Adding fractions​

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Step-by-step explanation:

-3x - 2x - 5 = -7

-5x - 5 = -7

-5x = -7 + 5

-5x = -2

x = 2/5

Answer:Therefore, the cost of a utility pole with a diameter of 42 cm and a height of 740 cm is approximately $1957.43.

Step-by-step explanation:First, we need to calculate the volume of the cylinder-shaped utility pole:

The radius of the pole is half the diameter, so it's 42 cm / 2 = 21 cm.

The height of the pole is 740 cm.

The volume of a cylinder is given by the formula V = πr²h, where π is approximately 3.14, r is the radius, and h is the height.

Substituting the values we have, we get V = 3.14 x 21² x 740 = 1,034,462.4 cm³.

Now we can calculate the mass of the pole:

The density of the metal is 6.3 g/cm³, which means that 1 cm³ of the metal has a mass of 6.3 g.

The volume of the pole is 1,034,462.4 cm³, so its mass is 6.3 x 1,034,462.4 = 6,524,772.72 g.

Next, we convert the mass to kilograms and calculate the cost:

1 kg is equal to 1000 g, so the mass of the pole in kilograms is 6,524,772.72 g / 1000 = 6524.77 kg.

The cost of the metal is $0.30 per kilogram, so the cost of the pole is 6524.77 kg x $0.30/kg = $1957.43.

Answer:

7.6 cm

Step-by-step explanation:

[tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]

[tex]a^{2}[/tex] + [tex]6.5^{2}[/tex] = [tex]10^{2}[/tex]

[tex]a^{2}[/tex] + 42.25 = 100 Subtract 42.25 from both sides

[tex]a^{2}[/tex] = 57.57

[tex]\sqrt{\a^{a} }[/tex] = [tex]\sqrt{57.57}[/tex]

a ≈ 7.6

Helping in the name of Jesus.

Answer:

7.6 cm

Step-by-step explanation:

a^2+ b^2=c^2

a^2+6.5^2=10^2

a^2+42.25=100 subtract 42.25 from both sides

a^2=57.57

a=√57.57

a=7.6 cm

The total amount of the principal, interest, down payment, and fees described for Brooke's condominium is $1,154,091.59

The first step is to calculate the mortgage amount, which is the purchase price minus the down payment:

Mortgage amount = $413,600 - 9% of $413,600 = $376,576

Next, we need to calculate the total cost of the fees and charges:

Discount points = 1% of $376,576 = $3,766

Origination fee = 0.75% of $376,576 = $2,823.42

Documentary stamp tax on deed = $0.70 per $100 or portion thereof, so for $413,600 it would be:

$0.70 * ($413,600 / $100) = $2,895.20

Documentary stamp tax on mortgage = $0.35 per $100 or portion thereof, so for $376,576 it would be:

$0.35 * ($376,576 / $100) = $1,318.02

Brokerage fee = $175 + 5% of $376,576 = $19411.8

Intangible tax = 0.2% of $376,576 = $753.15

Now we can calculate the total cost of the principal and interest payments over the life of the mortgage. We'll use a mortgage calculator to do this, based on the mortgage amount, interest rate, and term:

Total mortgage payments = $2,244 * 12 months * 25 years = $673,200

Finally, we can add up all of these amounts to get the total cost of the principal, interest, down payment, and fees:

Total cost = Purchase price + Down payment + Mortgage payments + Discount points + Origination fee + Documentary stamp tax on deed + Documentary stamp tax on mortgage + Brokerage fee + Intangible tax

Total cost = $413,600 + $37,224 + $673,200 + $3,766 + $2,823.42 + $2,895.20 + $1,318.02 + $19,411.80 + $753.15

Total cost = $1,154,091.59

Therefore, we got a total cost of $1,154,091.59

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At the end of the weekend, Elisa had the most biscuits (168). So, the answer is (E) Elisa baked the most biscuits on Saturday.

To determine who baked the most biscuits on Saturday, we need to calculate how many biscuits each child had at the end of the weekend.

