Can anyone help me with this?

Thus, the value of x found by Chord Arcs Theorem for the given Arc AD and arc CD is found as: x = 11.

The chords of such a circle are covered by a number of theorems. The chord arcs theorem is one such example. The intercepted arcs with congruent chords also were congruent according to this theorem.

Now,

chord AB  = chord DC

Thus,

m AB = m DC = 13x - 21

For the complete circle: angle = 360.

AB + DC + AD + BC = 360

(13x - 21) + (13x - 21) + 85 + 31 = 360

(36x - 42) + 116 = 360

26x - 42 = 244

26x = 244 + 42

x = 286/26

x = 11

Thus, the value of x found by Chord Arcs Theorem for the given Arc AD and arc CD is found as: x = 11.

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Complete question:

if m AD = 85 and m BC =31 find the value of x.

The diagram is attached.

Answer:

Step-by-step explanation:

You want three additional equivalent expressions to 6(3x +8) +32 +12x, one of which is the expression in simplest form.

Any expression you write along the path to simplifying the given expression will be an equivalent. Here's one way to get three different expressions:

  6(3x +8) +32 +12x . . . . . . given

  18x +48 +32 +12x . . . . . . eliminate parentheses

  30x +48 +32 . . . . . . . . . . combine x terms

  30x +80 . . . . . . . . . . . . . . combine constants (2 terms)

We can write another equivalent by factoring out a common factor:

  10(3x +8)

The quadratic function that represents the relationship in the given table is y =[tex]-2x^2 + 8x + 4,[/tex] which was verified by substituting the x-values from the table into the equation.

The quadratic function that represents the relationship in the given table is y [tex]= -2x^2 + 8x + 4.[/tex]To verify this, we can substitute the x-values from the table into the equation and compare the resulting y-values.

When x = 0, we get y =[tex]-2(0)^2 + 8(0) + 4 = 4[/tex], which matches the table.

When x = 1, we get y =[tex]-2(1)^2 + 8(1) + 4 = 4,[/tex] which matches the table.

When x = 2, we get y =[tex]-2(2)^2 + 8(2) + 4 = 2,[/tex] which matches the table.

When x = 3, we get y =[tex]-2(3)^2 + 8(3) + 4 = 4,[/tex] which matches the table.

When x = 4, we get y = [tex]-2(4)^2 + 8(4) + 4 = 6,[/tex] which matches the table.

Therefore, the quadratic function y =[tex]-2x^2 + 8x + 4[/tex]accurately represents the relationship in the given table.

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The relative frequency of respondents for a sample of 313 people who identified as Democrat, Republican, or Independent can be calculated by dividing the number of respondents for each group by the total number of respondents (313).

For example, if 100 respondents identified as Democrat, the relative frequency of Democrats would be 100/313, or approximately 32%. If 125 respondents identified as Republican, the relative frequency of Republicans would be 125/313, or approximately 40%. If the remaining 88 respondents identified as Independent, the relative frequency of Independents would be 88/313, or approximately 28%.

Therefore, the relative frequency of respondents in the sample of 313 people would be 32% Democrat, 40% Republican, and 28% Independent.

After using the antibacterial hand wash, there will be a remaining count of 203 bacterial cells.

The initial colony has 500 bacterial cells. We need to find the number of bacterial cells that will be left after 2 hours if an antibacterial hand wash is applied thoroughly. The antibacterial hand wash can kill 99.9% of the bacteria on a surface.

The doubling time of bacteria is given as 15 minutes. This means that every 15 minutes, the bacterial population doubles, which gives us an exponential growth rate. Therefore, the growth rate is given as follows:k = ln2 / Td where k is the growth rate, and Td is the doubling time.

Substituting the values we get:k = ln2 / 15min = 0.0462 min⁻¹We can find the number of bacteria present after a time t if the initial number of bacteria is N0 and the population growth rate is k using the following equation: Nt = N0 * e^(kt)where Nt is the number of bacteria after time t.As we know, the bacterial colony has 500 cells initially.

We can find the number of bacterial cells after 2 hours, which is 120 minutes, using the following equation: Nt = 500 * e^(0.0462 * 120min) = 202,599 bacteria. However, after applying an antibacterial hand wash, 99.9% of the bacteria will be killed.

