The ratio of Kaido's age to Hiroshi's age to Saitama's age is 5:8:24.
How to find the ratio of there ages?Hiroshi is 6 years older than Kaido. Saitama is three times as old as Hiroshi. The sum of their three ages is 79.
Therefore, the ratio of Kaido's age to Hiroshi's age to Saitama's age can be calculated as follows:
Hence,
let
x = Kaido age
Hiroshi age = 6 + x
Saitama age = 3(6 + x) = 18 + 3x
Therefore,
x + 6 + x + 18 + 3x = 79
5x = 79 - 24
5x = 50
x = 50 / 5
x = 10
Therefore,
x = Kaido age = 10 years
Hiroshi age = 6 + x = 6 + 10 = 16 years
Saitama age = 3(6 + x) = 18 + 3x = 18 + 3(10) = 48 years
Hence, the ratio of there ages are as follows:
10:16:48
Let's divide through by 2
5:8:24
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Joel measures the heights of some plants. The heights of the plants, in feet, are
î
2
, 1, , $; , and 1. Which line plot correctly shows Joel's data?
Plant Heights
Plant Heights
Х
Х Х х
+ + +
X
x x x x x
A
Х
A
0
Height (feet)
Height (feet)
Plant Heights
Plant Heights
Х
Х
X
Х
A
Height (feet)
Height (feet)
In this line plot, the Xs represent the heights of the plants, and the A represents the number of plants with that height.
How to find the line plot that correctly shows Joel's data?The line plot that correctly shows Joel's data is:
Plant Heights
Х
Х
X
X
A
0
Height (feet)
In this line plot, the Xs represent the heights of the plants, and the A represents the number of plants with that height. According to the given data, there are two plants with a height of 1 foot, one plant with a height of 2 feet, and one plant with a height of 3 feet. Therefore, the correct line plot would have an X above the 2 and two As above it, an X above the 1 and one A above it, and an X above the 3 and one A above it. The other line plot shown does not correctly represent Joel's data.
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A right triangle is shown. The length of the hypotenuse is 4 centimeters and the lengths of the other 2 sides are congruent.
The hypotenuse of a 45°-45°-90° triangle measures 4 cm. What is the length of one leg of the triangle?
2 cm
2 StartRoot 2 EndRoot cm
4 cm
4 StartRoot 2 EndRoot cm
Answer:
The length of one leg of this right triangle is 4/√2 = 2√2 cm.
The gcf of 16mn and 24m
How do you do this problem?
Knowing that tan(x) = 3/5 and using a trigonometric identity, we will get that:
tan(2x) = 1.875
How to find the tangent of 2x?There is a trigonometric identity we can use for this, we know that:
[tex]tan(2x) = \frac{2tan(x)}{1 - tan^2(x)}[/tex]
So we only need to knos tan(x), which we already know that is equal to 3/5, then we can replace it in the formula above to get:
[tex]tan(2x) = \frac{2*3/5}{1 - (3/5)^2}\\\\tan(2x) = \frac{6/5}{1 - 9/25} \\tan(2x) = 1.875[/tex]
That is the value of the tangent of 2x.
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The rate of change of the gender ratio for the United States during the twentieth century can be modeled as g(t) = (1. 68 · 10^−4)t^2 − 0. 02t − 0. 10
where output is measured in males/100 females per year and t is the number of years since 1900. In 1970, the gender ratio was 94. 8 males per 100 females.
(a) Write a specific antiderivative giving the gender ratio.
G(t) = _______________ males/100 females
(b) How is this specific antiderivative related to an accumulation function of g?
