Chemistry Table balance A+B→C
Table 1 attached

The pH of a 0.100M NaClO solution is 1.

pH, meaning power of hydrogen, is a measure of how acidic/basic a solution is. The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base.

pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in the water. It can be estimated using the following formula;

pH = - log {H+}

Where;

pH = - log {0.100}

pH = 1

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Five types of begging the question include: Circular reasoning, Loaded question, False analogy,  Suppressed evidence and Appeal to authority.

Begging the question is a logical fallacy that occurs when someone assumes the truth of a premise in their argument, without providing evidence or proof. There are several types of begging the question:

1. Circular reasoning: This occurs when someone uses their conclusion as one of their premises, essentially assuming what they are trying to prove.
Example: "God exists because the Bible says so, and the Bible is the word of God."

2. Loaded question: This occurs when someone asks a question that assumes a particular answer or perspective.
Example: "Have you stopped beating your spouse yet?" This question assumes that the person being asked was previously beating their spouse.

3. False analogy: This occurs when someone uses an analogy that is not relevant or applicable to the argument at hand.
Example: "Banning guns is like banning cars because both can be used to kill people." This analogy is false because cars have a primary function of transportation, whereas guns have a primary function of killing.

4. Suppressed evidence: This occurs when someone ignores or dismisses evidence that contradicts their argument.
Example: "I don't believe in climate change because it's cold outside today." This argument suppresses evidence that shows long-term trends of warming temperatures.

5. Appeal to authority: This occurs when someone uses an authority figure or expert as evidence, without providing any other support for their argument.
Example: "Dr. Smith says that this diet is the best for losing weight, so it must be true." This argument appeals to Dr. Smith's authority without providing any evidence or research to support the claim.

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A sunscreen made with Benzophenone-5 ([tex]C_1_4H_1_1NaO_6S[/tex]) would be expected to be more waterproof than benzophenone-3 ([tex]C_1_4H_1_2O_3[/tex]).

This is due to the presence of a sodium salt group (Na) and a sulfonic acid group ([tex]SO_3H[/tex] ) in benzophenone-5, which makes it more polar than benzophenone-3. Polar molecules interact more strongly with water molecules and are less likely to dissolve in nonpolar solvents such as oils.

Because sunscreen is designed to be water-resistant, the more polar benzophenone-5 should have stronger interactions with water and give more water resistance than benzophenone-3.

Moreover, the sulfonic acid group in benzophenone-5 may allow it to make stronger hydrogen bonds with water, increasing its water resistance even further.

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Answer:

two

Explanation:

the answer is two

option b

The partial pressure of the oxygen is 0.236 atm.

The pressure that one gas component in a mixture of gases exerts is known as partial pressure. It is the pressure that the gas would experience if it took up the same amount of space in the mixture at the same temperature on its own.

We know that;

P[tex]CO_{2}[/tex] = 0.285 torr or 0.000375 atm

P[tex]N_{2}[/tex] = 580.502 torr or 0.764 atm

P[tex]O_{2}[/tex] = ?

Total pressure = 1 atm

Then we have that;

PT =P[tex]CO_{2}[/tex]  +P[tex]N_{2}[/tex]+ P[tex]O_{2}[/tex]

P[tex]O_{2}[/tex] = PT - (P[tex]CO_{2}[/tex]  + P[tex]N_{2}[/tex])

P[tex]O_{2}[/tex] = 1 - (0.000375  + 0.764)

P[tex]O_{2}[/tex]= 0.236 atm

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Answer:

3.8 ⋅*10^-14

Explanation:

The standard free energy change (ΔG°) for the reaction at 298 K can be calculated using the following equation:

ΔG° = ΣnΔGf°(products) - ΣnΔGf°(reactants)

where ΔGf° is the standard molar free energy of formation of the species and n is the stoichiometric coefficient.

ΔG° = [1×ΔGf°(Fe2O3)] - [1×ΔGf°(FeO) + 1×ΔGf°(Fe) + 1×ΔGf°(O2)]

ΔG° = [1×(-822.16 kJ/mol)] - [1×(-271.9 kJ/mol) + 1×(0 kJ/mol) + 1×(0 kJ/mol)]

ΔG° = -550.26 kJ/mol

The standard enthalpy change (ΔH°) and standard entropy change (ΔS°) can be used to calculate the standard free energy change (ΔG°) at any temperature using the following equation:

ΔG° = ΔH° - TΔS°

where T is the temperature in Kelvin.