Anna had 24 biscuits, Berta had 25, Charlie had 26, David had 27, and Elisa had 28.

Let's start with the child who had twice as many biscuits as on Saturday. We can divide their total number of biscuits by 2 to get the number they had on Saturday.

If we try this calculation for each child, we find that only Elisa's total number of biscuits (28) is evenly divisible by 2. Therefore, Elisa must be the child who had twice as many biscuits as on Saturday, meaning she had 14 biscuits on Saturday.

We can use a similar process to determine how many biscuits each child had on Saturday:

- The child who had three times as many biscuits as on Saturday must have had a total of 42 biscuits, which means they had 14 biscuits on Saturday.
- The child who had four times as many biscuits as on Saturday must have had a total of 56 biscuits, which means they had 14 biscuits on Saturday.
- The child who had five times as many biscuits as on Saturday must have had a total of 70 biscuits, which means they had 14 biscuits on Saturday.
- The child who had six times as many biscuits as on Saturday must have had a total of 84 biscuits, which means they had 14 biscuits on Saturday.

Now we can add up the number of biscuits each child had on Saturday:

- Anna had 24 biscuits.
- Berta had 25 biscuits.
- Charlie had 26 biscuits.
- David had 27 biscuits.
- Elisa had 14 biscuits.

Therefore, David baked the most biscuits on Saturday with 27.
To determine who baked the most biscuits on Saturday, we need to consider the information given about the multiplication factors (twice, 3 times, 4 times, 5 times, and 6 times) and the initial number of biscuits baked by each child.

1. Anna baked 24 biscuits.
2. Berta baked 25 biscuits.
3. Charlie baked 26 biscuits.
4. David baked 27 biscuits.
5. Elisa baked 28 biscuits.

Now, let's apply the multiplication factors and see which child had the most biscuits at the end of the weekend:

1. Anna: 24 x 2 = 48
2. Berta: 25 x 3 = 75
3. Charlie: 26 x 4 = 104
4. David: 27 x 5 = 135
5. Elisa: 28 x 6 = 168

At the end of the weekend, Elisa had the most biscuits (168). So, the answer is (E) Elisa baked the most biscuits on Saturday.

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To calculate the relative frequency for each category, divide the number of marked mountain goats in each category by the total number of marked mountain goats.

Total marked mountain goats = 71 (male) + 93 (female) = 164
Total marked mountain goats = 103 (adult) + 61 (baby) = 164

Relative frequency for male goats = Male goats / Total marked mountain goats = 71/164
Relative frequency for female goats = Female goats / Total marked mountain goats = 93/164
Relative frequency for adult goats = Adult goats / Total marked mountain goats = 103/164
Relative frequency for baby goats = Baby goats / Total marked mountain goats = 61/164

Your answer:
Relative frequency for male goats = 71/164
Relative frequency for female goats = 93/164
Relative frequency for adult goats = 103/164
Relative frequency for baby goats = 61/164

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c = number of chickens

d = number of ducks

c = 4d because there are 4 times as many chickens as ducks

c = d+72 because there are 72 more chickens

4d = d+72 after using substitution

4d-d = 72

3d = 72

d = 72/3

d = 24

c = 4d = 4*24 = 96  ...or...  c = d+72 = 24+72 = 96

The coordinates of p so that p partitions the segment of AB in the ratio 7 to 2 if A( -5,4) and B( -8,-2) is P(x, y) = [-22/3, -2/3].

In this scenario, line ratio would be used to determine the coordinates of the point P on the directed line segment that partitions the segment into a ratio of 1 to 4.

