The work done to the mower is the product of the external force applied on the object and the distance covered by the object which is equal to 40,811 Joules.
What is Work done?Work done on an object can be defined as the product of external force applied on the object and the distance over which the force is being applied on the object. Work is done on an object when a force is applied to an object and the object is moved through certain distance.
From this we can see that the horizontal component of the force:
X-Component (horizontal component):
cos(θ) = x/F
Then,
X= F cos(θ).…..(1)
Now putting the values of F and θ in equation (1) we get,
X = 72 N × cos(40)
X = 72 N × 0.766
X= 55.15 N this is the x-component force
The work done to the mower is:
W = F × d
W = 55.15 × 740
W = 40,811 Joules
The work done to the mower is 40811 Joules.
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What is the answer please help help ( science)
Answer:
Number 19
10 x 7.2
72N
Explanation:
20.
1.66 x 7.2
11.9
Which is approximately
12N
As an object falls freely, the potential energy of the object
9. All of the following are adaptations of herbivores EXCEPT:
special digestive systems for digesting plant cellulose
Okeen eyesight for sporting prey
O coat colors that help them blend in with the land
fut teeth for chewing tough plant matter
PLZ HURRY PLZ IMM MARK BRAINLYEST
Answer:
B.KEEN EYESIGHT thats for predators !
Explanation:
Herbivores have multiple stomachs to process tough foods, coats to blend in so they don't get eaten, and tough teeth for chewing on the plants. THEY DO NOT HAVE PREY, THEY ARE THE PREY.
What is the average time for the toy car to move 1.0 m on cement?
Answer:
24.4
Explanation:
you would add all the numbers , 25.5+24.4+24.2= 73.1/3=24.36 and you round up you get 24.4
an electric train moving at 5m/s accelerates to a speed of 8m/s in 20 seconds. Fine the distance travelled in meters during the period of acceleration
===================================================
Explanation:
vi = 5 and vf = 8 are the initial and final velocities respectively. The change in time is t = 20 seconds.
So,
x = 0.5*(vi + vf)*t
x = 0.5*(5+8)*20
x = 130 meters
represents the distance traveled. The first equation shown above is one of the four kinematics equations.
5.33 A constant force F= (4.70-379, 2.09) N. acts on an object of mass 180 kg, causing a displacement of that object by F= (4.25, 3.69-245) m What is the total work done by this force
The total work done by this force is 28.9-1457.86 N m.
What is total work?Total work is the sum of all the energy expended in completing a job or task. It is the amount of effort and energy expended to accomplish a goal or complete a task. Total work can be calculated by adding up all of the individual components of the job or task, such as time, effort, and materials.
The total work done by this force can be calculated using the formula W = F * Δx, where F is the force vector, and Δx is the displacement vector. In this case, the total work done is:
W = (4.70-379, 2.09) * (4.25, 3.69-245) = (19.9-944.81, 8.00-513.05) N m
Therefore, the total work done is 28.9-1457.86 N m.
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1. What is a node?
2. What is an antinode?
3. What is a wavelength?
Will mark brainliest if correct!!
Answer:
Node:-
A node is a point along a standing wave where the wave has minimum amplitude. For instance, in a vibrating guitar string, the ends of the string are nodes. By changing the position of the end node through frets, the guitarist changes the effective length of the vibrating string and thereby the note played.
Anti Node:-
An antinode is simply a point along a medium which undergoes maximum displacement above and below the rest position.
Wavelength:-
The total length of circle.
or
Wavelength can be defined as the distance between two successive crests or troughs of a wave.
Millikan used tiny oil droplets and adjusted the electric field until the electric force balanced the weight of the droplet, and one of the droplets hovered in air. However, the drops are all different sizes and weights, and the amount of charge on each droplet also varies. So, the tuning of the electric field is different for droplets of different sizes, which carry different charges. Let us assume that the density of the oil Millikan used in his experiment is 800 kg m3
A. Calculate the mass (in kg) of the hovering droplet if its radius is measured to be 65 um.
B. Calculate the electric field (in V/m) required to counter the weight of the above droplet if it carries a charge q = 2e.
C. In the second trial, the hovering droplet has a mass of 10-15 kg. It carries a charge of q = 11e. calculate the electric field (in V/m) required to counter the weight of this droplet.