ΔG° = ΔH° - TΔS° = (-550.26 kJ/mol) - (298 K)(-0.08996 kJ/K/mol) = -524.05 kJ/mol

Now, we can calculate the equilibrium constant (K) for the reaction at 298 K using the following equation:

ΔG° = -RTlnK

where R is the gas constant (8.314 J/K/mol) and T is the temperature in Kelvin.

-524.05 kJ/mol = -(8.314 J/K/mol)(298 K)lnK

lnK = -200.16

K = e^(-200.16) = 3.89×10^(-87)

Therefore, the value of K for the reaction at 25 °C is 3.89×10^(-87). Answer: 3.8 ⋅*10^-14.

The specific heat capacity of the ring, given that the ring gives up 667.5 J of energy to the water is 0.444 J/gºC. The ring is made of nickel.

The specific heat capacity of the ring can be obtain as illustrated below:

Q = MCΔT

-667.5 = 25.5 × C × -59

-667.5 = -1504.5 × C

Divide both sides by -1504.5

C = -667.5 / -1504.5

C = 0.444 J/gºC

Thus, the specific heat capacity of the ring is 0.444 J/gºC. Hence, the ring is made of nickel

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The net ionic equation of the reaction is as follows:

4 Al3+(aq) + 12 NO3-(aq) + 3 Ag(s) = 4 Al(s) + 12 Ag+(aq) + 12 NO3-(aq)

Ions which remain in their ground state and do not take part in the reaction are called spectator ions. The net ionic equation cancels out these ions, which are present on both the reactant and product sides of the equation.

Spectator ions, which can be found on both the reactant and product sides, but are not included in the finished reaction from the net ionic equation. The [tex]NO^3^-[/tex] ions are spectator ions in this example, thus taking them out of the equation. The net ionic equation makes up the rest of the species.

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To calculate the amount of aluminum produced from 9.00 tons of Al2O3, we need to use stoichiometry. First, we'll convert the mass of Al2O3 to moles, and then use the balanced chemical equation to find the moles of aluminum. Finally, we'll convert the moles of aluminum back to mass.

1. Convert mass of Al2O3 to moles:
9.00 tons = 9,000 kg
Molar mass of Al2O3 = (2 * 26.98) + (3 * 16.00) = 101.96 g/mol
9,000 kg * (1000 g/kg) = 9,000,000 g
moles of Al2O3 = 9,000,000 g / 101.96 g/mol = 88,258 moles

2. Use balanced chemical equation to find moles of aluminum:
The balanced chemical equation is:
2 Al2O3 → 4 Al + 3 O2
Using stoichiometry, we find the ratio of Al2O3 to Al is 2:4 or 1:2.
moles of Al = 88,258 moles Al2O3 * (2 moles Al / 1 mole Al2O3) = 176,516 moles

3. Convert moles of aluminum back to mass:
Molar mass of Al = 26.98 g/mol
Mass of Al = 176,516 moles * 26.98 g/mol = 4,762,984 g
Mass of Al in tons = 4,762,984 g / (1000 g/kg) / (1000 kg/ton) = 4.76 tons

So, 4.76 tons of aluminum can be produced from 9.00 tons of Al2O3.

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the original temperature of the h ot iron bar was 327.9°C.

We can use the specific heat of iron to do this:

Q1 = m1 * C1 * (Ti - 32.8°C)

Q1 = 408 g * 0.45 J/g °C * (Ti - 32.8°C)

Q1 = 183.6 J/g °C * (Ti - 32.8°C)

where m1 is the mass of the iron bar, C1 is the specific heat of iron, and Ti is the initial temperature of the iron bar.

Next, let's calculate the heat gained by the cold water when it is heated from 20.0°C to 32.8°C:

Q2 = m2 * C2 * (32.8°C - 20.0°C)

Q2 = 1000 g * 4.184 J/g °C * (32.8°C - 20.0°C)

Q2 = 52272 J

where m2 is the mass of the water, C2 is the specific heat of water.