The specific antiderivative in part (a) is the formula for the accumulation function of g passing through (t, g) =
Answer:
(a) G(t) = (1.68 × 10^-4) × (1/3) t^3 - (0.02/2) t^2 - 0.10t - 2445.84
(b) A(t) = G(t) - G(1900) = (1.68 × 10^-4) × (1/3) (t^3 - 1900^3) - (0.02/2) (t^2 - 1900^2) - 0.10(t - 1900)
Step-by-step explanation:
(a) The antiderivative of g(t) can be found by integrating each term of the function with respect to t:
∫g(t) dt = ∫(1.68 × 10^-4)t^2 dt - ∫0.02t dt - ∫0.10 dt
= (1.68 × 10^-4) × (1/3) t^3 - (0.02/2) t^2 - 0.10t + C
where C is the constant of integration.
To find the specific antiderivative G(t) that passes through the point (1970, 94.8), we can use this point to solve for C:
94.8 = (1.68 × 10^-4) × (1/3) (1970)^3 - (0.02/2) (1970)^2 - 0.10(1970) + C
C = 94.8 + (1.68 × 10^-4) × (1/3) (1970)^3 - (0.02/2) (1970)^2 - 0.10(1970)
C ≈ -2445.84
Therefore, the specific antiderivative that gives the gender ratio is:
G(t) = (1.68 × 10^-4) × (1/3) t^3 - (0.02/2) t^2 - 0.10t - 2445.84
(b) The accumulation function of g is the integral of g with respect to t, or:
A(t) = ∫g(t) dt = G(t) + C
where C is the constant of integration. We can find the value of C using the initial condition given in the problem:
A(1900) = ∫g(t) dt ∣t=1900 = G(1900) + C = 0
Therefore, C = -G(1900), and the accumulation function of g is:
A(t) = G(t) - G(1900) = (1.68 × 10^-4) × (1/3) (t^3 - 1900^3) - (0.02/2) (t^2 - 1900^2) - 0.10(t - 1900)
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What is the mass of a cylinder of lead with a radius of 1 centimeter and a height of 3 centimeters, given that the density of lead is 11. 4 g/cm?
The mass of the cylinder of lead with a radius of 1 centimeter and a height of 3 centimeters is 107.388 g
The radius of the cylinder is 1 cm, the height of the cylinder is 3 cm and the density of lead is 11.4 g/cm.
Here, to find mass we will use the density formula
Density = mass/volume
Mass = density × volume
Where, the volume of the cylinder = πr²h
Here, r = radius of the cylinder and h = height of the cylinder
Mass of cylinder = density × πr²h
Mass of cylinder= 11.4×3.14×1×1×3
Mass of cylinder = 107.388 g
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2x + 7 = -1(3 - 2x) solve for X
This linear equation is invalid, the left and right sides are not equal, therefore there is no solution.
What in mathematics is a linear equation?
An algebraic equation with simply a constant and a first-order (linear) component, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation.
Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables. Equations with variables of power 1 are referred to be linear equations. axe+b = 0 is a one-variable example in which a and b are real numbers and x is the variable.
2x + -7 = -1(3 + -2x)
Reorder the terms:
-7 + 2x = -1(3 + -2x)
-7 + 2x = (3 * -1 + -2x * -1)
-7 + 2x = (-3 + 2x)
Add '-2x' to each side of the equation.
-7 + 2x + -2x = -3 + 2x + -2x
Combine like terms: 2x + -2x = 0
-7 + 0 = -3 + 2x + -2x
-7 = -3 + 2x + -2x
Combine like terms: 2x + -2x = 0
-7 = -3 + 0
-7 = -3
Solving
-7 = -3
Couldn't find a variable to solve for.
This equation is invalid, the left and right sides are not equal, therefore there is no solution.
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what is the volume of a cylinder, in cubic feet, with. height of 7 inches and a base diameter of 18ft
148.35 cubic feet is the volume of a cylinder with height of 7 inches and a base diameter of 18ft
We have to find the volume of a cylinder
V=πr²h
h is the height of cylinder and r is radius of the base.
