gravitational potential is the energy due to an object's:
a. motion
b. spring stretch or compression
c. position in a gravity field
d. chemical bonds.​

Answer: sliding

Explanation:

A snow skier slowing to a stop after skiing down a mountain is an example of sliding friction

Answer:

static friction

Explanation:

Answer:

1. Shield volcano

Runny,basaltic magma with low silica and low gas content. Has a broad,low profile.

2. Cinder cone volcano

Thick viscosity andesitic magma with high silica content and high gas content. Rapidly solidifying lava forms high,steep-sided cones.

3. Composite volcano

Medium viscosity rhyolitic magma with medium silicon content and medium gas content.Have flatter domes called cones.

Explanation:

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Step 1 First Draw a Diagram.

Step 2 Identify the givens

g= -9.8 m/sec2

x0 = 0 m

Y-Yo= 80m

V0 = 800m/s -30o inclined from horizontal

Xf= ?

t = ?

Step 3  * A 2 dimensional problem so break it down into x component and y component

Step 4   x component  

x= [Vox ][cos 30o][t]

x= [800m/s][cos 30o][tsec]

x=[692.8m/s][tsec]       <---------------Need t

Step 5 y component

Y-Yo= Voy - 1/2gt2

80m= -[v][sin30o][t] -1/2gt2

1/2gt2+[v][sin30o][t]+80m=0   <-------Form Quadratic Equation

Solve for t

t=   -[v sin 30]  +/-   [(v sin 30)-(4)(1/2)(9.8)(80)]1/2

                      (2)(1/2)(9.8)

t= 400+/- 398

        9.8

t= 0.2 sec

Step 6 Plug this into initial x component equation

x=[692.8m/s][tsec]

Answer: You can Identify any biases about the answer to the scientific question.

Explanation:

Elliptical galaxies are galaxies that are shaped like an ellipse. An ellipse is oval in shape, which means elliptical galaxies are oval in shape.

The two correct statements that describe elliptical galaxies are:

B. They are the most common galaxy type.

C. They typically contain very little gas and dust.

Therefore, from the above explanation, we can see that option B and C is the correct option.

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The statements which describes elliptical galaxies are Choice B and Choice C:

Ultimately, elliptical galaxies are the oldest and are the most common galaxy type and they typically contain very little gas and dust.

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The Ojibwe protected walleye populations as D. They said a limit on the number and size of Walleye a spearfisher can catch.

Wisconsin Walleye War was a series of protests regarding the fishing and hunting rights of the Ojibwes. Wisconsin wanted to regulate the rights of the people whenever they went fishing and hunting.

The protest eventually led to the state speaking to the people. This resulted in a resolution that there should be a limit on the number and size of Walleye a spearfisher can catch.

This was necessary in order to preserve the walleye for future generations.

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4.9 m/s to the right

Explanation:

We are going to use the conservation law of linear momentum to find her velocity. Initially, they are motionless so their initial total momentum is zero. Let's assume that anything moving to the left has a negative velocity and anything moving to the right has a positive velocity. We can write the conservation law of momentum as

[tex]0 = M_mv_m + M_wv_w[/tex]

where

[tex]M_m[/tex] = mass of the man = 55 kg

[tex]v_m[/tex] = velocity of the man = -4.3 m/s

[tex]M_m[/tex] = mass of the woman = 48 kg

[tex]v_w[/tex] = velocity of the woman

[tex]\Rightarrow 0 = (55\:\text{kg})(-4.3\:\text{m/s}) + (48\:\text{kg})v_w[/tex]

Solving for [tex]v_w,[/tex]

[tex]v_w = \left(\dfrac{55\:\text{kg}}{48\:\text{kg}}\right)(4.3\:\text{m/s}) = 4.9\:\text{m/s}[/tex]

going to the right.

Answer:

C. Acetylcholine; dopamine

Acetylcholine is to Alzheimer's disease dopamine as is to Parkinson's disease. That is option C.

The neurological disorders are does diseases that affect the nervous system of an individual.

Examples of the neurological disorder include:

Therefore, Acetylcholine is to Alzheimer's disease dopamine as is to Parkinson's disease.

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Answer:

hope you will understand

Explanation:

The Planck model for the black body and the emission spectrum of the atoms allows to find the results for the peaks in the spectrum of stars is:

The stars are very hot celestial bodies by nuclear fusion processes, in a good approximation they approximate an ideal body that absorbs or emits all the radiation called black body.

A black body is a cavity in thermal equilibrium at a dated temperature with a small hole, this hole is the so-called black body and its emission spectrum was explained by Planck, with the assumption that the energy is

             E = h νν

Where h is Planck's constant and ν is the frequency of the radiation. In the attachment we see the emission spectrum of a black body for various temperatures.

If in the material under study we have in addition the emission characteristics of some elements, it is energy appears as peaks in the emission spectrum and as black bands o valley in an absorption spectrum, therefore the existence of the structure is in a test of the existence of chemical elements within the stars.

In the attachment we can see the spectrum of a dwarf star where we can appreciate the spectrum of the black body and the emission and absorption lines of the chemical elements inside the star.

In conclusion using the Planck model for the black body and the emission spectra of the atoms we can find the results for the peaks in the spectrum of stars is:

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Answer:

the first answer is correct

The answer is C. 40N.

No. That won't help. It's not even true.

Answer:

1. Test tube

2. tongs

3.

4.  FUNNEL

5.  

6.

7. Flask

8. Beaker

9. Bunsen burner

10. Erlenmeyer Flask

11.  Molar and pestle

12. Wire gauze

13.  Graduated cylinder

14. Test tube rack

15.  Pipet

16. Filo

Explanation:

The actual speed or velocity of the man relative to the earth is 15.52km/hr.