Answer:
A. 9.203 × 10⁻¹⁰ kg
B. 2.82 × 10¹⁰ V/m
C. 5.56 × 10³ V/m
Explanation:
A. Calculate the mass (in kg) of the hovering droplet if its radius is measured to be 65 um.
We know density, ρ = mass of oil drop, m/volume of oil drop, v
m = ρv
ρ = 800 kg/m³ and v = 4πr³/3 (ince the oil drop is a sphere) where r = radius of oil drop = 65 μm = 65 × 10⁻⁶ m.
So, m = ρv = ρ4πr³/3
= 800 kg/m³ × 4π(65 × 10⁻⁶ m)³/3
= 800 kg/m³ × 4π274625 × 10⁻¹⁸ m³/3
= 878800000π × 10⁻¹⁸ kg/3
= 2760831623.97 × 10⁻¹⁸ kg/3
= 920277207.99 × 10⁻¹⁸ kg
= 9.203 × 10⁻¹⁰ kg
B. Calculate the electric field (in V/m) required to counter the weight of the above droplet if it carries a charge q = 2e.
Since the electric force F = qE where q = charge on oil drop = 2e where e = electron charge = 1.602 × 10⁻¹⁹ C and E = electric field equals the weight of the oil drop W = mg where m = mass of oil drop = 9.203 × 10⁻¹⁰ kg and g = acceleration due to gravity = 9.8 m/s².
So, F = W
qE = mg
E = mg/q
E = mg/2e
substituting the values of the variables into the equation, we have
E = 9.203 × 10⁻¹⁰ kg × 9.8 m/s²/(2 × 1.602 × 10⁻¹⁹ C)
E = 90.1894 × 10⁻¹⁰ kg-m/s²/3.204 × 10⁻¹⁹ C
E = 28.15 × 10⁹ V/m
E = 2.815 × 10¹⁰ V/m
E ≅ 2.82 × 10¹⁰ V/m
C. In the second trial, the hovering droplet has a mass of 10-15 kg. It carries a charge of q = 11e. calculate the electric field (in V/m) required to counter the weight of this droplet.
Since F = W
qE = mg
E = mg/q
E = mg/11e
E = 10⁻¹⁵ kg × 9.8 m/s²/(11 × 1.602 × 10⁻¹⁹ C)
E = 9.8 × 10⁻¹⁵ kg-m/s²/17.622 × 10⁻¹⁹ C
E = 0.556 × 10⁴ V/m
E = 5.56 × 10³ V/m
To understand the nature of electric fields and how to draw field lines In (Figure 2), what is wrong with panel B7 (Pick only those statements that apply to panel B) Electric field lines are a tool used to visualize electric foiled
Part B
In (Figure 2), what is wrong with panel B? (Fick only those statements that apply to panel B) Check all that apply.
Field liner caneot cross each other
The fold lines should be paraller becauze of the sheers symunner.
The field lnes chould spread apart as they leare the sheet to indiate mhr woakering of the field with gistance.
The field lines should always end on negative charges of at infinity.
in panel B, the field lines do end on negative charges, so this is not a problem No credit lost Try again D Submit Previous Answers
In (Figure 2), the wrong with panel B is: Field line can not cross each other the field lines should be parallel because of the sheers summoner.
What is electric field line?In general, an electric field line is a curve drawn with each point's tangent pointing in the direction of that point's net field. To designate the direction of the electric field from the two potential directions provided by a tangent to the curve, an arrow on the curve is obviously required. A field line is a space curve, or a three-dimensional curve.
The wrong with panel B is: Field line can not cross each other.
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A laser beam is incident on two slits with a separation of 0.180 mm, and a screen is placed 5.05 m from the slits. If the bright interference fringes on the screen are separated by 1.62 cm, what is the wavelength of the laser light
Answer:
The answer is "530 nm".
