a) The divergence of F is -4x - 2y,
b) The curl of F is (-2(x+y), 0, -2x).
A) To find the divergence of F, we need to take the dot product of the del operator with F. Therefore, we have:
div(F) = ∇ · F = ∂(yz)/∂x + ∂(-5xz)/∂y + ∂(-4xy)/∂z
= 0 - 5z - 4x
= -5z - 4x
To find the curl of F, we need to take the cross product of the del operator with F. Therefore, we have:
curl(F) = ∇ × F = ( ∂(-4xy)/∂y - ∂(-5xz)/∂z, ∂(yz)/∂z - ∂(4xy)/∂x, ∂(-yz)/∂x - ∂(-5xz)/∂y )
= (-5z, y, -5x)
B) To find the divergence of F, we need to take the dot product of the del operator with F. Therefore, we have:
div(F) = ∇ · F = ∂(-x²)/∂x + ∂(-(x+y)²)/∂y + ∂(0)/∂z
= -2x - 2(x+y)
= -4x - 2y
To find the curl of F, we need to take the cross product of the del operator with F. Therefore, we have:
curl(F) = ∇ × F = ( ∂(0)/∂y - ∂(-(x+y)²)/∂z, ∂(0)/∂z - ∂(-x²)/∂x, ∂(-(x+y))/∂x - ∂(-x²)/∂y )
= (-2(x+y), 0, -2x)
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Find the Zeros of each quadratic equation below by graphing
bro idrk but I think
Answer: The correct option is
(A) {-1, -5}.
Step-by-step explanation: We are given to find the zeroes of the quadratic function graphed in the figure shown.
We know that
the zeroes of a quadratic function f(x) are the value of x for which f(x) is equal to zero.
That is, the points on the graph where the curve crosses the X-axis.
From the graph, we note that the curve of the function crosses the X-axis at the points x = 1 and x = -5.
Therefore, the zeroes of the given function are x = -1 an x = -5.
Thus, option (A) is CORRECT.
I'm board so before this gets reported what's your fav show(s) on netflix
Mine is:
Lucifer
On my block
First few seasons of flash
Question 15
Find the area of the quadrilateral with the vertices A (-8, 6), B(-5, 8), C (-2, 6), and D (-5,0).
units²
Need help with this question?
Get a Hint
The area of the quadrilateral can be found by dividing it into two triangles and finding the sum of their areas. The line connecting points B and D divides the quadrilateral into two triangles ABD and BCD. The area of triangle ABD is 1/2 * base * height = 1/2 * 6 * 6 = 18 square units. The area of triangle BCD is 1/2 * base * height = 1/2 * 3 * 8 = 12 square units. Therefore, the area of the quadrilateral is 18 + 12 = 30 square units.
find the area of the circle
with steps pls
x = 3/8.
Starting from the left side of the equation:
2(x+1) - 3(x-2) = 7x + 5
Simplify the expressions in parentheses:
2x + 2 - 3x + 6 = 7x + 5
Combine like terms:
x + 8 = 7x + 5
Subtract 7x from both sides:
-8x + 8 = 5
Subtract 8 from both sides:
-8x = -3
Divide both sides by -8:
x = 3/8
Therefore, the solution to the equation is x = 3/8.
Answer: M=3
Step-by-step explanation:
Given:
tangent =4cm
secant outside of circle = 2 cm
Find:
M is secant inside of circle
Theorem:
Tangent-Secant Theorem => tangent² =(secant outside)(full secant)
Solution and Set up:
4²=(2)(2+M) >Set up from theorem, square 4 and distribute
16=4+4M >subtract 4 from both sides
12 = 4M >divide both sides by 4
M=3
The area of the shaded region under the curve of a function f(x) = ax + b on the interval [ 0, 4 ] is 16 square units.
The area of the given region under the curve of a function f(x) = ax + b on the interval [0, 4] is 16 square units. So, all the options satisfy the value of a and b except (7, -9).