Since the energy lost by the iron bar is gained by the water, we can set Q1 equal to Q2:

Q1 = Q2

183.6 J/g °C * (Ti - 32.8°C) = 52272 J

Now, let's solve for Ti:

183.6 J/g °C * Ti - 60236.8 J = 0

183.6 J/g °C * Ti = 60236.8 J

Ti = 327.9°C

Therefore, the original temperature of the h ot iron bar was 327.9°C.

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If we label the compounds ABCD from left to right;

A - 12.10

B - 15.90

C - 12.66

D - 12.35

A molecule or compound's acidity is quantified by the pKa, which is the negative logarithm (base 10) of the acid dissociation constant (Ka). The lower the pKa value, the stronger the acid; it reflects a compound's propensity to give a proton (H+) in a solution.

The compound that has the highest number of attachment of the most electronegative elements would have the greatest pKa.

The justification of the answer above is that, seeing that the compound labelled B has three highly electronegative atoms hence it would have the most or the highest pKa of about  15.90 among the other compounds. The other compounds A, C and D have fewer electronegative atoms attached and thus a lower pKa as shown

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The partial pressure of the Helium gas is  0.9 atm.

The pressure that a gas exerts on its own when it is collected over water, independent of the pressure that the water vapor in the collecting vessel also produces, is known as its partial pressure.

When gas is collected over water, some of the water vapor will dissolve in it and change the overall pressure in the collecting vessel. Water vapor has its own partial pressure, which is affected by the relative humidity and temperature of the air around it. This is why it behaves in this way.

We have that;

Vapor pressure of the gas = 19.8 mmHg or 0.026 atm

Partial pressure of the Helium gas = 0.926 atm - 0.026 atm

= 0.9 atm

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The maximum mass of water that can be produced by the reaction is 43.3 g, rounded to three significant figures.

The balanced chemical equation for the reaction between butane and oxygen is:

C4H10 + 13/2 O2 → 4 CO2 + 5 H2O

From the equation, we can see that 1 mole of butane reacts with 13/2 moles of oxygen to produce 5 moles of water.

moles of butane = 34. g / 58.12 g/mol = 0.585 mol

moles of oxygen = 200. g / 32.00 g/mol = 6.25 mol

Determining the limiting reactant.

butane : oxygen = 0.585 mol : 6.25 mol

= 0.0936 : 1.00

stoichiometric ratio = 1 : 13/2

= 0.7692 : 1.00

Since the actual ratio is lower than the stoichiometric ratio for oxygen, it is the limiting reactant.

The maximum amount of water that can be produced is determined by the amount of limiting reactant (oxygen).

moles of water = 5/13 * 6.25 mol

= 2.403 mol

Finally, we can convert the moles of water to grams:

mass of water = 2.403 mol * 18.015 g/mol

= 43.3 g

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The balanced chemical equation for the electrolysis of water is:

2H2O → 2H2 + O2

This equation shows that for every two moles of water that are electrolyzed, one mole of oxygen gas is produced. To solve this problem, we need to first convert the given mass of water (83.7 grams) to moles of water.

The molar mass of water (H2O) is:

2(1.008 g/mol H) + 15.999 g/mol O = 18.015 g/mol

So, 83.7 grams of water is equal to:

83.7 g / 18.015 g/mol = 4.646 mol H2O

Next, we need to determine how many moles of oxygen gas will be produced when 4.646 moles of water are electrolyzed. Since the mole ratio of water to oxygen is 2:1, we can use the following proportion:

2 mol H2O : 1 mol O2 = 4.646 mol H2O : x mol O2

Solving for x, we get:

x mol O2 = (1 mol O2 / 2 mol H2O) * 4.646 mol H2O = 2.323 mol O2

Finally, we can convert the moles of oxygen gas produced to grams using the molar mass of oxygen:

2.323 mol O2 * 32.00 g/mol O2 = 74.3 g O2

Therefore, 83.7 grams of water will produce 74.3 grams of oxygen gas by electrolysis.