The direction of the man's velocity relation to earth is 75° South of West.

Given the data in the question;

To get the velocity of the man relative to the earth. From Pythagorean theorem

We can simply say

[tex]v_E = \sqrt{(v_{mrs})^2 + (v_s)^2}[/tex]

We substitute in our given values

[tex]v_E = \sqrt{(4km/hr)^2 + (15km/hr)^2}\\\\v_E = \sqrt{(16km^2/hr^2) + (225km^2/hr^2})\\\\v_E = \sqrt{241km^2/hr^2}\\\\v_E = 15.52 km/hr[/tex]

Therefore, the actual speed or velocity of the man relative to the earth is 15.52km/hr

To get the direction of the man's speed. From the three main trigonometric ratios: SOH CAH TOA

[tex]tan\theta = \frac{opposite}{adjacent}[/tex]

[tex]tan\theta = \frac{v_s}{v_{mrs}}[/tex]

We substitute in our values;

[tex]tan\theta = \frac{15km/hr}{4km/hr}\\\\tan\theta = 3.75\\\\\theta = tan^{-1}( 3.75)\\\\\theta = 75^o[/tex]

Therefore, the direction of the man's velocity relation to earth is 75° South of West

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Answer:

yes by 30

Explanation:

uhnhuh

Answer:

5 is the tripoid stand

Thanks have a bangtastic day

Answer:

hii there

5 ) tripod

6 ) test tube holder

Explanation:

Hope it helps

Have a nice day : )

Option D is correct. Around the age of five, children begin to experience their first dreams and nightmares

By the time children are five years old, several developments occur in their sleep patterns.

Option A is incorrect because the typical 90-minute sleep cycles of alternating REM (Rapid Eye Movement) and NREM (Non-Rapid Eye Movement) are not yet established at this age.

Option B is also incorrect as the sleep time distribution between REM sleep and quiet sleep (similar to NREM stages 1 and 2) is not necessarily equal at this stage.

Option C is inaccurate because 60-minute sleep cycles producing up to 13 cycles per day do not align with the typical sleep patterns of five-year-olds.

However, option D is correct. Around the age of five, children begin to experience their first dreams and nightmares.

This is an important milestone in their cognitive and emotional development, as it reflects the maturation of the brain regions involved in dreaming and the processing of emotions during sleep.

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Answer:what is the problems

Explana:

Explanation:

A. is chemically identical to heroin.

Answer:

Explanation:

N = mg = (1.00 + 0.500)(9.81) = 14.7 N

The magnitude of the normal force exerted on book A by the table is 14.7 N

From the question, we are to determine the magnitude of the normal force.

The normal force ca be calculated by using the formula

[tex]F_{n} = mg[/tex]

Where [tex]F_{n}[/tex] is the normal force

m is the mass

and g is the gravitational field strength ( g = 9.8 m/s²)

The mass will be addition of the masses since Book B is placed on top of the book.

Thus,

m = 1.00 kg + 0.500 kg = 1.50 kg

Then,

[tex]F_{n} = 1.5 \times 9.8[/tex]

[tex]F_{n} = 14.7 \ N[/tex]

Hence, the magnitude of the normal force exerted on book A by the table is 14.7 N

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Answer: 1 sig fig

Explanation: because 0s aren‘t significant and yes decimal points matter but after the decimal it’s a 0. So it is 1. If it was 0.30 it would be 2 sig figs but 0.03 would be one sig fig.

The frequency of rotation of Mars is 0.0000113 Hertz.

Given the following data:

To find the frequency of rotation in Hertz:

First of all, we would convert the the value of period in days and minutes to seconds because the period of oscillation of a physical object is measured in seconds.

Conversion:

1 day = 24 hours

24 hours to minutes = [tex]60[/tex] × [tex]24[/tex] = [tex]1440[/tex] minutes

[tex]1440 + 37 = 1477 \; minutes[/tex]

1 minute = 60 seconds

1477 minute = X seconds

Cross-multiplying, we have:

[tex]X = 60[/tex] × [tex]1477[/tex]

X = 88620 seconds

Now, we can find the frequency of rotation of Mars by using the formula:

[tex]Frequency = \frac{1}{Period}\\\\Frequency = \frac{1}{88620}[/tex]

Frequency of rotation = 0.0000113 Hertz

Therefore, the frequency of rotation of Mars is 0.0000113 Hertz.

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Answer:

Explanation:

Without the FBD or a good description of the set up, I'd have to say we cannot tell.

If the set up is of the simplest form with a mass on a horizontal surface being acted on by a horizontal force, then that force must be 80 + 25 = 105 N.

As force is a vector, there are an infinite number of other possibilities for force magnitude depending on which direction the force is acting. The mass is also an unknown variable that would affect the applied force magnitude if the direction is not horizontal.

Answer:

The acceleration is g.

Taking the upward direction as positive

V = Vy y - 1/2 g t^2

Taking the downward direction as positive

V = -V y + 1/2 g t^2

One can choose either direction as positive, but the acceleration is

the same as g (it is g) while the projectile is in the air.

When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). Thus, the correct option is D.

Projectile motion is the motion of an object which is thrown or projected high into the air. After the initial force applied on the object that launches the object, the object only experiences the gravitational force. The object is called a projectile and the path of the object is called trajectory.

When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). When the object achieves highest point, then the vertical acceleration of a projectile is zero meter per second square when it is at the peak of its trajectory motion.

Therefore, the correct option is D.

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If the voltage across a resistor is increased by a factor of two, the current in the resistor doubles.

When all physical parameters and temperature are constant, Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

This current-voltage connection may be expressed mathematically as,

The Equation of Ohm's Law;

V∝I

V'∝I'

Hence, if the voltage across a resistor is increased by a factor of two, the current in the resistor doubles.

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