In Mathematics and Geometry, line ratio can be used to determine the coordinates of P and this is modeled by this mathematical equation:

P(x, y) = [(mx₂ + nx₁)/(m + n)],  [(my₂ + ny₁)/(m + n)]

By substituting the given parameters into the formula for line ratio, we have;

P(x, y) = [(mx₂ + nx₁)/(m + n)],  [(my₂ + ny₁)/(m + n)]

P(x, y) = [(7(-8) + 2(-5))/(7 + 2)],  [(7(-2) + 2(4))/(7 + 2)]

P(x, y) = [(-56 - 10)/(9)],  [(-14 + 8)/9]

P(x, y) = [-66/9],  [(-6)/(9)]

P(x, y) = [-22/3, -2/3]

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The height of the cone is 3.4cm

A cone is a shape formed by using a set of line segments or the lines which connects a common point, called the apex or vertex.

The volume of a cone is expressed as;

V = 1/3 πr²h

where πr² = base area. therefore the volume can be written as;

V = 1/3 base area × height

base area = 49cm²

height = 45.3 cm³

45 = 1/3 ×40h

135 = 40h

h = 135/40

h = 3.4cm

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The correct statement regarding the maximum values of the quadratic functions is given as follows:

Function 1 has the larger maximum at (4, 1).

The standard definition of a quadratic function is given as follows:

y = ax² + bx + c.

The x-coordinate of the vertex of a quadratic function is given as follows:

x = -b/2a.

Hence, for each function, the x-coordinate of the vertex is given as follows:

Each function has a negative leading coefficient, hence the vertex represents a maximum value, and the y-coordinate is given as follows:

1 > -14, hence the correct statement is given as follows:

Function 1 has the larger maximum at (4, 1).

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A compound inequality to show the distance from the boys home to the chief's camp is 5 < d < 8

The distance from the boy's home to the school is 5km.

The distance from the boy's home to the market is 8km.

The chief's camp is closer to the boy's home than the market, but further than the school

The chief's camp is closer to the boy's home than the market, so the distance from the boy's home to the chief's camp is less than 8km.

Putting these together, we can write a compound inequality to show the possible distances d from the boy's home to the chief's camp:

distance from home to school < distance < home to maket

5 < d < 8

The inequality is 5 < d < 8.

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Angela made $350 per week 25 years ago and Walker made $200 per week 25 years ago.

Let's assign variables to represent Angela and Walker's salaries 25 years ago. Let A be Angela's salary 25 years ago and W be Walker's salary 25 years ago.

Using the information given in the problem, we can set up two equations:

A + W = 550 (their total salary 25 years ago)
4A + 3W = 2000 (their total current salary)

To solve for A and W, we can use substitution or elimination. Let's use substitution.

From the first equation, we can rearrange to solve for A:

A = 550 - W

Substitute this into the second equation:

4(550 - W) + 3W = 2000

Distribute the 4:

2200 - 4W + 3W = 2000

Simplify:

W = 800

Now that we know Walker's salary 25 years ago was $800, we can plug that into the first equation to solve for Angela's salary:

A + 800 = 550

A = -250

Uh oh, a negative salary doesn't make sense in this context. We made a mistake somewhere.

Let's go back to our original equations and try elimination instead:

A + W = 550
4A + 3W = 2000

Multiplying the first equation by 4, we get:

4A + 4W = 2200

Subtracting the second equation from this, we get:

W = 200

Now we can plug this into either equation to solve for A:

A + 200 = 550

A = 350

So Angela made $350 per week 25 years ago and Walker made $200 per week 25 years ago.

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The inequality that is true is Negative 2 and three-fourths less-than negative 1 and one-half.

The first inequality from the number line can be shown to be :

( 1 / 4 ) < - 1 1 / 2

This is not possible as a negative cannot be larger than a positive.

The second inequality is:

- 2. 75 < - 1. 5

This is true as larger negative numbers are lower than smaller negative numbers.

The third inequality is:

- 2. 25 > - 1. 25

This is not possible for the reason explained.

In conclusion, option B is correct.

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The line intersects the plane at the point (-4, 15, -6).

