A small block sits at one end of a flat board that is 2.50 m long. The coefficients of friction between the block and the board are μs = 0.450 and μk = 0.400. The end of the board where the block sits is slowly raised until the angle the board makes with the horizontal is α0, and then the block starts to slide down the board.

Answer:

1.11 watts

Explanation:

power =  joules / sec

           184/45 = 1.11 Watts

Answer:

From this equation, it can be said that the escape velocity depends on the radius of the planet and the mass of the planet only and not on the mass of the body. Escape Velocity of Earth= 11.2 km/s. This was the derivation of the escape velocity of earth or any other planet.

Explanation:

The Magnetic field strength as a function of time will be 2.4 ×10⁻¹¹ T.it is denoted by B.

The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength

Given

The radius of cylinder is,R=2.8 mm = 0.028 m

[tex]\rm \oint B.ds = \frac{\mu_0 \epsilon_0 d\phi}{dt} \\\\ B \times 2\pi r = \frac{\mu_0 \EPSILON_0 d (EA)i}{dt} \\\\\ b = \frac{\mu_0 \epsilon_0 \times \PI r^ 2 d(E)}{dt} \times \frac{1}{2\pir} \\\\ B= \frac{\mu_0 \epsilon_0 \times rd (E)}{2dt} \\\\ B= \frac{1.26 \times 10^{-5}\times 8.85 \times 10^{-12}\times (3.2 \times 10^{-3})\times 1.4 \times 10^8}{2} \\\\ B =2.4 \times 10^{-11} \ T[/tex]

Hence, magnetic field strength as a function of time will be 2.4 ×10⁻¹¹ T.

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Answer:

the theorist that I chose is John Watson. He focused on the behaviors of a person on the outside. “He believed that a person’s physical responses provided the only insight into internal actions.”[ CITATION Goo15 \l 1033 ] He believed that behaviors are learned, as with the rat white and “Albert”. He taught “Albert” to fear the rat by making a sound any time the rat was shown. “Through learning, an initially neutral stimulus, the white rat, had become a stimulus for fear.”[CITATION Car17 \p 41 \l 1033

Explanation:

this is the answer

The biologist who had summarized the theory to explain the aspects of the theory is john watson.

Who was john watson?

John B. Watson was a trailblazing psychologist who made significant contributions to the growth of behaviorism. Watson thought that the main focus of psychology should be on observable behavior in science. He is famous for his studies on the process of conditioning.

Watson is particularly well-known for the Little Albert experiment, in which he showed how a young kid may be taught to fear a stimulus that was previously neutral. Additionally, his studies shown that this phobia might extend to other similar things.

Therefore, The biologist who had summarized the theory to explain the aspects of the theory is john watson.

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Answer:

the answer is equal to 2.00v

The voltage drops across 10 Ω resistance with voltage 120V is 20 V. Hence, option B is correct.

The potential difference between two points is defined as the amount of work done in moving a unit of positive charge from one point to another. The potential difference or voltage is measured in volts(v).

According to Ohm's law, voltage is directly proportional to the current flow in the circuit. Voltage drop in the circuit is defined as a decrease in electric potential along the path of the current in the circuit.

The voltage drop occurs because of the current flow in the circuit. It is related to resistance and impedance to the current flow in the circuit.

From the given,

the resistors are connected in series,

R(eq) = R₁ + R₂ + R₃

         = 10 + 20 + 30

        = 60 ohm

The equivalent resistance is 60 ohms.

To find current by using Ohm's law:

V= I×R

I = V/R

 = 120/60

= 2 A

The current flow in the circuit is 2 amperes.

To find voltage drop:

V= I×R

 = 2×10

 = 20 V

The voltage drop across the resistor 10Ω is 20 V.

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Hi there!

We can use Newton's Second Law:
[tex]\Sigma F = ma[/tex]

ΣF = Net force (N)
m = mass (kg)
a = acceleration (m/s²)

We can rearrange the equation to solve for the acceleration.

[tex]a = \frac{\Sigma F}{m}\\\\a = \frac{24}{4} = \boxed{6 \frac{m}{s^2}}[/tex]

The statement that is true about height and strength is that In boys, the strength spurt occurs about a year after their height spurt

Puberty is the transformational change that occur between childhood and adulthood. It is a stage of maturity

Height of a person is the distance from the feet of a person to the peak or his head.

Strength is the ability of a person to be very strong and can do vigorous things.

Therefore, The statement that is true about height and strength is that In boys, the strength spurt occurs about a year after their height spurt.

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When an item is raised, the work is done in opposition to gravity. When an item is worked on, energy is transmitted to it, and it develops gravitational potential energy. If the same thing falls from that height, gravity must do the same amount of effort to bring it back to the Earth's surface.

