For each equation determine whether it has no solutions, exactly one solution, or is true

for all values of x (and has infinitely many solutions). If an equation has one solution, solve

to find the value of x that makes the statement true.

a. 6r+8 = 7x + 13

b6r + 8 = 2(3x + 4)

c. 6r+8 = 6r+ 13

Answers

Answer 1

For the given equations , the solutions are as follows :

(a) the equation [tex]6x + 8 = 7x + 13[/tex] has exactly one solution , and the solution is  .

(b) the equation [tex]6x + 8 = 2(3x + 4)[/tex] has Infinitely Many Solutions .

(c) the equation [tex]6x + 8 = 6x + 13[/tex] has No Solution .

Equation (a) ;

the equation is given as [tex]6x + 8 = 7x + 13[/tex] , we solve the equation further ,

we get ;

[tex]7x - 6x = 13 - 8[/tex] ;

[tex]x = 5[/tex] ;

So , the equation has exactly one solution and the solution is [tex]x = 5[/tex] .

Equation (b) ;

the equation is given as [tex]6x + 8 = 2(3x + 4)[/tex] , we solve equation further ,

we get ;

[tex]6x + 8 = 6x + 8[/tex] ;

On solving further ,

we have ;

[tex]8 = 8[/tex] ;

So , the equation has infinitely many solutions .

Equation (c) ;

the equation is given as [tex]6x + 8 = 6x + 13[/tex] , we solve equation further ,

we get ;

[tex]8 = 13[/tex] ;

and we know that [tex]8\neq 3[/tex] ,

So , the equation have No Solution .

The given question is incomplete , the complete question is

For each equation determine whether it has no solutions, exactly one solution, or is true . for all values of x (and has infinitely many solutions). If an equation has one solution, solve to find the value of x that makes the statement true.

(a) 6x + 8 = 7x + 13

(b) 6x + 8 = 2(3x + 4)

(c) 6x + 8 = 6x + 13

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Step-by-step explanation:

do you need to show your work or just the answer?

-3x+7y=12                                   mulitply both sides by 3 of the bottom.

x-2y=-3

-3x+7y=12                    

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The expression (x - 8) is not the factor of the polynomial x⁶ - 64x⁴ + x² - 7x - 51.

What is factorization?

It is a method for dividing a polynomial into pieces that will be multiplied together. At this moment, the polynomial's value will be zero.

The polynomial is given below.

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