The line (x, y, z) = (2, -3, 0) + k(-1, 3, -1) can be expressed parametrically as:

x = 2 - k

y = -3 + 3k

z = k

The plane [x, y, 2] = [4, -15, -8] + s[1, -3, 1] + t[2, 3, 1) can be expressed in scalar form as:

x + y - 2z = 14 + s - 2t

To find the intersection of the line and the plane, we can substitute the parametric equations of the line into the scalar equation of the plane:

(2 - k) + (-3 + 3k) - 2k = 14 + s - 2t

Simplifying this equation, we get:

-4k + 3 = 14 + s - 2t

We can also express the line and plane equations in vector form:

Line: r = (2, -3, 0) + k(-1, 3, -1) = (2-k, -3+3k, k)

Plane: r = (4, -15, -8) + s(1, -3, 1) + t(2, 3, 1) = (4+s+2t, -15-3s+3t, -8+s+t)

To find the intersection of the line and the plane, we need to find the values of k, s, and t that satisfy both equations simultaneously. We can do this by equating the vector forms of the line and plane and solving for k, s, and t:

2 - k = 4 + s + 2t

-3 + 3k = -15 - 3s + 3t

k = -8 - s - t

Substituting k into the first equation, we get:

2 + 8 + s + t = 4 + s + 2t

Simplifying this equation, we get:

t = 4

Substituting t = 4 and k = -8 - s - t into the second equation, we get:

-3 + 3(-8 - s - 4) = -15 - 3s + 3(4)

Simplifying this equation, we get:

s = -2

Substituting t = 4 and s = -2 into the first equation, we get:

k = 8 - s - t = 8 + 2 - 4 = 6

Therefore, the line intersects the plane at the point (x, y, z) = (2, -3, 0) + 6(-1, 3, -1) = (-4, 15, -6).

So the line intersects the plane at the point (-4, 15, -6).

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The decay of isotope at compound rate is approximately 0.0140.

To find the continuous compound rate of decay of this isotope, we can use the following formula:

Nₜ = N₀e^(-λᵗ)

Where:
Nₜ is the amount of the isotope present after time t (years),
N₀ is the initial amount of the isotope,
λ is the continuous compound rate of decay, and
t is the time in years.

In this case, 91.9% of the isotope is still present 6 years after the disaster,

so Nₜ = 0.919 * N₀, and t = 6 years.

We want to find λ, the continuous compound rate of decay.

We can rewrite the formula as follows:

0.919 * N₀ = N₀ * e^(-λ * 6)

Divide both sides by N₀:

0.919 = e^(-λ * 6)

Now, take the natural logarithm (ln) of both sides:

ln(0.919) = -λ * 6

Divide by -6 to solve for λ:

λ = ln(0.919) / (-6)

Calculate the value:

λ ≈ 0.0140

So, the continuous compound rate of decay of this particular radioactive isotope is approximately 0.0140.

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The missing value in the frequency table from the electronics manufacturers would be 150.

The class interval of the battery life is in fives which means that between 25 and 30, the shaded region on the histogram would represent 28 ≤ x < 30.

Looking at the y axis, we can tell that the class interval is 50 thanks to the 120 achieved by 15 ≤ x < 20. This then means that as 28 ≤ x < 30 is sitting on the third y interval, we know that it has a value of 150.

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The possible coordinates of point A are (-9, -7) and (-9, 11).

Coordinates refers to a set of numbers that are used to identify the position of a point in a space, usually defined by an x-axis, y-axis, and in sometimes a z-axis.

Let the y-coordinate of point A be y. Then the coordinates of point A are (-9, y).

Using the distance formula, we have:

√[(3 - (-9))² + (2 - y)²] = 15

Simplify the equation:

√[(12)² + (2 - y)² = 15

Square both sides of the equation, we get:

(12)² + (2 - y)² = 15²

144 + (2 - y)² = 225

(2 - y)² = 225 - 144

(2 - y)² = 81

We now take the square root of both sides:

2 - y = ±9

Solve for y in each case, we get:

y = 2 - 9 = -7 or y = 2 + 9 = 11

Therefore, the possible coordinates of point A are (-9, -7) and (-9, 11).

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If Chris bought 5 tacos and 2 burritos for $13. 25 and  Brett bought 3 tacos and 2 burritos for $10. 75, the price of one taco is $1.25, and the price of one burrito is $3.50.