Given height is 7 inches which is 0.583333 feet
Diameter is 18 ft
Radius is 9 ft
Now plug in value of height and radius
Volume=π(9)²×0.5833
=3.14×81×0.5833
=148.35 cubic feet
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Sushi corporation bought a machine at the beginning of the year at a cost of $39,000. the estimated useful life was five years and the residual value was $4,000. required: complete a depreciation schedule for the straight-line method. prepare the journal entry to record year 2 depreciation.
Entry debits the Depreciation Expense account for $7,000 and credits the Accumulated Depreciation account for the same amount, reflecting the decrease in the value of the machine over time.
To calculate deprecation using the straight- line system, we need to abate the residual value from the original cost of the machine and also divide the result by the estimated useful life. Using the given values, we have
Cost of machine = $ 39,000
Residual value = $ 4,000
Depreciable cost = $ 35,000($ 39,000-$ 4,000)
Estimated useful life = 5 times
To calculate the periodic deprecation expenditure, we divide the depreciable cost by the estimated useful life
Periodic deprecation expenditure = $ 7,000($ 35,000 ÷ 5)
Depreciation Expense $7,000
Accumulated Depreciation $7,000
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The journal entry is as given in figure:
Find the exact location of all the relative and absolute extrema of the function. (Order your answers from smallest to largest x.) g(x) = 3x³ - 36x with domain [-4, 4] g has an absolute minimum at (x,y) =
We can see that the absolute minimum occurs at (x, y) = (2, -48).
To find the relative and absolute extrema of the function g(x) = 3x³ - 36x on the domain [-4, 4], we first need to find the critical points. We do this by finding the first derivative, setting it to zero, and solving for x.
g'(x) = d(3x³ - 36x)/dx = 9x² - 36
Setting g'(x) to 0:
0 = 9x² - 36
x² = 4
x = ±2
These are our critical points. To determine if these are minima, maxima, or neither, we use the second derivative test.
g''(x) = d(9x² - 36)/dx = 18x
At x = -2:
g''(-2) = -36 < 0, so it's a relative maximum.
At x = 2:
g''(2) = 36 > 0, so it's a relative minimum.
Now, we need to compare the function values at the critical points and endpoints of the domain to determine the absolute extrema.
g(-4) = 3(-4)³ - 36(-4) = -192
g(-2) = 3(-2)³ - 36(-2) = 48 (relative maximum)
g(2) = 3(2)³ - 36(2) = -48 (relative minimum)
g(4) = 3(4)³ - 36(4) = 192
From the above values, we can see that the absolute minimum occurs at (x, y) = (2, -48).
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Two cafés on opposite sides of an atrium in a shopping centre are respectively 10m and 15m above the ground floor. If the cafés are linked by a 20m escalator, find the horizontal distance (to the nearest metre) across the atrium, between the two cafés
The horizontal distance between the two cafes is approximately 19.36 meters.
To solve this problem, we can use the Pythagorean theorem which states that in a right-angled triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
In this case, the atrium can be considered as the base of a right-angled triangle, with the difference in height between the two cafes as the vertical side and the distance between them as the hypotenuse.
Let's call the horizontal distance we are looking for "x". Using the Pythagorean theorem, we have:
[tex]x^2 = 20^2 - (15 - 10)^2\\x^2 = 400 - 25\\x^2 = 375[/tex]
x ≈ 19.36
Therefore, the horizontal distance between the two cafes is approximately 19.36 meters.
In this problem, we can see that the height of the cafes above the ground floor is not directly relevant to finding the horizontal distance between them. Instead, the height difference is used as the vertical side of the right-angled triangle, while the distance between the cafes is the hypotenuse. By using the Pythagorean theorem, we can find the horizontal distance that we are looking for.