How to find the area of a region?The area of the given region under the curve of a function f(x) = ax + b on the interval [0, 4] is 16 square units.
f(x) is a linear function, the area under the curve on the interval [0,4] is a trapezoid with a height of 4 and bases of lengths f(0) and f(4).
The area of a trapezoid is the height times the average of the bases.
a. f(x)=-2x+8 f(0)=8, f(4)=0;
area = 4(8/2) = 16
b. f(x)=x+2; f(0)=2, f(4)=6;
area = 4(8/2) = 16
c. f(x)=3x-2; f(0)=-2, f(4)=10;
area = 4(8/2) = 16
d. f(x)=5x-6; f(0)=-6, f(4)=14;
area = 4(8/2) = 16
e. f(x)=7x-9; f(0)=-9, f(4)=19;
area = 4(10/2) = 20
Thus, The area is NOT 16 for choice e.
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Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoccupied seats per flight over the past year. To accomplish this, the records of 300 flights are randomly selected and the number of unoccupied seats is noted for each of the sampled flights. The sample mean is 11. 3 seats and the sample standard deviation is 4. 3 seats.
Required:
Construct a 92% confidence interval for the population mean number of unoccupied seats per flight
If a large airline wants to estimate its average number of unoccupied seats per flight over the past year Then a 92% confidence interval for the population mean number of unoccupied seats per flight is (10.334, 12.266) seats.
To construct a confidence interval for the population mean number of unoccupied seats per flight, we will use the following formula CI = X ± z*(σ/√n)
Where:
X = sample mean = 11.3 seats
σ = sample standard deviation = 4.3 seats
n = sample size = 300
z = z-score corresponding to the desired confidence level of 92%, which we can look up in a standard normal distribution table or use a calculator. For a 92% confidence level, the z-score is 1.75.
Plugging in the values, we get:
CI = 11.3 ± 1.75*(4.3/√300)
CI = 11.3 ± 0.966
Therefore, the 92% confidence interval for the population mean number of unoccupied seats per flight is (10.334, 12.266) seats. This means we can be 92% confident that the true population means a number of unoccupied seats per flight falls within this interval.
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PLEASE HELP ME ASAP
Can you please make a copy and put dots in eachone that goes where its supposed to go
Answer:
1
1
1
2
2
2
2
Step-by-step explanation:
HELP
I need all the help to figure this annoying thing out
Answer:
x = 30 , y = 54
Step-by-step explanation:
the figure is a trapezium
each lower base angle is supplementary to the upper base angle on the same side, then
4x + y + 6 = 180 ( subtract 6 from both sides )
4x + y = 174 ( subtract 4x from both sides )
y = 174 - 4x → (1)
and
2x + 12 + 2y = 180 → (2)
substitute y = 174 - 4x into (2)
2x + 12 + 2(174 - 4x) = 180
2x + 12 + 348 - 8x = 180
- 6x + 360 = 180 ( subtract 360 from both sides )
- 6x = - 180 ( divide both sides by - 6 )
x = 30
substitute x = 30 into (1)
y = 174 - 4(30) = 174 - 120 = 54
thus x = 30 and y = 54
Box and whisker plots
Answer: Box and whisker plots are plots on number lines with a box and two lines off the edges, called whiskers. The box has a line at the upper quartile(1), one at the lower quartile(2), and one in the center of the box at the median(3). The two lines go to the ends of the data, one at the minimum(4) and one at the maximum(5).
4 2 3 1 5
|-----[___|____]-----------|
₀__₁__₂__₃__₄__₅__₆__₇__₈
I hope this helps.
The enrollment of students at a school is decreasing at a constant rate of 5 % per year what percent remains after one year
Answer: depends but just subtract 5 from the original rate
Step-by-step explanation:
example
100 to 95 to 90 to 85 to 80 and etc.
Chase was on his school’s track team and ran the 2400m race. He has been working on his pace and can run 1600m in 5. 5 minutes. If he keeps this pace through the entire race, how long will it take him to finish the 2400m race?
A. 8. 25 minutes
B. 7. 75 minutes
C. 8. 5 minutes
D. 8. 42 minutes
Patty and Carol leave their homes in different cities and drive toward each other on the same highway.