Let the price of one taco be T and the price of one burrito be B. We have the following equations:

5T + 2B = $13.25
3T + 2B = $10.75

To find the prices of the taco and the burrito, we can use the system of equations. First, subtract the second equation from the first equation:

(5T + 2B) - (3T + 2B) = $13.25 - $10.75
2T = $2.50

Now, divide by 2 to find the price of one taco:

T = $1.25

Next, plug the value of T back into one of the equations (let's use the second equation):

3($1.25) + 2B = $10.75
$3.75 + 2B = $10.75

Now, subtract $3.75 from both sides:

2B = $7.00

Finally, divide by 2 to find the price of one burrito:

B = $3.50

So, the price of one taco is $1.25, and the price of one burrito is $3.50.

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The unknown number x = (6.1 ± sqrt(6.

Let's call the two numbers x and y.

We are given:

AM (Arithmetic Mean) between x and y exceeds their GM (Geometric Mean) by 2:

(x + y)/2 - sqrt(xy) = 2

GM between x and y exceeds their HM (Harmonic Mean) by 1.8:

sqrt(xy) - 2xy/(x+y) = 1.8

We can solve for one variable in terms of the other from the second equation and substitute into the first equation to solve for the remaining variable. Let's solve for y in terms of x from the second equation:

sqrt(xy) - 2xy/(x+y) = 1.8

sqrt(xy)(x+y) - 2xy = 1.8(x+y)

sqrt(xy)x + sqrt(xy)y - 2xy = 1.8x + 1.8y

sqrt(xy)(x+y-1.8) = 0.2x + 0.8y

x+y-1.8 = (0.2/0.8)sqrt(xy)(x+y-1.8)

x+y-1.8 = 0.25sqrt(xy)(x+y-1.8)

4x + 4y - 7.2 = sqrt(xy)(x+y)

Now we can substitute this expression for sqrt(xy)(x+y) into the first equation and solve for x:

(x + y)/2 - sqrt(xy) = 2

(x + y)/2 - (4x + 4y - 7.2)/4 = 2

2(x + y) - (4x + 4y - 7.2) = 8

12.2 = 2x + 2y

6.1 = x + y

Now we can substitute x + y = 6.1 into the expression we derived for sqrt(xy)(x+y) to solve for sqrt(xy):

4x + 4y - 7.2 = sqrt(xy)(x+y)

4x + 4y - 7.2 = sqrt(xy)(6.1)

sqrt(xy) = (4x + 4y - 7.2)/6.1

Finally, we can substitute both x + y = 6.1 and sqrt(xy) = (4x + 4y - 7.2)/6.1 into the equation sqrt(xy) - 2xy/(x+y) = 1.8 and solve for y:

sqrt(xy) - 2xy/(x+y) = 1.8

(4x + 4y - 7.2)/6.1 - 2xy/6.1 = 1.8

4x + 4y - 7.2 - 12.2xy = 11.38

4x + 4y - 11.38 = 12.2xy

4x + 4(6.1 - x) - 11.38 = 12.2xy (substituting x + y = 6.1)

xy = 4.08

Now we know that xy = 4.08, and we can use this to solve for x and y:

y = 6.1 - x

xy = 4.08

x(6.1 - x) = 4.08

6.1x - x^2 = 4.08

x^2 - 6.1x + 4.08 = 0

We can solve for x using the quadratic formula:

x = (6.1 ± sqrt(6.

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The colony will need to triple in number after about 7.58 days.

Since the number of bacteria doubles every 5 days, we can write the relationship between the number of bacteria and time as an exponential function:

N(t) = N0 x 2^(t/5)

where N0 is the initial number of bacteria and t is the time in days.