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d – 10 – 2d + 7 = 8 + d – 10 – 3d
d = –5
d = –1
d = 1
d = 5
Answer:
d=1
Step-by-step explanation:
(i have to write this cuz i cant write less than 20 words)
stressing outtt I need help its due in a few minuets
You suspect that an unscrupulous employee at a casino has tampered with a die; that is, he is using a loaded die. In order to test your suspicion, you rolled the die in question 200 times and obtained the following frequencies for each of the six possible outcomes of the die:
Number Frequency 1 2 3 4 5 6 45 39 35 25 27 29
Can you conclude that the die is loaded? Use a 0. 05 as the significance level and perform a hypothesis test. Remember to state the null and alternative hypothesis
Based on the hypothesis test, with a significance level of 0.05, there is no evidence to suggest that the die is loaded, as the p-value is greater than the significance level. The null hypothesis that the die is fair is failed to rejected.
To determine if the die is loaded, we need to perform a hypothesis test.
Null Hypothesis (H0) The die is fair; all outcomes are equally likely.
Alternative Hypothesis (Ha) The die is loaded, and not all outcomes are equally likely.
We will use a significance level of 0.05.
To test the hypothesis, we can use a chi-square goodness-of-fit test.
First, we need to calculate the expected frequencies for each outcome, assuming that the die is fair. Since there are six possible outcomes, each with an expected frequency of 200/6 = 33.33.
Number Observed Frequency (O) Expected Frequency (E) (O - E)² / E
1 45 33.33 3.48
2 39 33.33 0.87
3 35 33.33 0.07
4 25 33.33 1.83
5 27 33.33 0.99
6 29 33.33 0.44
The test statistic is the sum of (O-E)² / E, which is 7.68.
The degrees of freedom for this test are (number of categories - 1) = 5.
Using a chi-square distribution table or calculator, we find that the p-value associated with a test statistic of 7.68 and 5 degrees of freedom is approximately 0.177.
Since the p-value is greater than our significance level of 0.05, we fail to reject the null hypothesis. We cannot conclude that the die is loaded based on this data alone.
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f(x) = x(x2 − 4) − 3x(x − 2)
To simplify the given function F(x) = x(x^2 - 4) - 3x(x - 2), we need to use the distributive property and combine like terms.
First, we distribute x in the first term, and we get:
F(x) = x^3 - 4x - 3x^2 + 6x
Next, we can combine like terms:
F(x) = x^3 - 3x^2 + 2x
Therefore, the simplified form of the given function F(x) = x(x^2 - 4) - 3x(x - 2) is F(x) = x^3 - 3x^2 + 2x.
Patrick and brooklyn are making decisions about their bank accounts. patrick wants to deposit $300 as a principle amount, with an interest of 6% compounded quarterly. brooklyn wants to deposit $300 as the principle amount, with an interest of 5% compounded monthly. explain which method results in more money after 2 years. show all work.
please give full explanation and work
Patrick's method of depositing $300 as the principle amount with an interest rate of 6% compounded quarterly results in more money after two years, with a final amount of $337.95.
To compare the two methods, we need to calculate the total amount of money each person will have after 2 years.
For Patrick:
The formula for compound interest is: A = P (1 + r/n)^(nt)
Where:
A = the total amount of money after t years
P = the principle amount
r = the annual interest rate (as a decimal)
n = the number of times the interest is compounded per year
t = the number of years
So for Patrick, we have:
A = 300 (1 + 0.06/4)^(4*2)
A = 300 (1.015)^8
A = 300*1.1265 = 337.95
After 2 years, Patrick will have $337.95.
For Brooklyn:
Using the same formula, we have:
A = 300 (1 + 0.05/12)^(12*2)
A = 300 (1.004167)^24
A = 300 * 1.10495 = 331.485
After 2 years, Brooklyn will have $331.485.
Therefore, Patrick's method of depositing $300 as the principle amount with an interest rate of 6% compounded quarterly results in more money after two years. Patrick will have $337.95, which is slightly more than Brooklyn with $331.485.
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Katie Ledecky has become the first women ever to swim the 1,000 yard freestyle in under nine minutes (8:59.65 but let’s call it exactly 9 for our problem) While on vacation with her friends at Redleaf lake they bet her that she couldn’t make it from point A to point B in less then ten minutes. Assuming she can swim at her Olympic level pace should she take this bet? Justify your work.