• They start driving at the same time.
• The distance between the cities where they live is 300 miles.
• Patty drives an average of 70 miles per hour.
. Carol drives an average of 50 miles per hour.
Enter an equation that can be used to find the number of hours, t, it takes until Patty and Carol are at the same
location.
The equation to find the number of hours, t, until Patty and Carol are at the same location is: 70t + 50t = 300.
1. Patty and Carol start driving at the same time, towards each other on the same highway.
2. The distance between their cities is 300 miles.
3. Patty drives at an average speed of 70 mph, so in t hours she covers 70t miles.
4. Carol drives at an average speed of 50 mph, so in t hours she covers 50t miles.
5. As they drive towards each other, the sum of the distances they cover should equal the total distance between their cities.
6. Therefore, combining the distances covered by Patty and Carol, we get: 70t (Patty's distance) + 50t (Carol's distance) = 300 (total distance).
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Is there a relationship between the raises administrators at State University receive and their performance on the job? A faculty group wants to determine whether job rating (x) is a useful linear predictor of raise (y). Consequently, the group considered the straight-line regression model, (y) hat = (b) with subscript (1)x+ (b) with subscript (0). Using the method of least-squares regression, the faculty group obtained the following prediction equation, (y) hat=2,000x+ 14,000.
Interpret the estimated y-intercept of the line.
A)There is no practical interpretation, since rating of 0 is not likely and outside the range of the sample data.
B)For an administrator who receives a rating of zero, we estimate his or her raise to be $14,000.
C) The base administrator raise at State University is $14,000.
D) For a 1-point increase in an administrator's rating, we estimate the administrator's raise to increase $14,000
Yes, there is a relationship like a straight line between the raises administrators at State University receive and their performance on the job
The estimated y-intercept of the line in the given straight-line regression model is $14,000.The interpretation of this value is that for an administrator who receives a rating of zero, we estimate his or her raise to be $14,000. This value represents the base raise amount for the administrators at State University, regardless of their job performance rating.To obtain this interpretation, we consider the equation of the regression line, which relates the predicted raise amount (y hat) to the job performance rating (x). The y-intercept term in this equation is the value of y hat when x equals zero. Therefore, the estimated y-intercept of $14,000 represents the predicted raise amount for an administrator whose job performance rating is zero, which corresponds to the base raise amount at State University.
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The quantity of a substance can be modeled by the function R(t) that satisfies the differential equation dR/dt= -1/5(R – 20). One point on this function is R(2) = 35. Based on this model, use a linear approximation to the graph of Rat t = 2 to estimate the quantity of the substance at t 1.9. \
The estimated quantity of the substance at t = 1.9 is approximately 35.3 units.
To estimate the quantity of the substance at t = 1.9 using linear approximation, we can use the formula:
ΔR ≈ dR/dt * Δt
Given the point R(2) = 35 and the differential equation dR/dt = -1/5(R – 20), we can first find the value of dR/dt at t = 2.
dR/dt(2) = -1/5(R(2) – 20) = -1/5(35 – 20) = -1/5(15) = -3
Now, we can calculate Δt, which is the difference between the given t-value (2) and the desired t-value (1.9):
Δt = 1.9 - 2 = -0.1
Next, we can calculate ΔR using the linear approximation formula:
ΔR ≈ dR/dt * Δt ≈ -3 * (-0.1) = 0.3
Finally, we can estimate the quantity of the substance at t = 1.9 by adding ΔR to the given value of R(2):
R(1.9) ≈ R(2) + ΔR ≈ 35 + 0.3 = 35.3
Therefore, the estimated quantity of the substance at t = 1.9 is approximately 35.3 units.
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consider h(x)= 11x² - 6x calculate H (x) Fx 6.Xr1 유 11 6 3 (22.-6) 3 6 In(3) 11 A) 2 +1 (221 - 6)31 B) - (11r? - br)3*** In(3) 2 (3***") - 6 In(3) (221 - 63#* - (1142 – 63)3 (3***")" 2 +1 4 (221 - 63 - (1122 – 6x)3 In(3) i 1 D)
The answer is B) - (11x² - 6x)ln(3) + 2ln(3) - 6ln(x) + C, where C is the constant of integration.