To find out how long it will take for the colony to triple in number, we need to solve the equation:

N(t) = 3N0

Substituting the expression for N(t) from above, we get:

N0 x 2^(t/5) = 3N0

Dividing both sides by N0, we get:

2^(t/5) = 3

Taking the logarithm of both sides (with base 2) gives:

t/5 = log2(3)

Multiplying both sides by 5, we get:

t = 5 x log2(3)

Using a calculator or a computer program to evaluate the logarithm, we get:

t ≈ 7.58

Therefore, the colony will need to triple in number after about 7.58 days.

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Rounded to the nearest cubic centimeter, the volume of the regular hexagonal prism is approximately 82 [tex]cm^3.[/tex]

To calculate the volume of the regular hexagonal prism, we need to find the area of the base and multiply it by the height.

The base of the prism is a regular hexagon with side length 3 centimeters. The formula for the area of a regular hexagon is:

[tex]Area = (3√3/2) * (side length)^2.[/tex]

Substituting the given side length of 3 centimeters:

[tex]Area = (3√3/2) * 3^2[/tex]

= (3√3/2) * 9

= (27√3/2).

Now, let's calculate the volume by multiplying the base area by the height:

Volume = Area * height

= (27√3/2) * 7

≈ 81.729[tex]cm^3[/tex].

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To determine the cost of buying different numbers of songs for his mp3 player, Raymond needs to know the cost of a single song and the total number of songs he wants to buy, as well as consider bulk purchasing options like buying an album.

Assuming the cost of a single song is $1, if Raymond wants to buy 10 songs, the cost would be 10 x $1 = $10. Similarly, if Raymond wants to buy 20 songs, the cost would be 20 x $1 = $20. In general, the cost of buying n songs would be n x $1.

If the cost of a single song is not $1, then Raymond would need to adjust his calculations accordingly. For example, if the cost of a single song is $0.99, then the cost of buying 10 songs would be 10 x $0.99 = $9.90, and the cost of buying 20 songs would be 20 x $0.99 = $19.80.

Raymond could also consider purchasing songs in bulk, such as by buying an album, which typically offers a discounted price compared to purchasing individual songs. In this case, the cost of buying different numbers of songs would depend on the number of songs in the album and the cost of the album.

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Complete Question:

Raymond wants to know the costs of buying different numbers of songs for his MP3 player. The cost of each song is the same.

• Let s represent the possible number of songs Raymond could buy.

• Let d represent the amount of money, in dollars, Raymond would need to buy the songs.

Fill in the table for all missing values of s and d.

Number of songs, s

Amount of money ($), d

2

2.58

5.16

7

11

21.93

The probability that the outcome is a divisor of 4 given that it is prime is 0.125, or 12.5%.

Since we are given the probabilities of different outcomes, we can use the definition of conditional probability to find p(a|b), which represents the probability that the outcome is a divisor of 4 given that it is prime.

The formula for conditional probability is:

p(a|b) = p(a ∩ b) / p(b)

where p(a ∩ b) represents the probability of both events happening simultaneously.

Looking at the table of outcomes and their probabilities, we can see that there are four prime numbers: 2, 3, 5, and 7. Of these, only 2 is a divisor of 4.

Therefore, p(a ∩ b) is the probability that the outcome is 2, which is 0.1.

The probability of the outcome being prime is the sum of the probabilities of the four prime outcomes, which is:

p(b) = 0.1 + 0.2 + 0.3 + 0.2 = 0.8

Substituting these values into the formula for conditional probability, we get:

p(a|b) = p(a ∩ b) / p(b) = 0.1 / 0.8 = 0.125

Therefore, the probability that the outcome is a divisor of 4 given that it is prime is 0.125, or 12.5%.

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To conduct the science experiment, the temperature needs to be decreased from 36°C at a rate of 4°C every hour.

So, after 1 hour, the temperature will be 36°C - 4°C = 32°C. After 2 hours, the temperature will be 32°C - 4°C = 28°C. Continuing this pattern, after 10 hours, the temperature will be 36°C - (4°C x 10) = 36°C - 40°C = -4°C.

However, this temperature is below freezing and unlikely to be accurate for a science experiment.

