find the common ratio and the 12th term of the geometric sequence 64, 16, 4, ...​

Answers

Answer 1

Answer:

common ration = 1/4

12th term = 1/65536

Step-by-step explanation:

64

64*1/4 = 16

16 * 1/4 = 4

4* 1/4 = 1

1 * 1/4 = 1/4

1/4*1/4 = 1/16

1/16*1/4 = 1/64

etc

1/256

1/1024

1/4096

1/16384

12th term = 1/65536

Answer 2

Answer:

see explanation

Step-by-step explanation:

The common ratio r is calculated as

[tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{16}{64}[/tex] = [tex]\frac{1}{4}[/tex]

The n th term of a geometric sequence is

[tex]a_{n}[/tex] = a₁[tex](r)^{n-1}[/tex]

where a₁ is the first term and r the common ratio

Here a₁ = 64 and r = [tex]\frac{1}{4}[/tex] , thus

[tex]a_{12}[/tex] = 64 × [tex](\frac{1}{4}) ^{11}[/tex] = 64 × [tex]\frac{1}{4194304}[/tex] = [tex]\frac{64}{4194304}[/tex] = [tex]\frac{1}{65536}[/tex]


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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explaination

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Go to QuestionCove for better answers, it's too hard for me TwT

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