Answer:

Part 1: 0.3789

Part 2: 746 J

Part 3: 2.162 kW

Explanation:

Part 1:

Eff=  [tex]1-\frac{1223}{1969}[/tex]

Eff= 0.378873 ≈ 0/3789

Part 2:

W= 0.3789(1969)

W= 746 J

Part 3:

[tex]Power=\frac{W}{t}[/tex]

[tex]Power= \frac{746}{0.345}[/tex]

Power= 2162.3188 Watts

2162.3188 W-----> 2.162 kW

Answer:

Fnet = 45N

Explanation:

Fnet = m.a

= (15)(3)

= 45N

Answer:

option d is the answer of given statement

The surface area of the right cone is 54π units². Hence option D correct.

The surface area of a solid object is a total area measured that the surface of the object occupies. the surface area of the cube is 6 times side², cause it has 6 faces.

The surface area is total area occupied by the surface of the object.

A cone is geometrical shape which is having circular base and cone shaped body. when a line is drawn from tip to the center of the base it will make right angle between radius and height of the cone. We can apply Pythagoras theorem to get values of radius, height and hypotenuse.

The total area of the cone is nothing but area of the base plus curved area of the body.

Hence area of the cone is,

A = πr²+πr[tex]\sqrt[]{r^{2}+h^{2} }[/tex]

Given,

r = 3

hypotenuse = [tex]\sqrt[]{r^{2}+h^{2} }[/tex] = 15

A = ?

A = π3²+π3*15

A = π (9+45)

A = 54π units²

Hence area of the cone is 54π units².

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Answer:

[tex] \boxed{ \sf \: \Delta S = 0.219J /K}[/tex]

Explanation:

Given:

mass of substance (water) = 2 g

initial temperature= 0°C = 273.15 K

final temperature= 234°C= 507.15

thermal capacity = 1 J/kg.M

latent heat of vaporization = 54 J/Kg

To find:

Entropy change ∆S = ?

Solution:

Entropy is measure of randomness of a system.

The change in entropy can be calculated in many ways depending upon the nature of substance & process like solid or liquid in isothermal process and when the process is not isothermal, gases are real or ideal etc.

If the process is isothermal (Temperature doesn't change) then the general equation to find change in entropy is,

[tex]\sf \Delta S = \frac{ q_{rev}}{T}= state \: function[/tex]

If the temperature of reaction is changing then change in entropy can be calculated by

[tex] \sf \: \Delta S = nC_p ln \frac{T_f}{T_i} [/tex]

Where n is number of moles of substance,

Cp is thermal capacity,

& T f and Ti are final and initial temperature respectively.

In the above reaction the water is being heated from 0°C (liquid) to 234°C (steam), the number of processes happening is

Calculating the number of moles of substance,

Given mass of water= 2g

Molecular mass of water = 18 g

[tex] \sf n = \frac{given \: mass \:}{molar \: mass} = \frac{2}{18} = 0.11moles[/tex]

Change in entropy for physical process 1,

The initial temperature of water is 0°C(273.15 K), and the water turns into vapour at 100°C (373.15 K), this is a purely heating of liquid at constant pressure, hence the formula that would be used is,

[tex]\sf \: \Delta S_1 = nC_p ln \frac{T_f}{T_i} \\ \sf \: \Delta S_1 = 0.11 \times 1 \times ln \frac{373.15}{273.15} \\ \sf \: \Delta S_1 = 0.11 \times ln 1.366 \\ \sf \: \Delta S_1 = 0.11 \times 0.311 \\ \sf \: \Delta S_1 = 0.0343 J/K[/tex]

At boiling point of water the change in entropy for phase transformation of liquid water to gaseous vapours at 100°C can be calculated,

Now the latent heat of vaporization (∆H) is given,

(Latent heat is the heat which is required to change the phase of any substance)

Substituting the data,

[tex]\sf \: \Delta S_2 = \frac{\Delta H}{T} \\ \sf \: \Delta S_2 = \frac{54}{373.15} \\ \sf \: \Delta S_2 = 0.145 J/K[/tex]

Now the third and final physical process of heating vapours from 100°C to 234°C, at constant pressure,

[tex] \sf \: \Delta S_3 = nC_p ln \frac{T_f}{T_i} \\ \sf \: \Delta S_3 = 0.11 \times 1 \times ln \frac{507.15}{373.15} \\ \sf \: \Delta S_3 = 0.11 \times ln 1.359 \\ \sf \: \Delta S_3 = 0.11 \times 0.306 \\ \sf \: \Delta S_3 = 0.0337J/K[/tex]

The total entropy change ∆S during the process is,

[tex] \sf \: \Delta S = \Delta S_1+ \Delta S_2 + \Delta S_3 \\ \sf \: \Delta S = 0.0343+ 0.145 + 0.0337 \\ \sf \: \Delta S = 0.219J/K[/tex]

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Answer:

Answer:

Magnetism is the force of attraction or repulsion between substances.