To solve this problem, we are given a function h(x) and asked to find its antiderivative or indefinite integral, which is denoted by H(x) and is defined as the function whose derivative is h(x). We are also given a specific value of H(x) at x = 6 and asked to use it to find the constant of integration, denoted by C.
The given function is h(x) = 22x - 3x² - 6/x, and we want to find H(x), which is the antiderivative of h(x). Using the power rule of integration, we can integrate each term of h(x) separately:
∫ (22x - 3x² - 6/x) dx = ∫ 22x dx - ∫ 3x² dx - ∫ 6/x dx= 11x² - x³ - 6ln|x| + Cwhere C is the constant of integration. Note that we need to include an absolute value sign around x in the natural logarithm term because the function is not defined for x = 0.
Next, we are given that H(6) = 31, which means that when x = 6, the value of H(x) is 31. Substituting x = 6 and H(x) = 31 into the above equation, we get:
31 = 11(6)² - (6)³ - 6ln|6| + CSimplifying, we get:
31 = 132 - 216 - 6ln(6) + CC = 221/3 - 6ln(6)Therefore, the antiderivative of h(x) is:
H(x) = 11x² - x³ - 6ln|x| + 221/3 - 6ln(6)We can simplify the expression by using the identity ln|a/b| = ln|a| - ln|b|:
H(x) = 11x² - x³ - 6ln(3) - 6ln(x) + 2ln(3) + Cwhere C is the constant of integration. Thus, the final answer is:
B) - (11x² - 6x)ln(3) + 2ln(3) - 6ln(x) + C, where C is the constant of integration.To learn more about integration, here
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Find the following limit. Is the function continuous at the point being approached? lim sec (ysec²y- tan²y-1) y→ 1 lim sec (y sec²y-tan ²y-1)- (Simplify your answer.) y→ 1
The limit of sec(y sec²y - tan²y - 1) as y approaches 1 is undefined. The function is not continuous at the point being approached.
Explanation: To evaluate the limit, we can first simplify the expression inside the secant function using the trigonometric identity:sec²θ - tan²θ = 1/cos²θ - sin²θ/cos²θ = (1 - sin²θ)/cos²θ = cos²θ / cos²θ = 1Substituting this expression back into the limit, we get:lim sec(y sec²y - tan²y - 1)y→1= lim sec(y - 1)y→1As y approaches 1, the argument of the secant function approaches 0, which means that the secant function approaches infinity. Therefore, the limit is undefined.Since the limit is not defined, the function is not continuous at the point being approached. A function is continuous at a point if and only if the limit of the function as x approaches that point exists and is equal to the value of the function at that point. In this case, since the limit does not exist, the function is not continuous at y = 1.
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6. A football player throws a football. The function h given by h(t) = 6 + 75+ - 161
describes the football's height in feet † seconds after it is thrown.
A. The football is thrown from ground level.
B. The football is thrown from 6 feet off the ground.
C. In the function, - 167? represents the effect of gravity.
D. The outputs of h decrease then increase in value.
E. The function h has 2 zeros that make sense in this situation.
F. The vertex of the graph of h gives the maximum height of the foot
The correct options are:
The football is thrown from 6 feet off the ground. In the function, - 167? represents the effect of gravity.The vertex of the graph of h gives the maximum height of the footThe description of the football's heightOption B: The football is thrown from 6 feet off the ground.
when t = 0
h(t) = 6 * 75 * 0 + 16 * 0
= 6 feet
Option C : - 16t² represents the effect of gravity
we have
[tex]h = ut - \frac{1}{2}gt^2[/tex]
[tex]\frac{1}{2}gt^2=-16t^2[/tex]
F. The vertex of the graph of h gives the maximum height of the foot
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Directions: Write an equation for the circle shown on the graph in standard form. 15.
