A sketch tool can be useful for finding or checking the answer.

Given:

Two cards are drawn from a standard deck of cards without replacement.

To find:

The probability of drawing a heart and a club in that order.

Solution:

We have,

Total number of cards = 52

Number of cards of each suit (Spade, club, diamond, heart) = 13

The probability of drawing a heart card is:

[tex]P(Heart)=\dfrac{\text{Number of heart cards}}{\text{Total number of cards}}[/tex]

[tex]P(Heart)=\dfrac{13}{52}[/tex]

[tex]P(Heart)=\dfrac{1}{4}[/tex]

Now, the number of remaining card is 51. So, the probability of drawing a club card is:

[tex]P(club)=\dfrac{\text{Number of club cards}}{\text{Total number of remaining cards}}[/tex]

[tex]P(club)=\dfrac{13}{51}[/tex]

Using these probabilities, the probability of drawing a heart and a club in that order is:

[tex]P(\text{Heart and club})=P(\text{Heart})\times P(\text{Club})[/tex]

[tex]P(\text{Heart and club})=\dfrac{1}{4}\times \dfrac{13}{51}[/tex]

[tex]P(\text{Heart and club})=\dfrac{13}{204}[/tex]

Therefore, the required probability is [tex]\dfrac{13}{204}[/tex].

Answer:

942

I wish you luck! :D

give person above me brainliest since he/she/non-binary answered first

Answer:

942

Step-by-step explanation:

I just did this on a test and got 100% so I can verify this is right!

Answer:

No   g(x) = x/6     for (60, 10) to be a possible solution

by this function 60 people would have to donate 1/6th of a garment each to achieve 10 full garments

Step-by-step explanation:

g(x)   number of items

   x   number of people  

the data point (60, 10) make sense as a possilbe solution     NO

g(x) = number of items       x = 60   g(x) = 10

g(60) = x/6 = 10              

         = 60/10            

by this function 60 people would have to donate 1/6th of a garment each to achieve 10 full garments

Answer:

B

Step-by-step explanation:

N=4x0+12=12

Answer:

12

Step-by-step explanation:

N = 4m + 12 =

N = (4 x 0) + 12

N = 0 + 12 =

N = 12

Answer:

24xy - 32y

Step-by-step explanation:

4y × 6x =24xy

4y × -8 = -32y

brainliest plz? i got 1000+ points deleted

Answer:

4y(6x-8)

[tex]4y \times (6x - 8)[/tex]

[tex]4y \times - 6x + 8[/tex]

[tex] - 24xy + 8[/tex]

[tex] - 32xy[/tex]

Answer

Answer: a = -4

Step-by-step explanation:

Answer:

The test statistic is [tex]z = -2.1[/tex]

The p-value of the test is 0.0358 > 0.01, which means that the defective rates of the two suppliers are not significant different at the 1% significance level.

Step-by-step explanation:

Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

A simple random sample of 400 parts from supplier 1 finds 20 defective.

This means that:

[tex]p_1 = \frac{20}{400} = 0.05, s_1 = \sqrt{\frac{0.05*0.95}{400}} = 0.0109[/tex]

A simple random sample of 200 parts from supplier 2 finds 20 defective.

This means that:

[tex]p_2 = \frac{20}{200} = 0.1, s_2 = \sqrt{\frac{0.1*0.9}{200}} = 0.0212[/tex]

Let p1 and p2 be the proportion of all parts from suppliers 1 and 2, respectively, that are defective. Test whether the defective rates of the parts from two suppliers are significant different at the 1% significance level.

At the null hypothesis, we test if they are equal, that is, if the subtraction of the proportions is 0. So

[tex]H_0: p_1 - p_2 = 0[/tex]

At the alternate of the null hypothesis, we test if they are different, that is, if the subtraction of the proportions is different of 0. So

[tex]H_a: p_1 - p_2 \neq 0[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{s}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that [tex]\mu = 0[/tex]

From the sample proportions:

[tex]X = p_1 - p_2 = 0.05 - 0.1 = -0.05[/tex]

[tex]s = \sqrt{s_1^2+s_2^2} = \sqrt{0.0109^2 + 0.0212^2} = 0.0238[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{s}[/tex]

[tex]z = \frac{-0.05 - 0}{0.0238}[/tex]

[tex]z = -2.1[/tex]

P-value of the test and decision:

The p-value of the test is the probability that the sample proportion differs from 0 by at least 0.05, that is, P(|z| < 2.1), which is 2 multiplied by the p-value of Z = -2.1.

Z = -2.1 has a p-value of 0.0179

2*0.0179 = 0.0358.

The p-value of the test is 0.0358 > 0.01, which means that the defective rates of the two suppliers are not significant different at the 1% significance level.