Magnetism is defined as an attractive and repulsive phenomenon produced by a moving electric charge. The affected region around a moving charge consists of both an electric field and a magnetic field. The most familiar example of magnetism is a bar magnet, which is attracted to a magnetic field and can attract or repel other magnets.Magnetism is caused by the electromagnetic force, which is one of the four fundamental forces of nature. Any moving electric charge (electric current) generates a magnetic field perpendicular to it.

Answer:

Explanation:

The chart shows data for four moving objects.

Object

Initial Velocity

Final Velocity

Change in

(m/s)

(m/s)

Time (s)

29

6

X>N

10

34

12

12

40

20

28

8

Which object has the greatest acceleration?

W

x

Y

Answer:

the liquid state

Explanation:

because the particles can move about freely, a liquid has no definite shape and takes a shape dictated by its container.

Hi there!

Recall Ampere's Law:
[tex]\oint B \cdot dl = \mu_0 i_{encl}[/tex]

B = Magnetic Field Strength (T)
μ₀ = Permeability of Free Space (Tm/A)

i =  Enclosed Current (A)

dL = differential path length

To begin, we must derive an expression for the magnetic field strength inside a wire that contains a uniformly-distributed current.

Using the expression:

[tex]i = \int J \cdot dA[/tex]

Where 'J' is the density of current, and A is the cross-sectional area:
[tex]A = \pi r^2\\\\dA = 2\pi r dr[/tex]

We know that:
[tex]J = \frac{i_0 }{A}\\\\J = \frac{i_0}{\pi a^2}[/tex]

This is the current density. We can now integrate:

[tex]i = \int\limits^r_0 {\frac{i_0}{\pi a^2} \cdot 2\pi r} \, dr\\ \\i =\frac{i_0}{a^2}\int\limits^r_0 {2r } \, dr\\\\i = \frac{i_0}{a^2} \cdot r^2 = \frac{i_0 r^2}{a^2}[/tex]

Now, substitute this expression back into the above equation for the magnetic field:
[tex]\oint B \cdot dl = \mu _0 \frac{i_0r^2}{a^2}[/tex]

The path of integration is a closed loop of length 2πr, so:
[tex]B \cdot 2\pi r = \mu_0 \frac{i_0r^2}{a^2}\\\\B = \frac{\mu_0 i_0r}{2\pi a^2}[/tex]

We can now use this equation for the first 2 parts.

a)
If 'r' equals 0:
[tex]B = \frac{\mu _0 i_0 (0)}{2\pi a^2} = \boxed{0 T}[/tex]

b)

If 'r' equals a/2:
[tex]B = \frac{\mu _0 i_0 (\frac{a}{2})}{2\pi a^2} =B =\boxed{ \frac{\mu _0 i_0 }{4\pi a} T}[/tex]

c)
At the wire's surface, 'r' = a:
[tex]B = \frac{\mu _0 i_0 (a)}{2\pi a^2} =B =\boxed{ \frac{\mu _0 i_0 }{2\pi a} T}[/tex]

d)

At 'r' = 2a, since this is outside of the wire, the relationship between magnetic field and distance from the wire becomes a 1/r (inverse) relationship. This is found using Ampere's Law:
[tex]B = \frac{\mu_0 i_0}{2\pi r}\\[/tex]

[tex]B = \frac{\mu_0 i_0}{2\pi (2a)} \\\\\boxed{B = \frac{\mu_0 i_0}{4\pi a}\\}[/tex]

Answer:

See below

Explanation:

Normal force = m g cos 53 = 8 kg * 9.8 m/s^2 * cos 53 = 47.1823 N

  no work is done by this force

Force friction = coeff friction * force normal = .4 * 47.1823 = 7.55 N

   work of friction = 7.55 * 2 m = 15.1 j

Force Downplane = mg sin 53 = 62.61  N

    work = 62.61 * 2 = 125.22 j

Net Force downplane =   force downplane - force friction = 55.06 N

net Work = force * distance = 55.06 N * 2 M = 110.12 j

Answer:

Let x be the overhang of the plank

(4 - x) = Y      portion of plank less the overhang

Y / 2 M g = clockwise torque due to weight of plank

40 x = counterclockwise torque due to weight of woman

(4 - x) M g / 2 = 40 x

(4 - x) M g = 80 x        (I)