This means that only 0.1% of the bacterial population will remain. We can find the number of bacteria that will be left using the following formula:N_final = N_initial * (1 - %killed)N_final = 202,599 * (1 - 0.999) = 203 bacteria

Therefore, there will be 203 bacterial cells left after applying the antibacterial hand wash.

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The image vertices of L′M′N′ are (-2, 3), (-4, -1), and (-4, 3).

What is preimage?

The set of all domain elements for a given function that map to a certain subset of the codomain; (formally) given a function X Y and a subset B Y, the set 1(B) = x X: x B.

Here, we have

Given: Triangle LMN is drawn with vertices at L(−3, −2), M(1, −4), N(−3, −4).

We have to determine the image vertices of L′M′N′ if the preimage is rotated 90° clockwise.

The rule for rotating a point (x, y) 90° clockwise is:

(x,y) ⇒ (y, -x)

The vertices of triangle LMN will be mapped to:

L(-3,-2) ⇒L' (-2, 3)

M(1,-4) ⇒ M'(-4, -1)

N(-3,-4) ⇒ N'(-4, 3)

Hence, the image vertices of L′M′N′ are (-2, 3), (-4, -1), and (-4, 3).

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The sοlutiοn tο the system οf equatiοns is x = 17/5, which is apprοximately equal tο 3.4. Nοne οf the given answer chοices match this value exactly, sο there is nο sοlutiοn amοng the given chοices.

A linear equatiοn is a mathematical equatiοn that describes a straight line in a twο-dimensiοnal plane.

We can sοlve the system οf equatiοns by substituting the secοnd equatiοn intο the first equatiοn and then sοlving fοr x:

3x + 2y = 7 (equatiοn 1)

y = x - 5 (equatiοn 2)

Substituting equatiοn 2 intο equatiοn 1, we get:

3x + 2(x - 5) = 7

Simplifying the equatiοn, we get:

5x - 10 = 7

Adding 10 tο bοth sides, we get:

5x = 17

Dividing bοth sides by 5, we get:

x = 17/5

Therefοre, the sοlutiοn tο the system οf equatiοns is x = 17/5, which is apprοximately equal tο 3.4. Nοne οf the given answer chοices match this value exactly, sο there is nο sοlutiοn amοng the given chοices.

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Answer: the last box for minutes is 16

And the first box for customers is 1

Step-by-step explanation:

Answer:

See below.

Step-by-step explanation:

1st Box(First row)

We can set up a proportion to solve for the number of customers that would enter the store in 4 minutes:

3 customers is to 12 minutes as x customers is to 4 minutes

This can be written as:

3/12 = x/4

To solve for x, we can cross-multiply and simplify:

3/12 = x/4

3(4) = 12x

12 = 12x

x = 1

Therefore, we can expect 1 customer to enter the store in 4 minutes.

We can use the given ratios to find the time for 10 customers.

From the table, we can see that:

3 customers take 12 minutes.

1 customer takes 4 minutes (divide both sides of the ratio by 3).

So, 10 customers will take:

10 customers × 4 minutes per customer = 40 minutes.

Therefore, for 10 customers, the time is 40 minutes.

On average, 50% of athletes are able to begin activity 90 days after a knee operation, with a standard deviation of 15 days.

This means that the median time for 50% of athletes to be able to participate is 75 days, rounded to the nearest day.

The average time for an athlete to begin activity after a knee operation is 90 days, and the standard deviation is 15 days.

Standard deviation is a measure of how spread out the data points are in a data set; a larger standard deviation means that the data points are more spread out.

In this case, 50% of athletes can begin activity within 75 days, which is the median. By rounding to the nearest day, this would be 75 days. Therefore, 50% of athletes are able to participate within 75 days, rounded to the nearest day.

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Answer:  (a-b+c)²-(b-c+a)²​

=((a-b+c)) - ((b-c+a)) ((a-b+c)) - ((b-c+a))

= (a-b+c-b+c-a) ( a-b+c+b-c+a)

= (-2b + 2c ) (2a)

= (2( -2b/2+2c/2)) (2a)

=(2(-b+c)) (2a)

=2(-b+c) (2a)

Answer:

9231.60 cubic inches

Step-by-step explanation:

V = [tex]\pi r^{2} h[/tex]

V = [tex]\pi (14)^{2} (15)[/tex]

V = 9231.60 cubic inches

The percent change in the price of the lawnmower over the 2 years is -8.1%.