Explanation:
[tex]d=0.180 \ nm=0.180 \times 10^{-3} \ m\\\\L= 5.05\ m\\\\\Delta y= 1.62\ cm= 1.62 \times 10^{-2} \ m\\\\[/tex]
Using formula:
[tex]\Delta y=\frac{\lambda L}{d}\\\\\lambda =\frac{d\Delta y}{L}\\\\[/tex]
[tex]=\frac{0.180 \times 10^{-3} \times 1.62 \times 10^{-2} }{5.05}\\\\=5.30 \times 10^{-9} \times \frac{1 \ nm}{10^{-9} \ m}\\\\=530 \ nm[/tex]
The rabbit flea Spilopsyllus has a mass of 0.45 mg. It can jump vertically to aheight of about 3.5 cm. Biologists have hypothesized that the energy for the jump is most likely derived from the elastic potential energy stored in the resilin pads ofthe two rear legs of the flea. Each pad is estimated to have a volume of about and its strain typically reaches a value of 100%. The elastic modulus of resilience is about . Is the hypothesis plausible
Answer:
Therefore The hypothesis is not plausible Because
[tex]P.E \geq P.E_e[/tex]
[tex]P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J[/tex]
Explanation:
From the question we are told that:
Mass [tex]M=0.45mg[/tex]
Jump height [tex]h=3.5cm \approx 0.03m[/tex]
Percentage strain [tex]\mu =100\%[/tex]
Generally the equation for potential energy is mathematically given by
[tex]P.E=mgh[/tex]
[tex]P.E=0.45*10^{-3}*9.8*0.03[/tex]
[tex]P.E=12.435*10^{-5}J[/tex]
Generally the equation for Elastic potential energy is mathematically given by
[tex]P.E_e=0.5*stress*strain *volume[/tex]
[tex]P.E_e=0.5*1*2*10^6*1*1.4*10^{-4*(10^-3)^3}[/tex]
[tex]P.E_e=1.4*10^{-7}J[/tex]
The hypothesis is only plausible at conditions where
[tex]P.E\leq P.E_e[/tex]
Therefore The hypothesis is not plausible Because
[tex]P.E \geq P.E_e[/tex]
[tex]P.E=12.435*10^{-5}J \geq 1.4*10^{-7}J[/tex]
Why do nuclear power plants use fission rather than fusion to generate
electric energy?
A. Fusion requires very high pressure and temperature.
B. A problem might lead to an explosion in a fusion reactor, but not
in a fission reactor.
C. The isotope used in fission is more common than the one used
in fusion.
D. Fission produces less radioactive waste than fusion does.
Answer:
A. FUSION REQUIRES VERY HIGH PRESSURE AND TEMPERATURE
Explanation:
Fission is used in nuclear power reactors since it can be controlled, while fusion is not utilized to produce power since the reaction is not easily controlled and is expensive to create the needed conditions for a fusion reaction.
Nuclear Power Plants uses Nuclear Fission over Nuclear Fusion to generate electric energy because "Nuclear Fusion requires very high pressure and temperature".
What is Nuclear Fission?Nuclear fission is a reaction in which the nucleus of an atom splitting into two or more smaller nuclei and this process produces gamma photons and releases large amount of energy by the energetic standards of radioactive decay.
The Nuclear Fission process was discovered by Hahn, Strassman and Meitner in 1938.
What is Nuclear Fusion?Nuclear Fusion is a reaction in which two or more Atomic Nuclei are combined together to form one or more different atomic nuclei and subatomic particle.
The difference in mass between the reactants and products is manifested as either the release or the absorption of energy.
Robert Atkinson and Fritz Houtermans in 1929 measured masses of light elements to show that large amounts of energy could be used released by fusing small nuclei.
Nuclear Fusion cant be used as a source of energy for heat and electricity generation because developing technology for the required purpose is the subject of ongoing research which is at its nascent stage because to reach to Nuclear Fusion , one requires very high pressure and temperature and to reach such point in one closed area is quite a herculean task.
But Scientists are working towards Nuclear Fusion as it is more advantageous over Nuclear Fission and less pollutant.
Therefore, the correct answer will be option (A)
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What makes water move through the water cycle? A the sun the rain C precipitation the ground
Answer: A. The Sun
Explanation: A. The Sun makes water move through the water cycle
Which letter of the following shows lateral inversion in a mirrior
i.A
ii.N
iii.M
iv.V
Answer:
ii. N
Explanation:
N is not laterally symmetrical. so it shows inversion in a mirror.
Answer:
ii) N
hope it is helpful to you
Differentiate between mass and weight
Answer:
The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass.
Explanation:
Part A : A cylindrical water tank 10cm high and 520cm in diameter is filled with solution with a density of 0.75 g/cm^3
a) What is the water pressure on the bottom of the tank? (pressure in psi)
Show calculations
b) What is the average force on the bottom?