Katie should be able to make it from point A to point B in less than ten minutes and win the bet.
What is minute?A minute is a unit of time equal to 60 seconds or one sixtieth of an hour. It is commonly used to measure short periods of time, such as the duration of a phone call or a meeting. The symbol for minute is "min".
According to given information:To determine whether Katie Ledecky can make it from point A to point B in less than ten minutes, we need to calculate the distance between the two points and compare it to her swimming speed.
From the given information, we can use the Law of Cosines to find the distance between points A and B:
[tex]c^2 = a^2 + b^2 - 2ab cos(C)[/tex]
where c is the distance between points A and B, a is the distance from point A to point C, b is the distance from point B to point C, and C is the angle between sides a and b.
Plugging in the given values, we get:
[tex]c^2 = 620^2 + 455^2 - 2(620)(455) cos(150°)\\\\c^2 = 383,825[/tex]
c ≈ 619.5 yards
So the distance between points A and B is approximately 619.5 yards.
Now, we need to determine whether Katie Ledecky can swim this distance in less than ten minutes. We are given that she swam 1,000 yards in 8 minutes and 59.65 seconds, which is approximately 8.99 minutes. So her average speed for the 1,000 yard freestyle was:
speed = distance / time
speed = 1,000 yards / 8.99 minutes
speed ≈ 111.23 yards/minute
To swim the distance between points A and B in less than ten minutes, Katie would need to swim at an average speed of:
speed = distance / time
speed = 619.5 yards / 10 minutes
speed = 61.95 yards/minute
Katie's Olympic level swimming speed of 111.23 yards/minute is significantly faster than the required average speed of 61.95 yards/minute to swim from point A to point B in under ten minutes. Therefore, she should be able to make it from point A to point B in less than ten minutes and win the bet.
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Help with geometry on equations of circles. What would RSQ be?
Answer:
34.8°
Step-by-step explanation:
You want the angle between a tangent and a segment to the center from a point on the tangent that is 6 units from the circle of radius 8 units.
SineThe trig relation useful here is ...
Sin = Opposite/Hypotenuse
sin(S) = RQ/SQ
The length QT is the same as QR, so we have ...
sin(S) = 8/(8 +6)
S = arcsin(8/(8+6)) ≈ 34.8°
1. What is the probability of rolling a # larger than 2 and drawing an Ace or 4? A 2 3 4 5
The probability of rolling a number larger than 2 and drawing an Ace or 4 is 2/39. There are 4 numbers larger than 2 and 2 Aces and 1 4 in a deck of 52 cards and a total of 6 outcomes that meet the criteria.
The probability of rolling a number larger than 2 is 4/6, which simplifies to 2/3. The probability of drawing an Ace or 4 is 4/52, which simplifies to 1/13. To find the probability of both events happening, you multiply the probabilities
P(rolling a number larger than 2 and drawing an Ace or 4) = P(rolling a number larger than 2) x P(drawing an Ace or 4)
= (2/3) x (1/13)
= 2/39
Therefore, the probability of number larger than 2 and drawing an Ace or 4 is 2/39.
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Use the equations shown (attachment) to answer the following question.
Which of the equations are TRUE based on the exponential function 2x = 8 and show your work
I, III, and V
II, IV, and VI
II, III, and IV
I, V, and VI
The equations that are TRUE based on the exponential function 2x = 8, are I, III and V.