Answer: x(squared) + (y + 2)(squared) = 36
Step-by-step explanation:
The center of the circle is at (0 , -2), so we will eliminate the x value by just writing x(squared), and then we will write the y value as (y + 2)(squared) because the standard form for a circle is
(x - h)(squared) + (y + 2)(squared) = r(squared)
And if we count from the center to the top point of the circle, the number would be 6, so we would square 6 which would be 36.
In the diagram below, quadrilateral HIJK is inscribed in circle L. Solve for x and y.
The values of the variables x and y area 42 and 12 respectively
How to determine the valuesWe can see that the quadrilateral that is inscribed in the circle is a parallelogram.
The properties of a parallelogram includes;
The opposite sides of a parallelogram are equalThe opposite angles of a parallelogram are equalThere are adjacent and non- adjacent anglesThen, from the information given, we have that;
x + 35 = 77
Now. collect the like terms, we get;
x = 77 - 35
subtract the values, we have;
x = 42
Also,
4y + 46 = 94
collect the like terms
4y = 94 - 46
4y = 48
Divide by the coefficient of y, we have;
y = 12
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In an isosceles triangle, the measure of a base angle is 65. Find the number of degrees in the measure of the vertex angle
The number of degrees in the measure of the vertex angle is 50 degrees.
An isosceles triangle has two equal sides and two equal base angles. In your question, the measure of a base angle is 65 degrees. To find the measure of the vertex angle, we'll use the fact that the sum of angles in any triangle is always 180 degrees.
Since both base angles are equal, their combined measure is 2 * 65 = 130 degrees. Now, we subtract the sum of the base angles from the total angle measure of the triangle:
180 degrees (total angle measure) - 130 degrees (sum of base angles) = 50 degrees.
So, the measure of the vertex angle in the isosceles triangle is 50 degrees. In summary, when given the measure of a base angle in an isosceles triangle, we can use the triangle's angle sum property to find the measure of the vertex angle.
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Please help. The problem is found in the photo below, just please help.
Answer:
-4 = 5
0 = -1
2 = -4
4 = -7
(-4, 5)
(0, -1)
(2, -4)
(4, -7)
Step-by-step explanation:
First, let's identify what each term represents.
y-intercept: -1
slope: 3/2
Then, fill out the table.
x = -4
-1 - (3/2 · -4)
-1 - (-12/2)
-1 - (-6)
-1 + 6
y = 5
x = 0
-1 - (3/2 · 0)
-1 - 0
y = -1
x = 2
-1 - (3/2 · 2)
-1 - (6/2)
-1 - (3)
y = -4
x = 4
-1 - (3/2 · 4)
-1 - (12/2)
-1 - (6)
y = -7
Then, plot the points in the function on the graph.
(-4, 5)
(0, -1)
(2, -4)
(4, -7)
The height of three basketball players is 210 cm, 220 cm and 191 cm.
What is their average height?
Answer:
Average height = 207 cmStep-by-step explanation:
It's given that, The height of three basketball players is 210 cm, 220 cm and 191 cm.
h₁ = 210 cm
h₂ = 220 cm
h₃ = 191 cm
Total number of observations = 3.
Average = Sum of all observations/Total number of observations.
↠ Average = h₁ + h₂ + h₃/3
↠ Average = 210 +220 + 191 /3
↠ Average = 430 + 191/3
↠ Average = 621/3
↠ Average = 207
Therefore, The required average height is 207 cm.
The length of one diagonal of a rhombus is a geometric mean of the length of the other diagonal and the length of the side. Find angle measures of a rhombus
The angle measure of the rhombus with one diagonal of a rhombus is a geometric mean of the length of the other diagonal are measured to be 75.5° .