The partial pressure of each gas are:

First, we shall determine the mole of 8.00 g of methane, CH₄ and 18.0 g of ethane, C₂H₆. Details below:

For methane, CH₄

Mole = mass / molar mass

Mole of CH₄ = 8 / 16

Mole of CH₄ = 0.5 mole

For ethane, C₂H₆

Mole = mass / molar mass

Mole of C₂H₆ = 18 / 30

Mole of C₂H₆ = 0.6 mole

Next, we shall determine the total mole. Details below:

PV = nRT

3.70 × 10 = n × 0.0821 × 293

Divide both sides by (0.0821 × 293)

n = (3.70 × 10) / (0.0821 × 293)

n = 1.52 mole

Finally, we shall determine the partial pressure of each gas. Details below:

For methane, CH₄

Partial pressure = (Mole / total mole) × total pressure

Partial pressure of CH₄ = (0.5 / 1.52) × 3.70

Partial pressure of CH₄ = 1.22 atm

For ethane, C₂H₆

Partial pressure = (Mole / total mole) × total pressure

Partial pressure of C₂H₆ = (0.6 / 1.52) × 3.70

Partial pressure of C₂H₆ = 1.46 atm

For propane, C₃H₈

Partial pressure of C₃H₈ = Total pressure - (Partial pressure of CH₄ + Partial pressure of C₂H₆)

Partial pressure of C₃H₈ = 3.7 - (1.22 + 1.46)

Partial pressure of C₃H₈ = 1.02 atm

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The aluminum block absorbed 0.875 kJ of heat energy when it was dropped into the coffee.

let's calculate the heat lost by the coffee when it is cooled from its initial temperature of 90.0°C to its final temperature of 55.0°C:

Q1 = m1 * C1 * (90.0°C - 55.0°C)

Q1 = 850 g * 4.184 J/g °C * (90.0°C - 55.0°C)

Q1 = 125660 J

where m1 is the mass of the coffee, C1 is the specific heat of water.

Next, let's calculate the heat gained by the aluminum block when it is heated from 4.4°C to the final temperature of the mixture, which is 55.0°C:

Q2 = m2 * C2 * (55.0°C - 4.4°C)

Q2 = 18 g * 0.89 J/g °C * (55.0°C - 4.4°C)

Q2 = 875.16 J

where m2 is the mass of the aluminum block, and C2 is the specific heat of aluminum.

Since the energy lost by the coffee is gained by the aluminum block, we can set Q1 equal to Q2:

Q1 = Q2

125660 J = 875.16 J + m2 * C2 * (55.0°C - 4.4°C)

Solving for m2, we get:

m2 = (125660 J - 875.16 J) / (0.89 J/g °C * (55.0°C - 4.4°C))

m2 = 152.2 g

Therefore, the mass of the aluminum block that was dropped into the coffee is 152.2 g. To calculate the heat energy absorbed by the aluminum block, we can use the heat gained by the aluminum block that we calculated earlier:

Q2 = 875.16 J

Converting this to kJ, we get:

Q2 = 0.875 kJ

Therefore, the aluminum block absorbed 0.875 kJ of heat energy when it was dropped into the coffee.

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Answer:

3.29 grams

Explanation:

This is found by multiply 2.35 L by 1.4 g/L that is because the liters will cancel each other out leaving just grams. [tex]\frac{g}{L} * \frac{L}{1}[/tex]

Initially, there was a 266.8 mm Hg pressure.

solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas sample. The formula is:
(P1 × V1) ÷ (T1) = (P2 × V2) ÷ (T2)
where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.

We are given that:
- V1 = 436 mL
- V2 = 612 mL
- T1 = 24 C + 273.15 = 297.15 K (convert from Celsius to Kelvin)
- T2 = 97 C + 273.15 = 370.15 K
- P2 = 526 mm Hg

We want to find P1, the original pressure.
Plugging in the values, we get:
(P1 × 436 mL) ÷ (297.15 K) = (526 mm Hg × 612 mL) ÷ (370.15 K)

Solving for P1, we get:
P1 = (526 mm Hg × 612 mL × 297.15 K) ÷ (436 mL × 370.15 K) = 266.8 mm Hg

Therefore, the original pressure was 266.8 mm Hg.