What is the log equation of the function?To convert this equation into log equation, we will apply the general rule of logarithm equation as follows;
2x = 8
log2(2x) = log2(8)
Using the logarithmic rule that;
logb(xy) = ylogb(x),
We can simplify the left side of the equation to;
xlog2(2) = log2(8)
Since log2(2) = 1, we can simplify the equation further to;
x = log2(8)
Also in linear equation, we have
2x = 8
x = 8/2
x = 4
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Explain me that excersice step by step please3x((2x3)^-1x1/2^3)^-1x(3x2^2)^-2
Answer:
Begin by simplifying the phrases within the brackets, beginning with the innermost brackets:
(2 x 3)^-1 = 1/6 (because 2 x 3 = 6, and the negative exponent flips the fraction)
1/2^3 = 1/8 (because 2^3 = 8)
So, (2x3)^-1x1/2^3 = 1/6 x 1/8 = 1/48
Next, simplify the expression outside the parentheses:
(3x2^2)^-2 = 1/(3x2^2)^2 = 1/(3^2 x 2^4) = 1/36 x 1/16 = 1/576
Now, substitute the simplified terms back into the original expression and simplify:
3x(1/48)x(1/576) = 1/768
So the final answer is 1/768.
a project has two activities a and b that must be carried out sequentially. the probability distributions of the times required to complete each of the activities a and b are uniformly distributed in intervals [1,6] and [3,7] respectively. find the total project completion time and run 6000 simulation trials in excel. a) what is the output of the simulations? b) what is the excel functions would properly generate a random number for the duration of activity a in the project described above? c) what is the standard deviation of the project completion time in the project described?
The project completion time is output of the simulations, option A, the EXCEL function used is (c) 1+4*RAND() and the standard deviation is
(b) 1.47.
1) In this simulation, we enter commands based on the way that activity durations are distributed (here uniformly with predetermined intervals). We determine the project completion time as an output based on the command we used and our calculations. This value will fluctuate (slightly) when the simulation is run, hence it is not fixed.
Hence, the "project completion time" is an (a) Output of the simulation.
2) Here, it is given that time required to complete activity A is uniformly distributed in an interval [1, 5].
So, we require random numbers starting from 1 with an interval of length 5-1=4.
We know, during simulation using usual Excel function RAND() we obtain random numbers in an interval [0, 1].
Thus if we multiply usual Excel function RAND() by 4 and thus use 4*RAND(), then we obtain random numbers in an interval [0*4, 1*4] i.e
[0, 4].
Adding 1 to this Excel function i.e. using Excel function 1+4*RAND() we obtain random numbers in an interval [0+1, 4+1] i.e [1, 5].
Hence, the Excel function to be used to generate random numbers for the duration of activity A is (c) 1+4*RAND().
3) For [tex]\tiny X\sim Unif\left ( a,b \right )[/tex], variance is given by
[tex]\tiny Var\left ( X \right )=\frac{\left ( b-a \right )^2}{12}[/tex]
Variance for activity A is given by
[tex]\tiny \frac{\left ( 5-1 \right )^2}{12}=\frac{4^2}{12}=1.333333[/tex]
Variance for activity B is given by
[tex]\tiny \frac{\left ( 3-2 \right )^2}{12}=\frac{1^2}{12}=0.083333[/tex]
Variance for activity C is given by
[tex]\tiny \frac{\left ( 6-3 \right )^2}{12}=\frac{3^2}{12}=0.75[/tex]
Variance of project completion time in the project is \tiny [tex]1.333333+0.083333+0.75= 2.166666[/tex]
So, standard deviation of project completion time in the project is [tex]\tiny \sqrt {2.166666}=1.47196\approx 1.47[/tex]
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Complete question:
A project has three activities A, B, and C that must be carried out sequentially. The probability distributions of the times required to complete each of the activities A, B, and C are uniformly distributed in intervals (1,5), (2,3) and (3,6) respectively. Find the total project completion time and run 1000 simulation trials in Excel. 7. The "project completion time" is a(n)... a. Output of the simulation b. Input of the simulation c. Decision variable in the simulation d. A fixed value in the simulation 8. Which of the following Excel functions would properly generate a random number for the duration of activity A in the project described above? a. 5* RANDO b. 1+5 * RANDO c. 1+4* RANDO d. NORM.INV(RAND(),1,5) e. NORM.INV(RAND(0,5,1) 9. The standard deviation of the project completion time in the project described above is cl a 2.83 b. 1.47 c. 1.15 d. 1.82 e. 1.63
At the baby next checkup the baby weighed 11 pounds and four ounces how many ounces did the baby gain since the appointment mentioned in the first probloem
If at the previous appointment the baby weighed 10 pounds and 8 ounces, then the baby has gained 12 ounces since the last appointment.