Answer: [tex]0.1066\ psi, 15.611\ kN[/tex]
Explanation:
Given
the height of the tank is [tex]h=10\ cm[/tex]
The diameter of the tank is [tex]d=520\ cm[/tex]
Density of solution [tex]\rho=0.75\ g/cm^3\ or\ 750\ kg/m^3[/tex]
[tex](a)[/tex] Water pressure at the bottom of the tank is
[tex]P=\rho gh\\P=750\times 9.8\times 0.1\\P=735\ Pa[/tex]
[tex]1\ Pa=0.000145038\ psi[/tex]
[tex]\Rightarrow P=735\ Pa\ or\ 0.1066\ psi[/tex]
[tex](b) \text{Average force on the bottom is the product of pressure and area of the base}[/tex]
[tex]F_{avg}=735\times \pi \cdot (\frac{520}{200})^2\\\\F_{avg}=735\times 3.142\times 6.76\\F_{avg}=15,611.34\ N\ or\ 15.611\ kN[/tex]
______________ is the study of motion in fluids.
Hydrodynamics
Acceleration
Aerodynamics
Resistance
Answer:
i think its Hydrodynamics
Explanation:
because hydro is fluid
Which of the following light waves will have the highest frequency?
a. blue light
b. orange light
c. green light
d. red light
e. yellow light
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2. How can we make the percent error value as minimal as possible?
Answer:
Percent error can be reduced by improving both your accuracy and precision.
Answer:
Percent error can be reduced by improving both your accuracy and precision.
Explanation:
Kam does 4000J of work in climbing a set of stairs. if he does work in 6 seconds, whi is his power output?
Answer:
666.7 W
Explanation:
Power = P = W/t = 4000 J/6 s = 666.7 W (watts)
If could watch a rocket that's putting a satellite into orbit around the Earth, you'd see that it doesn't just go straight up. It eventually leans over and flies basically parallel to the Earth's surface when it gets up high. Why does it do this?
a. It needs to stay close to the Earth, so that the satellite doesn't get affected by the gravity of the Moon.
b. It needs to be moving horizontally at a high speed, in order for the satellite to stay in orbit once it's released from the rocket.
c. It has to release the satellite inside the Earth's atmosphere.
d. If it doesn't turn over horizontally, it'll release the satellite in a region where there's no gravity.
Answer:
the correct answers B
It needs to be moving horizontally at a high speed, in order for the satellite to stay in orbit once it's released from the rocket.
Explanation:
In this exercise, let's look for the solution to the problem before reviewing the statements to find out which one is correct.
When the satellite is in orbit it must comply with Newton's law
F = m a
the force of the universal attractive force and the acceleration is centripetal
a = v² / r
we substitute
- G m M /r² = -m v² / r
v² = G M / r
v = [tex]\sqrt{\frac{GM}{r} }[/tex]
When analyzing this expression, the satellite is in a stable orbit because its centripetal acceleration creates a change in the direction of the velocity in such a way that it remains in an orbit
when reviewing the correct answers B
What is true about the direction of the force of friction? A. It always points straight down. B. It always opposes the direction of motion. C. It always points straight up. D. It never changes direction.
Answer: it always opposes the directions of motion is the right answer
Explanation:
An object of mass 25kg is falling from the height h=10 m. calculate
a. The total energy of an object at h=10m.
b. Potential energy of the object when it is at h= 4m
c. Kinetic energy of the object when it is at h= 4m
d. What will be the speed of the object when it hits the ground?
Answer:
a. E = 2452.5 J = 2.45 KJ
b. P.E = 981 J = 0.98 KJ
c. K.E = 1471.5 J = 1.47 KJ
d. vf = 14 m/s
Explanation:
a.
At the highest point the total energy is equal to the potential energy of the object:
E = Potential Energy = mgh
where,
E = Total energy =?
m = mass of object = 25 kg
g = acceleration due to gravity = 9.81 m/s²
h = height = 10 m
Theerfore,
E = (25 kg)(9.81 m/s²)(10 m)
E = 2452.5 J = 2.45 KJ
b.
P.E = mgh
where,
h = 4 m
Therefore,
P.E = (25 kg)(9.81 m/s²)(4 m)
P.E = 981 J = 0.98 KJ
c.
First, we will find the velocity at 4 m by using the third equation of motion:
[tex]2gh = v_f^2-v_i^2[/tex]
where,
h = height lost = 10 m - 4 m = 6 m
vf = final speed = ?
vi = initial speed = 0 m/s
Therefore,
[tex]2(9.81\ m/s^2)(6\ m) = v_f^2-(0\ m/s)^2\\v_f = \sqrt{117.72\ m^2/s^2} \\v_f = 10.85\ m/s[/tex]
Hence, the kinetic energy will be:
[tex]K.E = \frac{1}{2} mv_f^2\\\\K.E = \frac{1}{2} (25\ kg)(10.85\ m/s)^2[/tex]
K.E = 1471.5 J = 1.47 KJ
d.