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The overall charge on the structure is negative one (-1).

The central boron atom in the structure is bonded to two hydrogen atoms. Boron has three valence electrons, and it has formed only two bonds, so it has a formal charge of +1.

Each of the hydrogen atoms has one valence electron, and each is bonded to the boron atom, so each hydrogen atom has a formal charge of -1. The sum of the formal charges in the structure is equal to the charge of the ion, which is -2. Adding up the formal charges of the atoms, we get:

B: +1

H: -1 (two times)

Overall charge = sum of formal charges = +1 - 1 - 1 = -1

Therefore, the overall charge on the structure is negative one (-1).

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The pressure of the gas when the volume is 1.09 L and the temperature is 308 K is 2.36 atm.

The final pressure of the gas is calculated by applying ideal gas law as follows;

(P₁V₁)/T₁ = (P₂V₂)/T₂

where

P₂ = (P₁V₁ x T₂)/(V₂ x T₁)

P₂ = (1.01 atm x 2.31 L x 308 K) / (1.09 L x 279 K)

P₂ = 2.36 atm

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We can use the combined gas law to determine the volume of the balloon at a higher altitude. The combined gas law relates the pressure, volume, and temperature of a gas:

(P1 x V1) / T1 = (P2 x V2) / T2

where P1, V1, and T1 are the pressure, volume, and temperature of the gas at the initial state, and P2, V2, and T2 are the pressure, volume, and temperature of the gas at the final state.

We are given the initial pressure (P1 = 761 mmHg), volume (V1 = 56.0 L), and temperature (T1 = 23.1 °C = 296.25 K) of the gas, and the final pressure (P2 = 0.0772 atm), and temperature (T2 = -6.97 °C = 266.18 K) of the gas. We can solve for V2, the final volume of the gas:

(P1 x V1) / T1 = (P2 x V2) / T2

V2 = (P1 x V1 x T2) / (P2 x T1)

V2 = (761 mmHg x 56.0 L x 266.18 K) / (0.0772 atm x 296.25 K)

V2 = 2,040 L (rounded to three significant figures)

Therefore, the volume of the weather balloon at the higher altitude is approximately 2,040 L.

In comparison to towns located inland, cities close to water features like lakes or oceans typically experience cooler summer temperatures.

Since water has a higher specific heat capacity than land, this is the case. The quantity of energy needed to raise a substance's temperature by a specific amount is known as its specific heat capacity. Compared to land, raising the temperature of water requires more energy because water has a higher specific heat capacity.

The summer sun warms both land and water, but due to land's lower specific heat capacity, land warms up more quickly than water. As a result, communities farther from water bodies tend to be hotter than cities closer to water.

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The value of H (in kJ) when 5.10 g of H2(g) is formed is 326 kJ (option B).

The given reaction is: CH3OH(I) —> CO(g)+2H2(g)

From the given value of H, we know that when one mole of CH3OH reacts, 128.1 kJ of heat energy is absorbed.

The molar mass of H2 is 2 g/mol. So, 5.10 g of H2 is equivalent to 5.10/2 = 2.55 moles of H2.

From the balanced equation, we can see that two moles of H2 are produced for each mole of CH3OH that reacts.

So, 2.55 moles of H2 are produced by 1.275 moles of CH3OH reacting (2.55/2).

Therefore, the amount of heat energy absorbed when 1.275 moles of CH3OH reacts can be calculated as:

Q = n x ΔH = 1.275 mol x 128.1 kJ/mol = 163.28 kJ

Since this amount of heat energy is absorbed when 1.275 moles of CH3OH reacts, to find the amount of heat energy absorbed when 2.55 moles of H2 is formed, we can simply double the value of Q:

Q = 2 x 163.28 kJ = 326.56 kJ

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The percent difference between the first two trials is 8.3% and final outcome would be an average molarity of 0.108 M.

To calculate the percent difference between the first two trials, use the formula:

% Difference = |(Value 1 - Value 2) / ((Value 1 + Value 2) / 2)| x 100%

% Difference = |(0.104 M - 0.113 M) / ((0.104 M + 0.113 M) / 2)| x 100%

% Difference = |-0.009 M / 0.1085 M| x 100%

% Difference = 8.3%

The percent difference between the first two trials is 8.3%.