To find the percent change in the price of the lawnmower over the 2 years, we can use the formula:

percent change = (new value - old value) / old value * 100%

Plugging in the values given in the problem, we get:

percent change = (329.99 - 358.99) / 358.99 * 100%

percent change = -8.1%

Therefore, the percent change in the price of the lawnmower over the 2 years is -8.1%. Note that the negative sign indicates a decrease in price.

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The value of the expression given is 144

Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.

Given is an expression 3(25+19) + 4(3) we need to simplify,

Using PEMDAS,

3(25+19) + 4(3)

= 75+57 + 12

= 132+12

= 144

Hence, the  value of the expression given is 144

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To create a figure of three rectangles with a perimeter of 140 yards, you can stack them on top of each other to make a plus sign, and label each side as 11 and 2/3 yards or 11 yards (by subtracting the fractions).

A rectangle is a four-sided geometric shape that has four right angles (90 degree angles) and opposite sides that are parallel and of equal length. The length of a rectangle is its longer side, while the width is its shorter side.

If we draw three rectangles stacked on top of each other like a plus sign, we can divide the perimeter of 140 yards by the number of sides, which is 12. This gives us a length of 11 and 2/3 yards per side.

To use only integers, we can subtract the fractions from each side to another, which gives us a length of 11 yards per side. We can then label each side of the figure with a length of 11 yards.

In the figure, we have three rectangles of equal size, with a length of 11 yards and a width of 35 yards. We can convert the measurements to feet by multiplying by 3, which gives us a length of 33 feet and a width of 105 feet.

Alternatively, if we wanted to use only whole numbers, we could increase the size of each rectangle slightly, so that the total perimeter is a multiple of 12. For example, we could make each rectangle 11.6667 yards by 35 yards, which gives us a total perimeter of 140.0008 yards. We can then divide this by 12 to get a length of 11 and 2/3 yards per side, and label each side with a length of 11 yards.

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Answer:

the distance between P and Q is ≈ 6.2 units

Step-by-step explanation:

calculate the distance d using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = P (1, 5 ) and (x₂, y₂ ) = Q (5.5, 9.25 )

d = [tex]\sqrt{(5.5-1)^2+(9.25-5)^2}[/tex]

   = [tex]\sqrt{(4.5)^2+(4.25)^2}[/tex]

   = [tex]\sqrt{20.25+18.0625}[/tex]

   = [tex]\sqrt{38.3125}[/tex]

   ≈ 6.2 ( to the nearest tenth )

The x-intercept is (4.5, 0) and  y-intercept is (0, -1) for the given function.

What are intercepts ?

Intercepts are the points at which a curve intersects with the x-axis and y-axis on a coordinate plane. The x-intercept is the point where the curve intersects with the x-axis, and its y-coordinate is zero. The y-intercept is the point where the curve intersects with the y-axis, and its x-coordinate is zero. The intercepts provide useful information about the behavior and properties of a curve, such as its roots and symmetry.

According to the question:

To find the x-intercept, we need to set y = 0 and solve for x:

[tex]0 = log(2x + 1) - 11 = log(2x + 1)10 = 2x + 19 = 2xx = 4.5[/tex]

Therefore, the x-intercept is (4.5, 0).

To find the y-intercept, we need to set x = 0 and evaluate the function:

[tex]f(0) = log(2(0) + 1) - 1[/tex]

= 0 - 1[tex]= log(1) - 1[/tex]

= -1

Therefore, the y-intercept is (0, -1).

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Direct variation means the ratio of y to x is constant.

y1/x1 = y2/x2 ⇒

y2 = (x2/x1) y1

Plug in

x1 = 3

y1 = 7

x2 = 7

and get y2.

Answer:

It's D

Step-by-step explanation:

[tex]1. \: gcf = 8x \\ 2. \: 8x( \frac{16x {}^{2} }{8x} + \frac{8x}{8x} ) \\ 3. \: 8x(2x + 1)[/tex]

Answer:

To find the total distance Lydia walks each week, we need to convert the distance to the library from meters to kilometers and then add up the distance she walks to and from the school and library.