Let d₁ and d₂ be the lengths of the diagonals of the rhombus and s as the side length. We have,
d₁ = s√2 (since the diagonal is the hypotenuse of a right triangle formed by two sides of length s)
d₁ = √d₂s
Combining these two equations, we get,
s√2 = √d₂s
Squaring both sides, we get,
2s² = d₂
Since the diagonals of a rhombus are perpendicular bisectors of each other, we have,
cosθ = (1/2) (where θ is one of the acute angles of the rhombus)
Using the law of cosines with sides s and d₂/2, we have,
(s² + (d₂/2)² - 2sd₂/2cosθ) = s²
Simplifying, we get,
d₂ = 4s cosθ
Substituting this expression for d₂ in 2s² = d₂, we get,
2s² = 4scosθ
Dividing both sides by 2s and simplifying, we get,
s = 2cosθ
Therefore, the angle measures of the rhombus are,
θ = arccos(s/2)
= arccos(cosθ/2)
= arccos(1/4)
= 75.5°
And the other acute angle has the same measure.
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A baker has a small and large bag of sugar for making cakes. The large bag contains 30 cups of sugar and is 2. 5 times larger than the small bag. The small bag contains enough sugar to make 9 cakes and has 0. 75 cups of sugar remaining.
how many cakes can be made with a large bag of sugar?
After solving the word problem, the large bag contains enough sugar to make 40 cakes
Since the large bag is 2.5 times larger than the small bag, and the small bag contains enough sugar to make 9 cakes, the large bag contains enough sugar to make:
2.5 * 9 = 22.5 cakes
However, since there are only 30 cups of sugar in the large bag, and we don't know how much sugar is needed to make a single cake, we cannot determine the exact number of cakes that can be made with a large bag of sugar.
As for the small bag, if it had enough sugar to make 9 cakes and there are 0.75 cups of sugar remaining, then each cake requires:
(sugar in bag - remaining sugar) / number of cakes
= (9 - 0.75) / 9
= 0.75 cups of sugar
Therefore, the large bag contains enough sugar to make:
30 cups / 0.75 cups per cake
= 40 cakes
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1. p(x)= f(x)+g(x)
Write the equation of p(x)
Answer:p(x)=3x+5
Step-by-step explanation:
f(x)=2x+3
g(x)=x+2
p(x)=(2x+2)+(x+2)= 3x+5
Answer:
p(x)=ax + b
Step-by-step explanation:
A shipping company must design a closed rectangular shipping crate with a square base. The volume is 12288ft3. The material for the top and sides costs $2 per square foot and the material for the bottom costs $10 per square foot. Find the dimensions of the crate that will minimize the total cost of material.
Optimize crate cost by expressing material cost in terms of x and y, calculating cost of all four sides, and finding minimum cost. Optimal dimensions: x = 16 ft, y = 48 ft. Minimum cost: $8704.
To find the dimensions of the crate that will minimize the total cost of material, we need to use optimization techniques, we need to express the cost of materials in terms of x and y then calculate the cost of all four sides, then find the minimum cost.
Let's start by defining the variables we need to work with:
Let x be the length of one side of the square base (in feet), Let y be the height of the crate (in feet).
From the given volume, we know that:
V = x^2 * y = 12288 ft^3
We can use this equation to solve for one of the variables in terms of the other:
y = 12288 / (x^2)
Now we need to express the cost of materials in terms of x and y.
The area of the bottom is x^2, so the cost of the bottom is:
[tex]C_b = 10 * x^2[/tex]
The area of each side is x * y, and there are four sides, so the cost of the sides is:
[tex]C_s = 4 * 2 * x * y = 8xy[/tex]
The area of the top is also x^2, so the cost of the top is:
[tex]C_t = 2 * x^2[/tex]
The total cost of materials is the sum of these three costs:
[tex]C = C_b + C_s + C_t = 10x^2 + 8xy + 2x^2[/tex]
Now we can substitute y = 12288 / (x^2) into this equation:
[tex]C = 10x^2 + 8x * (12288 / x^2) + 2x^2[/tex]
Simplifying this expression, we get:
[tex]C = 12x^2 + 98304 / x[/tex]
To find the minimum cost, we need to find the value of x that minimizes this expression. We can do this by taking the derivative of C with respect to x and setting it equal to zero:
C' = 24x - 98304 / x^2 = 0
Solving for x, we get:
x = 16 ft
Now we can use this value of x to find y:
y = 12288 / (16^2) = 48 ft
Therefore, the dimensions of the crate that will minimize the total cost of material are:
- Length of one side of the square base = x = 16 ft
- Height of the crate = y = 48 ft
To check that this is indeed the minimum cost, we can plug these values back into the expression for C and calculate the cost:
C = 10 * 16^2 + 8 * 16 * 48 + 2 * 16^2 = 8704
Therefore, the minimum cost of material for the crate is $8704.