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The quotient is -58x2 + 131x - 234 with a remainder of -5898.To solve this problem, we need to use long division. The dividend is 223 + 3x2 + 5x - 4 and the divisor is 22 + 2 + 1, which simplifies to 25.

We start by dividing 2 into 22, which gives us 11. We then write 11 above the 2 and multiply it by 25, which gives us 275. We subtract 275 from 223, which gives us -52. We bring down the 3, which gives us -523. We then repeat the process by dividing 2 into 52, which gives us 26. We write 26 above the 5 and multiply it by 25, which gives us 650. We subtract 650 from -523, which gives us -1173. We bring down the 1, which gives us -11731. We divide 2 into 117, which gives us 58.

We write 58 above the x and multiply it by 25, which gives us 1450. We subtract 1450 from -1173, which gives us -2623. We bring down the -4, which gives us -26234. We divide 2 into 262, which gives us 131. We write 131 above the 5 and multiply it by 25, which gives us 3275. We subtract 3275 from -2623, which gives us -5898. Therefore, the quotient is -58x2 + 131x - 234 with a remainder of -5898.

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If each bag of hot chips requires around 500 ml of soda to drink with, then 46,000 ml of soda would be needed to buy 20 bags of 4 bags of hot chips and 3 bottles of soda.

To determine how much soda is needed if you buy 20 bags of 4 bags of hot chips and 3 bottles of soda, we need to know the volume of each bottle of soda.

Assuming each bottle of soda contains 2 liters of soda, the total volume of soda needed can be calculated as follows:

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I see that this is a rate of change time of problem

If andy can run 20 miles in 6 hours, than our goal is to find out how much he runs in a hour

So, we just have to divide 20 by 6.

It's sorta hard to explain

Questions?

Anyhow, the answer is around 3.3 miles per hour

Answer:

3.33 miles

Step-by-step explanation:

We Know

Andy can run 20 miles in 6 hours.

How many miles can he run in 1 hour?

We Take

20 / 6 ≈ 3.33 miles

So, Andy can run about 3.33 miles in 1 hour.

a) The graph of the given lines is as attached

b) The area of the enclosed triangle is: 8 square units

The general form of expression of linear equations in slope intercept form is expressed as:

y = mx + c

where:

m is slope

c is y-intercept

We are given the equations as:

y = x + 5

y = 5

x = 4

The graph of these three linear equations is as shown in the attached file

2) The area of the given triangle enclosed by the three lines is gotten from the formula:

A = ¹/₂ * b * h

where:

A is area

b is base

h is height

Thus:

A = ¹/₂ * 4 * 4

A = 8 square units

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The different possible exams for the 6 essay questions from which only 4 appear is equal to 15.

n is the total number of items in the set = 6 essay questions

r is the number of items we want to choose = 4 questions

Using combinations,

which is a way of counting the number of ways to choose a certain number of items from a larger set without regard to order.

Choose 4 out of the 6 essay questions, without regard to the order in which they appear on the exam.

Use the formula for combinations,

C(n, r) = n! / (r! × (n - r)!)

Plugging in the values, we get,

⇒C(6, 4) = 6! / (4! × (6 - 4)!)

⇒C(6, 4) = 6! / (4! ×2!)

⇒C(6, 4) = (6 × 5 × 4 × 3) / (4 × 3 × 2 × 1)

⇒C(6, 4) = 15

Therefore, there are 15 different exams possible, each consisting of 4 out of the 6 essay questions provided by the professor.

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The difference between the abscissa of P and Q is 1.

The abscissa of a point is its x-coordinate, or horizontal distance from the origin (usually measured along the x-axis).

In the given problem, the abscissa of point P is -2, which means it is located 2 units to the left of the origin on the x-axis. The abscissa of point Q is -3, which means it is located 3 units to the left of the origin on the x-axis.

To find the difference between the abscissas of P and Q, we simply subtract the abscissa of Q from the abscissa of P:

(abscissa of P) - (abscissa of Q) = (-2) - (-3) = -2 + 3 = 1

Therefore, the difference between the abscissas of P and Q is 1 unit.

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