Distance to school = 827 meters

Distance to library = 1.4 kilometers = 1400 meters

Total distance walked to and from school in one day = 2 x distance to school = 2 x 827 = 1654 meters

Total distance walked to and from school in one week (5 days) = 5 x 1654 = 8270 meters

Total distance walked to and from library in one day = 2 x distance to library = 2 x 1400 = 2800 meters

Total distance walked to and from library in one week (1 day) = 1 x 2800 = 2800 meters

Total distance Lydia walks each week = distance to school + distance to library = 8270 + 2800 = 11070 meters

To convert meters to kilometers, we divide by 1000:

Total distance Lydia walks each week = 11070 meters ÷ 1000 = 11.07 kilometers

Therefore, Lydia walks a total of 11.07 kilometers to and from school and library each week.

Answer:

I think it is 399.

Step-by-step explanation:

The terms through degree 4 of the Maclaurin series of f(x) is [tex]8x+8x^{2} +(\frac{16}{3})x^{3}+(\frac{28}{3} ) x^{4}[/tex]

A Maclaurin series is a representation of a function as an infinite sum of terms involving its derivatives evaluated at a specific point, usually 0. It is a special case of a Taylor series, where the point of evaluation is 0.

The Maclaurin series is named after the Scottish mathematician Colin Maclaurin, who first used this method to study the properties of functions.

The general form of a Maclaurin series is:

[tex]f(x)=f(0)+f'(0)x+f''(0)x^{\frac{2}{2} } !+f'''(0)x^{\frac{3}{3} } !+....[/tex]

where f(0), f'(0), f''(0), f'''(0), etc. are the function and its derivatives evaluated at x = 0.

Maclaurin series can be used to approximate the value of a function at any point near 0, provided that the function has a sufficient number of derivatives at that point. They are commonly used in calculus, physics, and engineering to solve problems involving complex functions.

To find the Maclaurin series for [tex]f(x)=\frac{4sin2x}{1-x}[/tex], we can start by using the Maclaurin series for sin(2x) and for [tex](1-x)^{-1}[/tex]:

[tex]sin(2x)= 2x-2x^{\frac{3}{3} } !+2x^{\frac{5}{5} } !-...........\\(1-x)^{-1} =1+x+x^{2} +x^{3}+x^{4} +.....[/tex]

We can substitute these series into f(x) and multiply them together, then collect like terms:

[tex]f(x)=\frac{4sinx}{1-x} \\=4(2x-2x^{\frac{3}{3} }!+2x^{\frac{5}{5} }! -......)(1+x+x^{2} +x^{3}+x^{4+}.....)\\ =(8x+8x^{2} +8x^{3}+8x^{4}+....) -(8x^{\frac{3}{3} }!+8x^{\frac{5}{5} } ! +....)+(16x^{\frac{5}{5} }! +....)[/tex]

We can simplify this expression to get the first few terms of the Maclaurin series:

[tex]f(x)= 8x+8x^{2} +8x^{3}-8x^{4}-8x^{\frac{3}3} }-8x^{\frac{5}{30} }+ 16x^{\frac{5}{120} }+......=8x+ 8x^{2}+(\frac{16}{3}) x^{3}+(\frac{28}{3} ) x^{4}-(\frac{2}{15} ) x^{5} +............[/tex]

Therefore, the terms through degree 4 of the Maclaurin series of f(x) are:

[tex]8x+8x^{2} +(\frac{16}{3})x^{3}+(\frac{28}{3} ) x^{4}[/tex]

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Answer: 4y - (2/3)x + 20

Step-by-step explanation:

Write out problem: 4(y+5) - (2/3)x

Expand: 4y + 20 - (2/3)x

Reorder: 4y - (2/3)x + 20

To begin, we know that the median of the original collection of five positive integers is 4, which means that the middle number is 4. We also know that the unique mode is 3, which means that there is only one number in the collection that occurs more frequently than any other number.

Let's call the five positive integers in the original collection a, b, c, d, and e.

Since the mean of the original collection is 4.4, we can set up the equation:

(a+b+c+d+e)/5 = 4.4

Multiplying both sides by 5 gives:

a+b+c+d+e = 22

We also know that the mode is 3, which means that one of the numbers in the collection must be 3. Let's assume that a = 3, then we have:

3+b+c+d+e = 22

b+c+d+e = 19

Since the median is 4 and 3 is the unique mode, we can conclude that b, c, d, and e must be either 4 or 5. However, since there is only one unique mode, we know that there is only one number in the collection that is equal to 3. Therefore, we can conclude that the collection of five positive integers must be: 3, 4, 4, 4, 5.