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The length of one diagonal in a rhombus is 26. 4 cm and the area of the rhombus is 204. 6 cm squared. How long is the second diagonal?
A rhombus with a diagonal of 26.4 cm and an area of 204.6 square cm has another diagonal of length 15.5 cm
Rhombus is a 2-Dimensional shape. It is a quadrilateral. It is a specialized form of a parallelogram. All sides of a rhombus are equal in length.
Similar to a parallelogram, it has opposite sides parallel to each other and opposite angles of equal magnitude.
The area of a rhombus is expressed as half of the product of diagonals.
A = 0.5pq
A is the area
p is the length of one diagonal
q is the length of another diagonal
A = 204.6 square cm
p = 26.4 cm
204.6 = 0.5 * 26.4 * q
q = 15.5 cm
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Use logarithmic differentiation to find the derivative of the function y= x²/x y'(x)= 2 + 1 In x) x²
To use logarithmic differentiation to find the derivative of the function y = x²/x, we first take the natural logarithm of both sides:
ln(y) = ln(x²/x)
Using the properties of logarithms, we can simplify this to:
ln(y) = 2 ln(x) - ln(x)
Now we differentiate both sides with respect to x using the chain rule:
1/y * y' = 2/x - 1/x
Simplifying this expression, we get:
y' = y * (2/x - 1/x²)
Substituting back in the original expression for y, we have:
y' = x²/x * (2/x - 1/x²)
Simplifying further, we get: y' = 2x - 1/x
Therefore, the derivative of the function y = x²/x using logarithmic differentiation is y' = 2x - 1/x.
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A ball of radius 11 has a round hole of radius 4 drilled through its center.
Find the volume of the resulting solid.
The volume of the resulting solid is estimated 4,128.38 cubic units.
How do we calculate?
The volume of the ball isgitten as:
V_ball = (4/3)πr^3
r is the radius of the ball. In this scenario
r = 11, so:
V_ball = (4/3)π(11)^3
V_ball = (4/3)π(1331)
V_ball = 4,396.46 cubic units
The volume of the hole is gotten as :
V_hole = (4/3)πr^3
r is the radius of the hole.
In thisscenario, r = 4, so:
V_hole = (4/3)π(4)^3
V_hole = (4/3)π(64)
V_hole = 268.08 cubic units
In conclusion, the volume of the resulting solid is:
V_resulting_solid = V_ball - V_hole
V_resulting_solid = 4,396.46 - 268.08
V_resulting_solid = 4,128.38 cubic units
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Mrs. Thomas has two rolls of garden edging that are each 96 inches long.
She wants to make two new flower beds in her back yard. Each flower bed
will be bordered by one roll of the edging. One flower bed will be in the
shape of a quadrilateral. The other will be in the shape of a triangle.
Mrs. Thomas decides to make a scale drawing of each flower bed using a
scale of 1 centimeter = 5 inches. What will be the total length of each roll
of edging in her scale drawings?
The total length of each roll of edging in Mrs. Thomas's scale drawings will be 19.2 cm.
How to find the total length ?To find the total length of each roll of edging in her scale drawings, we need to convert the length from inches to centimeters using the given scale.
To convert the length to centimeters:
( Length in cm ) / ( Length in inches ) = ( 1 cm ) / ( 5 inches )
x / 96 inches = 1 cm / 5 inches
x 5 inches = 96 inches x 1 cm
5x = 96 cm
x = 96 cm / 5
x = 19.2 cm
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