We will find the velocity at the bottom by using the third equation of motion:
[tex]2gh = v_f^2-v_i^2[/tex]
where,
h = height lost = 10 m
vf = final speed = ?
vi = initial speed = 0 m/s
Therefore,
[tex]2(9.81\ m/s^2)(10\ m) = v_f^2-(0\ m/s)^2\\v_f = \sqrt{196.2\ m^2/s^2} \\[/tex]
vf = 14 m/s
The cooler star, the most ____ it is.
a) more luminous
b) more blue
c) redder
Answer:
c. more redder
def not blue cuz thats hottest and def not luminous
Answer:
it is c... redder
Explanation:
because i just look it up on googl3
If a Current Current of strength 3A flows through aresistance of 20 om for 10 minutes,then calculate the amount of heat produced in the resistance.
Answer:
1.08 x 10^5 J
Explanation:
First, apply the formula V = IR , where V is the voltage, I is the current and R is the resistance.
R -> 20 ohm (Given)
I -> 3A (Given)
Hence, V = 3 x 20 = 60V (60 volts)
Next, apply the formula E = Pt , where E is the energy produced, P is the power and t is the time in seconds
Furthermore, since P = IV (power = current x voltage)
The formula can be re-expressed as E = VIt
t -> 10 minutes = 600 seconds (don't forget to convert time to seconds!)
Therefore, energy = (60 x 3 x 600) J
= 108000 J
= 1.08 x 10^5 J (in scientific notation)
Hea produced in the resistance = energy produced in the resistor
= 1.08 x 10^5 J
In a particular crash test, an automobile of mass 1759 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 12 m/s and 2.2 m/s, respectively. If the collision lasts for 0.11 s, find the magnitude of the impulse due to the collision. Answer in units of kg · m/s. Calculate the magnitude of the average force exerted on the automobile during the collision. Answer in units of N.
Based on the data provided about the collision;
the magnitude of the impulse due to the collision is 21105.8 kg.m/sthe magnitude of the average force exerted on the automobile during the collision is 191870.91 NWhat is the magnitude of the impulse due to the collision of the vehicle with the wall?The magnitude of the impulse due to the collision of the vehicle with the wall is calculated using the formula of the impulse on an object given below as follows:
Impulse = change in momentum
Change in momentum = m(v - u)
where;
m is mass
v is the final velocity
u is the initial velocity
Impulse = 1759 (12 - 22)
Impulse = 21105.8 kg.m/s
The average force on the automobile will be:
Force = impulse/time
Force = 21105.8 / 0.11
Force = 191870.91 N
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Which describes the relationship between the frequency, wavelength, and speed of a wave as the wave travels through different media?
As speed changes, wavelength changes and frequency remains constant
As speed changes, frequency changes and wavelength remains constant As speed changes, wavelength and frequency change,
O As speed changes, wavelength and frequency remain constant
Answer: A) as speed changes, wavelength changes and frequency remains constant
Explanation: edg test
What is f if you have an object 2.0 m from the concave mirror, and the image is 4.0 m from the mirror?
Answer:
the f is 1.3 m
Explanation:
Given that
An object 2.0m is from the concave mirror
And, the image is 4.0m from the mirror
We need to find out the f
So,
u = -2 m
v = -4 m
1 ÷ f = 1 ÷ v + 1 ÷ u
= (-1 ÷ 4) + (-1 ÷ 2)
= -3 ÷4
f = -4 ÷ 3
= |1.3| m
Hence, the f is 1.3 m
A car is travelling at 27m/s and decelerates at a=5m/s2 for a distance of 10m. Calculate its final velocity. (Hint does deceleration imply that the acceleration is positive or negative?)
If deceleration = 5 m/s²
then acceleration = -5 m/s²
According to third law of motion,
= v² = 2as + u²
= v² = 2×-5×10 + 27²
= v² = -100 + 729
= v =√ 629
= 25.08 m/s
A snowboarder on a slope starts from rest and reaches a speed of 3.4 m/s after 7.3 s.
The acceleration of the snowboarder is 0.466 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the acceleration of the snowboarder, we use the formula below.
Formula:
a = (v-u)/t........................ Equation 1Where:
a = Accelerationv = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 3.4 m/su = 0 m/st = 7.3 sSusbtitute these values into equation 1
a = (3.4-0)/7.3a = 0.466 m/s²Hence, the acceleration is 0.466 m/s².
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