To find the average molarity, add the three calculated concentrations together and divide by the number of trials:

Average Molarity = (0.104 M + 0.113 M + 0.108 M) / 3

Average Molarity = 0.108 M

Based on the lab procedures guidelines, the average molarity would be the most accurate representation of the unknown concentration of HCI. Therefore, the average molarity of 0.108 M would be the final result.

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Answer:It might exposed

Explanation: or a spayed H2O might change because different water change over time

Mark would need a thermometer to determine the temperature change of a solution during a chemical reaction. A thermometer is a tool used to measure temperature and can be used to monitor and record changes in temperature during a chemical reaction. So the answer is thermometer .

There are different types of thermometers, such as liquid-in-glass thermometers, bimetallic strip thermometers, digital thermometers, and infrared thermometers, among others. The choice of thermometer depends on the specific requirements of the experiment or process being carried out.

By measuring the initial and final temperatures of the solution before and after the chemical reaction, Mark can determine the temperature change, which is an important parameter in many chemical reactions as it provides information about the heat energy involved in the reaction, and helps in understanding the thermodynamics and kinetics of the process. Therefore the answer is thermometer .

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To solve this problem, we need to use the balanced chemical equation for the reaction between zinc (Zn) and hydrochloric acid (HCl):

[tex]Zn + 2HCl - > ZnCl_2 + H_2[/tex]

According to the stoichiometry of this equation, one mole of Zn reacts with two moles of HCl to produce one mole of H2. Therefore, we need to determine the number of moles of Zn in 25 g, and then use the mole ratio to find the number of moles of H2 produced.

Finally, we can convert the number of moles of H2 to volume at STP using the molar volume of a gas.

First, we need to calculate the number of moles of Zn in 25 g:

The molar mass of Zn is 65.38 g/mol

The number of moles of Zn in 25 g is:

25 g / 65.38 g/mol = 0.383 mol Zn

Next, we use the mole ratio from the balanced equation to find the number of moles of H2 produced:

According to the balanced equation, one mole of Zn reacts with one-half mole of H2, so we produce 0.5 x 0.383 = 0.192 mol H2.

Finally, we can use the molar volume of a gas at STP to convert the number of moles of H2 to volume:

The molar volume of a gas at STP is 22.4 dm3/mol

Therefore, the volume of H2 produced is:

V = (0.192 mol) x (22.4 dm3/mol) = 4.30 dm3 or 4,300 ml

Therefore, the volume of hydrogen gas produced at STP is 4.30 dm3 or 4,300 ml when 25 g of zinc is added to excess dilute hydrochloric acid at 31°C and 778 mm Hg pressure.

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To identify the unknown alkene based on its H NMR spectrum, a qualified organic chemist would need to analyze the chemical shifts, integration values, and splitting patterns of the peaks in the spectrum, and compare them with known reference data and other spectroscopic techniques (such as C NMR, IR, and mass spectrometry) to make an accurate determination.

The alkene is likely to be a symmetrical alkene with two equivalent methyl groups attached to the double bond. This can be seen from the singlet at 1.7 ppm, which is characteristic of a methyl group, appearing twice in the spectrum. The ozonolysis of the alkene would lead to the formation of two carbonyl compounds, which are then oxidized to carboxylic acids under the given oxidizing conditions. Therefore, the alkene in question is likely to be cis-2-butene.

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_______________________________

2Na(s) + 2H2O(l) -> 2NaOH(aq) + H2(g)

Moles of NA = Given Mass (g) ÷ Molecular Mass (g/mol)

= 27.5 ÷ 22.9897

= 1.196 mol

Moles of H2 Produced = Mol of NA × 1 mol H2 ÷ 2 Mol NA

= 1.196 × 1 ÷ 2

= 0.60 mol

Number of Molecules = Moles × Avogadro's Number

= 0.60 × 6.023 × 10²³ mol - 1

= 3.61 × 10²³

The Number of Molecules of Hydrogen Gas Produced When Added To Water Is 3.61 × 10²³

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