To calculate this, we need to subtract the weight at the previous appointment from the weight at the current appointment:
11 pounds and 4 ounces - 10 pounds and 8 ounces = 12 ounces
So the baby has gained 12 ounces since the last appointment. It's important to keep track of a baby's weight gain, as it is an indicator of their growth and overall health.
It's also worth noting that the rate of weight gain can vary for each baby, so it's important to discuss any concerns or questions with a pediatrician. Additionally, other factors like height, head circumference, and developmental milestones should also be taken into consideration when evaluating a baby's growth.
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5. copy the table and find the quantities marked *. (take t = 3)
curved
total
surface
area
area
*
2
2
vertical surface
object radius height
(a) cylinder
4 cm
72 cm
*
(b) sphere
192 cm2
(c) cone
4 cm
60 cm?
*
(d) sphere
0.48 m²
(e) cylinder
5 cm
(f) cone 6 cm
(g) cylinder
* * *
330 cm?
225 cm
108 m2
2
2 m
The table shows the calculated curved surface area, total surface area, and vertical surface area for various geometric objects, including cylinders, cones, and spheres. The missing values are found for each object, with a given value of t = 3.
Radius is 4 cm
Height is 72 cm
curved surface area of cylinder
2πrt = 2π(4)(72) = 576π cm²
total surface area
2πr(r+h) = 2π(4)(76) = 304π cm²
vertical surface area
2πrh = 2π(4)(72) = 576π cm²
Radius is 4 cm
Height is 60 cm
curved surface area of cylinder of cone
πr√(r²+h²) = π(4)√(4²+60²) = 124π cm²
total surface area
πr(r+√(r²+h²)) = π(4)(4+√(4²+60²)) = 140π cm²
vertical surface area
πr√(r²+h²) = π(4)√(4²+60²) = 124π cm²
total surface area of sphere
0.48 m² = 48000 cm²
curved surface area of cylinder
Radius is 5 cm
Height 2 m = 200 cm
2πrt = 2π(5)(200) = 2000π cm²
total surface area
2πr(r+h) = 2π(5)(205) = 2050π cm²
vertical surface area
2πrh = 2π(5)(200) = 2000π cm²
curved surface area of cylinder
Radius is 6 cm
Height 10 cm
πr√(r²+h²) = π(6)√(6²+10²) = 34π cm²
total surface area
πr(r+√(r²+h²)) = π(6)(6+√(6²+10²)) = 78π cm²
vertical surface area
πr√(r²+h²) = π(6)√(6²+10²) = 34π cm²
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Which phase of the process cycle for customer relationship management represents the actual implementation of the customer strategies and programs?
The phase of the process cycle for customer relationship management that represents the actual implementation of the customer strategies and programs is the "Execution" phase.
This is where the plans and strategies that were formulated in the earlier phases of the process cycle are put into action to interact with customers and build strong relationships with them.
During the Execution phase, the focus is on carrying out specific tactics to engage with customers and meet their needs, such as targeted marketing campaigns, personalized communication, and efficient service delivery.
The success of this phase relies heavily on the quality of the planning and preparation done in the earlier phases, as well as ongoing monitoring and adaptation to customer feedback and changing market conditions.
Effective execution of customer strategies and programs is crucial for building loyal and satisfied customers, and ultimately driving business growth.
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Consider the function y = 5x3 - 9x2 + 9x + 10. Find the differential for this function.
The differential for the function y = 5x^3 - 9x^2 + 9x + 10 is dy/dx = 15x^2 - 18x + 9.