4 M g = (80 + M g) x   (II)

x = 4 M g / (80 + M g) = 4 / (80 / M g + 1)

x would be shorter with an increase in M

if x were 1 then

4 M g = 80 + M g      using (II)

M = 80 / (3 g) = 2.72 kg

Check: use x = 1 in equaton (I)

3 M g = 80

M = 80 / (3 * 9.8) = 2.72 kg

The law of conservation of energy asserts that total energy remains constant in an isolated system. That is, energy cannot be generated or destroyed, but it may be transferred from one form to another. Frictional forces can dissipate energy, which raises the question of whether it violates the law of conservation of energy. No, it does not. When there is friction, energy is transferred from one form to another. There will be no energy loss. To illustrate this issue, consider the following scenario: two buses collide. The buses are no longer moving as a result of the collision. Where does all of this energy go? The solution is simple: the friction between buses and between buses and the road allows energy to be transferred from one form to another. You may be aware that when we rub our hands together, heat is produced; what occurs here is frictional energy converting to heat energy. This is what happens in bus accidents, where the energies can be changed to thermal energy, acoustic energy, or any other type of energy owing to friction and impact. So the energy we believed we had wasted was really converted to heat and sound. Bus collisions are not only noisy, but they also cause a lot of friction on the ground and in the bent metal. Both heat and sound are types of energy.

Answer:

Explanation:

The interfering waves have form y

1

​

=Asin(kx−ωt) and y

2

​

=Asin(kx+ωt)

Thus the resultant wave has displacement y=y

1

​

+y

2

​

=2Asin(kx)cos(ωt)

Maximum displacement is obtained when cos(ωt)=1

Thus y

max

​

=2×3×sin(π×0.25)=4.24cm

The maximum transverse position of an element of the medium is 3.00 cm at x=0.250 cm, 0 cm at x=0.500 cm, and -3.00 cm at x=1.50 cm, and the three smallest values of x corresponding to antinodes are 0.150 cm, 0.450 cm, and 0.750 cm.

A transverse wave is a type of wave where the disturbance, or displacement, of the medium, is perpendicular to the direction in which the wave travels.

Here in the Question,

There appears to be a typo in the given wave functions, as they are both the same. I will assume that the second wave function is actually y2 = 3.00 sin(2πx - 0.600t).

The resulting wave function for the two waves is y = y1 + y2 = 3.00 sin π(x - 0.600t) + 3.00 sin(2πx - 0.600t).

(a) At x = 0.250 cm, the maximum transverse position occurs when sin π(x - 0.600t) = 1 and sin(2πx - 0.600t) = 0. Therefore, y = 3.00 cm.

(b) At x = 0.500 cm, the maximum transverse position occurs when sin π(x - 0.600t) = 0 and sin(2πx - 0.600t) = -1. Therefore, y = -3.00 cm.

(c) At x = 1.50 cm, the maximum transverse position occurs when sin π(x - 0.600t) = -1 and sin(2πx - 0.600t) = 0. Therefore, y = -3.00 cm.

(d) The antinodes occur at the maximum values of y, which correspond to when sin π(x - 0.600t) = 1 or -1 and sin(2πx - 0.600t) = 0. The three smallest values of x that satisfy these conditions are:

x = 0.25 cm, as found in part (a)

x = 0.75 cm, where sin π(x - 0.600t) = -1 and sin(2πx - 0.600t) = 0

x = 1.25 cm, where sin π(x - 0.600t) = 1 and sin(2πx - 0.600t) = 0

Therefore, The maximum transverse position of an element of the medium is 3.00 cm at x=0.250 cm, 0 cm at x=0.500 cm, and -3.00 cm at x=1.50 cm, and the three smallest values of x corresponding to antinodes are 0.150 cm, 0.450 cm, and 0.750 cm.

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The levels of critical thinking classify people into six categories depending on their ability to reflect.

This refers to the ability to analyze information, situations, etc. as well as apply, synthesize or evaluate the information learned.

According to Dr. Ridel, the levels are:

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The Force "F" applied on the unit electric charge "q" at a point describes the electric field.

Answer:

the answer is equal to non zero

Steve's misbehavior toward his little brother decreases. This is an example of Positive punishment

Positive punishment is a variation is a  conditioning theory. Its major goal is to minimize future behavior frequency by delivering an unpleasant stimulation after the action has occurred.

Steve is given extra chores each time he hits his little brother. After a few times of having extra chores given to him.

Steve's misbehavior toward his little brother decreases. This is an example of Positive punishment.

Hence positive punishment is the right answer.

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Answer:

north and south poles

Explanation:

Answer:

Explanation:

First, prime factorize the two pure tone values.

It is clear that the Highest Common Factor (HCF) is 5

The two tones can only be pure if they resonate from the same beat frequency.

As 5 is a common factor, it is the beat frequency.