If we add 8 to this collection, the new collection becomes: 3, 4, 4, 4, 5, 8. The new collection has six numbers, so the median is now the average of the two middle numbers. Since the middle two numbers are 4 and 5, the median is (4+5)/2 = 4.5.

Therefore, the new median is 4.5, expressed as a decimal to the nearest tenth.

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Dividing the circumference of a pumpkin by its diameter gives a value approximately equal to pi (π)

When you divide the circumference of a pumpkin by its diameter, you get a value that is approximately equal to the mathematical constant pi (π), which is approximately 3.14159.

This is because pi represents the ratio of the circumference of a circle to its diameter, and a pumpkin is roughly spherical in shape. So, no matter how big or small the pumpkin is, if you measure its circumference and diameter and divide them, the result will be very close to pi.

Mathematically, this can be represented by the formula

pi ≈ circumference / diameter

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the amount of terms in the expression is unaffected by the absence of plus or minus signs. Mary is incorrect in her thinking. The amount of terms in an expression is not based on whether plus or minus signs are present.

Mary's reasoning is not correct. The presence of plus or minus signs does not determine the number of terms in an expression.

In algebraic expressions, a term is a product of numbers and variables, and it can be separated from other terms by addition or subtraction signs.

In the expression a/z, there is only one term, which is a divided by z. It does not have any other terms because there are no other products of numbers and variables separated by addition or subtraction signs.

Therefore, in this case, the lack of plus or minus signs does not affect the number of terms in the expression.

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Answer:

In a right triangle, one angle is always 90 degrees (a right angle). The other two angles are acute angles, which means they are less than 90 degrees.

Let's call the acute angle we're interested in "a". We know that sin a = 3/5.

"Sin" is short for "sine", which is a ratio of two sides of the triangle. Specifically, it's the ratio of the length of the side opposite angle a to the length of the hypotenuse (the longest side of the triangle, which is always opposite the right angle).

So, in our triangle, if sin a = 3/5, that means the side opposite angle a is 3 units long and the hypotenuse is 5 units long.

Now, we can use the Pythagorean theorem to find the length of the third side of the triangle (the one adjacent to angle a). The Pythagorean theorem says that in a right triangle, the sum of the squares of the two shorter sides is equal to the square of the hypotenuse. In other words:

a^2 + b^2 = c^2

where a and b are the lengths of the two shorter sides, and c is the length of the hypotenuse.

In our triangle, we know that b is the side adjacent to angle a, so we're trying to find its length. We also know that a = 3 and c = 5, so we can plug those values into the Pythagorean theorem and solve for b:

3^2 + b^2 = 5^2

9 + b^2 = 25

b^2 = 16

b = 4

So the length of the side adjacent to angle a is 4.

Now, we can use the ratios of the trigonometric functions (sine, cosine, and tangent) to find the values of cosine and tangent for angle a.

Cosine (cos) is the ratio of the length of the adjacent side to the length of the hypotenuse. So in our triangle:

cos a = adjacent/hypotenuse = 4/5

Tangent (tan) is the ratio of the length of the opposite side to the length of the adjacent side. So in our triangle:

tan a = opposite/adjacent = 3/4

Therefore, if sin a = 3/5 in a right triangle, where a is an acute angle, then cos a = 4/5 and tan a = 3/4.

An [tex]11[/tex]-vertex full graph has around [tex]19,958,931,200[/tex] Hamiltonian circuits in a complete graph.

At one vertex, the Hamiltonian route begins, and at another, it finishes. Yet, when following a Hamiltonian route, every vertex is encountered. At the same vertex, the Hamiltonian circuit begins and terminates. For instance, if a Hamiltonian circuit's path began at vertex 1, the loop will also conclude at that vertex.

Single circuit is the sole trip a Hamiltonian circuit makes to each vertex. It must begin and terminate at same vertex since it is a circuit. A Hamiltonian route does not start and end in a single location, but it does visit each vertex just once with no repetitions.

We have to divide by [tex]2(n-2)[/tex]

[tex]11!/(2(11-2)!) = 11!/2,520[/tex] Hamiltonian circuits we get:

[tex]11!/2,520 = 19,958,931,200[/tex]

Therefore, there are approximately [tex]19,958,931,200[/tex] Hamiltonian circuits in a complete graph with [tex]11[/tex] vertices.

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