Given function,
y = 5x^3 - 9x^2 + 9x + 10.
Process of finding differential:
2. Differentiate the function with respect to x:
dy/dx = d(5x^3)/dx - d(9x^2)/dx + d(9x)/dx + d(10)/dx
3. Apply the power rule for differentiation (d(x^n)/dx = n*x^(n-1)):
dy/dx = 3*(5x^2) - 2*(9x) + 9
4. Simplify the expression:
dy/dx = 15x^2 - 18x + 9
So, the differential for the function y = 5x^3 - 9x^2 + 9x + 10 is dy/dx = 15x^2 - 18x + 9.
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A culture of bacteria has an initial population of 65000 bacteria and doubles every 2
hours. Using the formula Pt = Po 2a, where Pt is the population after t hours, Po
is the initial population, t is the time in hours and d is the doubling time, what is the
population of bacteria in the culture after 13 hours, to the nearest whole number?
.
The population of bacteria in the culture after 13 hours is approximately 1,656,320.
What is the equation?An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.
We have the initial population, Po = 65000, and the doubling time, d = 2 hours. To find the population after 13 hours, we need to use the formula:
[tex]Pt = Po * 2^{(t/d)[/tex]
where Pt is the population after t hours, Po is the initial population, t is the time in hours, and d is the doubling time.
Substituting the given values, we get:
Pt = 65000 x [tex]2^{(13/2)[/tex]
Pt ≈ 1,656,320
Rounding this to the nearest whole number, we get:
The population of bacteria in the culture after 13 hours is approximately 1,656,320.
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A square based pyramid has a side length of 10 inches and a volume of 3300 inches^3. What is the height of the pyramid?
the height of the pyramid is 99 inches.
(explain)
To solve this problem, we can use the formula for the volume of a square pyramid which is:
Volume = (1/3) x (base area) x (height)
Since the base of our pyramid is a square with a side length of 10 inches, the base area would be:
Base area = (side length)^2 = 10^2 = 100 square inches
Substituting the values given in the problem, we get:
3300 = (1/3) x 100 x height
Multiplying both sides by 3, we get:
9900 = 100 x height
Dividing both sides by 100, we get:
height = 99 inches
Therefore, the height of the pyramid is 99 inches.
i need help please
20pts
Answer:
the answer is A
Step-by-step explanation:
√3 = Irrational
√12 = Irrational
but if
√3 × √ 12 = √36 = 6 = rational
The histogram shows the numbers of rebounds per game for a middle school basketball player in a season.
A vertical bar graph titled, Rebounds per Game. The vertical axis is labeled frequency and ranges from 0 to 7. The horizontal axis is labeled rebounds and has bin in the following intervals: For 0 to 1, the bar height is 3. For 2 to 3, the bar height is 6. For 4 to 5, the bar height is 2. For 6 to 7, the bar height is 1.
a. Which interval contains the most data values?
Responses
0–1 rebounds
0–1 rebounds
2–3 rebounds
2–3 rebounds
4–5 rebounds
4–5 rebounds
6–7 rebounds
6–7 rebounds
Question 2
b. How many games did the player play during the season?
The player played
games.
Question 3
c. In what percent of the games did the player have 4 or more rebounds?
The player had 4 or more rebounds in
% of the games.
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a. Which interval contains the most data values?
2–3 rebounds
b. How many games did the player play during the season?
The player played 12 games.
c. In what percent of the games did the player have 4 or more rebounds?
The player had 4 or more rebounds in 25% of the games.
What is a Histogram?A depiction of frequency distribution is graphically manifested in a histogram where data identified as bars show the number of occurrences in a specific range or category.
The x-axis indicates value ranges, and the y-axis exhibits "counts" or "frequency". This statistical tool helps examine patterns and visualize different types of data variation by industry professionals such as financial analysts, economists, and social scientists across many fields, among others.
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